Parallelogram A B C D is shown. Line segment X Y goes from point X on side A B to point Y on side C D to form 2 trapezoids.
Figure ABCD is a parallelogram. Two trapezoids are created using line segment XY such that AX ≅ CY.

What is true about the areas of the trapezoids?

Each area is equal to half of the area of ABCD.
The area of AXYD is less than the area of BXYC.
The area of AXYD is greater than the area of BXYC.
Each area is equal to the area of ABCD.

Answer:

B. -0.07

Step-by-step explanation:

Apply the Law of signs find θ.

Cos θ = (a² + b² - c²)/2ab

Where,

a = 7

b = 8

c = 11

Plug in the values

Cos θ = (7² + 8² - 11²)/2*7*8

Cos θ = (49 + 64 - 121)/112

Cos θ = -8/112

Cos θ = -0.0714285714

Cos θ = -0.07 (to 2 decimal places)

Answer:

90°

Step-by-step explanation:

m∠x+m∠y+m∠z=180°

m∠x+m∠y+90=180

m∠x+m∠y=180-90=90°

Answer:

forst mark me as a brainleast

Cubic centimetres since they are cubes. Did you add any picture of the question? There seems to be none.

Step-by-step explanation:

Length of a rope is 5 meter. it means the rope is 5 meter long..

Answer:

2850

Step-by-step explanation:

1+2+3+4+5+6+7...74+75

just add up all the numbers from 1 to 75

Answer:

its a i think

Step-by-step explanation:

Answer: 24

Step-by-step explanation:

Answer:

there are 2 apples in the basket

there are 10 banana in the basket

Step-by-step explanation:

According to the Question,

let x for apple And y for banana So, x+y=12---Equation 1

Thus, 5x+7y=80 ----Equation 2

Now, (Equation 1) × 5 Subtract with (Equation 2) We get,

2y = 20 ⇒ y=10 (there are 10 banana in basket)

5x+70=80 ⇔ x=2(there are 2 apples in basket)

Answer:

r can be 0.5

Step-by-step explanation:

Here, we want to get a possible value of r

From the question, the value of r is between 0 and 3

Mathematically, we know that in degrees pi is the same as 180 degrees

In a case where we have r = 1/2

we have it that;

cos(pi/2) = 2 cos (pi/2)

Since pi/2 is 90 and cos 90 is zero; then we have it that the two sides of the equation is the same and r can be 1/2

the arc length is calculated by the formula                                                                    [tex]\displaystyle\bf C=\frac{2\pi r}{360} \cdot\alpha[/tex]   then   [tex]\displaystyle\bf C=\frac{2\cdot 8 \pi }{360} \cdot180=8\pi=3,14\cdot8=25.12[/tex]   or it can be calculated using the circumference of the circle since we have a semicircle the circumference 2πr must be divided by 2  С=2πr:2=πr =8π=25,12

Step-by-step explanation:

i think minerals and vitamins since they are micro nutrients

Answer:

a=1

Step-by-step explanation:

Hopefully this helps :)

The equation of the parabola is: y = (x - 2)² - 2. Finding the value of A

The vertex of the parabola is at (2,-2). Since the parabola opens upward, the equation of the parabola will be of the form:

y = A(x - 2)² - 2

We can plug the point (3,-1) into this equation to find the value of A.

-1 = A(3 - 2)² - 2

Simplifying the right side of the equation, we get:

-1 = A - 2

Adding 2 to both sides of the equation, we get:

1 = A

Therefore, the value of A is 1.

Writing the equation of the parabola

The equation of the parabola is:

y = (x - 2)² - 2

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Answer:

2ft

Step-by-step explanation:

The tide doesn't effect the part of ladder that is underwater that is always 2ft

How much of the ladder that will be underwater is 7 ft.

Since the ladder is 10 ft long and its last two feet are submerged under water, this implies that 2 ft of the ladder are submerged under water.

When the tide rises by five feet, the part of the ladder that would be under water is 2 ft + 5ft = 7ft.

So, how much of the ladder that will be underwater is 7 ft.

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Answer:

11.26 m

Step-by-step explanation:

The height of the tree is about 11.25 meters.

When the respective sides are proportional and the corresponding angles are congruent, two triangles are said to be similar.

Given that, the height of the person is 1.55 meters, the length of the tree's shadow is 38.15 meters, and the distance between the person and the tree is 32.9 meters.

Let the height of the tree be x.

Note that the scenario makes two similar triangles.

Since the ratio of the side lengths of similar triangles is proportional, it follows:

(38.15 - 32.9)/1.55 = 38.15/x

5.25/1.55 = 38.15/x

3.39 = 38.15/x

x = 38.15/3.39

x = 11.25

Hence, the height of the tree is about 11.25 meters.

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Answer:

Step-by-step explanation:

Population size: 17

Median: 30

Minimum: 12

Maximum: 49

First quartile: 21

Third quartile: 35

Interquartile Range: 14

Outliers: none

Answer:

X= − x ^3 + 2 x^2 − 3 x − 2 x ^3 ( x + 2 ) ( x − 2 ) = 0

Step-by-step explanation:

Step-by-step explanation:

The answer to the question is 3

Answer:

3

Step-by-step explanation:

1 + X = 4

4 - 1 = X

3 = X

Answer:

[tex]A(-3,2)\: B(-1,-2)\: C(1,3)[/tex]

[tex]A=1/2[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)][/tex]

[tex]=1/2[-3(-2-3)(+1(3-2)+1(2-(-2))][/tex]

[tex]=1/2(15+1+4)[/tex]

[tex]=1/2(20)[/tex]

[tex]=10[/tex]

[tex]ANSWER: 10 ~units^{2}[/tex]

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hope it helps...

have a great day!!

