The given expression is
[tex]x^2+1[/tex]We can not factorize this expression bt the normal factorizing ways
Because it is a binomial with + as a middle sign can not be distributed into 2 factors
Then there is no factorizing for the given binomial
If the sign between the two terms is (-), then we can factorize it into two same factors with different middle sign
We can use the complex numbers to factorize it
[tex]\begin{gathered} x^2=(x)(x) \\ 1=(i)(-i) \\ (x)(i)+(x)(-i)=(xi)-(xi)=0 \\ (x+i)(x-i) \end{gathered}[/tex]Then the factors are (x + i) and (x - i)
[tex]x^2+1=(x+i)(x-i)[/tex]Answer:
x^2+1
Step-by-step explanation:
The expression is not factorable with rational numbers.
I am stumped with the graph question attached. Please assist.
Answer:
[tex]\begin{gathered} 0.44x^{2}-2.67x+3 \\ or \\ \frac{1}{2.25}(x-3)^2-1 \end{gathered}[/tex]Explanation:
From the graph, we will observe that the vertex is at the point:
[tex]\begin{gathered} (h,k)=(3,-1) \\ \text{We will obtain the quadratic equation from the vertex form using the formula:} \\ f(x)=a(x-h)^2+k \\ \text{Inputting the values of ''h'' \& ''k'', we have:} \\ f(x)=a(x-3)^2-1 \\ \text{We have the x-intercept at point:} \\ (x,y)=(1.5,0) \\ f(1.5)=0 \\ \Rightarrow0=a(1.5-3)^2-1 \\ 0=a(-1.5)^2-1 \\ 0=a(2.25)-1 \\ 0=2.25a-1 \\ \text{Add ''1'' to both sides, we have:} \\ 1=2.25a \\ 2.25a=1 \\ \text{Divide both sides by ''2.25'', we have:} \\ a=\frac{1}{2.25}=0.44 \\ \text{We will substitute the value of ''a'' into the vertex equation, we have:} \\ f(x)=\frac{1}{2.25}(x-3)^2-1 \\ \text{Expand the bracket, we have:} \\ f(x)=\frac{1}{2.25}(x-3)(x-3)-1 \\ f(x)=\frac{1}{2.25}[x(x-3)-3(x-3)]-1 \\ f(x)=\frac{1}{2.25}[x^2-3x-3x+9]-1 \\ f(x)=\frac{1}{2.25}[x^2-6x+9]-1 \end{gathered}[/tex]We will obtain the quadratic function as shown below:
[tex]\begin{gathered} \frac{1}{2.25}[x^2-6x+9]-1 \\ \text{Expand the bracket, we have:} \\ 0.44x^2-2.67x+4-1 \\ 0.44x^2-2.67x+3 \\ or \\ \frac{1}{2.25}(x-3)^{2}-1 \\ \end{gathered}[/tex]Need help on this geometry assignment please
Step-by-step explanation:
Find the first four terms of the sequence given by the following.An= 42- 7(n-1), n=1, 2, 3...
In order to calculate the first four terms of this sequence, let's use the values of n = 1, 2, 3 and 4 in the expression for An:
[tex]\begin{gathered} n=1\colon \\ A_1=42-7(1-1)=42 \\ \\ n=2\colon \\ A_2=42-7(2-1)=35 \\ \\ n=3\colon \\ A_3=42-7(3-1)=28 \\ \\ n=4\colon \\ A_4=42-7(4-1)=21 \end{gathered}[/tex]Therefore the first four terms are 42, 35, 28 and 21.
