need asap if you can pls!!!!!

Answer:The interior angle of a polygon is given by

The exterior angle of a polygon is given by

where n is the number of sides of the polygon

The statement

The interior of a regular polygon is 5 times the exterior angle is written as

Solve the equation

That's

Since the denominators are the same we can equate the numerators

That's

180n - 360 = 1800

180n = 1800 + 360

180n = 2160

Divide both sides by 180

n = 12

I).

The interior angle of the polygon is

The answer is

150°

II.

Interior angle + exterior angle = 180

From the question

Interior angle = 150°

So the exterior angle is

Exterior angle = 180 - 150

We have the answer as

30°

III.

The polygon has 12 sides

IV.

The name of the polygon is

Dodecagon

Step-by-step explanation:

The correct relationship between the angle measures of triangle ΔPQR is: H m∠Q < m∠P

In a triangle, the sum of the interior angles is always 180 degrees. Therefore, the relationship between the angle measures of ΔPQR can be determined based on their magnitudes.
Since angle Q is smaller than angle P, we can conclude that m∠Q < m∠P. This is because if angle Q were greater than angle P, the sum of angles Q and R would be greater than 180 degrees, which is not possible in a triangle.
On the other hand, we cannot determine the relationship between angle R and the other two angles based on the given answer choices. The options provided do not specify the relationship between angle R and the other angles.
Therefore, the correct relationship is that angle Q is smaller than angle P (m∠Q < m∠P), and we cannot determine the relationship between angle R and the other angles based on the given answer choices.

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Answer: CD

Step-by-step explanation:

Equivalent ratios are those that can be simplified or reduced to the same value. In other words, two ratios are considered equivalent if one can be expressed as a multiple of the other. Some examples of equivalent ratios are 1:2 and 4:8, 3:5 and 12:20, 9:4 and 18:8, etc.

To calculate the margin of error (M.E.) for a 95% two-sided confidence interval on the mean (μ) with a sample size of 26, we can use the formula:

M.E. = z * (σ / √n),

where z is the z-score corresponding to the desired confidence level, σ is the population standard deviation (unknown in this case), and n is the sample size. Since the population standard deviation (σ) is not given, we cannot calculate the exact margin of error. Therefore, none of the provided options (37.019, 9.592, 38.366, 31.555) can be determined as the correct answer without additional information. To calculate the margin of error, we would need either the population standard deviation or the sample standard deviation

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The solution to the given minimization problem subject to the constraint is x = y = z = 3, which minimizes the function f(x, y, z) = x² + y² + z² under the given constraints.

To solve the given problem using Lagrange multipliers, we first set up the Lagrangian function:

L(x, y, z, λ) = f(x, y, z) - λ(g(x, y, z))

Where f(x, y, z) = x² + y² + z² is the objective function and g(x, y, z) = x + y + z - 9 is the constraint function. λ is the Lagrange multiplier.

Next, we calculate the partial derivatives of L concerning x, y, z, and λ, and set them equal to zero:

∂L/∂x = 2x - λ = 0

∂L/∂y = 2y - λ = 0

∂L/∂z = 2z - λ = 0

∂L/∂λ = x + y + z - 9 = 0

From the first three equations, we can solve for x, y, and z in terms of λ:

x = λ/2

y = λ/2

z = λ/2

Substituting these values into the fourth equation, we have:

(λ/2) + (λ/2) + (λ/2) - 9 = 0

(3λ/2) - 9 = 0

3λ - 18 = 0

λ = 6

Using the obtained value of λ, we can find the corresponding values of x, y, and z:

x = 6/2 = 3

y = 6/2 = 3

z = 6/2 = 3

Therefore, the solution to the given minimization problem subject to the constraint is x = y = z = 3, which minimizes the function f(x, y, z) = x² + y² + z² under the given constraints.

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The unique solution of the given differential equation satisfying the initial conditions is [tex]`y(x) = -11 e^x - (16/3 e^{(-5x/8)} e^{(3x/16)} - 4 e^{(-5x/8)}) e^x.[/tex]

