need help finding the measurement of s

The issue of too many proficient business-savvy programmers is least likely to arise in machine learning(ml) and artificial intelligence(ai).

What is machine learning?

The process by which computers learn to recognize patterns, or the capacity to continuously learn from and make predictions based on data, then make adjustments without being specifically programmed to do so, is known as machine learning (ML), a subcategory of artificial intelligence.

The operation of machine learning is quite complicated and varies according to the task at hand and the algorithm employed to do it. However, at its foundation, a machine learning model is a computer that analyzes data to spot patterns before using those realizations to better fulfill the work that has been given to it. Machine learning can automate any task that depends on a set of data points or rules, even the more difficult ones.

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The smaller number is 28.

Answer:

Solution Given:

let the smaller number be a.

and larger number be a+4.

By question

a+(a+4)=60

a+a+4=60

2a=60-4

2a=56

a=[tex] \frac{56}{2} [/tex]

a=28

Answer:

y = 28

Step-by-step explanation:

Given variables:

Create two equations with the given information.

Equation 1

If one number is 4 more than another, then:

⇒ x = y + 4

(Remembering that x is the larger number and y is the smaller number).

Equation 2

If their sum is 60, then:

⇒ x + y = 60

Substitute Equation 1 into Equation 2 and solve for y:

⇒ (y + 4) + y = 60

⇒ 2y + 4 = 60

⇒ 2y + 4 -4 = 60 - 4

⇒ 2y ÷ 2 = 56 ÷ 2

⇒ y = 28

Therefore, the value of the smaller number (y) is 28.

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Answer:

HL

Step-by-step explanation:

The hypotenuses and the long legs of the right triangles are congruent, therefore using the rule HL, the triangles are congruent.

The remaining factor of x^2y - 2xy - 24y is (x - 6)(x + 4)

The expression is given as:

x^2y - 2xy - 24y

Factor out y from the expression

y(x^2 - 2x - 24)

Expand the equation

y(x^2 + 4x - 6x - 24)

Factorize

y(x - 6)(x + 4)

Hence, the remaining factor of x^2y - 2xy - 24y is (x - 6)(x + 4)

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Answer:

16b > 94

Step-by-step explanation:

16b > 94

b > 5.875

Crystal needs 6 boxes to fit all 94 discs.

Answer:

Let Ji and Bi represent the initial amounts that Joe and Bill have at the start.  Number after J and B will be used to indicate subsequent steps in the problem.

We are told that "Joe has five times as much money as Bill," which we can write as:

   1)  Ji = 5Bi

We learn that "Joe pays Bill $5," which we can represent as:

   2)  J1 = Ji - 5

This would mean that Bill has added $5:

   3)  B1 = Bi + 5

We are then told that "Joe has just twice the amount Bill now has," which we can write as:

   4)  J1 = 2B1

===

We can rearrnage and substitute the above relationships to eliminate one of the two variables (B1 or J1)

J1 = Ji - 5                [from 2]

2B1 = Ji - 5              [Substitute 4 to eliminate J1]

Ji = 5Bi                    [from 1]

2B1 = 5Bi - 5           [Substitute 1 to eliminate Ji]

B1 = Bi + 5               [Rearrange]

2(Bi + 5) = 5Bi - 5    [Use the above expression in the previous equation to eliminate B1]

2Bi + 10 = 5Bi - 5    [Simplify]

-3Bi = -15                  [Simplify]

Bi = $5                       [Solve]

Ji = 5Bi                    [from 1]

Ji = 5*(5)                  [Since Bi = $5]

Ji = $25                    [Solve]  

===

CHECK:

Does Joe has five times as much money as Bill?

Ji = $25 and Bi = $5  YES

When Joe pays Bill $5 he owes him, does Joe has just twice the amount Bill now has?

J1 = $25 - $5 = $20

B1 = $5 + $5  = $10    YES

By applying inverse of a matrix, we find that the solution of the system of linear equations is (x, y) = (5/7, - 2/7).

