If pmf of a random variable is given by 4 f(X=n)= n(n+1)(n+2)
the answer to part (a) is:
Ë F(X = n) = 9n(n+1)
What is probability?
Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to happen.
a. To show that the cumulative distribution function (CDF) F(X) satisfies Ë F(X = n)=1, we need to show that the sum of the probabilities of all possible values of X is equal to 1.
The probability mass function (PMF) is given by:
f(X=n) = 4n(n+1)(n+2)
The CDF is defined as:
F(X=n) = P(X ≤ n)
We can calculate F(X=n) by summing up the probabilities of all values less than or equal to n:
F(X=n) = Σ f(X=i), for i = 0 to n
Substituting the given PMF:
F(X=n) = Σ 4i(i+1)(i+2), for i = 0 to n
Expanding the sum:
F(X=n) = 4(0)(1)(2) + 4(1)(2)(3) + 4(2)(3)(4) + ... + 4n(n+1)(n+2)
F(X=n) = 4 [ (0)(1)(2) + (1)(2)(3) + (2)(3)(4) + ... + (n)(n+1)(n+2) ]
Notice that the sum inside the brackets is a telescoping sum, which can be simplified as:
[(k-1)k(k+1) - (k-2)(k-1)k] = 3k(k-1)
Thus,
F(X=n) = 4 [ 3(0)(-1) + 3(1)(0) + 3(2)(1) + ... + 3(n)(n-1) ]
F(X=n) = 4 [ 3(0 + 1 + 2 + ... + (n-1)) ]
F(X=n) = 4 [ 3(n-1)n/2 ]
F(X=n) = 6n² - 6n
Therefore, Ë F(X = n) is given by:
Ë F(X = n) = Σ F(X=n) * P(X=n), for all n
Substituting the given PMF:
Ë F(X = n) = Σ [ 6n² - 6n ] * 4n(n+1)(n+2), for all n
Expanding the sum and simplifying:
Ë F(X = n) = 24 [ (n+2)(n+1)n(n-1)/4 - (n+1)n(n-1)(n-2)/4 ]
Ë F(X = n) = 24 [ (n-1)n(n+1)(n+2)/4 - (n-2)(n-1)n(n+1)/4 ]
Ë F(X = n) = 24 [ (n-1)n(n+1)(n+2) - (n-2)(n-1)n(n+1) ] / 4
Ë F(X = n) = 6n(n+1)(n+2) - 6n(n+1)(n-1) / 4
Ë F(X = n) = 6n(n+1)[ (n+2) - (n-1) ] / 4
Ë F(X = n) = 6n(n+1) * 3 / 4
Ë F(X = n) = 9n(n+1)/2
Substituting n = 0 and n = ∞ to get the bounds of the sum, we get:
E[X] = 2(0)(5(0)+8) / 3 + 2(∞)(∞+1)(5(∞)+8) / 3
Since the second term diverges to infinity, we can conclude that the expected value of X does not exist (i.e., it is undefined).
Therefore, the answer to part (a) is:
Ë F(X = n) = 9n(n+1)/
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If pmf of a random variable is given by 4 f(X=n)= n(n+1)(n+2)
the answer to part (a) is:
Ë F(X = n) = 9n(n+1)
What is probability?Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to happen.
a. To show that the cumulative distribution function (CDF) F(X) satisfies Ë F(X = n)=1, we need to show that the sum of the probabilities of all possible values of X is equal to 1.