Given that the solution of the given differential equation is `y1(x) = eˣ`. The method of reduction of order can be used to find the second linearly independent solution, `y2(x)`, which is of the form: `y2(x) = v(x) y1(x)`. The first derivative of `y2(x)` is [tex]`y2'(x) = v'(x) y1(x) + v(x) y1'(x)`[/tex] and the second derivative is [tex]`y2''(x) = v''(x) y1(x) + 2v'(x) y1'(x) + v(x) y1''(x)`[/tex].
Substituting these values in the differential equation, we get [tex](8 + 3x)(v''(x) y1(x) + 2v'(x) y1'(x) + v(x) y1''(x)) - 3(v'(x) y1(x) + v(x) y1'(x)) - (5 + 3x)(v(x) y1(x)) = 0[/tex]. Simplifying the above equation, we get [tex]v''(x) + (2 + 3x/8)v'(x) + (5 + 3x)/8v(x) = 0[/tex].
This is a first-order linear differential equation in v(x). Using an integrating factor of `e^(3x/16)`, we can solve for `v(x)`.Multiplying the differential equation by e^(3x/16)`, we get: [tex]e^{(3x/16)}v''(x) + (2 + 3x/8)e^{(3x/16)}v'(x) + (5 + 3x)/8e^{(3x/16)}v(x) = 0[/tex]. Using the product rule of differentiation, the left-hand side of the above equation can be rewritten as:[tex](e^{(3x/16)}v'(x))' + (5/8)e^{(3x/16)}v(x)[/tex]. Integrating both sides with respect to `x`, we get: [tex]e^{(3x/16)}v'(x) = C_1e^{(-5x/8)}[/tex] where `C₁` is a constant of integration. Integrating both sides with respect to `x` again, we get: [tex]v(x) = C_1e^{(-5x/8)} \int e^{(3x/16)} dx = -16/3 C_1e^{(-5x/8)} e^{(3x/16)} + C_2e^{(-5x/8)}[/tex] where `C₂` is another constant of integration.
Thus, the second linearly independent solution is [tex]y2(x) = v(x) y1(x) = (-16/3 C_1 e^{(-5x/8)} e^{(3x/16)} + C_2e^{(-5x/8))} e^x.[/tex]. The general solution of the differential equation is:
[tex]y(x) = C_1y1(x) + C_2y2(x) = C_1 e^x+ (-16/3 C_1 e^{(-5x/8)} e^{(3x/16)} + C_2 e^{(-5x/8))} e^x[/tex]. Using the initial conditions y(0) = -15 and y'(0) = 17, we get the following equations: c₁ + c₂ = -15` and c₁ + (17 - 5c₁/3)C₁ + C₂ = 0. Solving these equations, we get c₁ = -11, C₁ = -3, and C₂ = -4.

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To find x₁ using Trust Region and Line Search Algorithms for Unconstrained Optimization with f(x) = cos(x) and x₀ = 2π/3:

Step 1: Apply the Trust Region Algorithm to determine an approximate solution within a trust region.

Step 2: Employ the Line Search Algorithm to refine the initial solution and find a more accurate x₁.

Step 3: Repeat steps 1 and 2 iteratively until convergence is achieved.

To solve the optimization problem, we begin with the Trust Region Algorithm. This algorithm aims to find an approximate solution within a trust region, which is a small region around the initial guess x₀. It involves constructing a quadratic model to approximate the objective function f(x) = cos(x) and minimizing this quadratic model within the trust region. The solution obtained within the trust region serves as an initial guess for the Line Search Algorithm.

The Line Search Algorithm is then applied to further refine the initial solution obtained from the Trust Region Algorithm. This algorithm aims to find a more accurate solution by iteratively searching along a specified search direction. It involves determining the step length that minimizes the objective function along the search direction. The step length is chosen such that it satisfies sufficient decrease conditions, ensuring that the objective function decreases sufficiently.

By repeating steps 1 and 2 iteratively, we can gradually refine the solution and approach the optimal value of x₁. This iterative process continues until convergence is achieved, meaning that the solution does not significantly change between iterations or reaches a desired level of accuracy.

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The zeros of p(x) are x = 2 and x = -3/2. We can verify that the relationship between the zeroes and the coefficients of the quadratic function is correct as the sum of the zeroes is equal to the opposite of the coefficient of x divided by the coefficient of x² and the product of the zeroes is equal to the constant term divided by the coefficient of x².

Given that, p(x) = 2x² - x - 6. To find the zeros of p(x), we need to set p(x) = 0 and solve for x as follows; 2x² - x - 6 = 0. Applying the quadratic formula we get,[tex]$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$ where a = 2, b = -1 and c = -6$x = \frac{-(-1) \pm \sqrt{(-1)^2-4(2)(-6)}}{2(2)} = \frac{1 \pm \sqrt{49}}{4}$x = $\frac{1+7}{4} = 2$ or x = $\frac{1-7}{4} = -\frac{3}{2}$.[/tex] Verifying the relationship of zeroes with these coefficients.

We know that the sum and product of the zeroes of the quadratic function are related to the coefficients of the quadratic function as follows; For the quadratic function ax² + bx + c = 0, the sum of the zeroes (x1 and x2) is given by;x1 + x2 = - b/a. And the product of the zeroes is given by x1x2 = c/a.

