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Find the standard deviation of the data
9, 16, 23 ,30, 37, 44, 51.

the only correct option is that the equation is linear. The correct option is 2.

The given first-order ODE is `xdy/dx = 3xe^x - 2y + 5x^2`. Let's analyze each option:

- The equation is not exact because it cannot be written in the form `M(x,y)dx + N(x,y)dy = 0`.

- The equation is linear because it can be written in the form

`dy/dx + P(x)y = Q(x)`.

- `y=0` is not a solution to the given ODE.

- The equation is not separable because it cannot be written in the form `g(y)dy = f(x)dx`.

- The equation is not homogeneous because it cannot be written in the form `dy/dx = F(y/x)`.

So, the only correct option is that the equation is linear.

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The value of the radius of the pulley was r = 0.01 m, the experimental moment of inertia of the plate is 1.98 x 10^-4 kg m². This is option A

The moment of inertia of a rigid body is a physical quantity that indicates how resistant it is to rotational acceleration around an axis of rotation. Inertia is the term for a property of a body that makes it oppose any force that seeks to modify its motion. The body would be difficult to set into motion or halt if it has a high moment of inertia.

The formula for the moment of inertia is given below:

I = m * r²

where, I is the moment of inertia, m is the mass, and r is the distance from the axis of rotation to the center of mass.

The following is the procedure for calculating the moment of inertia of the plate from the angular velocity versus time graph:

Find the slope of the linear part of the graph to calculate the angular acceleration by the formula α = slope.Substitute the values into the formula τ = Iα to calculate the torque acting on the plate.

Substitute the values into the formula τ = F * r to determine the force acting on the plate.The weight of the hanging mass is converted to force F by the formula F = mg.

Substitute the values into the formula I = m * r²/α to obtain the moment of inertia.

I = m * r²/αI = (0.050 kg) * (0.01 m)²/ (5.5 rad/s²)

I = 1.98 x 10^-4 kg m²

Hence, the experimental moment of inertia of the plate is 1.98 x 10^-4 kg m².

So, the correct answer is A

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No, 1,1,1, , , is not an arithmetic sequence because there is no common difference between the terms.

The given sequence is 1,1,1, , ,. If it is arithmetic, then we need to identify the common difference. Let's try to find out the common difference between the terms of the sequence 1,1,1, , ,There is no clear common difference between the terms of the sequence given. There is no pattern to determine the next term or terms in the sequence.

Therefore, we can say that the sequence is not arithmetic. So, the answer to this question is: No, the sequence is not arithmetic because there is no common difference between the terms.

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Answer:

F(×)=2(3*)f(×)=3(2×)

The function that models the height of the triangle becomes y=50 tan θ . c. When θ = 22°, the height of the triangle is approximately 20.20 ft.

To find the height of the triangle when θ = 22°, we can use the given function y = 50 tan θ.

In the given function, y represents the height of the triangle, and θ represents the angle between the base of the triangle and the hypotenuse.

We are given that the length of the base of the triangle is reduced to 100 ft. So now we have a right triangle with a base of 100 ft.

We need to find the height of the triangle when the angle θ is 22°.

Substituting the given values into the function, we have:

y = 50 tan(22°)

To evaluate this expression, we can use a scientific calculator or trigonometric tables.

Using a calculator, we find that the tangent of 22° is approximately 0.4040.

Now we can substitute this value back into the equation:

y = 50 * 0.4040

Simplifying the calculation:

y ≈ 20.20 ft

Therefore, when θ = 22°, the height of the triangle is approximately 20.20 ft.

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a. The truck rental cost when you drive 85 miles is  $85.7.

b. The number of miles driven when the cost is $65.96 is 0.42x.

a. To find the truck rental cost when driving 85 miles, we can substitute the value of x into the given function.

f(x) = 0.42x + 50

Substituting x = 85:

f(85) = 0.42(85) + 50

= 35.7 + 50

= 85.7

Therefore, the truck rental cost when driving 85 miles is $85.70.

b. To determine the number of miles driven when the cost is $65.96, we can set up an equation using the given function.

f(x) = 0.42x + 50

Substituting f(x) = 65.96:

65.96 = 0.42x + 50

Subtracting 50 from both sides:

65.96 - 50 = 0.42x

15.96 = 0.42x

To isolate x, we divide both sides by 0.42:

15.96 / 0.42 = x

38 = x

Therefore, the number of miles driven when the cost is $65.96 is 38 miles.

