Please answer all. How do you determine the dose-specific response of a drug given f(x)?
Answers
__________________
Just replace in value of x in the function
f(0.1) = 100* (0.1)^2 / ((0.1)^2 + 0.17) = (1)/(0.18) = 5.56
f(0.1) = 5.56
f(0.8) = 100* (0.8)^2 / ((0.8)^2 + 0.17) = (64)/(0.81)= 79.01
f(0.8) = 79.01
_______________________
derivative of a quotient
Q(x)= f(x)/g(x)
Q'(x)= (f'(x)*g(x) - f(x)*g'(x)) / (g(x) ^2)
[tex]Q^{\prime}\mleft(x\mright)=\frac{f^{\prime}\mleft(x\mright)\cdot g\mleft(x\mright)-f\mleft(x\mright)\cdot g^{\prime}\mleft(x\mright)}{g\mleft(x\mright)^2}[/tex]_____________________________
If f(x) = 100* (x^2) / (x^2 + 0.17),
f'(x)= 100 * ( 2x* (x^2 + 0.17) - 2x*x^2 ) / (x^2 + 0.17)^2
f'(x)= 100 * ( 2x^3 + 2x* 0.17 - 2x^3 ) / (x^2 + 0.17)^2
f'(x)= 100 * ( 2x* 0.17 ) / (x^2 + 0.17)^2
f'(x)= 34*x/ (x^2 + 0.17)^2
_________________________
Just replace in value of x in the function
f'(0.1)= 34*(0.1)/ (0.1^2 + 0.17)^2
f'(0.1)= 3.4/ (0.18)^2
f'(0.1)= 104.9
f'(0.8)= 34*(0.8)/ (0.8^2 + 0.17)^2
f'(0.8)= 27.2/ (0.81)^2
f'(0.8)= 41.46
Related Questions
Find the range of the function for the given domain. {-5, -1, 0, 2, 10}
[tex]g(x)=x^{2}+2[/tex]
A. 2
B. -23
C. 3
D. 1
E. 102
F. 27
G. 6
Answers
The range of the function g(x) = x² + 2 for the given domain is found to be {27,3,25,6,102}.
What is the difference between domain and range in function?The domain of a function is the set of values that may be plugged into it. This set contains the x values in a function like f. (x). A function's range is the set of values that the function can take. This is the collection of values that the function returns when we enter an x value.
How do you find domain and range in the absence of numbers?To determine the domain of a function, f(x), determine which values of x cause f(x) to be undefined/not real. The usual procedure for determining range is to find x in terms of f(x) and then locate values of f(x) for which x is not defined.
Given:
g(x) = x² + 2
Domain of the function: {-5, -1, 0, 2, 10}
We need to find the range.
Let us substitute x = -5 in g(x)
g(-5) = (-5)² + 2
= 27
g(-1) = (-1)² + 2
= 3
g(0) = (0)² +(-5)²
= 25
g(2) = (2)² + 2
=6
g(10) = (10)² + 2
= 102
Therefore, the range of the given function g(x) = x² + 2 for a given domain is found to be {27,3,25,6,102}.
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Apply zero product theorem to solve for x[tex]x ^{2} = 9[/tex]
Answers
Answer:
[tex]\begin{gathered} x_1=-3 \\ x_2=3 \end{gathered}[/tex]Step-by-step explanation:
To apply the zero product theorem, put all the terms on the left side to equal zero.
[tex]x^2-9=0[/tex]Factoring the binomial:
[tex]\begin{gathered} (x+3)(x-3)=0 \\ x_1+3=0 \\ x_1=-3 \\ \\ x_2-3=0 \\ x_2=3 \end{gathered}[/tex]A line has a slope of 2/3 and contains point A(-6,-4) and point B (a, 2) what is the value of a?
Answers
From the point-slope formula, we have:
[tex]y-y_0=m(x-x_0)[/tex]where m is the slope, (x_0,y_0) are known points.
