The Velocity is 4270 m/s it is equal to product of frequency and wavelength.
Given: -
Frequency(f) = 700 Hz
Wavelength(λ) = 6.1m
velocity = f x λ
velocity = 700 x 6.1
velocity = 4270 m/s
Wavelength is a fundamental concept in physics, particularly in the study of waves, which includes electromagnetic radiation, light, and sound waves. It is defined as the distance between two successive points of the same phase, such as the crest or trough of a wave. This distance is usually measured in units of meters, and it is inversely proportional to the frequency of the wave.
In electromagnetic radiation, the wavelength is an important property that determines the type of radiation, such as radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Each type of radiation has a unique range of wavelengths that can be measured using instruments like a spectroscope or a radio antenna.
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A positively charged solid conducting sphere is contained within a negatively charged conducting spherical shell as shown. The magnitude of the total charge on each sphere is the same.
1)Which of the following statements best describes the electric field in the region between the spheres?
A.The field points radially outward
B.The field points radially inward
C.The field is zero
2.Which of the following statements best describes the electric field in the region outside the red sphere?
A.The field points radially outward
B.The field points radially inward
C.The field is zero
CAN u give me a explanation.
1) Statements best describes the electric field in the region between the spheres field points radially outward.
2) Statements best describes the electric field in the region outside the red sphere The field is zero.
For positive charge, E field lines are projecting outward of positive charge.
For negative charge, E field lines are projecting inward of negative charge.
Then, between the spheres,
because of q, E field lines are projecting outward of q and inward of- q;
and because of- q, E filed lines are projecting outward of q and inward of- q
So, The field points radially outward
2) C still, net charge inside the gaussian face is zero, If we draw a gaussian face outside the spheres.
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A simple circuit contains a 10 V battery connected with wires to a small bulb. If the power dissipated by the bulb is 0.5 W, what is the resistance of the bulb?
Group of answer choices
200 ohms
100 ohms
5 ohms
20 ohms
The resistance (slope of a curve) is about 490 so when bulb is lit. According to this model, the resistance was inversely proportional to temperature for materials (such this tungsten filament).200 ohms
LED lights have how many ohms?The datasheet for such LED will include this information as well as the forward dc voltage. LEDs typically demand 10 to 20mA. For instance, a 9V battery powered ultra-bright blue LED has a forwards voltage or 3.2V and a typical current is 20mA. Thus, the resistor must be 290 ohms and as close to that value as is feasible.
Are batteries highly resistant?Due to their relatively high resistance, alkaline, carbon-zinc, and the majority of primary batteries can only be used in low-current devices like flashlights, remotes, portable entertainment systems, and kitchen clocks. The resistance gets worse when these batteries run out of power.
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N₂O4(9) 2NO₂(g)
Colorless Brown
Keq = 6.16 x 10.3
What is the predicted direction of change?
Setup 1:
Setup 2:
Setup 3:
DONE ✔
Setup #
1
2
3
[N₂04]
0.098 M
0.150 M
0.420 M
[NO₂]
0.0064 M
0.0304 M
0.230 M
Here, when , the reaction quotient is less than the equilibrium constant, then, the reaction will move to the right. In the first set up, the reaction quotient is less than Keq. Then, the reaction moves to right.
What is reaction quotient ?The reaction quotient of a reaction is the ratio of molar concentration of the product to the molar concentration of the reactants.
In the first setup.
Keq = 6.16 x 10⁻³
Q = [0.0064]²/[0.098] = 4.18 × 10⁻⁴
Q<K⇒The reaction moved to the right (products)
Setup 2 :
Q = [0.0304]²/[0.150]
= 6.16 x 10⁻³
Q=K⇒the system at equilibrium
Setup 3 :
Q = [0.230]²/[0.420]
= 0.126
Q>K⇒The reaction moved to the left (reactants)
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Answer: products, equilibrium, reactants
Explanation:
its right on edge 2023
A 20 kg box moving at an initial speed of 10 m/s slides 25 m to the right on a horizontal floor before it comes to a complete stop.
A concrete floor surface will produce a coefficient for traditional footwear that is high enough (between 0.55 and 70) to eliminate the foreseeable risk of slipping.
