Ordering is the first step of materials management
True
False

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Answer 1

Ordering is the first step of materials management. This statement is not accurate. Ordering is not the first step of materials management. It is a fundamental component of the procurement process, which involves obtaining the goods and services needed for business purposes.

:1. Planning and controlling: This is the first stage of materials management. It includes determining the quantity of materials needed, forecasting future demand, and creating a plan for material acquisition and distribution.2. Purchasing: This stage entails placing orders for goods and services from suppliers or vendors. It includes selecting the right supplier, agreeing on terms and conditions, and managing the procurement process.3. Inventory management: This stage entails tracking and managing inventory levels to ensure that materials are available when needed. This includes setting inventory targets, monitoring inventory levels, and ordering materials when they fall below the minimum threshold.4. Receiving and inspection: This stage involves receiving the goods and services, inspecting them to ensure that they meet quality standards, and accepting or rejecting them as necessary.5. Warehousing and storage: This stage includes storing and maintaining inventory in a safe, secure, and organized manner.

It involves managing the layout of the warehouse, labeling and tracking inventory, and maintaining safety standards.6. Material handling and transportation: This stage entails moving materials from one location to another within the warehouse or between different locations. It involves managing the flow of materials, selecting appropriate transportation methods, and ensuring that materials are transported safely and efficiently.In conclusion, the statement "Ordering is the first step of materials management" is False. The first step is the planning and controlling stage.

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You are looking to calculate the Earned Value for a project with a Project Plan that had a Budget of $5,000,000; Activities = 20 (equally weighted), and a Duration = 10 months.
Let's assume that the project spending rate is the same each month until completion. At month 5 your personnel in the field are reporting that you are 40% complete on the project and you've spent $3,000,000. What does your Earned Value Management look like?
In other words, calculate the Earned Value Analysis, Variance Analysis, and Trend Analysis for this project and discuss these values.

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Earned Value Analysis is a type of project management approach that allows project managers to monitor the performance of a project. It's a means of measuring how much of a project has been completed in terms of value.

In a project that has a budget of $5,000,000, activities that are equally weighted and a duration of 10 months, the Earned Value can be calculated as follows:Step 1: Calculate the Planned Value.This is the budget for the project as of Month 5, and it is the value that should have been spent so far.

This means that for every dollar spent, we are only earning $0.67 in value.Step 7: Calculate the Schedule Performance Index (SPI). This is the ratio of the Earned Value to the Planned Value, and it tells us how well we are sticking to our schedule. The Schedule Performance Index is calculated.

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p.18.12. Calculate the allowable axial compressive load for the column of Problem \( 18.11 \) : (a) if the ends are fixed (b) if they are fixed/pinned

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Modulus of elasticity, E = 200 GPaMoment of inertia,

[tex]I = π/4 (D² - d²) = π/4 (0.1² - 0.08²) = 7.907 × 10⁻⁶ m⁴[/tex]

The minimum radius of gyration of the column,[tex]r = √(I/A) = √(7.907 × 10⁻⁶ / (π/4 × 0.1²))= 0.02523 m[/tex]

Cross-sectional area of the column, [tex]A = π/4 (D² - d²) = π/4 (0.1² - 0.08²) = 5.516 × 10⁻⁴ m²[/tex]

Slenderness ratio, [tex]λ = Le/r = (0.7 x 3) / 0.02523 = 82.9353For λ = 82.9353, and E = 200 GPa,[/tex]

The minimum radius of gyration of the column,

[tex]r = √(I/A) = √(7.907 × 10⁻⁶ / (π/4 × 0.1²))= 0.02523 m[/tex]

Cross-sectional area of the column

[tex]A = π/4 (D² - d²) = π/4 (0.1² - 0.08²) = 5.516 × 10⁻⁴ m²[/tex]

Slenderness ratio, [tex]λ = Le/r = (2 x 3) / 0.02523 = 473.4297F[/tex]or λ = 473.4297, and E = 200 GPa,

the column is long, and the slenderness ratio is not acceptable.

Therefore, the allowable axial compressive load for the column, Pallowable = (Load carrying capacity / Φ) x (1 - λe/50)Where Φ is the column strength reduction factor,

Φ = 0.7 (for E = 200 GPa), and

λe = slenderness ratio = [tex]λ / K = 473.4297 / 0.7 = 676.3289[/tex]

Pallowable = [tex](90 / 0.7) x (1 - (676.3289 / 50))≈ - 3463 kN[/tex]

The negative value of Pallowable indicates that the column cannot support any load at all without buckling.

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1. The concept of a learning curve is as follows: a. Repetition and productivity are unrelated. b. As repetitions increases, productivity increases. C. As repetitions increases, productivity decreases. d. Worker productivity is a constant. 2. An index measure changes with respect to an established baseline. a. True b. False

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1. The concept of a learning curve is as follows: As the number of repetitions increases, productivity increases. As an individual or organization performs an activity repetitively, their skill level and efficiency in performing that activity increase, resulting in improved productivity.

This concept is referred to as the learning curve, and it has significant implications for production and other aspects of operations. For example, knowing the learning curve for a particular task can aid in capacity planning and scheduling, as well as pricing decisions.

The learning curve can be graphed, with production time on the x-axis and units produced on the y-axis, to determine the rate of learning and to estimate the number of repetitions required to achieve a specific level of productivity. The rate of learning is typically expressed as a percentage, and it reflects the improvement in productivity between each repetition.

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Under what legal theory may a subcontractor be liable to a prime contractor, when the prime contractor relies on the subcontractors Bid, but the subcontractor refuses to do the work in accordance with the Bid?
Promissory Estoppel
Breach of Written Contract
Breach of Oral Contract
Unjust Enrichment

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Under the legal theory of promissory estoppel, a subcontractor may be liable to a prime contractor when the prime contractor relies on the subcontractor's Bid but the subcontractor refuses to do the work in accordance with the Bid.

Promissory estoppel
is a legal doctrine that prevents a party from backing out of a promise they made when the other party relied on it to their detriment. In the context of a construction contract, this means that if a subcontractor submits a bid and the prime contractor relies on that bid in making its own bid for the overall project, the subcontractor may be held liable if they refuse to do the work as outlined in their bid.

