Answer:
the answer of r is 8 i hope it will help
Find the volume (in cubic inches) of an exercise ball with a radius of 14 inches. (Round your answer to one decimal place.)
Answer:
11,494.0³
Step-by-step explanation:
Volume of a sphere= (4/3) × pi × radius³
4÷3 × 3.14 ×14³
= 11,494.0³
Help!! Picture included
Answer:
The answer is the last option- the fourth root of 16x^4.
Step-by-step explanation:
(16x^4)^(1/4) = 2*abs(x).
Whenever you are dealing with a square root of a variable, if you have an even root and get out an odd power, you're going to need to always include an absolute value.
Precision manufacturing: A process manufactures ball bearings with diameters that are normally distributed with mean 25.0 millimeters and standard deviation 0.07 millimeter. Round the answers to at least four decimal places. (a) Find the 60th percentile of the diameters. (b) Find the 67th percentile of the diameters. (c) A hole is to be designed so that 2% of the ball bearings will fit through it. The bearings that fit through the hole will be melted down and remade. What should the diameter of the hole be
Answer:
a) The 60th percentile of the diameters is of 25.0177 millimeters.
b) The 67th percentile of the diameters is of 25.0308 millimeters.
c) The diameter of the hole should be of 24.8562 millimeters.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with mean 25.0 millimeters and standard deviation 0.07 millimeter.
This means that [tex]\mu = 25, \sigma = 0.07[/tex]
(a) Find the 60th percentile of the diameters.
This is X when Z has a p-value of 0.6, so X when Z = 0.253.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]0.253 = \frac{X - 25}{0.07}[/tex]
[tex]X - 25 = 0.253*0.07[/tex]
[tex]X = 25.0177[/tex]
The 60th percentile of the diameters is of 25.0177 millimeters.
(b) Find the 67th percentile of the diameters.
This is X when Z has a p-value of 0.67, so X when Z = 0.44.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]0.44 = \frac{X - 25}{0.07}[/tex]
[tex]X - 25 = 0.44*0.07[/tex]
[tex]X = 25.0308[/tex]
The 67th percentile of the diameters is of 25.0308 millimeters.
(c) A hole is to be designed so that 2% of the ball bearings will fit through it. The bearings that fit through the hole will be melted down and remade. What should the diameter of the hole be.
This is the 2nd percentile, which is X when Z has a p-value of 0.08, so X when Z = -2.054.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-2.054 = \frac{X - 25}{0.07}[/tex]
[tex]X - 25 = -2.054*0.07[/tex]
[tex]X = 24.8562[/tex]
The diameter of the hole should be of 24.8562 millimeters.
Which inequality is true? Use the number line to help.
-2.5 -2 -1.5 -1
-0.5 0
0.5
1
1.5
2
2.5
0 -1.5 0.5
0 -0.50
O-1.5 <-0.5
o 2205
Answer:
C. -1.5 < -0.5
Step-by-step explanation:
On a number line, the farther a number is to the right away from 0, the greater the number. While the farther it is from 0 to the left, the smaller it is.
Thus, the out of the options given, the only inequality given that is true is:
-1.5 < -0.5
This is because, -1.5 on the numberline is farther away to the left from 0 than -0.5. therefore, -1.5 is lesser than -0.5.
The hypotenuse of a 45°, 45°, and 90° triangle is 26 sqrt(2) inches. What is the length of each of the other sides?
(A)13 sqrt(2) inches
(B)13 inches
(C)13 sqrt(3) inches
(D)26 inches
remember the pythagorean theorem:
a² + b² = c²
where c is the hypotenuse.
so:
[tex] {a}^{2} + {b}^{2} = { ( \sqrt{26)}}^{2} [/tex]
the square and the square root cancel each other out, so...
a² + b² = 26
we know that a and b are of equal length given the angles.
so it's
[tex] { \sqrt{13} }^{2} + { \sqrt{13} }^{2} = 26[/tex]
here the squares and square roots also cancel, but to keep the equation from the formula true we need to write them. that makes the difference between optional and B
Option A is correct,
[tex] \sqrt{13} inches[/tex]
1-0.4^n>=0.99 howwwwwwwwwwwwwwwwwwwwwwwwww
Answer:
n>=6
Step-by-step explanation:
1-0.4ⁿ>=0.99
1-0.99>=0.4ⁿ
0.4ⁿ<=0.01
Apply log10:
Log10(0.4ⁿ)<=log10(0.01)
n×log10(0.4)<=log10(0.01)=-2
Because log10(0.4)=-0.39794 is negative we get:
n>=5.028.
