A. The initial value of the linear formula is $40,500
The growth rate of the function is $950
B. The value of the car in 2020 is $69,000
C. The year in which the car is worth $61,400 is 2012.
What is the initial and growth rate value of the linear formula?.A. V = 40,500 + 950n
Where,
V = value in dollars
n = number of years since 1990
The initial value of the linear formula is $40,500
The growth rate of the function is $950
B. The value of the car in 2020;
When n = 30
V = 40,500 + 950n
= 40,500 + 950(30)
= 40,500 + 28,500
= $69,000
C. The year in which the car is worth $61,400
V = 40,500 + 950n
61,400 = 40,500 + 950n
subtract 40,500 from both sides
61,400 - 40,500 = 950n
20,900 = 950n
divide both sides by 950
n = 22 years
Therefore, 22 years after 1990 is 2012
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Simplify i) ( x-y )( x−y )( x−y )
The simplified expression for ( x - y ) ( x - y ) ( x - y ) is x³ - x²y - xy² + y³.
To simplify ( x - y ) ( x - y ) ( x - y ), we can expand the expression using the distributive property of multiplication. We can also simplify the expression by combining like terms.
In using the distributive property of multiplication, we multiply each term in the first set of parentheses by each term in the second set of parentheses. This gives us:( x - y ) ( x - y ) ( x - y ) = ( x(x - y) - y(x - y) ) ( x - y )= ( x² - xy - xy + y² ) ( x - y )= ( x² - 2xy + y² ) ( x - y )
Now we can further simplify the expression by combining like terms. We can use the difference of squares formula to simplify the second set of parentheses.( x² - 2xy + y² ) ( x - y ) = ( x - y ) ( x - y )²= ( x - y ) ( x² - 2xy + y² )= x³ - x²y - 2xy² + xy² - xy² + y³= x³ - x²y - xy² + y³
Therefore, the simplified expression is x³ - x²y - xy² + y³.
Summary: To simplify ( x - y ) ( x - y ) ( x - y ), we expand the expression using the distributive property of multiplication. We simplify the expression by combining like terms. We use the difference of squares formula to simplify the second set of parentheses. Finally, we simplify the expression further by combining like terms. The simplified expression is x³ - x²y - xy² + y³.
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p(-2,6),q(-8,4),r(1,2) what is the y value of p’
Answer:
OK, here is your answer
Step-by-step explanation:
AI-generated answer
We are given three points, p(-2, 6), q(-8, 4), and r(1, 2), and we are asked to find the y-value of p'. Since we are not given any information about p', we can assume that it is the reflection of p across the x-axis.To find the reflection of p across the x-axis, we need to negate the y-coordinate of p. Therefore, the y-value of p' is equal to the negative of the y-coordinate of p.
So, the y-value of p' is -6.
Hence, the coordinates of p' are (-2, -6).
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