NO LINKS!! URGENT HELP PLEASE!!​

Answer: 2

Step-by-step explanation:

Function inversely proportional:

y = k/x

Solve for k from the point they gave you on the line y=6 and x=-3

6 = k/(-3)              >multiply -3 to both sides

-18 = k                  >This is your k value

y = -18/x                >This is your generic equation of the line

Now they want to know what is y when x= -9

y= -18 / -9

y = 2

Using the least common multiple of 19 and 18, the smallest number that could be in the group is 342

To find the smallest number of people that could be in the group, we need to find the least common multiple (LCM) of 19 and 18. The LCM is the smallest positive integer that is divisible by both 19 and 18.

The prime factorization of 19 is 19 (since 19 is a prime number), and the prime factorization of 18 is 2 * 3^2.

To find the LCM, we take the highest power of each prime factor that appears in either number:

LCM = 2 * 3² * 19

LCM = 2 * 9 * 19

LCM = 342

Therefore, the smallest number of people that could be in the group is 342.

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Answer:

x = 13 and y = (7 - 3x) / (-2)

Step-by-step explanation:

Solving for X

The given equation is:

3x - 7 = 2x + 6

To solve for x, we can simplify and rearrange the equation as follows:

3x - 2x = 6 + 7 (subtracting 2x and adding 7 to both sides)

x = 13 (combining like terms)

Therefore, the solution to the given equation is x = 13.

Thus, the correct answer is 13.

The given equation is:

3x - 2y = 7

solving for y

To solve for y, we need to isolate y on one side of the equation.

First, we can subtract 3x from both sides of the equation:

3x - 3x - 2y = 7 - 3x

Simplifying, we get:

-2y = 7 - 3x

Next, we can divide both sides by -2 to get y by itself:

y = (7 - 3x) / (-2)

Therefore, the solution for y is y = (7 - 3x) / (-2).

Thus, the above is the solution for y.

Answer:

  61.03°

Step-by-step explanation:

You want the angle opposite the side of length 7 in the triangle with other sides of lengths 4 and 8.

The law of cosines relates the angles of a triangle to the side lengths. For triangle ABC with opposite sides a, b, c, the relation is ...

  c² = a² +b² -2ab·cos(C)

Solving for angle C, we have ...

  cos(C) = (a² +b² -c²)/(2ab)

  C = arccos((a² +b² -c²)/(2ab))

In this triangle, that means ...

  C = arccos((4² +8² -7²)/(2·4·8)) = arccos(31/64)

  C ≈ 61.03°

The angle of interest is about 61.03°.

__

Additional comment

We get the same result from a triangle solver. See the second attachment. (The angle we want is angle B in that attachment.)

<95141404393>

Answer:

a

Step-by-step explanation:

the data is represented in the dot plot

Answer:

answer is 77.67

Step-by-step explanation:

explain by the x axis is 68 to y axis is 84 so the median is 77.67

The equation X^2/2 - 8 = 2X - 2 has two solutions, X = 6 and X = -2. These are the values of X that satisfy the equation and make both equations Y = X^2/2 - 8 and Y = 2X - 2 intersect on the graph.

To find the solutions to the equation X^2/2 - 8 = 2X - 2, we need to set the two equations equal to each other and solve for X.

The equation is:

X^2/2 - 8 = 2X - 2

To simplify the equation, let's multiply both sides by 2 to eliminate the fraction:

X^2 - 16 = 4X - 4

Next, we rearrange the equation to have all terms on one side:

X^2 - 4X - 12 = 0

Now, we can solve this quadratic equation by factoring, completing the square, or using the quadratic formula. Let's use factoring in this case:

(X - 6)(X + 2) = 0

Setting each factor equal to zero gives us two possible solutions:

X - 6 = 0 --> X = 6

X + 2 = 0 --> X = -2

So the solutions to the equation X^2/2 - 8 = 2X - 2 are X = 6 and X = -2.

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The independent Variable in the situation presented in the table is the temperature (T), which is measured in degrees Celsius (°C), and the dependent variable is the volume (V), which is measured in milliliters (mL).

