One way to find the mass of an object is to
measure its acceleration when a force acts on
it. If a force of 80 N causes a box to accelerate at
0.10 m/s², what is the mass of the box?

The change in gravitational potential energy stored in 16 Jule.

What is gravitational potential energy?

In classical mechanics, of the  gravtitational potential at in a  location is equal to the work per unit mass that's would be needed to Move an object to that locations from a fixed references  location. It is analogous to the electric potential with the mass playing the role of charge.

Sol-As per the given question ∆PE = mgh

M= skg

g= 4m/s^2

∆h = 2m

∆PE = 2m×4m×2m

= 16 Joules.

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The best graph to use if I want to compare the price of six different cars would be a bar graph

A bar graph is a graphical representation of the given data . It uses bars that extend to different heights to depict value .

Bar graphs are used to compare different type of things between different groups or to see changes over a period of time. Hence , bar graph will fits the best if one want to compare the price of six different cars .

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The number of complete cycles the rotating mirror goes through before the angular velocity gets to zero is approximately 1166.8 revs

Angular velocity is the ratio of the angle turned to the time taken.

The kinematic equation for angular velocity are presented as follows;

ω = ω₀ + α·t

θ = θ₀ + ω₀·t + 0.5·α·t²

Where;

θ₀ = The initial angle turned = 0

ω₀ = The initial angular velocity of the mirrors = 115 rad/s clockwise

α = The angular acceleration = (115  - (-115))rad/s/(85 s) = -46/17 m/s²

t = The duration of the motion;

When the angular velocity, ω is zero, we get;

0 = 115 - 46/17·t

t = 85/2

Which indicates;

θ = 0 + 115× (85/2) + 0.5×(46/17) ×(85/2)² = 7331.25

θ = 7331.25 radians

θ = 7331.25/(2×π) ≈ 1166.8 rev

The mirrors would have turned through approximately 1166.8 revolutions when the angular gets to zero

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The density of 1 mole of oxygen at a pressure of 4×10⁻⁴ Nm⁻² and a temprature of 273.2 K is 2.82×10⁻⁶ g/m³

We'll begin by obtaining the volume of the oxygen. This can be obtained as follow:

PV = nRT

Divide both sides by P

V = nRT / P

V = (1 × 8.314 × 273.2) / 4×10⁻⁴

V = 5678462 m³

Finally, we shall determine the density of the oxygen. This can be obtained as follow:

Density = mass / volume

Density of oxygen = 16 / 5678462

Density of oxygen = 2.82×10⁻⁶ g/m³

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Explanation:

According to newton's second law.

The acceleration of the car would be 10 m/s² if the force (10 N) on it is doubled.

We know that the acceleration of an object can be calculated using the formula ⇒ a = F/m (i)

Here, the force experienced by the car is ⇒ F = 10 N

If this force is doubled we would have ⇒ 2×10 ⇒ 20 N (ii)

The mass of the car is ⇒ m = 2 kg (iii)

Now, putting the values of the doubled force and mass (ii and iii) in (i), we get ⇒ a = 20/2

a = 10 m/s²

Therefore, the car has an acceleration of 10 m/s² when the force on it is doubled.

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The magnitude of the force is 12.73N.

What is force?

this can be defined as a push or pull in a particular direction. It is calculated using the formula:

F=m*a

Where,

m=mass of the object

a=acceleration

What is magnitude of force?

This is the quantity or strength of the force. It is calculated using the formular:

Normal Force, N=m*g*Cos θ

From the question given:

     m   =5.00kg

Cos θ= 30°

        g=9.8m/s²

Coefficient of Friction, μ=Frictional force/Normal force

                                        =F/N

coefficient kinetic friction, μ=0.300

Magnitude of Force F= Coefficient of Friction*Normal Force

                                   =μN

                                   =μmg Cos θ

                                 F= 0.300*5.00*9.8*Cos30°

                                 F=0.300*5.00*9.8*0.8660

The magnitude of Force,F=12.73N

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The extra work is required to stretch the spring to an additional 9.95 cm is 25.61 J.