In this case, we have the slope and two points, we can substitute in the formula to get:
[tex]\begin{gathered} \text{if:} \\ (x,y)=(-6,-4) \\ \text{and} \\ (x_0,y_0)=(a,2) \\ \Rightarrow-4-2=\frac{2}{3}(-6-a) \\ \Rightarrow-6=-\frac{2\cdot6}{3}-\frac{2}{3}a \\ \Rightarrow-6=-4-\frac{2}{3}a \\ \Rightarrow-6+4=-\frac{2}{3}a \\ \Rightarrow-2=-\frac{2}{3}a\Rightarrow a=-\frac{2}{-\frac{2}{3}}=\frac{3\cdot2}{2}=\frac{6}{2}=3 \\ a=3 \end{gathered}[/tex]therefore, a=3
Note: you can also find a if you use the slope formula.
Question is in the picture.The options underneath are $100 per person $15 per person $10 per person and eight dollar per person I chose $100 but I need it to be explained
Answers
The graph provided plots the cost of a hall against the number of guests. The blue graph represents "Cosmic Hall".
The cost per person is the slope of the line that represents the hall in consideration.
The slope is calculated using the formula:
[tex]slope=\frac{y_2-y_1}{x_2-x_1}[/tex]From the graph, two points can be picked as shown below:
[tex]\begin{gathered} (x_1,y_1)=(0,6000) \\ (x_2,y_2)=(500,10000) \end{gathered}[/tex]Hence, the slope is calculated to be:
[tex]\begin{gathered} slope=\frac{10000-6000}{500-0}=\frac{4000}{500} \\ slope=8 \end{gathered}[/tex]i need help: question = Which process will create a figure that is congruent to the figure shown?
Answers
Solution
Option A
Option A is Congruent because the size of the image is not tampered with, we only rotate, reflect and translate
Option A is correct
Option B
Option B is not congruent because there is a translation of scale factor of 1/2
Option C
Option C is not congruent because the distance between each points and the x-axis are tripled
Option D
Option D is not also congruent because the distance between each points and the x-axis are doubled
Hence, Option A is correct
if (x=5)and y=10 which expression has the greatest value
Answers
Let's assume the question was as stated below;
"If x=5 and y=10, which expression has the greatest value?"
a. xy
b. x + y
c. x-y
d. x/y
Answer:
Option A. Expression xy has the greatest value.
Explanation:
To determine which of the given options has the greatest value, let's go ahead and evaluate each of them;
Option A;
[tex]xy=x\ast y=5\ast10=50[/tex]Option B;
[tex]x+y=5+10=15[/tex]Option C;
[tex]x-y=5-10=-5[/tex]Option D;
[tex]\frac{x}{y}=\frac{5}{10}=\frac{1}{2}[/tex]We can see that the expression (xy) gives the greatest value.
Therefore, option A would be our correct answer.
At a New Car Dealership, a particularmodel comes in 4 different trim levels(CX, DX, EX, and Si). The same modelcomes in 5 different colors (Night Black,Pearl White, Evening Blue, Sandy Red,and Forest Green). The model of car alsohas 3 different interior options (GreyCloth, Tan Cloth, Black Leather). Howmany different versions of this model canbe created from these options?
Answers
solution
diferent trim levels = 4
different colors = 5
different interior options = 3
then:
[tex]4\cdot5\cdot3=60[/tex]answer: 60 different versions of this model
what is .8 divided by 40
Answers
Problem
0.8 divided 40
Solution
We can do the following:
[tex]\frac{0.8}{40}=\frac{0.8\cdot10}{40\cdot10}=\frac{8}{400}[/tex]and if we simplify we got:
[tex]\frac{8}{400}=\frac{4}{200}=\frac{2}{100}=\frac{1}{50}=0.02[/tex]Find the values of the variables so that the figure is aparallelogram.
Answers
Given the following question:
[tex]\begin{gathered} \text{ The property of a }parallelogram \\ A\text{ + B = 180} \\ B\text{ + C = 180} \\ 64\text{ + }116\text{ = 180} \\ 116+64=180 \\ y=116 \\ x=64 \end{gathered}[/tex]y = 116
x = 64
I need help quick please i have to turn this in tomorrow it’s 4am.