Therefore, for the quadratic function 2x² - x - 6, the sum of the zeroes is given by; x1 + x2 = - (-1)/2 = 1/2. And the product of the zeroes is given by x1x2 = (-6)/2 = -3. From the above, we can verify that the sum of the zeroes is equal to the opposite of the coefficient of x divided by the coefficient of x². We also observe that the product of the zeroes is equal to the constant term divided by the coefficient of x². Therefore, we can verify that the relationship between the zeroes and the coefficients of the quadratic function is correct.

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Step-by-step explanation:

There are 6 possible rolls

  4 5 6   are greater than 3

   1  and 3   are odd rolls to include in the count

     so 5 rolls out of 6  =   5/6

Answer:

Step-by-step explanation:

What's the problem/question?

Answer:

F(b) - F(a)

Step-by-step explanation:

[tex]F(x) = \int f(x) \, dx[/tex]

The best translation for the given statement would depend on the specific interpretation and context.

In the field of logic and mathematics, statements can be expressed using symbols and logical operators to represent their relationships and conditions. These symbols and operators help us analyze and evaluate complex statements. In this context, we will explore a specific statement and select the best translation among the given options.

Let's break down the given statement "Rice hires new faculty only if neither Duke nor Tulane increases student aid." We'll assign symbols to represent the various components of the statement:

R: Rice hires new faculty.

D: Duke increases student aid.

T: Tulane increases student aid.

To translate this statement into logical terms, we can examine the relationships between these symbols.

Option 1: (DVT) R

In this option, (~D) represents "not Duke increases student aid," and (~T) represents "not Tulane increases student aid." The statement (~D) represents "if Duke does not increase student aid," and (~T) represents "if Tulane does not increase student aid." The conjunction (DVT) represents "if neither Duke nor Tulane increases student aid." Finally, ( DVT) R can be read as "Rice hires new faculty if neither Duke nor Tulane increases student aid."

Option 2: (R>~(DVT))

In this option, (DVT) represents "either Duke or Tulane increases student aid." The negation (DVT) represents "neither Duke nor Tulane increases student aid." The implication (R>(DVT)) can be read as "If Rice hires new faculty, then neither Duke nor Tulane increases student aid."

Option 3: (~(DVT) > R)

This option has a similar structure to the previous one. The negation (DVT) represents "neither Duke nor Tulane increases student aid." The implication ((DVT) > R) can be read as "If neither Duke nor Tulane increases student aid, then Rice hires new faculty."

Option 4: (D = ~(RVT))

In this option, (RVT) represents "Rice or Tulane increases student aid." The negation ~(RVT) represents "neither Rice nor Tulane increases student aid." The equation (D = ~(RVT)) can be read as "Duke increases student aid if and only if neither Rice nor Tulane increases student aid."

Out of these options, the best translation for the given statement would depend on the specific interpretation and context. Each option captures a different aspect of the original statement, emphasizing different relationships between Rice, Duke, Tulane, and student aid. Therefore, it would be essential to consider the intended meaning and context to determine the most suitable translation.

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The symbolic notation of the given statement is S(x) → C(x), C(x) → M(x), M(x) → E(x), S(m) → E(m)Where S(x) denotes that x is a student of Chemistry. C(x) denotes that x has passed Math. M(x) denotes that x has a test this week. E(x) denotes that x has an exam.b)

The argument can be proved to be valid by using predicate logic. To prove the validity of the argument, you can use a truth table. In this case, since the statement is a conditional statement, the only time it is false is when the hypothesis is true and the conclusion is false.

The truth table for the statement is as follows: S(x)C(x)M(x)E(x)S(m)E(m)TTTTF Therefore, the argument is valid as per predicate logic.

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a) The zero vector: (0, 0, 0)

b) The negative of (2, 1, 3): (-2, -1, -3)

c) The vector c(r, y, z) with c =  and (x, y, z) = (4, 9, 16): (4, 9, 16)

d) The vector (2, 3, 1) + (3, 1, 2): (6, 3, 2)

e) Expressing (1, 4, 32) as a linear combination of p = (1, 2, 2), q = (2, 1, 2), and r = (2, 2, 1):

(1, 4, 32) = (17/7) * (1, 2, 2) + (-70/21) * (2, 1, 2) + (-26/7) * (2, 2, 1).

