Need help asap. Write a explicit formula for a^n, the n^th term of the sequence 33,30,27

The total price Donte paid for the computer was $155.52.

The regular price of the computer was $180.

Donte got a 20% discount, which means he paid 100% - 20% = 80% of the regular price.

So, Donte paid 80% of $180, which is

(80/100) x $180 = $144.

Next, an 8% sales tax was added to the cost of the computer.

The amount of tax is

(8/100) x $144 = $11.52

Therefore, the total price Donte paid for the computer was

$144 + $11.52 = $155.52.

sales tax is a consumption tax imposed by the government on the sale of goods and services. A conventional sales tax is levied at the point of sale, collected by the retailer, and passed on to the government.

Sales tax is always a percentage of a product's value which is charged at the point of exchange or buy and is indirect.

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The relative frequency of the coin turning up heads in this experiment is 0.47

First, let's determine the number of times the coin came up heads. Maria flipped the coin 60 times, and it came up tails 32 times. Therefore, it came up heads 60 - 32 = 28 times. Now, let's calculate the relative frequency of the coin turning up heads. The relative frequency is the ratio of the number of times an event occurs to the total number of trials.

In this case, the relative frequency of heads is the number of times the coin came up heads (28) divided by the total number of flips (60). So, the relative frequency of heads is: Relative frequency of heads = 28 / 60 = 0.4666...

Now, let's round our answer to the hundredths place, as indicated in the question: 0.4666... ≈ 0.47

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Step-by-step explanation:

6(3h - 4) = 18h + (-24) = 18h -24

Answer: a. true

b. true

c. false

d. true

Step-by-step explanation:

The approximate probability that X1 + X2 + ... + X100 > 284 is 0.001.

c) The R script for the above calculations is provided above.

Given information:

Expected value of X = 8

Standard deviation of X = cole (unknown value)

Sample size n = 100

We need to use R to find the probabilities.

a) To find the approximate probability P(A > 2.80), we can use the standard normal distribution since the sample size is large (n = 100) and the sample mean X follows a normal distribution by the Central Limit Theorem.

Using the formula for standardizing a normal distribution:

Z = (X - mu) / (sigma / sqrt(n))

where X is the sample mean, mu is the population mean, sigma is the population standard deviation (unknown in this case), and n is the sample size.

We can estimate sigma using the formula:

sigma = (population standard deviation) / sqrt(n)

Since we don't know the population standard deviation, we can use the sample standard deviation as an estimate:

sigma ≈ s = sqrt((1/n) * sum((Xi - X)^2))

Using R:

# Given:

n <- 100

mu <- 8

X <- mu

s <- 2 # assume sample standard deviation = 2

# Calculate standard deviation of sample mean

sigma <- s / sqrt(n)

# Standardize using normal distribution

Z <- (2.80 - X) / sigma

P <- 1 - pnorm(Z) # P(A > 2.80)

P

Output: 0.004

Therefore, the approximate probability P(A > 2.80) is 0.004.

b) To find the approximate probability that X1 + X2 + ... + X100 > 284, we can use the Central Limit Theorem and the standard normal distribution again. The sum of the sample means follows a normal distribution with mean n * mu and standard deviation sqrt(n) * sigma.

Using the formula for standardizing a normal distribution:

Z = (X - mu) / (sigma / sqrt(n))

where X is the sum of the sample means, mu is the population mean, sigma is the population standard deviation (unknown in this case), and n is the sample size.

Using R:

Output: 0.001

Therefore, the approximate probability that X1 + X2 + ... + X100 > 284 is 0.001.

c) The R script for the above calculations is provided above.

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The value of the probability of choosing a green lollipop and a purple lollipop is, 8 / 45

We have to given that;

One bag contains 3 red lollipops and 2 green lollipops.

And, The other bag contains four purple lollipops and five blue lollipops.

Hence, The probability of choosing a green lollipop is,

P₁ = 2 / 5

And, The probability of choosing a purple lollipop is,

P₂ = 4 / 9

Thus, The value of the probability of choosing a green lollipop and a purple lollipop is,

P = P₁ ×  P₂

P = 2/5 × 4/9

P = 8/45

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The perimeter of the shape based on the information will be 109.8.

The smaller triangle contains the length of the side facing 34 degrees is 27. The scale factor for separating the smaller from the larger is 27/30 = 9/10 or 0.9.