Since n is integer, we have n>=6
Amy has 2$, Jack has 3 times as much as Amy. Catherine has twice as much as Jack. How much does Catherine have?
Answer: 12 dollars
Step-by-step explanation:
2x3x2=12
Easy math
A university found that 25% of its students withdraw without completing the introductory statistics course. Assume that 30 students registered for the course.Use Microsoft Excel whenever necessary and answer the following questions:Compute the probability that 2 or fewer will withdraw
Answer:
0.0106 = 1.06% probability that 2 or fewer will withdraw
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they withdraw, or they do not. The probability of an student withdrawing is independent of any other student, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
25% of its students withdraw without completing the introductory statistics course.
This means that [tex]p = 0.25[/tex]
Assume that 30 students registered for the course.
This means that [tex]n = 30[/tex]
Compute the probability that 2 or fewer will withdraw:
This is:
[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{30,0}.(0.25)^{0}.(0.75)^{30} = 0.0002[/tex]
[tex]P(X = 1) = C_{30,1}.(0.25)^{1}.(0.75)^{29} = 0.0018[/tex]
[tex]P(X = 2) = C_{30,2}.(0.25)^{2}.(0.75)^{28} = 0.0086[/tex]
[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0002 + 0.0018 + 0.0086 = 0.0106[/tex]
0.0106 = 1.06% probability that 2 or fewer will withdraw
3x+4 number of terms
9514 1404 393
Answer:
2
Step-by-step explanation:
In this expression, the terms are the parts of the sum. They are 3x and 4. There are 2 terms.
Find the area of the irregular figure. Round to the nearest hundredth.
Answer:
[tex]67.5\text{ [square units]}[/tex]
Step-by-step explanation:
The composite figure consists of one rectangle and two triangles. We can add up the area of these individual shapes to find the total area of the irregular figure.
Formulas:
Area of rectangle with base [tex]b[/tex] and height [tex]h[/tex]: [tex]A=bh[/tex] Area of triangle with base [tex]b[/tex] and height [tex]h[/tex]: [tex]A=\frac{1}{2}bh[/tex]By definition, the base and height must intersect at a 90 degree angle.
The rectangle has a base of 10 and a height of 5. Therefore, its area is [tex]A=10\cdot 5=50[/tex].
The smaller triangle to the left of the rectangle has a base of 2 and a height of 5. Therefore, its area is [tex]A=\frac{1}{2}\cdot 2\cdot 5=5[/tex].
Finally, the larger triangle on top of the rectangle has a base of 5 and a height of 5. Therefore, its area is [tex]A=\frac{1}{2}\cdot 5\cdot 5=12.5[/tex].
Thus, the area of the total irregular figure is:
[tex]50+5+12.5=\boxed{67.5\text{ [square units]}}[/tex]
solve the system of equations using substitution or graphing.
Step-by-step explanation:
I think substitution would be the easiest since you already have one of the variables solved for.
[tex]y=-x^2+4x+5\\y=x+1\\x+1=-x^2+4x+5\\x^2-3x-4=0\\(x-4)(x+1)=0\\x-4=0\\x=4\\x+1=0\\x=-1[/tex]
(You can just set the equations equal to each other since they both equal y).
Now, to get the points, plug in x = 4 and x = -1 into one of the equations (I'm going to plug them into y = x+1 because that one is much simpler)
[tex]y(4)=4+1\\y(4)=5\\y(-1)=-1+1\\y(-1)=0[/tex]
So, your final points are:
(4,5) and (-1,0)
Answer: A
Step-by-step explanation:
We can use substitution to solve this problem. Since we are given y=-x²+4x+5 and y=x+1, we can set them equal to each other.
-x²+4x+5=x+1 [subtract both sides by x]
-x²+3x+5=1 [subtract both sides by 1]
-x²+3x+4=0
Now that we have the equation above, we can factor it to find the roots.
-x²+3x+4=0 [factor out -1]
-1(x²-3x-4)=0 [factor x²-3x-4]
-1(x+1)(x-4)=0
This tells us that x=-1 and x=4.
