Morgan is stacking boxes of tissue for a store display. Each row of tissues has 2 fewer boxes than the row below. The first row has 23 boxes of tissue. Write a function to represent the arithmetic sequence. How many boxes will there be in the tenth row?

The equation of the Line of the form y = mx is y = -x + 3.

To write an equation of the form y = mx for the line shown below (-1,4), we need to determine the slope (m) of the line first.

Let (x₁, y₁) = (-1, 4) be a point on the line. Now let's find another point on the line. Let's say we have another point (x₂, y₂) = (1, 2).The slope (m) of the line can be calculated using the formula:m = (y₂ - y₁) / (x₂ - x₁)Substituting the values,

we get:m = (2 - 4) / (1 - (-1))= -2 / 2= -1

Now that we know the slope of the line, we can use the point-slope form of the equation of a line to write the equation of the line:y - y₁ = m(x - x₁)Substituting the values, we get:y - 4 = -1(x - (-1))y - 4 = -1(x + 1)y - 4 = -x - 1y = -x - 1 + 4y = -x + 3

Therefore, the equation of the line is y = -x + 3 in slope-intercept form. Since the question specifically asks for the equation of the form y = mx, we can rewrite the equation in this form by factoring out the slope:y = -x + 3y = (-1)x + 3

Thus, the equation of the line of the form y = mx is y = -x + 3.

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______________________________________

→ To calculate the area of the field:

A = length x height

A = 100 m x 50 m

A = 5000 m²

______________________________________

→ To calculate the amount of money:

Cost = A x cost per square meter

Cost = 5000 m² x $4.99/m²

Cost = $24,950

______________________________________

→ Therefore, it would cost $24,950.

Answer:

Step-by-step explanation:

You want the upper and lower bounds for speed, given that distance 160 was traveled in time 7.2 (both to 2 significant figures).

As the problem statement tells you, speed is proportional to distance and inversely proportional to time.

The upper bound for speed will be the upper bound for distance divided by the lower bound for time.

  165/7.15 ≈ 23.1 . . . . . speed units (maximum)

The lower bound will be the lower bound for distance divided by the upper bound for time.

  155/7.25 ≈ 21.4 . . . . . speed units (minimum)

__

Additional comment

Dividing the nominal values, the nominal speed is 22.22... speed units. Rounded to 2 sf, this would be 22 speed units. The implied bounds are 22±0.5. You can see that the upper and lower bounds computed here are actually about 22.25±0.85.

<95141404393>

The expression to estimate the number of containers of salsa needed is: 48 × 3 × 9. none of the option is correct.

To estimate how many containers of salsa are needed for all the tables in one day, we need to consider the total number of tables and the number of salsa containers required for each table.

Given that there are 48 tables and each table has 3 different types of salsa, we can estimate the total number of containers needed by multiplying the number of tables by the number of salsa types.

However, we also need to account for the fact that there are 9 different sets of customers throughout the day. Each set of customers will use all the tables, so we need to multiply the estimated number of containers by the number of sets of customers to get an accurate estimation for the day.

Let's analyze the options provided:

A) 50 × 9: This option assumes there are 50 tables, which is incorrect based on the given information.

B) 16 × 3 × 9: This option assumes there are 16 tables, which is incorrect based on the given information.

C) 50 × 3 × 10: This option assumes there are 50 tables and 10 different sets of customers. Although the number of tables is incorrect, this option accounts for the number of salsa types and the number of sets of customers. However, it does not accurately represent the given scenario.

D) 40 × 5 × 5: This option assumes there are 40 tables and 5 different sets of customers. It also considers the number of salsa types. However, it does not accurately represent the given scenario as the number of tables is incorrect.

None of the options provided accurately represent the given scenario. The correct expression to estimate the number of containers of salsa needed for all the tables in one day would be:48 × 3 × 9

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Ciana should purchase the skirt at the store across town because the total economic cost will be lowest.

Ciana makes $30 per hour at her work, and her purchase decision includes the opportunity cost of lost wages:

Total economic cost:

Local store = $114 + [1/4 hours x 2 (round trip) x $30] + (1/2 hours x $30 spent shopping) = $144

Across town = $86 + [1/2 hours x 2 (round trip) x $30] + (1/2 hours x $30 spent shopping) = $131

Neighboring city = $60 + [1 hour x 2 (round trip) x $30] + (1/2 hours x $30 spent shopping) = $135

Ciana should buy a skirt at the store across town. Because it has the lowest total economic cost ($131).

Opportunity cost is the lost benefit or additional cost of choosing one activity or investment over another. Economic costs include both accounting costs and opportunity costs.  

