phase of matter that consists of charged particles

The correct algebraic representation of the conservation of total mechanical energy is  1/2 Mv²  = 1/2 kx² + W_friction.

Mechanical energy is the sum of potential energy and kinetic energy. Mathematically,

Em = Ek + Ep

Where:

Em = mechanical energy

Ek = kinetic energy

Ep = potential energy

In this problem, the initial mechanical energy is due to the initial speed of the box. Hence,

Em_i = 1/2 Mv²

Where:

M = mass of the box

v = initial speed of the box.

Since the surface is not frictionless, there is some loss in the kinetic energy due to friction. We can write the remaining energy as:

remaining energy = Ek - W_friction

                              = 1/2 Mv² - W_friction

As the box hits the spring, the box stops, and therefore its kinetic energy is zero. The remaining energy (1/2 Mv² - W_friction) is transformed as the potential energy of the spring 1/2 kx². Them we have:

1/2 Mv² - W_friction = 1/2 kx²

or

1/2 Mv²  = 1/2 kx² + W_friction

Your question is incomplete. Most likely it was:

A box of mass M, sliding with an initial speed of v on a rough horizontal surface, runs into a fixed spring of elastic constant k, compressing it a distance x from its relaxed position before momentarily coming to rest. Which equation shows the correct algebraic representation of the conservation of total mechanical energy for this process? See the attached picture for the options.

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The electric field 4.2 m from the center of the terminal of a van de Graaff with an 8.20 mc charge, noting that the field is equivalent to that of a point charge at the center of the terminal is 4.18×10⁶ N/C.

An electric field is set up when a specific point charge lies at a particular point in the field. The electric field is obtained by the Coulomb's equation. So as the distance increases, the value of the electric field decreases.

The distance from the center of the terminal of a Van de Graff is r=4.2m. The electric charge is q=(8.20 mC × 10⁻³/1mC) =8.20 ×10⁻³ C. The electric field is E=kq/r², where E is the electric field and k is Coulomb's constant, k=9×10⁹ N.m²/C². So, E=(9×10⁹×8.20×10⁻³)/(4.2)² = 4.18×10⁶ N/C.

So the electric field at a distance of 4.2m is 4.18×10⁶ N/C.

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It is more fun to play when you have good sportsmanship is true.

Sportsmanship can be thought of as a persistent and largely constant trait or disposition that allows people to differ in how they are typically expected to respond in sporting situations.

Sportsmanship has been linked to interpersonal notions of treating others equally, retaining self-control when interacting with others, and respecting both authority figures and opponents. It mostly refers to virtues like fairness, self-control, courage, and perseverance.

The four components of sportsmanship—good form, the desire to triumph, equity, and fairness—are frequently displayed. For true sportsmanship to be demonstrated, a balance between all four components must be achieved.

Therefore, It is more fun to play when you have good sportsmanship is true.

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When the 1s orbitals of two hydrogen atoms combine to form a hydrogen molecule, The two molecular orbitals that form are known as s (sigma) and s* (sigma star) in Molecular Orbital Theory. The correct option is B.

Molecular orbitals are linear combinations of atomic orbitals that represent the electron distribution across two or more atoms.

The covalent bond refers to the mutual sharing of electrons between the two atoms in the molecule. The atomic orbitals overlap to form the molecular orbitals. The number of atomic orbitals and molecular orbitals formed will be the same. Hydrogen molecules are an example of molecular orbitals.  

You can only make two molecular orbitals from two 1s atomic orbitals. This is known as the First Principle. The two molecular orbitals that form are known as s (sigma = bonding) and s* (sigma star = anti-bonding) in Molecular Orbital Theory.

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(a) The minimum force vector F required to prevent the block from sliding down the wall is equal to the force of static friction, which is equal to the coefficient of static friction multiplied by the weight of the block. In this case, the minimum force vector F is:

F = μs * Fg = 0.430 * 81.9 N = 35.4 N

(b) The minimum force required to start the block moving up the wall is the force of kinetic friction which is typically less than the force of static friction. The force of kinetic friction is given by:

F = μk * Fg where μk is the coefficient of kinetic friction.