What best define about coefficient of friction of the floor?The ratio between the perpendicular force pushing the objects together and the frictional resistive force is known as the coefficient of friction.
The formula for the friction coefficient is = F N, where is the friction coefficient, is the frictional force, and is the normal force.
A numerical value known as the coefficient of friction (fr) is created by dividing the resistive force of friction (Fr), which pushes the objects together, by the normal or perpendicular force (N), which pushes them apart. It is represented by the formula below: fr = Fr/N.
X= 25 m
u = 10m/s
m = 20kg
F= uN
N= mg
[tex]a = \frac{uN}{m} = \frac{umg}{m}[/tex]
a= ug
[tex]v^{2} =u^{2} - 2ax[/tex]
[tex]o= (10)^2 - 2ug (25)[/tex]
[tex]50 ug = (10)^2 = 100[/tex]
[tex]u = \frac{2}{g} = \frac{2}{10} = 0.2[/tex]
Therefore, 0.2 is the coefficient of friction between the box and floor.
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If q had a different value, would W/q be different or would it have the same value regardless of the value of q? Explain. The electric potential difference AV between two points in an electric field is related to the work W needed to move a charge q from one point to another, and to the change in electric potential energy AU that the system experiences when the charge moves from one point to another: W ΔU ΔV =- 9 9 The SI unit for potential difference is the Volt (V) and potential difference is also frequently called "voltage." 20. Does the potential difference AV between two points in an electric field depend on the electric field (and the charges that created that field), or does it depend on a charge that moves between those two points, or does it depend on both? Explain your reasoning. 21. Two students are discussing their answers to question A20. Megan: The potential difference between two points is the work per unit charge. The electric field determines how much work is done when a charge moves from one point to another. But the value of that moving charge also matters, since q appears in the denominator. If you change the value of q, then you must change the value of W/q. That means the potential difference depends on both the electric field and the value of the charge that moves in that field. Aicha: I agree that the electric field determines W. But if you change q, then you also change the value of W. The amount by which W changes should equal the amount by which q changes, so Wlq should always be the same for an electric field regardless of the value of q. So I think that the potential difference between two points only depends on the electric field, and not on the value of any charge that moves between those points. Do you agree or disagree with either or both of the students? Explain your reasoning 15. Imagine that the electric field in Figure 1 has a magnitude of 20 N/C. Figures 3-5 below show three different paths (dashed lines) that a positive charge q = +3.0 C can take between two points. Find the work done by the electric field on the positive charge for each of these three paths. Show your work. Figure 3 Figure 4 Figure 5 60° 45° 454 30° 1.0 m 1.0 m 1.0 m 16. Does the work done by the electric field on the charge depend on the path that the charge takes to get from one point to another? 17. If q had a different value, would the work you calculated in question A15 be different or would it have the same value regardless of the value of q? Explain. 18. Calculate the work per unit charge W/q for the three paths you analyzed in question A15.
The effort required to transport a unit charge from a reference point to a specified place in opposition to an electric field is known as the electric potential.
That implies that it is dependent on the charge. As a result, altering q's value will also alter the electric potential's value. In other words, W/value q's will change.
Electric potential is a scalar quantity that represents the amount of electric potential energy per unit charge at a given point in space. It is also known as voltage and is measured in volts (V). Electric potential is created by the presence of electric charges, which can be either positive or negative. A positive charge creates a region of higher electric potential, while a negative charge creates a region of lower electric potential. The movement of electric charges from high potential to low potential is what generates an electric current. Electric potential is a fundamental concept in electricity and plays a crucial role in the design and operation of electrical circuits, devices, and systems.
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Four capacitors are of the same capacity. If three of them are connected in
parallel and the remaining one is connected in series with this combination, the
resultant capacity is 16.5 μF. Find the capacity of each capacito
Answer:
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
Explanation:
Continue where the red line would would go
Refraction would cause the red light to bend at the air/glass boundary.
What is refraction?While the question is unclear, I assume that you are trying to know something about the refraction of the red light across the air/glass boundary. I will tell you something about refraction!
Refraction is a phenomenon of light where it changes direction when it enters a medium with a different refractive index. Refractive index is a measure of how much a medium bends light that passes through it. When light passes from a medium with a lower refractive index to a medium with a higher refractive index, it bends towards the normal (an imaginary line perpendicular to the surface at the point of incidence). On the other hand, when light passes from a medium with a higher refractive index to a medium with a lower refractive index, it bends away from the normal.