In summary, when driving 85 miles, the truck rental cost is $85.70, and when the cost is $65.96, the number of miles driven is 38 miles.

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The similarity lies in the fact that both lists contain the same set of numbers, but their order is determined by different criteria - one based on magnitude and the other based on distance from zero.

Let's order the numbers -3, 5, -10, and 16 as requested.

From least to greatest:

-10, -3, 5, 16

The ordered list from least to greatest is: -10, -3, 5, 16.

Now let's order the same numbers from closest to zero to farthest from zero:

-3, 5, -10, 16

The ordered list from closest to zero to farthest from zero is: -3, 5, -10, 16.

Regarding the similarity between the two lists, both lists contain the same set of numbers: -3, 5, -10, and 16. However, the ordering criteria are different in each case. In the first list, we order the numbers based on their magnitudes, whereas in the second list, we order them based on their distances from zero.

By comparing the two lists, we can observe that the ordering changes since the criteria differ. In the first list, the number -10 appears first because it has the smallest magnitude, while in the second list, -3 appears first because it is closest to zero.

Overall, the similarity lies in the fact that both lists contain the same set of numbers, but their order is determined by different criteria - one based on magnitude and the other based on distance from zero.

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The equation is true for n = k+1. So, the equation is true for all natural numbers 'n'.

To prove the equation by mathematical induction,

N N Ž~- (2-) n³ = n=1 n=1

it is necessary to follow the below steps.

1: Basis: When n = 1, N N Ž~- (2-) n³ = 1

Therefore, 1³ = 1

The equation is true for n = 1.

2: Inductive Hypothesis: Let's assume that the equation is true for any k, i.e., k is a natural number.N N Ž~- (2-) k³ = 1³ + 2³ + ... + k³ - 2(1²) - 4(2²) - ... - 2(k-1)²

3: Inductive Step: Now, we need to prove that the equation is true for k+1.

N N Ž~- (2-) (k+1)³ = 1³ + 2³ + ... + k³ + (k+1)³ - 2(1²) - 4(2²) - ... - 2(k-1)² - 2k²

The LHS of the above equation can be expanded to: N N Ž~- (2-) (k+1)³= N N Ž~- (2-) k³ + (k+1)³ - 2k²= (1³ + 2³ + ... + k³ - 2(1²) - 4(2²) - ... - 2(k-1)²) + (k+1)³ - 2k²

This is equivalent to the RHS of the equation. Hence, the given equation is proved by mathematical induction.

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The cyclonona-1,3,5,7-tetraene is classified as non-aromatic based on the inscribed polygon method.

By using the inscribed polygon method, we can determine the aromaticity of cyclonona-1,3,5,7-tetraene. The molecule consists of a cyclic structure with alternating single and double bonds. The inscribed polygon method involves drawing an imaginary polygon inside the molecule, following the path of the pi electrons. If the number of pi electrons in the molecule matches the number of electrons in the inscribed polygon, the molecule is considered aromatic.

If the number of pi electrons differs by a multiple of 4, the molecule is antiaromatic. In this case, cyclonona-1,3,5,7-tetraene has 8 pi electrons, which does not match the number of electrons in any inscribed polygon, making it non-aromatic.

Cyclonona-1,3,5,7-tetraene is a cyclic molecule with alternating single and double bonds. To determine its aromaticity using the inscribed polygon method, we draw an imaginary polygon inside the molecule, following the path of the pi electrons.

In the case of cyclonona-1,3,5,7-tetraene, we have a total of 8 pi electrons. We can try different polygons with varying numbers of sides to see if any match the number of electrons. However, regardless of the number of sides, no inscribed polygon will have 8 electrons.

For example, if we consider a hexagon (6 sides) as the inscribed polygon, it would have 6 electrons. If we consider an octagon (8 sides), it would have 8 electrons. However, cyclonona-1,3,5,7-tetraene has neither 6 nor 8 pi electrons. This indicates that the molecule is not aromatic according to the inscribed polygon method.

Therefore, cyclonona-1,3,5,7-tetraene is classified as non-aromatic based on the inscribed polygon method.

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The determinant of the given matrix is 15.

By observing the matrix [4 6 -1 2 3 2 1 -1 1], we get the value of the determinant to be 15.