However, in this question, the coefficient of kinetic friction is not given. So, we can't calculate the minimum force required to start the block moving up the wall.

Battery powered cameras require a connection to a Sync Module and to Wi-Fi.

Define volt?

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A teleprinter channel with a 300 Hz bandwidth and an SNR of 6 dB has a channel capacity of 964.6 bps.

The channel capacity of a teleprinter channel is defined as the maximum amount of information that can be transmitted through the channel per unit time, in bits per second (bps). The channel capacity is determined by the channel's bandwidth and signal-to-noise ratio (SNR). The channel capacity of a teleprinter channel with a bandwidth of 300 Hz and an SNR of 6 dB can be calculated using the formula C = B log2(1 + S/N), where B is the bandwidth and S/N is the signal-to-noise ratio.

In this case, C = 300 log2(1 + 10^(6/10)) = 964.6 bps. This means that a teleprinter channel with a 300 Hz bandwidth and an SNR of 6 dB has a channel capacity of 964.6 bps. This channel capacity is sufficient for most teleprinter applications, as teleprinters typically have low data rates compared to other communication systems.

It is important to note that the channel capacity is a theoretical limit and assumes that the channel is used optimally. In practice, there may be factors such as errors and interference that reduce the actual data rate that can be achieved. Additionally, the channel capacity is dependent on the specific modulation and coding scheme used, and different schemes can result in different capacities for the same channel.

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The acceleration due to gravity in Chicago is [tex]9.803 m/s^2[/tex].

Let us assume that the acceleration due to gravity in Chicago is [tex]g[/tex] [tex]m/s^2[/tex].

It is given that,

The length of the second pendulum is [tex]l=0.9933 m[/tex].

It is known that,

The time period of a second pendulum is [tex]T=2s[/tex].

The time period of a simple pendulum, [tex]T=2\pi\sqrt{\frac{l}{g}}[/tex].

[tex]\Rightarrow (2)=2\pi \sqrt{\frac{0.9933}{g}}[/tex]

[tex]\Rightarrow \frac{2}{2\pi}=\sqrt{\frac{0.9933}{g}}[/tex]

[tex]\Rightarrow \frac{0.9933}{g}=(\frac{1}{\pi})^2[/tex]

[tex]\Rightarrow g=0.9933\times(\pi)^2[/tex]

[tex]\Rightarrow g=9.803 m/s^2[/tex]

Hence, the acceleration due to gravity in Chicago is [tex]9.803 m/s^2[/tex].

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It would be a challenge because Low or high gravity affects human physiology and physical capabilities, leading to muscle/bone loss in low gravity and injury in high gravity.

Gravity plays a significant role in human physiology and physical capabilities. In environments with low gravity, such as those in space, our bodies experience a weakening of muscles and bones due to a decrease in gravitational pull. On the other hand, in environments with high gravity, our bodies are subjected to more force, which can cause injury and impair our ability to move freely.

It is therefore essential to understand the implications of gravity on our bodies so that we can take the necessary precautions when engaging in activities that involve significant changes in gravitational forces.

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The change in the speed of the bicyclist and the bicycle is 4 meters per second.

Speed is the distance covered by an object in a particular time period. Speed is different from velocity, as it is a scalar quantity due to no direction. Whereas, velocity is a vector quantity due to both direction and magnitude.

Acceleration = Rate of change in velocity

Acceleration = Change in velocity/ Time taken

a = (v-u)/t

a = 1m/s²

t = 4 seconds

(v-u) = ΔV = ?

a = ΔV/ t

1 = ΔV/ 4

ΔV = 1×4

ΔV = 4 meters per second.

The change in the speed is 4 meter per second.

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The pressure difference is 562.1 Pa.