Answers
Answer:
sitting in his highchair modifies baby
Find the unit price in cents per diaper for each of the brands shown below. Round to the nearest tenth of a cent.Brand A: 36 Diapers, $ 11.99 ? : ¢ per diaper Brand B: 50 Diapers, $11.49? : ¢ per diaper Note: Rounding to the nearest tenth of a cent is the same as rounding to the nearest thousandth of a dollar.Which is the better buy?
Answers
It is required that you find the unit price in cents per diaper.
To do this, convert the prices in dollars to cents by multiplying by 100.
[tex]\begin{gathered} \$11.99=11.99\times100\text{ cents} \\ =1199¢ \end{gathered}[/tex][tex]\begin{gathered} \$11.49=11.49\times100\text{ cents} \\ =1149¢ \end{gathered}[/tex]Next, divide the respective prices in cents by the corresponding number of diapers:
For brand A:
[tex]\frac{1199}{36}\approx33.3¢\text{ per diaper}[/tex]For brand B:
[tex]\frac{1149}{50}=22.98\approx23.0¢\text{ per diaper}[/tex]Next, notice that Brand B has a lower unit price. Hence, it is the better buy.
Brand B is the better buy,
I dont really get it or what it is asking
Answers
ANSWER
• A vertical plane that cuts through the top vertex, perpendicular to the base,: ,triangle
,• A horizontal plane, that cuts through the pyramid, parallel to the base:, ,square
,• A vertical plane that cuts through the base and two opposite lateral faces:, ,trapezoid
EXPLANATION
• A vertical plane that cuts through the top vertex, perpendicular to the base,: if we draw a rectangle perpendicular to the base that passes through the vertex,
Hence, the cross-sectional shape is a triangle.
• A horizontal plane, that cuts through the pyramid, parallel to the base:, if it is a plane parallel to the base, then it should have the same shape as the base,
Hence, the cross-sectional shape is a square.
• A vertical plane that cuts through the base and two opposite lateral faces:, again, we can draw this plane. The cross-sectional shape will have one pair of parallel sides and one pair of non-parallel sides,
Hence, the cross-sectional shape is a trapezoid.
i really need help can you help me?
Answers
1. Madison's work is correct. Her there is no mistake
2. Kaleb's work is not correct. His mistake was when he divided by 4
If tan theta = 4/3 and pi
Answers
Given that tan theta = 4/3 and theta lies in the third quadrant.
[tex]\pi<\theta<\frac{3\pi}{2}[/tex]Divide the compound inequality by 2.
[tex]\frac{\pi}{2}<\frac{\theta}{2}<\frac{3\pi}{4}[/tex]This means theta/2 lies in the second quadrant. So, cos theta/2 and sec theta/2 are negative.
Use trigonometric identities to find sec theta.
[tex]\begin{gathered} \sec \theta=\sqrt[]{1+\tan ^2\theta} \\ =\sqrt[]{1+(\frac{4}{3})^2} \\ =\sqrt[]{1+\frac{16}{9}} \\ =\sqrt[]{\frac{25}{9}} \\ =-\frac{5}{3} \end{gathered}[/tex]we know that cosine is the inverse of secant. So, cos theta = -3/5.
now, using the half-angle formula, we have to find cos theta/2,
[tex]\begin{gathered} \cos (\frac{\theta}{2})=-\sqrt[]{\frac{1+\cos x}{2}} \\ =-\sqrt[]{\frac{1-\frac{3}{5}}{2}} \\ =-\sqrt[]{\frac{\frac{2}{3}}{2}} \\ =-\sqrt[]{\frac{1}{3}} \end{gathered}[/tex]a monument that is 169.4 ft tall is built on a site that is 67.3 Ft below sea level how many feet above sea level is the top of the monument
Answers
Answer:
102.1 ft
Explanation:
We can represent the situation as follows:
So, we need to find the value of H. Therefore, H is equal to:
H = 169.4 ft - 67.3 ft
H = 102.1 ft
So, the top of the monument is 102.1 ft above sea level.