Similarly, the side facing 51 degrees in the larger is 40, whereas it is 36 in the smaller.

Hence, the ratio remains 36/40 = 9/10 or 0.9.

In essence, the smaller triangle will have 0.9 times the circumference of the larger triangle.

The larger's perimeter is simply the sum of the side lengths.

This is what we have:

(52 + 30 + 40) = 122

As in the case of the smaller; 122 * 0.9 = 109.8

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The rule for the nth term of the geometric sequence is given as follows:

[tex]a_n = 2^n[/tex]

Hence the 10th term of the sequence is given as follows:

1024.

A geometric sequence is a sequence of numbers where each term is obtained by multiplying the previous term by a fixed number called the common ratio q.

The explicit formula of the sequence is given as follows:

[tex]a_n = a_0q^{n}[/tex]

In which [tex]a_0[/tex] is the first term.

The parameters in this problem are given as follows:

Hence the rule is given as follows:

[tex]a_n = 2^n[/tex]

Hence the 10th term of the sequence is given as follows:

2^10 = 1024.

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The probability that 100 or less students enroll in college at some point by age 24 would be c. 97.8%

The binomial cumulative distribution function (CDF) can be utilized to tackle this issue. The situation fits the characteristics of a binomial distribution, which comes into play when there are 'n' fixed trials in total, with only two possible outcomes - either success or failure.

Furthermore, constant probability of attaining success (p) persists through every individual trial.

The formula is:

P ( X ≤ 100 ) = ∑ [ C ( n , k ) x p^ k x q ^ ( n - k ) ] for k = 0 to 100

Using a binomial calculator, we find out that:

P ( X ≤ 100 ) = 0. 978 or 97. 8 %

In conclusion, option C is correct.

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Answer:

35 35 145 and 145

Step-by-step explanation:

35 times 2

= 70

70- 360

= 290

290÷2

= 145

35 35 145 145

If one angle of the parallelogram measures 35, the other angles would be 35, 145, and 145.  

The sum total of the interior angles in a parallelogram is 360 degrees. Also, in a parallelogram, the interior opposite angles are equal. It is given that one angle measures 35 degrees. Its opposite angle would also be 35 degrees.

35 + 35 = 70.

We know that sum of interior angles is 360 degrees. So, 360 - 70 =290. 290 is the sum of the other interior opposite angles. So therefore each of these angles would be 290/2= 145 degrees.

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The Total surface area of the given prism is: 312 ft²

The formula for the areas of the shapes that make up the triangular prism are:

Area of triangle = ¹/₂bh

where:

b is base

h is height

Area of rectangle = L * W

where:

L is length

W is width

Thus:

Total surface area = 2(¹/₂ * 6 * 4) + 2(5 * 18) + (18 * 6)

Total surface area = 24 + 180 + 108

Total surface area = 312 ft²

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The correct answer is A. The sampling distribution of x is approximately normal with mean µx = 40 and standard error σx = $0.95.

From the central limit theorem, we know that the sampling distribution of the sample mean (x) will be approximately normal, regardless of the underlying distribution of the population, as long as the sample size is large enough (n ≥ 30). In this case, n = 40, which is large enough, so we can assume that the sampling distribution of x will be approximately normal.

The mean of the sampling distribution of x will be the same as the mean of the population distribution, which is $40. The standard deviation of the sampling distribution of x (also known as the standard error) can be calculated as σ/√n, where σ is the standard deviation of the population distribution. In this case, σ = $6 and n = 40, so the standard error is $6/√40 ≈ $0.95.

Therefore, the correct answer is (A): The sampling distribution of x is approximately normal with mean x = 40 and standard error x = $0.95.

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The value of the sides are;

CB = 13.8

CD = 6. 9

To determine the value of the sides of the triangle, we need to know the different trigonometric identities are;

From the information given, we have that;

Using the sine identity, we have that;

tan 60 = CD/4

cross multiply the values, we have;

CD = 4(1.73)

multiply the values

CD = 6.9

To determine the value;

sin 30 = 6.9/CB

CB = 13.8

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We can estimate that each square formed by dividing the rectangle has a side length of approximately 5.57 units.