We can narrow down our answer to A, but let's plug in those values to be sure it is correct.
-(-1)²+4(-1)+5=(-1)+1 [exponent]
-1+4(-1)+5=-1+1 [multiply]
-1-4+5=-1+1 [add and subtract from left to right]
0=0
-------------------------------------------------------------------------------------------
-(4)²+4(4)+5=(4)+1 [exponent]
-16+4(4)+5=4+1 [multiply]
-16+16+5=4+1 [add and subtract from left to right]
5=5
Therefore, we can conclude that A is the correct answer.
Someone please help thanks
Answer:
By similar triangles: BE/20 = 18/25 BE 14.4
Also, (ED + 26) / 26 = 18/14.4
ED = 6.5 and AD = 32.5
Ask a question about your assignment
Answer:
Which video in YT has most number of views
Step-by-step explanation:
Which would result in a lower price to first discount an item by 10% and then by a further 15%, OR to first discount an item by 15% and then by a further 10%. Justify your reasoning.
Answer:
Neither one. They will both result in the same price.
Step-by-step explanation:
To discount an item 10%, you charge 90% of the price of the item. To find 90% of a price, you multiply the price by 0.9.
To discount an item 15%, you charge 85% of the price of the item. To find 85% of a price, you multiply the price by 0.85.
Since multiplication is commutative, multiplying a number by 0.9 and then by 0.85 is the same as multiplying the number by 0.85 first and then by 0.9.
Let's say the item costs x.
Take off the 10% discount first: 0.9x
Now take off the 15% discount: 0.85 * (0.9x)
Now do it the other way.
Take off the 15% discount first: 0.85x
Now take off the 10% discount: 0.9 * (0.85x)
Since 0.85 * 0.9 * x = 0.9 * 0.85 * x, the results are the same.
Answer: neither
Which equation can be simplified to find the inverse of
Answer:
x=y²-7hope it helps.
stay safe healthy and happy...In the following diagram HI || JK.
HELP MATES PLEASE WILL GIVE 15 POINTS
What is the measure of Zx?
Angles are not necessarily drawn to scale.
67°
H
K
46°
2°
I
A
Answer:
m∠ x = 67
Step-by-step explanation:
∠AJK = ∠AHI = 67 Corresponding Angles
180 - 67 - 46 = x
x = 67
Triangle Sum Theory - the sum of all angles in a triangle = 180
Also, when you see parallel lines look for Corresponding,
Alternate Interior or Same side Interiors.
The table gives estimates of the world population, in millions, from 1750 to 2000. (Round your answers to the nearest million.)
Year Population
1750 790
1800 980
1850 1260
1900 1650
1950 2560
2000 6080
(a) Use the exponential model and the population figures for 1750 and 1800 to predict the world population in 1900 and 1950 1900 1950 million people million people
(b) Use the exponential model and the population figures for 1800 and 1850 to predict the world population in 1950 million people
(c) Use the exponential model and the population figures for 1900 and 1950 to predict the world population in 2000 million people
Answer:
A.) 1508 ; 1870
B.) 2083
C.) 3972
Step-by-step explanation:
General form of an exponential model :
A = A0e^rt
A0 = initial population
A = final population
r = growth rate ; t = time
1)
Using the year 1750 and 1800
Time, t = 1800 - 1750 = 50 years
Initial population = 790
Final population = 980
Let's obtain the growth rate :
980 = 790e^50r
980/790 = e^50r
Take the In of both sides
In(980/790) = 50r
0.2155196 = 50r
r = 0.2155196/50
r = 0.0043103
Using this rate, let predict the population in 1900
t = 1900 - 1750 = 150 years
A = 790e^150*0.0043103
A = 790e^0.6465588
A = 1508.0788 ; 1508 million people
In 1950;
t = 1950 - 1750 = 200
A = 790e^200*0.0043103
A = 790e^0.86206
A = 1870.7467 ; 1870 million people
2.)
Exponential model. For 1800 and 1850
Initial, 1800 = 980
Final, 1850 = 1260
t = 1850 - 1800 = 50
Using the exponential format ; we can obtain the rate :
1260 = 980e^50r
1260/980 = e^50r
Take the In of both sides
In(1260/980) = 50r
0.2513144 = 50r
r = 0.2513144/50
r = 0.0050262
Using the model ; The predicted population in 1950;
In 1950;
t = 1950 - 1800 = 150
A = 980e^150*0.0050262
A = 980e^0.7539432
A = 2082.8571 ; 2083 million people
3.)
