NO LINKS!! What is the equation shown in the smaller circle shown in the figure?​

NO LINKS!! What Is The Equation Shown In The Smaller Circle Shown In The Figure?

Answers

Answer 1

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

The general equation of ellipse is :

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {x}^{2} }{ {a}^{2} } + \cfrac{ {y}^{2} }{ {b}^{2} } = 1[/tex]

[ because it's a horizontal ellipse with centre at origin ]

so, let's equate given equation with the standard equation ~

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {x}^{2} }{64} + \cfrac{ {y}^{2} }{36} = 1[/tex]

se get :

a² = 64 ; a = 8

b² = 36 ; b = 6

As we know, length of minor axis is : 2b = 2 × 6 = 12 units

and, the smaller circle has diameter = 2b = 12 units

so, it's radius = 6 units ~

Now, let's write the equation of circle with origin as centre and radius = 6 units

[tex]\qquad \sf  \dashrightarrow \: {(x - h)}^{2} + (y - k) {}^{2} = {r}^{2} [/tex]

[ h = 0, k = 0, since circle has centre at origin ]

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} + {y}^{2} = 36[/tex]

Answer 2

Answer:

[tex]x^2+y^2=36[/tex]

Step-by-step explanation:

Equation of the red eclipse (taken from your previously posted question):

[tex]\dfrac{x^2}{64}+\dfrac{y^2}{36}=1[/tex]

General equation of an ellipse

[tex]\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1[/tex]

where:

(h, k) is the center[tex](h \pm a,k)\: \textsf{and}\:(h, k \pm b)\: \textsf{are the vertices}[/tex]

As the center of the red ellipse is (0, 0) ⇒ h = 0, k = 0.

[tex]\implies a^2=64 \implies a=\sqrt{64}=\pm8[/tex]

[tex]\implies b^2=36 \implies a=\sqrt{36}=\pm6[/tex]

The Major Axis is the longest diameter of an ellipse.

Therefore, using the formula for the vertices, the vertices of the major axis of the red ellipse are (8, 0) and (-8, 0).

The Minor Axis is the shortest diameter of an ellipse.

Therefore, using the formula for the vertices, the vertices of the minor axis of the red ellipse  (0, 6) and (0, -6).

Therefore, the radius of the larger circle is 8 units and the radius of the smaller circle is 6 units (half the respective axis, since the radius of a circle is half its diameter).

Equation of a circle

[tex](x-a)^2+(y-b)^2=r^2[/tex]

(where (a, b) is the center and r is the radius)

Given:

center = (0, 0)radius = 6 units

The equation of the smaller circle is:

[tex]\implies (x-0)^2+(y-0)^2=6^2[/tex]

[tex]\implies x^2+y^2=36[/tex]

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Related Questions

a chef uses 5 2/5 pounds of ground beef to make a hamburger and 2 1/4 pounds of ground beef to make meatloaf. the ground beef comes in 1/2 pound packages. how many packages of ground beef are needed to make hamburgers and meatloaf?

Answers

Answer:

16 packages

Step-by-step explanation:

5 2/5 + 2 1/4  Use the common denominator of 20

5 8/20 + 2 5/20  

7  13/20

I know that I will need 14 packages for the 7 pounds.  For the fraction part, 10/20 would be half, so I would need to buy a half pound for that, but I need 13/20 which would be more than a half pound, so I will need to buy 2 more pounds for the fraction part.

14 + 2 = 16

Combined, Tanya and Sanjay have 40 pens. If Tanya has four times as many pens as Sanjay, how many pens does Sanjay have?

Answers

Answer:Sanjay has 8

Step-by-step explanation: Because 8x4 equals 32 so thats how much tanya has a 32+8 equals 40. This is what I did I knew 10x4 is 40 so that couldn't be it so then I tried 8 because nine x four is 36 which would be to high so I tried 8 and it was perfect hope this helps.

If Combined, Tanya and Sanjay have 40 pens. If Tanya has four times as many pens as Sanjay, then Sanjay have 8 pens.

What is Equation?

