NEEEEDD HELPP...........

Answer:

In a Newton's ring arrangement, the difference in the square of the diameters of successive rings is equal to four times the wavelength of light divided by the refractive index of the medium between the planoconvex lens and the plane glass plate.

If the wavelength of light is changed to 4.5 x 10-5 cm, then the difference in the square of the diameters of successive rings will be equal to four times 4.5 x 10-5 cm divided by the refractive index of the medium (which is assumed to be 1 if a liquid of refractive index 1.33 is not introduced).

If a liquid of refractive index 1.33 is introduced between the lens and the plate, then the difference in the square of the diameters of successive rings will be equal to four times 4.5 x 10-5 cm divided by 1.33.

If the radius of curvature of the convex surface of the plano-convex lens is doubled, then the difference in the square of the diameters of successive rings will remain the same.

To sketch the processes in a p-V diagram, we need to first determine the initial and final states of each process, as well as the path each process takes.

Process 1-2 is a constant pressure expansion from state 1 to state 2. So, the path is a straight horizontal line on the p-V diagram, from (0.2, 5) to (1, 5) (in units of m^3 and bar).

Process 2-3 is a constant volume cooling from state 2 to state 3, so the path is a straight vertical line on the p-V diagram, from (1, 5) to (1, 1).

Process 3-1 is a compression process during which the pressure-volume relationship is pV=constant. This implies that the path on the p-V diagram is a hyperbola, passing through state 3 and returning to state 1.

The work done in each process can be calculated using the following equations:

W = P(V2 - V1) for constant pressure process (1-2)

W = 0 for constant volume process (2-3)

W = -nRT ln(V2/V1) for isothermal process (3-1), where n is the number of moles of CO, R is the gas constant, and T is the temperature of the gas.

Assuming standard temperature and pressure conditions (STP), which is 1 atm and 273.15 K, the gas constant R can be taken as 0.0821 Latm/(molK).

Using these equations, we can calculate the work for each process as follows:

W1-2 = 5*(1-0.2) = 4 kJ

W2-3 = 0

W3-1 = -nRT ln(V2/V1) = -10.0821273.15 ln(1/0.2) = 11.1 kJ

Therefore, the total work done on the gas in the three processes is the sum of the work done in each process, which is 4 kJ + 0 kJ + 11.1 kJ = 15.1 kJ.

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Once the ball is thrown, the only force acting on it is gravity, which means that it's acceleration is -9.81 m/s² (negative means downward).

List the known and unknown quantities from the question.

u = initial velocity = 20 m/s

v = final velocity = ? m/s

g = acceleration due to gravity = -9.81 m/s²

t = time interval = ? s

s displacement = 11 m

Before calculating the time it takes for the ball to reach 11 m, the final velocity needs to be calculated using the following kinematic equation.

v² = u² + 2gs

v = √(u² + 2gs)

= √((20 m/s)² + (2x-9.81 m/s² x 11 m)) = 13.57 m/s V=

Calculate the time it takes the ball to reach 11 m using the following kinematic equation.

V = u + gt

Solve for t.

t = (v-u)/g

t (13 57 m/s - 20 m/s)/(-981 m/s²) = 0.655 s

a) The peak wavelength in 3.22 nanometers of an object is 345 nanometre, b) the emissive intensity of the object is 2.82 * 10⁸ W/m².

The relationship between the temperature,T and the peak wavelength, [tex]\lambda[/tex] emitted by a black body is given by wien's displacement law:

[tex]\lambda[/tex] = b / T

Where, b is a constant and it's value is 2.898 * 10-3 m-K

Given: T = 8400 K

So, [tex]\lambda[/tex] =   (2.898 * 10-3 )/8400

\lambda = 3.45 * 10-7  

\lambda = 345 nm

Hence, the peak wavelength of the object at this temperature is 345 nanometre.

The amount of power emitted per unit area, P is given by Stefan Boltzmann law:

P =[tex]\sigma[/tex]T⁴

Where,

Absolute temperature, T = 8400 K

Stefan Boltzmann constant, [tex]\sigma[/tex] = 5.67 * 10-8 W/m²K⁴

So, P = 5.67 * 10-8 * (8400)⁴

P = 2.82 * 10⁸  W/m²

Hence, the power emitted per unit area is 2.82 * 10⁸ W/m².

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Answer:

We can start by using the formula:velocity = distance/timeFirst, we need to calculate the distance traveled in kilometers.