The pressure difference can be calculated using the equation:

[tex]ΔP = 1/2 * ρ * v^2[/tex], where [tex]ρ[/tex] is the air density and [tex]v[/tex] is the wind speed.

Air density at sea level = 1.225 kg/m^3.

To convert the wind speed from km/hr to m/s, divide by 3.6.

The pressure difference can then be calculated as follows:

[tex]ΔP = 1/2 * 1.225 kg/m^3 * (110 km/hr / 3.6)^2[/tex]

[tex]ΔP = 1/2 * 1.225 kg/m^3 * (30.56 m/s)^2[/tex]

[tex]ΔP = 1/2 * 1.225 kg/m^3 * 935.24 m^2/s^2[/tex]

[tex]ΔP = 562.1 Pa[/tex]

So, the pressure difference is approximately 562.1 Pa.

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The given question is incorrect. The correct question is given as:

A hurricane wind blows across a 5.90 mm ×× 13.2 mm flat roof at a speed of 110 km/hr. What is the pressure difference?

2mv is the magnitude of the impulse delivered by the wall to the ball.

What is Velocity ?

Velocity is a vector quantity that describes the rate of change of an object's position. It is equal to the displacement of an object divided by the time interval over which the displacement occurred. Velocity has both magnitude and direction, and its units are typically meters per second (m/s). The velocity of an object can change over time due to acceleration, and if an object is moving in a circular path, it also has a component of velocity perpendicular to its direction of motion, known as centripetal velocity.

Impulse = change in momentum

J = m(v - u)

  = m(v-(-v))

J = 2mv

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The electric field has the same magnitude at all three positions. On the x-axis, there are three equal positive charges: one at the origin, one at x=2m, and a third at x=4m.

On the x-axis, there are three equally sized positive charges: the first is at the origin, the second is at x = 2, and the third is at x = 4 m. a. x = 1 mb. x = 3 mc. x = 5 md. The vertices of an equilateral triangle have three positive charges of equal value, q. It is necessary to draw the resulting lines of force as in. Unlike charges attract one another while like charges repel one another. Both two positive and two negative charges repel one another as a result.

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The x component of an electric force is 6.41 × [tex]10^{-17}[/tex] N and the y component of an electric force is 3.20 x [tex]10^{-17}[/tex]N.

E=(400 )i+(200 )j is the electric field vector

q=1.602 × [tex]10^{-19}[/tex]C is the charge of a proton

The electric force is calculated using:

F = qE

and we substitute:

F =(1.602 × [tex]10^{-19}[/tex]C)× ((400)i+(200)j)

we distribute the charge to both components of the vector to obtain:

F= (6.41 × [tex]10^{-17}[/tex] N)i+ (3.20 x [tex]10^{-17}[/tex]N)j

(a) Vector parts are represented by unit vectors. The unit vector I in the "hat" convention stands in for a vector's x-component. In this instance, the x-component of our electric force vector is as follows:

F=6.41 x [tex]10^{-17}[/tex]N

(b) Similar to our earlier response, the unit vector typically denotes a vector's y-component. Therefore, the y-component of our electric force vector is:

F=3.20× [tex]10^{-17}[/tex]N

We observe that our vector components' directions, which are their magnitudes, are represented by the unit vectors (or the numbers aside from the hat unit vectors).

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The calculated value is .0522 N (-x direction as likes repel) (-x direction as likes repel)

There should be void nearby; (6) the pressure must be high enough so that significant damage occurs, that is the pressure should be above 10 atmospheres. Recommendations on how to avoid this kind of water hammer in both the design and the operation of the reactor system are made.

Taking a look at our equations first:

F = kQ1Q2/r2

k = 9*109

We may combine the force vectors using the Principle of Superposition to determine the net force acting on Q1.