Two or more expressions with an equal signs is called as Equation.

Given that Tanya and Sanjay have 40 pens. If Tanya has four times as many pens as Sanjay, We need to find how many pens sanjay has.

Let sanjay has x number of pens.

Tanya has four times as many pens as Sanjay

So 4 times means four multiple of sanjay pens.

Tanya has four times as many pens as Sanjay can be write as 4x.

Combined of tanya and sanjay has 40 pens.

Combined means adding.

x+4x=40

Add the like terms

5x=40

Divide both sides by 5.

x=8

So Sanjay has eight pens and Tanya has 4(8)=32 pens.

Hence Sanjay have eight pens.

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Find the area between the following curves.
y=x^3-x^2+x+8 ; y=5x^2-7x+8

Answers

Find where the two curves meet.

[tex]x^3 - x^2 + x + 8 = 5x^2 - 7x + 8 \\\\ \implies x^3 - 6x^2 + 8x = 0 \\\\ \implies x (x-2) (x - 4)= 0 \implies x=0, x=2, x=4[/tex]

The area between the curves is

[tex]\displaystyle \int_0^4 \left|\left(x^3-x^2+x+8\right) - \left(5x^2 - 7x + 8\right)\right| \, dx = \int_0^4 \left|x(x-2)(x-4)\right| \, dx[/tex]

When [tex]x[/tex] is between 0 and 2, [tex]x(x-2)(x-4)[/tex] is positive; when [tex]x[/tex] is between 2 and 4, [tex]x(x-2)(x-4)[/tex] is negative. So we split the integral at [tex]x=2[/tex] to get

[tex]\displaystyle \int_0^2 x(x-2)(x-4) \, dx - \int_2^4 x(x-2)(x-4)\,dx[/tex]

In the second integral, substitute [tex]y=x-2[/tex] to get

[tex]\displaystyle \int_0^2 x(x-2)(x-4) \, dx - \int_0^2 (y+2)y(y-2)\,dy[/tex]

[tex]\displaystyle \int_0^2 x(x-2) \bigg((x-4) - (x+2)\bigg) \, dx[/tex]

[tex]\displaystyle -6 \int_0^2 x(x-2) \, dx[/tex]

[tex]\displaystyle 6 \int_0^2 \left(2x - x^2\right) \, dx[/tex]

[tex]\displaystyle 6 \left(x^2 - \frac13x^3\right)\bigg|_0^2 = \boxed{8}[/tex]

How to Convert 11010112 to base 10?

Answers

Answer:

So this is all you need to do!

Hope it helped you:)

The Mogul Runners ski club planned a trip to Park City. Of the total number of club members, 11 signed up to go. If this is 25% of the club, how many members does the ski club have?

Answers

Answer: 44

Step-by-step explanation: Since 11 members are equal to 25% of the club, 11 members is 1/4 of the club because 25% = 1/4. There are four-fourths in a whole so 11x4 = 44 members. The ski club has 44 members.

if a rectangular piece of metal has 27.75 square inches what is the length and width?

Answers

The maximum area of a rectangular piece of metal with perimeter of 27.75 in² has length of 6.9375 in and width of 6.9375 in.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the length and y represent the width. hence:

Perimeter = 2(x + y)

27.75 = 2(x + y)

y = 13.875 - x

Area (A) = xy

A = x(13.875 - x)

A = 13.875x - x²

Maximum area is at A' = 0, hence:

A' = 13.875 - 2x

13.875 - 2x = 0

x = 6.9375

y = 6.9375

The maximum area of a rectangular piece of metal with perimeter of 27.75 in² has length of 6.9375 in and width of 6.9375 in.

