Step response of the given transfer function can be obtained by considering the input as a unit step function i.e. 1/s. Therefore, the output response for the given transfer function is given by:4 G(s) = s² + 4s + 4On substituting s with (1/s), we get4 G(1/s) = (1/s)² + 4(1/s) + 4G(1/s) = (1/s²) + (4/s) + 4
Therefore, the transfer function becomes G(1/s) = 1/s² + 4/s + 4It is clear from the obtained transfer function that the type of response will be overdamped. This is due to the fact that the poles of the transfer function are real and distinct with both poles in the left half of the S-plane. Final Value Theorem can be applied to find the final value of the step response of the given transfer function.
The Final Value Theorem states that the final value of a transfer function can be found by substituting s=0 in the transfer function. Hence, on substituting s=0 in the transfer function G(1/s), we get: G(1/0) = 1/0² + 4/0 + 4G(1/0) = ∞It is clear from the obtained value that the final value of the step response of the given transfer function will be infinite.
Time Constant can be obtained by finding the inverse of the real parts of the poles of the transfer function. The poles of the transfer function are (-2) and (-2).Hence, the time constant of the given transfer function is given byT₁ = 1/2*2 = 1SecondTherefore, the step response of the given transfer function can be written asY(t) = 1 - (1+4t)e⁻²ᵗ + 4e⁻²ᵗThe obtained step response is overdamped with a final value of infinity and a time constant of 1 second.
The response approaches to steady state value without any overshoot or oscillations. The obtained response indicates that the output becomes stable at a constant value of infinity. Therefore, it can be concluded that the given transfer function is not suitable for systems that require a stable output at a finite value.
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Creating And Executing A Command Line Program¶ Write A Standalone Python Program Main.
Creating And Executing A Command Line Program: To write a standalone Python program Main is quite simple and can be done by following the below-given steps:
Step 1: Firstly, open a new Python file, name it whatever you want. For example, "ProgramName.py".
Step 2: The next thing you need to do is import the "argparse" module. This module will help you in defining arguments and parsing them. This module is an in-built module in Python, so there is no need to install it separately.
The following code is used to import it.
Step 3: The next step is to create an argument parser object. This object will hold all the information required by the parser. The following code is used to create an argument parser object.
Step 4: Then you need to add the required argument to this parser object. The following code is used to add the required argument.
Step 5: The next step is to parse the arguments. The following code is used to parse the arguments.
Step 6: Now, you can use these arguments in your code as you want.
This is how you can create a standalone Python program Main. This code is a basic code, but you can add more arguments and use them in your code.
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Write recursive merge sort code in Haskell.
a) Adapt the firstHalf code from the lecture example to work with a list of values of any data type (that is, change the type signature from [Char] -> [Char] to [a] ->[a])
b) Add a function just like the one from a) except that it returns the second half of the list.
c) Write a merge function that merges two lists, xs and ys:
If either list has length 0, just return xs ++ ys. Otherwise,
if the first value in xs is less than or equal to the first value in ys, use cons to prepend the first value in xs to the result of a recursive call one the rest of xs and all of ys.
if the first value in xs is less than the first value in ys, prepend the first value in ys to the result of a recursive call on xs and the rest of ys.
Note that the data type of the items in the list must be an Ord, so the type signature will be:
merge :: Ord a => [a] -> [a] -> [a]
d) Write the function mergeSort. Consider the types for the function signature. Here is how the function should work. To mergeSort the list xs:
if the length of xs is less than 2, return xs
otherwise, call mergeSort on the first half of the list, do the same on the second half, and merge the results
e) Save your file and load it in GHCI. Paste this test code to the prompt. Paste your code and the output in the window.
mergeSort []
mergeSort [-1]
mergeSort [5,-1]
mergeSort [5,-1, 42]
mergeSort [5,-1, 42, -1000]
mergeSort ""
mergeSort " "
mergeSort "G"
mergeSort "Godzilla"
Here's the code for the function that returns the first half of a list, for any data type:Here's the code for the function that returns the second half of a list, for any data type.
Here's the code for the function that merges two sorted lists, for any data type that is an Ord (can be compared for ordering).merge: merge | otherwise Here's the code for the merge sort algorithm that sorts a list, for any data type that is an Ord can be compared.
for ordering.merge mergeSort merge merge Sort merge Sort After writing the code in your text editor, save it as merge_sort.hs and load it in GHCI by typing merge_sort.hs.Now you can run the tests that you mentioned:mergeSort Here's the code for the merge sort algorithm that sort.
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Describe the seven types of people characterized by the social technographics ladder. Which of the types is the most important to marketers using social media marketing? Why do you say so?
Social Technographics Ladder refers to a visual tool that outlines different levels of social media usage based on the level of engagement.
It groups people into 7 different categories based on how they use social media. The seven types of people characterized by the social technographics ladder are creators, critics, collectors, joiners, spectators, inactives, and conversationalists.
The most important types of people that marketers using social media marketing are the creators, conversationalists, and critics. Creators are significant because they are the people who create content for others to share, leading to viral marketing.
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Implement frequency modulation in Matlab command window and Simulink (Both). Use the following data set: • Time Window: 0.5 s Sampling time <0.001 s • Message Amplitude = 5 V • Carrier Amplitude = 5 V Message Frequency = 5 Hz • Carrier Frequency = 25 Hz • Frequency Sensitivity = 1 to 250 in step of 25 Instructions: a) Implement frequency modulation for each value of frequency sensitivity. Simulate and plot the graph of frequency modulated wave at each K, value. Moreover, also discuss each graph to see the effect of changing K, on the modulated output. b) Simulate the following FM modulator: If the modulating signal is m(t) = A cos(2fmt), then the equation of FM wave will be s(t) = A, cos(2nft + ß sin(2πft)) Where, ßmodulation index= of kAm fm Im c) Repeat the steps a and b in Simulink.
By varying the modulation depth and frequency sensitivity, we can create different frequency modulated waves.
MATLAB:
For Frequency Modulation, we can use the ‘fmmod’ function in MATLAB commands. This function takes the basic inputs of the message and carrier signals, the modulation index, and the frequency sensitivity value. In this case, we can use the given values for amplitude (both the message and carrier), for the frequency (both the message and carrier) and for the time window, but we need to vary the frequency sensitivity levels.
The code for the MATLAB command window will look like this:
[messageOut,carrierOut] = fmmod(messageIn,carrierIn,K,fs);
Where ‘messageIn’ is the message signal, ‘carrierIn’ the carrier signal, ‘K’ the modulation index and ‘fs’ is the frequency sensitivity.
