One metal object is a cube with edges 3.00 cm and a mass of 140.4 g. a second is a sphere with a radius of 1.42 cm and a mass of 61.6 g. are these objects made of the same metal?

Final temperature of the solution formed is 50.93ºC

As we know,

heat = mass x specific heat x change in temperature

q = mC∆T

where, m = 111 g water

             C = 4.184 J/g/deg

             ∆T = ?

To find heat we need to first find moles Libr used in this reaction:

21.4 g Libr x 1 mole/86.84 g = 0.246 moles

Therefore,

q = 0.246 moles x (-48.8) kJ/mol = -12.00 kJ = -12000 J (since it is negative, this indicates an exothermic reaction, so temperature of solution will increase).

-12000 J = (111g)(4.184 J/g/deg)(∆T)

∆T = -25.83 degrees

Final temperature = 25.1º - (-25.83º) = 50.93ºC

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Answer:

.4 moles of hydrogen

Explanation:

Formula for water ==   H2 O  

   so you can see there are twice as many hydrogen moles as water moles

           .2 * 2 = .4

When the hydrocarbon was burned 0.20 mol of water were produced. 0.40 moles of hydrogen atoms are there in 0.20 mol of water.

A mole is a unit used to measure the concentration of a chemical in chemistry. It is described as the quantity of a substance that includes exactly the same number of atoms as there are in exactly 12 grammes of carbon-12. This number can be an entity (such as an atom, molecule, ion, or other particle). The dozen, which represents 12 items, and the pair, which represents 2 items, are two more basic units of measurement that are comparable to the mole.

2 moles H / 1 mole H2O = x moles H / 0.20 moles H2O

2 moles H ×0.20 moles H2O = 1 mole H × x moles H2O

0.40 moles H = x moles H2O

So, there are 0.40 moles of hydrogen atoms in 0.20 moles of water.

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The way to find the moles of CO2 in a pop are:

A mole is a measure of molecules that is equal to approximately 6.022x10^23 molecules. Using the ideal gas formula, one can find the number of moles of carbon dioxide in a container if you know the other needed parameters and conditions.

Based on the above, it should be noted that P is the pressure, V is the volume from, T is the temperature and R is a proportionality constant that is equal to 0.0821 L atm / K mol.

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When 1. 0 l of 0. 00010 m NaOH and 1. 0 l of 0. 0014 m mgso4 are mixed, there will be no precipitate formed.

The precipitate is the solid concentration of a substance that is collected over a solution.

First, we determine the concentration of magnesium and hydroxide

(Mg2+) = 7.00 × 10⁻⁴

(OH−) = 5.00 × 10⁻⁵

Now, we calculate the solubility quotient

Qc = (Mg2+) (OH−) ²

Qc = 7.00 × 10⁻⁴ x (5.00 × 10⁻⁵)²

Qc = 1.75 x 10⁻¹²

The solubility product of the magnesium hydroxide is 1.80 x 10⁻¹¹ which is more than the solubility quotient. Thus, there will be no precipitate form.

Thus, there will be no precipitate formed because the solubility quotient we calculated is less than the solubility product.

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Answer:

16 moles

Explanation:

from the equation:

4Fe + 3O2 -----> Fe2O3

the mole ratio of Fe to O2 follows,

3 moles O2 reacts with 4 moles Fe.

therefore,

1 mole O2 reacts with 4/3 moles Fe

and 12 moles O2 reacts with (4/3) × 12 moles Fe = 16 moles

Answer:

9.0 moles of O2 and produce 6.0 moles of Fe2O3

Explanation:

Fe→Fe3++3e− iron. Is oxidised: it's losing electrons

O2+4e−→2O2− oxygen Is reduced, it's gaining electrons

Balance for the electrons.

The smallest common product of 3 and 4 Is 12.