The area of triangle with vertices A(-3,2), B(1,-2), and c(1,3) is 12 units^2.

The area of a triangle is defined as the total space occupied by the three sides of a triangle in a 2-dimensional plane. The basic formula for the area of a triangle is equal to half the product of its base and height, i.e., A = 1/2 × b × h.

The green line represents the height of the triangle = 4 units

The red line represents the base of the triangle = 6 units

Area of the triangle = 1/2 x 6 x 4 = 12 units^2

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Answer:

y = 0x

Step-by-step explanation:

y=-4x-b

0 = -4(0) + b

0 = 0 + b

0

Answer:

m = 0

y intercept = 1

Step-by-step explanation:

The given equation of the line is ,

[tex]\implies y = 1[/tex]

We know that the Standard equation of Slope Intercept Form of the line is,

[tex]\implies y = mx + c[/tex]

Where ,

On comparing to the Standard form of the line we get ,

[tex]\implies Slope = 0 [/tex]

[tex]\implies y - intercept= 1[/tex]

Slope of the line is 0, since y=mx+c, if m = 0, then y = c, where the constant (c)=1

y intercept of the line is y = 1.

Answered by GAUTHMATH

Answer:

T(x) = 21 + 4.5x

Step-by-step explanation:

Given :

Original temperature = 21°C

Final temperature = 75°C

Time, x = 12 minutes

The temperature, T as a function of x, heating time in minutes :

We need to obtain the constant heating rate per minute :

Final temperature = initial temperature + (constant rate change,△t * time)

75 = 21 + 12△t

75 - 21 = 12 △t

54 = 12 △t

△t = 54 / 12

△t = 4.5°C

Hence, temperature change is 4.5°C per minute.

Hence,

T(x) = 21 + 4.5x

Answer:

T= 21+4.5x

Step-by-step explanation:

I got it right on Khan Academy

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Answer:

45

Step-by-step explanation:

Both angles have the same value, therefore, you can set your formula up as

5x-105=2x+30

5x = 2x + 30 + 105

5x - 2x = 135

3x = 135

x = 135/3

x = 45

Given:

Consider the given equation is:

[tex]p\div \sqrt{2}=\sqrt{\dfrac{t}{r+q}}[/tex]

To find:

The value of t in terms of p, q and r.

Solution:

We have,

[tex]p\div \sqrt{2}=\sqrt{\dfrac{t}{r+q}}[/tex]

It can be written as:

[tex]\dfrac{p}{\sqrt{2}}=\sqrt{\dfrac{t}{r+q}}[/tex]

Taking square on both sides, we get

[tex]\dfrac{p^2}{2}=\dfrac{t}{r+q}[/tex]

Multiply both sides by (r+q).

[tex]\dfrac{p^2(r+q)}{2}=t[/tex]

Therefore, the required solution is [tex]t=\dfrac{p^2(r+q)}{2}[/tex].

Answer:

Step-by-step explanation:

Answer:

$12.43

Step-by-step explanation:

Given :

Mean = $8.52

Standard deviation, = $2.38

Stock price which falls beyond 0.05 of the distribution is at the 95th percentile

The 95th percentile distribution has a Pvalue of 1.645 (standard normal table)

We obtain the value of x, with z = 1.645

Using the Zscore relation :

Zscore = (score - mean) / standard deviation

1.645 = (score - 8.52) / 2.38

Cross multiply :

1.645 * 2.38 = score - 8.52

3.9151 = score - 8.52

Score = 8.52 + 3.9151

Score = $12.4351

Stock price beyond 0.05 is $12.43

Answer:

please I don't know can u please help me out

Answer:

The answer to your question where SAS is given  

∠T ≈∠ W

Answer:

Falso.

Step-by-step explanation:

Sea [tex]d = \frac{a}{b}[/tex] un número racional, donde [tex]a, b \in \mathbb{R}[/tex] y [tex]b \neq 0[/tex], su opuesto es un número real [tex]c = -\left(\frac{a}{b} \right)[/tex]. En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) El exponente es cero.

(b) El exponente es un negativo impar.

(c) El exponente es un negativo par.

(d) El exponente es un positivo impar.

(e) El exponente es un positivo par.

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, [tex]c = d = 1[/tex]. La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

[tex]d' = d^{-n}[/tex] y [tex]c' = c^{-n}[/tex]

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

[tex]d' = \left(\frac{a}{b} \right)^{-n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}[/tex]

[tex]d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]y [tex]c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{b}{a} \right)\right]^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = - \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' \neq c'[/tex], la proposición es falsa.

(c) El exponente es un negativo par.

Si [tex]n[/tex] es par, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' = c'[/tex], la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

[tex]d' = d^{n}[/tex] y [tex]c' = c^{n}[/tex]

[tex]d' = \left(\frac{a}{b}\right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = - \left(\frac{a}{b} \right)^{n}[/tex]

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es par, entonces [tex]d' = c'[/tex] y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.