Negate the conditional statement.
(~ a V ~ b) ►c

Please show your work and give an explanation.

Answer:

[tex]{ \tt{5x + 3 \geqslant 48}} \\ { \tt{5x \geqslant 45}} \\ { \tt{x \geqslant 9}}[/tex]

Answer:

x[tex]\geq[/tex]9

Step-by-step explanation:

5x+3[tex]\geq \\[/tex]48  /-3

5x[tex]\geq[/tex]45   //5

x[tex]\geq[/tex]9

Answer:

0.96784

Step-by-step explanation:

17-13.3/2

=1.85

p(x<1.85)

=0.96784

The probability that randomly selected homework will require less than 17 minutes to grade is 0.9678.

Mean [tex]\mu[/tex]=13.3 minutes

Standard deviation[tex]\sigma[/tex]=2 minutes

The value of the z-score tells you how many standard deviations you are away from the mean.

So, the z-score of the above data

[tex]z=\frac{x-\mu}{\sigma}[/tex]

[tex]z=\frac{17-13.3}{2}[/tex]

[tex]z=1.85[/tex]

From the standard normal table, the p-value corresponding to z=1.85

Or, p(x<1.85)=0.9678 or 96.78%

Hence, the probability that randomly selected homework will require less than 17 minutes to grade is 0.9678.

To get more about the z-score visit:

https://brainly.com/question/25638875

Given:

The graph that represents the enrollment for college R between 1950 and 2000.

To find:

The average rate of increase in enrollment per decade between 1950 and 2000?

Solution:

The average rate of change of function f(x) over the interval [a,b] is:

[tex]m=\dfrac{f(b)-f(a)}{b-a}[/tex]

So, the average rate of increase in enrollment per year between 1950 and 2000 is:

[tex]m=\dfrac{f(2000)-f(1950)}{2000-1950}[/tex]

[tex]m=\dfrac{7-4}{50}[/tex]

[tex]m=\dfrac{3}{50}[/tex]

[tex]m=0.06[/tex]

It is given average rate of increase in enrollment per year between 1950 and 2000 is 0.06.

We need to find the average rate of increase in enrollment per decade between 1950 and 2000, So, multiply the average rate of increase in enrollment per year by 10.

[tex]0.06\times 10=0.6[/tex]

Therefore, the average rate of increase in enrollment per decade between 1950 and 2000 is 0.6.

Answer:

Standard deviation, means, skewness and kurtosis.

Step-by-step explanation:

Two normal curves may be same but they have different means, standard deviation and skewness. There can be different standard deviation for two curves and there is difference in skewness.

Answer:

Here we just want to find the Taylor series for f(x) = ln(x), centered at the value of a (which we do not know).

Remember that the general Taylor expansion is:

[tex]f(x) = f(a) + f'(a)*(x - a) + \frac{1}{2!}*f''(a)(x -a)^2 + ...[/tex]

for our function we have:

f'(x) =  1/x

f''(x) = -1/x^2

f'''(x) =  (1/2)*(1/x^3)

this is enough, now just let's write the series:

[tex]f(x) = ln(a) + \frac{1}{a} *(x - a) - \frac{1}{2!} *\frac{1}{a^2} *(x - a)^2 + \frac{1}{3!} *\frac{1}{2*a^3} *(x - a)^3 + ....[/tex]

This is the Taylor series to 3rd degree, you just need to change the value of a for the required value.

Answer:

There are 256 pairs in all.

Answer:

Slope is undefined. Line parallel to y-axis.

Step-by-step explanation:

By Analytic Geometry, we can determine the slope of a line by knowing two distinct lines and using the definition of secant line:

[tex]m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] (1)

Where:

[tex](x_{1}, y_{1})[/tex] - Coordinates of the initial point.

[tex](x_{2}, y_{2})[/tex] - Coordinates of the final point.

[tex]m[/tex] - Slope.

If we know that [tex](x_{1}, y_{1}) = (17, -13)[/tex] and [tex](x_{2}, y_{2}) = (17, 8)[/tex], then the slope of the line is:

[tex]m = \frac{8-(-13)}{17-17}[/tex]

[tex]m = \frac{21}{0}[/tex]

The slope is undefined, which means that line is parallel to y-axis.