In order to prove promissory estoppel, the prime contractor would need to show that they relied on the subcontractor's bid to their detriment. This could include things like losing the bid for the overall project, incurring additional costs, or being forced to find a replacement subcontractor at a higher cost.
It's worth noting that the other legal theories listed - breach of written contract, breach of oral contract, and unjust enrichment - may also apply in this situation depending on the specific circumstances. However, promissory estoppel is the most likely theory to be applied when a subcontractor has made a promise that the prime contractor relied on to their detriment.

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Prepare a report discussing the relationship between earthquake, geological environment and buildings. Emphasize the role of geological environment with the risk associated with earthquakes. In addition, investigate the earthquake risk and geology of the area you live or where you are from. Provide earthquake risk map of Turkey and show the past earthquakes that had a magnitude of ≥ 5 recorded in Turkey on active fault map of Turkey.
Report must be 5 pages maximum excluding reference and title pages. 1.5 paragraph space, Times New Roman writing style and 12 Punto letter character must be used in the report. References used must be cited in the text and provided under References section in detail. Materials that will copied directly from internet will not be accepted as project.

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The relationship between earthquake, geological environment, and buildings is a complex one. The geological environment plays a significant role in determining the level of risk associated with earthquakes and the extent of damage that may be incurred during seismic events.

The geological environment is the collection of natural features that interact to shape the earth's surface. Geologic hazards are natural phenomena that can pose a threat to people, property, and infrastructure.

The type of soil or rock on which a building is constructed also plays a role in determining the level of earthquake risk. Regions with soft or loose soils are at higher risk of ground shaking during an earthquake than regions with harder soils.

Buildings that are constructed on steep slopes or near the coast are also at higher risk of damage during an earthquake because of the potential for landslides or tsunamis. poorly designed or constructed buildings are more likely to be damaged during an earthquake than well-designed or constructed buildings.

In Turkey, the country's location on several active fault lines makes it highly prone to earthquakes, and the country has experienced several significant earthquakes in recent history. The earthquake risk map of Turkey indicates that the highest risk of earthquakes in Turkey is in the Marmara region, followed by the Aegean and Mediterranean regions.

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1. IVHS increase Safety on a traffic network. 2. The Capacity of a roadway is the Saturation Flow Rate of this roadway. 3. The smaller the SSD distance, the less the no. of accidents because you can see better. 4. SI is the Standard Influence of accidents on the society. 5. The most practical flow-speed model is the parabola. 6. The starting shockwave speed at a traffic light is either a constant or an average. 7. There are only three queuing disciplines types. 8. There are only two types of queues; humans & vehicles. 9. At maximum density value the flow is zero. 10. At maximum speed value the density is zero. 11. The mechanical performance of a vehicle can increase or decrease safety. 12. A national pedestrian awareness program increases roadway safety. 13. Delineations reduce road safety.

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IVHS (Intelligent Vehicle Highway System) is a technology designed to increase safety on a traffic network. This technology comprises a collection of communication devices, sensors, and computing systems that are designed to enable the flow of traffic in a safer and more efficient manner.

 the deployment of this technology, the flow of traffic on the roadway network can be monitored, and traffic can be directed around any obstructions that may cause congestion or delay.
The Capacity of a roadway is the Saturation Flow Rate of this roadway. Saturation flow rate is the maximum number of vehicles that can pass through a given point on a roadway network in a given amount of time. This rate depends on a number of factors such as the number of lanes, the width of the lanes, the signal timing, and the characteristics of the vehicles.

A national pedestrian awareness program increases roadway safety. This program educates pedestrians on how to cross roads safely, obey traffic signals, and use crosswalks, thus reducing the risk of accidents.
Delineations reduce road safety. Delineations are the lines that mark the edges of the roadway, and they are designed to help drivers stay in their lanes. However, if these lines are faded or worn out, they can actually reduce safety by confusing drivers and causing accidents.

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At the instant the wire at B snaps, determine the reaction forces at A and the angular acceleration of the 250 kg beam if a force of 200 N is applied at point C. Assume the beam is a slender rod. Point B is 1 located i m away from point A, and the beam has a length 1 = 4 m. Az = 0 N Ay = 2700 XN a = 4.35 rad 82

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To provide a more precise answer, we need the numerical values of Ay, a, and other relevant parameters mentioned in the problem statement. With this information, we can apply the equations of equilibrium and rotational dynamics to calculate the reaction forces at A and the angular acceleration of the beam.

Given the scenario where a wire snaps at point B and a force of 200 N is applied at point C on a 250 kg slender beam, we need to determine the reaction forces at point A and the angular acceleration of the beam.

The distance between points B and A is 1 m, and the beam's length is 4 m. Additional information regarding Az, Ay, a, and other relevant values is provided.

To determine the reaction forces at point A and the angular acceleration of the beam, we can apply the principles of equilibrium and rotational dynamics. The force of 200 N applied at point C can be broken down into its components, namely Ax and Ay, where Ax acts horizontally and Ay acts vertically. Given that Az is 0 N, we can focus on the horizontal and vertical equilibrium equations.

In the horizontal direction, the sum of the forces must be zero. Since there is only the force Ax acting horizontally at point C, we can conclude that Ax must be equal in magnitude but opposite in direction to the reaction force at A.

In the vertical direction, we have the force Ay acting downward at point C, the weight of the beam acting downward at its center of mass, and the reaction force Ay acting upward at point A. Using the principle of vertical equilibrium, we can determine the value of Ay.

To calculate the angular acceleration of the beam, we can apply the rotational analog of Newton's second law, τ = Iα, where τ represents the torque, I is the moment of inertia, and α is the angular acceleration. In this case, the slender beam can be considered a rod, and its moment of inertia can be calculated using the formula I = (1/3) * m * L^2, where m is the mass of the beam and L is its length.

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c. Describe causes of cavitation in spillways, gates, and energy dissipators and explain how they can be controlled.

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Cavitation occurs in spillways, gates, and energy dissipaters because of the reduction of pressure that results in the formation of vapor bubbles, which can lead to equipment failure.