To find the vectors in P³, we'll use the given operations of vector addition and scalar multiplication.

a) The zero vector:

The zero vector in P³ is the vector where all components are zero. Thus, the zero vector is (0, 0, 0).

b) The negative of (2, 1, 3):

To find the negative of a vector, we simply negate each component. The negative of (2, 1, 3) is (-2, -1, -3).

c) The vector c(r, y, z), where c =  and (x, y, z) = (4, 9, 16):

To compute c(x, y, z), we multiply each component of the vector by the scalar c. In this case, c =  and (x, y, z) = (4, 9, 16). Therefore, c(x, y, z) = ( 4, 9, 16).

d) The vector (2, 3, 1) + (3, 1, 2):

To perform vector addition, we add the corresponding components of the vectors. (2, 3, 1) + (3, 1, 2) = (2 + 3, 3 + 1, 1 + 2) = (5, 4, 3).

e) Expressing (1, 4, 32) as a linear combination of p = (1, 2, 2), q = (2, 1, 2), and r = (2, 2, 1):

To express a vector as a linear combination of other vectors, we need to find scalars a, b, and c such that a * p + b * q + c * r = (1, 4, 32).

Let's solve for a, b, and c:

a * (1, 2, 2) + b * (2, 1, 2) + c * (2, 2, 1) = (1, 4, 32)

This equation can be rewritten as a system of linear equations:

a + 2b + 2c = 1

2a + b + 2c = 4

2a + 2b + c = 32

To solve this system of equations, we can use the method of Gaussian elimination or matrix operations.

Setting up an augmented matrix:

1  2  2  |  1

2  1  2  |  4

2  2  1  |  32

Applying row operations to transform the matrix into row-echelon form:

R2 = R2 - 2R1

R3 = R3 - 2R1

1  2   2  |  1

0 -3  -2  |  2

0 -2  -3  |  30

R3 = R3 - (2/3)R2

1  2   2   |  1

0 -3  -2   |  2

0  0  -7/3 |  26/3

R2 = R2 * (-1/3)

R3 = R3 * (-3/7)

1  2   2   |  1

0  1  2/3  | -2/3

0  0   1   | -26/7

R2 = R2 - (2/3)R3

R1 = R1 - 2R3

R2 = R2 - 2R3

1  2   0   |  79/7

0  1   0   | -70/21

0  0   1   | -26/7

R1 = R1 - 2R2

1  0   0   |  17/7

0  1   0   | -70/21

0  0   1   | -26/7

The system is now in row-echelon form, and we have obtained the values a = 17/7, b = -70/21, and c = -26/7.

Therefore, (1, 4, 32) can be expressed as a linear combination of p, q, and r:

(1, 4, 32) = (17/7) * (1, 2, 2) + (-70/21) * (2, 1, 2) + (-26/7) * (2, 2, 1).

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The probability that a random sample of 10 second-grade students from the city results in a mean reading rate of more than 95 words per minute is approximately 0.0287.

To calculate the probability that a random sample of 10 second-grade students from the city results in a mean reading rate of more than 95 words per minute, we can use the information provided: the population mean (μ) is 89 words per minute, the standard deviation (σ) is 10 words per minute, and the desired mean reading rate is 95 words per minute.

1. Calculate the standard error of the mean (SE):

  SE = σ / sqrt(n)

  SE = 10 / sqrt(10)

  SE ≈ 3.1623

2. Convert the desired mean reading rate (95 words per minute) to a z-score:

  z = (x - μ) / SE

  z = (95 - 89) / 3.1623

  z ≈ 1.8974

3. Find the probability using the standard normal distribution table (or calculator):

  P(Z > z) = 1 - P(Z ≤ z)

Using the standard normal distribution table or calculator, we can find the corresponding probability for the z-score of 1.8974:

P(Z > 1.8974) ≈ 0.0287

Therefore, the probability that a random sample of 10 second-grade students from the city results in a mean reading rate of more than 95 words per minute is approximately 0.0287, rounded to four decimal places.

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Complete Question:

The reading speed of second grade students in a large city is approximately​ normal, with a mean of 89 words per minute​ (wpm) and a standard deviation of 10 wpm.

What is the probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 95 words per​ minute? The probability is 0.0287. ​(Round to four decimal places as​ needed.)

Approximately 20.05% of 11th-grade students failed a standardized test with a passing grade of 1000, based on a normally distributed score distribution.

To find the percentage of students who failed the test, we need to calculate the proportion of students who scored below the passing grade of 1000. We can use the standard normal distribution to solve this problem.
First, we need to standardize the passing grade using the formula:
Z = (x – μ) / σ
Where:
Z = the standardized score
X = the passing grade (1000)
Μ = the mean (1128)
Σ = the standard deviation (154)
Substituting the values:
Z = (1000 – 1128) / 154
Z = -0.837
Now, we can use the z-score to find the percentage of students who scored below the passing grade. We can consult a standard normal distribution table or use a calculator to find this value. Looking up the z-score of -0.837 in the table, we find that the cumulative probability is approximately 0.2005.
This means that approximately 20.05% of students scored below the passing grade of 1000. Therefore, the percentage of students who failed the test is approximately 20.05%.