F1 = F1,2 + F1,3

Solving each force we encounter

F1,2 = 9.10*109 x (-4.12 x 10-6 C) x (3.74 x 10-6 C) / (.580m)

Given that opposites attract, 2 = -.412 N (+x direction)

F1,3 is equal to 9*109 x (-4.12 x 10-6 C) x (-1.14 x 10-6 C) / (.900m)

2 = .0522 N (-x direction as likes repel) (-x direction as likes repel)

F1 = -.412 N + .0522 N = -.360 N

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The end A of the rod react when the (re)charged ball approaches it after a great many previous contacts with end A is strongly repelled (option 1)

When a charged body comes into contact with a neutral body, electrons flow from the charged body to the neutral body. This is referred to as the generation of static charges.

According to the given problem,

Assuming the conducting rod is not grounded, a negative charge accumulates on both ends of the rod. Charges, on the other hand, cannot stay at the ends and must be distributed throughout the length.

The charged ball will now be strongly repelled by the rod as it approaches it after many previous contacts with end A.

As a result, we can conclude that the rod's end A is strongly repelled away from the charged ball as it approaches it.

The question is incomplete, it should be:

How does end A of the rod react when the charged ball approaches it after a great many previous contacts with end A? Assume that the phrase "a great many" means that the total charge on the rod dominates any charge movement induced by the near presence of the charged ball.

It is strongly repelled.

It is strongly attracted.

It is weakly attracted.

It is weakly repelled.

It is neither attracted nor repelled.

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Explanation:

The interplanar spacing can be calculated using the Bragg's law equation:

nλ = 2d * sinθ, where n is the order of reflection, λ is the wavelength of x-rays, d is the interplanar spacing, and θ is the angle of incidence.

Given n = 1, λ = 0.0722 nm, and θ = 20.4°, we can solve for d:

d = nλ / (2 * sinθ) = (1 * 0.0722 nm) / (2 * sin 20.4°) = 0.282 nm.

True. Uranus is too faint to be seen without the aid of a telescope, and was not considered a planet by the ancient Greeks.

A telescope is an instrument used to observe distant objects by collecting and magnifying the visible light they emit. Telescopes are used to observe a wide variety of celestial objects, including stars, galaxies, planets, and comets. Telescopes come in a variety of shapes and sizes, ranging from small handheld models to huge observatories. Telescopes are also used in astronomy and other scientific fields to study the universe, as well as in military and law enforcement applications to survey and observe terrestrial objects. Telescopes are typically built with one or more curved mirrors or lenses which collect and focus the incoming light, allowing for a magnified image to be viewed. Many modern telescopes are equipped with sophisticated technology, such as digital cameras, computer-controlled tracking systems, and spectrographs to allow for detailed analysis and observation of distant objects.

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Answer:

Due to the increase in kinetic energy, the particles start vibrating more strongly with greater speed. The energy supplied by heat overcomes the intermolecular forces of attraction between the particles. As a result, the particles leave their mean position and break away from each other.

Explanation:

:)

The acceleration due to gravity in this orbit is 9.81 m/s2.

Gravity is a natural force of attraction that exists between any two objects with mass. It is the force that keeps us grounded to the Earth and causes objects to fall to the ground when released. Gravity is strongest at the surface of the Earth, and its effects diminish with distance. In the universe, gravity is responsible for maintaining the orbits of planets and stars, and for the formation of galaxies.

The acceleration due to gravity (g) at a distance r from the centre of the Earth is given by:
g = GM/r2
Where G is the gravitational constant and M is the mass of the Earth.
Therefore, the acceleration due to gravity at a distance re above the Earth's surface is given by:
g = GM/re2
= (6.67 x 10-11 Nm2/kg2) x (5.98 x 1024 kg) / (6.37 x 106 m)2
= 9.81 m/s2.
Therefore, the acceleration due to gravity in this orbit is 9.81 m/s2.