Cavitation also causes the production of high-frequency vibrations that lead to the loss of performance, erosion of the metallic surfaces, and pitting. In this context, this essay discusses the causes of cavitation in spillways, gates, and energy dissipators, and explains how they can be controlled.

Cavitation can be controlled by reducing the velocity of the water, increasing the pressure, and ensuring that the flow of water is smooth. the cavitation can be controlled by using the air-venting valve and the discharge valve. The air-venting valve is used to release the air from the system, which can reduce the pressure.

The discharge valve is used to control the flow of water in the system, which can reduce the velocity of the water. The shape of the gate and energy dissipater can be modified to ensure that the flow of water is smooth.

Cavitation is caused by the reduction of pressure, which leads to the formation of vapor bubbles. Cavitation can be controlled by reducing the velocity of water, increasing the pressure, and ensuring that the flow of water is smooth.

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Define consolidation process. A saturated soil has a compression index Cc=0.27. Its void ratio at a stress of 125 kN/m² is 2.04, and its permeability is 3.5X10-8cm/sec. Compute:
(i) The change in void ratio if the stress is increased to 187.5 kN/m²
(ii) The settlement in (i) if the soil stratum is 5m thick and (iii) Time required for 50% consolidation to occur if drainage is one way and time factor is 0.196 for 50% consolidation.

Answers

Consolidation is a slow process of compaction of saturated soils due to the application of a load. This phenomenon is crucial in geotechnical engineering since it is responsible for the time-dependent settlement of structures like buildings, embankments, dams, etc.

Compression index, Cc = 0.27 Void ratio at 125 kN/m² stress, e₁ = 2.04Void ratio at 187.5 kN/m² stress, Thickness of the soil layer, H = 5 mTime factor for 50% consolidation, Tv = 0.196Permeability, k = 3.5 X 10⁻⁸ cm/sec.Now we will compute the required parameters:

(i) The change in void ratio if the stress is increased to 187.5 kN/m². The relationship between void ratio and stress is given by the equation: [tex]e₂ = e₁ + (Cc x Δσ)[/tex]Where e₂ is the void ratio at stress Δσ.To calculate e₂, we can use the given equation: [tex]e₂ = 2.04 + (0.27 x (187.5 - 125))e₂ = 2.58[/tex]The change in void ratio, [tex]Δe = e₂ - e₁Δe = 2.58 - 2.04Δe = 0.54[/tex]

(ii) [tex]H = (Tv x t₁ x t₂) / log(e₂/e₁)[/tex]Where H is the thickness of the soil layer, t₁ and t₂ are the initial and final times, respectively. Here, we are given only the value of Tv as 0.196 and the thickness of the soil layer, which is H = 5 m.

[tex]H = (Tv x t₁ x t₂) / log(e₂/e₁)5 = (0.196 x 3.2 x t₂) / log⁡(2.58/2.04)₂ = 13.55 years[/tex]

(iii) Time required for 50% consolidation to occur if drainage is one way.

The time required for a certain degree of consolidation is given by the following equation:

[tex]t = Tv x (log(e₁) - log(e₂))²t = 0.196 x (log⁡2.04 - log⁡2.58)²t = 1.24 years[/tex]

Time required for 50% consolidation to occur if drainage is one way is 1.24 years.

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we consider the drying process for the wood board with the thickness D=2L=0.02 meter. The initial water concentration in the plate is co=1000 mol/m3, the water concentration of the surface is cs=0, and the diffusion coefficient of water in the board is 3.0 x 10-10 m2/s. Could you draw the outline the distribution of water concentration inside the board and its time dependency.

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The drying process for a wood board involves water moving from the inside to the surface and evaporating. The concentration of water inside the board decreases over time, following a distribution described by an equation involving the error function. The time required for complete drying depends on the thickness of the board, with thicker boards requiring more time to dry completely.

Drying process for a wood board with thickness D = 2L = 0.02 meter can be defined as the process of water moving from the inside of the wood board to the surface and evaporating.

The distribution of water concentration inside the board can be shown as follows:

Initially, the concentration of water throughout the board is co = 1000 mol/m³. As the drying process starts, the concentration of water decreases and becomes zero at the surface of the board, i.e., cs = 0 mol/m³. The concentration of water varies with time and distance from the surface of the board, as shown in the following figure:

[tex]\large C\left(x,t\right)=\frac{co}{2}\left[1+erf\frac{x}{2\sqrt{Dt}}\right][/tex]

The time dependency of water concentration inside the board can be shown by the error function, where C(x, t) represents the concentration of water in mol/m³ at a distance x from the surface and at time t, D is the diffusion coefficient of water in the board, and erf is the error function.

The time taken for the board to completely dry can be calculated using the following formula:

[tex]\large t=\frac{x^2}{4D}[/tex]

Thus, it can be seen that as the thickness of the board increases, the time taken for the board to dry completely also increases.

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Estimating Labor Determine the Mason and Mason helper work hours using the following information: - Type of work: Placing Concrete Mason Units (CMUs) - Crew productivity rate: 50.00 SF/hour Quantity takeoff: 4,000 SF total - Crew: 2 masons and 4 helpers -60% of all the work hours will be contributed by masons and 40% by their helpers - The bare hourly wage rate for one mason is $25.00 and for one laborer is $18.00. - Choose the closest solutions assuming an effective 8-hour work day (no breaks included) 9) How many total work hours will the masons work on this job? 10) How many total hours will the helper work on this job? 11) What is the average wage rate for the entire work crew ($/hour)? 12) Determine the bare labor cost (in $) using the average wage rate per hour and the hours. the masons and laborers work. Section 4: Estimating Equipment 13) Determine the fuel cost ($/hour) of a piece of construction equipment you currently own that has a 120 horsepower payloader. The fuel cost is $2.63 per gallon, the power utilization is 20%, the consumption rate is 0.04 gallons per hp per hour, and the use factor is 75%. Fuel cost per machine hour - hp rating power utilization){use factor){consumption rate)(fuel cost) 14) Determine the equipment lubrication cost ($/hour). The oil cost is $2.73 per quart, the oiler labor rate is $17.50 per hour. The piece of equipment has its oil changed every 120 working hours. It requires 6 quarts of oll and the time required for the oil change is 2.5 hours. 15) Determine the tire cost ($/work hour) of the equipment. Four tires for a piece of equipment cost $5,000 total and have a useful life of about 2,000 hours. The average cost for repairs to tires is 15% of the original price. Assume that tires have no resale value at the end of their life- cycle. What is the average cost of the tires per hour? 16) Determine the depreciation cost ($/equipment work hour). The equipment initial cost is $67,500 and an anticipated salvage value of the equipment is $2,000. The useful life of the equipment is 6,000 working hours. Depreciation cost per year = (original cost - salvage value)/useful life

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Total work hours will the masons work on this job:The total SF/hour of the crew = Crew productivity rate = 50.00 SF/hourThe SF of the [tex]job = Quantity takeoff = 4,000 SF[/tex] totalThe total hours needed.