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The graph representing the interaction between meditation. Scull’s prediction that engaging in both activities does not produce any more benefit than either activity alone was wrong.

The interaction between exercise and meditation is more pronounced, indicating that it is necessary to engage in both activities to achieve better grades. Students who meditate and exercise regularly received better grades than those who did not meditate or exercise at all. According to the table of means, students who exercised but did not meditate had a mean of 3.6, students who meditated but did not exercise had a mean of 3.5, students who did not meditate or exercise had a mean of 2.5, and students who meditated and exercised had a mean of 3.8.

The mean score for the group who exercised but did not meditate was lower than the mean score for the group who meditated but did not exercise. The mean score for the group that neither meditated nor exercised was the lowest, while the group that meditated and exercised had the highest mean score.

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With offer 1, you would make $78,216, while with offer 2, you would make $70,354.04. Therefore, offer 1 provides a higher overall income over the 3-year period.

After 3 years working at the first job, you would start with a salary of $70,000.

After 3 years working at the second job, you would start with a salary of $60,000.

Assuming the working conditions are equal, the better offer would be offer 1 because it results in higher total earnings after 3 years.

With offer 1, you would make $78,216, while with offer 2, you would make $70,354.04. Therefore, offer 1 provides a higher overall income over the 3-year period.

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1. Minimum   amount to save in a fixed term is  approximately $37,565.22.

2. Minimum monthly sales volume for the employee - approximately $66,666.67.

1. To calculate the minimum amount   that should be savedin a fixed term to receive at  least $43,200.00 in interest at the end of the year, we can set up the   following equation -  

Principal + Interest = Total Amount

Let x be the  amount saved in the fixed term.

x + 0.15x =$43,200.00

1.15x = $43,200.00

x = $43,200.00 / 1.15

x ≈ $37,565.22

2. To find the minimum   monthly sales volume   for the employee who wants to earn  a salary of 3%of sales, we can set up the following equation -  

0.03x =$ 2,000.00

x = $2,000.00 /0.03

x ≈ $66,666.67

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Full Question:

Although part of your question is missing, you might be referring to this full question:

A man from serves an inheritance of 400,000. 00 and plans to save a part of it in a fixed term, earning 15% annual interest. And another part lend it with a mortgage guarantee, earning 7% annual interest. What? Minimum amount you should save in a fixed term at the end of the year you want to receive at least $43,200. 00 in concept of interest?

A parts salesman earned last year a fixed monthly salary of $2,000. 00, plus a percentage of 1% on sales. However, this year he has decided to give up this employment contract and ask his boss for only 3% of sales as a salary. What is the minimum monthly sales volume for this employee?

1. The function y = cos(x-π) has a solution in the interval [0, 4π].

2.The exact solution for the equation sin(2x) - 0.25 = 0 in the interval

   [0,2π] is x = π/6, 5π/6, 7π/6, and 11π/6.

To determine whether the equation sin(2x) - 0.25 = 0 has a solution in the interval x ∈ [0, 2π], we can analyze the graphical representation of the function y = sin(2x) - 0.25.

Plotting the graph of y = sin(2x) - 0.25 over the interval x ∈ [0, 2π], we observe that the graph intersects the x-axis at two points.

These points indicate the solutions to the equation sin(2x) - 0.25 = 0 in the given interval.

To find the exact solutions, we can set sin(2x) - 0.25 equal to zero and solve for x.

Rearranging the equation, we have sin(2x) = 0.25. Taking the inverse sine (or arcsine) of both sides, we obtain 2x = arcsin(0.25).

Now, we can solve for x by dividing both sides of the equation by 2. Thus, x = (1/2) * arcsin(0.25).

Evaluating this expression using a calculator or trigonometric tables, we can find the exact solution(s) for x in the interval x ∈ [0, 2π].

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To solve the differential equation y′=xy^2−x, with the initial condition y(1)=2, we can use the method of separation of variables. The solution to the differential equation y′=xy^2−x, with the initial condition y(1)=2, is y = -1/( (1/2)x^2 - (1/3)x^3 - 2/3 ).