So we get:

4Fe→4Fe3++12e−

3O2+12e−→6O2−

Adding:

4Fe+3O2+12e−→4Fe3++12e−+6O2−

The electrons balance so they cancel out:

4Fe+3O2→4Fe3++6O2−

Since Fe and O can combine in a ratio of 2:3

4Fe+3O2→4Fe3++6O2−→2Fe2O3

Extra :

Pure iron. won't rust, because the oxide layer would form a protective skin (as aluminium does). It needs some impurities (mainly carbon) and, apart from the oxygen, some moisture -- even carbondioxide 'helps'. In that case iron.-hydroxy-oxides and -carbonates are formed, and these flake, no longer protecting the iron. underneath.

When 3. 41 g of C6H12O6 is dissolved in 85 ml of water the molality is 2.2m.

Molality is the amount of a substance dissolved in a certain mass of solvent.

Molality = moles of solute/ mass of solvent (kg)

Given,

Mass of solute = 3.14g

Molar mass of solute = 180 g

Mole of solute= given mass/molar mass

= 3.14/180

= 0.0189 mol.

Volume of solvent = 85 ml

Density of water = 1 g/cm3

Density = mass/ volume

mass = density × volume

= 1× 85

= 85g

Molality = (0.0189/ 85) × 1000

= 2.2m

Thus we find that the molality of given solution is 2.2m.

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A 45. 0 L gas cylinder contains 988 g He at 23 °C then pressure inside the cylinder is  134.67 atm.

Calculation,

Formula used :The ideal gas equation is given as,

PV = nRT                       ....(i)

Where , P is pressure of the gas = ?

V = volume of the gas =  45. 0 L

R = universal gas constant =  0. 08206 L⋅atm/mol⋅K

T = Temperature = 23 °C = 23 + 273 = 299 K

n = number of moles = given mass/ molar mass =  988 g/4 = 247 moles

Putting the value of P , V , T , R and n in equation (i) we get

P×45. 0 L  =  247 moles× 0. 08206 L⋅atm/mol⋅K×299 K

P = 247 moles× 0. 08206 L⋅atm/mol⋅K×299 K /45. 0 L = 134.67 atm

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When hexan-1-ol is treated with conc. H₂SO₄ at moderate temperatures, Di-n-hexyl ether is formed via SN₂ mechanism.

SN₂ Mechanism is mechanism involving the factors of steric hindrance following the order of 1° > 2° > 3°. It is a Nucleophilic substitution reaction.

Williamson Ether Synthesis is the synthesis of ether through SN₂ mechanism in which an ether is treated with conc. H₂SO₄ at moderate temperature.

When hexan-1-ol is treated with conc. H₂SO₄ at moderate temperatures, Di-n-hexyl ether is formed as below:

CH₃CH₂CH₂CH₂CH₂CH₂OH +Conc. H₂SO₄-->(CH₃CH₂CH₂CH₂CH₂CH₂)₂0

Hexan-1-ol                                                                 Di-n-hexyl ether

Williamson Ether Synthesis is a reaction involving a alcohol that is deprotonated to form an ether.

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Atomic or hybrid orbitals make up the sigma bond between c1 and c2 in ethane, ch3ch3 are one s orbital and 2 p orbital

Sigma bonds are the most powerful type of covalent chemical link. They are generated by atomic orbitals overlapping head-on. For diatomic molecules, sigma bonding is most readily explained using the language and tools of symmetry groups.

Chemical covalent bonds are sigma bonds and pi bonds. The overlap of atomic orbitals creates sigma and pi bonds. Sigma bonds are produced by overlapping from end to end, whereas Pi bonds are created when the lobe of one atomic orbital overlaps another.

Sigma bonding can be seen in the link between two hydrogen atoms. Sigma bonds are also formed between the sp3 orbitals of hybridized carbon and the s orbitals of hydrogen in methane.

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The  season that is shown in the picture attached is that:

Metals are known to often expand due to different factor. For example, the rails of a railway are known to often expand in summer and they tend to contract in winter. This tend to make the gaps kept to be between successive rails and it is one that allow for expansion.

Note also that  in Summer the expansion joint will tend to have little space as the two sides of the bridge is said to expand because of the heat and in terms of winter, it contract and there are bigger space as they tend to contract in the cold.

