Examples of following forces mentioned -
Normal Force :- Book kept on the table , Girl standing on floor, ...infact every object experience a normal force in the universe.Applied Force :- this term literally means force responsible for the movements in the object or changes in the object , like throwing stones , playing ball , pushing an object , moving a pen from desk to chair..etc...Friction force :-Force responsible for the resistance in the flow of system's work , For example air resistance a type of obstruction experienced in air when a Paper ball is thrown from terrace of a society , Viscosity of honey is also an example of liquid friction / viscous drag...Sometimes friction is useful for the stability of universe. But some times its necessary. It is due to this force we walk without collapsing into the core of earth as earth is a market of gravitational field. To substantiate the field effect , friction is necessary to necessitate the life in planet. Rubbing of hands in winter season is also another example.To Know more about different forces -
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Three masses are connected as shown on a smooth horizontal surface.
(Take acceleration due to gravity as 9.8ms^-2)
a)Calculate the acceleration of the mass M3.
b)Calculate the tension in each string.
c)If the surface was not smooth describe how:
1.the acceleration of the system would be affected.
2.the tension in each string would be affected.
a) The acceleration of the mass M3 is 14.42 m/s².
b) The tension in each string. is : T₁ = 5119 N.
T₂= 7714 N.
And T₃ . = 12833 N.
c) If the surface was not smooth, there will be a frictional force which lessen both tension and acceleration of the system.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Let the acceleration of the system = a.
And the tension in each string is T₁ , T₂ and T₃ respectively.
Then for M₁ mass;
tension in string T₁ = M₁a
For M₂ mass:
tension in string T₂ = M₂ a
For M₃ mass:
tension in string T₃ - M₃g = M₃ a.
⇒T₃ = M₃g + M₃ a.
And T₃ = T₁ + T₂.
⇒M₃g + M₃ a. = M₂ a + M₁a
⇒ a = M₃g/( M₁ +M₂ -M₃)
= 530× 9.8/ (355+535-530)
= 14.42 m/s².
Then, the tension in each string is T₁ = 355 * 14.42 N = 5119 N.
T₂ = 535×9.8 N = 7714 N.
And T₃ = T₁ + T₂ = 5119 N +7714 N. = 12833 N.
If the surface was not smooth, there will be a frictional force which lessen both tension and acceleration of the system.
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What role does fiction play in sport of your choice? Collect one picture of that sport in action where friction either supporting it or opposing it
a spiral spring loaded with a piece of metal extends by 9.4cm. when the metal is fully immersed in water, the spring extends by 3.5cm. assuming Hooke's law is obeyed, calculate the relative density of the metal
The relative density of the metal that is on a spiral spring which extends 9.4 cm in air and 3.5 cm in water is 1.59
RD = Weight of body in air / Upthrust
RD = Relative density
F = - k x
F = Spring force
k = Spring constant
x = Displacement
RD = - k ( 9.4 ) / - k ( 9.4 - 3.5 )
RD = 9.4 / 5.9
RD = 1.59
Relative density is the ratio of density of the substance to the density of the reference material. Density is the ratio of mass to volume. The unit of density is kg / m³. Relative density has no unit since it is density divided by density.
Therefore, the relative density of the metal is 1.59
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I'm stuck on b(i), because I don't understand what equation to use with what values.
Answer:
Apparently, it takes 3 * 5E-3 sec to travel from D to G
The distance is given as .68 m
V = S / t = .68 m / (3 * 5E-3 s) = 45 m/s
An object with a mass of 33g and a volume of 39cm^3 is placed in a liquid with a density of 1.25 g/cm^3. Find the volume of the part of the object that is NOT submerged in the liquid. Give your answer in cm^3 and with 3 significant figures.
Answer:
V₂ = 12.6 cm³ - volume of the NOT immersed part:
Explanation:
Given:
m = 33 g
V = 39 cm³
ρ = 1.25 g/cm³
____________
V₂ - ?