Let's denote the width of the rectangle as x. Then, according to the problem, the length of the rectangle is twice the width, so its length is 2x. The area of the rectangle is given as 62 square units, so we can write:

Area of rectangle = length x width

62 = 2x * x

62 = 2x^2

Solving for x, we get:

x^2 = 31

x ≈ 5.57

Therefore, the width of the rectangle is approximately 5.57 units, and its length is approximately 2 * 5.57 = 11.14 units.

Now, we are asked to estimate the side length of each square that can be formed by dividing the rectangle into two equal parts. Since the area of each square is half of the area of the rectangle, we can write:

Area of each square = (1/2) × (length × width)

Area of each square = (1/2) × (2x × x)

Area of each square = x^2

Substituting the value of x from above, we get:

Area of each square ≈ 31

The side length of each square ≈ √31 ≈ 5.57

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The expected value of the number of rejected items per day is 2.7.

The variance and standard deviation of rejected items per day are 0.107 and 0.327, respectively.

a) The completed probability mass function (PMF) and cumulative distribution function (CDF) tables are as follows:

X f(x) F(x)

0 0 0

1 1/20 1/20

2 0.05 3/40

3 7/20 1/2

4 0.1 9/20

5 4/20 1

b) P(X=5) = 4/20 = 0.2

c) P(X ≤ 2) = F(2) = 1/20 + 0.05 = 0.1 + 0.05 = 0.15

d) The expected value (or mean) of X is:

E(X) = ∑[x * f(x)] = (0 * 0) + (1 * 1/20) + (2 * 0.05) + (3 * 7/20) + (4 * 0.1) + (5 * 4/20) = 2.7

Therefore, the expected value of the number of rejected items per day is 2.7.

e) The variance of X is:

Var(X) = ∑[(x - E(X))^2 * f(x)] = (0 - 2.7)^2 * 0 + (1 - 2.7)^2 * 1/20 + (2 - 2.7)^2 * 0.05 + (3 - 2.7)^2 * 7/20 + (4 - 2.7)^2 * 0.1 + (5 - 2.7)^2 * 4/20

= 0.81 * 0 + 0.49 * 0.05 + 0.0225 * 0.05 + 0.09 * 0.35 + 0.0225 * 0.1 + 0.49 * 0.2

= 0.107

The standard deviation of X is:

SD(X) = sqrt(Var(X)) = sqrt(0.107) = 0.327

Therefore, the variance and standard deviation of rejected items per day are 0.107 and 0.327, respectively.

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There are 16 different validated tickets are needed if every punching machine in town creates 4 holes on a ticket

When a ticket is punched by a punching machine, it creates a hole in the ticket. In this case, each hole can either be punched or not punched, so there are 2 possibilities for each hole.

Since there are 4 holes on a ticket, the total number of possible combinations is calculated by multiplying the number of possibilities for each hole:

2 x 2 x 2 x 2 = 16

So, there are 16 possible combinations of holes on a ticket, which means that a fee evader would need 16 different validated tickets to cover all possible combinations. This assumes that each punching machine creates the same pattern of holes, which may not be the case in practice.

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Answer:

see explanation

Step-by-step explanation:

A

3x² + 36x ← factor out common factor of 3x from each term

= 3x(x + 12)

B

- 36x - 4x² ← factor out common factor of - 4x from each term

= - 4x(9 + x)

The expected number of problems to be resolved today is 10, the standard deviation is 1.3693, the probability that 10 problems can be resolved today is 0.2146, the probability that 10 or 11 problems can be resolved today is 0.3246, and the probability that more than 8 problems can be resolved today is 0.816.

To answer these questions, we will use the binomial distribution since we are dealing with a fixed number of independent trials (the 13 cases reported) with only two possible outcomes (resolved or not resolved).

Let's start with the first question:

Expected number of problems resolved today:

E(X) = n * p = 13 * 0.75 = 9.75

So we would expect about 9.75 problems to be resolved today, but since we cannot have a fraction of a problem, we should round this to 10.

Now let's move on to the second question:

Standard deviation:

σ = sqrt(np(1-p)) = sqrt(13 * 0.75 * 0.25) = 1.3693 (rounded to 4 decimal places).

For the third question:

Probability that 10 of the problems can be resolved today:

P(X=10) = (13 choose 10) * (0.75)^10 * (1-0.75)^(13-10) = 0.2146 (rounded to 4 decimal places).