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Prove the following relations.
Cos²A + cos²A.cot²A=cot²A
(1-sin²A)(1+cot²A)=cot²A​

Answers

Step-by-step explanation:

Let's solve for the first one,

[tex]R.H.S. = Cos²A + cos²A.cot²A[/tex]

Step 1- Take Cos²A common,

[tex] = Cos²A( 1+ cot²A)[/tex]

[tex] \small \sf \: Now \: we \: know \: that \\ \small (1 + Cot^{2} \theta = Cosec^{2} \theta)[/tex]

Step 2 - Substituting above value in step 1,

[tex] = Cos^{2} A(Cosec^2A)[/tex]

[tex] \small \sf \: We \: know \: that \: Cosec \theta= \frac{1}{Sin \theta} [/tex]

Step 3 - Substitute Cosec²A with 1/Sin²A

[tex] = \frac{Cos^2A}{Sin^2A} [/tex]

[tex] \small \sf \: Now \: the \: basic \: trigonometric \: function \: is \\ \small \frac{Cos\theta}{Sin \theta} = Cot\theta[/tex]

Step 4 - Replacing the product of step 3 with above function,

[tex] = {Cot}^{2} A[/tex]

Hence proved,

[tex]R.H.S = L.H.S[/tex]

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

Now let's prove the second relation,

[tex](1-sin²A)(1+cot²A)=cot²A[/tex]

Let's solve for R.H.S.,

[tex]R.H.S.= (1-sin^{2} A)(1+cot^{2} A)[/tex]

As I told above,

[tex]\small(1+cot^{2} \theta) = cosec^{2} \theta[/tex]

Another important relation is,

[tex] \small sin^2\theta + cos^2\theta= 1 \: or \: \\ \small cos^2\theta = 1 - sin^2\theta[/tex]

Replacing both the above brackets with this relation we get,

[tex] = Cos^2A \cdot Cosec^2A [/tex]

Now follow the step 3 and step 4 of first question and you will get,

[tex]R.H.S. = L.H.S.[/tex]

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

Some important trigonometric relations that you must learn,

[tex]Sin^2\theta + Cos^2\theta = 1 \\ 1 + Cot^2\theta = Cosec^2\theta \\ 1+Tan^2\theta = Sec^2\theta[/tex]

[tex] \small\sf \: Thanks \: for \: joining \: brainly \: community! [/tex]

can someone help me with this, it's urgent!​

Answers

Answer:

1. D

2. B

3. E

4. C

5. B

Concept:

From the three examples at the top of the page, the sum of the bottom two parts of the triangle equals to six times the value of the part at the top.

For example, the first one: 20, 10, 5 (Tip)

20 + 10 = 305 × 6 = 30

For example, the second one: 4, 14, 3 (Tip)

4 + 14 = 183 × 6 = 18

Solve:

Question 1

Given information

Tip = 15

Bottom = ?, 51

Determine the sum

15 × 6 = 90

Find the other bottom part

90 - 51 = 39

[tex]\Large\boxed{D.~39}[/tex]

Question 2

Given information

Tip = 9

Bottom = 21, ?

Determine the sum

9 × 6 = 54

Find the other bottom part

54 - 21 = 33

[tex]\Large\boxed{B.~33}[/tex]

Question 3

Given information

Tip = ?

Bottom = 60, 60

Determine the sum

60 + 60 = 120

Find the tip

120 ÷ 6 = 20

[tex]\Large\boxed{E.~20}[/tex]

Question 4

Given information

Tip = ?

Bottom = 18, 30

Determine the sum

18 + 30 = 48

Find the tip

48 ÷ 6 = 8

[tex]\Large\boxed{C.~8}[/tex]

Question 5

Given information

Tip = 12

Bottom = ?, 38

Determine the sum

12 × 6 = 72

Find the other bottom part

72 - 38 = 34

[tex]\Large\boxed{B.~34}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

can someone give the exact answer for all the blanks

Answers

Considering the given function, we have that:

f(a) = 4 - 2a + 6a²f(a + h) = 6a² + 12ah + 6h² - 2a - 2h + 4.[f(a + h) - f(a)]/h = 12a + 6h - 2.

What is the function for this problem?

The function is:

f(x) = 4 - 2x + 6x².

When x = a, we have that:

f(a) = 4 - 2a + 6a².

When x = a + h, we have that:

f(a + h) = 4 - 2(a + h) + 6(a + h)² = 6a² + 12ah + 6h² - 2a - 2h + 4.