Gravity:
F = m·g
Strength of Archimedes:
Fa = ρ·g·V₁
V1 - the volume of the submerged
The object is floating, so:
F = Fa
m·g = ρ·g·V₁
m = ρ·V₁
V₁ = m / ρ = 33 / 1.25 ≈ 26,4 cm³
V₂ - volume of the NOT immersed part:
V₂ = V - V₁ = 39 - 26.4 = 12.6 cm³
A plane is flying to Minnesota with a velocity of 373.52 km/h, N. The plane encounters a crosswind with a velocity of 64.90 km/h, W. What is the magnitude of the resultant velocity of the plane?
Answer:
379.12 km/h N 9.86° W
Explanation:
You want to know the resultant velocity when a plane's velocity of 373.52 km/h N is modified by a crosswind at 64.90 km/h W.
Vector sumIn (N, E) coordinates, the sum of the velocities is ...
(373.52, 0) +(0, -64.90) = (373.52, -64.90)
The magnitude of this vector is ...
|v| = √(373.52² +64.90²) ≈ 379.12 . . . . km/h
The direction will be west of north by the angle ...
θ = arctan(-64.90/373.52) ≈ -9.86° . . . . . . N = 0°, + = clockwise
The resultant velocity is 379.12 km/h N 9.86° W.
Pls draw me what a velocity time graph would look like : moving at a positive constant speed to then at rest? Thank you!!!
Answer:
See below
Explanation:
Here are a couple of options..... one where the object slows to a rest and the other where the object stops to a rest instantaneously
Which has the most momentum?
C: 150 g object at 5 m/s
D: 200 kg object at 2 m/s
A: 50 kg object at 5 m/s
B: 100 kg object at 10 m/s
Option D) 200 kg object at 2 m/s has the highest momentum.
What is momentum?
Momentum is calculated using Newtonian mechanics by multiplying an object's mass by its velocity.As a vector quantity with both a magnitude and a direction, it has both. Considering that an object's mass is m and its speed is v (also a vector quantity),Momentum formula, P = mv
p = momentum
m = mass \ velocity
The newton-second is a unit of measurement for momentum in the International System of Units (SI), and the kilogram metre per second (kg m/s) is its SI counterpart.
A) 50 kg object at 5 m/s
m = 50 kg
v = 5 m/s
Momentum, p = m x v
= 50 x 5
= 250 kg m/s
B) 100 kg object at 10 m/s
m = 100 kg
v = 10 m/s
Momentum, p = m x v
= 100 x 10
= 1000 kg m/s
C) 150 g object at 5 m/s
m = 150 g
= 0.15 kg
v = 5 m/s
Momentum, p = m x v
= 0.15 x 5
= 0.75 kg m/s
D) 200 kg object at 2 m/s
m = 200 kg
v = 2 m/s
Momentum, p = m x v
= 200 x 2
= 400 kg m/s
Hence, Option B has the highest momentum.
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a sample of cube X is shown above. If it’s mass is 244.4 mg, what is its density in g/cm^3
The density of the cube is 1.1 g/cm³
What is density?Density is described as the substance's mass per unit of volume. Mathematically, density is defined as mass divided by volume: density (rho) =mass/ Volume where ρ is the density, m is the mass, and V is the volume.
mass of cube= 244.4mg
volume of cube = 222.2 cm³
density = mass/ volume
density = 244.4/ 222.2 cm³
density = 1.1 g/cm³
Density is essentially a measurement of how tightly matter is packed together. density is a unique physical property of a particular object.
In conclusion, the principle of density was discovered by the Greek scientist Archimedes.
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Interpret information to make judgment.
The teacher is showing the class an experiment using a radioactive source. She insists on these safety precautions
a) No students may sit in the front row
b) The radioactive source is kept in a lead box when not in use.
Explain why each of these precautions is important.
These precautions are important to avoid radiation effects. Lead is powerful in shielding nuclear substances because of its physical residence.
It is dense and difficult, which means it is able to block x-rays and gamma rays from penetrating thru the cloth. whilst these radioactive waves touch the steel, they collide with the lead atoms and get dispersed
Lock radioactive stock materials and sealed assets in a secured box or a secured storage vicinity when not in use. A stock fabric is a radioactive material as provided by using the vendor and does no longer include material withdrawn from the original inventory for experimental use.
You must generally hold radioactive resources, along with any radioactive waste that's in the garage, in suitable boxes internal an appropriate store to defend against unintended harm or loss and to guard employees and the majority.
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Find the resultant force of 16N and the force of 25N acting at the same point on an object if the Force at : (1) In the same direction in the same line. (11) In the opposite direction but in the same straight line. (111) At right angles to each other.
1 ) Resultant force if the forces act in the same direction = 41 N
2 ) Resultant force if the forces act in the opposite direction = 9 N
3 ) Resultant force if the forces act at right angles to each other = 29.68 N
F1 = 16 N
F2 = 25 N
1 ) If the forces act in the same direction,
F = F1 + F2
F = 16 + 25
F = 41 N
2 ) If the forces act in the opposite direction,
F = F2 - F1
F = 25 - 16
F = 9 N
3 ) If the forces act at right angles to each other,
F² = F1² + F2²
F² = 16² + 25²
F² = 256 + 625
F² = 881
F = 29.68 N
Therefore,
1 ) F = 41 N
2 ) F = 9 N
3 ) F = 29.68 N
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In Graph C above, which line(s) shows an object that has a constant
velocity?
Answer:
it's D that has a constant velocity
A car is initially moving at 10.5 m/s and accelerates uniformly to reach a speed of 21.7 m/s in 4.34 s. How far did the car move during this
acceleration?
The care travelled a distance of 69.87 m.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. SI unit of acceleration is meter/second² (m/s²).
Given parameters:
Initial velocity of the car; u = 10.5 m/s.
Final velocity of the car; v = 21.7 m/s.
Time; t = 4.34 s.
The acceleration of the moving car; a = (Final velocity of the car - Initial velocity of the car)/time
= ( 21.7 m/s - 10.5 m/s)/4.34 s.
= 2.58 m/s².
Hence, the car move a distance during this acceleration; s = ut +1/2 at²
= 10.5×4.34 + 1/2 × 2.58×4.34² m.
= 69.87 m.
Hence, the car move a distance of 69.87 m during this acceleration.
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A car of mass 500 kg is moving at a speed of 1.2m/s. A man pushes the car increasing the speed to 2 m/s. How much work did the man do
Answer:
Work:
A = 640 J
Explanation:
Given:
m = 500 kg
V₁ = 1.2 m/s
V₂ = 2.0 m/s
____________
A - ?
The work is equal to the change in the kinetic energy of the car:
A = Δ Wk
A = m·V₂² / 2 - m·V₁² / 2
A = (m/2)·(V₂² - V₁²)
A = (500/2)·(2² - 1.2²) = 640 J
Please help! I don't understand how to do this!
A babysitter pushing a stroller starts from rest and accelerates uniformly at a rate of 0.778 m/s^2. What is the velocity of the stroller after it has traveled 5.54 m?
A babysitter pushing a stroller starts from rest and accelerates uniformly at a rate of 0.778 m/s^2. The velocity of the stroller after it has traveled 5.54 m will be 2.94 m/s
acceleration = 0.778 [tex]m/s^{2}[/tex]
distance = 5.54 m
initial velocity = 0
velocity of the stroller after it has traveled 5.54 m = ?
2as = [tex]v^{2} - u^{2}[/tex]
2 * 0.778 * 5.54 = [tex]v^{2}[/tex] - 0
v = 2.94 m/s
The velocity of the stroller after it has traveled 5.54 m will be 2.94 m/s
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Brooke is learning about electronic devices that use electric current to encode information. She learns that when a person speaks into the microphone of a telephone, the sound wave generated by the person’s voice is changed into an electronic signal. This electronic signal is then transmitted to another telephone where it is converted back to a sound wave so the other person can hear the voice. The sound wave is encoded by varying the voltage of the electronic signal. Brooke learns that the voltage can be changed in two ways, resulting in two types of electronic signals: analog and digital. Figure 1 and Figure 2 represent these two types of signals.
Identify the type of signal represented by each figure. Explain your reasoning.
The signals in this problem are classified as follows:
Figure 1: Digital signal.Figure 2: Analog signal.What are analog and digital signals?Analog signals are signals that are continuous in both domain and range, meaning that it can assume decimal values, hence it's graph is represented by a continuous curve.
Digital signals are signals that are discrete in both domain and range, meaning that it assumes only integer values, hence it's graph is composed by pulses.