To do this, we can subtract the exit numbers:

116 km - 35 km = 81 km

Next, we need to convert the time difference from hours and minutes to hours:

3:09 pm - 2:15 pm = 0.9 hours

Now we can use the formula to find the velocity:

velocity = 81 km / 0.9 hours

velocity ≈ 90 km/h

Finally, we can convert this velocity to meters per second by multiplying by 1000/3600:

velocity = 90 km/h x 1000 m/km / 3600 s/h

velocity ≈ 25 m/s

Therefore, your velocity is approximately 25 m/s.

Explanation:

An organ pipe with one end closed has a fundamental frequency of 1500 Hz. This pipe produces the highest number of overtones that the average person can hear.

The formula v=RTM, where M is the molar mass of the gas, determines the fundamental frequency and frequency of the sound produced when the organ pipe is filled with some gas. response the equation v2l provides the fundamental frequency.

Only one end of a closed organ pipe has an opening, and sound is transmitted through the open end. When an organ pipe is closed, the fundamental frequency is given as v=v4L, where v is the sound's velocity in the pipe's medium and L is its length.

Organ pipes have a fundamental frequency of v/4L when closed at one end and v/2L when open.

Therefore, new frequency would be 2000 Hz.

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The given question is incomplete. the complete question is given below.

An organ pipe open at one end, but closed at the other, is vibrating in its fundamental mode, producing sound of frequency 1000 hz. If you now open the closed end, the new fundamental frequency will be.

A) 2000 Hz.

B) 1000 Hz.

C) 500 Hz.

D) 250 Hz.

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Lets examine all three properties stated here ~

I) holes in lattice allow the electricity to flow through ?

- holes aren't a majority charge carrier in a conductor, in conductors electricity is conducted by free elecrons. so this statement is incorrect.

ll) Electricity flows easily through this type of material?

- That's true, conductors (usually metals) have free electrons to conduct electricity, which is responsible for good electricity Conductivity.

lll) A few electrons in every atom are loosely held by the nuclei.

- That's also true, Conductors (mainly metals) have a few electrons (say, 1, 2 or maybe 3) in there valence shell which experience quite less force of attraction from nucleus, hence they are free to move around the whole conductor randomly, making a sea of electrons.

So, the correct choice will be : D) ll and lll

The force needed by my friend to make the entertainment center move at a constant velocity is 600 N

To find the force application in a specific situation, one needs to consider the forces that are acting on an object and the net force (the vector sum of all forces acting on an object) which determines the motion of the object.

In order to make the entertainment center move at a constant velocity, the sum of the applied forces must equal the force of kinetic friction. If the maximum applied force you can provide is 1000 N, then your friend needs to apply a force of 1600 N - 1000 N = 600 N.

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In A. part, the magnetic field at (0, 50) is in west direction. In B. part, the strength of the field at (0,50) is 2.06 G.

A. The current is flowing up for west as shown by the front view figure at the bottom of the gadget. Your fingers will curve to the west if you wrap your right hand around the wire with your thumb up. Put a compass at (0,50) to check the direction as well. It indicates west.

B. By using the Pythagorean Theorem to determine the strength of the combined field, the strength of the field at (0,50) is 2.06 G.

The earth's magnetic field strength= 0.50 G

The induced current magnetic field strength= 2.0

B is given by=

[tex]\sqrt{0.50^{2} - 2.00^{2} }\\ =\sqrt{0.25-4.00}\\ =2.06[/tex]

Hence, we can also check by putting the probe on (0,50) and the probe reads 2.06 G.

Therefore, the strength of the field at (0,50) is 2.06 G.

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Answer:

The surfaces and structures in an urban area can have a significant influence on the urban heat island effect. For example, paved surfaces like roads and buildings absorb more heat than surfaces covered in vegetation, and structures like high-rise buildings can trap and reflect heat, resulting in higher temperatures in the urban area. Additionally, urban areas usually have less vegetation than their rural counterparts, meaning there is less vegetation to absorb heat from the sun and provide shade, further contributing to the urban heat island effect. Evidence of this can be seen in research at louisvilleky.gov/government/sustainability/urban-heat-island-project.

The time it takes for an object to attain a velocity of 127.4 m/s is 13 seconds.

The time it takes for an object to attain a velocity of 127.4 m/s after being dropped depends on several factors, including the object's mass, the strength of air resistance, and the acceleration due to gravity.

In the absence of air resistance, an object dropped from rest would attain a velocity of 127.4 m/s at a time, t calculated as;

v = u + gt

v = 0 + gt

v = gt

t = v/g

where;

t = ( 127.4 ) / (9.8)

t = 13 seconds

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Answer:

Newtons

Explanation:

In Figure 1, charge 2 should be placed along line D to make the free-body diagrams of charge 1 and charge 2 consistent.