The probability mass function (PMF) is given by:
f(X=n) = 4n(n+1)(n+2)
The CDF is defined as:
F(X=n) = P(X ≤ n)
We can calculate F(X=n) by summing up the probabilities of all values less than or equal to n:
F(X=n) = Σ f(X=i), for i = 0 to n
Substituting the given PMF:
F(X=n) = Σ 4i(i+1)(i+2), for i = 0 to n
Expanding the sum:
F(X=n) = 4(0)(1)(2) + 4(1)(2)(3) + 4(2)(3)(4) + ... + 4n(n+1)(n+2)
F(X=n) = 4 [ (0)(1)(2) + (1)(2)(3) + (2)(3)(4) + ... + (n)(n+1)(n+2) ]
Notice that the sum inside the brackets is a telescoping sum, which can be simplified as:
[(k-1)k(k+1) - (k-2)(k-1)k] = 3k(k-1)
Thus,
F(X=n) = 4 [ 3(0)(-1) + 3(1)(0) + 3(2)(1) + ... + 3(n)(n-1) ]
F(X=n) = 4 [ 3(0 + 1 + 2 + ... + (n-1)) ]
F(X=n) = 4 [ 3(n-1)n/2 ]
F(X=n) = 6n² - 6n
Therefore, Ë F(X = n) is given by:
Ë F(X = n) = Σ F(X=n) * P(X=n), for all n
Substituting the given PMF:
Ë F(X = n) = Σ [ 6n² - 6n ] * 4n(n+1)(n+2), for all n
Expanding the sum and simplifying:
Ë F(X = n) = 24 [ (n+2)(n+1)n(n-1)/4 - (n+1)n(n-1)(n-2)/4 ]
Ë F(X = n) = 24 [ (n-1)n(n+1)(n+2)/4 - (n-2)(n-1)n(n+1)/4 ]
Ë F(X = n) = 24 [ (n-1)n(n+1)(n+2) - (n-2)(n-1)n(n+1) ] / 4
Ë F(X = n) = 6n(n+1)(n+2) - 6n(n+1)(n-1) / 4
Ë F(X = n) = 6n(n+1)[ (n+2) - (n-1) ] / 4
Ë F(X = n) = 6n(n+1) * 3 / 4
Ë F(X = n) = 9n(n+1)/2
Substituting n = 0 and n = ∞ to get the bounds of the sum, we get:
E[X] = 2(0)(5(0)+8) / 3 + 2(∞)(∞+1)(5(∞)+8) / 3
Since the second term diverges to infinity, we can conclude that the expected value of X does not exist (i.e., it is undefined).
Therefore, the answer to part (a) is:
Ë F(X = n) = 9n(n+1)/
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Figure these out ……….
Answer:
o
Step-by-step explanation:
j^2+6j-40. factor helpppp
The expression is factorized to give j = -10 and j = 4
How to factor the expressionFrom the information given, we have the quadratic equation as;
j²+ 6j - 40
Using the factorization method, we have to mulitply the coefficient of j² by the constant.
After this, find the pair factors of the product that adds up to give 6
Substitute the values
Then, we have;
j² + 10j - 4j - 40
group the expression in pairs
(j² + 10j) - (4j- 40)
factor the common terms
j(j + 10) - 4(j + 10)
We have;
(j + 10) (j - 4)
j + 10 = 0
collect the terms
j = -10
j = 4
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A recent study found that the weight of a certain species of fish living in the Bahamas can be modeled by the function 0. 034213, where w is measured in grams and L, the length of the fish is measured in centimeters. Calculate the approximate length of a fish that weighs 250 grams. Round your answer to the nearest tenth of a centimeter.
L=____ centimeters
To solve this problem, we need to use the given function to find the length of a fish that weighs 250 grams. We can do this by setting the weight of the fish (w) to 250 grams and solving for the length of the fish (L):
w = 0.034213 L
250 = 0.034213 L
L = 250 / 0.034213
L ≈ 7304.4
Rounding to the nearest tenth of a centimeter, the approximate length of the fish is:
L ≈ 730.4 centimeters
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Help please. How many roots and what are they?
The function f(x) = 3x³ - 2x² - 2x + 3 has one root and the root is x = 1
How many roots and what are the roots?From the question, we have the following parameters that can be used in our computation:
f(x) = 3x³ - 2x² - 2x + 3
Next, we plot the graph of the function f(x)
See attachment
From the graph, we can see that the graph intersects with the x-axis once at x = -1
This means that it has one root and the root is x = 1
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What is the product of 1. 0 * 10^3 and 2. 0 x 10^5 expressed in scientific notation. HEEEELLLLPPPPP PLEASEEEEEEEE
The product of the exponents is given by A = 2.0 x 10⁸
Given data ,
Let the first number be p = 1 x 10³
Let the second number be q = 2 x 10⁵
From the laws of exponents , we get
mᵃ×mᵇ = mᵃ⁺ᵇ
A = p x q
On simplifying , we get
A = 1 x 10³ x 2 x 10⁵
A = 2 x 10³⁺⁵
A = 2.0 x 10⁸
Hence , the equation is A = 2.0 x 10⁸
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Partition each whole number interval into fourths. Label 7/4 and 9/4
We can see that 7/4 is located between 3/4 and 1 on the first interval, and 9/4 is located between 2 and 5/2 on the second interval.