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Answer: 120 yds

Step-by-step explanation:

48+30+24+18+120 yds

Answer:

Step-by-step explanation:

The equation that shows the Pythagorean identity is true for θ = 270° and is in the form sin²θ + cos²θ = 1 is option  B. 0² + (-1)² = 1

The Pythagorean identity is a fundamental trigonometric identity that relates the sine and cosine functions. It states that for any angle θ, the sum of the squares of the sine and cosine of that angle is equal to 1: sin²θ + cos²θ = 1.

We are given θ = 270° and we need to select the equation that satisfies the Pythagorean identity in the given form.

Let's evaluate each option:

A. 0² + 1² = 1

In this case, sin²θ = 0² = 0 and cos²θ = 1² = 1. Adding them together, we get 0 + 1 = 1, which satisfies the Pythagorean identity.

B. 0² + (−1)² = 1

Here, sin²θ = 0² = 0 and cos²θ = (−1)² = 1. Adding them, we have 0 + 1 = 1, which satisfies the Pythagorean identity.

C. (−1)² + 0² - 1

In this equation, sin²θ = (−1)² = 1 and co

s²θ = 0² = 0. However, the equation does not satisfy the Pythagorean identity because 1 + 0 - 1 ≠ 1.

D. 1² + 0² = 1

For this option, sin²θ = 1² = 1 and cos²θ = 0² = 0. Adding them together, we get 1 + 0 = 1, which satisfies the Pythagorean identity.

Based on our evaluation, options A and B both satisfy the Pythagorean identity for θ = 270°. Therefore, either A or B can be selected as the correct equation.The correct answer is  b.

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The Question was Incomplete, Find the full content below :

Which equation shows that the Pythagorean identity is true for θ = 270°?

Select the equation that is in the form sin²θ+ cos²θ = 1.

A. 0² + 1² = 1

B. 0² + (−1)² = 1

C. (-1)² + 0² - 1

D. 1² + 0² = 1

Answer:

x=6-x2-y

Step-by-step explanation:

Swap sides so that all variable terms are on the left hand side.

add x2 to both side

Subtract 6 from both sides.

Divide both sides by −1.

Dividing by −1 undoes the multiplication by −1.

Divide y+x2 −6 by −1.

The total amount due at maturity is $23,495.73.Given:Principal amount (P) = $24,000 Rate of interest (R) = 2.75% Time (n) = 4 years First partial payment (A) = $4,210 Time after first partial payment (t) = 4/12 years = 1/3 year Second partial payment (B) = $3,240 Time after second partial payment (t) = 6/12 years = 1/2 year.

We need to find the amount due at maturity.Amount due at maturity can be calculated by the formula given below;A = P [ i ( 1 + i )n ] / [ ( 1 + i )n – 1 ] Where,A = amount due at maturity P = principal amount R = rate of interest in decimal n = time in yearsi = rate of interest per period For yearly interest, i = R / 100.For monthly interest, i = R / (12 × 100)For quarterly interest, i = R / (4 × 100)For half-yearly interest, i = R / (2 × 100)

Now, we will find the value of i first, which can be calculated by dividing the yearly interest rate by 100. Here, the interest is compounded half-yearly.i = R / (2 × 100)i = 2.75% / (2 × 100)i = 0.01375

Let's substitute the values of P, R, n, i, A in the formula and calculate the amount due at maturity.P = $24,000R = 2.75%n = 4 yearsi = 0.01375A = $4,210t = 1/3 yearsA = P [ i ( 1 + i )n ] / [ ( 1 + i )n – 1 ]4,210 = 24,000 [ 0.01375 ( 1 + 0.01375 )16 ] / [ ( 1 + 0.01375 )16 – 1 ]On solving the above equation, we get;Amount of loan due after 4 months is $23,188.45.

Now, we will calculate the second amount due at maturity after the second partial payment.B = $3,240t = 1/2 year.Let's find the balance due at the end of 6 months using the following formula;B = C ( 1 + i )n

Where,B = balance due at the end of 6 monthsC = amount due at the end of 4 monthsi = 0.01375n = (6 - 4) / 12 yearsB = C ( 1 + i )nB = $23,188.45 ( 1 + 0.01375 )1/2

On solving the above equation, we get;Amount due at maturity after the second partial payment is $22,201.98

Now, we will calculate the amount due at maturity.Amount due at maturity = balance due after second payment + interest for remaining periodAmount due at maturity = $22,201.98 + interest for 3.5 years.Let's calculate the interest for 3.5 years;Interest = P × i × nInterest = $24,000 × 0.01375 × 3.5 Interest = $1,293.75 Amount due at maturity = $22,201.98 + $1,293.75Amount due at maturity = $23,495.73.

Therefore, the total amount due at maturity is $23,495.73.

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Answer:

x=-pie/12

sinxcosx=-1/4

multiply both sides by 2

sin2x = 2sinxcosx we know

now equation will be

sin2x = -1/2

2x=-pie/6

x=-pie/12

Answer:

C

Step-by-step explanation:

 2

+2

-----

 4

To solve the simultaneous equation: 2x+2y+3z=210, 2x+3y+4z=270, and 3x+4y+3z=300, we can use the elimination method. Here's how:

Step 1: Multiply the first equation by 2, and the second equation by -1 to eliminate x.4x + 4y + 6z = 420-2x - 3y - 4z = -270

Step 2: Add the two equations to eliminate x.2y + 2z = 150

Step 3: Multiply the first equation by -3, and the third equation by 2 to eliminate x.-6x - 6y - 9z = -6306x + 8y + 6z = 600

Step 4: Add the two equations to eliminate x.2y - 3z = -30

Step 5: Multiply the second equation by 2, and the fourth equation by 3 to eliminate y.4x + 6y + 8z = 540-6y + 9z = 90

Step 6: Add the two equations to eliminate y.4x + 17z = 630

Step 7: Substitute z = 2 into equation 2y + 2z = 150 to find y.2y + 4 = 150y = 73

Step 8: Substitute y = 73 and z = 2 into equation 4x + 17z = 630 to find x.4x + 34 = 630x = 149Therefore, the solution to the simultaneous equation 2x+2y+3z=210, 2x+3y+4z=270, and 3x+4y+3z=300 is x = 149, y = 73, and z = 2.

Answer:

Step-by-step explanation:

You want integers q and r such that 26 = 50q +r, and 0 ≤ r < 50.

Solving for q, we have ...

  (26 -r)/50 = q

For r in the range 0–49, possible values of q are in the range ...

   (26 -0)/50 ≥ q > (26 -49)/50

   0.52 ≥ q > -0.46

The only integer in that range is ...

  q = 0

Then the value of r is ...

  26 = 50·0 +r

  r = 26

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To obtain the graph of y = f(-x+5)-4 from y = f(x), shift the graph 5 units to the right, reflect it across the y-axis, and shift it 4 units downward.

To obtain the graph of y = f(-x+5)-4 from the graph of y = f(x), follow these steps:

1. Locate the point (5, -4) on the dashed curve. This is the new vertex of the transformed function.

2. Observe the distance between the original vertex of the function and the x-axis. Let's call this distance "a".

3. Measure the horizontal distance between the new vertex (5, -4) and the original vertex of the function. Let's call this distance "b".

4. Shift the entire dashed curve "b" units to the right. This can be done by moving all the points on the graph horizontally "b" units to the right.

5. Reflect the shifted dashed curve about the y-axis. This can be done by changing the signs of the x-coordinates of all the points on the graph.

6. Finally, shift the reflected curve "a" units downward. This can be achieved by moving all the points on the graph vertically "a" units downward.

By following these steps, you will be able to obtain the graph of y = f(-x+5)-4 (solid curve) using the graph of y = f(x) (dashed curve).

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Answer:

A) Line ZM is tangent to circle P.

The volume of the region bounded by the paraboloid and the triangle is 96 cubic units.

To find the volume of the region bounded by the paraboloid and the triangle, we can set up a double integral in the xy-plane. The paraboloid is represented by the equation z = x^2 + y^2, which forms a circular surface that extends infinitely in the positive z-direction. The triangle is defined by the lines y = x, x = 0, and x + y = 6 in the xy-plane.

To set up the integral, we need to determine the limits of integration for x and y. From the equations of the triangle, we can see that x ranges from 0 to 6, and y ranges from x to 6 - x. This means that for each value of x, y will vary within the corresponding range.

The volume can be calculated by integrating the function z = x^2 + y^2 over the given region. This gives us the double integral:

V = ∫∫[x^2 + y^2] dA,

where dA represents the differential area element in the xy-plane.

Integrating over the limits of integration for x and y, the volume can be expressed as:

V = ∫[0 to 6] ∫[x to 6 - x] (x^2 + y^2) dy dx.

To evaluate this double integral, we need to perform the integration step by step. First, we integrate with respect to y, treating x as a constant:

V = ∫[0 to 6] [xy + (y^3)/3] evaluated from y=x to y=6-x dx.

Simplifying the expression inside the square brackets, we have:

V = ∫[0 to 6] [x(6-x) + ((6-x)^3)/3 - x(x) - (x^3)/3] dx.

Combining like terms, we get:

V = ∫[0 to 6] [(6x - x^2) + (216 - 36x + 3x^2 - x^3)/3 - x^2 - (x^3)/3] dx.

Simplifying further, we have:

V = ∫[0 to 6] [(216 - 36x + 3x^2 - x^3)/3] dx.

Now, we integrate with respect to x:

V = [(72x - 18x^2 + x^3/3) / 3] evaluated from x=0 to x=6.

Substituting the limits of integration, we get:

V = [(72(6) - 18(6^2) + (6^3)/3) / 3] - [(72(0) - 18(0^2) + (0^3)/3) / 3].

Simplifying the expression, we find:

V = [(432 - 216 + 72) / 3] - [0 / 3].

V = 288 / 3.

V = 96.

Therefore, the volume of the region bounded by the paraboloid and the triangle is 96 cubic units.

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The solutions to the equation tan²x - 1 = 0 are x = π/4 and x = 3π/4

From the question, we have the following parameters that can be used in our computation:

tan²x - 1 = 0

Add 1 to both sides of the equation

So, we have

tan²x = 1

Take the square root of both sides

tan(x) = ±1

Take the arc tan of both sidesof tan(x) = ±1

So, we have

x = π/4 and x = 3π/4

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Answer:

  3902.2 ft

Step-by-step explanation:

You want the length of cable required to span the distance from the top of a mountain 3400 ft above the plain from a location 940 ft from the base of the mountain, which rises at an angle of 74°.

The edge of the base of the mountain will be at a horizontal distance from the point below the peak given by ...

  Tan = Opposite/Adjacent

  Adjacent = Opposite/Tan

  width to center = (3400 ft)/tan(74°) ≈ 974.93 . . . . feet

The cable is the hypotenuse of a right triangle with one leg 3400 ft and the other (974.93 +940) = 1941.93 ft. The length of that is ...

  c = √(3400² +1914.93²) ≈ 3902.2 . . . . feet

The shortest length of cable needed is about 3902.2 feet.

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Answer:

C) More than 1 solution

Step-by-step explanation:

[tex]3y-12x=18\\2y-8x=12\\\\3(y-4x)=18\\2(y-4x)=12\\\\y-4x=6\\y-4x=6\\\\6=6[/tex]

Therefore, since both sides will always be equal to each other, then there are infinitely many solutions (so C is the best choice)

Answer:

5 is the tens, 6 is the hundred

Answer:

Step-by-step explanation:

10s - 9

100ths - 6

To find the savings plan balance after 12 months with an APR of 3% and monthly payments of $200, you can use the formula for the future value of an annuity. So the savings plan balance after 12 months with an APR of 3% and monthly payments of $200 is $2,492.80.

The formula for the future value of an annuity: FV = PMT * [(1 + r/n)^(n*t) - 1] / (r/n), where: FV is the future value of the annuity, PMT is the periodic payment, r is the annual interest rate (as a decimal), n is the number of times the interest is compounded per year, and t is the number of years.

Using this formula, we have r = 3% = 0.03n = 12 (monthly payments)t = 12/12 = 1 year PMT

= $200FV

= 200 * [(1 + 0.03/12)^(12*1) - 1] / (0.03/12)FV

= 200 * [(1.0025)^12 - 1] / (0.0025)FV

= 200 * 0.03115 / 0.0025FV = $2,492.80

Therefore, the savings plan balance after 12 months with an APR of 3% and monthly payments of $200 is $2,492.80.

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The sum of the fractions 23/27 and 19/26, in its simplest form, is 1111/702.

To add the fractions 23/27 and 19/26 and simplify the result, you need to find a common denominator for both fractions. The common denominator is the smallest number that both 27 and 26 can evenly divide into. In this case, the common denominator is 702 since both 27 and 26 can divide evenly into it.

Now, let's convert the fractions to have a denominator of 702:

23/27 = (23 * 26)/(27 * 26) = 598/702

19/26 = (19 * 27)/(26 * 27) = 513/702

Now, we can add the fractions:

598/702 + 513/702 = (598 + 513)/702 = 1111/702

To simplify this fraction, we can find the greatest common divisor (GCD) of the numerator and denominator, and then divide both by the GCD:

GCD(1111, 702) = 1

Dividing both the numerator and denominator by 1, we get:

1111/702 = 1111/702

Therefore, the sum of the fractions 23/27 and 19/26, in its simplest form, is 1111/702.

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Answer:

180 houses

Step-by-step explanation:

For every 10 flats, there are 30 bungalows. So, if there are 30 bungalows then there will be 100 flats in the village.

For every 5 flats there are in the village, there are 9 houses. There are 100 flats in the village. So, we can divide 100 by 5.

[tex]\frac{100}{5}[/tex]=20

20(9)=180

Therefore, there are 180 houses in the village.

Good luck on your homework!

Answer:

A = 2x - 37

Step-by-step explanation:

A

= 11 + 2(x - 6) + 4(-3 - 6)

= 11 + 2x - 12 - 12 - 24

= 2x - 37

a. The value of L that maximizes output is approximately L ≈ 99.19.

b. The value of L that maximizes marginal product is approximately L ≈ 124.19.

c. The value of L that maximizes average product is approximately L ≈ 100.17.

To find the value of L that maximizes output (Q) in the short run production function Q = 61² - 0.41³, we need to find the value of L that yields the highest possible output.

a. To maximize output, we take the derivative of the production function with respect to L and set it equal to zero:

dQ/dL = 2(61)L - 3(0.41²)L² = 0

Simplifying the equation, we have:

122L - 1.23L² = 0

Factoring out L, we get:

L(122 - 1.23L) = 0

Setting each factor equal to zero, we have:

L = 0 (one possible solution)

122 - 1.23L = 0

Solving the second equation, we find:

L ≈ 99.19

Therefore, the value of L that maximizes output is approximately L ≈ 99.19.

b. To find the value of L that maximizes marginal product (MP), we take the derivative of the production function with respect to L:

dMP/dL = 2(61) - 6(0.41²)L

Setting this derivative equal to zero, we have:

2(61) - 6(0.41²)L = 0

Simplifying the equation, we find:

122 - 0.984L = 0

Solving for L, we have:

L ≈ 124.19

Therefore, the value of L that maximizes marginal product is approximately L ≈ 124.19.

c. To find the value of L that maximizes average product (AP), we use the formula:

AP = Q/L

Taking the derivative of AP with respect to L, we have:

dAP/dL = (dQ/dL)/L - (Q/L²)

Setting this derivative equal to zero, we find:

[(2(61)L - 3(0.41²)L²)/L] - [(61² - 0.41³)/L²] = 0

Simplifying the equation, we have:

2(61) - 3(0.41²)L = (61² - 0.41³)/L

Rearranging the equation, we get:

L³ = (61² - 0.41³)/(2(61) - 3(0.41²))

Solving for L, we find:

L ≈ 100.17

Therefore, the value of L that maximizes average product is approximately L ≈ 100.17.

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There are approximately 43.36 days on hand in inventory.

To calculate the number of days on hand in inventory, we need to divide the number of staplers in stock by the average number of staplers sold per day.

First, let's calculate the average number of staplers sold per day:

Average staplers sold per year = 1624

Number of days per year = 350

Average staplers sold per day = Average staplers sold per year / Number of days per year

= 1624 / 350

≈ 4.64 (rounded to two decimal places)

Now, we can determine the number of days on hand in inventory:

Number of staplers in stock = 201

Number of days on hand in inventory = Number of staplers in stock / Average staplers sold per day

= 201 / 4.64

≈ 43.36 (rounded to two decimal places)

Therefore, there are approximately 43.36 days on hand in inventory.

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The vertex of the graph is a maximum at (-2, 4)

From the question, we have the following parameters that can be used in our computation:

The graph

The graph is a quadratic function

From the graph, we can see that the graph has a maximum value

This maximum value represents the vertex of the graph

And it is located at (-2, 4)

So, we have

Maximum = (-2, 4)

Hence, the maximum value of the function is (-2, 4)

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Answer:

x = 34.5

Step-by-step explanation:

According to the Vertical Angles Theorem, when two straight lines intersect, the opposite vertical angles are congruent.

Therefore, the vertical angle opposite the angle labelled 40° is also 40°.

Assuming lines m and n are parallel, we can apply the Same-side Interior Angles Theorem to find the value of x.

According to the Same-side Interior Angles Theorem, when two parallel lines are intersected by a transversal, the angles that are interior to the parallel lines and on the same side of the transversal line sum to 180°.

Therefore, the angle labelled (4x + 2)° and the angle vertically opposite to the one labelled 40° sum to 180°:

[tex](4x + 2)^{\circ} + 40^{\circ} = 180^{\circ}[/tex]

Solve for x:

[tex]4x + 2 + 40 = 180[/tex]

[tex]4x + 42 = 180[/tex]

[tex]4x + 42-42 = 180-42[/tex]

[tex]4x =138[/tex]

[tex]\dfrac{4x}{4}=\dfrac{138}{4}[/tex]

[tex]x=34.5[/tex]

Therefore, the value of x is 34.5.