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An object starts from rest at the origin and moves along the x axis subject to the force shown in the figure below. If the mass of
the object is 38.0 kg, determine the speed of the object at the following positions. Each unit along the position axis is 2.00 m and
each unit along the force axis is 3.00 N.
The speeds of the object at the various positions are :
At x = A; speed = 2.06 m/sAt x = B; speed = 2.38 m/sAt x = speed = 0 m/sWhat is the formula to determine the velocity or speed?The formula to determine the velocity or speed is given below:
velocity or speed = √(2s * F/m)
where:
s the position or displacementF is the forcem is the massThe speeds of the object at the various points are given below:
At x = A: force = 9 N; s = 6 m
speed = √(2 * 6 * 9 / 38)
speed = 2.06 m/s
At x = B; Force = 9 N; s = 12 m
speed = √(2 * 12 * 9 / 38)
speed = 2.38 m/s
At x = C; Force = 0 N; s = 18 m
speed = √(2 * 12 * 0 / 38)
speed = 0 m/s
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2 A tank of water containing 2500 L of water is stored on the roof of a building. the Find its potential energy with respect to the floor, which is 12.0m below roof. b) Find its potential energy with respect to the basement, which is 4.0 m below the first floor (use g=10m/s²)
(a) The potential energy of the tank of water with respect to the floor is 294,000 J.
(b) The potential energy of the tank of water with respect to the basement is 392,000 J.
What is the potential energy?
The potential energy of the tank of water with respect to the floor can be calculated as follows:
Potential energy = mgh
where;
m is the mass of the water, g is the acceleration due to gravity, and h is the height of the tank with respect to the floor.We can first find the mass of the water using the density of water, which is approximately 1000 kg/m³:
Mass of water = density x volume
Mass of water = 1000 kg/m³ x 2500 L
Mass of water = 2500 kg
Now we can calculate the potential energy:
Potential energy = 2500 kg x 9.8 m/s² x 12.0 m
Potential energy = 294,000 J
The potential energy of the tank of water with respect to the basement can be calculated in a similar way. We can first calculate the height of the tank with respect to the basement:
Height of tank with respect to basement = 12.0 m + 4.0 m
Height of tank with respect to basement = 16.0 m
Now we can calculate the potential energy using the same formula as before:
Potential energy = 2500 kg x 9.8 m/s² x 16.0 m
Potential energy = 392,000 J
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In which direction will heat naturally flow?
from an object at 40°C to an object at 20°C
from an object at 40°C to an object at 40°C
from an object at 40°C to an object at 80°C
from an object at 0°C to an object at 100°C
Heat will naturally flow from an object at 40°C to an object at 20°C.
What is heat?Heat is described as the energy that is transferred from one body to another as the result of a difference in temperature.
Heat will naturally flow from an object at a higher temperature to an object at a lower temperature. So in the above scenario, heat will naturally flow from an object at 40°C to an object at 20°C.
In conclusion, the basic concept of thermodynamics states that heat will flow spontaneously from a higher-temperature body to a lower-temperature body in order to equalize the temperatures of the two bodies.
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Blood flows through a major artery at 1.2 m/s over a distance of 0.50m then at 0.70 m/s for another 0.50 m through a smaller artery.
Is the average speed of the blood 0.95 m/s greater than 0.95 m/s or less than 0.95 m/s (part a)
Verify your answer to Part A by calculating the average speed.
(part b)
The average speed of the blood is less than 0.95 m/s and the average speed is 0.884 m/s.
What is average speed?
Average speed is a measure of the rate of change in position of an object over a certain period of time. It is calculated by dividing the total distance traveled by the total time taken. In other words, it is the rate at which an object covers a given distance. Average speed is useful in determining the efficiency of a vehicle, or of a person, in covering a particular distance. For example, if a person drives for 2 hours and travels a total distance of 200 kilometers, the average speed of the body is 100 km/hr (200km / 2 hrs).