In linear algebra, systems of linear equations with a unique solution can be represented by the following expression:

[tex]\vec A \cdot \vec x = \vec B[/tex]      (1)

Where:

The solution of such systems is defined by:

[tex]\vec x = \vec A^{-1}\cdot \vec B[/tex]

[tex]\vec x = \frac{1}{\det(\vec A)}\cdot adj\left(\vec A\right) \cdot \vec B[/tex], where [tex]\det \left(\vec A\right) \ne 0[/tex].

Where:

For the case of [tex]\vec A \in \mathbb{R}_{2\times 2}[/tex], the inverse of [tex]\vec A[/tex] is:

[tex]\vec A^{-1} = \frac{1}{\det \left(\vec A\right)} \cdot \left[\begin{array}{cc}a_{22}&-a_{12}\\-a_{21}&a_{11}\end{array}\right][/tex]     (2)

If we know that [tex]\vec A = \left[\begin{array}{cc}3&4\\5&2\end{array}\right][/tex] and [tex]\vec B = \left[\begin{array}{cc}1\\3\end{array}\right][/tex], then the solution of the system of linear equations is:

[tex]\vec A^{-1}= \frac{1}{(3)\cdot (2) - (5) \cdot (4)}\cdot \left[\begin{array}{cc}2&-4\\-5&3\end{array}\right][/tex]

[tex]\vec A^{-1} = -\frac{1}{14}\cdot \left[\begin{array}{cc}2&-4\\-5&3\end{array}\right][/tex]

[tex]\vec A^{-1} = \left[\begin{array}{cc}-\frac{1}{7} &\frac{2}{7} \\\frac{5}{14} &-\frac{3}{14} \end{array}\right][/tex]

[tex]\vec x = \left[\begin{array}{cc}-\frac{1}{7} &\frac{2}{7} \\\frac{5}{14} &-\frac{3}{14} \end{array}\right] \cdot \left[\begin{array}{cc}1\\3\end{array}\right][/tex]

[tex]\vec x = \left[\begin{array}{cc}\frac{5}{7} \\-\frac{2}{7} \end{array}\right][/tex]

By applying inverse of a matrix, we find that the solution of the system of linear equations is (x, y) = (5/7, - 2/7).

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The points that are possible approximations for this system are; (2.2, -1.4) and (2.2, -1.35)

We are given the equations of the linear graphs as;

y = ⁷/₄x + ⁵/₂

y = ³/₄x - 3

Notice that the lines intersect each other and by definition, if the lines of the system of equations intersect, then the system has one solution. This means that the point of intersection of the lines is the solution of the system. It can be written as:

(x, y)

x is the x-coordinate .

y is the y-coordinate.

In this case, we can identify that:

- the x-coordinate of the point of intersection is between; x = 2 and x = 3

- The y-coordinate of the point of intersection is between y = -1 and y = -2

Based on the above, we can conclude that the points that are possible approximations for this system are; (2.2, -1.4) and (2.2, -1.35)

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Answer: B and C) 2.2, -1.4 and 2.2, -1.35

Step-by-step explanation:

Hope this helps!

Mark me brainliest!

Pls and Ty!

Answer:

312,847,415

Step-by-step explanation:

1. Define the given values:

2. Now interpret what other information the question gives:

3. upscale the ratio:

therefore, the total population in Texas = 312,847,415

Hope this helps :)

The number of complete packages the store have for sale is  x / 12

The donuts sells packages of 12 donuts. This means the each package has 12 donuts.

The store has made x donuts. This means the store made x number of donut. The donuts are not in packages.

Therefore, the number of complete packages the store have for sale is as follows:

12 donuts = 1 package

x donuts = ?

cross multiply

number of packages for sale = x / 12

Therefore, the number of complete packages the store have for sale is  x / 12

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Answer:Triangle A = 7.5 Triangle B= 15 Area=22.5

Step-by-step explanation:

So first we have to get the area of Triangle A. This means we have to find the height and base of it. The base is 5 and the height is 3 as you can see in the picture. So 5x3 equals 15, but because it's a triangle we have to divide by 1/2, which makes 7.5. So the area for Triangle A is 7.5.

