Basic blocks are identified because they are known to be a straight line that is known also as a code sequence that tends to have no branches in regards to its in and out branches and its exception is only to the entry and at the end.
Note that Basic Block is said to be a composition of statements that is known to be one that often always executes one after other, and this is often done in a sequence.
How do you create a flow graph from the basic blocks?Flow graph is gotten by:
Lets Block B1 be the initial node and also Block B2 will tend to follows B1, so from B2 to B1 there is seen a kind of an edge.Note that the first task is for a person to partition a sequence of three-address code and this is done into basic blocks.
Hence, Basic blocks are identified because they are known to be a straight line that is known also as a code sequence that tends to have no branches in regards to its in and out branches and its exception is only to the entry and at the end.
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pleaseeeee helpppppppp
Answer:
int
Explanation:
a (signed) int has a higher rank than a char, therefore the result will be int, and an implicit type promotion will take place.
What relation between two sets S and T must hold so that |S ∪ T| = |S| + |T|
Suppose S and T are sets. Then the intersection of S and T, denoted S∩T, is the set whose elements are only those that are elements of S and of T.
What is |S ∪ T| = |S| + |T|?DeMorgan’s Set Theory Laws
In Set Theory, there are analogous relationships called DeMorgan’s Set
Theory Laws. These laws are exactly the analogues of the corresponding logic
laws, where is replace by the complement, ∧ is replace by ∩, and ∨ is replaced
by ∪. DeMorgan’s Set Theory Laws are stated below:
S ∩ T = S ∪ T and S ∪ T = S ∩ T .
We will prove the latter of these below.
Theorem. Let S and T be sets. Then,
S ∪ T = S ∩ T .
two sets S and T must hold so that |S ∪ T| = |S| + |T|
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Line formatting can be accomplished by using
Answer:
How can line formatting be accomplished?
To format line spacing:
Select the text you want to format. Selecting text to format.
On the Home tab, click the Line and Paragraph Spacing command. A drop-down menu will appear.
Move the mouse over the various options. A live preview of the line spacing will appear in the document. Select the line spacing you want to use.
The line spacing will change in the document.
Input a list of employee names and salaries and store them in parallel arrays. End the input with a sentinel value. The salaries should be floating point numbers Salaries should be input in even hundreds. For example, a salary of 36,510 should be input as 36.5 and a salary of 69,030 should be entered as 69.0. Find the average of all the salaries of the employees. Then find the names and salaries of any employee who's salary is within 5,000 of the average. So if the average is 30,000 and an employee earns 33,000, his/her name would be found. Display the following using proper labels. Save your file using the naming format LASTNAME_FIRSTNAME_M08 FE. Turn in your file by clicking on the Start Here button in the upper right corner of your screen. 1.Display the names and salaries of all the employees. 2. Display the average of all the salaries 3. Display all employees that are within 5,000 range of the average.
Using the knowledge in computational language in JAVA it is possible to write the code being Input a list of employee names and salaries and store them in parallel arrays
Writting the code in JAVA:
BEGIN
DECLARE
employeeNames[100] As String
employeeSalaries[100] as float
name as String
salary, totalSalary as float
averageSalary as float
count as integer
x as integer
rangeMin, rangeMax as float
INITIALIZE
count = 0;
totalSalary =0
DISPLAY “Enter employee name. (Enter * to quit.)”
READ name
//Read Employee data
WHILE name != “*” AND count < 100
employeeNames [count] = name
DISPLAY“Enter salary for “ + name + “.”
READ salary
employeeSalaries[count] = salary
totalSalary = totalSalary + salary
count = count + 1
DISPLAY “Enter employee name. (Enter * to quit.)”
READ name
END WHILE
//Calculate average salary with mix , max range
averageSalary = totalSalary / count
rangeMin = averageSalary - 5
rangeMax = averageSalary + 5
DISPLAY “The following employees have a salary within $5,000 of the mean salary of “ + averageSalary + “.”
For (x = 0; x < count; x++)
IF (employeeSalaries[x] >= rangeMin OR employeeSalaries[x] <= rangeMax )
DISPLAY employeeNames[x] + “\t” + employeeSalaries[x]
END IF
END FOR
END
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convert the following decimaal numbers to octal numbers
1. 500
2. 169
3. 53
4.426
1. 500--->764
2. 169--->251
3. 53--->65
4.426--->652