The average speed is,
[tex]V_{avg} = \frac{d_{1}+ d_{2} }{\frac{d_{1} }{V_{1} }+ \frac{d_{2} }{V_{2} } }[/tex]
[tex]= \frac{0.50m + 0.50m}{\frac{0.50m}{1.2m/s}+\frac{0.50m}{0.70m/s} }[/tex]
= 0.884 m/s
Due to the average speed is 0.884 m/s the average speed of the blood becomes less than 0.95 m/s.
Therefore, the average speed of the blood is less than 0.95 m/s and the average speed is 0.884 m/s.
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(a) Is the electric field E in Gauss’s law, Int E*dA= Qencl/?o, created only by the charge Qencl? Explain. (b) Define gravitational flux in analogy to electric flux. Are there "sources" and "sinks" for gravitational field as there are for electric field? Discuss.
Answer:
A) Electric flux depends on the charge Q within and enclosed surface regardless of the shape of the surface - this concept is particularly useful for symmetric surfaces (centralized charge within a sphere) - field outside a uniform cylinder - whenever charges are symmetric with respect to the external environment.
B) Since the gravitational field has the same form as the electric field - F = G M1 M2 / R^2 the same arguments apply to the gravitational field - Field lines passing out thru an enclosed surface are sources of field whereas field lines passing inward thru an enclosed surface are sinks for the field
While an object is in projectile motion (with upward being positive) with no air resistance.
Its vertical acceleration is equal to -g, while the horizontal component of its velocity is unchanged.
This is due to the projectile's dual components of vertical and horizontal velocities. But when the item moves, its vertical component of velocity changes but its horizontal component does not.
The projectile's horizontal component of velocity remains constant, therefore it only has a vertical component of acceleration and no horizontal component. The horizontal component of velocity remains unchanged as a result.
Since the only vertical force acting on the object is the weight, the vertical component of acceleration is equal to -g.
Therefore, the vertical component of its acceleration is equal to -g, while the horizontal component of its velocity remains constant.
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Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person?
The magnitude of the charges must be 1.67 x 10⁻⁵ C in order for the force exerted by them to be comparable to the weight of a 50 kilogram individual.
The force of attraction between two point charges Q1 and Q2 separated by a distance r is given by Coulomb's law:
[tex]F = k * (Q1 * Q2) / r^2[/tex]
here,
k is Coulomb constant, value is [tex]9.0 * 10^9 Nm^2/C^2[/tex].
To find the magnitude of the charges such that the force between them equals the weight of a 50 kg person, we need to set the force equal to the weight of the person:
F = m * g
here,
m is mass of the person and
g is the acceleration gravity, value [tex]9.81 m/s^2[/tex].
Reserving values:-
[tex]m * g = k * (Q1 * Q2) / r^2[/tex]
We know that Q1 and Q2 are equal, so we can write Q1 = Q2 = Q. Reserving equation above:-
[tex]m * g = k * Q^2 / r^2[/tex]
Solving for Q:-
[tex]Q = \sqrt{[(m * g * r^2) / k]}[/tex]
Reserving values:-
[tex]Q = \sqrt{x} \sqrt{[(50 kg * 9.81 m/s^2 * (1.0 m)^2) / (9.0 x 10^9 Nm^2/C^2)]}[/tex]
Simplifying and evaluating:-
[tex]Q = 1.67 * 10^-^5 C[/tex]
Therefore, the magnitude of each of the charges should be approximately [tex]1.67 * 10^-^5 C[/tex].
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A ball strikes the floor for 0.0105 s and experiences a change in momentum of 1.52 kg·m/s. What is the force experienced by the ball?*
A.1.60 N
b. 144.76 N
c.23.82 N
d. 0.016 N
Answer: B is right
Explanation: Change in Momentum / Time Therefore, the force experienced by the ball is: Force = 1.52 kg·m/s / 0.0105 s Force = 144.76 N Answer: B. 144.76 N
a Charge Q1 = +8 x 10^-6C, Q2 = -5 x 10^-6C, and the Coulomb force between the two charges is .2N. Calculate the distance between these charges.
The distance between the two charges is approximately 0.0134 meters.
The Coulomb force between two point charges is given by Coulomb's Law,
[tex]F = \dfrac{k Q_1 Q_2}{r^2}[/tex]
where k is Coulomb's constant, Q1 and Q2 are the magnitudes of the two charges, and r is the distance between them.