Given f(x)=x^2+4x+5, what is f(2+h)-f(2)/h equal to?A. h^2 + 8hB. 2x + h + 4C. 8 + hD. h + 4
Answers
ANSWER:
C. 8 + h
STEP-BY-STEP EXPLANATION:
We have the following expression:
[tex]f\mleft(x\mright)=x^2+4x+5[/tex]We evaluate each case and obtain the following:
[tex]\begin{gathered} f(h+2)=\left(2+h\right)^2+4\left(2+h\right)+5 \\ \\ f(2+h)=4+4h+h^2+8+4h+5 \\ \\ f(2+h)=h^2+4h+4h+4+8+5 \\ \\ f(2+h)=h^2+8h+17 \\ \\ \\ f(2)=\left(2\right)^2+4\left(2\right)+5 \\ \\ f(2)=4+8+5 \\ \\ f(2)=17 \end{gathered}[/tex]We substitute each function evaluated to determine the final result, just like this:
[tex]\begin{gathered} \frac{f(2+h)-f(2)}{h}=\frac{h^2+8h+17-17}{h} \\ \\ \frac{f(2+h)-f(2)}{h}=\frac{h^2+8h}{h} \\ \\ \frac{f(2+h)-f(2)}{h}=h+8=8+h \end{gathered}[/tex]Therefore, the correct answer is C. 8 + h
wХ14. Given: WX || YZ, WX = YZProve: AWXZ AYZXZ
Answers
how to solve (s + 5)(s - 5)
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Here, we want to solve an expansion
To get this, we simply multiply the terms in the first bracket with the terms in the second, before we proceed to collect like terms
We have this as follows;
[tex]\begin{gathered} (s+5)(s-5)\text{ = s(s-5)+5(s-5)} \\ =s^2-5s+5s-25 \\ =s^2-25 \end{gathered}[/tex]Karl borrowed $5,700 from the bank for a year at 9% simple interest. What was the amount he paid back to the bank?
Answers
Simple interest = PRT /100
where P is the principal
R is the rate
T is the time in year
From the question
P=$5700 R=9 T=1
substitute the values into the formula;
S.I = 5700 x 9 x 1 /100
=$513
Amount pay back = $5700 + $513 = $6,213
The height of the triangle is 3 feet less than twice its base. The area of the triangle is 52 ft2. What is the height of the triangle?
Answers
Given:
Base of triangle = b
Height of triangle, h, is 3 feet less than twice its base. This is expressed as:
h = 2b - 3
Area of triangle = 52 ft²
To find the height of the triangle, use the Area of a triangle formula below:
[tex]A=\frac{1}{2}bh[/tex]Thus, we have:
[tex]\begin{gathered} 52=\frac{1}{2}\times b\times(2b-3) \\ \\ 52=\frac{b(2b-3)}{2} \end{gathered}[/tex]Let's solve for the base, b:
[tex]\begin{gathered} 52=\frac{2b^2-3b}{2} \\ \\ Multiply\text{ both sides by 2:} \\ 52\times2=\frac{2b^2-3b}{2}\times2 \\ \\ 104=2b^2-3b \end{gathered}[/tex]Subtract 104 from both sides to equate to zero:
[tex]\begin{gathered} 2b^2-3b-104=104-104 \\ \\ 2b^2-3b-104=0 \end{gathered}[/tex]Factor the quadratic equation:
[tex](2b+13)(b-8)[/tex]Thus, we have:
[tex]\begin{gathered} (2b+13)\text{ = 0} \\ 2b\text{ + 13 = 0} \\ 2b=-13 \\ b=-\frac{13}{2} \\ \\ \\ (b-8)=0 \\ b=8 \end{gathered}[/tex]We have the possible values for b as:
b = - 13/2 and 8
Since the base can't be a negative value, let's take the positive value.