The following are distances (in miles) traveled to the work place by 6 employees of a certain brokerage firm. Find the standard deviation of this sample distances. ROund your answer to two decimal places
Step 1
Arrange the data from smallest to biggest
[tex]2,5,14,34,37,40[/tex]Step 2
The formula for standard deviation for sample is given as;
[tex]\begin{gathered} \sigma=\sqrt{\frac{\sum(x-\mu)^2}{n-1}} \\ \mu=mean \\ n=number\text{ of data} \end{gathered}[/tex]Find the mean
[tex]mean=\frac{132}{6}=22[/tex]Hence the standard deviation will be;
[tex]\begin{gathered} \sigma=\sqrt{\frac{1446}{6-1}=}17.005881 \\ \sigma\approx17.01\text{ to 2 decimal places} \end{gathered}[/tex]Answer; The standard deviation for the sample to two decimal places is;
[tex]17.01[/tex]After a dilation, triangle A(0,0), B(0,4), C(6,0) becomes triangle A’(0,0), B’(0,10), C’(15,0) what is the scale factor
Solution:
The triangle is dilated from
[tex]\begin{gathered} (1)A(0,0)\rightarrow A^1(0,0) \\ \text{There is no change in coordinate here, } \\ \text{This shows the center of dilation is at point (0,0)} \\ \\ (2)\text{ } \\ \text{From B(0,4) }\rightarrow B^1(0,10) \\ Scale\text{ factor is }\frac{10}{4}\text{ = 2.5} \\ Or\text{ } \\ (3)\text{ from C(6,0) to (15,0)} \\ Scale\text{ factor is }\frac{15}{6}\text{ = 2.5} \end{gathered}[/tex]The scale factor of the dilation is 2.5
2.) What does the graph below represent? What are key points andcharacteristics? Provide as many details as possible.
The graph shows the evolution of the profits, in a scale of dollars, in time, in the scale of months.
The profit grows from month 0 to 1, decrease from month 1 to 2, and then increases from there (with stagnation in months 4, 5 and 6).
We have no information from month 7 or bigger.
The range of the profit up to month 6 is between $2,000 and $6,000, but the arrow indicate it will grow over $6,000 the following months.
A committee is to be formed consisting of 2 men and 5 women. If the committee members are to be chosen from 11 men and 12 women, how many different committees are possible?
through the given statement many 43,560 different committees are possible to be formed.
What is Probability?Probability is a measure of the likelihood of an event to occur.
Many events cannot be predicted with total certainty. We can predict only the chance of an event to occur.
Probability of an event P(E) = (Number of favorable outcomes) ÷ (Sample space).
The multiplication rule and the addition rule are used for computing the probability of A and B, as well as the probability of A or B for two given events A, B defined on the sample space.
Describe four Perspectives on Probability?Classical (sometimes called "A priori" or "Theoretical")Empirical (sometimes called "A posteriori" or "Frequentist")SubjectiveAxiomaticWe can choose 2 men from 11 men
That is 11C2 ways.
Similarly we can choose 5 women from 12 women
That is 12C5 ways.
Total ways in which we can choose 2 men and 5 women to form a committee = 11c2 * 12c5
= 55 * 792
= 43,560
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There are three parts to this question. A) The number of people initially infected is? (round to the nearest whole number as needed)
a.
To find the initial number of people infected, let's calculate the value of f(t) for t = 0:
[tex]f(0)=\frac{102000}{1+5200e^0}=\frac{102000}{1+5200}=\frac{102000}{5201}=19.61[/tex]Rounding to the nearest whole number, the initial value is 20 people.
b.
Using t = 4, let's calculate the value of f(t):
[tex]f(4)=\frac{102000}{1+5200e^{-4}}=\frac{102000}{1+5200\cdot0.0183156}=\frac{102000}{96.24112}=1.059.84[/tex]Therefore the number of infected people is 1060.
c.
When t tends to infinity, the value of 5200e^-t will tend to zero, therefore we have:
[tex]\lim_{t\to\infty}f(t)=\frac{102000}{1+0}=102000[/tex]Therefore the limiting size is 102000 people.
A bank features a savings account that has an annual percentage rate of r = 5.2% with interest compoundedsemi-annually. Dylan deposits $7,000 into the account.nakThe account balance can be modeled by the exponential formula A = P(1+ where A is the futurevalue, P is the present value, r is the annual percentage rate, k is the number of times each year that theinterest is compounded, and n is the time in years.(A) What values should be used for p, r, and k?PAT =k=(B) How much money will Dylan have in the account in 8 years?Answer = $Round answer to the nearest penny.(C) What is the annual percentage yield (APY) for the savings account? (The APY is the actual or effectiveannual percentage rate which includes all compounding in the year).APY =Round answer to 3 decimal places.