To verify this result, we can compute the determinant as follows:`Δ = [4(3(-1) - (-1)(2)) - 6(2(-1) - 1(2)) + (-1)(2(2) - 3(1))]

`Expanding the equation, we get: `Δ = [4(-5) - 6(-6) + (-1)(-1)]`

Δ = [-20 + 36 - 1]

`Δ = 15`

Therefore, the determinant of the given matrix is 15.

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Answer:

sin (Q) = 15/17

sin (R) = 8/17

cos (Q) = 8/17

cos (R) = 15/17

tan (Q) = 15/8

tan (R) = 8/15

Step-by-step explanation:

Step 1:  Find the length of side QR (i.e., the hypotenuse):

a^2 + b^2 = c^2, where

Thus, we can plug in 16 and 30 for a and b to find x, the hypotenuse (aka the length of side QR):

16^2 + 30^2 = c^2

256 + 900 = c^2

1156 = c^2

√1156 = √1156

34 = c

Thus, the length of side QR (the hypotenuse) is 34 units.

Step 2:  Find sin Q and sin R:

sin Q:

The sine ratio is given by sin (θ) = opposite / hypotenuse, where

Thus, sin (Q) = 30/34.  This simplifies to sin (Q) = 15/17.

sin R:

When angle R is the reference angle, QS is the opposite side and QR is the hypotenuse.

Thus sin (R) = 16/34.  This simplifies to sin(R) = 8/17.

Step 3:  Find cos Q and cos R:

The cosine ratio is given by:

cos (θ) = adjacent / hypotenuse, where

cos Q:

Thus cos (Q) = 16/34.  This simplifies to cos (Q) = 8/17.

cos R:

Thus, cos (R) = 30/34.  This simplifies to cos (R) = 15/17.

Step 4:  Find tan Q and tan R:

The tangent ratio is given by:

tan (θ) = opposite / adjacent, where

tan (Q):

Thus tan (Q) = 30/16.  This simplifies to tan (Q) = 15/8.

tan (R):

Thus, tan (R) = 16/30.  This simplifies to tan (R) = 8/15.

The ingredients provided will make approximately 1 and 11/24 cups of lemonade.

1. The problem states that the lemonade recipe requires specific quantities of lemon juice, sugar, and water, given as fractions. These fractions have different denominators, which means they cannot be added directly.

2. To add fractions with different denominators, we need to find a common denominator. In this case, the least common multiple (LCM) of the denominators 6, 4, and 8 is 24.

3. We convert the fraction for each ingredient to have a common denominator of 24:

  a. For the 5/6 cup of lemon juice, we multiply the numerator and denominator by 4 to get (5/6) * (4/4) = 20/24 cup of lemon juice.

  b. For the 1/4 cup of sugar, we multiply the numerator and denominator by 6 to get (1/4) * (6/6) = 6/24 cup of sugar.

  c. For the 3/8 cup of water, we multiply the numerator and denominator by 3 to get (3/8) * (3/3) = 9/24 cup of water.

4. Now that all the fractions have the same denominator, we can add them together:

  20/24 cup of lemon juice + 6/24 cup of sugar + 9/24 cup of water = 35/24 cup of lemonade.

5. The resulting fraction 35/24 represents the total amount of lemonade made with the given ingredient quantities. However, since 35/24 is greater than 1 (the whole), we can simplify it to a mixed number.

6. By dividing 35 by 24, we get 1 as the whole number and a remainder of 11. Therefore, the mixed number representation of 35/24 is 1 11/24.

7. Thus, the ingredients provided will make approximately 1 and 11/24 cups of lemonade.

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The solution to the system of linear equations is x = 3 and y = 5.

To solve the system of linear equations using elimination, we manipulate the equations to eliminate one variable. Let's consider the given system:

Equation 1: 5x + 3y = 30

Equation 2: 10x + 3y = 45

We can eliminate the variable y by multiplying Equation 1 by -2 and adding it to Equation 2:

-10x - 6y = -60

10x + 3y = 45

The x-term cancels out, and we are left with -3y = -15. Solving for y, we find y = 5. Substituting this value back into Equation 1 or Equation 2, we can solve for x:

5x + 3(5) = 30

5x + 15 = 30

5x = 15

x = 3

Therefore, the solution to the system of linear equations is x = 3 and y = 5.