The electric field lines produced by charge 2 should point towards charge 1 to provide the attractive force between them. As shown in the free-body diagram of charge 1, the electric field lines point towards the left, which means that charge 2 should be placed on the left side of charge 1. Similarly, in Figure 2, charge 2 should be placed along line F to make the free-body diagrams of charge 1 and charge 2 consistent. The electric field lines produced by charge 2 should point towards the left to provide the attractive force between them. In Figure 1, charge 2 should be placed along line D to make the free-body diagrams of charge 1 and charge 2 consistent.

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Momentum is conserved in both elastic and perfectly inelastic collisions.

In an elastic collision, the total momentum of the colliding objects is conserved before and after the collision. This means that the sum of the momentum of the objects before the collision is equal to the sum of the momentum of the objects after the collision.

In a perfectly inelastic collision, the two objects stick together after the collision, forming a single object with new momentum. In this case, the total momentum of the system is also conserved.

However, in an inelastic collision, momentum is not conserved, as some of the momenta are transformed into other forms of energy, such as heat or sound. This means that the total momentum of the objects before the collision is not equal to the total momentum of the objects after the collision.

Answer:

Explanation:

A

10cm is the farthest the object moves along the x-axis in the positive direction .0.15J is the object’s kinetic energy when its displacement is -8 cm. 0.316m/s is the object’s speed at x = 0.

Define kinetic energy.

Kinetic energy, which may be seen in the movement of an item or subatomic particle, is the energy of motion. Kinetic energy is present in every particle and moving object. Examples of kinetic energy in action include a person walking, a baseball soaring through the air, a piece of food falling from a table, and a charged particle in an electric field.

Given,

Total energy is 0.4J

m is 3kg

The farthest the object moves along the x-axis in the positive direction would be as potential energy is 0.4J. So from given diagram, displacement will be 10cm

If displacement is -8cm , P.E from diagram will be 0.25J

According to energy conservation formula ,

ME ⇒ U+KE

KE ⇒ ME-U ⇒ 0.4-0.25 ⇒ 0.15J

At x ⇒ 0,

KE ⇒ 1/2 mv^2

0.15 ⇒ 0.5*3*v^2

v ⇒ 0.316m/s

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Answer:

B. force equals mass multiplied by acceleration

Explanation:

Newton's second law of motion states that the acceleration of an object equals the net force acting on the object divided by the object's mass. According to the second law, there is a direct relationship between force and acceleration and an inverse relationship between mass and acceleration.

Newton's second law of motion is F = ma, or force is equal to mass times acceleration.

The law of Newton that is related to momentum is:

B.) Newton's second law

Newton's second law states that the rate of change of momentum of an object is directly proportional to the force applied to the object and occurs in the direction in which the force is applied. This law is often expressed as F = ma, where F is the force, m is the mass of the object, and a is the acceleration of the object. This law provides the mathematical relationship between force, mass, and acceleration, which is crucial in understanding the concept of momentum.

Option C is the accurate answer. The act of preservation of instigation is grounded on Newton’s third act because of the act of conservancy of instigation.

It can subsist deduced from the act of act and response, which states that every workforce has a repaying level and contrary force. However, the hedge pushes ago against you with an equal quantum of workforce, if you drive against a barrier.  

This act signifies individual harmony in complexion workforces always do in dyads, and one core can not ply a workforce on another without passing a workforce itself.  

Newton’s third act of motion states that:    

“When one core exerts a workforce on the different mass, the foremost core gests a workforce which is collected at the moment on the contrary direction of the force which is wielded ”.  

The above statement means that in every commerce, there's a brace of forces acting on the interacting objects. The magnitude of the workforces are level and the command of the workforce on the foremost thing is contrary to the order of the workforce on the alternate thing.

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If the Earth were only half the size it is now, the acceleration due to gravity (represented by "g") at the surface would also be halved.

This is because the gravitational force between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them.

With the Earth's mass reduced by a factor of 2 and its radius reduced by a factor of 2, the distance between an object on the surface and the Earth's center would also be reduced by a factor of 2. Thus, the net effect is that the acceleration due to gravity would be halved, resulting in a smaller value of "g" than what we currently observe on Earth.

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Answer:

the expanse or amount of space between two things, points, lines, anything in science or math.

DISTANCE...

