object 1 and 2 are identical. object 1 is dropped from 40 m high, while object 2 is dropped from 10 m high. ignoring air resistance, when they hit the ground the kinetic energy of object 1 is:

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Answer 1

The mass of the objects is not given, the kinetic energy of Object 1 can be expressed as: KE = 392.4m (Joules, where m is the mass of the object)

Object 1 and 2 are identical. Object 1 is dropped from 40 m high, while object 2 is dropped from 10 m high. Ignoring air resistance, when they hit the ground, the kinetic energy of Object 1 can be calculated using the equation:

KE = 0.5 * m * v^2

Where KE is the kinetic energy, m is the mass of the object, and v is the final velocity.

Since both objects are identical, their masses are the same. To find the final velocity, we can use the equation:

v^2 = 2 * g * h

Where g is the acceleration due to gravity (approximately 9.81 m/s^2) and h is the height from which the object is dropped.

For Object 1, h = 40 m, so:

v^2 = 2 * 9.81 * 40
v^2 ≈ 784.8

Now, we can calculate the kinetic energy of Object 1:

KE = 0.5 * m * 784.8

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Related Questions

In the diagram below, which particle is anti-matter?
e+
p
pn
v

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The anti-matter particle in the diagram is e+ (positron), which has the same mass as an electron but a positive charge opposite that of an electron. (matter particle).

The other particles in the diagram are all matter particles (p, p, n, and v).

In the picture, e+ (positron) is the anti-matter particle since it has the same mass as an electron but a positive charge that is opposite to that of an electron. (matter particle).

Anti-matter is matter's polar opposite, composed of particles with the same mass but opposite charge as matter particles.

When matter and anti-matter particles collide, they annihilate each other and emit a massive amount of energy in the form of gamma rays. grasp the fundamental laws of physics and the beginnings of the world requires a thorough grasp of anti-matter.

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A plate (1 m x 1 m) was an array of 20 fins exposed to air. Each fin as constant rectangular cross-section: thickness t = 0.006 m, length L = 0.040 m. There is no contact resistance. The thermal conductivity of the plate and fins is 240 W/ m K. The average convection coefficient is 100 W/m^2.K for both the fins and the unfinned plate surfaces If the overall temperature difference between the base and the air is n = 100°C, what is the overall heat flow?

Answers

The heat flow will be 0.0005 W.

To calculate the overall heat flow, we need to first calculate the resistance of the plate and fins. The resistance of each fin can be calculated using the formula:

R = t / (kA)

where R is the resistance, t is the thickness of the fin, k is the thermal conductivity, and A is the cross-sectional area of the fin.
For each fin, A = 0.006 x 0.040 = 0.00024 m²

So, the resistance of each fin is:
R = 0.006 / (240 x 0.00024) = 10

There are 20 fins in the array, so the total resistance of the fins is:
R_fins = 20 x 10 = 200

The resistance of the unfinned plate can be calculated using the formula:
R_plate = L / (kA)

where A is the area of the plate, which is 1 x 1 = 1 m².

So, the resistance of the unfinned plate is:
R_plate = 0.040 / (240 x 1) = 0.0001667

The overall resistance of the plate and fins is the sum of the resistance of the fins and the unfinned plate:
R_overall = R_fins + R_plate = 200 + 0.0001667 = 200.0001667

The overall heat flow can be calculated using the formula:
Q = (T_base - T_air) / R_overall

where T_base is the temperature of the plate and fins, T_air is the temperature of the air, and R_overall is the overall resistance.

The temperature difference is given as n = 100°C, so T_base - T_air = 100.

Substituting the values, we get:
Q = 100 / 200.0001667 = 0.0005 W

Therefore, the overall heat flow is 0.0005 W.

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An electric current flows in a closed loop made of two fixed rails, power supply, and a very light rod that is free to move on the top of the rails. A uniform magnetic field is perpendicular to the plane of the circuit. What is the direction of the magnetic force on the rod? оа. -у O b. -X O C. +x O d. +y

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On the rod, the magnetic force of current flow is flowing in a -y direction.

What direction does the current move in?

Conventionally, an electric current flows in the direction that a positive charge would.As a result, the positive terminal of the battery receives less current in the external circuit than the negative terminal does.Electrons go from a negative potential to a positive potential, and vice versa.

Why does positive to negative current flow?

Because of the high potential electron concentration at the positive terminal and the low potential electron concentration at the negative terminal, electric current flows. Current is calculated as the quantity of electrons passing across the cross section of a conductor in a second.

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If a company’s ROA is 4.0% and its total assets to total equity ratio is 3.0, what is its ROE (return on equity)? Enter your answers as a percentage rounded to 2 decimal places. For example, enter 8.43 (%) instead of 0.0843)

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If a company’s ROA is 4.0% and its total assets to total equity ratio is 3.0, what is its ROE (return on equity) is 12.00%.

To find the company's ROE (return on equity), we can use the given information: its ROA (return on assets) is 4.0% and its total assets to total equity ratio is 3.0.

1: Convert the ROA percentage to a decimal.
ROA = 4.0% = 0.04

2: Use the relationship between ROA, ROE, and the assets to equity ratio.
ROA = ROE / (Total Assets / Total Equity)

3: Substitute the given values and solve for ROE.
0.04 = ROE / 3.0

4: Multiply both sides of the equation by 3.0 to isolate ROE.
ROE = 0.04 * 3.0

5: Calculate the ROE value.
ROE = 0.12

6: Convert the ROE decimal value back to a percentage.
ROE = 0.12 * 100 = 12%

So, the company's ROE (return on equity) is 12.00%.

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a bicycle wheel has some masses attached to it. in which case will it be harder to accelerate the bicycle?

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When a bicycle wheel has masses attached to it, the overall weight of the wheel increases. This increase in weight leads to the higher rotational inertia of the wheel, which makes it harder to accelerate the bicycle.

Inertia is a property of matter that describes the resistance of an object to change its state of motion. When the rotational inertia of the wheel is higher, it takes more force to overcome this resistance and accelerate the bicycle.

In addition to the weight of the masses attached to the wheel, the distribution of these masses also plays a role in how hard it is to accelerate the bicycle. If the masses are evenly distributed around the wheel, the rotational inertia will be higher than if the masses are concentrated in one area. This is because the masses located farther from the axis of rotation have a greater effect on the wheel's inertia.

Therefore, if a bicycle wheel has masses attached to it that are evenly distributed around the wheel, it will be harder to accelerate the bicycle compared to a wheel with no masses attached. This is because the overall weight of the wheel has increased, and the distribution of these masses increases the wheel's rotational inertia.

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The 2 Mg car has a velocity of V1 = 108 km/h when the driver sees an obstacle in front of the car. It takes 2s for him to react and lock the brakes, causing the car to skid. If the car stops when it has traveled a distance of 260 m, determine the coefficient of kinetic friction between the tires and the road.

Answers

the coefficient of kinetic friction between the tires and the road is approximately 1.53.

To solve this problem, we can use the following kinematic equation:

v_f^2 = v_i^2 + 2ax

where v_f is the final velocity (which is 0 since the car stops), v_i is the initial velocity, a is the acceleration, and x is the distance traveled.

First, we need to convert the initial velocity from km/h to m/s:

V1 = 108 km/h = 30 m/s

Next, we can calculate the acceleration of the car using the reaction time of 2 seconds:

a = (0 - V1) / t = (0 - 30 m/s) / 2 s = -15 m/s^2

Note that the acceleration is negative because it is in the opposite direction to the initial velocity.

Now we can use the given distance traveled to solve for the coefficient of kinetic friction:

x = (v_f^2 - v_i^2) / (2a)

260 m = (0 - (30 m/s)^2) / (2*(-15 m/s^2))

260 m = 450 m^2/s^2 / 30 m/s^2

260 m = 15 s

Finally, we can use the equation for the coefficient of kinetic friction:

μ_k = (g - a) / g

where g is the acceleration due to gravity, which is approximately 9.81 m/s^2:

μ_k = (9.81 m/s^2 - |-15 m/s^2|) / 9.81 m/s^2

μ_k = 1.53

Therefore, the coefficient of kinetic friction between the tires and the road is approximately 1.53.
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an emf is induced in response to a change in magnetic field inside a loop of wire. which of the following changes would increase the magnitude of the induced emf? a. reducing the diameter of the loop b. turning the plane of the loop to be parallel to the magnetic field c. changing the magnetic field more rapidly d. reducing the resistance of the wire of which the loop is made

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If there is increase the magnitude of the induced emf it changes the magnetic field more rapidly. The correct answer is (c).

According to Faraday's law of electromagnetic induction, the magnitude of the induced emf is proportional to the rate of change of magnetic flux through the loop. Magnetic flux is the product of magnetic field and the area of the loop perpendicular to the field.

Therefore, any change that increases the rate of change of magnetic flux will increase the induced emf. Option (c) suggests changing the magnetic field more rapidly, which means that the rate of change of magnetic flux would be higher, leading to a higher induced emf.

Options (a) and (b) are irrelevant because they do not affect the rate of change of magnetic flux. Option (d) would affect the current in the wire but not the induced emf. Hence, option c is correct.

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Suppose the distance between two slits in a given experiment is d = 0.040 mm and that the distance between the slit mask and the display screen is D = 2.50 m. If the distance between adjacent bright spots (for low n) is 3.0 cm on the screen, what is the wavelength of the light involved?

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The given problem involves calculating the wavelength of light involved in an interference experiment, given the distance between the slits, the distance between the slits and the screen, and the distance between adjacent bright spots on the screen.

Specifically, we are asked to determine the wavelength of the light based on the properties of the interference pattern observed on the screen.To calculate the wavelength of the light, we need to use the formula for the distance between adjacent bright spots in an interference pattern, which is given by d*sinθ = m*λ, where d is the distance between the slits, θ is the angle between the bright spots and the central maximum, m is the order of the bright spot, and λ is the wavelength of the light.In this case, we are given the distance between the slits, the distance between the slits and the screen, and the distance between adjacent bright spots on the screen.

We can use these values to calculate the angle between the bright spots and the central maximum, and then use the formula for the distance between adjacent bright spots to solve for the wavelength of the light.The final answer is a number, which represents the wavelength of the light in meters.Overall, the problem involves applying the principles of optics and interference to determine the wavelength of light involved in an interference experiment. It also requires an understanding of the properties of the interference pattern observed on the screen, as well as the formula for the distance between adjacent bright spots in the pattern.

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a gas of 5.00×1019 atoms or molecules has 0.800 j of thermal energy. its molar specific heat at constant pressure is 20.8 j/mol k.

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The molar specific heat at constant pressure for a gas of 5.00×1019 atoms or molecules with 0.800 J of thermal energy is 20.8 J/mol K, and the change in temperature required to achieve this energy transfer is 0.0384 K.

The molar specific heat at constant pressure is a measure of the amount of energy required to raise the temperature of one mole of a substance by one degree Kelvin. In this case, the gas has a thermal energy of 0.800 J, and it contains 5.00×1019 atoms or molecules.

To find the molar specific heat at constant pressure, we can use the formula: Cp = (ΔE / n) / ΔT, where: Cp = molar specific heat at constant pressure, ΔE = change in thermal energy, n = number of moles of gas, ΔT = change in temperature.

Since we know that the gas has a thermal energy of 0.800 J, we can substitute this value for ΔE. We also know that the gas contains 5.00×1019 atoms or molecules, which is not enough information to determine the number of moles, but we can assume that it is a small enough amount that we can treat it as one mole.

Finally, we are not given a specific change in temperature, so we cannot determine the value of ΔT. However, we can still use the given formula to find the molar specific heat at constant pressure:

Cp = (0.800 J / 1 mol) / ΔT

Cp = 0.800 J/mol K / ΔT

Substituting the given value for the molar specific heat at constant pressure, we get: 20.8 J/mol K = 0.800 J/mol K / ΔT

Solving for ΔT, we get: ΔT = 0.800 J/mol K / 20.8 J/mol K, ΔT = 0.0384 K

Therefore, the molar specific heat at constant pressure for a gas of 5.00×1019 atoms or molecules with 0.800 J of thermal energy is 20.8 J/mol K, and the change in temperature required to achieve this energy transfer is 0.0384 K.

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A solid sphere, a solid cylinder, a hollow sphere and a hollow cylinder (all of the same mass ) simultaneously start rolling down from top of an inclined plane, then the time to reach bottom of inclined plane is : _________

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A solid sphere, a solid cylinder, a hollow sphere, and a hollow cylinder all begin to descend from the top of an inclined plane at the same time. When the hollow cylinder reaches the bottom of the inclined plane.

The time taken for each object to roll down the inclined plane depends on various factors such as the mass, radius, and moment of inertia of the object. However, since all the objects mentioned in the question have the same mass, we can focus on their moments of inertia.

The moment of inertia is a measure of an object's resistance to rotational motion. For a given mass and shape, the moment of inertia can be different depending on how the mass is distributed relative to the axis of rotation. The moment of inertia of an object rolling down an inclined plane affects its speed and acceleration.

The moment of inertia of a solid sphere is I = (2/5) * m * r^2, where m is the mass of the sphere and r is its radius. The moment of inertia of a solid cylinder is I = (1/2) * m * r^2, where m is the mass of the cylinder and r is its radius. The moment of inertia of a hollow sphere is I = (2/3) * m * r^2, where m is the mass of the sphere and r is its outer radius. The moment of inertia of a hollow cylinder is I = m * r^2, where m is the mass of the cylinder and r is its outer radius.

Since all the objects have the same mass, we can compare their moments of inertia based on their shape. The hollow cylinder has the smallest moment of inertia, followed by the solid cylinder, the hollow sphere, and finally, the solid sphere, which has the largest moment of inertia.

The objects with smaller moments of inertia require less torque to rotate and hence can accelerate faster. Therefore, the hollow cylinder would reach the bottom of the inclined plane first, followed by the solid cylinder, the hollow sphere, and finally, the solid sphere, which would take the longest time to reach the bottom.

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explain what determines wheteher the net torque acting on the rigid object is clockwise or counterclockwise

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The direction of the net torque (clockwise or counterclockwise) depends on the balance of torques acting in each direction.

1. Torque: Torque is the rotational force applied to an object, which tends to cause a change in its rotational motion.
2. Force: The force applied to an object has both magnitude and direction, which together determine the torque acting on the object.
3. Lever arm: The lever arm is the perpendicular distance from the axis of rotation to the line of action of the force. A longer lever arm leads to a larger torque.
4. Direction of force: The direction of the force applied to the object determines the direction of the torque. If the force is applied in a direction that causes the object to rotate counterclockwise, the torque is positive. Conversely, if the force is applied in a direction that causes the object to rotate clockwise, the torque is negative.
5. Net torque: The net torque is the sum of all individual torques acting on an object. To determine whether the net torque is clockwise or counterclockwise, you need to calculate the sum of all torques and their directions.
If the sum of torques acting counter clockwise is greater than the sum of torques acting clockwise, the net torque will cause the object to rotate counterclockwise. Conversely, if the sum of torques acting clockwise is greater than the sum of torques acting counterclockwise, the net torque will cause the object to rotate clockwise.
In summary, the net torque acting on a rigid object is determined by the magnitudes, directions, and lever arms of the individual forces applied to the object, as well as the sum of all torques in each direction. The direction of the net torque (clockwise or counterclockwise) depends on the balance of torques acting in each direction.

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the minimum temperature usually occurs near sunrise because:

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The minimum temperature usually occurs near sunrise because this is typically the coolest part of the day as the sun has not yet had a chance to warm the air. As the sun rises and begins to heat the ground, the air temperature gradually increases.

Therefore, the lowest temperature of the day is often observed around sunrise before the sun's rays have a chance to fully warm the surrounding environment. The minimum temperature usually occurs near sunrise because during the night, the Earth's surface cools as it radiates heat into the atmosphere without receiving much incoming solar radiation. As the night progresses, the temperature continues to decrease until sunrise. At sunrise, the incoming solar radiation starts to warm the Earth's surface again, causing the temperature to rise. Therefore, the minimum temperature typically occurs close to sunrise.

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if the suspended object moves downward a distance of 3.40 m in 2.01 s , what is the mass of the wheel?if the suspended object moves downward a distance of 3.40 m in 2.01 s , what is the mass of the wheel?

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The mass of the wheel is approximately 8.48 kilograms.

The distance moved by the object hanging from the wheel in a time of 2.01 seconds is equal to the distance traveled by a point on the wheel's circumference in the same time period. Let's call the radius of the wheel "r". The distance traveled by a point on the wheel's circumference is equal to the circumference of the wheel, which is 2πr.

So, we can write:

distance = 2πr

We know the distance traveled by the hanging object is 3.40 m, so we can write:

3.40 m = 2πr

Solving for r, we get:

r = 3.40 m / (2π) ≈ 0.541 m

Now we can use the formula for centripetal force, which relates the force required to keep an object moving in a circle to the object's mass, the radius of the circle, and the speed of the object:

force = (mass x speed²) / radius

We don't know the speed of the object, but we do know that it moved 3.40 m in 2.01 s, so we can find the speed using the formula for average speed:

speed = distance / time = 3.40 m / 2.01 s ≈ 1.69 m/s

Now we can plug in the known values and solve for the mass:

force = (mass x speed²) / radius

The force is the weight of the hanging object, which is given as 53.0 N. The radius is 0.541 m, and the speed is 1.69 m/s. Plugging these values in,

53.0 N = (mass x 1.69²) / 0.541 m

Solving for mass, we get:

mass = (53.0 N x 0.541 m) / 1.69² ≈ 8.48 kg

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What is the thermal energy of 100 cm3 of aluminum at 200 ∘C? Express your answer with the appropriate units.

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The thermal energy of 100 cm³ of aluminum at 200°C is 43,596.6 Joules (J).

To calculate the thermal energy of 100 cm³ of aluminum at 200°C, we need to use the formula:

Thermal energy (Q) = mass (m) × specific heat capacity (c) × temperature change (ΔT)

First, we need to find the mass of the aluminum. The density of aluminum is 2.7 g/cm³, so:

mass (m) = volume × density
m = 100 cm³ × 2.7 g/cm³
m = 270 g

The specific heat capacity (c) of aluminum is 0.897 J/(g·°C).

Next, we need to find the temperature change (ΔT). We will assume the initial temperature of the aluminum is 20°C (room temperature):

ΔT = final temperature - initial temperature
ΔT = 200°C - 20°C
ΔT = 180°C

Now we can calculate the thermal energy (Q):

Q = m × c × ΔT
Q = 270 g × 0.897 J/(g·°C) × 180°C
Q = 43,596.6 J

So, the thermal energy of 100 cm³ of aluminum at 200°C is 43,596.6 Joules (J).

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The thermal energy of 100 cm³ of aluminum at 200°C is 43,596.6 Joules (J).

To calculate the thermal energy of 100 cm³ of aluminum at 200°C, we need to use the formula:

Thermal energy (Q) = mass (m) × specific heat capacity (c) × temperature change (ΔT)

First, we need to find the mass of the aluminum. The density of aluminum is 2.7 g/cm³, so:

mass (m) = volume × density

m = 100 cm³ × 2.7 g/cm³

m = 270 g

The specific heat capacity (c) of aluminum is 0.897 J/(g·°C).

Next, we need to find the temperature change (ΔT). We will assume the initial temperature of the aluminum is 20°C (room temperature):

ΔT = final temperature - initial temperature

ΔT = 200°C - 20°C

ΔT = 180°C

Now we can calculate the thermal energy (Q):

Q = m × c × ΔT

Q = 270 g × 0.897 J/(g·°C) × 180°C

Q = 43,596.6 J

So, the thermal energy of 100 cm³ of aluminum at 200°C is 43,596.6 Joules (J).

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If a rock is thrown from the ground with an initial velocity of 120 ft/sec, then the height of the rock, in feet, at t seconds can be modeled by s(t)=1200-16t, osts 7.5. (a) The velocity is v(t) = The acceleration is a(t) = (b) The time at which the rock reaches its maximum height is ta seconds. (c) The maximum height the rock reaches is feet (d) The acceleration of the rock when it reaches its maximum height is -Select- an initial velocity of 120 ft/sec, then the height of the rock, in feet, at t seconds sits maximum height is t = seconds. Ches is feet. it reaches its maximum height is

Answers

The maximum height the rock reaches is 1080 feet, and the acceleration at this point is 0.

Based on the given information, we have:

(a) The height of the rock is modeled by the function s(t) = 1200 - 16t. To find the velocity v(t), we differentiate s(t) with respect to time t:

v(t) = ds/dt = -16

To find the acceleration a(t), we differentiate v(t) with respect to time t:

a(t) = dv/dt = 0

(b) Since the acceleration is constant and the velocity is linear, the rock reaches its maximum height when its velocity is 0. As v(t) = -16, this situation does not occur within the given domain of t.

(c) Given the domain of 0 ≤ t ≤ 7.5 seconds, the maximum height will occur at t = 7.5 seconds. To find this height, plug t = 7.5 into s(t):

s(7.5) = 1200 - 16(7.5) = 1080 feet

(d) The acceleration of the rock when it reaches its maximum height is:

a(t) = 0

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in an r-c series circuit, what percentage of one time constant passes until the voltage across the capacitor equals half of the battery’s emf

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The percentage of one time constant that passes until the voltage across the capacitor equals half of the battery's EMF is approximately 69.3%

In an R-C series circuit, the time constant (τ) is the product of the resistance (R) and the capacitance (C), represented by τ = R × C. The time constant indicates how long it takes for the voltage across the capacitor to reach approximately 63.2% of the battery's EMF.

To find the percentage of one time constant at which the voltage across the capacitor equals half of the battery's EMF, you can use the voltage charging equation:

V(t) = V_battery × (1 - e^(-t/(R×C)))

Where V(t) is the voltage across the capacitor at a specific time t, V_battery is the battery's EMF, and e is the base of the natural logarithm (approximately 2.71828).

To find the time at which the voltage is half of the battery's EMF, set V(t) to 0.5 * V_battery:

0.5 * V_battery = V_battery × (1 - e^(-t/(R×C)))

Solve for t:

0.5 = 1 - e^(-t/(R×C))
0.5 = e^(-t/(R×C))
ln(0.5) = -t/(R×C)

Now, to find the percentage of one time constant that has passed, divide t by the time constant τ:

percentage = (t/τ) × 100

Since τ = R*C, the equation simplifies to:

percentage = (t/(R×C)) × 100
percentage = (-ln(0.5) × 100) / (R×C)

The percentage of one time constant that passes until the voltage across the capacitor equals half of the battery's EMF is approximately 69.3% (since -ln(0.5) ≈ 0.6931).

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what is the pressure if an additional 30.8 kg of nitrogen is added without changing the temperature?

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The pressure would increase by approximately 180.4 atm if an additional 30.8 kg of nitrogen is added without changing the temperature.

Assuming the nitrogen is added to a closed container, the pressure would increase due to the additional mass of nitrogen. The pressure increase can be calculated using the ideal gas law, which states:

PV = nRT

where P is the pressure, V is the volume of the container, n is the number of moles of gas (which can be calculated using the mass of nitrogen added and the molar mass of nitrogen), R is the gas constant, and T is the temperature.

Since the temperature is not changing, we can simplify the equation to:

P1V = n1RT
P2V = (n1 + n2)RT

where P1 is the initial pressure, n1 is the initial number of moles of nitrogen, and n2 is the additional number of moles of nitrogen added (which can be calculated using the mass of nitrogen added and the molar mass of nitrogen).

Solving for P2, we get:

P2 = (n1 + n2)RT / V

Substituting in the given values, we get:

n1 = m1 / M = 30.8 kg / 28.014 g/mol = 1098.3 mol
n2 = m2 / M = 30.8 kg / 28.014 g/mol = 1098.3 mol
R = 0.08206 L·atm/K·mol
T = constant
V = constant

Therefore,

P2 = (1098.3 mol + 1098.3 mol) x 0.08206 L·atm/K·mol x T / V
P2 = 180.4 atm

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While traveling through a conductor, an electric current produces a(n) A. eddy current B. electrical disharge C. magetic field.

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The magnetic field is produced because moving charges (i.e., the electrons) create a magnetic field. The strength of the magnetic field depends on the amount of current flowing through the conductor, as well as the distance from the conductor.

While traveling through a conductor, an electric current produces a magnetic field. This is due to the interaction between the moving electrons in the conductor and the magnetic field created by the current.

Eddy currents, on the other hand, are created when a conductor experiences a change in magnetic field, which causes circular currents to flow within the conductor.

Electrical discharge refers to the sudden release of stored electrical energy, which can occur when a high voltage is applied to a conductor.

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L M Experiment 1 L 2M Experiment 2 2L M Experiment 3 Three different experiments are conducted that pertain to the oscillatory motion of a pendulum. For each experiment, the length of the pendulum and the mass of the pendulum are indicated. In all experiments, the pendulum is released from the same angle with respect to the vertical. The pendulum from Experiment 1 has been experimentally determined to have a period of To when released from an angle 2. The pendulum is then attached to the ceiling of an elevator that travels upward. The pendulum is released from rest at an angle , at t=0 s. From t=0 s to t = 10 s, the elevator travels with a constant speed. From t = 10 s to t= 20 s, the elevator decreases its speed with a constant acceleration. From t = 20 s to t = 30 s, the elevator remains at rest. Which of the following graphs represents the period of the pendulum as a function of time? Period 0 30 10 20 Time (s) Period TO 0 30 10 20 Time (s) Period Tot 0 10 20 30 Time (s) Period то 0 30 10 20 Time (s)

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In the three different pendulum experiments, the factors affecting the pendulum's period are the length (L) and mass (M) of the pendulum. However, it is important to note that the period of a pendulum is independent of its mass and only depends on its length and the acceleration due to gravity (g).

The formula for the period of a pendulum is:
T = 2π √(L/g)

When the pendulum is attached to the ceiling of an elevator, the effective acceleration due to gravity (g') is the sum of the actual acceleration due to gravity (g) and the elevator's acceleration (a). So, g' = g + a.

Considering the given information about the elevator's motion:

1. From t=0 s to t=10 s, the elevator has a constant speed, so its acceleration (a) is 0. The period remains constant at T0.
2. From t=10 s to t=20 s, the elevator has a constant negative acceleration (decreasing its speed), so the effective acceleration due to gravity (g') will be greater than g. The period will decrease during this time.
3. From t=20 s to t=30 s, the elevator is at rest, so its acceleration (a) is 0 again. The period returns to T0.

Based on this information, the graph representing the period of the pendulum as a function of time would have three segments:

1. A constant period T0 from t=0 s to t=10 s.
2. A decreasing period from t=10 s to t=20 s.
3. A constant period T0 from t=20 s to t=30 s.

You should choose the graph that best represents these characteristics.

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a professional video camera lens has a 17 cm focal length and a lens diameter of 6.0 cm. what is its f-number? report as f/

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The f-number of the professional video camera lens is f/2.83.

The f-number of a lens is calculated by dividing the focal length by the diameter of the lens aperture. This ratio is a measure of how much light can enter the camera and is expressed as f/number.

In the given scenario, the professional video camera lens has a focal length of 17 cm and a lens diameter of 6.0 cm.
To calculate the f-number, we simply divide the focal length by the lens diameter:
f-number = focal length / lens diameter
f-number = 17 cm / 6.0 cm
f-number = 2.83

This means that the lens can allow a significant amount of light to enter the camera, making it ideal for low-light situations.
In addition to the f-number, there are other factors that affect the quality of the video captured by a camera lens. These include the aperture size, the depth of field, and the lens construction. It is important to consider all of these factors when choosing a camera lens to ensure that the desired results are achieved.

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Titan completes one orbit about Saturn in 15.9 days and the average Saturn-Titan distance is 1.22 x 109 m m. Calculate the angular speed w of Titan as it orbits Saturn. 2.52 x10-2 0 = rad/s Incorrect

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Angular speed of Titan as it orbits Saturn is approximately 4.57 × 10^-6 rad/s.. To do this, we will use the following formula:

ω = 2π / T

where ω is the angular speed, 2π represents a full circle (360 degrees) in radians, and T is the orbital period.

Given that Titan completes one orbit around Saturn in 15.9 days, we need to convert this period into seconds:

T = 15.9 days × 24 hours/day × 60 minutes/hour × 60 seconds/minute = 1,374,240 seconds

Now, we can calculate the angular speed (ω) of Titan as it orbits Saturn:

ω = 2π / 1,374,240 seconds ≈ 4.57 × 10^-6 rad/s

So, the angular speed of Titan as it orbits Saturn is approximately 4.57 × 10^-6 rad/s.

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A total of 10000 kg of water per second flows over a waterfall 30 m high.If half of the power this flow represents could be converted into electricity, how many 100-W light bulbs could be supplied?

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The potential energy of the water can be calculated using the formula: potential energy = mass x gravity x height. So, if half of the power this flow represents could be converted into electricity, 14,715 100-W light bulbs could be supplied.

So, potential energy = 10000 kg/s x 9.8 m/s^2 x 30 m = 2.94 x 10^6 watts or 2.94 MW.
If half of this power can be converted into electricity, that would be 1.47 MW.
To find out how many 100-W light bulbs this can supply, we need to divide the power by the power of each bulb.
Number of bulbs = 1.47 MW / 100 W = 14,700.
The flowing water over the waterfall can supply 14,700 100-W light bulbs if half of its power is converted into electricity.

To determine how many 100-W light bulbs could be supplied, we need to follow these steps:
1. Calculate the potential energy of the water flow (PE = mgh)
2. Calculate the power available by converting half of this potential energy (P = 0.5 * PE/t)
3. Divide the power available by the power required for each light bulb (100 W)
Here's the calculation:
1. PE = mgh = 10000 kg * 9.81 m/s^2 * 30 m = 2,943,000 J (joules)
2. P = 0.5 * PE/t = 0.5 * 2,943,000 J / 1 s = 1,471,500 W (watts)
3. Number of light bulbs = P / 100 W = 1,471,500 W / 100 W = 14,715 bulbs.

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Electric charge can accumulate on an airplane in flight. You may have observed needle-shaped metal extensions on the wing tips and tail of an airplane. Their purpose is to allow charge to leak off before much of it accumulates. The electric field around the needle is much larger than the field around the body of the airplane and, can become large enough to produce dielectric breakdown of the air, discharging the airplane. To model this process, assume that two charged spherical conductors are connected by a long conducting wire and a charge of 33.0 muC is placed on the combination. One sphere, representing the body of the airplane, has a radius of 6.00 cm, and the other, representing the tip of the needle, has a radius of 2.00 cm. What is the electric potential of each sphere? r = 6.00 cm V r = 2.00cm V What is the electric field at the surface of each sphere? r = 6.00 cm V/m r = 2.00 cm V/m

Answers

Electric potential of airplane body: V = 165 kV. Electric potential of needle tip: V = 495 kV. Electric field at airplane body surface: E = 82.5 kV/m. Electric field at needle tip surface: E = 247.5 kV/m.

Electric charge gathering on a plane in flight is a huge worry because of the potential for a perilous development of charge. To forestall this, slender molded metal augmentations are introduced on the wingtips and tail to permit the charge to disperse before it gathers.

The electric field around the needle is a lot more grounded than the field around the plane body, and on the off chance that it turns out to be areas of strength for excessively, can cause dielectric breakdown of the air, which can release the plane.

To display the course of charge development, we can expect that two charged round conduits are associated by a long leading wire, with a charge of 33.0 μC put on the mix. One circle addresses the plane body, with a span of 6.00 cm, and the other addresses the tip of the needle, with a sweep of 2.00 cm.

To decide the electric capability of every circle, we can utilize the equation V = kQ/r, where k is the Coulomb steady, Q is the charge, and r is the sweep of the circle. The electric capability of the circle addressing the plane body is around 165 kV, and the electric capability of the circle addressing the tip of the needle is roughly 495 kV.

To compute the electric field at the outer layer of every circle, we can utilize the recipe E = kQ/r^2, where r is the span of the circle. The electric field at the outer layer of the circle addressing the plane body is around 82.5 kV/m, and the electric field at the outer layer of the circle addressing the tip of the needle is roughly 247.5 kV/m.

All in all, the slender molded metal augmentations on the wingtips and tail of a plane assist with forestalling the aggregation of electric charge during flight, which can be perilous.

Demonstrating the course of charge development utilizing two charged circular channels associated by a long leading wire shows that the electric potential and electric field at the outer layer of the circle addressing the tip of the needle are a lot higher than those of the circle addressing the plane body.

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0.5 kg of water evaporates at 100 kPa in a piston-cylinder device. a. Show this process on a p-v diagram and indicate salient values. (2) b. Calculate the volume change as the liquid changes to vapor. (5) c. Calculate the latent heat (i.e. enthalpy) of vaporization. (3)

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The salient values for this process would be the initial volume of the liquid water, the final volume of the water vapor, the pressure at which the process occurs (100 kPa), and the temperature at which the water begins to boil (which is dependent on the initial temperature of the water). We can use this equation to calculate the initial and final volumes of the water, and then subtract the two to get the volume change. This gives us a latent heat of vaporization of 2260 kJ/kg.

a. To show this process on a p-v diagram, we would draw a vertical line at 100 kPa (the constant pressure), starting from the initial volume of the liquid water. This would represent the process of heating the water until it reaches its boiling point, at which point it begins to evaporate. Then, we would draw a horizontal line at the final volume of the water vapor, indicating that the volume remains constant as the vapor is formed.

b. To calculate the volume change as the liquid changes to vapor, we need to use the ideal gas law, which states that PV=nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature. We can assume that the amount of water that evaporates is negligible compared to the total volume of the piston-cylinder device, so the number of moles of gas remains constant. We also know that the pressure is constant at 100 kPa, so we can simplify the ideal gas law to V=nRT/P. We can use this equation to calculate the initial and final volumes of the water, and then subtract the two to get the volume change.

c. To calculate the latent heat (i.e. enthalpy) of vaporization, we need to use the formula Q=mL, where Q is the heat transferred, m is the mass of the substance, and L is the latent heat of vaporization. We know that 0.5 kg of water evaporates, so we can use the latent heat of vaporization for water, which is 40.7 kJ/mol. To convert this to joules per kilogram, we need to divide by the molar mass of water, which is approximately 18 g/mol. This gives us a latent heat of vaporization of 2260 kJ/kg.

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how does the transit method tell us planetary size, and in what cases can we also learn mass and density?

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The transit method helps us determine the planetary size by analyzing the drop in brightness during a transit event. In combination with other methods, such as radial velocity, we can also estimate the mass and density of exoplanets, providing valuable information about their properties and potential habitability.


The transit method works by observing the decrease in a star's brightness when a planet passes in front of it, blocking a portion of its light. This is called a transit event. The amount of light blocked depends on the size of the planet relative to its host star, which allows us to determine the planet's radius.
To calculate the planet's size, astronomers measure the drop in brightness and compare it to the star's known properties. The ratio of the planet's radius to the star's radius can be derived using the following formula:
[tex](\frac{R_{planet}}{ R_{star}} )^2=   \frac{(Brightness_{star} - Brightness_{transit})}{Brightness_{star}}[/tex]
To determine the mass and density of the planet, additional observations and methods are needed.

One such method is the radial velocity method, which measures the gravitational effect of the planet on its host star. As the planet orbits the star, it causes the star to "wobble" slightly.

By measuring this wobble, astronomers can estimate the mass of the planet using the following equation:
[tex]M_{planet} / M_{star}= (Velocity_{star}/ Velocity_{planet} \times (Distance_{planet}/ Distance_{star})^2[/tex]
Once both mass and radius are known, the planet's density can be calculated using the formula:
Density = Mass / Volume
With the mass, radius, and density determined, scientists can gain insights into the planet's composition and its potential to support life.
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Two particles in a high-energy accelerator experiment are approaching each other head-on, each with a speed of 0.9540 as measured in the laboratory. Part A What is the magnitude of the velocity of one particle relative to the other? Express your answer using four significant figures.

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The velocity of one particle with respect to the other is 1.7501 times the speed of light.

To find the magnitude of the velocity of one particle relative to the other, we'll use the formula for relative velocity in terms of velocities in the same direction:

Relative velocity [tex]V_{rel} = \frac{(V_1 + V_2)} { 1 + (V_1 \times V_2) / c^2}[/tex]

Here, V1 and V2 are the velocities of the two particles, and c is the speed of light. Given that both particles have a speed of 0.9540 times the speed of light, we have:

V₁ = 0.9540 × c
V₂ = 0.9540 × c

Now we can plug these values into the relative velocity formula:

[tex]V_{rel} = \frac{0.9540 \times c + 0.9540 \times c} { 1 + (0.9540 \times c \times 0.9540 \times c) / c^2}[/tex]

Simplify the equation:

[tex]V_{rel} = (1.9080 \times c) / (1 + 0.9098)[/tex]

[tex]V_{rel} = (1.9080 \times c) / 1.0902[/tex]

[tex]V_{rel} = 1.7501 \times c[/tex]

The magnitude of the velocity of one particle relative to the other is 1.7501 times the speed of light or 1.7501c.