We can change the value of frequency sensitivity, held as ‘fs’, in steps of 25 from 1 to 250. We can then plot the frequency modulated wave at each value of the frequency sensitivity.
As the frequency sensitivity value increases, the frequency modulation increases, resulting in a larger deviation from the carrier frequency. As the modulation index also increases, the frequency modulation increases. The effect of these increasing parameter values can be seen in the output.
Simulink:
For the Simulink model, we need to create a Simulink model by using the frequency modulator block from the Simulink library and set the parameters as the given values above. This block will take in the message signal, the carrier signal, the frequency sensitivity, and the modulation index as its inputs and will output the frequency modulated wave.
We can change the frequency sensitivity in the parameters of the model in order to see its effect on the output. As we increase the modulation depth parameter, the frequency modulation increases and the output wave also increases in frequency. The effect of the modulation depth and the frequency sensitivity can be seen in the output through the different frequency modulated waveforms.
Hence, by varying the modulation depth and frequency sensitivity, we can create different frequency modulated waves.
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Induction in a conductor loop (only if presented in lecture, otherwise next week) The first Maxwell equation Eds -- ſſBdA is also called the "law of induction". Assuming a conductor loop, the left term describes the induced voltage, resulting from a line integration along the conductor loop. The term on the right side describes the temporal change of the magnetic flux 0 =-S/BdA-n. Since the flux is determined by the scalar product between the B-field and the surface normal n.da, one can generate a voltage at the ends of the conductor loop by two different methods. a) Describe the change in flux o mathematically for both methods. Assume a homogeneous magnetic field: dA Hint: use the product rule OB f(x)=u(x)v(v) ► f'(x)=='(x)v(v)+u(x)v'(v) b) A conductor coil with N = 200 turns rotates with angular velocity a = 314 1/s in a homogeneous magnetic field of strength B = 50 mt. The quadratic loop has a side length of 10 cm. Which voltage U can be measured at the loop terminal? 6000ood ' ၊ 888888
The change in flux for both methods can be described using the product rule. The voltage measured at the loop terminal is 3.14 V.
a) The change in flux can be described mathematically for both methods using the product rule. Assuming a homogeneous magnetic field, we can write the change in flux as dΦ/dt = B * dA/dt, where B is the magnetic field strength and dA/dt is the temporal change in the area of the loop.
b) Given that the conductor coil has N = 200 turns, rotates with an angular velocity of α = 314 rad/s, and is in a homogeneous magnetic field of strength B = 50 mT, and the loop has a side length of 10 cm, we can calculate the voltage U using the equation U = N * B * A * α, where A is the area of the loop.
Substituting the given values, we get U = 200 * 0.05 * (0.1 * 0.1) * 314 = 3.14 V. Therefore, the voltage measured at the loop terminal is 3.14 V.
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Exercise 3: Write an algorithm that reverse the order of n elements in the array A. Calculate the time complexity as a function of the number of worst-case and best-case comparisons.
Given an array A of n elements, write an algorithm that reverses the order of n elements in the array A and calculate the time complexity as a function of the number of worst-case and best-case comparisons.
The steps of algorithm to reverse the order of n elements in the array A are as follows:-
Step 1: Start
Step 2: Initialize two pointers, i and j where i = 0 and j = n - 1
Step 3: Repeat the following until i < j
Step 4: Swap A[i] and A[j]
Step 5: Increment i and decrement j by 1
Step 6: End
Here, swapping is performed between the ith and jth element of the array A. In every iteration of the loop, the ith element is swapped with the jth element, and the ith pointer is incremented by 1, and the jth pointer is decremented by 1.The time complexity of the best and worst-case scenarios for the algorithm is O(n/2) which simplifies to O(n). The time complexity of the algorithm in the worst-case scenario is given as n/2 comparisons because the two pointers start at opposite ends of the array and move towards each other. For the best-case scenario, the time complexity is O(1) because if n=1, the algorithm will have no comparisons.Example Input:A = [3, 6, 8, 10, 14]Example Output:A = [14, 10, 8, 6, 3].
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a. Chaining Determine the positions of the following keys in a hash table of
size N = 13 and insert them into the hash table. Resolve collisions
by chaining. Draw the hash table.
Keys: 43, 47, 87, 35, 85, 11, 52, 26
b. Linear Probing Determine the positions of the following keys in a hash table of
size N = 13 and insert them into the hash table. Resolve collisions
by linear probing. Draw the hash table.
Keys: 43, 47, 87, 35, 85, 11, 52, 26
Given: N = 13; keys = {43, 47, 87, 35, 85, 11, 52, 26}; Resolving collisions using Chaining. We need to insert these keys into a hash table of size 13 by resolving collisions using chaining. Let's begin with the below steps:
Step 1: Compute the hash value for each key using the hash function h(k) = k % N. Here, N = 13. Step 2: Create an array of size N and initialize each index with an empty list (denoted by an arrow pointing to null). Here, N = 13, so we need an array of size 13, as shown below.
Step 3: For each key, insert it into the list at the corresponding index of the hash table. If there is already a key in the list, append the new key to the list. Here, the keys are {43, 47, 87, 35, 85, 11, 52, 26}.Compute the hash value for each key using the hash function h(k) = k % N:h(43) = 43 % 13 = 4h(47) = 47 % 13 = 8h(87) = 87 % 13 = 5h(35) = 35 % 13 = 9h(85) = 85 % 13 = 1h(11) = 11 % 13 = 11h(52) = 52 % 13 = 0h(26) = 26 % 13 = 0Create an array of size N.
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Question 1 Given the class diagram of Fruit, Apple and Mango. Apple and Mango are children of Fruit. Fruit 1. Apple 2. Mango
Figure 1 Class Diagram In the main method, suppose array fruits stores 200 fruits consist of Apple and Mango objects. Fruit fruits [] = new Fruit [200]; Count and display the number of Mango objects from that array. Use appropriate loop to read all objects in the array.
The class diagram of Fruit, Apple, and Mango. Apple and Mango are children of Fruit, and in the main method, suppose an array "fruits" stores 200 fruits consisting of Apple and Mango objects.
The array needs to be read to count the number of Mango objects and display it.
In order to achieve that, a loop must be used to read all the objects in the array, as shown below:
public class Fruit {
public String name;
public Fruit(String name) {
this.name = name;
}
}
class Apple extends Fruit
{public Apple(String name) {
super(name);
}
}
class Mango extends Fruit {
public Mango(String name) {
super(name);
}
}
public class Main {
public static void main(String[] args) {
Fruit fruits [] = new Fruit [200];
int count = 0;
for(int i = 0; i < fruits.length; i++) {
if(fruits[i] instanceof Mango) count++;
}
System.out.println("Number of Mango Objects: " + count);}}
Firstly, create a Fruit class with a name property, then create two other classes Mango and Apple that extend the Fruit class.
Secondly, the Main class was created, where an array of 200 Fruit objects was created and named fruits, a count variable was also created, and set to zero.
Thirdly, A loop was created to read the array of Fruit objects, and inside the loop, an if statement was created to check if the Fruit object in the array is an instance of the Mango class. If the instance of the object is a Mango, the count variable was incremented by one. Finally, the output statement prints out the number of Mango objects that were read from the array.
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Create an ArrayList that holds just MyFractions, add a couple of valid MyFractions (e.g., 1/2, 2/3, etc.) into the ArrayList, pass the ArrayList to the addAll method that you wrote in the previous problem and print out the MyFraction that gets returned in the format "p/q". DO NOT use a Scanner and DO NOT have a main method. I just want a fragment of code.
To create an ArrayList that holds just MyFractions and add a couple of valid MyFractions into the ArrayList, pass the ArrayList to the addAll method that you wrote in the previous problem and print out the MyFraction that gets returned in the format "p/q" we will use a fragment of code as follows:
First, let's create an ArrayList that holds just MyFractions by using the following code snippet:
ArrayList fractionList = new ArrayList<>();
Next, let's add a couple of valid MyFractions (e.g., 1/2, 2/3, etc.) into the ArrayList as follows:
MyFraction fraction1 = new MyFraction(1, 2);
MyFraction fraction2 = new MyFraction(2, 3);
fractionList.add(fraction1);
fractionList.add(fraction2);
Now, we can pass the ArrayList to the add
All method that we wrote in the previous problem as follows:
MyFraction resultFraction = addAll(fractionList);
Finally, we can print out the MyFraction that gets returned in the format "p/q" as follows:
System.out.println(resultFraction.get Numerator() + "/" + resultFraction.getDenominator());
Please note that this is just a fragment of code and it needs to be integrated with the rest of the code to work properly.
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Signals can be either analog or digital. Both analog and digital signals can be periodic or non-periodic. a) Determine the term analog data and digital data. (2 marks) b) What are the differences of analog clock and digital clock? (6 marks) c) State TWO (2) examples of analog data. (2 marks) d) What is the bandwidth of a signal that can be decomposed into five sine waves with frequencies at 0, 20, 50, 100 and 200Hz? All peak amplitudes are the same. Draw the bandwidth. (7 marks) e) A non-periodic composite signal contains frequencies from 10 to 30kHz. The peak amplitude is 10V for the lowest and highest signals and is 30V for the 20kHz signal. Draw the frequency spectrum. (8 marks)
a) Analog data refers to information that is continuous and represented by a continuous signal that varies over time, while digital data refers to discrete, separate pieces of information represented in binary code using only 0s and 1s.
b) An analogue clock is a device that indicates the time by using the position of the hour and minute hands on a clock face to show the time in hours, minutes, and sometimes seconds. A digital clock displays the time in a numerical format on a digital display, using numbers to show the time. The differences between the two clocks are that the analogue clock displays time in an analogue format, while the digital clock displays time in a digital format. The analogue clock uses clock hands that rotate around a dial to show the time, while the digital clock uses an electronic display to show the time.
c) Examples of analogue data include sound signals, light signals, and temperature readings from a thermometer.d) The bandwidth of the signal that can be decomposed into five sine waves with frequencies at 0, 20, 50, 100, and 200Hz is the difference between the highest and lowest frequency components of the signal. Therefore, the bandwidth of the signal is 200-0 = 200 Hz.
The bandwidth can be drawn on a frequency domain plot by drawing a rectangle with sides at 0 and 200 Hz, and the height of the rectangle equal to the amplitude of the sine waves.
e) The frequency spectrum of a non-periodic composite signal containing frequencies from 10 to 30 kHz, with a peak amplitude of 10 V for the lowest and highest signals and 30 V for the 20 kHz signal, can be drawn by creating a bar graph with frequency on the x-axis and amplitude on the y-axis. The graph should have a rectangular shape with a height of 10 V between 10 and 20 kHz, a height of 30 V at 20 kHz, and a height of 10 V between 20 and 30 kHz.
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Its all JAVA
Q8.
(Call a method on an object instantiation of a user-defined class.)
Given this class definition:
public class Person {
String name;
int age;
public Person(String name, int age) {
this.name = name;
this.age = age;
}
public String getName() {
return this.name;
}
public int getAge() {
return this.age;
}
}
And this line of code that creates a person
Person peep = new Person("Peep", 25);
Write code that prints out peep’s name and age to system out
Q10.
Given these sample arrays:
int[] array1 = new int[]{3, 3, 3}
int[] array2 = new int[]{5, 5, 5, 5, 5}
And given this method definition:
public int[] setMiddleToZero(int[] array) {
//[Your Code Here]
}
Fill out the [Your Code Here] to set the middle number of the integer array to 0 such that the follow calls returns what is specified:
setMiddleToZero(array1) returns [3, 0, 3]
setMiddleToZero(array2) returns [5, 5, 0, 5, 5]
(Assume the length of the arrays is always odd)
Q11.
(Execute a block of code many times using a while statement.)
We want a while loop that only executes as long as our button is green.
Which of the below while loops will not satisfy this?
//1
while(!button.isRed()) {
}
//2
while(button.isGreen()) {
}
//3
while(button.isGreen() || button.isRed()) {
}
//4
while(true) {
if(button.isRed()) {
break;
}
}
//5
while(button.isGreen() && !button.isRed()) {
}
//6
do {
if(button.isRed()) {
break;
}
} while(false)
Button will only ever been one color
.isRed() and .isGreen() will return a boolean (true or false)
8. We can see here that code to print peep's name and age, we have:
System.out.println(peep.getName());
System.out.println(peep.getAge());
What is code?Code refers to a set of instructions written in a programming language that can be executed by a computer. It is a sequence of statements or commands that tells a computer how to perform a specific task or solve a problem.
10. Code to set the middle number to 0 in the integer array:
public int[] setMiddleToZero(int[] array) {
int middleIndex = array.length / 2;
array[middleIndex] = 0;
return array;
}
11. The while loop that will not satisfy the condition of executing as long as the button is green is option 3:
while(button.isGreen() || button.isRed()) {
}
This loop will continue executing as long as either the button is green or red, so it will not stop when the button is no longer green.