To partition each whole number interval into fourths, divide each interval by 4. Label 7/4 between 3/4 and 1 and label 9/4 between 2 and 5/2 on an extended scale from 0 to 3.
To partition each whole number interval into fourths, we can divide each interval by 4. For example, the interval from 0 to 1 can be divided into fourths as follows:
0 -------- 1/4 -------- 1/2 -------- 3/4 -------- 1
Now, to label 7/4 and 9/4 on this scale, we can extend it by adding another interval from 1 to 2 and dividing it into fourths as well. This would give us the following scale:
0 -------- 1/4 -------- 1/2 -------- 3/4 -------- 1 -------- 5/4 -------- 3/2 -------- 7/4 -------- 2 -------- 9/4 -------- 5/2 -------- 11/4 -------- 3
So we can see that 7/4 is located between 3/4 and 1 on the first interval, and 9/4 is located between 2 and 5/2 on the second interval.
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Let d be the relation defined on z as follows: for every m, n ∈ z, m d n ⇔ 3 | (m2 − n2). (a) prove that d is an equivalence relation
Since d satisfies all three properties of an equivalence relation, we conclude that d is indeed an equivalence relation on Z.
To prove that d is an equivalence relation on Z, we need to show that it satisfies three properties: reflexivity, symmetry, and transitivity.
Reflexivity: For any m ∈ Z, we have [tex]m^2 - m^2[/tex] = 0, which is divisible by 3. Therefore, m is related to itself under d, so d is reflexive.
Symmetry: If m d n, then [tex]3 | (m^2 - n^2)[/tex]). This means that there exists an integer k such that [tex]m^2 - n^2 = 3k.[/tex]
Rearranging this equation, we get n^2 - m^2 = -3k, which implies that 3 divides (n^2 - m^2) as well. Therefore, n d m, and d is symmetric.
Transitivity: Suppose m d n and n d p. Then, we have [tex]3 | (m^2 - n^2)[/tex] and [tex]3 | (n^2 - p^2)[/tex].
Adding these two equations, we get [tex]3 | ((m^2 - n^2) + (n^2 - p^2)),[/tex], which simplifies to [tex]3 | (m^2 - p^2).[/tex] Therefore, m d p, and d is transitive.
Since d satisfies all three properties of an equivalence relation, we conclude that d is indeed an equivalence relation on Z.
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Use the following notations: r = radius of a circle, v = linear velocity, w = angular velocity. Find the missing quantity. Round to the nearest tenth if necessary. V= 1235 m/min, r = 65 m, w = ?
The angular velocity of the circle is approximately 19 m/s.
In order to find the missing quantity, we can use the relationship between linear velocity and angular velocity in a circle. The linear velocity of a point on the edge of a circle is the product of the radius and the angular velocity. This can be expressed as:
v = r * w
where v is the linear velocity, r is the radius, and w is the angular velocity.
To find the value of w, we can rearrange this equation to solve for w:
w = v / r
Substituting the given values of v and r, we get:
w = 1235 m/min / 65 m
w = 19 m/s
It's important to note that units must be consistent when using formulas to solve problems. In this case, we converted the given linear velocity from m/min to m/s before plugging it into the formula. Also, we rounded the answer to the nearest tenth, as instructed, since the given values were rounded to the nearest unit.
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solve for length of segment D a=4 cm b=12 cm c=6 cm 4 • ? = ? • D
The length of segment d is 8 when the value segment a is 4 cm, b is 12 cm , c is 6 cm
If two segments intersect inside or outside the circle then ab=cd
Given values of a is 4 cm, b is 12 cm , c is 6 cm and d is x
ab=cd
Plug in the values of a, b , c and d
4×12=6×d
48=6d
Divide both sides by 6
8=d
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When the population standard deviation is known, the confidence interval for the population mean is based on the:Chi-square statistict-statisticz-statisticF-statistic
When the population standard deviation is known, the confidence interval for the population mean is based on the z-statistic.