Therefore, the base of the triangle, b = 8 feet
To find the height, substitute b for 8 from the height equation, h=2b-3
Thus,
h = 2b - 3
h = 2(8) - 3
h = 16 - 3
h = 13 feet.
Therefore, the height of the triangle, h = 13 feet
ANSWER:
13 feet
In a circle v, UTw =50 solve for X . If mUW= (9x-34)
Answers
Answer:
X=14.9
Step-by-step explanation:
mUW=2 . m <utw
so (9x - 34) = 2.50
9x - 34 = 100
x = 14.9
Ruth has a piece of wood that measures 2 2/9 feet. She cut off 1 1/3 feet of
wood for a project. How much wood does she have remaining?
Answers
After finding the difference between total measure of wood and cut off wood, she have remaining 8/9 wood.
In the given we have to find the remaining wood.
Ruth has a piece of wood that measures 2 2/9 feet.
Now converting the mixed fraction in improper fraction by multiplying the 2 and 9 then add 2 in the multiplication of 2 and 9.
So the improper fraction is 20/9.
So The measure of wood = 20/9 feet
She cut off 1 1/3 feet of wood for a project.
Now converting the mixed fraction in improper fraction by multiplying the 1 and 3 then add 1 in the multiplication of 1 and 3.
So the improper fraction is 4/3.
So, she cut the wood = 4/3 feet
Now the remaining wood = Total measure of wood−cut the wood
Remaining wood =20/9−4/3
Now equal the denominator of both values.
Remaining wood =20/9 −4/3 ×3/3
Remaining wood =20/9 −12/9
Remaining wood =(20−12)/9
Remaining wood =8/9
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if your able to answer all of them i will be giving you 5 stars
Answers
The function given is:
[tex]f(x)=-16x^2+60x+16[/tex]PART AThe factorization steps are shown below:
[tex]\begin{gathered} f(x)=-16x^2+60x+16 \\ f(x)=4(-4x^2+15x+4) \\ f(x)=4(-4x^2+16x-x+4) \\ f(x)=4(-4x(x-4)-1(x-4)) \\ f(x)=4(-4x-1)(x-4) \end{gathered}[/tex]PART BTo find the x intercepts, we set f(x) equal to 0 and solve for x:
[tex]\begin{gathered} f(x)=4(-4x-1)(x-4) \\ f(x)=0 \\ 4(-4x-1)(x-4)=0 \\ -4x-1=0--------(1) \\ OR \\ x-4=0---------(2) \end{gathered}[/tex]Solving (1), we have:
[tex]\begin{gathered} -4x-1=0 \\ 4x=-1 \\ x=-\frac{1}{4} \\ x=-0.25 \end{gathered}[/tex]and, solving (2), we have:
[tex]\begin{gathered} x-4=0 \\ x=4 \end{gathered}[/tex]The x-intercepts are
[tex]\begin{gathered} x=-0.25 \\ x=4 \end{gathered}[/tex]PART CThe standard equation of a quadratic is
[tex]f(x)=ax^2+bx+c[/tex]The parabola opens upward when a is positive and opens downward when a is negative
1. When parabola opens upward, the end behavior can be described as:
[tex]\begin{gathered} x\rightarrow\infty \\ y\rightarrow\infty \\ \text{and} \\ x\rightarrow-\infty \\ y\rightarrow\infty \end{gathered}[/tex]2. When parabola opens downward, the end behavior can be described as:
[tex]\begin{gathered} x\rightarrow\infty \\ y\rightarrow-\infty \\ \text{and} \\ x\rightarrow-\infty \\ y\rightarrow-\infty \end{gathered}[/tex]Our equation has an "a" value that is negative! So, the parabola opens downward and the end behvaior can be described as:
As x goes to infinity (gets infinitely large), y goes to negative infinity (gets infinitely small) and as x goes to negative infinity (gets infinitely small), y goes to negative infinity (get infinitely small).
PART D
In Part B, we found the x-intercepts. Those are the x-axis cutting points. We can draw those first.