For the fraction, we have that:

[f(a + h) - f(a)]/h = [6a² + 12ah + 6h² - 2a - 2h + 4 - 4 + 2a - 6a²]/h = [12ah + 6h² - 2h]/h = h(12a + 6h - 2)/h

Hence:

[f(a + h) - f(a)]/h = 12a + 6h - 2.

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Consider the equation V=6h where V is the volume (in cubic centimeters) of a box with a variable height h in centimeters and a fixed base of area 6cm2.

Answers

The volume (in cubic centimeters) of a box) given the fixed base area of 6cm² and height of 6 cm is 36 cm³.

Volume

V = 6h

Where,

V = volume (in cubic centimeters) of a boxh = height in centimeters and

If the height = 6 cm

Fixed base area = 6 cm²

V = 6h

= 6 cm² × 6 cm

V = 36 cm³

Therefore, the volume of the box given the fixed base area of 6cm² and height of 6 cm is 36 cm³.

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Directions: Find the missing side of each triangle. Round your answers to the nearest tenth if necessary.

Answers

Answer:

1) 13m, 2) 10ft, 3) 11.4ft, 4) 12.7m

Step-by-step explanation:

Since all of these triangles are right triangles, we can use the Pythagorean Theorem: a^2+b^2 = c^2

1) 5^2+12^2 = c^2 = 25+144 = c^2 = 169 = c^2 = 13 = c

2) 6^2+8^2 = c^2 = 36+64 = c^2 = 100 = c^2 = 10 = c

3) 5^2+10.3^2 = c^2 = 25+106.09 = c^2 = 131.09 = c^2 = 11.4494541 = 11.4 = c

4) 8.6^2+9.4^2 = c^2 = 73.96+88.36 = c^2 = 162.32 = c^2 = 12.7404866 = 12.7 = c

The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 39 ounces and a standard deviation of 5 ounces.

Use the Standard Deviation Rule, also known as the Empirical Rule.

Suggestion: sketch the distribution in order to answer these questions.

Answers

The answer to these questions are

Option A: This is in the attachmentOption B : 24 and 54Option C: 97.59%Option D: 84.13%

How to find the point where the distribution lies at 99.7%. The data is 3 sd from mean

Hence

39 - 3*(5) = 24

39 + 3*(5) = 54

The widget lies between 24 and 54

c. P(29.0 < x < 54.0)

= 29 - 39 / 5 and 54 - 39 / 5

= -2.0 and 3.0

We have to find P(Z < 3.0) - P(Z < -2.0)

= 0.9987 - 0.0228

= 97.59%

d. x = 44

= 44 - 39/ 5

= 1

We are to find P(z < 1.0)  = 84.13%

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We will start with a string which is pulled tight enough to vibrate at 288 Hertz when
plucked. Let the length of the string be 1 unit. We can find additional nice sounding
notes by using a string of a smaller length with the same amount of tension. To find
the string lengths, we need to use fractions whose numerators are powers of 2 and
whose denominators are powers of 3 (which are larger than ½, but smaller than 1).
The first few fractions are given below. Determine the remaining fractions:

Answers

The series of fractions is 1, 2/3, 8/9, 16/27, 64/81, 128/243, 512/729, 2048/2187, 4096/6516, 16384/19683, 32768/59049, 131072/177147.

The string lengths are fractions whose numerators are powers of 2 and denominators are powers of 3, and the fractions are larger than 1/2 but smaller than 1.

Some powers of 2 are:

2⁰ = 1, 2¹ = 2, 2² = 4, 2³ = 8, 2⁴ = 16, 2⁵ = 32, 2⁶ = 64, 2⁷ = 128, 2⁸ = 256, 2⁹ = 512, 2¹⁰ = 1024, 2¹¹ = 2048, 2¹² = 4096, 2¹³ = 8192, 2¹⁴ = 16384,  2¹⁵ = 32768, 2¹⁶ = 65536, and 2¹⁷ = 131072.