Now we have to find the area for Triangle B. The height is 3 and the base is 10. So like we did with Triangle A we have to multiply and then divide by 1/2. Which makes 15.

Now that you have both areas you just have to add them together. Which makes 22.5.

So 22.5 is the answer. Give brainilest if you can!

The value of the missing length in the image shown using the Pythagoras theorem is x = 1500

An equation is an expression that shows the relationship between two or more variables and numbers.

Let h represent the missing red line. Using Pythagoras:

x² = h² + 900²

h² = x² - 900²

Also:

r² = h² + 1600²

r² = x² - 900² + 1600²

And:

(1600 + 900)² = r² + x²

(1600 + 900)² = (x² - 900² + 1600²) + x²

x = 1500

The value of the missing length in the image shown using the Pythagoras theorem is x = 1500

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The total area of the composite figure is 176 ft

The area of a composite figure can be found as follows;

Therefore,

Total area = area of rectangle + area of triangle

area of rectangle = lw

where

Therefore,

area of a rectangle = 16 × 8

area of a rectangle = 128 ft²

area of triangle = 1 / 2 bh

where

Therefore,

area of triangle = 1 / 2 × 12 × 8

area of triangle = 48 ft²

Total area of the composite figure = 48 + 128 = 176 ft

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Answer:

x = 3

Step-by-step explanation:

4x + 3 = 2x + 9
1. Remove 3 from both sides
4x = 2x + 6
2. Remove 2x from both sides
2x = 6
3. x = 3

Answer:

here is the answer

hope it helps u

stay safe and healthy

{ BTS ARMY GIRL }

Rashmi

Answer:

Step-by-step explanation: all oof it equals to = 2c c2 = b1

Answer:

When the data are nominal or ordinal.

Step-by-step explanation:

Spearman's correlation

Spearman's correlation measures the strength and direction of monotonic association between two variables.

Monotonicity is "less restrictive" than that of a linear relationship.

For example, the middle image above shows a relationship that is monotonic, but not linear.

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The data exists nominal or ordinal. Spearman's correlation estimates the strength and direction of the monotonic relationship between two variables.

a) Pearson correlation

b) Kendall rank correlation

c) Spearman correlation

d) Point-Biserial correlation.

The data exists nominal or ordinal. Spearman's correlation estimates the strength and direction of the monotonic relationship between two variables.

Monotonicity exists as "less restrictive" than that of a linear relationship.

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The factors illustrate they the sides of the rectangles are:

The first equation given is x² - 3x + 2.

= x² - 3x + 2.

= x² - x - 2x + 2

= x(x - 1) - 2(x - 1)

= (x - 1)(x - 2)

Therefore, the side lengths are (x - 1) and (x - 2).

In the rectangular figure, the length and width should be the expressions above.

The second equation given is 2x² + x - 6.

= 2x² + x - 6.

= 2x² + 4x - 3x - 6

= 2x(x + 2) - 3(x + 2)

= (2x - 3)(x + 2)

Therefore, the side lengths are (2x - 3) and (x + 2).

In the rectangular figure, the length and width should be the expressions above.

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This might help a bit, i hope

Answer:

D

Step-by-step explanation:

Your equation would be 2x^2-3=y

This means that it should touch the y axis at -3, but since there is an exponent, it should be a parabola, not a straight line. Hence the answer is D

Answer: If your opponent is winning 3:1 then they are probably better then you if they are winning more then you are. (or you are just having a bad day)

Posterior probability of scenario A: P(A|data) ≈ (0.0625 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.134

Posterior probability of scenario B: P(B|data) ≈ (0.216 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.466

Posterior probability of scenario C: P(C|data) ≈ (0.05184 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.400

Let's denote the three possibilities as follows:

A: Equally talented, each player has a 0.5 probability of winning a game.

B: You are slightly better, with a 0.6 probability of winning a game.

C: Your opponent is slightly better, with a 0.6 probability of winning a game.