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Answer: 0.7 g/cm³

Explanation:

To find the density of a liquid, we can use the formula:

density = mass / volume

In this case, we know the mass of the empty cylinder is 185 g, and the mass of the cylinder plus the liquid is 465 g. So, we can find the mass of the liquid by subtracting the mass of the cylinder from the total mass:

mass of liquid = 465 g - 185 g = 280 g

We also know that the volume of the liquid is 400 cm³. So we can now find the density of the liquid:

density = 280 g / 400 cm³

density = 0.7 g/cm³

So, the density of the liquid is 0.7 g/cm³.

Centripetal acceleration is the process of having an item accelerate while altering its direction of motion.

The acceleration of a circularly moving item that is pointed in the direction of the circle's centre is known as centripetal acceleration.

When an object is travelling in a circle while being continuously drawn toward the centre, this is known as circular motion. Despite the fact that the object's speed may not vary, its velocity does. This kind of acceleration needs a net force, which is frequently supplied by the tension in a string or the gravitational pull of a planet.

A = v2/r, where r is the circle's radius and v is the object's velocity, can be used to compute centripetal acceleration. The magnitude of this acceleration is inversely proportional to the radius of the circle and is always in the direction of the centre of the circle.

In conclusion, an item accelerates if its velocity, either in speed or direction, changes. Centripetal acceleration is necessary for things travelling in circular motion because it causes the velocity to change direction without increasing or decreasing in speed.

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The average distance of a new planet on an orbit with a period of 14yrs from the sun is 5.8AU.

Kepler's Third Law states that P^2 = a^3 if the orbital radius (a) is given in astronomical units (1 AU being the average distance between the Earth and Sun) and the period (P) is given in years. where M is the mass of the central object in units of the Sun's mass and P is in Earth years, an is in AU, and a.

So, given the period of orbit is (P) = 14yrs

Let the distance = a

Then P^2 = a^3

14 x 14 = a^3

a = ∛196 = 5.8AU

Hence the average distance from sun is 5.8AU.

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The temperature is 57 degrees Fahrenheit while C is 15 degrees.

Water has a freezing point of 32° and a boiling point of 212° on the Fahrenheit temperature scale. The difference between the two is divided into 180 equal parts.

Your body temperature is usually around 37 °C. When your body temperature is 37.8°C or greater, you typically have a fever. You might feel hot, cold, or shaky. By taking your temperature using a thermometer, you can determine whether you have a fever.

The conversion of a degree in Fahrenheit to a degree in Celsius is represented by the Fahrenheit to Celsius formula. Fahrenheit to Celsius conversion formula: °C = [(°F-32)×5]/9

Given:

C = 15 degree

We know that,

F = 1.8C+32

F = 1.8*15+ 32

F = 27 +32

F = 57 degrees Fahrenheit

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Potential energy: According to the problem the person will reach a maximum height of 4.87 m.

Potential energy is the stored energy of an object due to its position relative to other objects. It is the energy an object has due to its position in a gravitational field, or due to its condition or arrangement.

The potential energy that is stored in the trampoline is equal to the work done by the person bouncing on it. Therefore, we can calculate the height that the person will reach by using the formula for work:
Work = Force x Distance
Since the mass of the person is known (70 kg), we can calculate the force applied by the person by rearranging the formula as follows:
Force = Work / Distance
Force = 350 J / Distance
Since the distance is the height of the person when they reach their maximum height, we can calculate it by rearranging the formula again:
Distance = Work / Force
Distance = 350 J / (70 kg x 9.81 m/s2)
Distance = 4.87 m
Therefore, the person will reach a maximum height of 4.87 m.

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The magnitude of the electric field at a point equidistant from the two lines of charge, with a distance of 2d from both lines, is 5.89 x 10^5 N/C.

An electric field is an invisible force field that surrounds any electric charge. It exerts a force on other charges in the field, either pushing them away or pulling them closer. The strength of the field is determined by the magnitude of the charge; the greater the charge, the stronger the field.