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(a) For the recursive definition f(n+1) = -3f(n), f(1) = -9, f(2) = 27, f(3) = -81, f(4) = 243.(b) For the recursive definition f(n+1) = 3f(n) + 4, f(1) = 13, f(2) = 43, f(3) = 133, f(4) = 403.(c) For the recursive definition f(n+1) = f(n)^2 - 3f(n) - 4, f(1) = -2, f(2) = 8, f(3) = 40, f(4) = 1556.

In the given recursive definitions:

(a) For f(n+1)=-3f(n), the function is multiplied by -3 at each step, resulting in alternating signs. This pattern can be observed in the values of f(1)=-9, f(2)=27, f(3)=-81, f(4)=243.(b) For f(n+1)=3f(n)+4, the function is multiplied by 3 and then 4 is added at each step. This leads to an increasing sequence of values. This pattern can be observed in the values of f(1)=7, f(2)=25, f(3)=79, f(4)=241.

(c) For f(n+1)=f(n)^2-3f(n)-4, the function is squared and then subtracted by 3 times itself, followed by subtracting 4. This leads to a more complex pattern in the sequence of values. The values of f(1)=-3, f(2)=-4, f(3)=4, f(4)=20 can be obtained by applying the recursive rule.

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The average rate of change for the function f(x) = 2x³ - 5x² + 3 over the interval from x = -1 to x = 2 is 1. This means that on average, the function increases by 1 unit for every unit increase in x over that interval.

To find the average rate of change for the function f(x) = 2x³ - 5x² + 3 over the interval from x = -1 to x = 2, we can use the formula:

Average rate of change = (f(2) - f(-1)) / (2 - (-1))

First, let's calculate the values of f(2) and f(-1):

f(2) = 2(2)³ - 5(2)² + 3

     = 2(8) - 5(4) + 3

     = 16 - 20 + 3

     = -1

f(-1) = 2(-1)³ - 5(-1)² + 3

      = 2(-1) - 5(1) + 3

      = -2 - 5 + 3

      = -4

Now we can substitute these values into the formula:

Average rate of change = (-1 - (-4)) / (2 - (-1))

                     = (-1 + 4) / (2 + 1)

                     = 3 / 3

                     = 1

Therefore, the average rate of change for f(x) over the interval -1 to 2 is 1.

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The probability describing this event is 1.

The probability of an event is a measure of the likelihood that the event will occur. In this case, when it is stated that an event will happen, the probability of that event occurring is 1. A probability of 1 indicates absolute certainty that the event will happen. It means that the event is guaranteed to occur and there is no chance of it not happening.

In probability theory, a probability of 1 represents a certain event. It signifies that the event will occur without any doubt. This certainty arises when all possible outcomes are accounted for, and there is no room for any other outcome to happen. In other words, when the probability is 1, there is a 100% chance of the event taking place. This is in contrast to probabilities less than 1, where there is some level of uncertainty or possibility for other outcomes to occur.

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The  graph shows a function and its is the graph in option A.

The original path is reflected on the line y = x. The two functions are said to be inverses of one another if the graphs of both functions are symmetric with respect to the line y = x. This is due to the fact that (y, x) lies on the inverse function of the function if (x, y) lies on the original function.

The inverse function is shown on a graph with the use of a vertical line test. The line has a slope and travels through the origin.

Instance is the  f(x) = 2x + 5 = y. Then, is the inverse of [tex]g(y) = \frac{ (y-5)}{2} = x[/tex] f(x).Reflecting over the y and x gives us the function of the inverse.

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Hiya, hope these help! :)

Formula for a triangle: A=1/2(base of triangle x height of triangle)

Triangle a: 120cm²
A= 1/2(b x h)
A= 1/2(20 x 12)
A= 1/2 (240)
A= 120

Triangle b: 72cm²
A= 1/2(b x h)
A= 1/2(12 x 12)
A= 1/2 (144)
A= 72

Triangle c: 154cm²
A= 1/2 (b x h)
A= 1/2 (28 x 11)
A= 1/2 (308)
A= 154

Triangle d: 49cm²
A= 1/2 (b x h)
A= 1/2 (14 x 7)
A= 1/2 (98)
A= 49

Triangle e: 105cm²
A= 1/2 (b x h)
A= 1/2 (14 x 15)
A= 1/2 (210)
A= 105

Triangle f: 160cm²
A= 1/2 (b x h)
A= 1/2 (20 x 16)
A= 1/2 (320)
A= 160

Triangle g is missing the base number! It's not shown fully in the screenshot, therefore it will just be whatever answer is leftover! :)

Triangle h: 288cm²
A= 1/2 (b x h)
A= 1/2 (36 x 16)
A= 1/2 (576)
A= 288

Let me know if you have any more questions!