Explanation:

Answer: I am assuming you're asking for the cliff height, which is 24M

We can use the kinematic equations to find the horizontal and vertical components of the ball's velocity and its final position.

The initial velocity components are:

v_x = 33 m/s * cos(60∘) = 28.6 m/s

v_y = 33 m/s * sin(60∘) = 33 * √3/2 m/s

The displacement components can be found using the kinematic equation:

x = v_x * t = 28.6 m/s * 4.0 s = 114.4 m

y = v_y * t - 0.5 * g * t^2 = 33 * √3/2 m/s * 4.0 s - 0.5 * 9.8 m/s^2 * (4.0 s)^2 = 102.4 m - 78.4 m = 24.0 m

The ball lands on the edge of the cliff, so its height must be equal to h, or:

y = h

24.0 m = h

So, the height of the cliff is 24.0 m.

The correct answer is c. The exponential decay constant's value is [tex]2.6*10^{-55 }s^{-1}[/tex].

To find the value of the exponential decay constant, we need to calculate Ks, the thermal conductivity of the sample. We employ the equation to arrive at this. [tex]Ks = mc + mow[/tex],

where m is the mass of Polly, c is the specific heat of the human tissues, and mow is the mass of the water. Plugging in the values for Polly's mass (60 kg), the specific heat of the human tissues (3500 J/(kg°C)) and

the mass of the water (300 kg),

and the specific heat of the water (4186 J/(kg°C)),

we get Ks = 0.5 W/(m°C).

Now, we can plug in the values for Ks, A, I, and Ax into the equation for[tex]Tdif = (constant) e^{-t}[/tex]

to calculate the exponential decay constant. By entering the values, we obtain the equation.

[tex]Tdif = (constant) e^{-t} = (0.5 W/(mC) * 2nrl * 1.5 m * 0.5 m) e^{-t}.[/tex]

Simplifying, we get  [tex]Tdif = 2.6*10^{-55} e^{-t}.[/tex].

Therefore, the value of the exponential decay constant is  [tex]2.6*10^{-55 }s^{-1}[/tex].

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Answer:

Height difference: approximately [tex]63\; {\rm m}[/tex].

The first ball was dropped from a height of approximately [tex]123\; {\rm m}[/tex].

(Assumptions: both balls were released from rest, air friction is negligible, and that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].)

Explanation:

Under the assumptions, both ball would accelerate at a constant [tex]a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}[/tex].

Let [tex]t[/tex] denote the time since the first ball was released.

Height of the first ball at time [tex]t[/tex] can be modelled with the SUVAT equation [tex]h(t) = (1/2)\, a\, t^{2} + u\, t + h_{0}[/tex], where [tex]u[/tex] is the initial velocity. However, since [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex] by assumption, this equation simplifies to [tex]h(t) = (1/2)\, a\, t^{2} + h_{0}[/tex].

Since this ball reached the ground after [tex]t = 5.0\; {\rm s}[/tex], [tex]h(5.0) = 0\; {\rm m}[/tex]. In other words:

[tex]\begin{aligned}\frac{1}{2}\, (-9.81)\, (5.0)^{2} + h_{0} = 0\end{aligned}[/tex].

Simplify and solve for the initial height of this ball, [tex]h_{0}[/tex]:

[tex]\begin{aligned}h_{0} &= -\frac{1}{2}\, (-9.81)\, (5.0)^{2} \\ &\approx 123\; {\rm m}\end{aligned}[/tex].

In other words, the first ball was dropped from a height of approximately [tex]123\; {\rm m}[/tex].

Similarly, the height of the second ball may be modelled as [tex]h(t) = (1/2)\, a\, t^{2} + h_{0}[/tex].

Since this ball reached the ground [tex]t = (5.0 - 1.5)\; {\rm s} = 3.5\; {\rm s}[/tex] after being released, [tex]h(3.5) = 0\; {\rm m}[/tex]. The initial height of this ball would be:

[tex]\begin{aligned}h_{0} &= -\frac{1}{2}\, (-9.81)\, (3.5)^{2} \\ &\approx (-60)\; {\rm m}\end{aligned}[/tex].

Subtract the initial height of the second ball from that of the first ball to find the difference in initial height:

[tex](123 - 60) \; {\rm m} \approx 63\; {\rm m}[/tex].

The three phases of bromine are: liquid, gas, and solid. To order these phases based on the distance between bromine particles, from least to greatest.

We need to consider how the intermolecular forces change as the temperature and pressure change.