Given that you won the second game but lost the first, third, and fourth games, we want to find the probability of scenario C given this outcome. Let P(C) represent the prior probability of scenario C being true.

According to the given information, each of the three scenarios (A, B, and C) is equally likely, so P(A) = P(B) = P(C) = 1/3.

Now, let's update the probabilities based on the outcome of the match:

In scenario A:

The probability of winning the second game is 0.5, and the probability of losing the first, third, and fourth games is 0.5 each. Therefore, the overall probability of the observed outcome in scenario A is (0.5 * 0.5 * 0.5 * 0.5) = 0.0625.

In scenario B:

The probability of winning all three games (assuming you are slightly better) is (0.6 * 0.6 * 0.6) = 0.216.

In scenario C:

The probability of winning the second game (assuming your opponent is slightly better) is 0.4, and the probability of losing the first, third, and fourth games is 0.6 each. Therefore, the overall probability of the observed outcome in scenario C is (0.4 * 0.6 * 0.6 * 0.6) = 0.05184.

Now, we can update the probabilities based on Bayes' theorem:

Posterior probability of scenario A: P(A|data) = (P(data|A) * P(A)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))

Posterior probability of scenario B: P(B|data) = (P(data|B) * P(B)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))

Posterior probability of scenario C: P(C|data) = (P(data|C) * P(C)) / (P(data|A) * P(A) + P(data|B) * P(B) + P(data|C) * P(C))

P(data|A) = 0.0625

P(data|B) = 0.216

P(data|C) = 0.05184

Plugging in the values, we get:

Posterior probability of scenario A: P(A|data) ≈ (0.0625 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.134

Posterior probability of scenario B: P(B|data) ≈ (0.216 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.466

Posterior probability of scenario C: P(C|data) ≈ (0.05184 * 1/3) / (0.0625 * 1/3 + 0.216 * 1/3 + 0.05184 * 1/3) ≈ 0.400

So, after the match, the posterior probability that your opponent is slightly better than you is approximately 0.400 or 40%.

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The difference between the mean times is about 2 times the absolute deviation of the data sets.

Given that the difference of the means is found.

The difference in the means is basically the absolute difference between the mean of two groups. It explains the mean of two groups. It explains how much difference that exists between the average between two groups.Calculating mean difference is significant during clinical trials where we have the experimental group and the control group. The mean absolute deviations is basically the variation of each data value from the mean. It tells us how much the values in a set of data differ from the mean value. It explains the reach of values in a data set. There is a relationship that exists between the difference of the mean absolute deviations.

Hence the difference between the mean times is about 2 times the absolute deviation of the data sets.

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Answer:

Angle symbol

Angle ACB

Angle ACE

Angle DCE

Step-by-step explanation:

step 1: how many dolphins

there are 6 sharks

sharks to dolphins is 3 to 5

3 S to 5 D

we can divide 6 (amount of sharks known) by 3, to get what a ratio of 1 is

6 ÷ 3 = 2

so 2 sharks is = 1 part or ratio

now we can times by 5 to get a ratio of 5

5 × 2 = 10

there are 10 Dolphins

Step 2: How many starfish

repeat the steps above but for the ratio 2: 7 where 2 is the Dolfin ratio and there are 10 dolphins

put in questions answer you got

Answer:

35 starfish

Step-by-step explanation:

shark/dolphin  *  dolphin /starfish = shark / starfish

Now. put in the numbers given:

3/5 * 2/7 =      6/35  = shark / starfish    put in '6' for shark (given)

        6/35 = 6/starfish        cross multiply

        6 * starfish = 35* 6

           starfish = 35  

The stock's current price  is  53.413455.

What is CAPM ?