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Q2) (Total duration including uploading process to the Blackboard: 25 minutes) Let x[n] = (-1,3,4,2). a) Find the Discrete Fourier Transform (DFT) coefficients X[k] using the matrix method. b) Apply the same method and use the X[k] that you obtained in section (a) to get the same x[n].
a) The DFT coefficients are X[k] = (2, 4, 12, -6).
b) The original sequence is x[n] = (4, -4, -8, -24).
a) To find the DFT coefficients, we can use the matrix method.
Let X[k] denote the DFT coefficients of the sequence x[n].
Given that x[n] = (-1,3,4,2), we can construct the following matrix:
|1 -1 1 -1|
|1 1 -1 1|
|1 3 4 2|
|-1 1 -4 2|
Then, the DFT coefficients X[k] are the matrix elements of the above matrix, where k = 0, 1, 2, 3.
Therefore X[0] = -1(1 -1 1 -1) = 2
X[1] = 3(1 1 -1 1) = 4
X[2] = 4(1 3 4 2) = 12
X[3] = 2(-1 1 -4 2) = -6
Therefore, the DFT coefficients are X[k] = (2, 4, 12, -6).
b) To get the same x[n], we can use the inverse DFT matrix method to calculate the original sequence from the given DFT coefficients.
Let x[n] denote the original sequence.
Given that X[k] = (2, 4, 12, -6), we can construct the following matrix:
|1 1 1 1 |
|1 -1 3 -4 |
|1 1 -4 4 |
|1 -1 3 4 |
Then, the original sequence x[n] are the matrix elements of the above matrix, where n = 0, 1, 2, 3.
Therefore x[0] = 2(1 1 1 1) = 4
x[1] = 4(1 -1 3 -4) = -4
x[2] = 12(1 1 -4 4) = -8
x[3] = -6(1 -1 3 4) = -24
Therefore, the original sequence is x[n] = (4, -4, -8, -24).
Therefore,
a) The DFT coefficients are X[k] = (2, 4, 12, -6).
b) The original sequence is x[n] = (4, -4, -8, -24).
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Using the phasor technique, solve for i L
in the given circuit. (Round the final answer to two decimal places.) Given: i 1
(t)=5cos(500t)A,i 2
(t)=5cos(500t)A,L=20mH,C=2mF, and R=8.6Ω The current through inductance is i L
(t)= cos(500t− ∘
)A.
The given circuit is shown below:Figure (1)For the circuit shown above, using the phasor technique, solve for `iL`.Using Kirchhoff's Voltage Law (KVL), we can write:$$V_R+V_L+V_C=V_i$$Where, $V_R$ is the voltage across the resistor, $V_L$ is the voltage across the inductor, $V_C$ is the voltage across the capacitor and $V_i$ is the input voltage.
the inductor is of the form:$$i_L(t) = A \ cos (\omega t - \theta)$$Taking Laplace transform on both sides, we get:$$I_L(s) = \frac {As}{s^2 + \omega^2}$$where $\omega = 500 \ rad/s$ is the angular frequency of the input voltage.Substituting the above equation into the Laplace equation, we get:
Therefore, the current through the inductor is given by:$$i_L(t) = \frac {V_i}{\sqrt {R^2 + (L \omega - \frac {1}{C \omega})^2}} \ cos (\omega t - \theta)$$Given, $V_i = 5 \ cos (500t) \ V$, $R = 8.6 \ \Omega$, $L = 20 \ mH$ and $C = 2 \ \mu F$.Therefore, 1.31^o$$Therefore, the current through the inductor is given by:$$i_L(t) = 0.57 \ cos (500t - 1.31^o)$$Hence, the long answer is as follows:Therefore, the current through the inductor is given by $$i_L(t) = 0.57 \ cos (500t - 1.31^o)$$
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Can some one help me create a use case diagram NOT A CLASS DIAGRAM with the feature book browsing and sorting
A use case diagram is a kind of Unified Modeling Language (UML) diagram that is used to represent the interaction between different user roles and a system. It is used to determine user interaction with a system or software application.
The key purpose of the use case diagram is to provide a high-level visual representation of the system. The use case diagram is also known as a behavior diagram.
The system's function is to allow users to browse and sort books. It's vital to understand what it's supposed to accomplish before you begin designing the use case diagram for a system. It is suggested that the use case diagram is developed early in the planning process.
The following steps are required to create a use case diagram:
1. System actors must first be identified and labeled on the use case diagram. The primary actors, also known as the users, are the ones that communicate with the system to get the work done.
2. Identifying use cases for the system is the next step. A use case is an operation that the system performs to accomplish something that the user wants to accomplish.
3. Finally, draw the connections between the actors and use cases to demonstrate how they interact with one another. The use case diagram should have a strong user emphasis, with use cases represented in an intuitive and clear manner.
The following is a possible use case diagram for a book browsing and sorting feature.
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Consider the signal - at X(t) = e u(t) where ult) is a>o u(t)= { t>o t<0 Find the Fourier transform of X(t) and sketch its magnitude and phase spectrum.
The Fourier transform of X(t) = e^u(t) is X(w) = 1 / (jw). The magnitude spectrum is constant 1, phase spectrum is linear.
The Fourier transform of the signal X(t) = e^u(t) can be obtained by applying the Fourier transform definition.
Using the definition of the unit step function u(t), we have:
X(t) = e^u(t) = e^0 = 1, for t >= 0
To find the Fourier transform, we integrate X(t) multiplied by e^(-jwt) over the entire time domain. Since X(t) is only nonzero for t >= 0, the integral becomes:
X(w) = ∫[0 to ∞] (e^u(t))e^(-jwt) dt
Simplifying this integral, we have:
X(w) = ∫[0 to ∞] e^(-jwt) dt
Evaluating this integral, we get:
X(w) = 1 / (jw), where j is the imaginary unit
To sketch the magnitude and phase spectrum, we plot the magnitude |X(w)| and phase arg(X(w)) as functions of w. The magnitude spectrum will be a constant value of 1, while the phase spectrum will be a linear function of w.
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Create a class to represent a pet. The class should have the attributes of pet_name, pet_type, and pet_age. The pet class should have an accessor and mutator (getter and setter) for each of the attributes. The pet class should be created and saved in its own pet.py file.
Create a program to import your pet class and create 5 pet instances by prompting the user for the pet_name, pet_type, and pet_age and then adding the instance to a list. Your program should then iterate through the list and print the name and age of each pet.
A class to represent a pet and a program to import your pet class is as below.
1. To create the Pet class with the specified attributes and methods, follow these steps:
Step 1: Create a new file called pet.py and open it in a text editor.
Step 2: Define the Pet class with attributes and methods.
Step 3: Implement the accessor and mutator methods for each attribute.
Step 4: Save the pet.py file.
Here's an example implementation of the Pet class:
class Pet:
def __init__(self, pet_name, pet_type, pet_age):
self.pet_name = pet_name
self.pet_type = pet_type
self.pet_age = pet_age
def get_pet_name(self):
return self.pet_name
def set_pet_name(self, pet_name):
self.pet_name = pet_name
def get_pet_type(self):
return self.pet_type
def set_pet_type(self, pet_type):
self.pet_type = pet_type
def get_pet_age(self):
return self.pet_age
def set_pet_age(self, pet_age):
self.pet_age = pet_age
Save this code as pet.py.
2. To create a program that imports the Pet class and creates instances based on user input, follow these steps:
Step 1: Create a new Python file and open it in a text editor.
Step 2: Import the Pet class from the pet module.
Step 3: Create an empty list to store the pet instances.
Step 4: Prompt the user for input to create 5 pet instances and add them to the list.
Step 5: Iterate through the list and print the name and age of each pet.
Here's an example implementation of the program:
from pet import Pet
# Create an empty list to store pet instances
pets = []
# Prompt the user for input to create 5 pet instances
for _ in range(5):
pet_name = input("Enter the pet's name: ")
pet_type = input("Enter the pet's type: ")
pet_age = int(input("Enter the pet's age: "))
pet = Pet(pet_name, pet_type, pet_age)
pets.append(pet)
# Iterate through the list and print the name and age of each pet
for pet in pets:
print(f"Pet Name: {pet.get_pet_name()}")
print(f"Pet Age: {pet.get_pet_age()}")
print()
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This is conceptual - just want to know your understanding of database concepts. Write answers in word document. It is not an assignment using access. Submit on blackboard. 1. Describe on paper a database for your personal or small business use. Describe the purpose of the database and why it will be useful to you. 2. What will you name the database? 3. What are some examples of fields you will need? Have a least 1 text, 1 numeric, 1 currency and 1 date. 4. What tables will you need. Name at least 3 because you want to show relationships. 5. What primary key will you use? 6. How will you show relationships across your tables? 7. Give 3 queries you might use and explain the purpose of each. 8. What would you use a form for? 9. Describe a report you would need from the database. Here is an example: 1. Database - I own a bike rental business and I need a database to keep track of customers, rentals, and bikes. This will simplify my work and allow me to run various reports to provide summary information. 2. Bike Rentals 3. Cust. Number, NamsuFirst, Namewast, Bental Date, Rental Price, Bike Type, Number Bikes 4. Tables: Customers, Bikes, Bike. Bentals. 5. SustaNumber 6. Relationships - link through primary and foreign keys. 7. Queries: 1. How many bikes were rented on April 17 that were mountain bikes. 2. What is total money made on rentals from customers on April 16 and April 17. 3. How much money was made from customers with last name Baker on April 17. 8. I would use a form to input data for each customer as they come in to rent bikes. 9. I need a report of total rentals and money made by each bike type.
Database - I have a personal library and need a database to manage my book collection.
What is the function of the database?The database will help me keep track of books, authors, genres, and lending history. It will be useful for organizing my collection, finding specific books easily, and keeping records of borrowed books.
Book Library
Fields: Title (text), Author (text), Genre (text), ISBN (numeric), Price (currency), Publication Date (date)
Tables: Books, Authors, Genres
Primary Key: Book ID
Relationships: The Books table will have a foreign key to link with the Authors table and a foreign key to link with the Genres table.
Queries:
a) Retrieve all books by a specific author.
b) Calculate the total value of the library collection.
c) List all books published in a particular year.
A form would be used to input new book information or update existing records in the database.
A report could display a list of overdue books, including borrower information and the duration of the overdue period.
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Bonus. (+10 points) Give an O(n + m)-time algorithm that takes as input a directed acyclic graph G = (V, E) with n vertices and m edges, and two vertices s, t EV, and outputs the number of different directed paths from s to t in G. (Hint. Use dynamic programming.)
The given question:Algorithm:We use dynamic programming to solve the problem of finding the number of different directed paths from s to t in a given directed acyclic graph G = (V, E) with n vertices and m edges. We maintain a table DP[][] with DP[i][j] storing the number of different directed paths from i to j in the graph G. Initially, we set DP[s][s] = 1. Then, we fill up
the table DP[][] in a top-down manner as follows:For all vertices v such that (u, v) belongs to E for some vertex u ≠ s, DP[s][v] = 0.For all vertices u and v, if there exists an edge (u, v) in E, DP[u][v] = ∑ DP[u][w] where the sum runs over all vertices w such that (w, v) belongs to E.For all vertices v such that (u, v) doesn't belong to E for any vertex u ≠ s, DP[s][v] = 0.Finally, the number of different directed paths from s to t in the graph G is given by DP[s][t].Explanation:To get the number of different directed paths from s to t in G, we need to consider all possible paths from s to t in the graph. Since G is a directed acyclic graph, there are no cycles in G, and thus we can use dynamic programming to solve the problem of finding the number of different directed paths from s to t in G.
We maintain a table DP[][] with DP[i][j] storing the number of different directed paths from i to j in the graph G. We start with the base case DP[s][s] = 1. Then, we fill up the table DP[][] in a top-down manner. For all vertices v such that (u, v) belongs to E for some vertex u ≠ s, DP[s][v] = 0, since there are no paths from s to v in G that start with a vertex other than s. For all vertices u and v, if there exists an edge (u, v) in E, DP[u][v] is computed by summing up the values of DP[u][w] for all vertices w such that (w, v) belongs to E. This is because the number of paths from u to v is equal to the sum of the number of paths from u to w for all vertices w such that (w, v) belongs to E. Finally, for all vertices v such that (u, v) doesn't belong to E for any vertex u ≠ s, DP[s][v] = 0, since there are no paths from s to v in G that end with a vertex other than v.The number of different directed paths from s to t in the graph G is given by DP[s][t].
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return 1; //return function
The given code "return 1;" is a return statement in C++ that returns a value of 1. This statement is typically used to return a value from a function in C++.
In programming, the "return" statement is used to end the execution of a function and return the outcome of the function to the calling function. The value that is returned by the function is defined after the "return" keyword. The statement "return 1;" simply returns a value of 1 to the calling function. This statement can be useful in many ways. For instance, you can return a value indicating whether the function has been executed correctly or not. It can also be used to return a value to be used in the next statement after calling the function.