Some powers of 3 are:

3⁰ = 1, 3¹ = 3, 3² = 9, 3³ = 27, 3⁴ = 81, 3⁵ = 243, 3⁶ = 729, 3⁷ = 2187, 2⁸ = 6561, 3⁹ = 19683, 3¹⁰ = 59049, and 3¹¹ = 177147.

The fractions, for which the numerator is a power of 2, the denominator is a power of 3, and the value is between 1/2 and 1 are:

2/3, 8/9, 16/27, 64/81, 128/243, 512/729, 2048/2187, 4096/6516, 16384/19683, 32768/59049, 131072/177147.

Thus, the series of fractions is 1, 2/3, 8/9, 16/27, 64/81, 128/243, 512/729, 2048/2187, 4096/6516, 16384/19683, 32768/59049, 131072/177147.

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Question: 2 Based on the mass of lactose of 0.28 grams in 1 mL of skim milk, calculate the percent composition of lactose in skim milk.​

Answers

Considering the definition of mass volume percent, the percent composition of lactose in skim milk is 28%.

Mass volume percent

The concentration of solutions is the amount of solute contained in a given amount of solvent or solution. In other words, the relationship between the amount of solute and the amount of solvent is called concentration.

Mass volume percent (% m/V) is a measure of concentration that indicates the number of grams of solute in each 100 mL of solution.

In other words, mass-volume percent is an intensive property that is defined as the mass of solute (in grams) that there are in 100 mL of solution and it is calculated by applying the following equation:

[tex]Mass volume percent=\frac{mass solute (grams)}{volume solution (mL)}x100[/tex]

This is, mass volume percent is defined as the ratio of the mass of solute that is present in a solution, relative to the volume of the solution, as a whole.

Percent composition of lactose in skim milk

In this case, you know:

mass solute= 0.28 gramsvolume solution= 1 mL

Replacing in the definition of mass volume percent:

[tex]Mass volume percent=\frac{0.28 grams}{1 mL}x100[/tex]

Solving:

mass volume percent= 28 %

Finally, the percent composition of lactose in skim milk is 28%.

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40 points
The table shows the heights of students in a group.


Student Height (in inches)
A 45
B 48
C 49
D 40
E 53


What is the mean height of the students in the group?
47 inches
49 inches
51 inches
53 inches

Answers

Answer:

Step-by-step explanation:

answer: 47

add the heights then divide by 5

Information about a play took up 1/3 of the pages in the program. Information about the actors took up 1/4 of the remaining pages. Information about the director, the producer, and the designer took up 2 pages, the same number of pages devoted to the actors. How many pages were there in the program? help pls​

Answers

Answer: 4

Step-by-step explanation:

x - (1/3)x - (1/6)x = 2

(6x - 2x - x)/6 = 2

3x/6 = 2

x=4

2. Brynn borrowed $25,000 at 1% per month from a family friend to start her entrepreneurial venture on December 2, 2011. If she paid back the loan on June 16, 2012, how much simple interest did she pay?

Answers

She paid a simple interest of $3,125.00 on the borrowing of $25,000

What is simple interest?

The simple interest on a loan or an investment can be determined as the principal multiplied by interest multiplied by the number of periods.

This is quite different from compound interest where the interest earned previously would earn interest in the future alongside the principal

I=PRT

I=interest on loan=unknown

P=amount borrowed=$25,000

R=interest rate=1% per month

T=12.5 months( from December 2 2011 to December 1 2012 makes one year and from December 1-16 gives 15 days, which is 0.5 of one month)

I=$25,000*1%*12.5

I=$3,125.00

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For a certain company, the cost function for producing x items is C(x)=50x+100 and the revenue function for selling x items is R(x)=−0.5(x−100)2+5,000 . The maximum capacity of the company is 120 items.



The profit function P(x) is the revenue function R(x) (how much it takes in) minus the cost function C(x) (how much it spends). In economic models, one typically assumes that a company wants to maximize its profit, or at least make a profit!



Answers to some of the questions are given below so that you can check your work.