1900 1650
1950 2560
t = 1900 - 1950 = 50
Using the exponential format ; we can obtain the rate :
2560 = 1650e^50r
2560/1650 = e^50r
Take the In of both sides
In(2560/1650) = 50r
0.4392319 = 50r
r = 0.4392319/50
r = 0.0087846
Using the model ; The predicted population in 2000;
In 2000;
t = 2000 - 1900 = 100
A = 1650e^100*0.0087846
A = 1650e^0.8784639
A = 3971.8787 ; 3972 million people
find the measures of m and n.
Answer:
m = 4
n = 5
Step-by-step explanation:
[tex]m + 8 = 3m\\\\m - 3m = - 8\\\\-2m = - 8\\\\m = 4[/tex]
[tex]2n - 1 = 9 \\\\2n = 9 + 1\\\\2n = 10\\\\n = 5[/tex]
Approximately 5% of workers in the US use public transportation to get to work. You randomly select 25 workers and ask if they use public transportation to get to work. Find the probability that exactly 2 workers say yes.
Answer:
0.2305 = 23.05% probability that exactly 2 workers say yes.
Step-by-step explanation:
For each worker, there are only two possible outcomes. Either they say yes, or they say no. The probability of a worker saying yes is independent of any other worker, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
5% of workers in the US use public transportation to get to work.
This means that [tex]p = 0.05[/tex]
You randomly select 25 workers
This means that [tex]n = 25[/tex]
Find the probability that exactly 2 workers say yes.
This is P(X = 2). So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 2) = C_{25,2}.(0.05)^{2}.(0.95)^{23} = 0.2305[/tex]
0.2305 = 23.05% probability that exactly 2 workers say yes.
In a test of a heat-seeking rocket, a first rocket is launched at 2000 fts and the heat-seeking rocket is launched along the same flight path 20 s later at a speed of 3000 fts. Find
the timest, and t, of flight of the rockets until the heat-seeking rocket destroys the first rocket
What are the times of the flight?
Answer:
Time of flight of first rocket = 60 seconds
Time of flight of second rocket = 40 seconds
Step-by-step explanation:
Let the time of flight of first rocket be t1.
Since the second rocket is launched 20 seconds later, then it means that;
t1 = t2 + 20
Where t2 is the time of flight of the second rocket.
When destruction has occurred, it means that both of the rockets would have covered the same distance.
We know that;
Distance = speed × time
Thus;
2000t1 = 3000t2
We know that t1 = t2 + 20
Thus;
2000(t2 + 20) = 3000t2
2000t2 + 40000 = 3000t2
3000t2 - 2000t2 = 40000
1000t2 = 40000
t2 = 40000/1000
t2 = 40 seconds
Thus;
t1 = 40 + 20
t1 = 60 seconds
Which equation represents a line which is parallel to the line y = -7x - 8?
7x + y = -3
x+ 7y = 7
y - 7x = 6
x- -7y = -28
Answer:
7x+y=-3
Step-by-step explanation:
if m is the slope of a line, then the slope of its parallel line will have the same slope m,
in the given equation, y=-7x-8, the slope is -7
among the options, 1st option has a slope of -7, since,
7x+y=-3
or, y=-7x-3
Answered by GAUTHMATH
Why does it help to rearrange
addends in Example B to show that
2.5n +9.9+(-3n) is equal to
2.5n + (-3n) + 9.9?
Answer:
You don't really need to do it, but it helps you keep things more organized and easier to follow. Imagine if you're doing some multi-variable equation,
2a + 5b + 4d + 3c + b + a + 2d
that looks like a mess, it'll be easier to look at if you put all the similar variables next to each others like this:
a + 2a + b + 5b + 3c + 2d + 4d
(a + 2a) + (b + 5b) + 3c + (2d + 4d)
now you can add them up much easier.