The geometric average of -10%, 20%, and 40% is approximately -20.2%.

To find the geometric average of a set of numbers, you need to multiply them together and then take the nth root, where n is the number of values.

In this case, we have three values: -10%, 20%, and 40%.

Step 1: Convert the percentages to decimal form by dividing by 100.

-10% becomes -0.10

20% becomes 0.20

40% becomes 0.40

Step 2: Multiply the decimal values together.

-0.10 * 0.20 * 0.40 = -0.008

Step 3: Take the cube root (since we have three values) of the result.

∛(-0.008) ≈ -0.202

Step 4: Convert the result back to a percentage by multiplying by 100.

-0.202 * 100 ≈ -20.2%

Therefore, the geometric average of -10%, 20%, and 40% is approximately -20.2%.

None of the given options (11.2%, 14.8%, 20.3%, and 21.4%) matches the calculated value.

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Answer:

a) ∠BAD  = 67.4

b)  ∠BDC = 22.6

c) BC = 4.6

Step-by-step explanation:

a) tan θ = opposite/adjacent

In Δ ABD,

tan ∠BAD = DB/AD

tan ∠BAD =  12/5

∠BAD = tan⁻¹(12/5)

∠BAD  = 67.4

b) In  In Δ ABD,

∠BAD + ∠ABD + ∠ADB = 180°

⇒ ∠ABD = 180 - ∠BAD - ∠ADB

= 180 - 67.4 - 90

∠ABD = 22.6

In trapezium, since AB and DC are parallel,

∠BDC = ∠ABD (alternate interior angles)

⇒ ∠BDC = 22.6

c) In  In Δ ABD,

AB² = AD² + DB²

= 5² + 12²

= 25 + 144

= 169

= 13²

AB² = 13²

⇒ AB = 13

In Δ ABD and Δ BDC,

∠ADB = ∠BCD

∠ABD = ∠BDC

Since two angles are equal, the thrid angle must also be equal

∠BAD = ∠BDC

∴ Δ ABD and Δ BDC are similar

∴ the ratio of the corresponding sides should be equal

⇒ [tex]\frac{BD}{AB} = \frac{BC}{AD}= \frac{DC}{BD} \\[/tex]

[tex]\implies \frac{12}{13} = \frac{BC}{5}= \frac{DC}{12} \\\\\\\implies \frac{12}{13} = \frac{BC}{5}\\\\\implies BC = \frac{12*5}{13}\\\\\implies BC = \frac{60}{13}[/tex]

⇒ BC = 4.6

In a circle with a radius of 12 m, the length of the arc that subtends a central angle of measure 70° is roughly 8.37 m.

To find the length of the arc that subtends a central angle of measure 70° in a circle of radius 12 m, we can use the formula:

Length of arc = (Angle measure/360°) * 2 * π * radius

In this case, the angle measure is 70° and the radius is 12 m. Plugging these values into the formula, we get:

Length of arc = (70°/360°) * 2 * π * 12 m

Simplifying this expression, we have:

Length of arc = (7/36) * 2 * π * 12 m

To evaluate this expression, we can first simplify the fraction:

Length of arc = (7/18) * 2 * π * 12 m

Multiplying the fraction by 2, we get:

Length of arc = (7/18) * 2 * π * 12 m

Length of arc = (14/18) * π * 12 m

Next, we can simplify the fraction by dividing both the numerator and denominator by their greatest common divisor, which is 2:

Length of arc = (7/9) * π * 12 m

Finally, multiplying the remaining terms, we have:

Length of arc = 7/9 * 12 * π m

Length of arc ≈ 8.37 m

Therefore, the length of the arc that subtends a central angle of measure 70° in a circle of radius 12 m is approximately 8.37 m.

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The value of the account at the end of the 2-year period would be $6,497.14.

