NO LINKS! Please help me with this problem​

Answer:

(10,10)

Step-by-step explanation:

y = .5x + 5

If you put in 10 for x, we get 10 for y.

y = .5(10) + 5

y =5 + 5

y = 10

When x is 10, y is 10 (10,10)

The time it would take for the print to reach 100 percent completion is 12,101 minutes 9 seconds.

The mathematical operations that would be used to determine the required value are division and multiplication. Division is the process of grouping a number into equal parts using another number. The sign used to denote division is  ÷. Multiplication is the process of determining the product of two or more numbers. The sign used to denote multiplication is ÷.

Other mathematical operations that are used to solve problems include addition and subtraction.

Time it would take to reach 100% completion = (minutes it takes to print 87% of the words x 100%) / 87%

Time it would take to reach 100% completion = (10,528 x 1) / 0.87 =

10.528 / 0.87

= 12,101. 15

= 12,101+ (0.15 x 60)

= 12,101 minutes 9 seconds

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We conclude that the width of the rectangular garden is 80 feet.

Let's define the variables:

The perimeter of a rectangle of length L and width W is given by the simple formula:

P = 2*(L + W)

The perimeter is equal to 400ft, then:

400ft = 2*(L + W)

And we know that the length is 120ft, then:

L = 120ft.

Replacing the length in the perimeter equation we get:

400ft = 2*(120ft + W)

Now we can solve this linear equation for W.

400ft/2 = 120ft + W

200ft = 120ft + W

200ft - 120ft = W

80ft = W

We conclude that the width of the rectangular garden is 80 feet.

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The derivatives of the functions are listed below:

(a) [tex]f'(x) = -7\cdot x^{-\frac{9}{2} }- 2\cdot x + 4 - \frac{1}{5} - 5\cdot x^{-2}[/tex]    

(b) [tex]f'(x) = \frac{1}{3}\cdot (x + 3)^{-\frac{2}{3} }\cdot (x+ 5)^{\frac{1}{3} } + \frac{1}{3} \cdot (x + 5)^{-\frac{2}{3} } \cdot (x + 3)^{\frac{1}{3} }[/tex]

(c) f'(x) = [(cos x + sin x) · (x² - 1) - (sin x - cos x) · (2 · x)] / (x² - 1)²    

(d) f'(x) = (5ˣ · ㏑ 5) · ㏒₅ x + 5ˣ · [1 / (x · ㏑ 5)]

(e) f'(x) = 45 · (x⁻⁵ + √3)⁻⁸ · x⁻⁶

(f) [tex]f'(x) = (\ln x + 1)\cdot [7^{x\cdot \ln x \cdot \ln 7}+7\cdot (x\cdot \ln x)^{6}][/tex]

(g) [tex]f'(x) = -2\cdot \arccos x \cdot \left(\frac{1}{\sqrt{1 - x^{2}}} \right) - \left(\frac{1}{1 + x} \right) \cdot \left(\frac{1}{2} \cdot x^{-\frac{1}{2} }\right)[/tex]

(h) f'(x) = cot x + cos (㏑ x) · (1 / x)

In this question we must obtain the first derivatives of each expression by applying differentiation rules:

(a) [tex]f(x) = 2 \cdot x^{-\frac{7}{2} } - x^{2} + 4 \cdot x - \frac{x}{5} + \frac{5}{x} - \sqrt[11]{2022}[/tex]

(b) [tex]f(x) = \sqrt[3]{x + 3} \cdot \sqrt[3]{x + 5}[/tex]

(c) f(x) = (sin x - cos x) / (x² - 1)

(d) f(x) = 5ˣ · ㏒₅ x

(e) f(x) = (x⁻⁵ + √3)⁻⁹

(f) [tex]f(x) = 7^{x\cdot \ln x} + (x \cdot \ln x)^{7}[/tex]

(g) [tex]f(x) = \arccos^{2} x - \arctan (\sqrt{x})[/tex]

(h) f(x) = ㏑ (sin x) + sin (㏑ x)

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The answer is t ≤ 11.

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

[tex] \qquad❖ \: \sf \:6 = 2(y + 2)[/tex]

[tex] \qquad❖ \: \sf \:(y + 2) = \cfrac{6}{2} [/tex]

[tex] \qquad❖ \: \sf \:y + 2 = 3[/tex]

[tex] \qquad❖ \: \sf \:y = 3 - 2[/tex]

[tex] \qquad❖ \: \sf \:y = 1[/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

It's easy to show that [tex]7\tan(4x)[/tex] is strictly increasing on [tex]x\in\left[0,\frac\pi8\right][/tex]. This means

[tex]M = \max \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/12} = 7\sqrt3[/tex]

and

[tex]m = \min \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/16} = 7[/tex]

Then the integral is bounded by

[tex]\displaystyle 7\left(\frac\pi{12} - \frac\pi{16}\right) \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le 7\sqrt3 \left(\frac\pi{12} - \frac\pi{16}\right)[/tex]

[tex]\implies \displaystyle \boxed{\frac{7\pi}{48}} \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le \boxed{\frac{7\sqrt3\,\pi}{48}}[/tex]

If we solve the equations x-2y=5 and 4x+12y=-20 then we will get x=1 and y=-2.

Given two equations x-2y=5 and 4x+12y=-20.

We are required to find the value of x and y through substitution method.

Equation is like a relationship between two or more variables expressed in equal to form. Equations of two variables look like ax+by=c. Equation can be a linear equation,quadratic equation, cubic equation or many more depending on the power of variable.

They can be solved as under:

x-2y=5---------------1

4x+12y=-20--------2

Finding value of variable x from equation 1.

x=5+2y--------------3

Use the value of variable  x in equation 2.

4x+12y=-20

4(5+2y)+12y=-20

20+8y+12y=-20

20y=-20-20

20y=-40

y=-40/20

y=-2

Use the value of variable y in equation 3.

x=5+2y

x=5+2*(-2)

x=5-4

x=1

Hence if we solve the equations x-2y=5 and 4x+12y=-20 then we will get x=1 and y=-2.

Question is incomplete as it should include one more equation x-2y=5.

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Split up [0, 16] into 4 equally-spaced subintervals of length [tex]\frac{16-0}4=4[/tex],

[0, 16] = [0, 4] U [4, 8] U [8, 12] U [12, 16]

with midpoints 2, 6, 10, and 14, respectively.

Then with the midpoint rule, we approximate the integral to be about

[tex]\displaystyle \int_0^{16} \sin(\sqrt x) \, dx \approx 4 \left(\sin(\sqrt2) + \sin(\sqrt6) + \sin(\sqrt{10}) + \sin(\sqrt{14})\right) \approx \boxed{4.1622}[/tex]

The least number of colors you need to correct color in the sections of these pictures so that no two touching sections are the same color is 5 colors. This can be obtained by simply giving colors to the small shapes according to the criteria.

From the question the figure, the number of colored sections with which are not colored with respect to a "touching" colored section, would not be half of the total colored sections since the sections are not alternating as they still meet at a common point.

After all, it notes no two touching sections, not adjacent sections.

There is no equation to calculate this requirement with respect to the total number of sections.

Taking one triangle or square as the starting we can give colors to each small units. This figure will be the start of sequence of other small figures.

If a square were to be this starting shape that have same color as that color of the square.

Now from the remaining given another color to the starting figure. We will get that shapes, that will have same color.

Like that the remaining figures are given colors.          

Therefore, the least number of colored sections you can color in the sections meeting the given requirement, is 5 sections for this first figure.

Hence the least number of colors you need to correct color in the sections of these pictures so that no two touching sections are the same color is 5 colors.

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The vector in component form is given by:

V = i - j.

A vector is given by the terminal point subtracted by the initial point, hence:

(3,-4) - (2, -3) = (3 - 2, -4 - (-3)) = (1, -1)

A vector (a,b) in component form is:

V = a i + bj.

Hence, for vector (1,-1), we have that:

V = i - j.

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Answer:

OB:.242.T gives it's area in square inches

The 4.2 inches base length and 36 in.² area of the given triangle and the 5.6 inches base length of the similar triangle gives the area of the similar triangle as 64 square inches

Area of a triangle = (Base length × Height)/2

Area of the given triangle = 36 in.²

Base length of the given triangle = 4.2 inches

Base length of the similar triangle = 5.6 inches

Therefore;

Area of the given triangle = (Base length × Height)/2

Which gives;

36 = (4.2 × h)/2

Where;

h = Height of the given triangle

36 × 2 = 4.2 × h

[tex]h = \mathbf{\frac{36 \times 2}{4.2}} = 17 \frac{1}{7} [/tex]

Height of the given triangle, h = 17+ 1/7

The ratio of corresponding sides of similar triangles are the same, which gives;

[tex] \frac{5.6}{4.2} = \frac{h'}{17 \frac{1}{7}} [/tex]

Where;

h' = The height of the similar triangle

Which gives;

[tex] h' = \frac{5.6}{4.2} \times 17 \frac{1}{7} = 22 \frac{6}{7} [/tex]

The area, A', of the similar triangle is therefore;

[tex] A' = \frac{1}{2} \times 5.6 \times 22 \frac{6}{7} = 64 [/tex]

The area can also be obtained using the scale factor of area as follows;

Which gives;

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Step-by-step explanation:

second one

explanation: trust me bro

Answer:

Step-by-step explanation:

(1400x14.5x5%) + 1400 =2415

Answer: 14.5 months

For a standard normal distribution, the probability of the 2 - scores P(-1.64 < z < 0.2) is 0.52876

We want to find the p-value between 2 z-scores expressed as;

P(-1.64 < z < 0.2)

To solve this, we will solve it as;

P(-1.64 < z < 0.2) = 1 - [P(z < -1.64)  + P(z > 0.2)]

From normal distribution table, we have that;

P(x < -1.64) = 0.050503

P(x > 0.2) = 0.42074

Thus;

P(-1.64 < z < 0.2) = 1 - (0.050503 + 0.42074)

P(-1.64 < z < 0.2) = 0.52876

Thus, For a standard normal distribution, the probability of the 2 - scores P(-1.64 < z < 0.2) is 0.52876

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Answer:

B

Step-by-step explanation:

Cos is the adjacent side over the hypotenuse.  The adjacent side to <E is side ED.  The hypotenuse is side EF.  ED/EF.  They do not go right out and give you this choice, but you see that B says the same thing.

**Disclaimer** Hi there! I assumed the question is to represent W in terms of all other variables (P, L). The following answer corresponds to this understanding. If it is incorrect, please let me know and I will modify my answer.

Answer: W = (P/2) - L

Step-by-step explanation:

Given equation

P = 2L + 2W

Factorize 2 out

P = 2 (L + W)

Divide 2 on both sides

P / 2 = 2 (L + W) / 2

P / 2 = L + W

Subtract L on both sides

(P / 2) - L = L + W - L

[tex]\Large\boxed{W=\frac{P}{2} -L}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

[tex]\displaystyle{W = \dfrac{P}{2} - L}[/tex]

Step-by-step explanation:

To solve for W, we have to isolate the W-variable. First, we can factor the expression 2L + 2W to 2(L+W):

[tex]\displaystyle{P = 2(L+W)}[/tex]

Next, we'll be dividing both sides by 2:

[tex]\displaystyle{\dfrac{P}{2} = \dfrac{2(L+W)}{2}}\\\\\displaystyle{\dfrac{P}{2} = L+W}[/tex]

Then subtract both sides by L:

[tex]\displaystyle{\dfrac{P}{2} - L= L+W-L}\\\\\displaystyle{\dfrac{P}{2} - L= W}[/tex]

Therefore, we'll obtain W = P/2 - L.

Note that the given formula is perimeter formula of a rectangle where Perimeter = 2 * Length + 2 * Width.

So if we solve for W (Width) then we'll get Width = Perimeter / 2 - Length which can be useful to find width with given perimeter and length.

(infinity -1/2]u [-1/2 -1/2] u [1/2 infinity)

Answer:

[tex]3x^{2} - 4xy + 2y { }^{2} - 1 \\ 3 \times ( - 3) { }^{2} - 4 \times ( - 3) \times 5 + 2 \times 5 {}^{2} - 1 \\ (3 \times 9) - ( - 60) + 50 - 1 \\ 27 + 60 + 50 - 1 \\ 165 [/tex]

Answer: 136

Substitute -3 for x and 5 for y.

[tex]3x^2 - 4xy + 2y^2 - 1[/tex]

[tex]3(-3)^2-4(-3)(5)+2(5)^2-1[/tex]

[tex]3(9)-4(-15)+2(25)-1[/tex]

[tex]27+60+50-1[/tex]

[tex]87+50-1[/tex]

[tex]137-1[/tex]

[tex]136[/tex]

hope this helped!

Answer: -1

Step-by-step explanation:

Here, we are subtracting two fractions; therefore, we must make the denominators the same by finding the least common multiple. Since we have x - 3 for one denominator and x + 2 for the other, we don't have any common factors. Hence, the least common multiple would be their product.

[tex](x-3)(x+2)\\x(x-3)+2(x-3)\\x^2-3x+2x-6\\x^2-x-6[/tex]

The question is looking for the coefficient of the second term. Since there is just a negative sign in front of the x, the "?" can be filled with either a negative sign or a -1.

The given statement that's true about the function is g(-13) = 20 is true for g.

From the information given, the function, g, has a domain of -20 < x < -5 < g(x) <45 and that g(0)= -2 and g(-9)= 6.

Let's analyze the options that are given in the scenario. g(7) = -1. It should be noted that 7 isn't in our domain. Therefore, this isn't possible.

g(-13) = 29

x = 13 is in our domain and 20 is also is in our range. Therefore, this is true for g.

g(0) = 2.

This isn't true because it is given that g(0) = 2

In conclusion, the given statement that's true about the function is g(-13) = 20 is true for g.

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❄ Hi there,

keeping in mind that the sum of complementary angles is 90°,

set up an equation, letting [tex]\angle2[/tex]  be x  –

[tex]\triangleright \ \sf{\angle1+x=90}[/tex]                 {and we know that [tex]\boxed{\angle1=45}[/tex]}

[tex]\triangleright \ \sf{45+x=90}[/tex]

[tex]\triangleright \ \sf{x=90-45}[/tex]

[tex]\triangleright \ \sf{x=45}[/tex]

[tex]\triangleright \ \sf{\angle2=45\textdegree}[/tex]

      __________

Keeping in mind that a right angle is 90°,

set up an equation, letting [tex]\angle1[/tex] be x:

[tex]\triangleright \ \sf{x+\angle2=90}[/tex]                       {and we know that [tex]\boxed{\angle2=63}[/tex]}

[tex]\triangleright \ \sf{x+63=90}[/tex]

[tex]\triangleright \ \sf{x=27}[/tex]

[tex]\triangleright \ \sf{\angle1=47\textdegree}[/tex]

❄

Answer:

Step-by-step explanation:

The correct value of w is 20 as the width of a rectangle must be positive. A quadratic function always has 2 zeroes and in a case like this the negative one is ignored.

Answer:(5-1)(7-1)

Step-by-step explanation:

We have give 4 numbers that are 1,1,5,7. we have to apply operations on it to make it 24.

» ( 7 - 1) × (5 - 1)

» (6) × (4)

» 24

Here's our answer..!!

Answer:

x = 46 degrees

Step-by-step explanation:

180 - 134 = 46

Answer:

46°

Step-by-step explanation:

134 + x   add to a straight line angle = 180

134+x = 180

x = 46

Answer: 57 cm²

Step-by-step explanation:

We can split this figure into two shapes: the rectangle on the left and the triangle on the right. We can find the area of each separately and add them to get the total area.

The area of a rectangle is [tex]lw[/tex], where l is the length and w is the width. We can just multiply 8 and 6 to get the area of the rectangle.

[tex]A=8*6\\A=48[/tex]

The area of the triangle is [tex]\frac{1}{2}bh[/tex], where b is the base of the triangle and h is the height. Here' the base would be 6 cm as opposite sides of a rectangle have the same measure, and the height is 3.

[tex]A=\frac{1}{2}(6*3)\\A=\frac{1}{2}(18)\\A=9[/tex]

The total area would just be the sum of the two separate areas.

[tex]48+9=57[/tex]

Hence, the area of the figure is 57 cm².

Answer: 57 cm^2

Step-by-step explanation:

To find the entire area of the figure, we have to find the area of the rectangle and the triangle and sum it up

The area of the rectangle is 6 * 8 = 48 cm^2

The area of the triangle is 1/2 * 3 * 6(Opposite sides of a rectangle have equal lengths) = 9 cm^2

So the area of the figure is 48 + 9 = 57 cm^2

Answer:

1 section should be labelled "bilingual".

4 sections should be labelled "monolingual".

Step-by-step explanation:

If 20% of students in the school are bilingual, then 80% of students in the school are monolingual, since 100% - 20% = 80%.

If the spinner is to be divided into 5 equally sized sections, with each section labeled as "bilingual" or "monolingual" to represent the corresponding proportion of students in the school, then:

Bilingual

  20% of 5

= 20/100 × 5

= 100/100

= 1 section

Monolingual

  80% of 5

= 80/100 × 5

= 400/100

= 4 sections

Therefore:

The graph is shown in the attached image.

She needs to lay 11 slabs on each row to make a square

The total number of slabs is given as:

Total = 121 slabs

Let this represent the area of the slab.

The area of a square is calculated as:

Area = Length^2

Substitute the known values in the above equation

Length^2 = 121

Take the square root of both sides

Length = 11

Hence, she needs to lay 11 slabs on each row to make a square

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