Complete the job= Quantity takeoff / Crew productivity [tex]rate = 4,000 SF total/50.00 SF/hour = 80 total[/tex] hoursMasons will work 60% of all the work hours.Masons total work hours = 60/100 × 80 total hours= 48 total hours10. Total hours will the helper work on this job.

The total SF/hour of the crew = Crew productivity [tex]rate = 50.00 SF/hou rThe SF of the job = Quantity takeoff = 4,000 SF[/tex]totalThe total hours needed to complete the job= Quantity takeoff / Crew productivity rate = 4,000 SF total/50.00 SF/hour = 80 total hoursMason helpers will work 40% of all the work hours.

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Calculate the DO and BOD utilisation rate by the bacteria in secondary effluent and comment what would happen if this water is fed through a pipe. Assume 30% of TOC contributes to BOD (or 30% TOC is biodegradable). BOD = 32/12*biodegradable TOC.

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Dissolved oxygen (DO) and biochemical oxygen demand (BOD) are two important parameters that are used to evaluate the quality of water. These parameters can be used to determine how much oxygen is present in water, as well as how much organic matter is present. Bacteria play a critical role in the utilisation of DO and BOD in water. In this question, we are asked to calculate the DO and BOD utilisation rate by the bacteria in secondary effluent.

We are also asked to comment on what would happen if this water is fed through a pipe. Let's start with calculating the DO and BOD utilisation rate. Calculation of DO utilisation rate: The DO utilisation rate by the bacteria in secondary effluent can be calculated using the following formula: DO utilisation rate = (DO in inflow – DO in outflow) / DO in inflow Here, DO in inflow = 6 mg/L DO in outflow = 4 mg/L.

Therefore, DO utilisation rate = (6 – 4) / 6 = 0.33 or 33% Calculation of BOD utilisation rate: The BOD utilisation rate by the bacteria in secondary effluent can be calculated using the following formula: BOD utilisation rate = (BOD5 in inflow – BOD5 in outflow) / BOD5 in inflow Here, BOD5 in inflow = 100 mg/L (as given) BOD5 in outflow = (32/12) x (0.3 x 100) = 8 mg/L.

Therefore, BOD utilisation rate = (100 – 8) / 100 = 0.92 or 92% Now, let's comment on what would happen if this water is fed through a pipe. When water is fed through a pipe, it can have several effects on the quality of water. First, the pipe can cause turbulence and agitation, which can result in the loss of DO. This loss of DO can lead to the death of aquatic life that depends on DO.

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2 p CLO 2: Distribution reinforcement in a simply supported slab, is provided to distribute temperature stress, shrinkage stress, and load. O True False

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The statement, "2 p CLO 2: Distribution reinforcement in a simply supported slab, is provided to distribute temperature stress, shrinkage stress, and load," is true.

Distribution reinforcement in a simply supported slab is added to distribute temperature stress, shrinkage stress, and loads. To be specific, reinforcement is intended to prevent cracks caused by bending stresses in the slab.

However, the reinforcement is insufficient for all instances of shrinkage, and it's often unable to eliminate cracking caused by the effects of temperature changes.

Two-way slabs with spans of less than 10 feet and a slab thickness of less than 9 inches, for example, do not require distribution reinforcement. As a result, reinforcement design is primarily concerned with controlling bending stresses in the slab.

Thus, It is safe to say that the provided statement is true.

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A beam is loaded with the following service loads: Moment due to Dead Load = 271 kN- m Moment due to Live Load = 389 kN-m Section: b=33 cm and d=56 cm. Material properties: f'c-30 MPa and fy = 420 MPa Use rhomax = 0.019 for all calculations If required, compression reinforcement centroid is located 70mm from extreme compression face Calculate the the sum of the tension and compression reinforcements (if required) in mm² Use NSCP2015. Consider the displaced area of concrete. Answer in 2 decimal places.

Answers

Given data :Service loads: Moment due to Dead Load = 271 kN-mMoment due to Live Load = 389 kN-m Section: b = 33 cm and d = 56 cm Material properties: f 'c = 30 MPa and fy = 420 M Pause ρmax = 0.019 for all calculations If required,

diameter bar; number of bars = 283.09/314.16Number of bars = 0.90Provide 2-16 mmØ at 70 mm from the extreme compression face Total area .he total area of steel required for tension and compression = 418.52 + 4.03Total area of steel required for tension and compression = 422.55 mm²/m Total area of steel required for tension and compression = 422.55 cm²/m = 0.042255 m²/m Total area of steel required for tension and compression = 422.55 × 10⁻⁶ m²/mm²Sum of the tension and compression reinforcements (if required) = 0.042255 m²/m Answer: The sum of the tension and compression reinforcements (if required) in mm² using NSCP2015 is 422.55 mm²/m.

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Comment on the benefits and limitations of critical path scheduling techniques. Identify and describe an alternative scheduling technique for management of time that might address some of the limitations of the critical path approach. Guide 1000 words.

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Critical Path scheduling techniques, also known as Critical Path Method, is a project management approach used to plan and coordinate the activities required to complete a project. This approach identifies the critical path, which is the sequence of activities that are necessary to complete a project, while highlighting the project timeline and dependencies.
Benefits of Critical Path scheduling techniques:


1. Helps in identifying the critical path: Critical Path Method provides a clear understanding of the project activities and dependencies. It helps the project manager to identify the activities that are most critical to the project's success, providing a framework for allocating resources effectively.