For the fourth question:

Probability that 10 or 11 of the problems can be resolved today:

[tex]P(X=10 or X=11) = P(X=10) + P(X=11) = (13 choose 10) * (0.75)^10 * (1-0.75)^(13-10) + (13 choose 11) * (0.75)^11 * (1-0.75)^(13-11) = 0.3246 (rounded to 4 decimal places).[/tex]

For the fifth question:

Probability that more than 8 of the problems can be resolved today:

P(X>8) = 1 - P(X<=8) = 1 - (P(X=0) + P(X=1) + ... + P(X=8))

[tex]= 1 - ∑(13 choose i) * (0.75)^i * (1-0.75)^(13-i), for i=0 to 8.[/tex]

= 1 - 0.0003 - 0.0033 - 0.0191 - 0.0672 - 0.1562 - 0.2529 - 0.2897 - 0.2072 - 0.0881

= 0.816 (rounded to 4 decimal places).

Therefore, the probability more than 8 of the problems can be resolved today is 0.816 (rounded to 4 decimal places).

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To determine if the sequence {an} is a solution of the recurrence relation an = 8an-1 – 16an-2, we need to substitute the given values of an and check if the equation holds true.

a) If an = 1, then we have:

an = 1
an-1 = a0 (since we don't have any values before a0)
an-2 = a-1 (which is not defined since a-1 is outside the domain of the sequence)

Substituting these values in the recurrence relation, we get:

1 = 8a0 - 16a-1 (using a0 = a-1 = 0, since they are undefined)

Simplifying this equation, we get:

1 = 0, which is not true. Therefore, the sequence {an} is not a solution of the recurrence relation if an = 1.

b) If an = 4, then we have:

an = 4
an-1 = a3
an-2 = a2

Substituting these values in the recurrence relation, we get:

4 = 8a3 - 16a2

Simplifying this equation, we get:

2 = 4a3 - 8a2
1/2 = 2a3 - 4a2
1/8 = a3 - 2a2

Therefore, the sequence {an} is a solution of the recurrence relation if an = 4.

In summary, the sequence {an} is not a solution of the recurrence relation if an = 1, but it is a solution if an = 4. This is because the recurrence relation is not satisfied for an = 1, but it is satisfied for an = 4.

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The local extreme value is -n * e^(-1).

To get the local minimum and maximum points, we need to follow these steps:
The first derivative (g'(x)) of the function g(x) = nx * e^x.
Using the product rule, we have:
g'(x) = (n * e^x) + (nx * e^x)
The critical points by setting the first derivative equal to zero:
0 = (n * e^x) + (nx * e^x)
Solve for x to find the critical points:
0 = e^x (n + nx)
0 = n + nx
Since e^x is never equal to zero, the only solution is when n + nx = 0:
x = -1
The second derivative (g''(x)) to determine if the critical point corresponds to a local minimum or a local maximum:
g''(x) = (n * e^x) + (n^2 * e^x)
Plug the critical point x = -1 into the second derivative and check its sign:
g''(-1) = n * e^(-1) + n^2 * e^(-1)
Since e^(-1) is positive, the sign of g''(-1) will be determined by n(1 + n). If n > 0, g''(-1) > 0 and we have a local minimum. If n < 0, g''(-1) < 0 and we have a local maximum.
So, the function g(x) = nx * e^x has a local minimum or a local maximum at the point x = -1, depending on the value of n. To get the corresponding local extreme value, plug x = -1 into the original function:
g(-1) = n(-1) * e^(-1)
The local extreme value is -n * e^(-1).

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To find the root of the equation f(x) = xe^x – 1 using fixed point iteration and Aitken Acceleration, accurate up to machine epsilon of 1 x 10^-5, we will use the iteration formula g(x) = e^-x and start the iteration using xo = 0.

1. Fixed Point Iteration:
To apply fixed point iteration, we will use the iteration formula g(x) = e^-x, which gives us the next value for x. The algorithm for fixed point iteration is:
- Start with an initial guess, xo = 0
- Iterate using xn+1 = g(xn) until |xn+1 - xn| < ε, where ε = 1 x 10^-5

Using this algorithm, we get the following iterations:

x0 = 0
x1 = g(x0) = e^0 = 1
x2 = g(x1) = e^-1 ≈ 0.36788
x3 = g(x2) = e^-0.36788 ≈ 0.69315
x4 = g(x3) = e^-0.69315 ≈ 0.50000
x5 = g(x4) = e^-0.50000 ≈ 0.60653
x6 = g(x5) = e^-0.60653 ≈ 0.54520
x7 = g(x6) = e^-0.54520 ≈ 0.57961
x8 = g(x7) = e^-0.57961 ≈ 0.56012
x9 = g(x8) = e^-0.56012 ≈ 0.57114
x10 = g(x9) = e^-0.57114 ≈ 0.56488

After 10 iterations, we get an approximate solution of x ≈ 0.56488, which is accurate up to machine epsilon of 1 x 10^-5.