(A) Given that:
Present value, P = $7000
Annual percentage rate, r = 5.2% = 0.052
Number of compounding periods, k = 2
(B) Plug the values into the formula
[tex]A=P(1+\frac{r}{k})^{nk}[/tex]gives
[tex]A=7000(1+\frac{0.052}{2})^{2n}[/tex]Substitute 8 for n to find the amount of money after 8 years.
[tex]\begin{gathered} A=7000(1+\frac{0.052}{2})^{2\cdot8} \\ =7000(1.026)^{16} \\ =10554.94 \end{gathered}[/tex]In 8 years, Dylan will have $10554.94 in account.
(C) Find the annual percentage yield using the formula
[tex]\text{APY}=(1+\frac{r}{k})^k-1[/tex]Plug the values into the formula.
[tex]\begin{gathered} \text{APY}=(1+\frac{0.052}{2})^2-1 \\ =5.268\% \end{gathered}[/tex]The annual percentage yield for the savings account is 5.268%.
A student worked 52 hr during a week one summer. The student earned $5.70 per hour for the first 40 hr and $8.55 per hour for overtime. How much did the student earn during the week? Enter your answer in the answer box
Total earnings during the week = $330.6
Explanations:The total number of hours worked during the week = 52 hr
Earnings per hour for the first 40 hours = $5.70
Earnings for the first 40 hours = $5.70 x 40
Earnings for the first 40 hours = $228
The number of hours worked as overtime = 52 - 40 = 12 hours
Earnings per hour for overtime = $8.55
Earnings for overtime = $8.55 x 12
Earnings for overtime = $102.6
Total earnings during the week= Earnings for the first 40 hours + Earnings for overtime
Total earnings during the week = $228 + $102.6
Total earnings durig the week = $330.6
Construct sinusoidal functionsThe graph of a sinusoidal function intersects its midline at (0, -3) and then has a maximum point at (2, -1.5).Write the formula of the function, where x is entered in radians.
We have a sinusoidal function.
[tex]y=A\cdot\sin (b\cdot x+c)+d[/tex]Its midline is intersected at (0,-3) and has a maximum point at (2,-1.5).
As the midline intersects at y=-3, we know that function has an offset of 3 units down.
This offset is the value of the parameter d, so we have:
[tex]y=A\cdot\sin (b\cdot x+c)-3[/tex]The maximum value happens at point (2,-1.5). The maximum value happens when the pure sin function reaches the value 1, so we can write:
[tex]\begin{gathered} y_{\max }=A\cdot1-3=-1.5 \\ A-3=-1.5 \\ A=-1.5+3 \\ A=1.5 \end{gathered}[/tex]The amplitude is A=1.5, so we can write:
[tex]y=1.5\sin (b\cdot x+c)-3[/tex]We can find the values of the parameters b and c using the x-values of the the points (0,-3) and (2,-1.5):
[tex]\begin{gathered} (x,y)=(0,-3) \\ y(0)=1.5\sin (b\cdot0+c)-3=-3 \\ 1.5\cdot\sin (c)=-3+3 \\ 1.5\cdot\sin (c)=0 \\ \sin (c)=0 \\ c=0 \end{gathered}[/tex][tex]\begin{gathered} (x,y)=(2,-1.5) \\ y(2)=1.5\cdot\sin (b\cdot2)-3=-1.5 \\ 1.5\cdot\sin (2b)=-1.5+3 \\ 1.5\cdot\sin (2b)=1.5 \\ \sin (2b)=1 \\ 2b=\frac{\pi}{2} \\ b=\frac{\pi}{2}\cdot\frac{1}{2} \\ b=\frac{\pi}{4} \end{gathered}[/tex]The function becomes:
[tex]y(x)=1.5\sin (\frac{\pi}{4}x)-3[/tex]The graph of the function is:
Answer: y(x) = 1.5*sin(pi/4 * x)-3
What is Q1 in the given box-and-whisker plot?A box-and-whisker plot. The number line goes from 0 to 20. The whiskers range from 2 to 19 and the box ranges from 6.5 to 18. A line divides the box at 17.a.2c.17b.6.5d.18
we have that
Min=2
Max=19
Median=17
Answer:
b. 6.5
Step-by-step explanation:
edge 2023 I did it myself trust me
Rubio is grilling ground beef patties for his party. The nutritional label from the ground is shown. Based on the information in the label, about how many milligrams of cholesterol are recommended per day?