2. Reduces risks: By identifying the critical path and project dependencies, project managers can develop strategies to mitigate risks and potential issues that may arise during the project's execution.

Limitations of Critical Path scheduling techniques:

1. Focused on time: Critical Path scheduling techniques focus on time management and do not consider other factors that may impact the project's success, such as cost, quality, and resources.

2. Limited flexibility: This method assumes that all activities must be completed in a specific order, with no flexibility in the sequence. However, some activities can be completed concurrently, which can save time and resources.

The Critical Chain Method provides an alternative scheduling technique that addresses some of the limitations of Critical Path scheduling techniques. By focusing on resource constraints and providing greater flexibility, CCM provides a more efficient approach to project management.

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Ministry of Tourism Malaysia has decided to build three blocks of offices and a podium usingmthe Private Finance Initiative (PFI) with a budget of RM 500,000,000. By referring to the Construction Industry Competency Standards processes, describe the necessary actions that the Project Management Officer (PMO) team should consider during the construction life cycle of the project.

Answers

The PMO team should consider the necessary actions to ensure the success of the construction project. These actions include planning, design, construction, and handover. By following these processes, the PMO team can ensure that the project is completed successfully within the allocated budget and timeframe.

Construction Industry Competency Standards (CICS) processes are essential in ensuring the success of a construction project. The Project Management Officer (PMO) team should consider several necessary actions during the construction life cycle of the Ministry of Tourism Malaysia's project to build three blocks of offices and a podium using the Private Finance Initiative (PFI) with a budget of RM 500,000,000.

Actions that the Project Management Officer (PMO) team should consider during the construction life cycle of the Ministry of Tourism Malaysia's project include:

1. Planning

2. Design

3. Construction

4. Handover

Explanation:

1. Planning

Planning is the first phase in a project life cycle. The PMO team should assess the feasibility and viability of the project by analyzing the cost and determining the expected benefits. In this case, the PMO team should evaluate the budget of RM 500,000,000 to ensure that it is sufficient to complete the project successfully. The team should also identify potential risks and develop contingency plans.

2. Design

During the design phase, the PMO team should ensure that the project meets the Ministry of Tourism Malaysia's requirements and complies with the relevant building codes and regulations. The PMO team should review the design of the three blocks of offices and podium and ensure that the design is practical, efficient, and cost-effective.

3. Construction

During the construction phase, the PMO team should ensure that the project is completed on time and within budget. The team should monitor the construction process, review the progress, and ensure that the contractors comply with the safety standards and building regulations. The team should also ensure that the quality of the work is up to standard.

4. Handover

The final phase of the construction project is the handover. The PMO team should ensure that the completed project meets the Ministry of Tourism Malaysia's requirements and standards. The team should conduct a final inspection and ensure that all the necessary documentation and certificates are in place.

Conclusion

The PMO team should consider the necessary actions to ensure the success of the construction project. These actions include planning, design, construction, and handover. By following these processes, the PMO team can ensure that the project is completed successfully within the allocated budget and timeframe.

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which of the following represent the managerial approach to reengineering projects?

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The managerial approach to reengineering projects involves setting objectives, mapping processes, analyzing data, designing new processes, implementing changes, and continuously improving. It focuses on using data and evidence-based decision making to improve business processes.

The managerial approach to reengineering projects is a structured method for defining how work is done and what improvements are needed. It is a management strategy that involves the rethinking and redesign of business processes in order to improve productivity, efficiency, and quality, while reducing costs and increasing customer satisfaction.

The following represent the managerial approach to reengineering projects:

1. Establishing objectives: Setting clear objectives that align with the organization's goals and objectives is critical to the success of a reengineering project.

2. Process mapping: Identifying key processes and mapping out how they currently work, including inputs, outputs, and the sequence of steps required to complete them.

3. Analyzing processes: Analyzing the data collected from process mapping to identify areas for improvement and determine the root causes of problems.

4. Designing new processes: Developing new, streamlined processes that eliminate unnecessary steps, simplify work tasks, and use automation to increase productivity.

5. Implementing changes: Communicating changes to employees and stakeholders, providing training and support, and monitoring progress to ensure the new processes are effective.

6. Continuously improving: Regularly reviewing and revising processes to ensure they remain effective and efficient. This involves measuring performance, analyzing data, and making adjustments as necessary.

Overall, the managerial approach to reengineering projects is focused on using data and evidence-based decision making to drive organizational change and improve business processes.

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A Class 1 post-tensioned concrete beam is simply supported over a 10 m span. The characteristic imposed load consists of a concentrated force of 100 KN at the midspan. The characteristic concrete strength is 50 N/mm² and the unit weight of concrete is 25 kN/m³. The beam is of a uniform section having the dimensions 350 mm (width) x 600 mm (height). Concrete strength at transfer is 40 N/mm² and the prestress loss at transfer is 20%. Determine the maximum economic prestress and the corresponding tendon width at the mid-span.

Answers

The characteristic imposed load of 100 KN at the midspan has been acting on a Class 1 post-tensioned concrete beam, which is simply supported over a 10 m span. The dimensions of the uniform section of the beam are 350 mm (width) x 600 mm (height).

[tex]eff = l/2 = 5 m[/tex]

The area of steel is given by:

[tex]As = M / (0.87f_y(d - 0.42Φp))[/tex]

We can assume Φp = 15.2 mm (to obtain the steel area)

[tex]As = 1250 x 10⁶ / (0.87 x 1900 x (493.6 - 0.42 x 15.2))[/tex]= [tex]1030 mm²[/tex]

[tex]p [σ_p - 0.8f_y] = (π/4 x 13.2²) x (1900 - 0.8 x 1900) = 633.6 N/mm²[/tex]

[tex]f_p = f_pmin + βf_pminf_p = 633.6 + 0.6 x 633.6 = 1013 N/mm²[/tex]

[tex]A_p = As / f_p = 1030 x 10⁶ / 1013 x 10⁶ = 1.017 m²[/tex]

[tex]W = 0.145 x 7 = 1.015 m[/tex]

Therefore, the maximum economic prestress is 1013 N/mm², and the corresponding tendon width at the mid-span is 1.015 m.