Hence, The  season that is shown in the picture attached is that:

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Answer: The main disadvantages of evaporation are high capital, energy and maintenance costs; large size of apparatus; enhanced temperatures; corrosion problems; and scaling or foaming.

Explanation:

Formic acid, Sodium formiate will generate a buffer solution with pH around 3. 5.

It must consider the acid whose pKa = pH in order to choose the base or acid that can produce a buffer solution with such a pH of about 3.5.

However, it also need to consider buffer capacity, which is a factor that can alter the pH of a solution by one unit in a liter.

The connection between the components' concentrations and their concentrations themselves affects buffer capacity in addition to their individual concentrations.

Therefore, Formic acid, Sodium formiate will generate a buffer solution with pH around 3. 5.

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In order to react with the hydrochloric acid (HCl) created when the hexanediamine combines with the adiptic acid, NaOH was added to the hexanediamine solution. By combining with the HCl to create NaCl and water, the NaOH preserves the pH of the solution. HCl is taken out of the solution and the reaction is pushed in the direction of the products.

A C6 alkane-alpha, omega-diamine is hexanediamine. It serves as a xenobiotic metabolite for humans. It comes from a hydride.

What is the purpose of hexanediamine?

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2.3352 g of PbCl₂ are formed when 50. 0 ml of 0. 336 m KCl react with pb(no3)2.

The balanced equation for the above double displacement reaction is as follows;

2KCl + Pb(NO₃)₂ ---> PbCl₂ + 2KNO₃

Stoichiometry of KCl to PbCl₂ is 2:1

This means that 2 mol of KCl would react with every 1 mol of PbCl₂

The molarity of KCl = 0. 336 M

in 1 L of KCl, there are mol

Therefore in  50. 0 ml of KCl, there are=  [tex]\frac{0. 336 * 50}{1000}[/tex]

Number of KCl moles reacted = 0.0168 mol

according to stoichiometry

number of PbCl₂ moles formed =  1/2 x number of KCl moles reacted

Therefore number of PbCl₂ moles formed = 0.0168 mol/2 = 0.0084 mol

molar mass of PbCl₂ = 278 g/mol

mass of PbCl₂ formed = 278 g/mol x 0.0084 mol = 2.3352 g

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[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

B. How much of the reactants are needed and how much product will be made.

Chemists use mole in calculations to calculate the amount of product that will be formed when certain known amount of reactants are used at the end of reaction.

The moles are used to determine the atoms and molecules in a substance. It is used by chemists to determine the amount of reactants needed and products produced. Thus, option B is correct.

A mole is said to be defined as the estimation of the small entities like the atoms as that of the Avagadro's number 6.022 × 10²³. It defines the number of particles contained in a substance.

The moles of the substances are determined by the mass of the substance and its molar mass. The moles are given as,

Moles = mass ÷ molar mass

The moles give the estimation of the amount of the reactants needed to produce the products in a chemical reaction.

Therefore, option B. the moles tell the amount of the reactants required to produce the product.

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The molecules can be a reactant in a Friedel-crafts reaction will be aniline .

The Lewis acid as well as the chlorine atom of such acid chloride form a complex during the Friedel-Crafts acylation reaction. Cleaving the complex's C-Cl link produces an acylium ion. The acylium ion undergoes resonance stabilized but also has a positive electrical charge upon that carbon atom.

The Friedel-Crafts alkylation reaction, an electrophilic aromatic substitution process, may add an alkyl to a benzene molecule. One illustration is the insertion of a methyl group into a benzene ring.

Therefore, the molecules can be a reactant in a Friedel-crafts reaction will be aniline .

Hence, the correct answer will be option (a)

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In the polymerization reaction, the lone pair electrons on the NH₂ groups of hexanediamine attack the C=O groups of the dicarboxylic acid in a nucleophilic substitution reaction as shown in the image.