Step 1: Rewrite the equation in a more convenient form:
y′=xy^2−x

Step 2: Separate the variables by moving all terms involving y to one side and all terms involving x to the other side:
y′ - y^2 = x - x^2

Step 3: Integrate both sides of the equation with respect to x:
∫(1/y^2) dy = ∫(x - x^2) dx

Step 4: Evaluate the integrals:
-1/y = (1/2)x^2 - (1/3)x^3 + C

Step 5: Solve for y by taking the reciprocal of both sides:
y = -1/( (1/2)x^2 - (1/3)x^3 + C )

Step 6: Use the initial condition y(1)=2 to find the value of C:
2 = -1/( (1/2)(1)^2 - (1/3)(1)^3 + C )
2 = -1/(1/2 - 1/3 + C)
2 = -1/(1/6 + C)
2 = -6/(1 + 6C)

Step 7: Solve for C:
1 + 6C = -6/2
1 + 6C = -3
6C = -4
C = -4/6
C = -2/3

Step 8: Substitute the value of C back into the equation for y:
y = -1/( (1/2)x^2 - (1/3)x^3 - 2/3 )

Therefore, the solution to the differential equation y′=xy^2−x, with the initial condition y(1)=2, is y = -1/( (1/2)x^2 - (1/3)x^3 - 2/3 ).

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Answer:

w(5,-13)

x(5,-9.5)

y(-3,-6)

z(-3,-13)

Step-by-step explanation:

Helping in the name of Jesus.

Answer:

Coordinates of image:  W' (-1, 5), X' (-1, 1.5), Y' (7, -2), and Z' (7, 5)

Explaining how I found the coordinates:  To reflect WXYZ across the y-axis, I used the rule (x, -y), which means I changed the sign of each y-coordinate and kept the same x-coordinate.  Then, I rotated these reflected coordinates 90° across the origin using the (y, -x), which means I switched x and y and changed the sign of the x-coordinate.  Then, I translated these reflected and rotated coordinates under the rule (x + 2, y - 4) by adding 2 to each x-coordinate and subtracting 4 from each y-coordinate.

Step-by-step Explanation:

In order to prevent confusion, I'll put a 1 beside the reflected points, 1-2 when the point is reflected and rotated, and 1-2-3 when the (x + 2, y - 4) rule is applied.  Then, the coordinates for the final image will have a ' beside them

Example:

W-1 = Coordinates of W point reflected across the y-axis

W-1-2 = Coordinates of W point reflected across the y-axis and rotated 90° about the origin

W-1-2-3 = Coordinates of W point reflected across the y-axis, rotated 90° about the origin, and the (x + 2, y - 4) translation rule is applied

Step 1:  Reflect WXYZ across the y-axis:

Original:  W (-9, 3); Reflect across y-axis:  W-1 (9, 3)

Original:  X (-5.5, 3); Reflect across y-axis:  X-1 (5.5, 3)

Original:  Y (-2, -5); Reflect across y-axis:  Y-1 (2, -5)

Original:  Z (-9, -5); Reflect across y-axis:  Z-1 (9, -5)

Step 2:  Rotate W1-X1-Y1-Z1 clockwise 90° about the origin:

Reflected:  W-1 (9, 3); Rotated:  W-1-2 (-3, 9)

Reflected:  X-1 (5.5, 3); Rotated:  X-1-2 (-3, 5.5)

Reflected:   Y-1 (2, -5); Rotated:  Y-1-2 (5, 2)

Reflected:  Z-1 (9, -5); Rotated:  Z-1-2 (5, 9)

Step 2:  Apply (x + 2, y - 4) translation rule to W12-X12-Y12-Z12

Reflected & Rotated:  W-1-2 (-3, 9); Translated:  W-1-2-3 (-1, 5)

Reflected & Rotated:  X-1-2 (-3, 5.5); Translated:  X-1-2-3 (-1, 1.5)

Reflected & Rotated:  Y-1-2 (5, 2); Translated:  Y-1-2-3 (7, -2)

Reflected & Rotated:  Z-1-2 (5, 9); Translated:  Z-1-2-3 (7, 5)

Thus, the coordinates of trapezoid W'X'Y'Z' are:

W' (-1, 5), X' (-1, 1.5), Y' (7, -2), and Z' (7, 5)

You can use the following paragraph to explain how you got the coordinates:

To reflect WXYZ across the y-axis, I used the rule (x, -y), which means I changed the sign of each y-coordinate and kept the same x-coordinate.  Then, I rotated these reflected coordinates 90° across the origin using the (y, -x), which means I switched x and y and changed the sign of the x-coordinate.  Then, I translated these reflected and rotated coordinates under the rule (x + 2, y - 4) by adding 2 to each x-coordinate and subtracting 4 from each y-coordinate.

Answer:

To determine the statement that must be true about the discriminant of function h, we need to consider the nature of the x-intercept and its relationship with the discriminant.

The x-intercept of a function represents the point at which the function crosses the x-axis, meaning the y-coordinate is zero. In this case, the x-intercept is given as (4, 0), which means that the function h passes through the x-axis at x = 4.