The electric field at any point along the line of charge is given by the equation E= kQ/r^2, where k is the Coulomb's constant (8.99 x 10^9 Nm^2/C^2), Q is the charge, and r is the distance from the line of charge.
Applying this equation to the given situation, we can calculate the electric field as follows:
E = (8.99 x 10^9 Nm^2/C^2) x (40.00 x 10^-6 C/m) / (2 x 4.70 m)^2
E = 5.89 x 10^5 N/C
Thus, the magnitude of the electric field at a point equidistant from the two lines of charge, with a distance of 2d from both lines, is 5.89 x 10^5 N/C.

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When a car turns on a curved road, the centripetal force is generated. This force, which is applied to the circular path's centre, is what causes the body's velocity to change direction.

The force is provided by the friction between the tyres of the car and the road surface. This friction is a part of the normal force, which acts perpendicular to the road's surface.

The other component of the normal force, the normal reaction, acts in the opposite direction to the centripetal force and helps in balancing the weight of the car.

The normal force thus plays an important role in providing the centripetal force and keeping the car balanced. Without it, the car would not be able to turn on a curved road.

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The weight of 1 kg on Mars would be 0.38 N, 1 slug would be 3.72 N, and 1 lbm would be 0.17 N.

The weight of an object is determined by its mass and the force of gravity acting upon it. On Earth, the acceleration due to gravity is 9.8 m/s^2. However, on Mars, the acceleration due to gravity is 38% of that on Earth, or 3.71 m/s^2.

To calculate the weight of an object, we multiply its mass by the acceleration due to gravity. So, the calculation would be:

For 1 kg on Mars:

1 kg * 3.71 m/s^2 = 3.71 N

For 1 slug on Mars:

1 slug * 3.71 m/s^2 = 14.59 N

For 1 lbm on Mars:

1 lbm * 3.71 m/s^2 = 0.82 N

Therefore, the weight of 1 kg on Mars is 3.71 N, 1 slug is 14.59 N, and 1 lbm is 0.82 N.

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The pressure inside a soap bubble is  0.813 N/m^2, with internal diameter d=15.9 mm and external diameter d=16 mm, when the surface tension of the soap is σ=0.06 n/m.

The pressure inside a soap bubble can be calculated using the Laplace law, which states that the pressure difference between the inside and outside of a spherical bubble is proportional to the surface tension of the soap and the radius of the bubble.

The Laplace law can be expressed as:

= P

= 2σ / r

here P is pressure difference,

σ is surface tension of soap,

r is radius of the bubble.

To calculate the pressure inside the soap bubble, we first need to calculate the internal and external radii of the bubble:

=> Internal radius (ri)

= d / 2

= 15.9 mm / 2

= 7.95 mm

=> External radius (re)

= (d + 2t) / 2

= 16 mm / 2

= 8 mm

here t is thickness of soap film.

Next, Using Laplace's law, we determine the difference in pressure:

= P

= 2σ / r

= 2 x 0.06 N/m / (8 mm - 7.95 mm)

= 0.813 N/m^2

So, the pressure inside the soap bubble is 0.813 N/m^2.

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The frequencies of the harmonics are calculated using the equation [tex]f = \frac{nV}{2L}[/tex].

From calculations the length of the organ pipe is 5.73m.  

Harmonics are the multiples of fundamental frequencies. The frequencies here are the frequencies of the wave. Here two successive frequencies are given. So we can calculate the length by using these frequencies.

First frequency is 210 Hz. It can be expressed in the equation as

   n₁V/ 2L = f₁

  n₂V/2L =f₂

Since they are successive, Let n₁= n, then n₂ will be (n+1).

f₁ = nV/2L

f₂ = (n+1)V/2L

Dividing f₁ by f₂

 [tex]\frac{f_{1} }{f_{2} } = \frac{nV/2L)}{(n+1)V/2L}\\ \\\frac{210}{240} = \frac{n}{n+1}\\\\n=7[/tex]

Since n=7 and V= 344

f₁ = nV/2L

210   = 7× 344/ 2L

2L =  7× 344/210

L = (7×344)/(210×2)

L = 5.73m

So length of the organ pipe is 5.73 m

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