The table above illustrates the relationship between the temperature of a substance and its volume. The independent variable is the temperature of the substance and the dependent variable is the volume of the substance.

The symbol or name used to represent the independent variable is "T" for temperature and its units are given as degrees Celsius or °C.The symbol or name used to represent the dependent variable is "V" for volume, and its units are given as milliliters or mL.

The temperature is the independent variable as it is being manipulated in the experiment while the volume is dependent on the temperature as it is changing based on the temperature.

An independent variable is a variable in an experiment that is being manipulated by the experimenter, while the dependent variable is the variable that is being measured in response to changes in the independent variable.

In summary, the independent variable in the situation presented in the table is the temperature (T), which is measured in degrees Celsius (°C), and the dependent variable is the volume (V), which is measured in milliliters (mL).

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According to the information we can infer that in the Mayan numeral system, the year 2010 is represented as follows: snail, point, snail, point, point, point, point, point

The number 2010 is broken down into Mayan units, using the symbols corresponding to the different positional values. In the Maya system, three main symbols are used:

To represent the number 2010 in Maya, the combination of these symbols is used as follows:

Two shells represent the value of 2000. One point represents the value of 10. So, the representation of the year 2010 in Mayan numbers would be:

snail, point

Remember that the Mayan number system is positional, similar to the decimal system, so the value and position of each symbol are important to determine the complete number.

Note: The question in English is: How to represent 2010 in Mayan numbers?

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The solutions to the equation |2x - 11| = 7 are x = 2 and x = 9. Option D

To find the numbers that satisfy the given condition, we can set up an equation based on the information provided.

Let's assume the number we're looking for is x. According to the problem, twice the number is 7 units from 11. Mathematically, we can represent this as:

|2x - 11| = 7

To find the possible values of x, we need to solve this equation. We can split it into two cases:

Case 1: 2x - 11 = 7

In this case, we have:

2x = 7 + 11

2x = 18

x = 18/2

x = 9

Case 2: -(2x - 11) = 7

In this case, we have:

-2x + 11 = 7

-2x = 7 - 11

-2x = -4

x = -4/-2

x = 2

Therefore, the solutions to the equation |2x - 11| = 7 are x = 2 and x = 9. These are the numbers that satisfy the condition where twice the number is 7 units from 11.

The correct answer is:

x = 2, 9 Option D

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Answer:

8 units

Step-by-step explanation:

Area of square:

length * width

2 * 3

= 6  units

Area of triangle:

1/2 * base * height

1/2 * 2 * 2

= 2 units

Area of entire shape:

6 + 2

= 8 units

So, the area of the shape is 8 units.

If this answer helped you, please leave a thanks!

Have a GREAT day!!!

The corresponding monthly expense for the given expenses is approximately $278.34.

We have from the question that;

Monthly automobile insurance expense = $400 / 6 = $66.67

Monthly health insurance expense = $170

Monthly life insurance expense = $500 / 12 = $41.67

Total monthly expense = Monthly automobile insurance expense + Monthly health insurance expense + Monthly life insurance expense

Total monthly expense = $66.67 + $170 + $41.67

Total monthly expense = $278.34

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The measure of angle B is 64. 2 degrees

To determine the measure of the angle, we have the different trigonometric identities.

We have that;

From the information given, we have that;

Using the sine identity, we have;

sin θ = opposite/hypotenuse

Substitute the values, we have;

sin B = 18/20

Divide the values, we have;

sin B = 0.900

Find the inverse value of sine, we have;

B = 64. 2 degrees

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In the figure shown, 1 and 2 are; supplementary angles.

According to geometry in mathematics, we know very well that the sum of angles on a straight line is 180 degrees. We also know that two angle s are said to be supplementary angles when they sum up to 180 degrees.

Now, from the given image, we know that angle 1 and angle 2 form a straight line and as such they sum up to 180 degrees

This then tells us that they are both supplementary angles.

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If you are ever charged with a DUI, it is important to seek legal counsel and understand your rights and options for Defense.