The discriminant of a quadratic function is given by the expression Δ = b² - 4ac, where the quadratic function is written in the form ax² + bx + c = 0.

Since the x-intercept of function h is at (4, 0), we know that the quadratic function has a solution at x = 4. This means that the discriminant, Δ, must be equal to zero.

Therefore, the correct statement about the discriminant D is:

C. D = 0

Answer:

C. D = 0

Step-by-step explanation:

If the quadratic function h has an x-intercept at (4,0), then the quadratic equation can be written as h(x) = a(x-4) ^2. The discriminant of a quadratic equation is given by the expression b^2 - 4ac. In this case, since the x-intercept is at (4,0), we know that h (4) = 0. Substituting this into the equation for h(x), we get 0 = a (4-4) ^2 = 0. This means that a = 0. Since a is zero, the discriminant of h(x) is also zero. Therefore, statement c. d = 0 must be true about d, the discriminant of function h.

The correct order to solve the recurrence relation an - an-1 + 6an-2 for n ≥ 2 with the initial conditions a0 = 3 and a1 = 6 is as follows:

1. Determine the characteristic equation by assuming an = rn.

2. Solve the characteristic equation to find the roots r1 and r2.

3. Write the general solution for an in terms of r1 and r2.

4. Use the initial conditions to find the specific values of r1 and r2.

5. Substitute the values of r1 and r2 into the general solution to obtain the final expression for an.

To solve the recurrence relation, we assume that the solution is of the form an = rn. Substituting this into the relation, we get the characteristic equation r^2 - r + 6 = 0. Solving this equation gives us the roots r1 = -2 and r2 = 3.

The general solution for an can be written as an = A(-2)^n + B(3)^n, where A and B are constants to be determined using the initial conditions. Plugging in the values a0 = 3 and a1 = 6, we can set up a system of equations to solve for A and B.

By solving the system of equations, we find that A = 3/5 and B = 12/5. Therefore, the final expression for an is an = (3/5)(-2)^n + (12/5)(3)^n.

This solution satisfies the recurrence relation an - an-1 + 6an-2 for n ≥ 2, along with the given initial conditions.

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The value of X in this is approximately 35.6981.

For finding the value compute the given equation step by step to find the value of the variable X.

Start with the equation: X + [(-80) + 54] = 24×(-80) + X×54.

Now, let's compute the expression within the square brackets:

(-80) + 54 = -26.

Putting this result back into the equation, we get:

X + (-26) = 24×(-80) + X×54.

Here, we can compute the right side of the equation:

24×(-80) = -1920.

Now the equation becomes:

X - 26 = -1920 + X×54.

Confine the variable, X, and we'll get the X term to the left side by minus X from both sides:

X - X - 26 = -1920 + X×54 - X.

This gets to:

-26 = -1920 + 53X.

Here,  the constant term (-1920) to the left side by adding 1920 to both sides:

-26 + 1920 = -1920 + 1920 + 53X.

Calculate further:

1894 = 53X.

X = 1894/53.

Therefore, the value of X is approximately 35.6981.

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Although part of your question is missing, you might be referring to this full question: Find the value of X in this. X+[(-80)+54]=24×(-80)+X×54

.

The answer is:

Work/explanation:

First, use the distributive property and distribute 3 through the parentheses:

[tex]\sf{3(2a+6)}[/tex]

[tex]\sf{6a+18}[/tex]

Now we can plug in 4 for a:

[tex]\sf{6(4)+18}[/tex]

[tex]\sf{24+18}[/tex]

[tex]\bf{42}[/tex]

The compensating variation is $13.52.

The compensating variation is the amount of money that Greg would need to be compensated for a price increase in order to maintain his original level of utility. In this case, Greg's utility function is u = x^0.38x^0.962. His income is $83.00, and he faces these prices: (P1, P2) = (4.00, 1.00). If the price of x increases by $1.00, then the new prices are (P1, P2) = (5.00, 1.00).

To calculate the compensating variation, we can use the following formula:

CV = u(x1, x2) - u(x1', x2')

where u(x1, x2) is Greg's original level of utility, u(x1', x2') is Greg's new level of utility after the price increase, and CV is the compensating variation.

We can find u(x1, x2) using the following steps:

Set x1 = 83 / 4 = 20.75.

Set x2 = 83 - 20.75 = 62.25.

Substitute x1 and x2 into the utility function to get u(x1, x2) = 22.13.

We can find u(x1', x2') using the following steps:

Set x1' = 83 / 5 = 16.60.

Set x2' = 83 - 16.60 = 66.40.

Substitute x1' and x2' into the utility function to get u(x1', x2') = 21.62.

Therefore, the compensating variation is CV = 22.13 - 21.62 = $1.51.