Hence the classification of the signals for each figure in this problem are given as follows:
Figure 1: Digital signal, as the graph is composed only by pulses.Figure 2: Analog signal, as the graph is represented by the continuous and oscillating curve.More can be learned about analog and digital signals at https://brainly.com/question/22858440
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16) What is the acceleration of the ball on its way up?
a) 0m/s
b) 8m/s
c) -9.81m/s^2
d) +9.81m/s
The acceleration of the ball on it way up is -9.81m/s².
The correct option is C)
What is acceleration?
This is the rate of change of velocity with respect to time. The speed and direction of the accelerating object are also very important. It unit is meters per second square, m/s².
What is Gravity?
This is the force that pulls a body toward the center of the earth. This force causes objects to fall freely. This free-falling object has an acceleration of 9.8m/s downward the earth. This is called acceleration gravity.
What is velocity?
This refers to the speed at which an object moves in a given direction. It unit is meters per second, m/s.
Recall that the direction of motion is assumed to be the positive direction. Other parameters depend on the direction of motion. Hence for upward acceleration, the direction of motion is positive but the acceleration due to gravity is negative because the direction is downwards.
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function of a transformer in electrical circuits
Explanation:
There two types of transformers which are mainly stepup and step down transformers
the former is used for increasing voltage while the latter is used for reducing voltage
Move over Jeff Bezos, this invention is about to make you the richest person in the world. You have just invented the OyOy (that's YoYo spelled backwards). It is the very latest in home safety and so easy to use!
If your building is on fire, simply reach out and grab the cord on the OyOy and you will be lowered safely toward the ground at a low velocity. The OyOy has a total mass M = 95.0 kg and is shaped like a cylinder of radius R = 0.940 meters. The secret to the operation of the OyOy is its patented shaft whose radius is only r = 0.0900 meters. The cord is wound around the small shaft and this is the secret to your low velocity.
We will use the approximation that the shaft is of negligible mass compared to the total. This means that you can treat the entire OyOy as though it is a solid cylinder with mass M and radius R. Imagine that a customer of mass m = 78.5 kg is using the OyOy and begins his decent from an initial height of y0 = 12.55 meters.
Find velocity of customer at ground.
Answer: The correct answer is 144.716
Explanation: This is the correct answer because the velocity of the customer at ground is higher than it should be
what happens to the reflection when it hits the triangular prisms? the reflection is from air to glass. critical angle=42° please help me i need it right now:(
Answer: TIR (total internal reflection) occurs
Explanation: TIR occurs because the angle of refraction reaches a 90-degree angle before the angle of incidence reaches a 90-degree angle. The only way for the angle of refraction to be greater than the angle of incidence is for light to bend away from the normal. Since light only bends away from the normal when passing from a more dense medium into a less dense medium, then this would be a necessary condition for total internal reflection.
Honey is a technology company that provides online coupons to its subscribers. Honey's analytics staff has developed a classification method to predict whether a customer who has been sent a coupon will apply the coupon toward a purchase. For a sample of customers, the following table lists the classification model's estimated coupon usage probability for a customer. For this particular campaign, suppose that when a customer uses a coupon, Honey receives $1 in revenue from the product sponsor. To target the customer with the coupon offer, Honey incurs a cost of $0.05. Honey will offer a customer a coupon as long as the expected profit of doing so is positive. Using the equation
Expected Profit of Coupon Offer = P(coupon used) × Profit if coupon used + (1 - P(coupon used)) × Profit if coupon not used
determine which customers should be sent the coupon.
Customer Probability of Using Coupon
1 0.44
2 0.34
3 0.24
4 0.11
5 0.06
Determine the expected profit for each customer. Round your answers to the nearest cent. Enter negative value as negative number, if any.
Customer Expected Profit
1 $
2 $
3 $
4 $
5 $
The expected profit is positive for customers (Select your answer: 2 and 3, 4 and 5, 1, 2, and 33, 4, and 5, 1, 2, 3, and 4, 1, 2, 3, and 5, 2, 3, 4, and 5, 1, 2, 3, 4, and 5) so these customers (Select your answer: should be offered or should not be offered) the coupon.
The expected profit is positive for the customers 1, 2, 3, 4, 5.
What is expected profit?This is the term that is used to refer to the gain that would be expected to be gotten based on the fact that a person has engaged in a business.