2/3 - 10/9and5/3 and 7/9
Step-by-step explanation:
always Pythagoras with the coordinate differences as sides and the distance the Hypotenuse.
c² = (2/3 - 5/3)² + (-10/9 - -7/9)² = (-3/3)² + (-10/9 + 7/9)² =
= (-1)² + (-3/9)² = 1 + (-1/3)² = 1 + 1/9 = 10/9
c = sqrt(10)/3
Answer:
Step-by-step explanation:
Point 1 ([tex]\frac{2}{3}[/tex] , [tex]\frac{-10}{9}[/tex]) in the form (x1,y1)
Point 2 ( [tex]\frac{5}{3}[/tex] , [tex]\frac{-7}{9}[/tex]) in the form (x2,y2)
use the distance formula
dist = sqrt[ (x2-x1)^2 + (y2-y1)^2 ]
dist = sqrt [ [tex]\frac{5}{3}[/tex] -[tex]\frac{2}{3}[/tex])^2 + ( [tex]\frac{-7}{9}[/tex] - ( [tex]\frac{-10}{9}[/tex] ) )^2 ]
dist = sqrt [ ([tex]\frac{3}{3}[/tex])^2 + ([tex]\frac{3}{9}[/tex])^2 ]
dist = sqrt [ 1 + ([tex]\frac{1}{3}[/tex])^2 ]
dist = sqrt [ [tex]\frac{9}{9}[/tex] + [tex]\frac{1}{9}[/tex] ]
dist = [tex]\sqrt{\frac{10}{9} }[/tex]
dist = [tex]\sqrt{10}[/tex] *[tex]\sqrt{\frac{1}{9} }[/tex]
dist = [tex]\sqrt{10}[/tex] * [tex]\frac{1}{3}[/tex]
dist = [tex]\frac{\sqrt{10} }{3}[/tex]
Learning Task No. 1 Randy, Manny and Jan put 3 As, 4 Bs and 5 Cs in the box. They will take turns in getting a letter from the box. They are trying to test the probability of getting their favourite letter.
Randy - A
Manny-B
Jan-C
1. What is the probability of getting each boy's favourite letter? a. Randy b. Manny c. Jan
2. If you are next to Jan to pick up a letter and your favourite letter is A , What is the probability of getting your favourite letter?
3. Who is most unlikely to get his favourite letter.
Answer:
1. A = 3/12
B= 4/12
C = 5/12
2......
3. Randy
Step-by-step explanation:
3+4+5 = 12
therefore there are 12 letters in the box
we can say that there are 3/12 A's in the box and do the same for the remaining letters
question two does not make sense
3. the person who has the lowest fraction in value which is A
A researcher believes that 9% of males smoke cigarettes. If the researcher is correct, what is the probability that the proportion of smokers in a sample of 664 males would differ from the population proportion by greater than 3%
Answer:
0.0070 = 0.70% probability that the proportion of smokers in a sample of 664 males would differ from the population proportion by greater than 3%
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
A researcher believes that 9% of males smoke cigarettes.
This means that [tex]p = 0.09[/tex]
Sample of 664
This means that [tex]n = 664[/tex]
Mean and standard deviation:
[tex]\mu = p = 0.09[/tex]
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.09*0.91}{664}} = 0.011[/tex]
What is the probability that the proportion of smokers in a sample of 664 males would differ from the population proportion by greater than 3%?
Proportion below 9 - 3 = 6% or above 9 + 3 = 12%. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.
Probability the proportion is below 6%
P-value of Z when X = 0.06. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.06 - 0.09}{0.011}[/tex]
[tex]Z = -2.7[/tex]
[tex]Z = -2.7[/tex] has a p-value of 0.0035
2*0.0035 = 0.0070
0.0070 = 0.70% probability that the proportion of smokers in a sample of 664 males would differ from the population proportion by greater than 3%
The following data includes the year, make, model, mileage (in thousands of miles) and asking price (in US dollars) for each of 13 used Honda Odyssey minivans. The data was collected from the Web site.
year make model mileage price
2004 Honda Odyssey EXL 20 26900
2004 Honda Odyssey EX 21 23000
2002 Honda Odyssey 33 17500
2002 Honda Odyssey 41 18999
2001 Honda Odyssey EX 43 17200
2001 Honda Odyssey EX 67 18995
2000 Honda Odyssey LX 46 13900
Required:
Compute the correlation between age (in years) and price for these minivans.