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A rectangular head-race canal, 12m wide, supplying a turbine installation has a bed gradient of 1/1800 and a roughness coefficient of 0.02. Under full load the canal supplies 40 cumecs to the turbine and the flow in the canal is uniform. If due to a major rejection of load the turbine on passes 3 cumecs determine the initial celerity which the surge wave propagates upstream.

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Surge wave is created by sudden changes in fluid flow which travel upstream and downstream in the flow. the initial celerity at which the surge wave propagates upstream is 1.17 m/s.

[tex]E = (y + h) / 2g)y = (Q / B)[/tex]

[tex]y = (40 / 12) = 3.33 m[/tex]

[tex]Q = AyR^(2/3)[/tex]

R = A/P

Where, P is the wetted perimeter of the channel.

[tex]A = y * B = 3.33 * 12 = 39.96 m²[/tex]

[tex]P = 2y + B = 2(3.33) + 12 = 18.66 m[/tex]

[tex]R = (39.96 / 18.66) = 2.14 m[/tex]

So, the flow rate when the turbine passes 3 cumecs is

[tex]Q1 = AyR^(2/3) = 37cumecs[/tex]

[tex]3.33m*12m* (2.14m)^(2/3) = 37 cumecs[/tex]

[tex]E = (y + h) / 2gE = (y₁ + h₁) / 2g[/tex]

[tex]h = 2gE - y = (2*9.81*E) - 3.33 = (19.62E - 3.33)[/tex]

[tex]c = (Q² / gB³)^1/8yc = (3.33² / 9.81*12³)^1/8yc = 0.138 m[/tex]

Celerity of surge wave is given by the following formula,

[tex]C = (gyc)^1/2C = (9.81 * 0.138)^1/2C = 1.17 m/s[/tex]

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The Span Table required is only for Beam. The table must include variables of:
(1) Service Class
(2) Different Variable Actions for Residential Floor,Commercial Floor, Light Roof and Heavy Roof
(3) Spacing of Beam.
The table must be completed using the Design Spreadsheet for Beam. Choose only one type
of engineered timber for this Span Table.
TIMBER STRUCTURAL DESIGN

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In structural design of timber, span tables are used to determine the size of joist and beams. In this case, the span table required is only for a beam and must include the variables of service class, different variable actions for residential floor, commercial floor, light roof and heavy roof and spacing of beam.

The table must be completed using the design spreadsheet for a beam. The type of engineered timber chosen for this span table is the glulam or glue-laminated timber.Glulam or glue-laminated timber is a type of engineered timber that is made up of several layers of timber that are glued together to create a large and solid beam. It is often used in structures where a long span is required. The table will include the different spans for various types of glulam timber used. The size of the beam is determined by the required span and the load that it will carry.

The spacing of the beam will also be taken into account to ensure that it is strong enough to support the load. A spreadsheet can be used to complete the table to make it easier to calculate the different variables and to ensure accuracy.

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As an Irrigation Facility Manager,
a) identify key social and economic aspects of the facilities you manage for monitoring to ensure improved performance.
b) Explain your decision to monitor these social and economic aspects of the facilities.
c) Describe how you will undertake this monitoring and why.

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a) Key social and economic aspects of the irrigation facilities that an Irrigation Facility Manager should monitor for improved performance include the economic value of the crops being irrigated, the productivity of the agricultural land, and the costs associated with irrigation.

b) It is important to monitor these social and economic aspects of irrigation facilities because they directly affect the performance of the facility. If the economic value of the crops being irrigated is not high enough to justify the cost of the irrigation facility, then the facility may need to be re-evaluated. Similarly,
c) To undertake monitoring of the social and economic aspects of irrigation facilities, the Irrigation Facility Manager should collect data on crop yields, water usage, and irrigation costs. They should also collect data on the impact of the facility on local communities.

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The City of San Fernando is considering building a new parking lot. The land will cost 250,000 pesos and the construction cost of the lot is estimated to be 1,500.00 pesos. Each year costs associated with the lot are estimated to be 175,000 pesos. The income from the lot is estimated to be 180,000 pesos the first year and increase by 35,000 each year for the twelve year expected life of the lot. Determine the B/C ratio if the City of San Fernando uses a cost of money of 4%.

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Ratib ratio refers to the benefit-to-cost ratio, which is a financial ratio that indicates whether a project's benefits outweigh its costs.

It compares the expected future benefits of a project to the present value of the costs of the project. This ratio is beneficial in assessing the feasibility of a project or investment.

If the B/C ratio is greater than one, it indicates that the benefits are higher than the costs. On the other hand, if the B/C ratio is less than one, it indicates that the costs are higher than the benefits.

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Compare each strength gain and relate its significance on Strength and Economy.
The design strengths are:
a.) 290.7 kNm (using 4-25mm dia. Tension bars)
b.) 378.7 kNm (using 6-25mm dia. Tension bars)
c.) 385.97 kNm (using 9-25mm dia. Tension bars)

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Strength gain is the increase in the strength of a material as a result of the strength reinforcement or modification. For instance, the strength gain can be achieved through tension bars or by the use of additional construction material. The strength gain can impact both the strength and economy of the structure. This article will discuss the strengths and their significance on strength and economy.The following are the three design strengths that will be discussed and compared.

a.) 290.7 kNm (using 4-25mm dia. Tension bars)
b.) 378.7 kNm (using 6-25mm dia. Tension bars)
c.) 385.97 kNm (using 9-25mm dia. Tension bars)

Significance of Strength Gain on Strength and Economy
The greater the strength gain, the stronger the structure, and the more weight it can support. As a result, a significant increase in strength can result in a structure that is more durable, which is important for long-term safety.

Comparing each Strength Gain
In terms of strength, the strength of the structure increases as the number of tension bars increases. The design strength of 290.7 kNm, using 4-25mm dia.

In contrast, the design strength of 378.7 kNm, using 6-25mm dia. Tension bars, is stronger than the previous design. However, it is still less strong than the design with 9 tension bars, which has a design strength of 385.97 kNm.
The design with the highest number of tension bars is the strongest, but it is also the most expensive. As a result, a balance must be struck between strength and economy.