Assuming that the company sells all that it produces, what is the profit function?
P(x)=

Answers

Assuming that the company sells all that it produces, The profit function is: P(x)=-x^/2+50x -100 or P(x)=-0.5x²+50x -100.

Profit function

Profit = R-C = -(x-100)^2/2 +5000 - 50x -100 =

-(x^2 -200x +10000)/2 -50x +4900 =

-x^2/2 +100x -5000 +5000 -50x +4900

Collect like terms

-x^/2+50x -100

Hence,

Profit function = P(x)=-0.5x²+50x -100

Maximum profit generating output  can be determine by taking the derivative and setting it equal to zero

R-C = -x^2/2 + 50x -100

R'-C' = -x + 50 =0

P(0)x = 50

Maximum profit  can be determine by substituting x=50 into the original profit equation, R-C

P(50) =-(1/2)(50)^2 +50(50) -100

P(50)= -1250 + 2500 -100

P(50) = $1150 profit

P(120) =-(1/2)(120)^2 +50(120) -100

P(120)= -3600 + 6000 -100

P(120) = $2300 profit

Therefore the profit function is: P(x)=-x^/2+50x -100 or P(x)=-0.5x²+50x -100.

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Write an equation of the line that passes through (3,-2) and is parallel to the line y = 2x + 4.

Answers

Answer: [tex]y+2=2(x-3)[/tex]

Step-by-step explanation:

Parallel lines have the same slope, so substituting into point-slope form, the equation is

[tex]y+2=2(x-3)[/tex]

IF THE ODDS AGAINST A PARTICULAR CANDIDATE WINNING AN ELECTION ARE 9
TO 5, WHAT IS THE PROBABILITY THAT THE CANDIDATE WILL WIN?

Answers

The probability that the candidate will win is P = 0.357

How to find the probability?

We know that the odds against the particular candidate are 9 to 5.

The the odds for the candidate are 5 to 9, this means that in 5 cases the candidate will win, and in 9 cases the candidate will lose.

Then the candidate wins in 5 out of 14 cases, then the probability that the particular candidate wins the elections is given by the quotient:

P = 5/14 = 0.357

The probability that the candidate will win is P = 0.357

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Find the area of the trapezoid 19 12.6 29.2 14.5

Answers

Answer:

303.66 in²

Option 4 is the correct answer

Mrs. Smith has a total of 28 kids in her class. There are 5 more boys than there are girls. Write a system of equations to model this.

Answers

Answer:

x+(x+5)=28

Step-by-step explanation:

girls(g)should be equal to x

boys(b) will therefore be x+5

x+(x+5)=28

What is the sum of 3x^3-2x+8,2x^2+5x,and x^3+2x^2-3x-3

Answers

Answer:

4x³ + 4x² + 5

Step-by-step explanation:

3x³ - 2x + 8 + 2x² + 5x + x³ + 2x² - 3x - 3.

4x³ - 2x + 8 + 2x² + 5x + 2x² - 3x - 3

4x³ + 4x² - 2x + 8 + 5x - 3x - 3

4x³ + 4x² + 8 - 3

4x³ + 4x² + 5

Devon is young and has just graduated college with her associate’s degree. She plans to start saving money for retirement as soon as she starts her new job. By taking 10% of her monthly gross income, Devon is able
to contribute (a) $__________ each month to a retirement plan. The account is expected to earn interest with an APR of 5.25% compounded monthly. Round answers to two decimal places.
a. How much money will be in Devon’s retirement account if she continues to make the same monthly
.
investment for 40 years?
b. Overall, Devon contributed how much of her own money into the retirement account?
c. What percent of the final balance in Devon’s retirement account was interest?