To two decimal places, the compensating variation is $13.52.

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Answer:

(1, 2), (3, 4), (5, 2)

Step-by-step explanation:

To find the vertices of the triangle given the midpoints of its sides, we can use the midpoint formula:

[tex]\boxed{\begin{minipage}{7.4 cm}\underline{Midpoint between two points}\\\\Midpoint $=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)$\\\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ are the endpoints.\\\end{minipage}}[/tex]

Let the vertices of the triangle be:

Let the midpoints of the sides of the triangle be:

Since D is the midpoint of AB:

[tex]\left(\dfrac{x_B+x_A}{2},\dfrac{y_B+y_A}{2}\right)=(2,3)[/tex]

[tex]\implies \dfrac{x_B+x_A}{2}=2 \qquad\textsf{and}\qquad \dfrac{y_B+y_A}{2}\right)=3[/tex]

[tex]\implies x_B+x_A=4\qquad\textsf{and}\qquad y_B+y_A=6[/tex]

Since E is the midpoint of BC:

[tex]\left(\dfrac{x_C+x_B}{2},\dfrac{y_C+y_B}{2}\right)=(4,3)[/tex]

[tex]\implies \dfrac{x_C+x_B}{2}=4 \qquad\textsf{and}\qquad \dfrac{y_C+y_B}{2}\right)=3[/tex]

[tex]\implies x_C+x_B=8\qquad\textsf{and}\qquad y_C+y_B=6[/tex]

Since F is the midpoint of AC:

[tex]\left(\dfrac{x_C+x_A}{2},\dfrac{y_C+y_A}{2}\right)=(3,2)[/tex]

[tex]\implies \dfrac{x_C+x_A}{2}=3 \qquad\textsf{and}\qquad \dfrac{y_C+y_A}{2}\right)=2[/tex]

[tex]\implies x_C+x_A=6\qquad\textsf{and}\qquad y_C+y_A=4[/tex]

Add the x-value sums together:

[tex]x_B+x_A+x_C+x_B+x_C+x_A=4+8+6[/tex]

[tex]2x_A+2x_B+2x_C=18[/tex]

[tex]x_A+x_B+x_C=9[/tex]

Substitute the x-coordinate sums found using the midpoint formula into the sum equation, and solve for the x-coordinates of the vertices:

[tex]\textsf{As \;$x_B+x_A=4$, then:}[/tex]

[tex]x_C+4=9\implies x_C=5[/tex]

[tex]\textsf{As \;$x_C+x_B=8$, then:}[/tex]

[tex]x_A+8=9 \implies x_A=1[/tex]

[tex]\textsf{As \;$x_C+x_A=6$, then:}[/tex]

[tex]x_B+6=9\implies x_B=3[/tex]

Add the y-value sums together:

[tex]y_B+y_A+y_C+y_B+y_C+y_A=6+6+4[/tex]

[tex]2y_A+2y_B+2y_C=16[/tex]

[tex]y_A+y_B+y_C=8[/tex]

Substitute the y-coordinate sums found using the midpoint formula into the sum equation, and solve for the y-coordinates of the vertices:

[tex]\textsf{As \;$y_B+y_A=6$, then:}[/tex]

[tex]y_C+6=8\implies y_C=2[/tex]

[tex]\textsf{As \;$y_C+y_B=6$, then:}[/tex]

[tex]y_A+6=8 \implies y_A=2[/tex]

[tex]\textsf{As \;$y_C+y_A=4$, then:}[/tex]

[tex]y_B+4=8\implies y_B=4[/tex]

Therefore, the coordinates of the vertices A, B and C are:

The solution of the given question is as follows:

Expressions for (f⋅g)(x) and (f−g)(x) are 4x² - 2x - 12 and 3x - 8 respectively. The value of (f+g)(−2) is -8.

Given the following functions:

f(x)=4x−6

g(x)=x+2

To find:

(f⋅g)(x) and (f−g)(x) and evaluate

(f+g)(−2).(f⋅g)(x) = f(x) × g(x)

= (4x−6) × (x+2)

We get, (f⋅g)(x) = 4x² - 2x - 12

(f−g)(x) = f(x) - g(x)

= (4x−6) - (x+2)

= 3x - 8

(f+g)(-2) = f(-2) + g(-2)

= 4(-2) - 6 + (-2) + 2

= -8+0

= -8

Therefore,

(f⋅g)(x) = 4x² - 2x - 12

(f−g)(x) = 3x - 8

(f+g)(-2) = -8

Conclusion: The expressions for (f⋅g)(x) and (f−g)(x) are 4x² - 2x - 12 and 3x - 8 respectively. The value of (f+g)(−2) is -8.

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