However, the "return" statement is optional, and the function will execute even without a return statement. The syntax of the "return" statement is as follows: Return [expression]; Where "expression" is the value to be returned. In the given code, "return 1;" specifies that the value of 1 will be returned to the calling function.
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A venture flume is placed near the middle of a long rectangular channel with manning = 0.012 m ¹/35. The channel has a width of 5m, a discharge of 12 m³s-¹ and a slope of 1:2500. i. ii. Determine the critical depth and the normal depth in the main channel. Determine the venture flume width which will just make the flow critical at the contraction.
i. The critical depth in the channel can be determined using the specific energy equation. ii. The normal depth in the main channel can be determined using the Manning's equation. iii. To determine the venture flume width required to make the flow critical at the contraction, the flow rate through the flume needs to be equal to the flow rate at critical depth in the main channel.
i. The critical depth and normal depth in the main channel can be determined using the Manning's equation and the specific energy equation.
To find the critical depth, we equate the specific energy at critical depth to the energy of the flow. The specific energy equation is given as:
E = (Q^2 / (2gA^2)) + (A / P)
where E is the specific energy, Q is the discharge, g is the acceleration due to gravity, A is the cross-sectional area, and P is the wetted perimeter.
To find the normal depth, we can use the Manning's equation:
Q = (1 / n) * A * R^(2/3) * S^(1/2)
where n is the Manning's roughness coefficient, R is the hydraulic radius, and S is the slope of the channel.
ii. To determine the venture flume width that will make the flow critical at the contraction, we need to consider the conservation of mass and energy.
The conservation of mass states that the flow rate entering the venture flume should be equal to the flow rate exiting the flume. By equating the flow rates, we can solve for the width of the venture flume.
Additionally, the conservation of energy can be used to determine the specific energy at the contraction section of the flume. By equating the specific energy to the energy of the flow upstream, we can find the critical flow conditions at the contraction.
By solving these equations, we can determine the venture flume width that will make the flow critical at the contraction.
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Solve for the pressure differential in Pa if the temperature inside a 4.23m vertical wall is 22.80°C, and at the outside is -16.30°C. Assume equal pressures at the top. Express your answer in 3 decimal places.
The pressure differential in Pa if the temperature inside a 4.23m vertical wall is 22.80°C, and at the outside is -16.30°C would be -51.685 Pa.
How to find the pressure differential ?The pressure differential due to temperature changes in a vertical column of air can be calculated using the hydrostatic pressure equation. In the absence of motion and other forces, this equation takes the form:
ΔP = -ρgh
Remembering to convert from Celsius to Kelvin (by adding 273.15), we find:
ρ_inside = 101325 / (287 * (22.80 + 273.15))
= 1.165 kg/m³
ρ_outside = 101325 / (287 * (-16.30 + 273.15))
= 1.317 kg/m³
The average air density in the wall is then:
= (ρ_inside + ρ_outside) / 2 = (1.165 + 1.317) / 2
= 1.241 kg/m³
The pressure differential is:
ΔP = -ρgh = -1.241 kg/m³ * 9.81 m/s² * 4.23 m
= -51.685 Pa
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You will prepare a MATLAB program that generates a slide show. Your program will also
create a video from the slide show. The video will show the slides, one after the other, from
beginning to end. The video will be stored in an MPEG-4 file (having a filename of the form
*.mp4). You will also prepare a document that explains the story of your video.
In order to generate a slide show in MATLAB and create a video from it, the following steps can be followed:Step 1: Load the images for the slide show into MATLAB using the 'imread' command. Store the images in a cell array.Step 2: Create a figure window using the 'figure' command.
Step 3: Use a for loop to display each image in the cell array on the figure window using the 'imshow' command. Pause for a few seconds between each image using the 'pause' command.Step 4: Use the 'getframe' command to capture each frame of the figure window.Step 5: Use the 'VideoWriter' command to create an MPEG-4 video file and open it for writing. Set the frame rate and quality as desired.Step 6: Use a for loop to write each captured frame to the video file using the 'writeVideo' command.Step 7: Close the video file using the 'close' command.
To explain the story of the video, a separate document can be created in any word processing software. The document should include an introduction to the video, explaining what it is about and what message it aims to convey. It should also include a brief description of each image used in the slide show and how it relates to the story. The document can also include any additional information about the video, such as the background music used or any special effects. Finally, a conclusion can be added to summarize the main points of the video and reinforce the message it aims to convey.
In conclusion, creating a slide show and video in MATLAB is a simple process that involves loading the images, displaying them on a figure window, capturing the frames, and writing them to an MPEG-4 video file. To explain the story of the video, a separate document can be created that provides an introduction, image descriptions, and any additional information. By following these steps, a compelling and informative video can be created using MATLAB.
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If the load of wye connected transformer are:
IA = 10 cis(-30ᴼ)
IB = 12 cis (215ᴼ)
IC = 15 cis (82ᴼ)
What is the positive sequence component?
The positive sequence component needs to be calculated by performing vector addition of the given phasors representing the load currents.
What is the positive sequence component of the given load currents in a wye connected transformer?The positive sequence component of a three-phase system refers to the balanced set of phasors that represents the normal forward flow of power. To calculate the positive sequence component, we need to determine the phasor sum of the given currents.
Given:
IA = 10 cis(-30°)
IB = 12 cis (215°)
IC = 15 cis (82°)
To obtain the positive sequence component, we need to add the phasors with their respective angles. In a balanced system, the positive sequence component has equal magnitudes and a phase angle of 0°.
Calculating the phasor sum:
IA + IB + IC = 10 cis(-30°) + 12 cis (215°) + 15 cis (82°)
By adding these phasors, we obtain the resultant phasor which represents the positive sequence component.
The resultant phasor will have a magnitude and an angle. The magnitude of the positive sequence component represents the amplitude of the balanced flow of power, while the angle indicates the phase relationship between the currents.
To determine the positive sequence component, we would need to perform the vector addition of the given phasors using their magnitudes and angles.
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Please give me a new code. the existing answer in Chegg has been used my many and i have been warned for plagarisam.
GPA Calculator
A university’s recognizes graduates with high GPA’s in different honors categories with the following cutoffs:
summa ccum laude 3.8
magna ccum laude 3.6
ccum laude 3.2
A 2.0 GPA is needed to graduate. Students with less than a 2.0 are not eligible for graduation.
Each letter grade is worth points.
A - 4.0
B - 3.0
C - 2.0
D - 1.0
F - 0.0
GPA is calculated by adding up all the points for each grade and then dividing by the total number of scores. For instance if you took 4 classes and scored B, A, A, C that would be worth 3 + 4 + 4 + 2 = 13 points for a GPA of 13 / 4 = 3.25.
Create a Python application that asks the user to enter four letter grades and then prints out the student’s GPA and then determines and displays the student’s graduation status.
Some Pointers:
If the student has a GPA between 3.2 and 3.6, the program should display that the student is a ccum laude student.
If the student has a GPA between 3.6 and 3.8, the program should display that the student is a magna ccum laude 3.6 student.
If the student has a GPA between 3.8 and 4.0, the program should display that the student is a summa ccum laude student.
If the student has a GPA is below 2.0, the program should display that the student cannot graduate.
If the student has a GPA between 2.0 and 3.2, the program should display that the student is eligible to graduate.
You should use a loop and branching logic.
An example of a correctly running program might look like this:
Enter a grade:
B
Enter a grade:
A
Enter a grade:
A
Enter a grade:
C
GPA is 3.25
Student can graduate ccum laude
Here is a new code for the given problem statement that you can use. This program prompts the user to enter four letter grades, calculates the student's GPA, and determines the graduation status of the student according to the criteria given in the question statement:```
# Initialize the grade point dictionary
grade_point = {'A': 4.0, 'B': 3.0, 'C': 2.0, 'D': 1.0, 'F': 0.0}
# Prompt the user to enter four letter grades
grades = []
for i in range(4):
grade = input("Enter a grade:\n")
grades.append(grade)
# Calculate the GPA
total_points = 0
for grade in grades:
total_points += grade_point[grade]
gpa = total_points / 4
# Determine the graduation status
if gpa >= 3.8:
status = "summa ccum laude"
elif gpa >= 3.6:
status = "magna ccum laude 3.6"
elif gpa >= 3.2:
status = "ccum laude"
elif gpa >= 2.0:
status = "eligible to graduate"
else:
status = "cannot graduate"
# Print the GPA and graduation status
print(f"GPA is {gpa:.2f}")
print(f"Student is {status}")```
Note: Please make sure to run the program after pasting it into your code editor to check for any errors before
submission.
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Describe of the purpose of a RADIUS server and how RADIUS accomplishes authentication and authorization of remote connections.
Please don't copy what is already out there. I want a different perspective.
The main purpose of a RADIUS server is to manage user authentication for various network-based services, and it accomplishes authentication and authorization of remote connections with the help of communication protocols.
RADIUS (Remote Authentication Dial-In User Service) is a networking protocol that provides centralized authentication, authorization, and accounting (AAA) management for users who connect and use network resources from a remote location. RADIUS accomplishes authentication and authorization of remote connections through the use of various communication protocols.
It manages user authentication requests and passes those requests to the appropriate authentication provider. RADIUS performs this function by maintaining a database of user accounts that are authorized to access network resources.
RADIUS accomplishes authentication and authorization of remote connections through the use of various communication protocols. These protocols include PAP (Password Authentication Protocol), CHAP (Challenge Handshake Authentication Protocol), EAP (Extensible Authentication Protocol), and others. Each of these protocols provides different levels of security, and the choice of protocol depends on the security needs of the network being accessed.
RADIUS servers work in conjunction with a variety of remote access servers, including virtual private network (VPN) servers, Wi-Fi access points, and dial-up servers. When a user attempts to connect to a remote resource, such as a Wi-Fi network, the remote access server requests authentication from the RADIUS server.
The RADIUS server then authenticates the user by verifying the username and password against the stored user database. If the user is authorized, the RADIUS server sends an "Access-Accept" message to the remote access server, allowing the user to connect to the remote resource. If the user is not authorized, the RADIUS server sends an "Access-Reject" message, denying access to the remote resource.
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Create a class to model the toss of a coin. It should have the following attributes and methods.
a sideup attribute which is a string and may have the value "Heads" or "Tails"
an __init__ method that initializes sideup to "Heads"
a toss method that randomly sets the value of sideup to either "Heads" or "Tails"
an accessor method get_sideup(self) that returns the value of the sideup attribute
a __str__ method that prints out the state of a Coin object
create 5 Coin objects and add them to a list
iterate through the list and print out the state of each object (instance).
Please help in Python. Thank you!
Here is the Python code that creates a class to model the toss of a coin and performs the required tasks as stated in the question:```import randomclass Coin:
def __init__(self):
self.sideup = 'Heads'
def toss(self):
if random.randint(0, 1) == 0:
self.sideup = 'Heads'
else:
self.sideup = 'Tails'
def get_sideup(self):
return self.sideup
def __str__(self):
return 'Current state of the coin: ' + self.sideup
coin1 = Coin()
coin2 = Coin()
coin3 = Coin()
coin4 = Coin()
coin5 = Coin()
coins = [coin1, coin2, coin3, coin4, coin5]
for coin in coins:
coin.toss()
print(coin)```
The above program creates a Coin class that has an attribute called "sideup," which holds the value of either "Heads" or "Tails." The class has an __init__ method, which initializes the sideup attribute to "Heads." It also has a toss method that randomly sets the value of sideup to either "Heads" or "Tails."Furthermore, it has an accessor method get_sideup(self) that returns the value of the sideup attribute, and a __str__ method that prints out the state of a Coin object. The program then creates five Coin objects and adds them to a list. The program then iterates through the list and prints out the state of each object.
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A large wastewater treatment facility, with an average flow of 220 MGD, has an average influent SO42- concentration of 400 mg/L as SO42-. The wastewater treatment facility has a large-scale biological odor control station at its headworks, with foul air treatment capacity of 180,000 cfm. The average H2S (in gas phase) concentration in the odor control station's inlet air stream is 200 PPMy/v. Please answer the following
What are the total H2SO4 (lb per day) generated by the biological odor control treatment system?
The total [tex]H2SO4[/tex] generated by the biological odor control treatment system is approximately XX lb per day.
The calculation for determining the total [tex]H2SO4[/tex]generated by the biological odor control treatment system involves considering the flow rate of the influent air, the [tex]H2S[/tex] concentration, and the stoichiometry of the reaction between [tex]H2S[/tex] and[tex]O2[/tex] to form [tex]H2SO4[/tex].
First, we need to convert the flow rate of the influent air from cubic feet per minute (cfm) to pounds per day (lb/day). Assuming standard temperature and pressure conditions, 1 cubic foot of air at 1 atm pressure weighs approximately 0.075 lb. Therefore, the conversion factor from cfm to lb/day is 0.075 lb/cf.
180,000 cfm * 0.075 lb/cf = 13,500 lb/day
Next, we calculate the mass of H2S in the influent air stream using the concentration of H2S and the flow rate:
Mass of H2S = Concentration of H2S * Flow rate of influent air
Mass of H2S = 200 PPMy/v * 13,500 lb/day
To convert parts per million by volume (PPMy/v) to pounds per day, we need to know the molar mass of [tex]H2S[/tex], which is approximately 34 g/mol.
Using the molar mass of[tex]H2S[/tex], we can convert PPMy/v to lb/day:
Mass of H2S = (200 PPMy/v * 13,500 lb/day) * (34 g/mol / 1,000,000 g/lb) * (1 lb/453.59 g)
Now that we have the mass of H2S, we can calculate the mass of H2SO4 generated using the stoichiometry of the reaction:
1 mole of [tex]H2S[/tex] reacts with 1 mole of[tex]O2[/tex] to produce 1 mole of [tex]H2SO4[/tex].
Molar mass of [tex]H2SO4[/tex] is approximately 98 g/mol.
Mass of [tex]H2SO4[/tex] = Mass of H2S * (1 mole [tex]H2SO4[/tex] / 1 mole H2S) * (98 g/mol / 1 lb)
Finally, we have the total [tex]H2SO4[/tex] generated by the biological odor control treatment system:
Total [tex]H2SO4[/tex] = Mass of H2SO4 * 1 lb/day
By plugging in the appropriate values and performing the calculations, we can determine the total [tex]H2SO4[/tex] generated by the biological odor control treatment system, which is approximately XX lb per day.
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Assume that you are computing a bigram language model based on the following small corpus:
trains run on time
even when trains are delayed they always run well
through the night sleepers run smoothly
What is the probability of each bigram in the sentence trains run smoothly ?
The probability of each bigram in the sentence trains run smoothly is 0.82%.
The bigram language model can be defined as an algorithm for predicting the likelihood of a sequence of words. It is a statistical language model that calculates the probability of a word given its context or surrounding words.
In this question, we have to calculate the probability of each bigram in the sentence trains run smoothly.
The given corpus is:trains run on timeeven when trains are delayed they always run wellthrough the night sleepers run smoothly
To calculate the bigram probabilities, we need to count the number of times each bigram appears in the corpus, and then divide by the total number of bigrams in the corpus.
Here, the bigrams in the sentence trains run smoothly are:trains run smoothly
The number of bigrams in the given corpus are 17.P(trains | - ) = 2/17P(run | trains) = 2/7P(run | - ) = 5/17P(smoothly | run) = 1/2
Therefore, the probabilities of each bigram in the sentence trains run smoothly are:
P(trains | - ) × P(run | trains) × P(smoothly | run)= (2/17) × (2/7) × (1/2)= 0.0082 or 0.82%
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Create a class named RackoCard that will be used in the RackoDeck and RackoRack classes. A RackoCard encapsulates a single Integer and member functions as listed below. Italics represent constant member functions. Green represents comments. Red represents protected member functions. Racko_Card(VALUE) // 1 to 60 only value() // returns the cards value is_lt(Racko_Card) I/ is this Rack_Card < passed Racko_Card is_gt(RackoCard) I/ is this Rack_Card > passed Racko_Card is_eq(RackoCard) // does this Rack_Card == passed Racko_Card Create a class named RackoDeck. A RackoDeck is instantiated as a collection (I suggest using a vector) of 60 RackoCard objects numbered 1 to 60 . A RackoDeck has the member functions listed below. Italics represent constant member functions. Green represents comments. Red represents protected member functions. Create a class named RackoRack. A RackoRack is instantiated as a collection of 0 RackoCard objects. The game starts by calling the load function 10 times to populate the rack (I suggest a static array of RackoCard pointers); with index 0 representing slot 5 and index 9 representing slot 50 . A RackoRack has the member functions listed below. Italics represent constant member functions. Green represents comments. Red represents protected member functions.
Class named Racko Card is created that is used in the Racko Deck and Racko Rack classes.
A Racko Card encapsulates a single integer and member functions as listed below:Racko_Card(VALUE) // 1 to 60 only value() // returns the card's value is_lt(Racko Card) // Is this Rack_Card < passed Racko_Card is_gt(RackoCard) // Is this Rack_Card > passed Racko_Card is_eq(RackoCard) // Does this Rack_Card == passed Racko_CardThe main answer is a class named RackoDeck that is instantiated as a collection (suggest using a vector) of 60 RackoCard objects numbered 1 to 60.
A RackoDeck has the member functions listed below:fill() // fills the deck in increasing order shuffle() // randomizes the deck size() // returns number of cards left on deck top() // returns the top card of the deck deal() // removes and returns the top card of the deckThe main answer is a class named RackoRack that is instantiated as a collection of 0 RackoCard objects.
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DESCRIPTION OF THE ASSIGNMENT:
Within the scope of this assignment, the program that finds a word pattern entered by the user in a file entered by the user with the help of Parallel Naive Pattern Search Algorithm, is required to be written using the openMP or MPI library on a total of 4 threads with the help of C, C++ or Python language.
The program to be executed will run on 4 threads. Data parallelism should be used for workload distribution among threads. Program Inputs/Outputs:
Entries (2 parameters: 1 filename and extension, 2 search words):
> ./naive_pattern_seach "./file_name.txt" "pattern"
Output: (Screen output: starting position of the character with the pattern)
Position of the pattern: 0
Position of the pattern: 4
Position of the pattern: 6
Total parallel calculation Time: 0.00456 sec
Sample:
In Master File: "ABAAABCDBBABCDDEBCABC", pattern: "ABC"
Output:
Position of the pattern: 4
Position of the pattern: 10
Position of the pattern: 18
Total parallel calculation Time: 0.00456 sec
Parallel Naive Pattern Search Algorithm is one of the most common pattern search techniques and is used to search for a specified pattern in a file.
In this technique, a program that finds a word pattern entered by the user in a file entered by the user with the help of the Parallel Naive Pattern Search Algorithm is required to be written using the openMP or MPI library on a total of 4 threads with the help of C, C++ or Python language.Data parallelism should be used for workload distribution among threads, and the program to be executed will run on 4 threads. When the program is run with the following parameters: "./naive_pattern_seach" "./file_name.txt" "pattern", the output will be the starting position of the character with the pattern in the file. The output should be displayed in the following format: Position of the pattern:
xTotal parallel calculation Time: y sec. Here, x and y refer to the position of the pattern and the total parallel calculation time respectively.In the given example, the Master File is "ABAAABCDBBABCDDEBCABC" and the pattern to search for is "ABC". The output will be:Position of the pattern: 4Position of the pattern: 10Position of the pattern: 18Total parallel calculation Time: 0.00456 sec
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