We have 1 - 0.05 = 0.95 profit if the coupon is used
-0.05 is the profit if the coupon is not used
for consumer 1
the probability = 0.44
expected profit = 0.44 x 0.95 - 0.05 x 0.56
= 0.418 - 0.028
= 0.39
for consumer 2
the probability = 0.34
expected profit = 0.34 x 0.95 - 0.05 x 0.66
= 0.323 - 0.033
= 0.29
For consumer 3
the probability = 0.24
expected profit = 0.24 x 0.95 - 0.05 x 0.76
= 0.228 - 0.038
= 0.19
For consumer 4
the probability = 0.11
expected profit = 0.11 x 0.95 - 0.05 x 0.89
= 0.1045 - 0.0445
= 0.06
For consumer 5
the probability = 0.06
expected profit = 0.06 x 0.95 - 0.05 x 0.94
= 0.057 - 0.047
= 0.01
The expected profits can be listed as:
0.390.290.190.060.01The expected profits are positive for all of 1, 2, 3, 4, and 5, hence these customers can purchase the coupon.
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Does Monera move?
20 points
Answer:
Prokaryotic Bacteria
Explanation:
A student is performing bomb calorimetry for a combustion reaction. The bomb calorimeter normally holds 5 L of water with a heat capacity of 4.184 J/g•°C. However, the student misread the directions and used 6 L of ethanol which has a heat capacity of 2.46 J/g•°C. If the student calculates the energy released by the reaction assuming it was 5 L of water, what will be the difference between the actual energy of the reaction and the calculated energy? Note: the densities of ethanol and water under normal conditions are 0.8 g/mL and 1.0 g/mL, respectively.
The difference between the actual heat energy of the reaction and the calculated heat energy is 9092ΔT.
What is the heat energy released if 6 L of are used for a combustion reaction?The heat energy released if 6 L is used for a combustion reaction is calculated as follows:
Heat change = mcΔTwhere;
m is massc is the specific heat capacity ΔT is temperature changewhen 6.0 L of ethanol was used;
Mass of ethanol = volume * density
The volume of ethanol = 6.0 L or 6000 mL
Mass of ethanol = 6000 * 0.8
Mass of ethanol = 4800 g
Heat change = 4800 * 2.46 * ΔT
Heat change = 11808ΔT
If 5.0 L of water was used:
Mass of ethanol = volume * density
The volume of ethanol = 5.0 L or 6000 mL
Mass of water = 5000 * 1.0
Mass of ethanol = 5000 g
Heat change = 5000 * 4.18 * ΔT
Heat change = 20900ΔT
Heat difference = 20900ΔT - 11808ΔT
Heat difference = 9092ΔT
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A soccer coach is working with a device that measures the velocity of a soccer ball after it has
been kicked.
Which units should the coach use for velocity?
Choose 1 answer:
meters per second
kilograms
meters
meters per second
What is Velocity?
The pace at which an object's position changes in relation to a frame of reference and time is what is meant by velocity. Although it may appear sophisticated, velocity is just the act of moving quickly in one direction. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction. Its SI equivalent is the meter per second (ms-1). A body is considered to be accelerating if the magnitude or direction of its velocity changes.
Therefore, it will measured in meters per second.
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A 50.0-kilogram cheetah has a kinetic energy of 18000J How fast is the cheetah running ? ( Hint : Rearrange the equation to solve for v .)
I found that people say it’s 36 but there is no explanation for it
Answer:
Explanation:
here take kinetic energy =1/2×m×v²
m=50.0-kilogram (given)
kinetic energy=18000J (given)
now by taking the given values we get v²=(2×18000)/50
⇒v²=720
⇒v=26.8328m/s
done!
A 0.056 kg sample of an unknown substance is heated to 89.6 °C in a hot water tube. It is then quickly removed and placed into an insulated jar holding 188 ml of water initially at 132.8° F. The final equilibrium temperature of the system is 67° C. What is the specific heat of this unknown substance?
