Now I skipped the question but I have a recollection of what it looks like :)

Answer:

.

Step-by-step explanation:

.............................

Answer:

mike spent 6 dollars, each pen cost 2$

Answer:

-1,0 and -11,0 because you already factored and solved.

Answer:

at 7 months old, the cat weighs 4 kilograms

Step-by-step explanation:

all functions have an input and output. in this case, the question tells us that the information you put into the function is how many months old the kitten is, which is your input, 7. your output is the weight of the kitten in kilograms, so 4.

Answer:

Not it is not a whole number, since when divided, it is a decimel

[tex](-\dfrac{1}{3})\cdot(\dfrac{3}{5})\cdot(-\dfrac{5}{7})=-\dfrac{1}{5}\cdot(-\dfrac{5}{7})=\boxed{\frac{1}{7}}[/tex]

Answer: 1/7

Step-by-step explanation: use math  way next time

Answer:

I think its P= 34/41. sorry

Answer:

34/41 yuuhhhh

Step-by-step explanation:

Answer:

Number 8 the answer is 120

Number 10 answer is 115

Step-by-step explanation:

8. 180-60=120

it's because the straight line is 180 then you just need to solve it use this

10. 180-65=115

the reason same like number 8

Hope this answer can help you to solve the math problems

Answer: Ello mate, this image I provided below should help you out, let me know if you need anything else.

Step-by-step explanation:

Step-by-step explanation:

5/11 as a decimal is 0.45454545454545

Answer:

5/11 as a decimal is 0.45454545454545

Step-by-step explanation:

Answer:

true is answerrrrrrrrrr

Answer:

it would be false

Step-by-step explanation:

Answer:

You cant check your answer by yourself

if your procces is Right then obviously your answer will be correct

I hope you will understand

thank you

jay Nepal

Answer: i think it is.

you cant divide both numbers by the same number

Step-by-step explanation:

Answer:

[tex]\displaystyle \text{(1)}\\x=1+\sum_{k=1}^{n-1}2k\\\\\text{(2)}\\\displaystyle \frac{\displaystyle \sum_{k=1}^{n}2k\left(1+\displaystyle \sum_{k=1}^{n}2k \right)}{2}-\frac{\displaystyle \sum_{k=1}^{n-1}2k\left(1+\displaystyle \sum_{k=1}^{n-1}2k \right)}{2}[/tex]

Step-by-step explanation:

Notice that Group 1 starts with 1 and we keep counting up by 1.

Part 1:

The total number of numbers from Group 1 to Group [tex]n[/tex] can be found by:

[tex]\displaystyle \sum_{k=1}^{n}2k[/tex]

To find the first number in a certain group [tex]g[/tex], we'll find the total number of numbers from Group 1 to Group [tex]g-1[/tex], then add 1.

Here's why.

Let's say we want to find the first number of Group 3, which we can clearly see is 7. Take advantage of the fact that the sequence of numbers counts up by 1, starting from 1. We will use the formula above to to find the total number of numbers from Group 1 to Group 2, which is 6, then add 1 to achieve the number of 7.

Therefore, the first number in group [tex]n[/tex] must be:

[tex]\boxed{\displaystyle 1+\sum_{k=1}^{n-1}2k}[/tex]

Part 2:

Recall that the sum of the numbers from [tex]1[/tex] to positive integer [tex]n[/tex] inclusive is given by [tex]\displaystyle\frac{n(n+1)}{2}[/tex].

Therefore, if we find the total number of numbers from Group 1 to Group [tex]n[/tex], we can simply substitute that value into the formula above to find the total sum of the numbers from Group 1 to Group [tex]n[/tex].

To find the total sum of the numbers exclusively in Group [tex]n[/tex] simply subtract the sum of numbers from Group 1 to Group [tex]n-1[/tex].

Short example on how that works:

The sum of all numbers in Group 3 is equal to the sum of the numbers from Group 1 to Group 3 minus the sum of the numbers from Group 1 to Group 2.

We've already found the formula for the total number of numbers from Group 1 to Group [tex]n[/tex] in the previous part, so convert this concept into summation notation like such:

[tex]\boxed{\displaystyle \frac{\displaystyle \sum_{k=1}^{n}2k\left(1+\displaystyle \sum_{k=1}^{n}2k \right)}{2}-\frac{\displaystyle \sum_{k=1}^{n-1}2k\left(1+\displaystyle \sum_{k=1}^{n-1}2k \right)}{2}}[/tex]

Answer:

A. B and F

Step-by-step explanation:

.................

The answer could be ∠B and  ∠F

Answer:

142 is the answer of this your homework

Answer:

(c) Write a directed number to show this single journey.

Step-by-step explanation:

9514 1404 393

Answer:

  AB = 6

  BC = 12

Step-by-step explanation:

AB +BC = AC

  x + 2x = 18

  x = 18/3 = 6

AB = x = 6

BC = 2x = 2·6 = 12

Answer:

the orange line is the reflection y=-1

To plot the reflection of a function across the line y = -1, you'll need to follow these steps:Understand Reflection Across a Line: Reflection across a line involves flipping the points of the original function over the given line.

For reflection across the line y = -1, you'll be swapping the positions of the points above the line with those below it.

Choose a Function: Let's say you want to plot the reflection of a function f(x) across y = -1. Choose a function that you want to reflect. For demonstration purposes, let's consider a simple quadratic function, [tex]f(x) = x^2.[/tex]

Calculate the Reflected Points: To calculate the reflected points, follow these steps for each point (x, y) on the original function:

a. Find the vertical distance between the point and the reflection line (y = -1). This distance is the difference between the original y-coordinate and -1: distance = y - (-1) = y + 1.

b. The reflected y-coordinate (y') will be -1 minus the distance calculated in the previous step: y' = -1 - distance = -1 - (y + 1) = -2 - y.

c. The x-coordinate remains the same: x' = x.

d. The reflected point is (x', y').

Plot the Reflected Points: Plot the original function f(x) and then plot the reflected points (x', y') that you calculated in the previous step. This will show you the reflection of the function across y = -1.

To know more about reflection:

https://brainly.com/question/15487308

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[tex] \large \mathfrak{Solution : }[/tex]

let's solve :

[tex] \huge \boxed{\mathfrak{Question} \downarrow}[/tex]

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

[tex] \sf2 [ 30 - ( 1 + 4 ) ^ { 2 } ][/tex]

[tex] \sf2\left(30-5^{2}\right) [/tex]

[tex] \sf2\left(30-25\right) [/tex]

[tex] \sf2\times 5 [/tex]

[tex] \boxed{ \boxed{ \boxed{ \mathfrak{ = 10}}}}[/tex]