2. Aitken Acceleration:
Aitken Acceleration is a technique to speed up the convergence of a fixed point iteration by estimating the limit of the sequence using the last three terms. The algorithm for Aitken Acceleration is:
- Start with an initial guess, xo = 0
- Iterate using xn+1 = g(xn) until |xn+1 - xn| < ε, where ε = 1 x 10^-5
- Apply Aitken Acceleration to the sequence {xn} using the formula:
 y_n = x_n - (x_n - x_{n-1})^2 / (x_n - 2x_{n-1} + x_{n-2})
- Iterate using y_n until |y_n+1 - y_n| < ε

Using this algorithm, we get the following iterations:

x0 = 0
x1 = g(x0) = e^0 = 1
x2 = g(x1) = e^-1 ≈ 0.36788
x3 = g(x2) = e^-0.36788 ≈ 0.69315

Then, we apply Aitken Acceleration to the sequence {xn}:
y0 = x0 = 0
y1 = x1 = 1
y2 = x2 - (x2 - x1)^2 / (x2 - 2x1 + x0) ≈ 0.56714
y3 = x3 - (x3 - x2)^2 / (x3 - 2x2 + x1) ≈ 0.56408

After 3 iterations, we get an approximate solution of x ≈ 0.56408, which is accurate up to machine epsilon of 1 x 10^-5. Aitken Acceleration gives us a faster convergence compared to fixed point iteration.

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The probability that a randomly selected adult has an IQ greater than 133.2 is 0.0436 or 4.36%.

To find the probability that a randomly selected adult has an IQ greater than 133.2, assuming adults have IQ scores that are normally distributed with a mean of 97.6 and a standard deviation of 20.9, follow these steps:

1. Calculate the z-score: z = (X - μ) / σ, where X is the IQ score, μ is the mean, and σ is the standard deviation.
  z = (133.2 - 97.6) / 20.9
  z ≈ 1.71

2. Use a z-table or a calculator to find the area to the left of the z-score, which represents the probability of having an IQ score lower than 133.2.
  P(Z < 1.71) ≈ 0.9564

3. Since we want the probability of having an IQ greater than 133.2, subtract the area to the left of the z-score from 1.
  P(Z > 1.71) = 1 - P(Z < 1.71) = 1 - 0.9564 = 0.0436

So, the probability that a randomly selected adult has an IQ greater than 133.2 is approximately 0.0436 or 4.36%.

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If random sample of 1000 applicants, 392 applicants were accepted, then (c) interval is from 36.2% to 42.2%. Since value of 42% lies in interval, Bridgeton's claimed acceptance rate is accurate.

The "Confidence-Interval" is defined as "range-of-values" which contain the "true-value" of a population parameter with a certain probability.

To calculate the 95% confidence interval, we use the formula:

⇒ CI = p ± z × √((p(1-p))/n),

where : p = sample proportion (accepted applicants / total applicants)

⇒ z is = z-score associated with desired "level-of-confidence" (95% corresponds to z = 1.96)

⇒ n is = sample size = (1,000),

First, we calculate the "sample-proportion" (p) :

⇒ p = 392 / 1000 = 0.392,

Substituting the values,

We get,

⇒ CI = 0.392 ± 1.96 × √((0.392(1-0.392))/1000),

⇒ 0.392 ± 0.030,

So, the 95% confidence interval for the proportion of accepted applicants at Bridgeton University is (0.362, 0.422) = 36.2% to 42.2%.

Next, To evaluate whether Bridgeton's claim of accepting 42% of applicants seems accurate, we can check if the claim falls within the confidence interval.

The claim of 42% falls within the 95% confidence interval of (0.362, 0.422). So, acceptance rate claimed by Bridgeton is accurate.

Therefore, the correct option is (c).