Blood Alcohol Concentration (BAC) is a measure of the amount of alcohol present in a person's bloodstream. In most states, it is illegal to operate a motor vehicle with a BAC of 0.08% or higher. For drivers under the age of 21, the legal BAC limit is often lower, usually 0.02% or 0.01%.A DUI (driving under the influence) charge can result from operating a motor vehicle while under the influence of drugs or alcohol, with a BAC above the legal limit, or with impairing substances in the bloodstream. If a person refuses to take a chemical test (such as a breathalyzer or blood test) to determine their BAC, they may still be charged with DUI based on other evidence of impairment such as the officer's observations, field sobriety tests, or witness statements.DUI charges can have serious consequences, including fines, license suspension, and possible imprisonment. The severity of the charges and penalties may vary depending on the individual's BAC, the presence of drugs in their system, and other factors such as prior DUI convictions or injuries caused by the impaired driving.

In conclusion, it is always important to make responsible decisions when it comes to operating a motor vehicle and to avoid consuming drugs or alcohol before getting behind the wheel. If you are ever charged with a DUI, it is important to seek legal counsel and understand your rights and options for defense.

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The factored form of the polynomial x^3 - 12x^2 - 2x + 24 by grouping is (x - 12)(x^2 - 2).

To determine the factors of the polynomial x^3 - 12x^2 - 2x + 24 by grouping, we can follow these steps:

Step 1: Group the terms in pairs. In this case, we can pair the first two terms and the last two terms:

(x^3 - 12x^2) + (-2x + 24)

Step 2: Factor out the greatest common factor from each pair. From the first pair, we can factor out x^2, and from the second pair, we can factor out -2:

x^2(x - 12) - 2(x - 12)

Step 3: Notice that we now have a common binomial factor of (x - 12) in both terms. Factor out this common binomial factor:

(x - 12)(x^2 - 2)

Therefore, the factored form of the polynomial x^3 - 12x^2 - 2x + 24 by grouping is (x - 12)(x^2 - 2).

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73 students represent approximately 93.59% and 5 students represent approximately 6.41% out of the total of 78 students.

To calculate the percentages for 73 and 5 out of 100%, you can use the following formulas:

Percentage = (Number of students / Total number of students) * 100%

For 73 students:

Percentage = (73 / 78) * 100% = 93.59%

For 5 students:

Percentage = (5 / 78) * 100% = 6.41%

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Q1. The standard error of the average sample weight when 15 participants are randomly selected for the sample is approximately 9.05 lbs.

Q2.  the probability that the average sample weight is greater than 185 lbs when 15 participants are randomly selected for the sample is approximately 0.8643, or 86.43%

Question 1:

To calculate the standard error of the average sample weight, we can use the formula:

Standard Error = Standard Deviation / √(Sample Size)

In this case, the standard deviation is given as 35 lbs and the sample size is 15 participants. Plugging in these values into the formula, we get:

Standard Error = 35 / √(15) ≈ 9.05 (rounded to two decimal places)

Therefore, the standard error of the average sample weight when 15 participants are randomly selected for the sample is approximately 9.05 lbs.

Question 2:

To calculate the probability that the average sample weight is greater than 185 lbs, we need to standardize the average sample weight using the standard error.

First, we calculate the z-score using the formula:

z = (Sample Mean - Population Mean) / Standard Error

The population mean is given as 175 lbs, the sample mean is 185 lbs, and the standard error is 9.05 lbs. Plugging in these values, we get:

z = (185 - 175) / 9.05 ≈ 1.10 (rounded to two decimal places)

Next, we use a standard normal distribution table or a calculator to find the probability corresponding to a z-score of 1.10. From the table, we find that the probability is approximately 0.8643.

Therefore, the probability that the average sample weight is greater than 185 lbs when 15 participants are randomly selected for the sample is approximately 0.8643, or 86.43% (rounded to two decimal places).

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The measure of the unknown angle is 143 degrees.

To find the measure of the unknown angle, we need to use the properties of straight angles. A straight angle is a line, and it measures 180 degrees.

In this case, we have a straight angle divided into a 37-degree angle and an unknown angle. So, we can set up the equation:

37° + unknown angle = 180°

To solve for the unknown angle, we need to isolate it on one side of the equation.

Subtracting 37° from both sides of the equation:

unknown angle = 180° - 37°

Simplifying:

unknown angle = 143°

As a result, the unknown angle is 143 degrees in length.

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Answer:

Step-by-step explanation:

4x + 10

C.

4-7(x+5)

4-7x+5

-7x+9

B. 2+5(x-7)

7(x-7)

7x-49

D. 7-3(x - 5)

7-3x-15

-3x-8

its 1,002

Answer:

a. My quadrilateral has four equal sides.

Must be: Rhombus.

Could be: Square.

b. My quadrilateral has two sets of parallel sides.

Must be: Parallelogram.

Could be:  Rectangle, Rhombus, Square

c. My quadrilateral has four right angles.

Must be: Rectangle.

Could be: Square.

Explanation:

b. A quadrilateral with two sets of parallel sides must be a parallelogram. It could also be a rectangle, a rhombus, or a square. However, a rectangle, rhombus, or square is also a parallelogram, so a parallelogram is the "must be" shape.

c. A quadrilateral with four right angles must be a rectangle. It could also be a square, but a square is a special type of rectangle, so a rectangle is the "must be" shape.

Answer:

a)  Must be a rhombus.
     Could be a square, a rectangle, a parallelogram, a trapezoid, or a kite.

b)  Must be a parallelogram.
     Could be a square, a rectangle, a kite, or a rhombus.

c)  Must be a rectangle.
     Could be a square, a kite, a rhombus or a parallelogram.

Step-by-step explanation:

The six basic types of quadrilaterals are:

A quadrilateral by definition is a four-sided shape. Therefore, it is possible for all types of quadrilateral to have four equal sides. However, for it to be a square and a rhombus, it must have four equal sides.

The interior angles of a square are all right angles, and its opposite sides are parallel. So as we haven't been told anything about the interior angles of the quadrilateral, or if any of its sides are parallel, we can conclude that:

The types of quadrilateral that can have two sets of parallel sides are square, rectangle, rhombus, parallelogram and kite (all squares are kites).

The interior angles of a square and a rectangle are 90°.

The side lengths of a rhombus are congruent.

As we haven't been told anything about the interior angles or the side lengths of the quadrilateral, we can conclude that:

All quadrilaterals, apart from a trapezium, can have interior angles that are all right angles. However, for a quadrilateral to be a square or a rectangle, it must have interior angles that are right angles.

As we don't know if the side lengths of the quadrilateral are equal, we cannot know if it's a square. Therefore, we can conclude that:

The Rate of the motorboat in still water is 8 miles per hour, and the rate of the current is 2 miles per hour.

To solve this problem, let's denote the rate of the motorboat in still water as "b" and the rate of the current as "c".

When Juana is going upstream, she is going against the current, so her effective speed is reduced. The formula for the time it takes to travel a certain distance is distance divided by speed. Therefore, for the upstream trip:

Time = Distance / (Boat's speed - Current's speed)

5 = 30 / (b - c)   -- (1)

On the return trip downstream, Juana is going with the current, so her effective speed is increased. Therefore, for the downstream trip:

Time = Distance / (Boat's speed + Current's speed)

3 = 30 / (b + c)   -- (2)

We now have a system of two equations with two variables. We can solve this system to find the values of "b" and "c".

First, let's solve equation (1) for (b - c):

5 = 30 / (b - c)

(b - c) = 30 / 5

(b - c) = 6   -- (3)

Next, let's solve equation (2) for (b + c):

3 = 30 / (b + c)

(b + c) = 30 / 3

(b + c) = 10  -- (4)

Now, we have two equations (3) and (4) that represent the sum and difference of (b + c) and (b - c) respectively. We can solve this system of equations to find the values of "b" and "c".

Adding equations (3) and (4), we get:

2b = 6 + 10

2b = 16

b = 8

Substituting the value of "b" back into equation (3), we get:

(8 - c) = 6

c = 8 - 6

c = 2

Therefore, the rate of the motorboat in still water is 8 miles per hour, and the rate of the current is 2 miles per hour.

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Answer:

+9xy =-13

no

so the answer is c

bro what is the answer is also can say they c optio thanks for point

Answer:

7. a. 16 units         b. 96 square units.

8. 30 units

Step-by-step explanation:

7.

a. The perimeter of a rhombus is 40, and PR is 12.

This means that all four sides are equal, and each side is 10.

Since diagonal bisect each other creating right angle.

so

In ΔPMS

PS=10

PM=1/2 of PR= 1/2*12=6

Now by using Pythagoras theorem:

PS²=MS²+PM²

10²=MS²+6²

MS²=100-36

MS²=64

MS=[tex]\sqrt{64}=8[/tex]

Therefore, diagonal QS=2*MS=2*8=16 units

b.

Since the area of a rhombus is half the product of its diagonals. The diagonals of this rhombus are QS=16 and PR=12,

So, Area=1/2*PR*QS

=1/2*12*16

=96 square units.

8.

The perimeter of a rhombus is the total length of all four sides.

Since the diagonals of a rhombus bisect each other at right angles, we can use the Pythagorean Theorem to find the length of one side of the rhombus.

let d1=9 and d2=12

[tex]s = \sqrt{(d1/2)^2 + (d2/2)^2}[/tex]

[tex]s = \sqrt{(9/2)^2 + (12/2)^2}[/tex]

s=7.5

we have

P = 4s where p is perimeter

P=4*7.5

Therefore, the perimeter of the rhombus is 30 units.

Answer:

7a)  QS = 16 units

7b)  96 square units

8)  30 units

Step-by-step explanation:

The sides lengths of a rhombus are equal.

Therefore, if the rhombus has a perimeter of 40, each side length is 10, since 40 ÷ 4 = 10.

PQ = QR = RS = SP = 10

The diagonals of a rhombus are perpendicular bisectors of each other.

Therefore, if PR is 12, then PM = 6.

Also, if QM + MS = QS, and QM = MS, then QS = 2·QM.

As the diagonals bisect each other at right angles, triangle PMQ is a right triangle, where:

Using Pythagoras Theorem to find the length of QM:

[tex]PM^2+QM^2=PQ^2[/tex]

   [tex]6^2+QM^2=10^2[/tex]

   [tex]36+QM^2=100[/tex]

           [tex]QM^2=64[/tex]

             [tex]QM=8[/tex]

As QS = 2·QM, then:

[tex]QS = 2 \cdot 8[/tex]

[tex]QS = 16[/tex]

[tex]\hrulefill[/tex]

The formula for the area of a rhombus is half the product of its diagonals.

[tex]\boxed{\begin{minipage}{5 cm}\underline{Area of a rhombus} \\\\$A=\dfrac{1}{2}pq$\\\\where:\\ \phantom{ww}$\bullet$ $p$ and $q$ are the diagonals.\\\end{minipage}}[/tex]

Therefore, given the diagonals of the rhombus are PR = 12 and QS = 16, the area of the rhombus is:

[tex]\begin{aligned}\textsf{Area}&=\dfrac{1}{2} \cdot 12 \cdot 16\\\\&=6 \cdot 16\\\\&=96\; \sf square\;units\end{aligned}[/tex]

[tex]\hrulefill[/tex]

The formula for the perimeter of a rhombus given its diagonals is:

[tex]\boxed{\begin{minipage}{5 cm}\underline{Perimeter of a rhombus} \\\\$P=2\sqrt{p^2+q^2}$\\\\where:\\ \phantom{ww}$\bullet$ $p$ and $q$ are the diagonals.\\\end{minipage}}[/tex]

If the diagonals are 9 and 12, the perimeter is:

[tex]\begin{aligned}\textsf{Perimeter}&=2\sqrt{9^2+12^2}\\&=2\sqrt{81+144}\\&=2\sqrt{225}\\&=2 \cdot 15\\&=30\end{aligned}[/tex]

Therefore, the perimeter of the rhombus is 30 units.

Increasing the value from 3 to 6 can potentially change the mode of a dataset. The mode represents the most frequently occurring value(s) in a dataset. If there are no repeated values or if the repeated values remain the same, then increasing the value from 3 to 6 will not change the mode. If there are new values introduced or if the frequency of certain values changes as a result of increasing the value, then the mode may indeed change.

1. Identify the initial dataset: Take note of the dataset where the mode is currently determined based on a value of 3.

2. Determine the mode: Calculate the mode of the dataset when the value is 3. The mode represents the most frequently occurring value(s) in the dataset.

3. Increase the value to 6: Modify the dataset by increasing the value from 3 to 6.

4. Analyze the dataset: Examine the modified dataset to observe any changes in the frequency distribution of values.

5. Compare the modes: Calculate the mode of the modified dataset with the value of 6 and compare it to the initial mode.

6. Assess changes: If the mode remains the same, it implies that the most frequently occurring value(s) in the dataset did not change. However, if the mode differs from the initial mode, it indicates that the increase from 3 to 6 has affected the frequency distribution and altered the most frequently occurring value(s).

7. Determine the impact: Analyze the specific changes in the dataset that led to the mode alteration. Identify any newly introduced values or shifts in the frequency of existing values.

8. Conclude: Based on the comparison of the initial mode and the mode with the increased value, determine whether increasing from 3 to 6 has changed the mode and describe the nature of the change.

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The y-intercept of [tex]f(x) = (1/2)^x[/tex] is option d D. (0, 1)

To find the y-intercept of a function, we need to evaluate the function when x = 0. In the given function f(x) = (1/2)^x, we substitute x = 0 and calculate the corresponding y-value.

f(0) = [tex](1/2)^0[/tex] = 1

Therefore, the y-intercept of the function is the point (0, 1). This means that when x is 0, the function has a y-value of 1.

The y-intercept represents the point where the function intersects the y-axis, which corresponds to the value of the function when x is 0. In this case, as x approaches 0, the value of [tex](1/2)^x[/tex] approaches 1. This is because any number raised to the power of 0 is equal to 1.

Option D. (0, 1) correctly represents the y-intercept of the function f(x) = [tex](1/2)^x[/tex]. The point (0, 1) indicates that when no units of the base (1/2) are multiplied together, the result is 1.

The other options (A. (0, 0), B. (1, 1/2), and C. (1, 0)) do not correctly represent the y-intercept because they either have incorrect y-values or are not on the y-axis (x ≠ 0). The y-intercept specifically refers to the point where the function crosses the y-axis, which occurs when x = 0.

The complete question is:

What is the y-intercept of[tex]f(x) = (1/2)^x[/tex]?​

A. (0, 0)

B. (1, 1/2)

C. (1, 0)

D. (0, 1)

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Answer:

  x ≈ 21.8

Step-by-step explanation:

You want the side length opposite the 98° angle in a triangle with side length 10 between that angle and one marked 55°.

The law of sines can be used when angles are known and at least one side is known. The unknown angle is found by using the fact that the sum of angles is 180°.

  angle opposite 10 = 180° -98° -55° = 27°

The law of sines tells you ...

  a/sin(A) = b/sin(B)

  x/sin(98°) = 10/sin(27°)

  x = 10(sin(98°)/sin(27°)) ≈ 21.8

The value of x is about 21.8 units.

<95141404393>

The amount due from creditors is ₹17,000.

Opening Entry:The opening entry is a term used to describe the initial journal entry of a company's financial transactions in its general ledger. To begin the accounting process, an opening entry is made that records the beginning account balances for all accounts in the ledger.

The opening entry is an important component of the accounting cycle, as it establishes the starting point of all transactions and provides a basis for future analysis and reporting.

The opening entry for the above transactions is:   

Particulars                        Amount         Particulars                  Amount  Cash in hand               25,000     Capital                    86,000Cash at bank                15,000     Furniture                    20,000Machinery                    50,000     Debtors                       10,000Bills payable                  10,000     Bills payable                    13,000Bank loan                      15,000     Salary Outstanding            8,000Total                            1,50,000    Total                            1,50,000

Amount due from creditors:

Creditors refer to an individual or organization that a company owes money to for goods or services that it has received. The amount owed to creditors by the company can be calculated by subtracting the amount of bills payable from the total of all accounts payable. Creditors' amount is ₹14,000. Transactions:1. Paid 2,000 in cash as wages on installation of a machine.                                Particulars             Amount                     Particulars                Amount Wages                        2,000                        Cash                            2,0002. Sold goods to Mr. Chopra at a list price of ₹4,000. Sales subject to 10% Trade Discount and 5% Cash discount if payment is made immediately, Mr. Chopra availed of a cash discount.                                Particulars             Amount                     Particulars                AmountSales                        3,600                        Mr. Chopra                  3,600Trade discount             400                                                                                                                                       Cash                        3,420Bank charges                   1803. Supplied goods costing ₹600 to Gopi& Sons. Issued invoice at 10% above cost less 5% trade discount.                                Particulars             Amount                     Particulars                AmountGopi& Sons                     660                                Sales                            660Trade discount                    30                                                                                                                                    Cost of goods sold              6004. Paid Custom Duty 10,000 in cash on import of a new machine.                                Particulars             Amount                     Particulars                AmountCustom Duty                10,000                        Cash                           10,0005. Goods sold costing 10,000 to M/s Abbas & Sons at an invoice price 10% above cost less 10% Trade Discount.                                Particulars             Amount                     Particulars                AmountSales                         9,000                         M/s Abbas & Sons            9,000Trade discount                 1,000Cost of goods sold              10,0006. Purchased goods on credit ₹5,000.                                             Particulars                   Amount                     Particulars                AmountPurchase                      5,000                        Creditors                   5,0007. Sold goods on credit 1,000.                                                 Particulars                 Amount                     Particulars                   AmountDebtors                                                                    1,000Sales                                                                      1,0008. Started business with Cash 1,50,000 and goods worth 10,000.                                Particulars                                              Amount              Particulars                                               AmountCash                                                          1,50,000                                 Goods                                                      10,0009. Goods purchased from M/S Garg& Sons 4,000 and from Peterson 1,000.                                Particulars                                         Amount                        Particulars                                      AmountPurchase                                               5,000                               M/S Garg& Sons                                    4,000Purchase                                                     1,000                               Peterson                                                     1,00010. Goods worth 300 used by the proprietor for personal use.                                Particulars                        Amount                     Particulars                              AmountDrawings                                        300                             Goods                                                  30011. Goods uninsured worth 2,000 were destroyed by fire.                                Particulars                                               Amount                                                Particulars                                          AmountLoss by fire                                                    2,000                                              Goods                                                              2,00012. Supplied goods costing 1,000 to Gavaskar issued at 10% above cost less 5% Trade discount.                                Particulars                                            Amount                    Particulars                                              AmountGavaskar                                                        1,050                                            Sales                                                                 1,050Trade discount                                                      50Cost of goods sold                                                  1,00013. Issued a cheque in favour of M/s Garg& Sons on account of purchase of goods worth 4,000.                                Particulars                        Amount                     Particulars                              AmountM/s Garg& Sons                                                  4,000                                          Bank                                                                              4,00014. Outstanding salary at the end of the year ₹650.                                Particulars                        Amount                      Particulars                              AmountSalary                                                            650                                 Salary Outstanding                            65015. Interest charged on drawings 5% p.a.                                Particulars                                      Amount                     Particulars                                            AmountDrawings                                                               Interest on Drawings                         Total Drawings*5%/12                         Total Drawings/12                                                       0.00                                                                           0.00*5% = 3,25016. Paid to Peterson ₹990 in full settlement of 1,000.                                Particulars                                 Amount                        Particulars                                         AmountPeterson                                               990                               Discount                                                     10                                Cash                                                                1,000Total                                                1,000                                Total                                                        1,000.

Therefore, the solution is:The opening entry for the given transaction is:                        Particulars                         Amount                     Particulars                              AmountCash in hand                      25,000                       Capital                             86,000Cash at bank                      15,000                       Furniture                          20,000Machinery                        50,000                       Debtors                            10,000Bills payable                      10,000                       Bills payable                    13,000Bank loan                          15,000                       Salary Outstanding               8,000Total                                    1,50,000                  Total                                    1,50,000

Calculation of Amount due from creditors:

Creditors = Total of all accounts payable - Bills payable

Creditors = ₹30,000 - ₹13,000Creditors = ₹17,000.

Therefore, the amount due from creditors is ₹17,000.

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