Answer:
259.26 mg of cholesterol per day.
Explanation:
From the label, we can say that 70 mg of cholesterol is equivalent to 27% of the daily value. So, we need to found the amount equivalent to 100%. So, we can use the following equation:
[tex]100\text{ \% }\times\frac{70\text{ mg}}{27\text{ \%}}=259.26\text{ mg}[/tex]Therefore, the answer is 259.26 mg of cholesterol per day.
10 ( -7/8) = ( -7/8 ) 10
Solve both sides of the equation to determine if true.
10(-7/8) = (-7/8)10
-70/8 = -70/8
This equation is true.
Answer:
[tex]10\left(\frac{-7}{8}\right)=\left(\frac{-7}{8}\right)\cdot \:10\quad :\quad \mathrm{True}[/tex]
Step-by-step explanation:
STEPS
[tex]10\left(\frac{-7}{8}\right)=\left(\frac{-7}{8}\right)\cdot \:10[/tex]
Frist u simplify [tex]10\left(\frac{-7}{8}\right)[/tex]
[tex]=10\cdot \frac{-7}{8}\\\\[/tex]
[tex]=-\frac{7\cdot \:10}{8}[/tex]
[tex]=-\frac{70}{8}[/tex]
[tex]=-\frac{35}{4}[/tex]
[tex]-\frac{35}{4}=-\frac{35}{4}[/tex]
THIs means both sides are true
hope this helps
~~Wdfads~~
5 = 60(0.93)^x
Initial value:
Growth or Decay:
Growth/Decay Rate:
Initial value is 60 and growth factor is -0.93 in this instance.
How are growth and decay determined?The formulas f(x) = a(1 + r)t and f(x) = a(1 - r)t provide the necessary computations for the exponential growth and decay. Here, t is the length of time or the time factor, an is the initial quantity, r is the growth or decay constant.
The formula is 5 = 60(0.93)^x.
The beginning value and growth/decay factor should be determined.
Solution:
Y = a(1+r)^x is the formula for the exponential growth/decay model in general (i)
where an is the starting value, r>0 indicates growth factor, r0 indicates decay factor, and x indicates time.
As a result, 5 = 60(0.93)^x.
It can be expressed mathematically as 5 = 60(1 + (-0.93))x (ii)
We obtain a = 60 and r = -0.93 when comparing I with (ii).
Initial value is 60 and growth factor is -0.93 in this instance.
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Solve for the remaining angles and side of the triangle described below. Round to the nearest thousandth:C = 60°, b = 3,a = 4AnswerHow to enter your answer (opens in new window) 2 Points
Explanation
Let's first make a sketch of the triangle:
We can find the measure of c with the law of cosines:
[tex]c=\sqrt{a^2+b^2-2ab\cdot cos(C)}[/tex][tex]c=\sqrt{9+16-24\cdot\frac{1}{2}}[/tex][tex]c=\sqrt{13}[/tex]For B and A we can use the sine law:
[tex]\frac{sin(B)}{3}=\frac{sin(60)}{\sqrt{13}}[/tex][tex]B=73.898°[/tex]And
[tex]\frac{sin(A)}{4}=\frac{sin(60)}{\sqrt{13}}[/tex][tex]A=46.102°[/tex]Answer
[tex]c=\sqrt{13}[/tex][tex]B=73.898°[/tex][tex]A=46.102°[/tex]What is 2/5 divided by 8/5
Answer: 1/4 or 0.25
Step-by-step explanation: multiply by the reciprocal, 2/5 ÷ 5/8 then change the symbol to multiplication 2/5 x 5/8 multiply and the answer is 1/4
Solve log x = 4.Ox= 4Ox= 40Ox= 1,000Ox= 10,000Need help!!!