Q1 = +8 x 10^-6C, Q2 = -5 x 10^-6C, and F = 0.2 N.
k = 9 x 10^9 N m^2/C^2.
Substituting these values into Coulomb's Law,
[tex]0.2 N = \dfrac{9 \times 10^9 \times 8 \times 10^{-6} \times -5 \times 10^{-6}}{ r^2}[/tex]
Multiplying both sides by r^2, we get:
r^2 = (3.6 x 10^-5 N) / 0.2
r^2 = 1.8 x 10^-4 m^2
r ≈ 0.0134 m
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Microevolution three mechanisms that cause allelic frequencies to change in a population: gene flow, genetic drift, natural selection bottleneck effect founder effect population gene pool stabilizing, directional and disruptive selection hardy-weinberg equilibrium five conditions that must be met in order for population to be in hardy-weinberg equilibrium adptive evolution relative fitness sexual selection sexual dimorphism intrasexual selection intersexual selection neutral variation balancing selection heterozygote advantage hardy-weinberg problems
Microevolution refers to the evolution occurring at species-level involves three mechanisms that cause allelic frequencies to change in a population: gene flow, genetic drift, and natural selection.
Changes in the environment can affect population gene pools on both a small- and large-scale. Microevolution is the process of population-level changes in allele frequency. Some alterations take place at the species level or lower. There are hence variations in allele frequencies between or within groups.
Natural selection is one of the mechanisms of microevolution. It serves as an editor for allele frequency in populations to determine whether individuals with particular features have a higher or lower chance of surviving and procreating. Populations' gene pools can occasionally shift as a result of individuals leaving or entering the community. This transfer of alleles between populations is referred to as gene flow. Genes can "flow" from one area to another just like water does in a river.
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An FM radio station broadcasts at 9.23x10^7 Hz. Given that the radio waves travel at 3.00x10^8 m/s, what is the wavelength of these waves?
If a radio station broadcasts at 9.23 x 10⁷Hz and the velocity of the waves is 3 x 10⁸m/s, the wavelength of these waves is 3.25m.
How to find the wavelength of radio waves?According to the question,
Frequency of the FM radio = 9.23 x 10⁷Hz
Velocity of the waves = 3 x 10⁸m/s
The wavelength of the wave =?
To find the wavelength of the wave, we conclude the velocity equation;
Velocity = frequency x wavelength.
Since to find unknown is the wavelength, we have to solve for it:
3 x 10⁸ = 9.23 x 10⁷ x wavelength
wavelength = 3 x 10⁸/ 9.23 x 10⁷
wavelength = 3.25m
Therefore, the wavelength of these waves is 3.25m.
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A particle moves in a straight line such that its displacement, x meters, from a fixed point 0 on the line at time t seconds is given by x = (t — 1)^3 -2t^2 +1 .
(a) Find the time when the particle is instantaneously at rest.
(b) Find the displacement of the particle from O when t=6 s.
(c) Find the total distance travelled during the first 6 seconds of its motion.
(a) The particle is instantaneously at rest at time, t = 3/2 seconds.
(b) The displacement of the particle is 54 meters from the fixed point O at t = 6 seconds.
(c) The total distance travelled by the particle during the first 6 seconds of its motion is 52 meters.
What is the time when the particle is instantaneously at rest?To find the time when the particle is instantaneously at rest, we need to find the time when its velocity is zero. The velocity of the particle can be found by taking the derivative of its displacement with respect to time, which gives us the velocity function, v(t) = d(x)/dt.
Taking the derivative of x = (t — 1)^3 -2t^2 +1 with respect to time t, we get:
v(t) = 3(t - 1)^2 - 4t
To find when the velocity is zero, we set v(t) = 0 and solve for t:
0 = 3(t - 1)^2 - 4t
3(t - 1)^2 = 4t
t = (3(t - 1)^2)/4
t = (3(t - 1)^2)/4
Solving this equation, we find t = 3/2 seconds. So, the particle is instantaneously at rest at t = 3/2 seconds.