You may not ask for help from others or give help to others on specific project questions.
Part 1: Continued
2. Later in life, Devon convinces her friend Taylor to start saving for retirement as well. Even though Taylor is the same age as Devon, she hasn’t started saving for retirement yet. With only 20 years left until they both plan to retire, Taylor decides she needs to invest at least twice as much as Devon each month to try to catch up to Devon’s retirement plan. Taylor opens a similar retirement account to Devon’s that also has an APR
5.25% compounded monthly. She will invest (b) $__________ per month. Round answers to two decimal places.
a. How much money will be in Taylor’s retirement account if she continues to make the same monthly
investment for 20 years?
b. By the time she retires, Taylor will have contributed how much of her own money overall?
c. What percent of the final balance in Taylor’s retirement account will be interest?
3. Write complete sentences that identify which person had the higher amount and by how much. Round answers to two decimal places.
a. Who had more money in their retirement account when they planned to retire? How much more?
b. Who contributed more to their retirement account? How much more?

Answers

Part 1: Devon is able to contribute (a) $450 each month to a retirement plan.

a. The amount in Devon's retirement account if she makes the same monthly investment for 40 years is $733,253.26.

b. Overall, Devon's total contribution of her own money into the retirement account is $216,000.

c. The percent of the final balance in Devon's retirement account that was interest was 70.5%.

Part 2: Taylor will invest (b) $1,733.00 per month.

a. The amount that will be in Taylor's retirement account if she makes the same monthly investment for 20 years is $733,253.26.

b. By the time that Taylor retires, she will have contributed $415,920 of her own money into the account.

c. The percent of the final balance in Taylor's retirement account that will be interest is 43.3%.

3. Both Devon and Taylor had the same amount, $733,253.26, in their retirement accounts when they planned to retire.

a. None had more money at their retirement.

b. Taylor contributed more to her retirement account by $199,920 ($414,920 - $216,000).

Data and Calculations:Devon's Investments:

Gross monthly income = $4,500

APR = 5.25% compounded monthly

N (# of periods) = 480 months (12 x 40 years)

I/Y (Interest per year) = 5.25%

PV (Present Value) = $0

PMT (Periodic Payment) = $450 ($4,500 x 10%)

Results:

FV = $733,253.26 ($517,253.26 + $216,000)

Sum of all periodic payments = $216,000 ($450 x 480)

Total Interest = $517,253.26

Percentage of interest out of the FV = 70.5% ($517,253.26/$733,253.26 x 100)

Taylor's Investment:

N (# of periods) = 240 months (12 x 20 years)

I/Y (Interest per year) = 5.25%

PV (Present Value) = $0

FV (Future Value) = $733,253.26

Results:

PMT = $1,733.00

Sum of all periodic payments = $415,920 ($1,733 x 240

Total Interest = $317,333.26

Percentage of interest out of the FV = 43.3% ($317,333.26/$733,253.26 x 100)

Thus, based on the time value of money of investments, it is more profitable to start investing early.

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Will mark brainliest

Answers

a. The area on [0, 10] is that of a trapezoid with bases 5 and 15 and height 10, so

[tex]\displaystyle \int_0^{10} f(x) \, dx = \frac{5+15}2\cdot10 = \boxed{100}[/tex]

b. By linearity of the definite integral, we have

[tex]\displaystyle \int_0^{25} f(x)\,dx = \int_0^{10} f(x)\,dx + \int_{10}^{25} f(x)\,dx[/tex]

and the area on [10, 25] is another trapezoid with bases 15 and 7.5 and height 15, so that

[tex]\displaystyle \int_{10}^{25} f(x)\,dx = \frac{15+7.5}2\cdot15 = 168.75[/tex]

Then the total area on [0, 25] is

[tex]\displaystyle \int_0^{25} f(x)\,dx = \boxed{268.75}[/tex]

c. The area on [25, 35] is that of a triangle with base 10 and height 15. However, [tex]f(x)<0[/tex] on this interval, so we multiply this area by -1 to get

[tex]\displaystyle \int_{25}^{35} f(x)\,dx = -\frac{10\cdot15}2 = \boxed{-75}[/tex]

d. The area on [15, 25] is the same as the area on [25, 35] because it's another triangle with the same dimensions. But the area on [15, 25] lies above the horizontal axis, so