The spring constant of the spring is determined by applying the formula for elastic potential energy of a spring as shown below.

E = ¹/₂kx²

where;

kx²= 2E

k = 2E/x²

k = (2 x 5.91)/(0.0478²)

k = 5,173.2 N/m

The work done to stretch the string to 9.95 cm is calculated as;

E = ¹/₂kx²

E = ¹/₂(5173.2)(0.0995)²

E = 25.61 J

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The period of the ball's motion is 0.142 s and the frequency of the motion is 7 Hz.

The period of the ball's motion is calculated by applying the following kinematic equation as shown below.

v = 2πr/T

ωr = 2πr/T

ω = 2π/T

T = 2π/ω

where;

The angular speed of the ball = 7 rev/s = 7 rev/s  x 2π rad/rev = 14π rad/s

T = 2π/14π

T = 1/7 s = 0.142 s

The frequency of the ball's motion is the inverse of the period of the motion and can be calculated as follows;

f = 1/T

f = (1) / (1/7) = 7 Hz

Thus, the period of the ball's motion is determined from the angular speed of the ball while the frequency of the ball's motion is the reciprocal of the period of the motion.

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The amount of work that the force does as the particle crosses the 21.0 J. Work done refers to the amount of energy used by a force that move an object.

A force's output is defined as the product of the force's component acting in the displacement's direction and its magnitude. Formula. The following formula can be used to determine work: multiply force by distance traveled inside the direction of force. W = F × d.

A force is said to have completed its work when it exerts itself on an object and the object really moves in the direction of the applied force. A product of the force as well as the object's displacement in the force's direction is the work that the force produces.

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Answer:

Explanation:

The work is numerically equal to the area of ​​the figure lying under the graph of the function.

(a)

A₁ = (1/2)·80·6 = 240 J

(b)

A₂ = (1/2)·40·3 = 60 J

(c)

A = A₁ + A₂ = 240 + 60 = 300 J

Answer:

KE + PE = constant       conservation of energy

At 50 m   KE = zero and PE = m g h

PE = 700 kg* 9.80 m/s^2 * 50 m = 343,000 Joules

PE + KE = 343,000 J

At point R

PE = 343,000 J - 1/2 * 700 kg * 400 m^2 / s^2 = 203,000 J

m g h = 203,000 J       at point R

h = 203,000 J / (700 kg * 9.80 m/s^2 = 29.6 m    height of point R

Check:

343,000 = 700 * 9.80 * 29.6 + 350 * 400 = 343,000    

Adding PE and KE at point R

The work done will be zero, since the object does not move. Also, the power will be zero since the work done is zero because the force must be applied in the direction of motion.

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(a) To generate a 1 T magnetic field inside the solenoid, we need 7.96 x 10⁶ turns.

(b) If we had an iron core inside the solenoid with relative permeability of 64,000, the number of  turns would be 124 turns.

The number of turns of the solenoid is determined by applying the following equation for magnetic field strength at the center of the solenoid.

B = μnI

where;

n = B/ μI

N/L = B/μI

N = (BL)/μI

where;

n = (1 x 0.01) / (4π x 10⁻⁷  x 0.001)

n = 7.96 x 10⁶ turns

If we had an iron core inside the solenoid with relative permeability of 64,000, the number of turns would be calculated as;

N = (BL)/(μI x μr)

where;

N = (1 x 0.01) / (4π x 10⁻⁷  x 0.001 x 64,000)

N = 124 turns

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Answer:

Explanation:

velocity describes the directional speed of an object in motion as an indication of its rate of change in position (includes magnitude but not the direction) while acceleration is the change in velocity (inculdes direction and magintude)

Examples of following forces mentioned -

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The average mass  of nitrogen isotopes is 14.3 amu.

By adding the relative average atomic masses of each atom in the system, the mass of an ion or molecule is computed and weighted for its isotopic composition. Hydrogen, for instance, has an average atomic mass of 1.00797 Da, while carbon's is 12.01115 Da.