Given data:

The formula to calculate the value of the account with compound interest is [tex]A = P * (1 + R/n)^{n*t}[/tex]

Substituting values:

[tex]A = 6000 * (1 + 0.04/4)^{4*2}\\A = 6000 * (1 + 0.01)^8\\A = 6000 * (1.01)^8\\A = 6,497.14023377\\A = 6,497.14[/tex]

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The value of the account at the end of the specified time period, with a principal of $6,000, an annual interest rate of 4% compounded quarterly, and a time period of 2 years, is approximately $6489.60.

Given a principal amount of $6,000, an annual interest rate of 4% compounded quarterly, and a time period of 2 years, we need to determine the value of the account at the end of the specified time period.

To calculate the value of the account at the end of the specified time period, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A is the future value of the account,

P is the principal amount,

r is the annual interest rate (expressed as a decimal),

n is the number of compounding periods per year, and

t is the time period in years.

Given the values:

P = $6,000,

r = 0.04 (4% expressed as 0.04),

n = 4 (compounded quarterly), and

t = 2 years,

We can plug these values into the formula:

A = 6000(1 + 0.04/4)^(4*2)

Simplifying the equation:

A = 6000(1 + 0.01)^8

A = 6000(1.01)^8

A ≈ 6000(1.0816)

Evaluating the expression:

A ≈ $6489.60

Therefore, the value of the account at the end of the specified time period, with a principal of $6,000, an annual interest rate of 4% compounded quarterly, and a time period of 2 years, is approximately $6489.60.

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The number of free samples given for chocolate chip is approximately 67. The yogurt stand gave out approximately 67 free samples of vanilla, 67 free samples of chocolate, and 67 free samples of chocolate chip.

The given statement is related to a yogurt stand that gave out 200 free samples of frozen yogurt, one free sample per person. The three sample choices were vanilla, chocolate, or chocolate chip.Let's determine the number of free samples given for each flavor of frozen yogurt:Vanilla: Let the number of free samples given for vanilla be xx + x + x = 2003x = 200x = 200/3.Therefore, the number of free samples given for vanilla is approximately 67.

Chocolate: Let the number of free samples given for chocolate be yy + y + y = 2003y = 200y = 200/3 Therefore, the number of free samples given for chocolate is approximately 67.Chocolate Chip: Let the number of free samples given for chocolate chip be zz + z + z = 2003z = 200z = 200/3 Therefore, the number of free samples given for chocolate chip is approximately 67. Therefore, the yogurt stand gave out approximately 67 free samples of vanilla, 67 free samples of chocolate, and 67 free samples of chocolate chip.

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The first six terms of the sequence defined by the formula an = n² + 1 are 2, 5, 10, 17, 26, and 37.

The first six terms of the sequence defined by the formula an = n² + 1 are:

a1 = 1² + 1 = 2

a2 = 2² + 1 = 5

a3 = 3² + 1 = 10

a4 = 4² + 1 = 17

a5 = 5² + 1 = 26

a6 = 6² + 1 = 37

The sequence starts with 2, and each subsequent term is obtained by squaring the term number and adding 1. For example, a2 is obtained by squaring 2 (2² = 4) and adding 1, resulting in 5. Similarly, a3 is obtained by squaring 3 (3² = 9) and adding 1, resulting in 10.

This pattern continues for the first six terms, where the term number is squared and 1 is added. The resulting sequence is 2, 5, 10, 17, 26, 37.

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The interest earned in a savings account is $10.

Given: Balance = $1000 Interest rate = 1% Compounded yearly Time = 12 months (1 year). We can calculate the interest earned in a savings account using the formula; A = [tex]P(1 + r/n)^ (^n^t^),[/tex] Where, A = Total amount (principal + interest) P = Principal amount (initial investment) R = Annual interest rate (as a decimal)

N = Number of times the interest is compounded per year T = Time (in years). First, we need to convert the annual percentage rate (APY) to a decimal by dividing it by 100.1% APY = 0.01 / 1 = 0.01

Next, we plug in the values into the formula; A = [tex]1000(1 + 0.01/1)^(1×1)[/tex]A = 1000(1.01) A = $1010. After 12 months on a balance of $1000 at an interest rate of 1% APY compounded yearly, the interest earned in a savings account is $10. Answer: $10

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Answer:

RS + ST = RT

9 + 2x - 6 = x + 7

2x - 3 = x + 7

x = 10

Answer:

The t-distribution, also known as the Student's t-distribution, is a type of probability distribution that is similar to the normal distribution with its bell shape but has heavier tails. It estimates population parameters for small sample sizes or unknown variances.

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