Hydroxide is added to remove any H⁺ ions present and keep the hexanediamine in the deprotonated form, so that the NH₂ lone pair electrons are available for reaction.

If hydroxide is not added, the NH₂ groups will get protonated by H⁺  ions present to give NH₃⁺ groups, which cannot react.

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The statement NADH and FADH2 donates electrons to the electron transport chain at the same point is true.

In this step  NADH and FADH2, donates electrons to the electron transport chain at the same time. Hence, with the above details we can conclude that the given statement is true.

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The volume of methanol necessary to prepare the antifreeze good for antifreeze solution is 3.2 L

M₁V₁ = M₂V₂

Where

The volume of the methanol necessary to prepare the solution can be obtained as illustrated below:

M₁V₁ = M₂V₂

24.7 × V₁ = 10 × 8

24.7 × V₁= 80

Divide both side by 24.7

V₁ = 80 / 24.7

V₁ = 3.2 L

Thus, the volume of methanol necessary to prepare the antifreeze good for antifreeze solution is 3.2 L

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The "break-even" interest rate for year n that equates the return on an n-period zero-coupon bond to that of an n - 1 - period zero-coupon bond rolled over into a one-year bond in year n is defined as the forward rate.

A forward rate is a specified price agreed by all parties involved for the delivery of a good at a specific date in the future. The use of forward rates can be speculative if a buyer believes the future price of a good will be greater than the current forward rate. Alternatively, sellers use forward rates to mitigate the risk that the future price of a good materially decreases.

Regardless of the prevailing spot rate at the time the forward rate meets maturity, the agreed-upon contract is executed at the forward rate. For example, on January 1st, the spot rate of a case of iceberg lettuce is $50. The restaurant and the farmer agree to the delivery of 100 cases of iceberg lettuce on July 1st at a forward rate of $55 per case. On July 1st, even if the price per case has decreased to $45/case or increased to $65/case, the contract will proceed at $55/case.

To extract the forward rate, we need the zero-coupon yield curve.

We are trying to find the future interest rate [tex]{\displaystyle r_{1,2}}{\displaystyle r_{1,2}}[/tex]  for time period  

[tex]{\displaystyle (t_{1},t_{2})}(t_1, t_2), {\displaystyle t_{1}}t_{1}[/tex]  and  [tex]{\displaystyle t_{2}}t_{2}[/tex]  expressed in years, given the rate  [tex]{\displaystyle r_{1}}r_{1}[/tex]  for

time period  [tex]{\displaystyle (0,t_{1})}(0, t_1)[/tex]  and rate [tex]{\displaystyle r_{2}}r_{2}[/tex]  for time period [tex]{\displaystyle (0,t_{2})}(0, t_2)[/tex].  To do this, we use the property that the proceeds from investing at rate  [tex]{\displaystyle r_{1}}r_{1}[/tex] for

time period [tex]{\displaystyle (0,t_{1})}(0, t_1)[/tex]  and then reinvesting those proceeds at rate

[tex]{\displaystyle r_{1,2}}{\displaystyle r_{1,2}}[/tex]  for time period  [tex]{\displaystyle (t_{1},t_{2})}(t_1, t_2)[/tex]  is equal to the proceeds from

investing at rate [tex]{\displaystyle r_{2}}r_{2}[/tex] for time period [tex]{\displaystyle (0,t_{2})}(0, t_2)[/tex].

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Answer:

Explanation:.

The two ways were,

A cathode-ray tube, often known as a CRT, is a vacuum tube that houses one or more electron cannons that produce electron beams that are then bent to produce pictures on a phosphorescent screen. The visuals might be pictures (from a television or computer display), electrical waveforms (from an oscilloscope), radar targets, or other occurrences.

Tomson came to the conclusion that atoms can be divided into their constituent corpuscles (atoms are made up of smaller particles).

The electron was discovered in 1897 by J. J. Thomson.

His "plum pudding" concept from 1904 postulated that the positive charge contains embedded electrons.

With this model, he disproved his first theory (the atom was composed of immaterial vortices).