Given parameter:

30% of the nitrogen atoms have a mass = 15amu.

70% of the nitrogen atom isotopes have an atomic mass = 14 amu.

So, average mass of nitrogen = 15 amu × 30% + 14 amu × 70%

= 14.3 amu.

Hence, the average mass of the nitrogen is 14.3 amu.

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Astronomers refer to as retrograde motion of the planets to an apparent movement of the planets westward from night to night.

The retrograde movement or the retrogradation of the planets is the apparent movement that a planet makes in the opposite direction to the other bodies that make up the system where it is.

This movement is actually an optical illusion that occurs due to the difference in speed between the different planets, looking as if one of them were moving backwards from east to west.

Therefore, we can confirm that the correct answer is option D. apparent movement of the planets westward from night to night.

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It is evident from Isaac Newton's equation for universal gravitation that ANY TWO masses will act as an easily calculable attractive force on one another. Cavendish proved that this was accurate (for masses that he gathered in his shed).

The Cavendish experiment was the first to accurately determine the gravitational constant and the force of gravity between masses in a laboratory setting. Cavendish's work does not directly mention the gravitational constant due to the unit norms in use at the time. Instead, the outcome was initially stated as Earth's specific gravity, or alternatively, as Earth's mass. The first precise values for these geophysical constants came from his experiment.

Thus, by measuring the universal  gravitational constant though experiment,  Cavendish's experiment makes easy to calculate gravitational attraction force for minute objects also.

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You may find out an object's total displacement—or how far it is from its point of origin—by using the football player's total displacement, d=46.10yd,definite integral of velocity function of an item.

It's common for people to believe that distance & displacement are really just different labels for the same thing. Displacement and distance are different ideas, though. The overall distance traveled by an object during its voyage will be more than the displacement between those two points if it changes direction.

In terms of its density and volume, the displaced fluid's mass can be stated as m = V. W = mg, where g is the acceleration due to gravity, is the weight of the fluid that has been displaced. As a result, W = Vg can be used to indicate the weight of the displaced fluid.

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Velocity of the object parameters would affect the fall if air drag is also considered.

Velocity can be defined as the rate at which that moves in a specific direction. as the velocity of a car driving north on a road or the pace at which a rocket takes off. Because the velocity vector is scalar, its integrand magnitude will always equal the motion's speed.

A moving object has a negative velocity when it is moving in the wrong direction. If an object is slowing down, its generate and evaluate is pointing away from the direction in which it is moving (in this case, a positive acceleration).

An object must move at a constant speed and direction in order to have a constant velocity. The object can only travel in a straight line if the direction is constant. So, motion in a single direction at a constant speed is defined as having a constant velocity.

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Total displacement of the football player is 49.09 yards.

Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude.

A football player runs due east for 30 yards then cuts up the field due north for a distance of 35 yards before running into the end zone.

Total displacement of the football player is 49.09 yards.

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The person who threw the punch remains stationary, and their hand undamaged because the impulse received by the opponent is greater than the reaction force experienced by the person who threw the punch.

Newton's third law of motion states that for every action, there is an equal and opposite reaction. That is, action force and reaction force are equal and opposite.

Mathematically, the Newton's third law of motion can be stated as follows;

Fa = Fb

where;

In a barfight, when one person swings a punch with their bare hand and knocks another person over a table in spectacular fashion. The person who threw the punch remains stationary, their hand undamaged because the impulse received by the opponent is greater than the reaction force experienced by the person who threw the punch.

The force applied by the person who threw the punch maybe equal and opposite to reaction he received but the impulse experienced by the opponent is greater.

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Answer:

Approximately [tex]1.9\times 10^{4}\; {\rm N}[/tex] (rounded up) assuming that [tex]g = (-9.81)\; {\rm N \cdot kg^{-1}}[/tex] (downwards.)

Explanation:

The car is accelerating at a constant [tex]a = 0.60\; {\rm m\cdot s^{-2}}[/tex] (positive since the car is accelerating upwards.) Hence, the net force on this car will be:

[tex]\begin{aligned}F_{\text{net}} &= m\, a \\ &= 1800\; {\rm kg} \times 0.60\; {\rm m\cdot s^{-2}} \\ &= 1080\; {\rm N}\end{aligned}[/tex].

Note that since net force points in the same direction as acceleration (upwards,) [tex]F_{\text{net}}[/tex] is also positive.

The main forces on this car are:

With a mass of [tex]m = 1800\; {\rm kg}[/tex], the weight on this car will be [tex]m\, g = 1800\; {\rm kg} \times (-9.81)\; {\rm N \cdot kg} = (-17658)\; {\rm N}[/tex] (negative since weight points downwards to the ground.)

The net force on this car is the sum of the external forces:

[tex]F_{\text{net}} = F(\text{tension}) + m\, g[/tex].

It is shown that [tex]F_{\text{net}} = 1080\; {\rm N}[/tex] while [tex]m\, g = (-17658)\; {\rm N}[/tex]. Substitute both values into the equation and solve for [tex]F(\text{tension})[/tex]:

[tex]1080\; {\rm N} = F(\text{tension}) + (-17658)\; {\rm N}[/tex].

[tex]\begin{aligned}F(\text{tension}) &= 1080\; {\rm N} + 17658\; {\rm N} \approx 1.9\times 10^{4}\; {\rm N} \end{aligned}[/tex] (rounded up.)

In the article the study author recommends going on a photo hunt and the purpose of this activity is Becoming more assertive.

The reason why the author gave the recommedation about going for the photo hunt is that the activity can bring about assertiveness which has not been seen in the participants before.

It should be noted that with the assertion, there will be display of  confident as well as  forceful personality as they are taking part in the photo hunt, because it involves the activity whereby the participants will be competing with themselves in the collection of the greatest number of objects which is been goteen from the predetermined list.

In conclsion, the recomedation about going to the photo hunts by te author was made so that they can become more assertive.

Therefore , the last option is correct.

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In arrangement B) , mirrors are placed mutually perpendicular to each other .

A retroreflector is a device or surface that reflects radiation back to its source with minimum scattering.

When two mirrors are placed perpendicular to each other , and if a  light ray that strikes an object consisting of two mutually perpendicular reflective surfaces is reflected back exactly parallel to the direction to the source it came from.

out of all arrangements , it can be observed that in arrangement B) , mirrors are placed mutually perpendicular to each other .

hence , correct option will be

option B

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White's narrative approach encourages families to option a. create alternative accounts of their lives.

A type of therapy called narrative therapy seeks to detach the patient from the issue, allowing them to externalize their problems rather than keep them inside. It depends on the person's own abilities and sense of purpose to get them through challenging situations.

Note that Writing or reading stories with problems and answers related to the person's circumstances might be part of a narrative approach. The goal of narrative techniques is to give children a different means of expressing their feelings through words.

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See full question below

White's narrative approach encourages families to:

a. create alternative accounts of their lives

b. gain awareness of the origins of their problem

c. attend to reflecting team observations

d. develop a problem-saturated perspective

The Force exerted by the physicist as she steps on a piece of gum is 18 Newtons and the right option is B) 18 Newtons.

Force can be defined as the product of mass and acceleration. The S.I unit of force is Newton (N) or kilogram- meter-per-seconds (kgm/s).

To calculate the amount of force she would exert, we use the formula below.

Formula:

Where:

From the question

Given:

Substitute these values into equation 1

Hence, the force exerted by the physicist is 18 N.

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The simple conclusion I can make from the task given above is that all the objects in the universe possess constant acceleration under the influence of a free fall is actually due to gravity.

It has been practically proven that all objects or bodies; regardless of their masses have the same acceleration as long as they are under a free fall as a result of the Earth's gravitational force.

So therefore, it can now be deduced with understanding that all free falling objects have the same acceleration due to gravity.

Complete question:

What conclusion can you make on acceleration and free falling objects grade?

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