To find the displacement of the particle from O when t=6 s, we simply substitute t = 6 into the displacement function:
x = (6 - 1)^3 - 2 * 6^2 + 1
x = 125 - 72 + 1
x = 54 meters
To find the total distance travelled during the first 6 seconds of its motion, we need to find the definite integral of the velocity function over the interval [0, 6].
x(t) = ∫v(t) dt
x(t) = ∫(3(t - 1)^2 - 4t) dt
x(t) = (t - 1)^3 - 2t^2 + C
where C is the constant of integration. We can determine the value of C by using the initial condition that x(0) = 0:
0 = 0 - 2 * 0^2 + C
C = 0
So, x(t) = (t - 1)^3 - 2t^2.
Finally, to find the total distance travelled during the first 6 seconds of its motion, we evaluate the definite integral of x(t) from 0 to 6:
d = x(6) - x(0)
d = [(6 - 1)^3 - 2 * 6^2] - [(0 - 1)^3 - 2 * 0^2]
d = 125 - 72 - 1
d = 52 meters
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You are driving through town at 16 m/s when suddenly a car backs out of a driveway in front of you. You apply the brakes and begin decelerating at 3.5 m/s2
Find your speed after braking half the time found in part A.
(answer for part a- t=4.6s)
The time is 5s.
In this problem, the observer is driving through town at
vi =16 m/s applies the brakes and begin decelerating with }a=−3.2 m/s²
We calculate the time for the vehicle to stop, and the speed after half the stopping time.
We use the velocity-time equation of the vehicle. When the vehicle stops, the velocity is
vf ⟹ =vi +at
T = Vf−vi
= 0−16 m/s / −3.2 m/s²
= 5.0 s
What is time?
Time is the ongoing pattern of existence and things that happen in what seems to be an unbreakable succession from the past through the present and into the future.It is a constituent quantity of many measurements that are used to compare the lengths of events or the gaps between them, to compare the sequence of occurrences, and to measure the rates at which certain quantities in the physical world or in conscious experience change.In addition to the three spatial dimensions, time is frequently considered a fourth dimension.To know more about time, click the link given below:
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A battery is connected to an electrical circuit. During each second, 2.3 coulombs of charge pass through the battery when the switch is closed. The battery supplies energy to each coulomb of charge at a rate of 4.2J C^-1. Take 1 C = 6.24 x 10^18 electrons
State the potential difference across the battery
Answer:
The potential difference across the battery can be calculated using the equation:
Potential difference (V) = Energy supplied (J) / Charge (C)
Energy supplied during each second = 2.3 coulombs * 4.2 J/C = 9.66 J
Therefore, the potential difference across the battery would be:
Potential difference (V) = 9.66 J / 2.3 C = 4.2 V
So the potential difference across the battery is 4.2 volts.
A bag of cookies 6 oatmeal cookies, 5 pecan cookies and 1 peanut butter cookies. Mary selects 2 cookies at random. What is the probability that the selected 2 oatmeal cookies?.
The probability that the selection is made of 2 oatmeal cookies are 1/6.
As per given data in the question:
Oatmeal cookies - 6
Pecan Cookies - 5
Peanut butter cookies - 1
Total cookies in the jar - 12
The probability that the selection is of 2 oatmeal cookies, it is as follows:
P (oatmeal cookies) = 2/12 = 1/6
Probability deals with the likelihood of an event or phenomena occurring and is quantified as a number between 0 and 1 inclusive, where 0 indicates an impossible chance of occurrence and 1 denotes the certain probable outcome of an event.
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The graph depicts the motion of two objects. Which statement BEST describes the acceleration of the two objects?
Responses
A Acceleration 1 - no acceleration. Acceleration 2 - speeds up and slows down.Acceleration 1 - no acceleration. Acceleration 2 - speeds up and slows down.
B Acceleration 1 - no acceleration. Acceleration 2 - negative acceleration.Acceleration 1 - no acceleration. Acceleration 2 - negative acceleration.
C Acceleration 1 - positive acceleration. Acceleration 2 - negative acceleration.Acceleration 1 - positive acceleration. Acceleration 2 - negative acceleration.
D Acceleration 1 - constant acceleration. Acceleration 2 - varied acceleration.
Acceleration 1 - constant acceleration. Acceleration 2 - varied acceleration. The correct option is D.
What is acceleration?Acceleration of any object is defined as the variation in the speed of the object with the variation of time. Acceleration is a vector term and to define it we require both the magnitude and the direction. The unit of acceleration can be m / sec², miles / sec², etc.