Answer:

(2,3)

Step-by-step explanation:

Given:

The numbers are [tex]\dfrac{3}{5},2,0,1,-0.45, 1.44[/tex].

To find:

All the values that cannot be probabilities.

Solution:

We know that,

[tex]\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]

The minimum value of favorable outcomes is 0 and the maximum value is equal to the total outcomes. So, the value of probability lies between 0 and 1, inclusive. It other words, the probability lies in the interval [0,1].

[tex]0\leq \text{Probability}\leq 1[/tex]

From the given values only [tex]\dfrac{3}{5}, 0, 1[/tex] lie in the interval [0,1]. So, these values can be probabilities.

The values [tex]2,-0.45, 1.44[/tex] does not lie in the interval [0,1]. So, these values cannot be probabilities.

Therefore, the correct values are [tex]2,-0.45, 1.44[/tex].

Given:

The triangle ABC is reflected over the x-axis.

The distance between point A and A’ is 14.

To find:

The distance between the x-axis and A’.

Solution:

If a figure is reflected across the x-axis then the corresponding parts are mirror image of each other about the x-axis.

It means the distance between A and x-axis is same as the distance between x-axis and A'.

The distance between point A and A’ is 14.

Let d be the distance between the x-axis and A’. Then,

[tex]d+d=14[/tex]

[tex]2d=14[/tex]

[tex]d=\dfrac{14}{2}[/tex]

[tex]d=7[/tex]

Therefore, the correct option is 1.

Lauren will get 2/25 because the coin only lands on heads or tail

Answer:

36 introverts

Step-by-step explanation:

Total number of adults in the survey = 120

Ratio of introverts to extroverts = 3:7

Number of introverts = ratio number of introverts / ratio total × 120

Ratio number of introverts = 3

Ratio total = 3 + 7 = 10

Number of introverts = 3/10 × 120

= 36

Answer:

1-x^2/x^3 - 1 = 1/x

Step-by-step explanation:

First rewrite x^3 as x^2 * x cancel x^2  in both numerator and denominator.

   Write below

1 - 1/x - 1

Subtract

   1 - 1 = 0

now simplify

1 -1 /x - 1 = 1/x

1/x  = Answer

Can you Understand

Answer:

a AND ~c

Step-by-step explanation:

you can find the full explanation in wikipedia:

https://en.m.wikipedia.org/wiki/Material_conditional

under "Negated conditionals"

Hello,

[tex]if\ n=1\ then\ 1^2=1\ and\ \dfrac{1}{6}*1*2*3=1:\ true\ for\ n=1\\[/tex]

We suppose the property true for n:

1²+2²+...+n²=n(n+1)(2n+1) / 6

and we are going to demonstrate that the property is true for n+1:

1²+2²+..+(n+1)²=(n+1)*(n+2)*(2n+3)/6

[tex]1^2+2^2+...+n^2+(n+1)^2\\\\=n*(n+1)*(2n+1)/6+(n+1)^2\\\\=(n+1)/6*[n(2n+1)+6n+6]\\\\=(n+1)/6*(2n^2+7n+6)\\\\=(n+1)(n+2)(2n+3)/6\\[/tex]

here you go it's too easy

Step-by-step explanation:

Explanation is in the attachment .

Hope it is helpful to you ❣️☪️❇️

Answer:

The correct one is 3 over b equals 7 over a

Answer:

3/b = 7/a

Step-by-step explanation:

I took it on Edge

Answer:

Step-by-step explanation:

1 - 8

2 - 14

3 - 22

Answer:

8,14,22

Step-by-step explanation:

Tn = n^2 +3n +4

n=1

    = 1^2 +3(1) +4

    = 1 +3+4

   = 8

n=2

    = 2^2 +3(2) +4

    = 4 +6+4

   = 14

n=3

    = 3^2 +3(3) +4

    = 9 +9+4

   = 22

Answer:

157,476 people

Step-by-step explanation:

the formula :

P(x) = 86700. (1+ 0.089)^r

for r = 7

=> P(x) = 86700 × (1+ 0.089)^7

= 86700 × (1.089)^7

= 86700 × 1.8163

= 157,476 people

Answer:

3x-3

Step-by-step explanation:

3x has a variable attach, because no other numbers have a variable attached leave it alone.

2+(-5) are like terms so combine these two. 2+(-5)=-3

now put back in the equation

3x-3

Hi there!