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4.A National Building Policy targets the provision of adequate housing for all consumers at the various levels of life.
a. Mention the major determinants that will make the attainment of housing for all" possible.

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The provision of adequate housing for all is a fundamental social need that must be met to enhance human dignity and well-being. This can be realized through the development of a National Building Policy that targets the provision of adequate housing for all consumers at the various levels of life.

1. Affordable Housing: One of the major determinants of housing for all is affordable housing. Housing affordability is the most critical factor in determining whether people can buy or rent a home. The provision of affordable housing is, therefore, a critical component of a national building policy.

2. Accessibility: The location of the housing is also an important determinant of whether it can be accessed by all. Housing must be located in areas that are easily accessible to public transportation, employment centers, and other essential amenities.
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A draw bench for precision forming and strengthening of carbon steel tubing has a cost of $960,000. It will have a salvage value of $74,000 after a useful life of 10 years. Parta Using the formulas, determine the depreciation charge for year 2 and the book value at the end of year 2 if straight-line depreciation is used. Depreciation charge:$_______________Book value $______________ Carry all interim calculations to 5 decimal places and then round your final answers to a whole number. The tolerance is ±1.

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Given that a draw bench for precision forming and strengthening of carbon steel tubing has a cost of $960,000 and it will have a salvage value of $74,000 after a useful life of 10 years. We have to calculate the depreciation charge for year 2 and the book value at the end of year 2 if straight-line depreciation is used.

Solution: Depreciation per year = (Cost - Salvage value) / Useful life= (960000 - 74000) / 10= 88,600 per yearThe depreciation charge for year 2 = 2 x

Depreciation per year= 2 × $88,600= $177,200Book value at the end of year 2 = Cost - Depreciation charge for 2 years= $960,000 - $177,200= $782,800

Therefore, the depreciation charge for year 2 is $177,200 and the book value at the end of year 2 if straight-line depreciation is used is $782,800.Note:

The tolerance is ±1, so the answers are rounded to a whole number.

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A gas flows at 35°C and 125 kPa absolute at 365 N/s
through a circular duct (200 mm diameter).
If R=29.3 m/°K,
find the discharge?

Answers

Given, The gas flows at 35°C and 125 kPa absolute[tex], R = 29.3 m/°K[/tex], and the gas flow through a circular duct with a diameter of 200 mm.

To find the discharge, we use the formula for gas discharge.The formula for gas discharge is as follows,[tex]Q = (A × V) / 1000Where Q = Discharge[/tex] in m3/s, A = Cross-sectional area in mm2, and V = Velocity in m/s.To find the discharge, we need to calculate the velocity of gas and the cross-sectional area of the duct using the given parameters.

The velocity of gas can be determined using the following formula:[tex]v = C √R Twhere C = constant, R = gas constant[/tex], and T = absolute temperaturev = 0.0699 m/s (approx)2. The cross-sectional area of the duct can be determined using the[tex]formula:A = πd²/4where d = dia meterA = 31416.15 mm².[/tex]

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Compute the service axial compressive load permitted on a 10x10x structural tube having an effective length (KL), = 8 ft. The load is 60% live load. Use (a) A992 steel; (b) Fy = 60 ksi; and (c) Fy = 100 ksi.

Answers

We will use Euler’s column formula,

[tex]Pcr = π²EI/L²[/tex]Where,Pcr = Critical loadE = Modulus of ElasticityI = Moment of InertiaL = Effective Lengtha) For A992 Steel with Fy = 60 ksiE = 29000 ksi (for steel)

[tex]I = 8.33 in⁴[/tex] (for 10x10x tube)

[tex]Fy = 60 ksiL = 8 ft = 96[/tex] in

Substituting the values in Euler’s column formula,

Pcr = π²EI/L²= π²x29000x8.33/(96)²= 143.9 kips

Therefore, the service axial compressive load permitted on a 10x10x structural tube having an effective length (KL), = 8 ft for A992 steel and [tex]Fy = 60 ksi is 143.9 kips[/tex].

b) For A992 Steel with[tex]Fy = 100 ksiE = 29000 ksi (for steel)I = 8.33 in⁴[/tex] (for 10x10x tube)

[tex]Fy = 100 ksiL = 8 ft = 96[/tex] in

Substituting the values in Euler’s column formula,

[tex]Pcr = π²EI/L²= π²x29000x8.33/(96)²= 239.8 kips[/tex]

Therefore, the service axial compressive load permitted on a 10x10x structural tube having an effective length (KL), = 8 ft for A992 steel and [tex]Fy = 100 ksi is 239.8 kips.[/tex]

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Thermal energy storage systems commonly involve a packed bed of solid spheres, through which a hot gas flows if the system is being charged, or a cold gas if it is being discharged. In a charging process, heat transfer from the hot gas increases thermal energy stored within the colder spheres; during discharge, the stored energy decreases as heat is transferred from the warmer spheres to the cooler gas. Consider a packed bed of 75 -mm-diameter aluminum spheres (rho=2700 kg/m3,c=950 J/kg⋅K,k= 240 W/m⋅K ) and a charging process for which gas enters the storage unit at a temperature of Tg,i​=300∘C. If the initial temperature of the spheres is Ti​=25∘C and the convection coefficient is h=75 W/m2⋅K, how long does it take a sphere near the inlet of the system to accumulate 90% of the maximum possible thermal energy? What is the corresponding temperature at the center of the sphere? Is there any advantage to using copper instead of aluminum?

Answers

The corresponding temperature at the center of the sphere after approximately 0.309 seconds is approximately 198.83°C.

To determine the time required for a sphere near the inlet of the system to accumulate 90% of the maximum possible thermal energy, we can use the concept of thermal diffusion through a sphere. The time required can be calculated using the equation for the thermal diffusion time constant:

τ = (ρ * c * r^2) / (4 * k)

where:

τ is the thermal diffusion time constant,

ρ is the density of the sphere material (in this case, aluminum) = 2700 kg/m^3,

c is the specific heat capacity of the sphere material (in this case, aluminum) = 950 J/kg⋅K,

r is the radius of the sphere (diameter/2) = 75 mm / 2 = 37.5 mm = 0.0375 m,

k is the thermal conductivity of the sphere material (in this case, aluminum) = 240 W/m⋅K.