In a velocity-time graph, the acceleration corresponds to the slope of the curve.
In fact, acceleration is defined as the ratio between the change in velocity and the time interval:
a = Δv / Δt
However, in a velocity-time graph, corresponds to the y-variable increment (), while corresponds to the x-variable increment (). (). As a result, acceleration can also be expressed as,
a = Δy / Δx
For object 1, the slope is constant: this means that the acceleration is constant.
For object 2, the slope varies: this means that the acceleration varies as well.
The missing graph is attached with the answer below.
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The following table shows the distance from the sun of some unknown planets of equal mass.
Distance from Sun
Planet Distance from Sun
W 1.5 AU
X 0.723 AU
Which of the following best explains which planet revolves at a faster speed?
Planet X, because the sun pulls it with a greater force
Planet W, because the sun pulls it with a greater force
Planet W, because the gravitational force is weakened by distance
Planet X, because the gravitational force is strengthened by distance
(D was wrong, I'm taking the test again)
The correct answer is : Planet X, because the sun pulls it with a greater force
The speed at which a planet revolves around the sun is determined by its distance from the sun and the gravitational force between the planet and the sun. The closer a planet is to the sun, the stronger the gravitational force, and the faster it will orbit. Therefore, Planet X, which is closer to the sun than Planet W, will revolve around the sun at a faster speed, assuming that both planets have equal masses. Thus, the correct answer is "Planet X, because the gravitational force is strengthened by distance." The farther a planet is from the sun, the weaker the gravitational force, but this would result in a slower orbital speed, not a faster one.To know more about planets visit:
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Answer: A A A !!!!
Explanation: just did the test, got it right thx thx!!!
The momentum of an object is calculated by?
A.multiplying mass by acceleration.
B.dividing force by acceleration.
C.dividing mass by velocity.
D.multiplying mass by velocity.
D. Multiplying mass by velocity.
The momentum of an object is a measure of its motion and is defined as the product of its mass and velocity. It is a vector quantity, meaning it has both magnitude and direction.
The formula for momentum is given by p = mv, where p is the momentum, m is the mass of the object, and v is its velocity. So, the momentum of an object can be calculated by multiplying its mass by its velocity.
Option A is incorrect because momentum is not simply the product of mass and acceleration. Option B is incorrect because force is not directly related to momentum. Option C is incorrect because dividing mass by velocity does not give momentum, it gives the velocity of the object.
A cement block accidentally falls from rest from the ledge of a 84.9-m-high building. When the block is 16.6 m above the ground, a man, 1.90 m tall, looks up and notices that the block is directly above him. How much time, at most, does the man have to get out of the way?
The man has at most 3.55 s to get out of the way.
What is kinematic equations?
Kinematics can be defined as a subfield of physics developed in classical mechanics that describes the motion of points, bodies and systems of bodies without considering the forces that cause them to move.
We can solve this problem using kinematic equations.
First, we can find the time it takes for the block to fall from a height of 84.9 m using the formula:
y = 1/2 * g * t^2
where
y is the distance fallen (84.9 m)g is the acceleration due to gravity (9.81 m/s^2) t is the timeRearranging this equation, we get:
t = sqrt(2y/g) = sqrt(2 * 84.9 m / 9.81 m/s^2) = 4.09 s (to two significant figures)
So the block will hit the ground after 4.09 s of falling.
Next, we can find the time it takes for the block to fall from a height of 16.6 m using the same formula:
t = sqrt(2y/g) = sqrt(2 * 16.6 m / 9.81 m/s^2) = 1.41 s (to two significant figures)
So the block will take 1.41 s to fall from a height of 16.6 m to the ground.
The man has to get out of the way before the block falls the remaining distance of (84.9 - 16.6) = 68.3 m. We can find the time it takes for the block to fall this distance using the same formula:
t = sqrt(2y/g) = sqrt(2 * 68.3 m / 9.81 m/s^2) = 3.55 s (to two significant figures)
Therefore, the man has at most 3.55 s to get out of the way.
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At the end of the day, you remember that pulling up on an object will make it easier to slide the object. Using this knowledge you decide to move your 3000 N Grand Piano using a rope. You pull the rope so that it provides an upward force of 900 N and a horizontal force of 1600 N. What is the coefficient of kinetic friction if the piano is being bulled at a constant speed?