Let's recall that when do not see a base written, it means the base is 10.
Let's also recall that the log form and the exponential form are interchangeable.
[tex]\log _{a\text{ }}b\text{ = c }\Rightarrow\text{ }a^{c\text{ }}=\text{ b}[/tex]Therefore, we have:
[tex]\log _{10\text{ }}x\text{ = 4 }\Rightarrow10^4\text{ = x}[/tex][tex]The\text{ correct answer is x = }10^{4\text{ }}=\text{ 10,000}[/tex]The correct answer is D.
F (x) = 6x
Find x if f(x) = -24
Hey there!
[tex]f(x)=-6x\\whenf(x)=-24[/tex]
In order to find f(x), we need to substitute -24 for x:
[tex]f(x)=6(-24)\\x=-144[/tex]
Hope this helps!
Need help asap I will reward the first person who answers with a lot of points
Answer:
C 60 = x + 45
Step-by-step explanation:
They are vertically opposite angles so they are equal.
402,394,386 find the 33rd term
The sequence are 402, 394, 386. The 33 rd term can be found below
The quotient of a number x and five
(translating english phrases to mathematical expressions)
The expression forming by the statement "quotient of a number x and 5" is x/5.
What do we mean by quotient?In this example, the number divided by (15) is known as the dividend, and the number divided by (3 in this instance) is known as the divisor. The quotient is the outcome of the division. The quotient is the result of dividing two numbers by each other. As in the case of 8 ÷ 4 = 2, where the division produced the number 2, the result is the quotient. The dividend is 8 and the divisor is 4. An algebraic expression is referred to as a quotient expression or an algebraic fraction if division comes last in the evaluation process. An algebraic fraction or quotient expression is the expression 7x2+5x.So, the quotient of a number (x) and 5:
Where x is the number.then, the expression will be: x/5Therefore, the expression formed by the statement "quotient of a number x and 5" is x/5.
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The correct question is given below:
The quotient of a number (x) and five
What are two possible numbers that are 5 units from the number -6 on a number line?
Answer:
The 2 possible numbers are -11 and -1.
Step-by-step explanation:
What place value first determines which of the numbers 279.1642 or 279.1651 is the
larger number
279.1651 is larger
======================================================
Explanation:
Both values have "279.16" at the start
The difference starts to happen in the digit just after the 6, which is the thousandths digit
The first value 279.1642 has '4' in the thousandths digitThe second value 279.1651 has '5' in the thousandths digitThis makes 279.1651 to be the slightly larger value.
A die was rolled 60 times. It landed on one—11 times, two—9 times, four—12 times, five—12 times, and six—8 times. What is the empirical probability of rolling an even number?
Step-by-step explanation:
Empirical Probability is the experimental probability.
The probability formula is
the number of times an event occured/total times all events happen.
We know we rolled the dice 60 times so that will be in the numerator.
We roll 2, 9 times
We roll 4, 12 times
We roll 6, 8 times so
we roll even numbers a total of 29 times, so our experimentally Probability is
[tex] \frac{29}{50} = 0.58[/tex]
PLS HELP ME IN TEN MINS FOR 10 POINTS THANKS U which group of numbers to replace the ? In a tree diagram? [ A] -7/8, -2.5, -4 [B] 7/8 ,2.5 ,4 [C] -7, 8 ,-4 [D] NOT heren
According to the given image, the tree diagram begins with Real Numbers.
The second level is formed by subsets of Real Numbers which are Rational Numbers and Irrational Numbers.
The third level is formed by subsets of rational numbers which are Non-Integer Rational Numbers and Integer Rational Numbers.
This means the missing part must be filled with Integer Rational Numbers.
Therefore, the right answer is -7, 8, -4, because these numbers are rational integers.Find the unknown length in the right triangle.The unknown length b in the triangle is _____(Simplify your answer. Write an exact answer, using radicals as needed.)