The capital asset pricing model (CAPM) to know the value of the stock

[tex]Ke = rf + \beta ( r_{m} - r_{f} )[/tex]

risk free = 0.085

premium market =(market rate - risk free) = 0.045

beta(non diversifiable risk) 1.3

Ke = 0.085 + 1.3(0.045)

Ke = 0.14350

Now we need to know the present value of the future dividends:

D0 = 2.8

D1 = D0 × ( 1 +g ) = 2.8  = 2.8 * 1.23 = 3.444

D2 3.444 x 1.23 = 4.2361200

The next dividends, which are at perpetuity will we solve using the dividned grow model

[tex]\frac{divends}{return - growth} = Intrinsic value[/tex]

In this case dividends will be:

4.23612 x 1.07 = 4.5326484

return will be how return given by CAPM and g = 7%

plug this into the Dividend grow model.

[tex]\frac{4.5326484}{0.1435 - 0.07} = Intrinsic value[/tex]

value of the dividends at perpetity: 61.6686857

Finally is important to note this values are calculate in their current year. We must bring them to present day using the present value of a lump sum:

[tex]\frac{principal}{(1 + rate)^{time} } = PV[/tex]

[tex]\frac{3.444}{(1 + 1. 1435)^{1} } =PV[/tex]

3.011805859

[tex]\frac{4.23612}{( 1 + 0.1435)^{2} } = PV[/tex]

3.239633762

[tex]\frac{61.6686857}{(1 + 0.1435)^{2} } = PV[/tex]

47.16201531

We add them and get the value of the stock  is 53.413455.

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The approximate solution to the given system of equation is (-2.71, 2.14)

From the question, we are to determine the approximate solution to the given system of linear equations.

The given equations are

y = 0.5x + 3.5

y = -2/3 x+ 1/3

From the given information, we are to show the solutions on a graph

The graph that shows the solution to the given system of equation is shown below.

The solution to the given system is the point of intersection of the lines. The coordinate of the point of intersection of the lines is (-2.71, 2.14). That is, x = -2.71, y = 2.14.

Hence, the approximate solution to the given system of equation is (-2.71, 2.14)

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Answer:

Sum of 374 and 25 = 374+25 = 399

now subtract 9 from the sum, i.e. 399 = 399 - 9 = 390 is your answer

Answer:

Step-by-step explanation:

374+25

=399

Now, subtracting the sum from 9

9-399

=   -390

Answer:

Step-by-step explanation:

if x= -2, f(x)= -8

x= -1, y= -1

x=0, y=0

The equation of a line that exists perpendicular to line g contains (P, Q) exists x + 4y = 4Q + P.

Given: Coordinate plane with line g that passes through the points (-2,6) and (-3,2).

The coordinate of G: (-2,6) and (-3,2)

Let, [tex]$&\left(x_{1}, y_{1}\right)=(-2,6) \\[/tex] and [tex]$&\left(x_{2}, y_{2}\right)=(-3,2)[/tex]

The slope of a line [tex]$\mathbf{g}$[/tex] :

[tex]$m &=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\[/tex]

[tex]$m &=\frac{2-6}{-3-(-2)} \\[/tex]

[tex]$m &=\frac{-4}{-1} \\[/tex]

m = 4

So, the slope of a line g exists 4.

To find the slope of a line perpendicular to g,

[tex]$&m_{1}=-\frac{1}{m} \\[/tex]

[tex]$&m_{1}=-\frac{1}{4}[/tex]

The equation of the slope point form of the line exists

[tex]$\left(y-y_{1}\right)=m\left(x-x_{1}\right)$[/tex]

[tex]$y-Q=-\frac{1}{4}(x-P)$[/tex]

[tex]$4 y-4 Q=-x+P$[/tex]

[tex]$x+4 y=4 Q+P$[/tex]

Therefore, the equation of a line that exists perpendicular to line g contains (P, Q) exists x + 4y = 4Q + P.

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The system that can help to model this are

We have the following equation. Remember that a good understanding of the question is what would help us to write the equation

The condition says:

The square of first number is equal to the sum of the second number and 16:

First number = x. Square of x = x²

second number = y + 16

For the second

The difference of 4 times the second number and 1 is equal to the first number multiplied by 7:

second number is y

4*y - 1= x*7

= 4y - 1 = 7x

Hence we would have the following as our equations

x² = y + 16

4y - 1 = 7x

The solution to the equation when graphed = 5, 9

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