When the population standard deviation is known, the confidence interval for the population mean is based on the z-statistic.
The formula for the confidence interval for the population mean when the population standard deviation is known is given by:
CI = X ± z(α/2) * σ/√n
Where:
X is the sample mean
σ is the population standard deviation
n is the sample size
z(α/2) is the z-score corresponding to the desired level of confidence (e.g. for a 95% confidence interval, α = 0.05 and z(α/2) = 1.96)
The z-statistic is used in this formula to determine the width of the confidence interval. It is based on the standard normal distribution and represents the number of standard deviations the sample mean is from the population mean. The z-score is calculated using the formula:
z = (X - μ) / (σ/√n)
Where μ is the population mean.
The z-score is used to find the critical values for the confidence interval, which are obtained by multiplying it by the standard error of the mean (σ/√n). These critical values define the endpoints of the confidence interval.
In summary, when the population standard deviation is known, the confidence interval for the population mean is based on the z-statistic, which is used to calculate the critical values for the confidence interval.
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2 - 3(x + 4) = 3(3 - x)
The equation 2 - 3(x + 4) = 3(3 - x) has no solution for x
Calculating the eqautionFrom the question, we have the following parameters that can be used in our computation:
2 - 3(x + 4) = 3(3 - x)
Open the brackets
So, we have
2 - 3x - 12 = 9 - 3x
Evaluate the like terms
So, we have
-10 = 9
The above equation is false
Hence, the equation has no solution
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interior and exterior triangles
Answer:
∠ PQR = 18°
Step-by-step explanation:
the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ PQR is an exterior angle of the triangle , then
∠ PQR = ∠OPQ + ∠ QOP , that is
4x - 10 = x + 9 + x - 5
4x - 10 = 2x + 4 ( subtract 2x from both sides )
2x - 10 = 4 ( add 10 to both sides )
2x = 14 ( divide both sides by 2 )
x = 7
Then
∠ PQR = 4x - 10 = 4(7) - 10 = 28 - 10 = 18°
can quite get it can someone help me?!!
The area of the shaded portion of the given shape is: 114 yd²
What is the area of the shaded region?The formula for the area of a rectangle is expressed as:
A = L * W
Where:
L is Length
W is Width
Now, to find the area of the shaded part, we will find the area of the bigger rectangle and subtract the area of the unshaded rectangle from it.
Thus:
Area of shaded part = (20 * 12) - (14 * 9)
Area of shaded part = 240 - 126
Area of shaded part = 114 yd²
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If a cell group is formatted with multiple conditional formats, the rules are applied _______.
a. based on the hierarchy of the rule type
b. in the order in which they are created
c. based on which rule best applies to the first cell in the range
d. in alphanumeric order by the name of the rule
If a cell group is formatted with multiple conditional formats, the rules are applied in the order in which they are created.
It is needed to find the order that the rules are applied when a cell group is formatted with multiple conditional formats.
For a cell group, when multiple conditional formats are used, then the last rule that is added is the one that will be done first
However, this can be changed by clicking on the conditional formatting and then manage rules.
So the order of the rules will be of the order that the rules are created.
Hence the correct option is b.
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A sample of 33 blue-collar employees at a production plant was taken. Each employee was asked to assess his or her own job satisfaction (x) on a scale of 1 to 10. In addition, the numbers of days absent (y) from work during the last year were found for these employees. The sample regression line Y; = = 10.7 – – 0.2 x; was estimated by least squares for these data. Also found were T=Σ x = 7.0 Σ(x, -x = 50.0 SSE= 70.0 a. Test, at the 5% significance level against the appropriate one-sided alternative, the null hypothesis that job satisfaction has no linear effect on absenteeism. b. A particular employee has job satisfaction level 8. Find a 99% prediction interval for the number of days this employee would be absent from work in a year. 33 2 -X)=
Answer:
Step-by-step explanation :
I suggest you ask an expert
Quadratic function f has a vertex (4, 15) and passes through the point (1, 20). Which equation represents f ?
f(x)=−5/9(x−4)^2+15
f(x)=5/9(x−4)^2+15
f(x)=−35/9(x−4)^2−15
f(x)=35/9(x−4)^2−15
A car drives 10.5 miles in 1/6 hour. What is its average speed, in miles per hour?
Answer:
63 mph
Step-by-step explanation:
10.5 × 6 is 63
you multiply by the fraction of the hour so you can get how fast the car is going in miles per an hour
Answer:
The average speed of the car = 63miles per hour
Step-by-step explanation:
Given, the total distance traveled by the car= 10.5 miles
total time is taken by the car to cover 10.5 miles = 1/6 hour
formula to calculate average speed
average speed = total distance/total time
average speed = 10.5/(1/6)
= 10.5×6
= 63 miles per hour
therefore, the average speed of the car is 63 miles per hour
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about 1 in 1,100 people have IQs over 150. If a subject receives a score of greater than some specified amount, they are considered by the psychologist to have an IQ over 150. But the psychologist's test is not perfect. Although all individuals with IQ over 150 will definitely receive such a score, individuals with IQs less than 150 can also receive such scores about 0.08% of the time due to lucky guessing. Given that a subject in the study is labeled as having an IQ over 150, what is the probability that they actually have an IQ below 150? Round your answer to five decimal places.
The probability that the subject actually has an IQ below 150 given that they are labeled as having an IQ over 150 is approximately 0.00073276, or 0.07328% when rounded to five decimal places.
Let's use Bayes' theorem to solve the problem. Let A be the event that the subject has an IQ over 150, and B be the event that the subject actually has an IQ below 150. We want to find P(B|A), the probability that the subject has an IQ below 150 given that they are labeled as having an IQ over 150.
From the problem, we know that P(A) = 1/1100, the probability that a random person has an IQ over 150. We also know that P(A|B') = 0.0008, the probability that someone with an IQ below 150 is labeled as having an IQ over 150 due to lucky guessing.
To find P(B|A), we need to find P(A|B), the probability that someone with an IQ below 150 is labeled as having an IQ over 150. We can use Bayes' theorem to find this probability:
P(A|B) = P(B|A) * P(A) / P(B)
We know that P(B) = 1 - P(B'), the probability that someone with an IQ below 150 is not labeled as having an IQ over 150. Since everyone with an IQ over 150 is labeled as such, we have:
P(B) = 1 - P(A')
where P(A') is the probability that a random person has an IQ below 150 or, equivalently, 1 - P(A).
Plugging in the given values, we have:
P(A|B) = P(B|A) * P(A) / (1 - P(A))
P(A|B) = P(B|A) * 1/1100 / (1 - 1/1100)
P(A|B) = 0.0008 * 1/1100 / (1 - 1/1100)
P(A|B) ≈ 0.00073276
Therefore, the probability that the subject actually has an IQ below 150 given that they are labeled as having an IQ over 150 is approximately 0.00073276, or 0.07328% when rounded to five decimal places.
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Solve the following equation using the zero product property. Enter one solution per box. No brackets {} are needed.
The solution is, the solutions using the Zero Product Property: is x =8 and -5.
The expression to be solved is:
(x-8) (x + 5) = 0
we know that,
The zero product property states that the solution to this equation is the values of each term equals to 0.
now, we have,
(x-8) (x + 5) = 0
i.e. we get,
(x-8) × (x + 5) = 0
so, using the Zero Product Property:
we get,
(x-8) = 0
or,
(x + 5) = 0
so, we have,
x = 8 or, x = -5
The answers are 8 and -5.
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Alex painted 178 ft2 of his apartment’s walls with 13 1 3 gallon of paint. He has 2 gallons of paint in all. If he wants to cover 1,000 ft2 of his apartment, does he have enough paint? Complete a true statement
From multiplcation operation, Alex has enough paint to cover 1,000 ft² of his apartment. The true statement is 2 gallons of paint will cover 1068 ft², Alex have enough paint of quantity 2 gallons.