Then,
Using the end behavior information that we found in Part C, we can draw the parabola. The rough sketch is shown:
The exact graph is shown below, for reference:
Answer two questions about Equations A and B:Skill SumA. 5 = -2(x - 1)sidesB. 5 = -20 +21) How can we get Equation B from Equation A?Choose 1 answer:a) Rewrite one side (or both) by combining like terms0215b) Rewrite one side for both) using the distributive propertyc) Multiply/divide both sides by the same non-zero constantd) Multiply/divide both sides by the same variable expression Based on the previous answer, are the equations equivalent? In other words,do they have the same solution?
Answers
Rewrite one side(or both) by combining like terms
Explanation:
Equation A: 5 = -2(x - 1)
Equation B: 5 = -20 +2
To get Equation B from Equation A, we equate the right sides of both equations since equating the left side give the same answer.
Left side: 5 = 5
Right side: -2(x - 1) = -20 +2
Then we solve:
-2x + 2 = -18
-2x = -18-2
-2x = -20
x = -20/-2
x = 10
To get Equation B from Equation A, we make x = 10
Rewrite one side(or both) by combining like terms
I will show you the question
Answers
The given system is
[tex]\begin{cases}3x+6y=12 \\ x+2y=4\end{cases}[/tex]First, we multiply the second equation by -3.
[tex]\begin{cases}3x+6y=12 \\ -3x-6y=-12\end{cases}[/tex]Then, we combine the equations
[tex]\begin{gathered} 3x-3x+6y-6y=12-12 \\ 0=0 \end{gathered}[/tex]This means the system has infinitely many solutions.
Hence, the answer is D.(06.02)
Solve the system 2x + 2y = -6 and 3x - 2y = 11 by using graph paper or graphing
technology. What is the solution to the system?
O (1,-4)
O (-1,-7)
O (3,-2)
O (2,-1)
Answers
Answer:
(1-4)
Step-by-step explanation:
Solve for the first variable(x or y) in one of the equations(you choose which equation) and then after finding the first variable(x or y) you plug it in into the equation u didnt use and solve
392196 divided by 87(using king division)
Answers
Answer: The result of 392,196 divided by 87 is 4,508
A parabola has a vertex at (2, -1) and a y- intercept at (0,3). Is this enough information to sketch a graph? Explain your answer. Henny Yoffe . 11:20 AM
Answers
It is given that the parabola has the vertex at (2,-1)and y intercept of 3,
Consider the general equation of the parabola with vertex (p,q),
[tex]y=a(x-p)^2+q[/tex]Sbstitute 2 for 'p' and -1 for 'q',
[tex]y=a(x-2)^2-1[/tex]Given that the y-intercept is 3, it means that the curve passess through (0,3),
So it must satisfy the equation,
[tex]3=a(0-2)^2-1\Rightarrow4a=4\Rightarrow a=1[/tex]Substitute the value of 'a', 'p', and 'q' in the standard equation,
[tex]y=1(x-2)^2-1\Rightarrow y=(x-2)^2-1[/tex]Thus, the equation of the parabola can be obtained using the given conditions.
I need help with a math assignment i linked the picture below with the question
Answers
Answer:
[tex]P\text{ = 29x+5}[/tex]Explanation:
Here, we want to get the perimeter of the rectangle
Mathematically, that is:
[tex]P\text{ = 2(L + B)}[/tex]Where L is the length of the rectangle, given as 6.5x + 9 ft and B is the width of the rectangle which is 8x-6.5
Substituting these values into the formula, we have the perimeter of the rectangle as follows:
[tex]\begin{gathered} P=2(6.5x\text{ + 9 +8x-6.5)} \\ P\text{ = 2(14.5x+2.5)} \\ P\text{ = 29x+5} \end{gathered}[/tex]What is the range 12 ,20,18,25,6
Answers
The maximum of data is 25
The minimum of data is 6
Then, the range is:
range = maximum - minimum
range = 25 - 6
range = 19