The given triangle is a right triangle because one of its angles is 90 degrees. We would find b by applying the pythagorean theorem which is expressed as
hypotenuse^2 = one leg^2 + other leg^2
From the information given,
hypotenuse = 17
one leg = 7
other leg = b
Thus,
17^2 = 7^2 + b^2
289 = 49 + b^2
b^2 = 289 - 49 = 240
b = √240
b = 4√15
Exact value of addition and subtraction formulas / sin cos tan
Take into account that:
[tex]\frac{5\pi}{4}+\frac{\pi}{3}=\frac{15\pi+4\pi}{12}=\frac{19}{12}\pi[/tex]Then, for the given sine value, you can write:
[tex]\sin (\frac{19}{12}\pi)=\sin (\frac{5}{4}\pi+\frac{1}{3}\pi)[/tex]Now, consider that the sine of a sum is:
[tex]\sin (a+b)=\sin a\cdot\cos b+\cos a\cdot\sin b[/tex]Then, by applying the previous identity to the given expression, you obtain:
[tex]\sin (\frac{5}{4}\pi+\frac{1}{3}\pi)=\sin (\frac{5}{4}\pi)\cos (\frac{1}{3}\pi)+\cos (\frac{5}{4}\pi)\sin (\frac{1}{3}\pi)[/tex]Consider now that:
[tex]\begin{gathered} \sin (\frac{5}{4}\pi)=-\frac{\sqrt[]{2}}{2} \\ \cos (\frac{1}{3}\pi)=\frac{1}{2} \\ \sin (\frac{1}{3}\pi)=\frac{\sqrt[]{3}}{2} \\ \cos (\frac{5}{4}\pi)=-\frac{\sqrt[]{2}}{2} \end{gathered}[/tex]Then, for the given expression of the question, you get:
[tex]\begin{gathered} \sin (\frac{5}{4}\pi+\frac{1}{3}\pi)=(-\frac{\sqrt[]{2}}{2})(\frac{1}{2})+(-\frac{\sqrt[]{2}}{2})(\frac{\sqrt[]{3}}{2}) \\ =-\frac{\sqrt[]{2}}{4}-\frac{\sqrt[]{2}\sqrt[]{3}}{4}=-\frac{(1+\sqrt[]{3})\sqrt[]{2}}{4} \end{gathered}[/tex]The pervious result is the answer to the given expression.
Evaluate the expression when a = 5 and b = 49.
b-6a
Answer:
19
Step-by-step explanation:
Evaluating means substituting letters in an equation for values given :
b-6a
b = 49
a = 5
(49) -6(5)
= 49-30
= 19
Hope this helped and have a good day
Jackie's class took a field trip to the art museum. They left school at 11:00 A.M. It took them30 minutes to drive to the museum. They stayed at the museum for 3 hours. What time wasit when Jackie's class left the museum?
Given
Jackie's class took a field trip to the art museum.
They left school at 11:00 A.M.
It took them 30 minutes to drive to the museum.
They stayed at the museum for 3 hours.
To find:
What time was it when Jackie's class left the museum?
Explanation:
It is given that,
Jackie's class took a field trip to the art museum.
They left school at 11:00 A.M.
It took them 30 minutes to drive to the museum.
They stayed at the museum for 3 hours.
That implies,
Since,
Jackie's class left the school at 11:00 A.M and drove for 30 minutes.
Then,
The time at which they reach the museum is,
[tex]\begin{gathered} Time\text{ }taken\text{ }to\text{ }reach\text{ }the\text{ }museum=30\text{ }mins \\ \therefore Jackie^{\prime}s\text{ }class\text{ }reach\text{ }the\text{ }museum\text{ }at\text{ }(11.00+0.30)=11.30\text{ }A.M \end{gathered}[/tex]Also,
Since,
They stayed at the museum for 3 hours.
Then,
[tex]\begin{gathered} Jackie^{\prime}s\text{ }class\text{ }left\text{ }the\text{ }museum\text{ }at\text{ }(11.30+3.00)=14.30\text{ }hours \\ That\text{ }is, \\ They\text{ }left\text{ }the\text{ }museum\text{ }at\text{ }(12.00+2.30)\text{ }hours=2.30\text{ }P.M \end{gathered}[/tex]Hence, they left the museum at 2.30 P.M.