We have Mr. Alex painted his apartment. Area of his apartment'walls = 178 ft²
Quantity of paint used by him to paint his apartment'walls with area 178 ft² =[tex] \frac{1}{3} \: \: gallons[/tex]
Total quantity of paint used in all
= 2 gallons
We have to check the provide paint is enough or not to cover 1,000 ft² of his apartment. Let the required paint for 1000 ft² be x gallons. Using multiplcation, 1/3 gallons quantity of paint will cover the area of apartment = 178 ft², so, 1 gallons quantity of paint will cover the area of apartment = 178 ×3 ft²= 534 ft²
Now, 2 gallons quantity of paint will cover the area of apartment = 2× 534 ft² = 1068 ft²> 1000 ft²
But he wants to paint 1000 ft² of his apartment in 2 gallons quantity (x=1.9 gal ). So, he has enough paint to paint his apartment.
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Complete question:
The above figure complete the question.
Alex painted 178 ft2 of his apartment’s walls with 1/3 gallon of paint. He has 2 gallons of paint in all. If he wants to cover 1,000 ft2 of his apartment, does he have enough paint? Complete a true statement
Refer to the Background Information and Passage to answer the following questions. Be sure to answer the questions completely, and focus on the argument being made by the intern working with MARTA. Background Information: In an article in The Signal, April 11, 2017, author Wesley Dunkirk writes that Atlanta residents voted to approve a sales tax referendum which would raise $3.5 billion over the next 35 years to support efforts in expanding the Metro Atlanta Rapid Transit Authority (MARTA) throughout the Metro Atlanta area. For Atlanta to continue its expansion as one of the largest economies in the southeast, having an expansive and reliable form of public transit is necessary. Passage: While there are many complicated areas of MARTA that could use the additional money, the conflict so far has seemed to center on whether the money should be spent on either the rail or bus services. The MARTA bus system helps transport thousands of people every day. It is easy to access and can take commuters to places throughout Atlanta that the rail line cannot access. One Georgia State student (who interned in MARTA's long range planning department) spoke to The Signal. The student intern said that MARTA buses help connect areas that could be difficult to access for those without a vehicle. The many benefits offered by MARTA's bus service make it easy to create an argument that expanding the bus system is the best option for those making the decisions on what the sales tax referendum money should go towards. Either MARTA will use the tax referendum to expand the rail system or bus system. The intern argues that due to the benefits of expanding the bus system, MARTA should consequently not expand rail system.
Part A
Identify the argument presented in the passage. First, locate the conclusion and then the premises. Next, standardize the argument using numbered premises. Make sure to use ( ) around the number of a stated premise or conclusion, and [ ] around the number of an unstated premise or conclusion.
Part B
What kind of statements are the premises (e.g., is it empirical, definitional, or a statement made by an expert, etcetera) and why? If there is more than one premise in the argument, be sure to say something about each premise.
Part C
Should you assume that each premise is uncontroversially true? Why or why not? If there is more than one premise in the argument, be sure to say something about each premise.
Part D
Are each of the premises an accurate description of the world and why? If there is more than one premise in the argument, be sure to say something about each premise.
Part E
Does the argument pass the true premise test? Why or why not?
Part F
Is the argument deductive or inductive? Why? Part G What is the form of this argument (e.g., denying a disjunct, statistical argument, analogical argument, etc.)? Why?
Part H
Are the premises relevant to the conclusion? Why or why not? Part I Does the argument contain any fallacies (Hasty Generalization, Biased Sample, etcetera)? If so, which one(s)?
Part J
Does the argument pass the proper form test? Why or why not? Be sure to use terms that we've used in the course (e.g., "strong" or "weak," "valid" or "invalid").
Part K
Considering how the argument performed on both the true premises test and the proper form test, how good is the argument? Why? Be sure to use terms that we've used in the course (e.g., "cogent" or "not cogent," "sound" or "unsound").
Part A:
Conclusion: MARTA should not expand the rail system.
Premise 1: MARTA buses help connect areas that could be difficult to access for those without a vehicle.
Premise 2: The many benefits offered by MARTA's bus service make it easy to create an argument that expanding the bus system is the best option for those making the decisions on what the sales tax referendum money should go towards.
Standardized Argument:
(1) MARTA buses help connect areas that could be difficult to access for those without a vehicle.
(2) The many benefits offered by MARTA's bus service make it easy to create an argument that expanding the bus system is the best option for those making the decisions on what the sales tax referendum money should go towards.
Therefore, (3) MARTA should not expand the rail system.
Part B:
Premise 1 is an empirical statement because it describes the current situation with MARTA buses. Premise 2 is a statement that involves value judgments because it claims that expanding the bus system is the best option based on the benefits it offers.
Part C:
The truth of premise 1 is not controversial as it is an empirical statement. However, the truth of premise 2 may be controversial because it is based on value judgments and may be subject to different opinions.
Part D:
Premise 1 accurately describes the world because it is an empirical statement. Premise 2 accurately describes the potential benefits of expanding the bus system, but it may not accurately represent the views of those who think that expanding the rail system is a better option.
Part E:
The argument does not pass the true premise test because premise 2 may not be uncontroversially true.
Part F:
The argument is inductive because the premises provide reasons to support a probable conclusion rather than a necessary conclusion.
Part G:
The form of the argument is an argument from value because it is based on value judgments about the benefits of expanding the bus system.
Part H:
The premises are relevant to the conclusion because they provide reasons for why expanding the bus system is a better option than expanding the rail system.
Part I:
The argument does not contain any fallacies.
Part J:
The argument is weak because it does not pass the true premise test.
Part K:
The argument is not cogent because it is weak, meaning it is not both strong and has true premises. The argument is not strong because premise 2 is not uncontroversially true. Therefore, the argument is unsound.
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Rewrite the statements in if-then form.
Exercise
Catching the 8:05 bus is a sufficient condition for my being on time for work
The statement Catching the 8:05 bus is a sufficient condition for my being on time for work can be written as if a, then b, where, a is the case where I catch the 8:05 bus and b is the case where I reach the office on time.
Here we have been given that the sufficient condition for my being on time for work is catching the 8:05 bus.
Whenever we are denoting to cases say x and y, we say x being a sufficient condition for y by the notation
y ⇒ x
Here, let there be cases a and b
a is the case where I catch the 8:05 bus and
b is the case where I reach the office on time
Since a is a sufficient condition for b, we can write
a ⇒ b
In the If- then form, we say
If a, then b.
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uppose that Y, YS,. … Y n constitute a random sample from a population with probabil- ity density function 0, elsewhere. Suggest a suitable statistic to use as an unbiased estim ator for θ.
Therefore,
E(R) = E(max(Y1, Y2, ..., Yn)) - E(min(Y1, Y2, ..., Yn))
= θ + (b - θ)/n - θ - (a - θ)/n
= (b - a) / n
Hence, R is an unbiased estimator for θ with E(R) = (b - a) / n.
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Since the probability density function is 0 elsewhere, we can assume that the population follows a uniform distribution on some interval (a, b).
A suitable statistic to use as an unbiased estimator for θ would be the sample range R = max(Y1, Y2, ..., Yn) - min(Y1, Y2, ..., Yn).
To see why this is an unbiased estimator, we can calculate its expected value:
E(R) = E(max(Y1, Y2, ..., Yn) - min(Y1, Y2, ..., Yn))
= E(max(Y1, Y2, ..., Yn)) - E(min(Y1, Y2, ..., Yn))
Since each Yi has the same distribution, we have:
E(max(Y1, Y2, ..., Yn)) = E(Y1) = θ + (b - θ)/n
E(min(Y1, Y2, ..., Yn)) = E(Yn) = θ + (a - θ)/n
Therefore,
E(R) = E(max(Y1, Y2, ..., Yn)) - E(min(Y1, Y2, ..., Yn))
= θ + (b - θ)/n - θ - (a - θ)/n
= (b - a) / n
Hence, R is an unbiased estimator for θ with E(R) = (b - a) / n.
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Use the figure to find the Lateral Area.
15 un2
24 un2
12 un2
The lateral surface area of a cone is 15π units².
Option A is the correct answer.
We have,
The lateral area of a three-dimensional object is the total surface area of the object excluding the area of the bases.
So,
The given figure is a cone.
Now,
The lateral surface area of a cone = πrl
where r is the radius of the base of the cone, and l is the slant height of the cone.
The slant height is the distance from the apex of the cone to any point on the edge of the base.
Now,
Applying the Pythagorean,
l² = 4² + 3²
l² = 16 + 9
l² = 25
l = 5
So,
Substituting the values.
The lateral surface area of a cone
= πrl
= π x 3 x 5
= 15π units²
Thus,
The lateral surface area of a cone is 15π units².