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The ∆G° for the dissolution of AgCl solid is 55.7 kJ/mol.

The gibbs free energy is termed as thermodynamic quantity which is equal to the enthalpy (of a system or process) subtracted by the product of the entropy and the absolute temperature.

The gibbs free energy of the reaction is given by:

∆G°(rxn) =sum of ([∆G°] products)- sum of ( [∆ G°] reactants)

Reaction can be given as:

AgCl(S) » Ag+ (aq) + Cl- (aq)

Gibbs free energy of silver ions = ∆G°f, (Ag+) = 77.1kJ/mol

Gibbs free energy of formation of chloride ions = ∆G°f, (Cl-)= -131. 2kJ/mol

Gibbs free energy of formation of silver chloride solid = ∆ G°f, (AgCl) = - 109.8kJ/mol

The gibbs free energy of the reaction of dissolution of AgCl) :∆ G°rxn:

∆G°rxn = (77.1kJ/mol) – (- 109.8kJ/mol)

55.7kJ/mol

Thus, we found that the ∆G° for the dissolution of AgCL solid is 55.7 kJ/mol.

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Answer: KMnO4 (subscript 4)

Answer: 2 C2H6(g) + 7 O2(g) → 4 CO2(g) + 6 H2O(g)

Explanation:

Apologies for the error. Let me provide the correct balanced equation for the combustion of C2H6 (ethane) and address your additional question:

1. Combustion of Ethane (C2H6):

C2H6(g) + 3.5 O2(g) → 2 CO2(g) + 3 H2O(g)

To remove the half-coefficient, you can multiply the entire equation by 2:

2 C2H6(g) + 7 O2(g) → 4 CO2(g) + 6 H2O(g)

2. Combustion of Propane (C3H8):

C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)

3. Combustion of Butane (C4H10):

C4H10(g) + 6.5 O2(g) → 4 CO2(g) + 5 H2O(g)

In all these reactions, the hydrocarbon (ethane, propane, butane) reacts with oxygen gas (O2) to produce carbon dioxide (CO2) and water (H2O).2C2H6(g)+7O2(g)→4CO2(g)+6H2O(g)

option (b) freezing water is the correct answer.

Freezing water is an example of an exothermic process.

We can observe that melting of an ice is an example of endothermic process whereas, freezing of water is considered to be an example for exothermic process.

Water releases heat when it solidifies, warming the area around it. As a result, freezing is an exothermic process.

In the above given options,

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Answer:

B.) Freezing water

Explanation:

I got it correct on founders edtell

Eutrophication

In an aged aquatic habitat like a lake, eutrophication is the progressive rise in the concentration of phosphorus, nitrogen, and other plant nutrients. As the volume of organic matter that can be converted into nutrients increases, the productivity or fertility of such an ecosystem also naturally rises.

Eutrophication may be caused by a number of things, including overuse of fertilisers, untreated sewage, the use of phosphorous-containing detergents, and industrial waste discharge.

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Answer:

compound(C) mixture(M)

Explanation:

COMPOUNDS MIXTURES

(C)In nature they are homogeneous. (M)They can be homogeneous as well as heterogeneous in nature.

(C)They have a definite melting and boiling point. (M)They do not have any definite melting or boiling point.

(C)Example: Baking soda, salt, etc.(M) Example: Salt and sand, sugar and water.

The Hbr has highest boiling point followed by Kr , [tex]Cl_{2}[/tex] and [tex]F_{2}[/tex] .

The Hbr has  highest boiling point due to presence of intermolecular H-bonding that is hydrogen bonding.

The electronegativity of bromine is greater than hydrogen atom. The electronegativity difference hydrogen atom and bromine atom is high. So, due to this a positive dipole is generated at hydrogen atom and partial negative charge, these partial charge is called dipole. In a HBr molecule one H-atom attracted by Br-atom of another atom by force of attraction and this partial force of attraction is called H-bonding.

Other all given molecules are arrange according to its molecular mass because boiling points is directly proportional to the molecular mass of molecule.

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