In the solid phase, bromine molecules are packed tightly together, with the minimum distance between particles. This is because the intermolecular forces, including London dispersion forces and dipole-dipole forces, are strong enough to hold the particles in a fixed position.

In the liquid phase, the bromine molecules are further apart than in the solid phase, but still close enough to experience intermolecular forces. The temperature of the liquid is high enough to overcome the attractive forces and cause the particles to move about more freely, but not enough to separate the particles completely.

In the gas phase, the bromine molecules are separated by the greatest distance, with no strong intermolecular forces to hold them in place. The high temperature of the gas causes the particles to move rapidly, colliding with each other but not sticking together.

Therefore, the order of the three phases based on the distance between bromine particles is solid < liquid < gas.

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a) 4225m or 4.225km b) 11.1s

For part a; convert 65km/h to km/min, to do so all you do is divide 65/60 as there are 60 minutes per hour. Afterwards, multiply by 3.90 to find the distance travelled in 3.90mins.

For part b; convert km/h to km/s, in this one we divide 65/3600 as there are 3600 seconds in one hour. Then, using the S = D/T, where S = speed, D = distance and T= time, we isolate for T and get T = D/S. So then we sub for T=0.20/0.018 (0.018 is the product of 65/3600) and we get T=11.1s.

A. the magnitude of E ->  is √10.

B.  the magnitude of F -> is √10

C. the magnitude of G -> = E-> +F -> is √20

D. the magnitude of H-> =−E -> −2F ->  is √50.

The magnitude or size of a mathematical object is described as a property which determines whether the object is larger or smaller than other objects of the same kind.

A. The magnitude of the vector E -> is given by the formula:

|E -> | = √(3^2 + 1^2) = √(9 + 1) = √10

So, the magnitude of E -> is √10.

B. The magnitude of the vector F -> is given by the formula:

|F -> | = √(1^2 + (-3)^2) = √(1 + 9) = √10

So, the magnitude of F -> is √10.

C. The magnitude of the vector G -> is given by the formula:

G -> = E-> + F ->

|G -> | = √((3 + 1)^2 + (1 - 3)^2) = √(4^2 + (-2)^2) = √(16 + 4) = √20

So, the magnitude of G -> is √20.

D. The magnitude of the vector H -> is given by the formula:

H -> = -E-> - 2F->

|H -> | = √((-3 - 2 * 1)^2 + (-1 - 2 * -3)^2) = √((-5)^2 + 5^2) = √50

So, the magnitude of H -> is √50.

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The first scenario results in a higher current of 4 amperes.

Current is defined as the amount of charge flowing per unit time.

For the first scenario, 40 coulombs in 10 seconds, the current would be:

I = Q/t = 40 C / 10 s = 4 A

For the second scenario, 2 coulombs in 1 second, the current would be:

I = Q/t = 2 C / 1 s = 2 A

Therefore, the first scenario results in a higher current of 4 amperes than the second scenario of 2 amperes current.

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Answer:

calculate the expected time of arrival, we need to divide the total distance by the speed of the truck.

In this case, the expected time of arrival would be:

640 km ÷ 110 km/h = 5.82 hours

So the driver should be able to arrive at the destination within 6 hours if he can hold his current speed.

In this case, the force is 23 N, and the distance is 4.2 m. Therefore, the work required is 97.6 joules (J).

Joules is a unit of energy. It is a derived unit of the International System of Units (SI) and is used to measure energy, work, or the amount of heat generated or absorbed. It is typically used to measure energy in various forms, such as the kinetic energy of a moving object, the energy of a wave, or the energy stored in an electric field or a magnetic field. In the SI, one joule is equal to the energy expended by a force of one newton when its point of application moves one meter in the direction of the force. The joule is also a unit of energy in many other systems of measurement, including the British thermal unit (BTU), the calorie, and the watt hour.

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a. The force required on the small piston to raise a 10 N load on the large piston is 0.403 N.

b.  The load would be raised to a height of 63.13 cm when the small piston has moved 0.1 m.

The formula is F1 / F2 = A2 / A1

where F1 is the force applied on the small piston, F2 is the force exerted on the large piston, A1 is the area of the small piston, and A2 is the area of the large piston.

A1 = (π / 4) * (1 cm)^2 = 0.0079 cm^2

A2 = (π / 4) * (5 cm)^2 = 0.196 cm^2

F1 / F2 = 0.0079 cm^2 / 0.196 cm^2 = 0.0403

F2 = 10 N

F1 = F2 * (A1 / A2) = 10 N * 0.0403 = 0.403 N

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