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Which equation represents this graph
The exponential function that represents the graph is given as follow:
y = 2^(x - 1) + 2.
How to define an exponential function?An exponential function has the definition presented as follows:
y = ab^x.
In which the parameters are given as follows:
a is the value of y when x = 0.b is the rate of change.The function in this problem has a horizontal asymptote at y = 2, hence:
y = ab^x + 2.
When x increases by one, y is multiplied by two, hence the parameters a and b can given as follows:
a = 1, b = 2.
The function is translated one unit right, hence it is defined as follows:
y = 2^(x - 1) + 2.
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now suppose that the bag has 7 white balls and 3 red balls. you draw one ball without looking. please type a number between 0 and 100 for the percent chance that the ball you draw is white. %
The percent chance that the ball you draw is white is 70%.
To find the percent chance of drawing a white ball, we will calculate the probability and then convert it into a percentage.
1. First, determine the total number of balls in the bag: 7 white balls + 3 red balls = 10 balls.
2. Next, determine the number of favorable outcomes, which is the number of white balls: 7 white balls.
3. Calculate the probability by dividing the number of favorable outcomes by the total number of balls: 7 white balls ÷ 10 balls = 0.7.
4. Convert the probability to a percentage by multiplying it by 100: 0.7 x 100 = 70%.
So, the percent chance that the ball you draw is white is 70%.
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please help!!
Using the Golfer Data in the Quiz Conf. Intervals Hypoth. Testing Templates compute a 90% confidence interval for the population proportion of females. a. 18 to 29 .19 to 28 20 to 27 9 d. 16 to 31 C
The 90% confidence interval for the population proportion of females is (0.261, 0.375). Answer: d. 16 to 31.
To compute a 90% confidence interval for the population proportion of females using the Golfer Data, you can use the following formula:
CI = p ± z*√(P(1-P)/n)
where P is the sample proportion, z is the z-score associated with the desired confidence level (in this case, 1.645 for 90% confidence), and n is the sample size.
From the Golfer Data, we can see that there are 84 females out of a total of 264 golfers:
n = 264
P = 84/264 = 0.318
Plugging these values into the formula, we get:
CI = 0.318 ± 1.645*√(0.318(1-0.318)/264)
CI = 0.318 ± 0.057
CI = (0.261, 0.375)
Therefore, the 90% confidence interval for the population proportion of females is (0.261, 0.375). Answer: d. 16 to 31.
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Suppose you are using α = 0. 05 to test the claim that μ = 1620 using a P-value. You are given the sample statistics n-35, X_bar=1590 and σ=82. Find the P-value. State the answer only and no additional work. Make sure to use the tables from the book. Do not round the final answer
The P-value is 0.0107 for the sample statistics n-35 and the coefficient of standard deviation is 82.
α = 0. 05
μ = 1620
size (n)= 35
X_bar=1590
σ=82
From the given sample statistics, the test statistics will be calculated as:
t = (X_bar - μ) / (σ / sqrt(n))
t = (1590 - 1620) / (82 / sqrt(35))
t = (-2.5411)
Using the t-distribution table with 34 degrees of freedom, the critical value will be:
t_critical = -1.6909
Here the calculated test statistic is less than the critical value.
P - value = 2*P(-100< t < -1.9720, when df = 34)
P = tcf (-100,-2.4103,34)
P = 0.0107
Therefore we can conclude that the P-value is 0.0107.
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Simplify: 5m (5m^4 + 5m^2 -4)
Here is a list of ingredients for making 10 cookies. Ingredients To make 10 cookies 120 g of butter 75 g of sugar 180 g of plain flour 150 g of chocolate chips 2 eggs Pam wants to make 25 cookies. Work out how much butter she needs.
Amount of butter that Pam needs is 300 g.
Given ingredients to make 10 cookies.
Ingredients needed for 10 cookies is,
Butter : 120 g
Sugar : 75 g
Plain flour : 180 g
Chocolate chips : 150 g
Eggs : 2
The proportion of each ingredient will be same.
To make 25 cookies,
Amount needed = 25 / 10 = 2.5
Amount of butter needed = 2.5 × 120 = 300 g
Hence the amount of butter needed is 300 g.
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