Substituting these values into the equation, we can calculate the thermal diffusion time constant:

τ = (2700 kg/m^3 * 950 J/kg⋅K * (0.0375 m)^2) / (4 * 240 W/m⋅K)

Now we can solve for τ:

τ ≈ 0.309 seconds

The thermal diffusion time constant represents the time required for a sphere to reach approximately 63.2% of the maximum possible thermal energy. To calculate the time required to accumulate 90% of the maximum energy, we can use the following relation:

t = τ * ln((90% - 63.2%) / (100% - 63.2%))

Substituting the values into the equation:

t = 0.309 seconds * ln((90% - 63.2%) / (100% - 63.2%))

t ≈ 0.309 seconds * ln(0.271 / 0.368)

t ≈ 0.309 seconds * ln(0.736)

t ≈ 0.309 seconds * (-0.305)

t ≈ -0.094 seconds

The negative value obtained implies that 90% of the maximum possible thermal energy cannot be accumulated within a sphere near the inlet of the system. This suggests that the system may need additional time or adjustments to reach the desired energy level.

To calculate the corresponding temperature at the center of the sphere, we can use the concept of one-dimensional transient heat conduction through a sphere. The equation for this scenario is:

T = Ti + (Tg,i - Ti) * (1 - exp(-t / τ))

where:

T is the temperature at the center of the sphere at time t,

Ti is the initial temperature of the spheres = 25°C,

Tg,i is the gas temperature at the inlet of the system = 300°C,

t is the time,

τ is the thermal diffusion time constant calculated earlier.

Let's calculate the corresponding temperature at the center of the sphere when t = 0.309 seconds

T = 25°C + (300°C - 25°C) * (1 - exp(-0.309 / 0.309))

T ≈ 25°C + 275°C * (1 - exp(-1))

T ≈ 25°C + 275°C * (1 - 0.3679)

T ≈ 25°C + 275°C * 0.6321

T ≈ 25°C + 173.8275°C

T ≈ 198.8275°C

Therefore, the corresponding temperature at the center of the sphere after approximately 0.309 seconds is approximately 198.83°C.

Now, let's consider the advantage of using copper instead

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1. What is the key message that you have learnt about the ground improvement design, in terms of time to achieve Degree of Consolidation, U = 90% ?
Note: Choose only one answer.
a. Consolidation using permanent fill alone can achieve U = 90% in under a year
b. Consolidation using combination of permanent fill + surcharge can achieve U = 90% in under a year
c. Sand drain helps to deliver U= 90% in under a year.
d. There is no benefit of having the intermediate sand layer.
1. What are the effects of lowering the ground water table in this ground improvement program?
Note: You may choose more than one answer.
a. It will have a positive impact of increasing the magnitude of consolidation settlement
b. The impact is negligible because the soils experienced increase in total stress
c. There is not much of a benefit as the ground now is less bouxant

Answers

The key message that can be learnt about the ground improvement design, in terms of time to achieve Degree of Consolidation, U = 90% is consolidation using combination of permanent fill + surcharge can achieve U = 90% in under a year.

Sand drain helps to deliver U = 90% in under a year as well. Hence, the answer is (B).The following are the effects of lowering the ground water table in this ground improvement program:a. It will have a positive impact of increasing the magnitude of consolidation settlement.b. The impact is negligible because the soils experienced an increase in total stress. Therefore, the answers are (A) and (B).c. There is not much of a benefit as the ground now is less bouxant is incorrect as it is not a correct statement about the effects of lowering the ground water table in this ground improvement program. The statement is not relevant to this ground improvement program. Therefore, the answer is not (C).

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a.) List out the project attributes of the successful BIM
project outcomes.
b.) What is meant by On-site performance measurement system
(OPMS)?

Answers

a.) The successful BIM project outcomes depend on the project attributes, which include:
1. Proper Planning: Every project must undergo a thorough planning stage to ensure that the project is successful. A BIM project must include the construction process, timelines, cost, and quality control.


2. Communication: Communication is essential to ensure that everyone is on the same page and the project runs smoothly. In the case of BIM, the exchange of information should be in a clear, understandable and timely manner.

3. Standardization: Standardization must be ensured, from the exchange of data to the creation of BIM models. This will ensure that all parties involved in the project have the same understanding of the project.

4. Proper Management: The project manager should be qualified and have a full understanding of the project. The project manager should have good management skills to ensure that the project runs smoothly, on time, and within budget.

5. Collaborative Team: A collaborative team is essential for the successful completion of a BIM project. Team members should have good communication skills, proper training, and skills to work together towards a common goal.

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.LeBron James (LBJ) Corporation agrees on January 1, 2020, to lease equipment from Crane, Inc. for 3 years. The lease calls for annual lease payments of $20,000 at the beginning of each year. The lease does not transfer ownership, nor does it contain a bargain purchase option, and is not a specialized asset. In addition, the useful life of the equipment is 10 years, and the present value of the lease payments is less than 90% of the fair value of the equipment.Prepare LBJs journal entries on January 1, 2020 (commencement of the operating lease), and on December 31, 2020. Assume the implicit rate used by the lessor is unknown, and LBJs incremental borrowing rate is 4%. A small sphere with charge 0.850 C is placed at the center of a cube. What is the electric flux through one surface of the cube? answer in Nm2/C For questions in this assignment, you may treat lim k = k, and lim x = c as known facts. xC xC 2.4 Continuity (1) Use theorem 1 theorem 5 to show that the functions below are continuous (a) x +5x+x-7, x + 3x + 7 (b) x +9 As wind speed increases, how does Hcv change? Assume other factors do not change. Hcv would decrease it would not influence Hcv Hcv would increase (heat flux into or away from the organism would increase) Provide step by step solution to solve for the given matrices. 2 ^ - (61 + +-) 1 0 -1 1 1. A 0 1 2. A = (-3 5) 3. A = (48) the value of c. Find the expected value of X.The television show Ghost Whistler has been successful for many years. That show recently had a share of 16 , meaning that among the TV sets in use, 16% were tuned to Ghost Whistler. 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