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The domain of the function f(x) = {√(x + 2)} is x ≥ -2, where {} denotes the fractional part.

To find the domain of the function, we need to consider the values of x for which the expression inside the square root is defined. In this case, the expression x + 2 must be non-negative (since we cannot take the square root of a negative number). So we set x + 2 ≥ 0 and solve for x.

x + 2 ≥ 0

x ≥ -2

Therefore, the domain of the function is x ≥ -2. This means that the function is defined for all real numbers greater than or equal to -2.

In the second paragraph, we explain that the domain of the function f(x) = {√(x + 2)} is x ≥ -2. The function involves taking the square root of (x + 2) and then considering the fractional part of the result.

The expression inside the square root must be non-negative, which means x + 2 ≥ 0. Solving this inequality, we find x ≥ -2. Thus, any real number greater than or equal to -2 is included in the domain of the function.

For example, if we choose x = -2, the expression inside the square root becomes 0, and taking the square root of 0 gives us 0. The fractional part of 0 is also 0. As we move to x > -2, the square root expression becomes positive, resulting in non-zero fractional parts.

So, the function is defined and has a non-zero fractional part for all real numbers greater than -2. However, for x < -2, the expression inside the square root becomes negative, which is not defined in the real number system. Therefore, the domain of the function is x ≥ -2.

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Answer:

(C) Multiply first equation by -2 and second equation by 3, solution (1, 1)

Step-by-step explanation:

Simultaneous equations are set of equations which possess a common solution. The equations can be solved by eliminating one of the unknowns by multiplying each of the equations in a way that a common coefficient is obtained in the unknown to be eliminated.

Given the simultaneous equations:

3x - 5y = -2

2x + y = 3

First step:

Multiply first equation by -2 and multiply second equation by 3,

-6x + 10y = 4

6x + 3y = 9

Second step:

Add the two equations together,

13y = 13

Divide both sides by 13

y = 1

Third step:

Put y = 1 in the first equation

3x - 5(1) = -2

3x - 5 = -2

3x = 5 - 2

3x = 3

Divide both sides by 3:

x = 1

solution (x,y) = (1,1)

Option C

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