Find complete data below :
Answer:
R = - 0.94
Step-by-step explanation:
Since data was collected in 2005 ; we subtract the data collection year from the make year to obtain the age :
Age (x) :
1,1, 3,3,4,4,5,5,5,5,6,7,10
Price (y) :
26900,23000,17500,18999,17200,18995,13900,15250,13200,11000,13900,8350,5800
Using technology, the correlation Coefficient between age of car and price is : - 0.94
With a correlation Coefficient of - 0.94, we can conclude that there exists a strong negative correlation between age and price of the Odyssey mini vans. This could be interpreted to mean that ; As the age of cars in increases, the price decreases
To find the quotient of 8 divided by one-third, multiply 8 by
O One-eighth
O One-third
O 3
O 8
Answer:
3
Step-by-step explanation:
Skip,Flip,Multiply Method
[tex] \frac{8}{ \frac{1}{3} } = \frac{8}{1} \times 3 = 24[/tex]
Answer:
3
Step-by-step explanation:
SCALCET8 3.9.015. A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along a straight path. How fast is the tip of his shadow moving when he is 35 ft from the pole
Answer:
[tex]X=6.67ft/s[/tex]
Step-by-step explanation:
From the question we are told that:
Height of pole [tex]H_p=15[/tex]
Height of man [tex]h_m=6ft[/tex]
Speed of Man [tex]\triangle a =4ft/s[/tex]
Distance from pole [tex]d=35ft[/tex]
Let
Distance from pole to man=a
Distance from man to shadow =b
Therefore
[tex]\frac{a+b}{15}=\frac{b}{6}[/tex]
[tex]6a+6b=15y[/tex]
[tex]2a=3b[/tex]
Generally the equation for change in velocity is mathematically given by
[tex]2(\triangle a)=3(\triangle b )[/tex]
[tex]2*4=3(\triangle b)[/tex]
[tex]\triangle a=\frac{8}{3}[/tex]
Since
The speed of the shadow is given as
[tex]X=\triangle b+\triangle a[/tex]
[tex]X=4+8/3[/tex]
[tex]X=6.67ft/s[/tex]
SCALCET8 3.10.025. Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 126
Answer:
[tex]f(126) \approx 5.01333[/tex]
Step-by-step explanation:
Given
[tex]\sqrt[3]{126}[/tex]
Required
Solve using differentials
In differentiation:
[tex]f(x+\triangle x) \approx f(x) + \triangle x \cdot f'(x)[/tex]
Express 126 as 125 + 1;
i.e.
[tex]x = 125; \triangle x = 1[/tex]
So, we have:
[tex]f(125+1) \approx f(125) + 1 \cdot f'(125)[/tex]
[tex]f(126) \approx f(125) + 1 \cdot f'(125)[/tex]
To calculate f(125), we have:
[tex]f(x) = \sqrt[3]{x}[/tex]
[tex]f(125) = \sqrt[3]{125}[/tex]
[tex]f(125) = 5[/tex]
So:
[tex]f(126) \approx f(125) + 1 \cdot f'(125)[/tex]
[tex]f(126) \approx 5 + 1 \cdot f'(125)[/tex]
[tex]f(126) \approx 5 + f'(125)[/tex]
Also:
[tex]f(x) = \sqrt[3]{x}[/tex]
Rewrite as:
[tex]f(x) = x^\frac{1}{3}[/tex]
Differentiate
[tex]f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}\\[/tex]
Using law of indices, we have:
[tex]f'(x) = \frac{x^\frac{1}{3}}{3x}[/tex]
So:
[tex]f'(125) = \frac{125^\frac{1}{3}}{3*125}[/tex]
[tex]f'(125) = \frac{5}{375}[/tex]
[tex]f'(125) = \frac{1}{75}[/tex]
So, we have:
[tex]f(126) \approx 5 + f'(125)[/tex]
[tex]f(126) \approx 5 + \frac{1}{75}[/tex]
[tex]f(126) \approx 5 + 0.01333[/tex]
[tex]f(126) \approx 5.01333[/tex]
Which graph shows the solution to this system of linear inequalities?
y<-1/3x+2
y<_2x-3
Answer:
C
Step-by-step explanation:
Since all the graphs have the same line, you’re just looking for the correct shaded region. Since for both equations you want the shaded region to be less than the line, answer c solves the inequality.