The specific heat of the unknown substance is 6.84 J/gºC
How do I determine the specific heat capacity?First, we shall convert 132.8° F to ° C. Thisis illustrated below:
Temperature (° F) = 132.8 ° FTemperature (° C) =?°C = (°F − 32) × 5/9
°C = (132.8 − 32) × 5/9
°C = 56 °C
Next, we shall determine the heat absorbed by the water. This is illustrated below:
Volume of water (V) = 188 mLDensity of water (d) = 1 g/mLMass of water (M) = dV = 1 × 188 = 188 gInitial temperature (T₁) = 56 °CFinal temperature (T₂) = 67 °CChange in temperature (ΔT) = 67 - 56 = 11 °CSpecific heat capacity of copper (C) = 4.184 J/gºC Heat absorbed (Q) =?Q = MCΔT
Q = 188 × 4.184 × 11
Q = 8652.512 J
Finally, we shall determine the specific heat capacity of the unknown metal. This can be obtained as follow:
Heat absorbed (Q) = 8652.512 JHeat released (Q) = -8652.512 JMass of unknown substance (M) = 0.056 kg = 56 gInitial temperature (T₁) = 89.6 °CFinal temperature (T₂) = 67 °CChange in temperature (ΔT) = 67 - 89.6 = -22.6 °CSpecific heat capacity of unknown substance (C) = ?Q = MCΔT
-8652.512 = 56 × C × -22.6
-8652.512 = C × -1265.6
Divide both sides by -1265.6
C = -8652.512 / -1265.6
C = 6.84 J/gºC
Thus, the specific heat capacity is 6.84 J/gºC
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What is the gravitational force acting on a 70.0 kg object standing on the Earth’s surface?
The radius of the earth is 6.371 x 106 m and the mass is 5.972 x 1024 kg.
The gravitational force acting on a 70.0 kg object standing on the Earth’s surface is 687.37N
What is gravitational force ?
A mass attracts a mass; the amount of the gravitational force is directly proportional to the masses of the two items and inversely proportional to the square of the distance between the two objects. Gravitational force is an attractive force that exists between all objects with mass.
The square of the distance between two things has an inverse relationship with the force of gravity, which depends directly on the masses of the two items. Accordingly, the force of gravity increases with mass but decreases as object distance increases.
F = G (M*m) /r2
F = 6.674×10−11 * 5.972*10^24*70/ (6.371*10^6)^2
= 687.37N
F = gravitational force
G = gravitational constant
m = mass of the body
M = mass of the earth
r = distance between them
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does the current stays the same throughout in a parallel circuit
Answer:
When the current splits, the current in each branch after the split adds up to the same as the current just before the split.
No, the current is not constant across the entire parallel circuit.
The circuit is known to be divided into branches by the parallel connection. Consequently, those branches are formed from the total current.
A parallel circuit may have one or more branches. The total current splits into its corresponding branches as soon as it enters one. Less current flows through the branches than across the entire system. The branch resistance affects the branch current values. In parallel circuits, the current is therefore different. All components in a parallel arrangement share the same voltage.
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Which one of the following is true of centrifugal force?
Centrifugal force is a fictional force.
Centrifugal force is a real force.
Centrifugal force pulls in a circular motion.
Centrifugal force causes objects moving in a circular path to move in.
Answer:
a is answer
Explanation:
centrifugal force, a fictitious force, peculiar to a particle moving on a circular path, that has the same magnitude and dimensions as the force that keeps the particle on its circular path (the centripetal force) but points in the opposite direction.
How might these traits change from individual to individual? (Hint: Do you think the newts are all exactly the same color or size?)
Newts hatch in water, but they spend the most of their lives on land, returning to water only for mating.
They have rough skin, are 8 inches long, and have stubby legs and fangs. In the Pacific Northwest, some of them are toxic.
Rough-skinned newts have brown skin on their backs and bright orange skin on their bellies. When frightened by predators, these newts coil their bodies and show off their orange necks and tails. Predators are warned to stay clear from this orange tint.
It is to be noted that none of the newts are the same traits that is color or size.
What are traits?A phenotypic trait (simply trait or character state) is a distinct variety of an organism's feature that is visible and quantifiable and manifests itself in an observable manner.
For example, eye color (green, blue, brown, and hazel) is a phenotypic feature that is passed down by polygenetic inheritance.
Height, wing length, and hair color are all phenotypes. Phenotypes also include observable traits that may be evaluated in the lab, such as hormone levels or blood cell counts.
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