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a 2.5-kg cart is rolling along a frictionless, horizontal track towards a 1.4-kg cart that is held initially at rest. the carts are loaded with strong magnets that cause them to attract one another. thus, the speed of each cart increases. at a certain instant before the carts collide, the first cart's velocity is 4.7 m/s, and the second cart's velocity is -1.2 m/s. (a) what is the total momentum of the system of the two carts at this instant? (b) what was the velocity of the first cart when the second cart was still at rest? (a) number units

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The total momentum of the system of the two carts at the instant before they collide is 10.07 kg m/s. The first cart was moving at a velocity of 2.46 m/s whereas the second cart is at rest.

(a) The individual degree of resistance of each object are added together to form the outcomes obtained of a pair of objects. The equation p= mv, where p is velocity, m is mass, and v is velocity, can be used to determine the angular momentum of the two carts prior to collision in this scenario.

Let v1 be the speed of its first cart and v2 be the speed of the second cart. The two carts' momenta just before they collision are as follows:

m1v1 = (2.5 kg)(4.7 m/s) = 11.75 kg m/s where p1 = m1v1

1.4 kg)(-1.2 m/s) = -1.68 kg m/s, where p2 = m2v2

The system's overall momentum is thus:10.07 kg/s is equal to p = p1 + p2 = 11.75 kg/s - 1.68 kg/s.

The total momentum of the system is then:

p = p1 + p2 = 11.75 kg m/s - 1.68 kg m/s = 10.07 kg m/s.

(b) We may apply the theory of momentum conservation to determine the first cart's velocity when the other cart continued to rest. The overall momentum of the system is constant as in absence of an external influences.

Prior to the carts colliding, the system's overall momentum is: p = m1v1 + m2v2

The carts travel as one unit of mass (m1 + m2) after colliding and sticking together. Let v' represent the combined carts' speed. According to momentum conservation, the system's overall momentum following the impact is: p = (m1 + m2) v'

The system's initial momentum is 0 because the carts are originally at rest. As a result, the overall momentum prior to and following the contact must be identical.

m1v1 + m2v2 = (m1 + m2) v'

When we enter the values provided, we get:

2.5 kilogramme at 4.7 m/s plus 1.4 kg at 0 m/s equals (2.5 kg plus 1.4 kg). v'

By finding v', we obtain:

The formula for v' is (2.5 kg)(4.7 m/s) / (2.5 kg + 1.4 kg) = 2.46 m/s.

As a result, the combined carts' speed after the accident is 2.46 m/s. Given that the other cart was completely at still, the speed of the initial cart prior to the collision is equal to the combined velocity of the two carts following the impact: v1 = v' = 2.46 m/s .

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A turntable turning at rotational speed 31 rpm stops in 40 s when turned off. The turntable's rotational inertia is 1.8×10−2kg⋅m2. Determine the magnitude of the resistive torque that slows the turntable.

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The negative sign indicates that the torque is in the opposite direction to the initial rotation of the turntable. Therefore, the magnitude of the resistive torque that slows the turntable is 5.886×10−3 N·m.

We can use the formula for rotational motion to solve this problem:

τ = Iα

where τ is the torque, I is the rotational inertia, and α is the angular acceleration. We can use the fact that the turntable stops from an initial rotational speed of 31 rpm to a final speed of 0 rpm in 40 s to find the angular acceleration:

α = (ωf - ωi)/t = (0 - (31/60) * 2π)/40 = -0.327 rad/[tex]s^2[/tex]

where ωi is the initial angular velocity in radians per second, ωf is the final angular velocity in radians per second, and t is the time interval.

Substituting the values into the formula, we get:

τ = Iα = (1.8×10−2) * (-0.327) = -5.886×10−3 N·m

The negative sign indicates that the torque is in the opposite direction to the initial rotation of the turntable. Therefore, the magnitude of the resistive torque that slows the turntable is 5.886×10−3 N·m.

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Match the term in column A with the definitions in column B. Write the letter of the definition in the space provided.

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6. Corporation - E. A business organization legally distinct from its owners, treated as if it were an individual.

What is business?

Business is an economic activity involving the exchange of goods and services for money or other goods and services. It involves the production, distribution and sale of goods and services to customers. Businesses can be located in physical stores or online.

7. Stock - A. A portion of ownership of a firm.
8. Share - G. Represents ownership of a firm.
9. Dividend - C. Profit paid to a shareholder.
10. Common Stock - D. Stock that provides shareholders a voice in how the company is run and a share in the profits.
11. Preferred Stock - B. Provides guaranteed dividends but no voice in running a corporation.
12. Corporate Bond - I. Certificate issued by a corporation in exchange for money borrowed from an investor.
13. Principal - F. The actual amount of money borrowed.
14. Interest - H. Predetermined amount of money a borrower must pay for the use of borrowed funds.

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is the proton's speed v2 at point 2 larger than, smaller than, or equal to v3 ? explain.

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If the magnetic field strength varies, we cannot make any conclusive statements about the proton's speed at point 2 compared to point 3 without additional information.

To answer this question, we need to understand the context of point 2 and point 3. Without further information, we cannot determine the specific speeds at these points. However, we do know that the proton's speed will change as it moves through a magnetic field due to the Lorentz force. This force is proportional to the velocity of the particle and the strength of the magnetic field.

Therefore, if the magnetic field strength is constant, the proton's speed will be higher at point 2 if it was accelerated from point 1, and will be lower at point 2 if it was decelerated from point 3. On the other hand, if the magnetic field strength varies, we cannot make any conclusive statements about the proton's speed at point 2 compared to point 3 without additional information.

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