The coefficient of kinetic friction is approximately 0.533.
What is the coefficient of kinetic friction?
To find the coefficient of kinetic friction, we can use the equation of the force of friction, which is given by:
f_friction = friction_coefficient x f_norm
where;
f_friction is the force of friction, friction_coefficient is the coefficient of kinetic friction, and f_norm is the normal force.Since the piano is being pulled at a constant speed, the net force on the piano must be zero, which means that the sum of the forces must be equal to zero:
f_net = f_horizontal - f_friction = 0
friction_coefficient = f_friction / f_norm
= (f_horizontal) / (f_norm)
= (1600 N) / (3000 N) = 0.533
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An old-fashioned single-play vinyl record rotates on a turntable at 45.0 rpm. What are (a) the angular velocity in rad/s and (b) the period of the motion? nand (h the period of the
The angular velocity in rad/s are 4.7124 rad/s and the period of the motion is 1.333s.
a) Find angular velocity
Given
45 rpm that is rotations per min converting it in to rad/s
we know that the angular displacement for one rotation is 2pi rad
45 rpm = 45*2pi/60
= 4.7124 rad/s
So,the angular velocity is W = 4.7124 rad/s
b) We have relation between the angular velocity and time period is
W = 2pi /T
T = 2pi/W
T = 2pi/4.7124 s
T = 1.333 s
Angular velocity is a physical quantity that describes the rate of change of the angular displacement of an object with respect to time. It is a vector quantity, and its direction is perpendicular to the plane in which the object is rotating. The magnitude of the angular velocity is given by the ratio of the angular displacement of the object to the time taken to complete the displacement. It is measured in radians per second (rad/s).
Angular velocity is an important concept in physics and is used in the study of rotational motion. It is used to calculate the centripetal force required to maintain circular motion and is also used to describe the motion of planets and other celestial bodies. In addition, angular velocity is used in engineering and mechanics to design and analyze rotating machines and devices.
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Where on the physical activity pyramid do sedentary activities belong? a. A b. B c. C d. D please select the best answer from the choices provided.
In the physical activity pyramid, sedentary activities belong to Level D.
The Physical Activity Pyramid is a graphic representation of the different types of physical activities that are recommended for a healthy lifestyle.
The pyramid is divided into four levels, with the most important activities at the bottom and the least important at the top. The greatest and most significant activities for healthy everyday life are at the bottom and the least healthy activities at the top, which you should only perform occasionally.
Sedentary activities, which are activities that involve little or no physical movement, belong at the top of the pyramid, in Level D.
Level D is the smallest section of the pyramid, and it represents activities that should be limited in order to maintain good health.
Hence, option D is the correct choice.
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The cart is given an initial push up the ramp. After this push, as the car moves up the ramp, the direction of the acceleration of the cart is_________the ramp. After ther turns around, and begins moving down the ramp, the direction of the acceleration of the cart is__________ eaches its highest point, the ramp. At the highest point the cart reaches on the ramp, when the cart momentarily comes to rest, the magnitude of the acceleration of the cart is_________O down, down, zeroO up, down, nonzeroO down, down, nonzeroO up, down, zero
The correct answers to the blanks are 1. UP ,2. UP and 3. ZERO
When the cart is initially given a push up the ramp, the direction of the acceleration of the cart is up the ramp. This is because the net force acting on the cart is directed up the ramp, in the same direction as the component of the gravitational force that is parallel to the ramp. As a result, the cart accelerates up the ramp in the same direction as the net force.
When the cart turns around and begins moving down the ramp, the direction of the acceleration of the cart is still up the ramp. This is because the component of the gravitational force that is parallel to the ramp is still directed down the ramp, but the net force acting on the cart is directed up the ramp due to the normal force exerted by the ramp on the cart. As a result, the cart accelerates down the ramp in the opposite direction to the net force, which is up the ramp.
At the highest point that the cart reaches on the ramp, when the cart momentarily comes to rest, the magnitude of the acceleration of the cart is zero. This is because at this point, the cart is at the highest point on the ramp and has stopped moving. As a result, the velocity of the cart is zero, and therefore the acceleration of the cart is also zero.
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