[tex]\large\boxed{(-\infty, 9)}[/tex]

We can find the range using completing the square:

y = -x² - 2x + 8

Factor out a -1:

y = -(x² + 2x) + 8

Use the first two terms. Take the second term's coefficient, divide by 2, and square:

y = -(x² + 2x + 1) + 8  

Remember to add by 1 because we cannot randomly add an additional number into the equation:

y = -(x² + 2x + 1) + 8 + 1

Simplify:

y = -(x + 1)² + 9

Since the graph opens downward (negative coefficient), the range is (-∞, 9)

Answer:

i hope you understand easily

mark me brainlist

Step-by-step explanation:

Answer:

C.[tex]P(7.0039<x<7.8026)=0.1334[/tex]

D.[tex]P(7.0039<\bar{x}<7.8026)\approx 0.2942[/tex]

Step-by-step explanation:

We are given that

n=18

Mean, [tex]\mu=6.75[/tex]

Standard deviation, [tex]\sigma=2.28[/tex]

c.

[tex]P(7.0039<x<7.8026)=P(\frac{7.0039-6.75}{2.28}<\frac{x-\mu}{\sigma}<\frac{7.8026-6.75}{2.28})[/tex]

[tex]P(7.0039<x<7.8026)=P(0.11<Z<0.46)[/tex]

[tex]P(a<z<b)=P(z<b)-P(z<a)[/tex]

Using the formula

[tex]P(7.0039<x<7.8026)=P(Z<0.46)-P(Z<0.11)[/tex]

[tex]P(7.0039<x<7.8026)=0.67724-0.54380[/tex]

[tex]P(7.0039<x<7.8026)=0.1334[/tex]

D.[tex]P(7.0039<\bar{x}<7.8026)=P(\frac{7.0039-6.75}{2.28/\sqrt{18}}<\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}})<\frac{7.8026-6.75}{2.28/\sqrt{18}})[/tex]

[tex]P(7.0039<\bar{x}<7.8026)=P(0.47<Z<1.96)[/tex]

[tex]P(7.0039<\bar{x}<7.8026)=P(Z<1.96)-P(Z<0.47)[/tex]

[tex]P(7.0039<\bar{x}<7.8026)=0.97500-0.68082[/tex]

[tex]P(7.0039<\bar{x}<7.8026)=0.29418\approx 0.2942[/tex]

Answer:

1) C

2) D

3) A

4) B

hope it helps

Answer:

6x

Step-by-step explanation:

If x is the length of one side, and each side is the same length, you will multiply it by 6 times (there are 6 sides in a hexagon).

So, you will add it up 6 times, but you can say 6x for short.

Answer:

This is a Categorical variable and the measurement scale is ordinal scale.

Step-by-step explanation:

The measurement scale that is being used to classify sleep is the ordinal measurement. In this question, the variable that is called sleep quality is a categorical variable. categorical variables are variables that have the data representing groups. sleep quality has been given this categorical order extremely low very low low and extreme high.

The ordinal scale is a scale that denotes order it has all variables in a specific order.

Answer:

Step-by-step explanation:

P(answers correctly)=1/5

P(answers incorrectly)=1-1/5=4/5

P( answers correctly second question)=4/5 ×1/5=4/25

Answer:

[tex]\sum_{n = 1}^{7} -2 -2n[/tex]

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference of consecutive terms is always the same, called common difference.

The nth term of a sequence is given by:

[tex]a_{n} = a_1 + (n-1)d[/tex]

In which [tex]a_1[/tex] is the first term and d is the common difference.

Sigma notation to represent the sum of the first seven terms

Sum going from the index starting at 1 and finishing at 7, that is:

[tex]\sum_{n = 1}^{7} f(n)[/tex]

Now we have to fund the function, which is given by an arithmetic sequence.

−4, −6, −8,

First term -4, common difference - 6 - (-4) = -6 + 4 = -2, so [tex]a_1 = -4, d = -2[/tex]

Then

[tex]f(n) = a_{n} = a_1 + (n-1)d[/tex]

[tex]f(n) = -4 + (n-1)(-2)[/tex]

[tex]f(n) = -4 - 2n + 2 = -2 - 2n[/tex]

Sigma notation:

Replacing f(n)

[tex]\sum_{n = 1}^{7} -2 -2n[/tex]