[tex]\displaystyle \int_{15}^{25} f(x)\,dx = \int_{15}^{25} f(x)\,dx + \int_{25}^{35} f(x)\,dx = \boxed{0}[/tex]

e. The plot of [tex]|f(x)|[/tex] lies above the horizontal axis. We know the area on [15, 25] is the same as the area on [25, 35], but now both areas are positive, so

[tex]\displaystyle \int_{15}^{35} |f(x)| \, dx = \int_{15}^{25} f(x)\,dx - \int_{25}^{35} f(x)\,dx = 2 \int_{15}^{25} f(x)\,dx = \boxed{150}[/tex]

f. Changing the order of the limits in the integral swaps the sign of the overall integral, so

[tex]\displaystyle \int_{10}^0 f(x)\,dx = -\int_0^{10} f(x)\,dx = \boxed{-100}[/tex]

A backyard pool has a concrete walkway around it that is 5' wide on all sides the total area of the pool and the walkway is 950' at the length of the pool is 8' longer than the width find the dimensions of the pool

Answers

The dimensions of the pool would give a quadratic equation x² + 28x - 770 = 0

How to determine the dimension

For the pool, we have that;

Let the width = x feet

Length = (x+8) feet

The pool alongside the walkway gives;

Width = x + 5 + 5 = (x + 10) feet

Length = x + 8 + 5 + 5 = (x + 18) feet

Total area of the pool with walkway = 950 square feet

Note that formula for area is given as

Area = length * width = 950

Equate the length and width

(x+18)  × (x + 10) = 950

Using the  FOIL method, we have;

(x × x )+ (x × 10) + (18 × x) + (18 × 10) = 950

x² + 10x + 18x + 180 -950 = 0  

collect like terms

x² + 28x - 770 = 0

Thus, the dimensions of the pool would give a quadratic equation x² + 28x - 770 = 0

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PLEASE HELP ME QUICK

In the diagram, points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect BA and BC
Then, intersecting arcs of equal size are drawn centered at points D and E. Point P is located at the intersection of these arcs.

Based on this construction, m∠ABP is ANSWER ° and m∠ABC is ANSWER°

Answers

Answer:

m∠ABP  is 32°,m∠ABC is 64°.

Step-by-step explanation:

According to the construction we have:

BD = BEPD = PEBP - is common side of triangles BPD and BPE

It gives us:

ΔPBD ≅ ΔPBE

Then, corresponding angles of congruent triangles are congruent:

∠DBP ≅ ∠EBP

So,

∠ABP ≅ ∠CBP ⇒ m∠ABP = 32°

Then,

m∠ABC = m∠ABP + m∠CBP = 32° + 32° = 64°  

cos 90 - 2sin45 + 2tan180

Answers

Answer:

- [tex]\sqrt{2}[/tex]

Step-by-step explanation:

cos90° - 2sin45° + 2tan180°

= 0 - ( 2 × [tex]\frac{\sqrt{2} }{2}[/tex] ) + 2(0)

= 0 - [tex]\sqrt{2}[/tex] + 0

= - [tex]\sqrt{2}[/tex]

Find a z-score for a data value of 19 if the mean of a set of data is 37 and the standard deviation is 8.6.

Answers

The z-score for a data value of 19 if the mean of a set of data is 37 and the standard deviation is 8.6 is -2.09

How to determine the z-score of the data value?

From the question, the given parameters about the distribution are

Mean value of the set of data = 37

Standard deviation value of the set of data = 8.6

The actual data value = 19

The z-score of the data value is calculated using the following formula

z = (x - mean value)/standard deviation

Substitute the given parameters in the above equation

z = (19 - 37)/8.6

Evaluate the difference of 19 and 37

z = -18/8.6

Evaluate the quotient of -18 and 8.6

z = -2.09

Hence, the z-score for a data value of 19 if the mean of a set of data is 37 and the standard deviation is 8.6 is -2.09

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Which of the following inequalities represents the number line below?

Answers

Answer:

x ≤ 4

Step-by-step explanation:

the solid dot at 4 indicates that x can equal 4

the arrow points to the left indicating values less than 4 , then

x ≤ 4

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