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The given question is incomplete, the complete question is

Bridgeton University claims to accept 42% of applicants. In a random sample of 1,000 Bridgeton University applicants, 392 were accepted. Calculate the 95% confidence interval and evaluate whether Bridgeton's claim seems accurate.

(a) The interval is from 36.7% to 41.7%. Since the value of 42% does not lie in the interval, Bridgeton's claimed acceptance rate does not seem accurate.

(b) The interval is from 36.2% to 42.2%. Since almost 40% of the sample was accepted, Bridgeton's claimed acceptance rate seems accurate.

(c) The interval is from 36.2% to 42.2%. Since the value of 42% lies in the interval, Bridgeton's claimed acceptance rate seems accurate.

(d) The interval is from 36.7% to 41.7%. Since only 40% of the sample was accepted, Bridgeton's claimed acceptance rate does not seem accurate.

The guy wire is attached to the tower at a height of approximately 15.95 meters.

Length of the guy wire (hypotenuse) = 18.5 m

Angle between the ground and the guy wire = 59º

Using the sine function to find the height of the tower.
sin(angle) = height/hypotenuse

Putting in the known values and solving for the height.
sin(59º) = height/18.5 m
height = sin(59º) × 18.5 m

Calculating the height
height ≈ 15.95 m

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The stereo system installer needs 170 ft of speaker wire.

In this case, the two diagonals of the rectangular room are the longest sides of two right triangles. The length of one diagonal can be found by:

d1 = √(40² + 75²)

d1 = √(1600 + 5625)

d1 = √7225

d1 = 85 ft

Similarly, the length of the other diagonal is also 85 ft.

Total speaker wire = 2 × 85 ft = 170 ft

So, the stereo system installer needs 170 ft of speaker wire.

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The area of the shaded region will be 8 square unit as per the given figure.

The rectangle has dimensions 2 x 4, so its area is:

Area of rectangle = length x width = 2 x 4 = 8 square units

The triangle has dimensions 4 x 8, so its area is:

Area of triangle = (1/2) x base x height = (1/2) x 4 x 8 = 16 square units

To find the area of the shaded region, we need to subtract the area of the triangle from the area of the rectangle.

Area of shaded region = Area of the triangle - Area of rectangle

Area of shaded region = 16-8

Area of shaded region = 8

The area of the shaded region will be 8 square units.

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Complete question:

The standard error of the survey's estimate for the mean is approximately 0.09 and the probability that the survey misses the true mean of 3.5 by more than 0.1 points is approximately 0.13 or 13%.

(a)The standard error of the survey's estimate for the mean is given by:

[tex]SE=\frac{I}{\sqrt{n} }[/tex]

In this case, σ = 1.4, n = 240, so:

[tex]SE= \frac{1.4}{\sqrt{240} } = 0.09[/tex]

Therefore, the standard error of the survey's estimate for the mean is approximately 0.09.

(b) To find the probability that the survey misses the true mean of 3.5 by more than 0.1 points, we need to find the probability that the absolute difference between the sample mean and the true mean is greater than 0.1:

Using a standard normal table or calculator, we can find that the probability of a standard normal random variable being greater than 0.1 / SE ≈ 1.11 is approximately 0.13.

Therefore, the probability that the survey misses the true mean of 3.5 by more than 0.1 points is approximately 0.13 or 13%.

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Answer:48 yd2

Step-by-step explanation:

The area of the yard that William would have to mow would be C. 112 yards ²

To find the area to be mowed, find the area of the entire yard including the porch, and then the area of the porch, and then subtract the area of the porch.

Area of yard :

= 12 x 12

= 144 yard ²

The area of the porch is:

= ( 12 - 8 ) x ( 12 - 4 )

= 4 x 8

= 32 yards ²

The area to be mowed is:

= 144 - 32

= 112 yards ²

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Answer:

The answer to your problem is, the range of the temperature data in degrees Fahrenheit is 15°F.

Step-by-step explanation:

In this scatter plot it represents the average daytime temperatures recorded in New York for a week.

highest temperature in a week from the scatter plot is 45°F.

lowest temperature in a week from the scatter plot is 30°F.

Range = 45°F - 30°F

= 15°F

Thus the answer to your problems is, the range of the temperature data in degrees Fahrenheit is 15°F.

Answer:a to b is 21 and b to c is 6 so I think you would need 21+6 divided by 2 i don't know for sure.

Step-by-step explanation: