Ole has a window that has the dimensions and shape like the trapezoid shown below. He also has a large rectangular piece of poster board that measures 25 inches by 60 inches. If Ole cuts out a piece of poster board that is exactly the same size as the window, which equation can be used to calculate the amount of poster board that will be left over?

Answer:

  (-2, 10)

Step-by-step explanation:

You want the point that would be a solution to the inequalities ...

It can be useful to graph the inequalities, or develop a mental picture of what the graph would look like. Both boundary line slopes are fairly steep, and the lines cross in the third quadrant. The V-shaped space above that intersection  is the solution space.

The attachment shows the point (-2, 10) is a solution.

From the shape and location of the solution space, we can eliminate the choices ...

  (-8, 2) — too close to the x-axis in the far left part of the 2nd quadrant

  (10, -3) — no part of the 4th quadrant is in the solution space

It can work nicely to rewrite the inequalities as a comparison to zero.

  5x -2y +4 ≤ 0 . . . . . the first inequality in general form

  point (-2, 10): 5(-2) -2(10) +4 = -10 -20 +4 = -26 ≤ 0 . . . a solution

  point (4, 9): 5(4) -2(9) +4 = 20 -18 +4 = 6 > 0 . . . . . . . not a solution

  4x +y +7 ≥ 0 . . . . . . the second inequality in general form

  point (-2, 10): 4(-2) +(10) +7 = -8 +10 +7 = 9 ≥ 0 . . . . . . a solution

  point (4, 9): don't need to test (already known not a solution)

Point (-2, 10) is a solution.

__

Additional comment

We chose the use of "general form" inequalities for evaluating answer choices because ...

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Answer:

he should have subtracted 17 from both sides of the equation

Step-by-step explanation:

x+ 17 = 22

subtract 17 from both sides

X + 17 = 22

-17 -17

x = 5

The actual distance from the movie theater to the school is given as follows:

A. 15 miles.

The actual distance from the movie theater to the school is obtained applying the proportions in the context of the problem.

On the map, the grocery store is 2 inches away from the library. The actual distance is 1.5 miles, hence the scale factor is of:

2 inches = 1.5 miles

1 inch = 0.75 miles.

The same map shows that the movie theater is 20 inches from the school, hence the actual distance is given as follows:

20 x 0.75 = 15 miles.

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The population of the country will be 796 million approximately in the year 2022.

To find when the population of the country will be 796 million, we can set the equation equal to 796 and solve for t:

[tex]A = 433.4e^{(0.032t)}\\796 = 433.4e^{(0.032t)}[/tex]

Divide both sides by 433.4:

[tex]e^{(0.032t)} = 1.836[/tex]

Take the natural logarithm of both sides:

[tex]ln(e^{(0.032t)}) = ln(1.836)[/tex]

0.032t = 0.605

Divide both sides by 0.032:

t = 18.91

Therefore, the population of the country will be 796 million approximately 19 years after 2003. To find the year, we add 19 to 2003:

2003 + 19 = 2022

Therefore, the population of the country will be 796 million approximately in the year 2022.

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Answer:

Step-by-step explanation:

Given function is

[tex]f(x) = \dfrac{\left(x^2-9\right)}{\left(x^2-x-6\right)}[/tex]

Part 1

Graph attached

y-intercepts can be found by finding f(0) ie the value of f(x) at x = 0

[tex]f(0) = \dfrac{\left(0^2-9\right)}{\left(0^2-0-6\right)} = \dfrac{-9}{-6} = \dfrac{3}{2}[/tex]

Roots of a function can be found by setting f(x) = 0 and solving for x

Setting f(x) = 0

==> [tex]\dfrac{x^2-9}{x^2-x-6} = 0\\\\[/tex]

We can factor the numerator  as follows:
x² - 9 = (x + 3) (x -3)     since (a + b)(a-b) = a² - b²

Denominator can be factored as follows
x² - x - 6 = (x-3)(x+2)

So
[tex]f(x) = \dfrac{(x + 3)(x-3)}{(x-3)(x+2)}\\\\[/tex]

The (x-3) term cancels leaving
[tex]f(x) = \dfrac{x+3}{x+2}[/tex]

Setting this equal to 0 gives
[tex]\dfrac{x+3}{x+2} = 0[/tex]

This is 0 when x + 3 = 0 or x = -3

So there is only one root and that is x = -3

Asymptotes

The vertical asymptote occurs when at a value of x when the denominator becomes 0

The given function has been factored as
[tex]f(x) = \dfrac{x + 3}{x + 2}[/tex]

The denominator becomes 0 at x = -2
Vertical asymptote is x = - 2

To find the horizontal asymptote use the fact that when the degrees of the numerator and denominator are equal, the horizontal asymptote is given by
[tex]y=\dfrac{\mathrm{numerator's\:leading\:coefficient}}{\mathrm{denominator's\:leading\:coefficient}}[/tex]

The degree of the numerator x + 3 is 1 and the degree of the denominator x + 2 is also 1

So the horizontal asymptote is y = 1/1 = 1

y = 1 is the horizontal asymptote

End behavior is the behavior of the function as x → ±∞  

This is determined by examining the leading term of the function and determining what its behavior is as x → ±∞

In the function
[tex]f(x) = \dfrac{x + 3}{x + 2}[/tex]
which is the factored form of the originally given function
the domain of x = all real numbers with the exception of -2 since at x = -2, the function is undefined

The end behavior can be determined by finding the limit of f(x) as x tends to infinity

[tex]\lim _{x\to \infty \:}\left(\dfrac{x+3}{x+2}\right)\\\\\dfrac{x+3}{x+2} \text{ can be transformed by dividing by x both numerator and denomiator :}\\\\\\=\dfrac{\dfrac{x}{x}+\dfrac{3}{x}}{\dfrac{x}{x}+\dfrac{2}{x}}\\\\\\=\dfrac{1+\frac{3}{x}}{1+\dfrac{2}{x}}[/tex]

[tex]\lim _{x\to \infty \:}\left(\dfrac{x+3}{x+2}\right) \\\\\\\\=\lim _{x\to \infty \:}\left(\dfrac{1+\dfrac{3}{x}}{1+\dfrac{2}{x}}\right)\\\\\\\\=\dfrac{\lim _{x\to \infty \:}\left(1+\dfrac{3}{x}\right)}{\lim _{x\to \infty \:}\left(1+\dfrac{2}{x}\right)}[/tex]

[tex]\lim _{x\to \infty \:}\left(1+\dfrac{3}{x}\right) = 1\\\\\lim _{x\to \infty \:}\left(1+\dfrac{2}{x}\right) = 1[/tex]

[tex]\lim _{x\to \:-\infty \:}\left(\dfrac{x+3}{x+2}\right) = 1[/tex]

End behavior
[tex]\mathrm{as}\:x\to \:+\infty \:,\:y\to \:1,\:\:\mathrm{and\:as}\:x\to \:-\infty \:,\:y\to \:1[/tex]

Table:
x                y

-4            1/2

- 3            0

-1               2

0               3/2

1                4/3

2                5/4

3               6/5

Note that the function is undefined at x = -2

The length of fencing needed around her triangular garden is 41 feet.

A given shape which has three sides and three measures of internal angles which add up to 180^o is said to be a triangle.

For Mary to build a fence around her triangular garden, the amount of fencing needed can be determined by adding the length of each side of the garden.

So that;

A + B + C = 180^o

A + 49 + 40 = 180

A = 180 - 89

   = 91

A = 91^o

Applying the sine rule, we have;

a/Sin A = b/Sin B = c/Sin C

a/Sin A = b/Sin B

a/Sin 91 = 13/ Sin 49

aSin 49 = 13*Sin 91

             = 12.998

a = 12.998/ 0.7547

  = 17.22

a = 17 ft

Also,

b/Sin B = c/Sin C

13/Sin 49 = c/ Sin 40

cSin 49 = 13*Sin 40

             = 8.3562

c = 8.3562/ 0.7547

  = 11.0722

c = 11 feet

Thus the amount of fencing required = 13 + 17 + 11

                                                    = 41

The fencing required is 41 feet length.

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i) The monthly basic salary of the married COAS General is Rs 79,200.

ii. Taxable Income = Rs 1,60,400 - Rs 57,920 = Rs 1,02,480

iii. The total income tax paid by him is Rs 24.8.

His taxable income can be calculated as follows:

Total Monthly Income = Rs 79,200 + Rs 2,000 + Rs 79,200 = Rs 1,60,400

EPF Contribution = 10% of Basic Salary = 10% of Rs 79,200 = Rs 7,920

Life Insurance Premium = Rs 50,000

Total Deductions = EPF Contribution + Life Insurance Premium = Rs 7,920 + Rs 50,000 = Rs 57,920

Taxable Income = Total Monthly Income - Total Deductions

Taxable Income = Rs 1,60,400 - Rs 57,920 = Rs 1,02,480

For income up to Rs 6,00,000: No income tax

For income between Rs 6,00,001 and Rs 8,00,000: 1% of the amount exceeding Rs 6,00,000

Taxable Income in this slab = Rs 2,480 (Rs 1,02,480 - Rs 6,00,000)

Income tax for this slab = 1% of Rs 2,480 = Rs 24.8

Therefore, the total income tax paid by him is Rs 24.8.

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Using the cosine ratio, the value of the marked side in the image given below is approximately: y = 167.7.

The cosine ratio is defined as the ratio of the length of the hypotenuse of the right triangle over the length of the side that is adjacent to the reference angle. It is given as:

cos ∅ = length of hypotenuse/length of adjacent side.

From the image attached below, we have the following:

Reference angle (∅) = 37°

length of hypotenuse = 210

length of adjacent side = y

Plug in the values:

cos 37 = y/210

210 * cos 37 = y

y = 167.7

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Answer:

B} 7/20

Step-by-step explanation:

total: 80

section 1: 28

p(section 1) = 28/80 = 7/20

The percentage of people with blood pressure below 133 is 78.81%.

First, we need to calculate the Z-score for the value 133 using the formula:

Z = (X - μ) / σ

where X is the value (133), μ is the mean (121), and σ is the standard deviation (15).

Z = (133 - 121) / 15

Z = 12 / 15

Z = 0.8

Next, we can use a standard normal distribution table or a calculator to find the area under the curve to the left of the Z-score 0.8.

Looking up the Z-score of 0.8 in the standard normal distribution table, we find that the area to the left of 0.8 is 0.7881.

Therefore, the percentage of people with blood pressure below 133 is 78.81%.

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The equation in the standard form of a circle and find the centre and radius:

(x - 1)²/31 + (y + 3)²/31/3 = 1

To graph by completing the square, we need to rearrange the equation so that it has the form:

(x - h)² + (y - k)² = r²

Starting with x² - 2x + y² + 6y - 6 = 0:

First, we can factor out a 2 from the x terms and a 6 from the y terms:

2(x² - 2x) + 6(y² + 6y) - 6 = 0

Next, we need to complete the square for the x and y terms:

2(x² - 2x + 1) + 6(y² + 6y + 9) - 6 = 2(1) + 6(9)

Simplifying, we get:

2(x - 1)² + 6(y + 3)² = 62

Now we can rewrite the equation in the standard form of a circle and find the centre and radius:

(x - 1)²/31 + (y + 3)²/31/3 = 1

The centre of the circle is (1, -3), and the radius is √(31/3).

The graph is attached with the answer below.

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Answer:

Step-by-step explanation:

$100x0.5x1=$5

The solution is :

After the row operation replaces the second row, the augmented matrix is : [tex]\left[\begin{array}{ccc}-6 &3& -4 \\0&-3&11\end{array}\right][/tex]

Here, we have,

The designated sum can replace either row. Consult your curriculum materials for the intent.

Here, we'll replace row 2 with the sum.

 3(2, -2, 5) +(-6, 3, -4) = (3(2)-6, 3(-2)+3, 3(5)-4) = (0, -3, 11)

After the row operation replaces the second row, the augmented matrix is ... [tex]\left[\begin{array}{ccc}-6 &3& -4 \\0&-3&11\end{array}\right][/tex]

Hence, The solution is :

After the row operation replaces the second row, the augmented matrix is : [tex]\left[\begin{array}{ccc}-6 &3& -4 \\0&-3&11\end{array}\right][/tex]

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The values of c  on the interval [-5, 5] are c = -[tex]5^{1/4[/tex]) and c = [tex]5^{1/4[/tex].

According to the Mean Value Theorem for Integrals, if f(x) is continuous on the interval [a, b], then there exists a value c in [a, b] such that:

f(c) = 1/(b-a) . ∫(a to b) f(x) dx

For f(x) = x⁴ on the interval [-5, 5], we have:

∫(-5 to 5) x⁴ dx = (1/5) . (5⁵ - (-5)⁵)/5

= (1/5) . (3125 + 3125)

= 1250

So we need to find c such that f(c) = 1250/10 = 125.

f'(x) = 4x³, so we can use the Mean Value Theorem for Derivatives to find a value of c that satisfies the condition.

f'(c) = (1/(5-(-5)))  . ∫(-5 to 5) f'(x) dx

= (1/10)  . [f(5) - f(-5)]

= (1/10) . [(5⁴) - ((-5)⁴)]

= 100

Therefore, by the Mean Value Theorem for Derivatives, there exists a value c in [-5, 5] such that f'(c) = 100.

Now, we need to check if there exists a value c in [-5, 5] such that f(c) = 125.

f(c) = c⁴, so we need to solve the equation c⁴ = 125.

c = ±[tex]5^{1/4[/tex]

Both of these values are in the interval [-5, 5], so they satisfy the Mean Value Theorem for Integrals.

Therefore, the values of c that satisfy the Mean Value Theorem for integrals for f(x) = x⁴ on the interval [-5, 5] are c = -[tex]5^{1/4[/tex]) and c = [tex]5^{1/4[/tex].

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Answer: x= 10

Step-by-step explanation:

2x+4=24

2x=24-4

2x=20

x=10

Answer:

Step-by-step explanation:

2x+4=4

subtract 4 from both sides

2x=0

divide by 2 on both sides

x=0

Answer:

The answer is 64°

Step-by-step explanation:

opposite angles are equal

x=64°

Answer:

X is 64 degrees.

Step-by-step explanation:

X is directly across from 64 degrees. These angles are equal. So are angle y and 18, and angle z and the blank angle at the bottom.

Answer:

a₁₀₀ = 1074

Step-by-step explanation:

the nth term of an arithmetic sequence is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

given a₃ = 7 and a₁₂ = 106 , then

a₁ + 2d = 7 → (1)

a₁ + 11d = 106 → (2)

solve the equations simultaneously to find a₁ and d

subtract (1) from (2) term by term to eliminate a₁

(a₁ - a₁) + (11d - 2d) = 106 - 7

0 + 9d = 99

9d = 99 ( divide both sides by 9 )

d = 11

substitute d = 11 into (1) and solve for a₁

a₁ + 2(11) = 7

a₁ + 22 = 7 ( subtract 22 from both sides )

a₁ = - 15

Then

a₁₀₀ = - 15 + (99 × 11) = - 15 + 1089 = 1074

The measurement of DE is 10 inches.

If we know that E is the point where the diagonals of the rectangle intersect, then we know that DE is equal to half the length of the diagonal BD.

Using the Pythagorean theorem, we can relate the length of the diagonal BD to the sides of the rectangle.

Let's assume that the length of the rectangle is L and the width of the rectangle is W. Then, the length of the diagonal BD is given by:

BD = √(L^2 + W^2)

Since we know that the diagonals of a rectangle are equal, we have:

AC = BD

BD = 20

Therefore, DE = 1/2 BD = 1/2 (20) = 10 inches.

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The values of the constants m and c include the following:

m = -1.3

c = 7.1

In Mathematics and Geometry, the slope-intercept form of the equation of a straight line is given by this mathematical equation;

y = mx + c

Where:

Since the point P(-7, 2) is mapped onto P' (3, -11) by the reflection y = mx + c, we can write the following system of equations;

2 = -7m + c    ...equation 1.

-11 = 3m + c    ...equation 2.

By solving the system of equations simultaneously, we have:

2 = -7m - 3m - 11

11 + 2 = -10m

13 = -10m

m = -1.3

c = 7m + 2

c = 7(-1.3) + 2

c = -7.1

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Using z - score, the percentage of students above 83 is 15.9%

To find the number of students that scored above 83 can be calculated using z - score formula.

This is given as

z = x - μ / σ

Substituting the values into the formula;

z = 83 - 75 / 8

z = 1

The z-score is 1

Let's find the percentage of z -score under the score

p(x > 83) = 1 - P(x < 83) = 0.15866

p = 15.9%

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Peter left Town A around 10 a.m., traveling at an average speed of 84 km/h. William would reach Town B at 1:23 PM.

Firstly, we need to find the distance between Town A and Town B which can be calculated by calculating the distance travelled by Peter

Time taken by Peter = 2PM - 10AM

= 4 hrs

Speed of Peter = 84 km/h

Distance travelled by Peter = speed × time

= 84 × 4

= 336 km

So, the distance between Town A and Town B  = distance travelled by Peter = 336 km.

Now, we will calculate time taken by William.

Speed of William = 70 km / hr

Distance travelled by William = distance between Town A and town B = 336 km

Time taken by William = distance / speed

= 336 / 70 hr

= 4.8 hr

This can b converted into hrs and minutes

4.8 hr = 4 hr + 0.8 × 60

= 4 hr 48 mins

Time William took off = 10 AM - 1hr 25 mins

= 8:35 AM

Now, we will calculate the time William would reach town B.

Time = 8:35 + 4hr 48 mins

= 1:23 PM

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Answer:

36

Step-by-step explanation:

48/8 = 6. 6*6 = 36.

The probability that the sample's mean length is greater than 6.3 inches is0.8446.

Here, we have,

Given mean of 6.5 inches, standard deviation of 0.5 inches and sample size of 46.

We have to calculate the probability that the sample's mean length is greater than 6.3 inches is 0.8446.

Probability is the likeliness of happening an event.

It lies between 0 and 1.

Probability is the number of items divided by the total number of items.

We have to use z statistic in this question because the sample size is greater than 30.

μ=6.5

σ=0.5

n=46

z=X-μ/σ

where μ is mean and

σ is standard deviation.

First we have to find the p value from 6.3 to 6.5 and then we have to add 0.5 to it to find the required probability.

z=6.3-6.5/0.5

=-0.2/0.5

=-0.4

p value from z table is 0.3446

Probability that the mean length is greater than 6.3inches is 0.3446+0.5=0.8446.

Hence the probability that the mean length is greater than 6.3 inches is 0.8446.

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Answer:

1)  A = 32.6°, C = 111.4°, b = 12.0

2) A = 53.6°, B = 85.7°, C = 40.7°

Step-by-step explanation:

Given values of triangle ABC:

First, find the measure of side b using the Law of Cosines for finding sides.

[tex]\boxed{\begin{minipage}{6 cm}\underline{Law of Cosines (for finding sides)} \\\\$c^2=a^2+b^2-2ab \cos (C)$\\\\where:\\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides.\\ \phantom{ww}$\bullet$ $C$ is the angle opposite side $c$. \\\end{minipage}}[/tex]

As the given angle is B, change C for B in the formula and swap b and c:

[tex]b^2=a^2+c^2-2ac\cos(B)[/tex]

Substitute the given values and solve for b:

[tex]\implies b^2=11^2+19^2-2(11)(19)\cos(36^{\circ})[/tex]

[tex]\implies b^2=482-418\cos(36^{\circ})[/tex]

[tex]\implies b=\sqrt{482-418\cos(36^{\circ})}[/tex]

[tex]\implies b=11.9929519...[/tex]

Now we have the measures of all three sides of the triangle, we can use the Law of Cosines for finding angles to find the measures of angles A and C.

[tex]\boxed{\begin{minipage}{7.6 cm}\underline{Law of Cosines (for finding angles)} \\\\$\cos(C)=\dfrac{a^2+b^2-c^2}{2ab}$\\\\\\where:\\ \phantom{ww}$\bullet$ $C$ is the angle. \\ \phantom{ww}$\bullet$ $a$ and $b$ are the sides adjacent the angle. \\ \phantom{ww}$\bullet$ $c$ is the side opposite the angle.\\\end{minipage}}[/tex]

To find the measure of angle A, swap a and c in the formula, and change C for A:

[tex]\implies \cos(A)=\dfrac{c^2+b^2-a^2}{2cb}[/tex]

[tex]\implies \cos(A)=\dfrac{19^2+(11.9929519...)^2-11^2}{2(19)(11.9929519...)}[/tex]

[tex]\implies \cos(A)=0.842229094...[/tex]

[tex]\implies A=\cos^{-1}(0.842229094...)[/tex]

[tex]\implies A=32.6237394...^{\circ}[/tex]

To find the measure of angle C, substitute the values of a, b and c into the formula:

[tex]\implies \cos(C)=\dfrac{a^2+b^2-c^2}{2ab}[/tex]

[tex]\implies \cos(C)=\dfrac{11^2+(11.9929519...)^2-19^2}{2(11)(11.9929519...)}[/tex]

[tex]\implies \cos(C)=-0.364490987...[/tex]

[tex]\implies C=\cos^{-1}(-0.364490987...)[/tex]

[tex]\implies C=111.376260...^{\circ}[/tex]

Therefore, the remaining side and angles for triangle ABC are:

[tex]\hrulefill[/tex]

To solve for the remaining angles of the triangle ABC given its side lengths, use the Law of Cosines for finding angles.

[tex]\boxed{\begin{minipage}{7.6 cm}\underline{Law of Cosines (for finding angles)} \\\\$\cos(C)=\dfrac{a^2+b^2-c^2}{2ab}$\\\\\\where:\\ \phantom{ww}$\bullet$ $C$ is the angle. \\ \phantom{ww}$\bullet$ $a$ and $b$ are the sides adjacent the angle. \\ \phantom{ww}$\bullet$ $c$ is the side opposite the angle.\\\end{minipage}}[/tex]

Given sides of triangle ABC:

Substitute the values of a, b and c into the Law of Cosines formula and solve for angle C:

[tex]\implies \cos(C)=\dfrac{a^2+b^2-c^2}{2ab}[/tex]

[tex]\implies \cos(C)=\dfrac{21^2+26^2-17^2}{2(21)(26)}[/tex]

[tex]\implies \cos(C)=\dfrac{828}{1092}[/tex]

[tex]\implies C=\cos^{-1}\left(\dfrac{828}{1092}\right)[/tex]

[tex]\implies C=40.690560...^{\circ}[/tex]

To find the measure of angle B, swap b and c in the formula, and change C for B:

[tex]\implies \cos(B)=\dfrac{a^2+c^2-b^2}{2ac}[/tex]

[tex]\implies \cos(B)=\dfrac{21^2+17^2-26^2}{2(21)(17)}[/tex]

[tex]\implies \cos(B)=\dfrac{54}{714}[/tex]

[tex]\implies B=\cos^{-1}\left(\dfrac{54}{714}\right)[/tex]

[tex]\implies B=85.6625640...^{\circ}[/tex]

To find the measure of angle A, swap a and c in the formula, and change C for A:

[tex]\implies \cos(A)=\dfrac{c^2+b^2-a^2}{2cb}[/tex]

[tex]\implies \cos(A)=\dfrac{17^2+26^2-21^2}{2(17)(26)}[/tex]

[tex]\implies \cos(A)=\dfrac{524}{884}[/tex]

[tex]\implies A=\cos^{-1}\left(\dfrac{524}{884}\right)[/tex]

[tex]\implies A=53.6468753...^{\circ}[/tex]

Therefore, the measures of the angles of triangle ABC with sides a = 21, b = 26 and c = 17 are:

The trigonometric relations are solved and equation is A = 3/4

Given data ,

Let the trigonometric relation be represented as A

Now , the value of A is

A = Tan²60° × Sin60° x Tan30° x Cos²45°

On simplifying the equation , we get

Tan²60° = 3

Sin60° = √3/2

Tan30° = 1/√3

And , Cos²45° = 1/2

Now , the equation is A = 3 x √3/2 x 1/√3 x 1/2

A = 3/4

Hence , the trigonometric equation is solved and A = 3/4

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There are 14 dogs and 46 chickens in the farmyard.

The supposition that there are d dogs and c chickens.

Each chicken has two legs, but each dog has four.

Consequently, the total number of legs may be written as follows:

4d + 2c

Since we are aware that there are 148 legs in total, we can construct the following equation:

4d + 2c = 148

We may create another equation since we know that there are a total of 60 heads (dogs and chickens):

d + c = 60

Now that we have two equations with two variables, we may answer them both at the same time.

2d + 2c = 120 is the result of multiplying the second equation by two.

When we deduct this from the first equation, we obtain 2d = 28.

So, d = 14.

Reintroducing this into the second equation, we get:

14 + c = 60

So, c = 46.

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1. The equation of the form y = a • bˣ is y = 81 x (¹/₃)ˣ

2. His stamp should be worth approximately $7,851.47 after 6 years.

3. The equation of the form y = a • bˣ is y = (¹/₁₆) x 2²ˣ ⁺ ⁵

1. One will see that y is decreasing by a factor of 3 as x increases by 1. Therefore, we can write the equation as:

y = 81 x (¹/₃)ˣ

2. The increase in value of the stamp can be calculated using the formula:

V = P(1+r)ᵗ

where V is the future value, P is the present value, r is the annual interest rate as a decimal, and t is the number of years.

Substituting the given values:

V = 4900(1+0.075)⁶

V ≈ $7,851.47

Therefore, the stamp should be worth approximately $7,851.47 after 6 years.

3. One will see that y is increasing by a factor of 2 as x increases by 1. Therefore, we can write the equation as:

y = (1/16) x 2²ˣ ⁺ ⁵

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Answer:

x = -5

Step-by-step explanation:

-5 - 15x - 10 = -4x - 8x

-5 - 10 = -4x - 8x + 15x

-15 = -12x + 15x

-15 = 3x

x = -5

The type of model that best fits the situation of a $500 raise in salary each year is a linear model.

In a linear model, the dependent variable changes a constant amount for constant increments of the independent variable.

In the given case, the dependent variable is the salary and the independent variable is the year.

You may build a table to show that for increments of 1 year the increments of the salary is $500:

Year         Salary        Change in year         Change in salary

2010           A                           -                                       -

2011           A + 500     2011 - 2010 = 1          A + 500 - 500 = 500

2012          A + 1,000   2012 - 2011 = 1          A + 1,000 - (A + 500) = 500

So, you can see that every year the salary increases the same amount ($500).

In general, a linear model is represented by the general equation y = mx + b, where x is the change of y per unit change of x, and b is the initial value (y-intercept).              

In this case, m = $500 and b is the starting salary: y = 500x + b.

For the given linear equation y = (1/4)*x + 5/4.

Here we have the linear equation:

y = (1/4)*x + 5/4.

to check if (1, 1.5) is a solution we need to evaluate this in x = 1 and see if we get 1.5.

y = (1/4)*1 + 5/4

y = 6/4 = 3/2 = 1.5

Then (1, 1.5) is a solution.

For the second point we evaluate in x = 12.

y = (1/4)*12 + 5/4

y = 3 + 5/4 = 4.25

So (12, 4) is not a solution.

Finally, to find the x-intercept, we evaluate in y = 0.

0 = (1/4)*x + 5/4

-4/5 = (1/4)*x

4*(-4/5) = x

-16/5 = x

The x-intercept is (-16/5, 0).

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