Please answer my question.

Explanation:

To make 100 mL of a 1 M NaCl solution, you need to add 58.44 grams of NaCl (sodium chloride).

The formula for molarity (M) is:

M = m/V

where

m = mass of solute (NaCl)

V = volume of solution (100 mL)

Given that M = 1, we can rearrange the formula to find m:

m = M x V

m = 1 x (0.1 L) x (58.44 g/mol)

m = 58.44 g

So, you need to add 58.44 grams of NaCl to 100 mL of water to make a 1 M NaCl solution.

4-12 , carbon atoms and the boiling range

The hydrocarbons in gasoline generally comprise 4-12 carbon atoms and have a boiling range of 30 to 210 °C, whereas diesel fuel has hydrocarbons with 12-20 carbon atoms and a boiling range of 170 to 360 °C.

Hydrocarbons are a type of chemical that exclusively consists of hydrogen and carbon atoms. Polycyclic aromatic hydrocarbons, or PAHs, are those that combine hydrogen with carbon atom rings. Hydrocarbons containing additives, such as gasoline, are also mentioned. Gasoline is a petroleum-derived product that consists of a combination of liquid aliphatic and aromatic hydrocarbons with carbon atoms ranging from C4 to C12 with a boiling temperature range of 30-225°C.

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According to the query, they will create an ionic bond by sharing electrons to fill out their respective eight valence electrons. BeO

Here are 2.228 moles of beryllium oxide, or BeO. BeO is stated as the chemical formula for beryllium oxide. The amount of beryllium oxide that was produced weighs 555.7 grams. To determine the number of moles, The moles are calculated by dividing the substance's mass by its molar mass. Molar mass = Mass formed 55.7 grams of BeO were produced in total. BeO has a molar mass of 25g/mol. Assigning values, BeO moles = 55.7/25 BeO is made up of 2.228 moles. Therefore, 2.228 moles of beryllium oxide were produced. The ability of an element to combine with other atoms to form chemical compounds or molecules is measured by the element's valence or valency.

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The grams of potassium carbonate neede to make 400ml of 2.5M solution is 186g.

A answer's molarity tells you approximately the variety of moles of solute this is found in 1 L of answer. You can say:

Molarity(M)=moles of solute1 litre of answer Molarity(M)=moles of solute/litre of answer

We recognise that with a purpose to calculate a answer's molarity, you must recognise the variety of moles of solute this is found in 1 L i.e. a thousand mL of answer.

We can use the molar mass of a compound to decide the variety of moles gift withinside the pattern so variety of moles of a compound may be calculated via way of means of making use of the subsequent system:

Number of moles=Mass(g)Molar mass(gmol−1)Number of moles=Mass(g)/Molar mass(gmol−1)

In the given question, we already recognise the molarity in addition to quantity of the answer that are as follows:

Molarity=2.5Volume=400mL=0.4LMolarity=2.5Volume=400mL=0.4L

Substituting those given values withinside the system of molarity, we can calculate the variety of moles as depicted below:

1 =moles of solute0.4 variety of moles=1 moles of K2CO32=moles of solute0.2 variety of moles=1 moles of K2CO3

Molar mass of K2CO3K2CO3 may be calculated via way of means of including the atomic mass of every of the atom gift withinside the molecule as proven below:

Molecular mass of K2CO3=(2×K)+(1×C)+(3×O)=(2×39)+(1×12)+(3×16)=138gmol−1Molecular mass of K2CO3=(2×K)+(1×C)+(3×O)=(2×39)+(1×12)+(3×16)=138gmol−1

Now substituting the values withinside the variety of moles system, we get the mass of K2CO3K2CO3 as proven below:

1=Mass(g)138Mass(g)=69g0.five=Mass(g)138Mass(g)=138g

Hence, 138 grams of potassium carbonate K2CO3K2CO3 are had to make four hundred mL of a 2.five M answer.

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Answer: C. 140 g K2CO3

Explanation:

Considering the combined law equation, the pressure when the volume is 1.05 L and the temperature is 308 K is 2.33 atm.

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant.

Mathematically, this law expresses that the product of the pressure by the volume is constant:

P×V= k

where:

Charles' law states that the volume is directly proportional to the temperature of the gas when the pressure is constant.

Mathematically, this law establishes that the ratio between volume and temperature is constant:

V÷T=k

where:

Gay-Lussac's law states that the pressure of a gas is directly proportional to its temperature when the volume is constant.

Mathematically, this law establishes that the ratio between pressure and temperature is constant:

P÷T=k

where:

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

(P×V)÷T=k

Analyzing an initial state 1 and a final state 2, it is fulfilled:

(P₁×V₁)÷T₁= (P₂×V₂)÷T₂

In this case, you know:

Replacing int the combined law equation:

(1.02 atm×2.20 L)÷282 K= (P₂×1.05 L)÷308 K

Solving:

[(1.02 atm×2.20 L)÷282 K] × (308 K÷1.05 L)= P₂

2.33 atm=  P₂

In summary, the final pressure is 2.33 atm.

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Answer:

The equation shows that for every 1 mole of KCIO3 that is decomposed, 1 mole of KCI is produced.

If 5.0g of KCIO3 is decomposed, we can use the molar mass of KCIO3 to convert that to moles.

Molar mass of KCIO3 = 39 + 35.5 + 3(16) = 138.5 g/mol

5.0g of KCIO3 is equal to (5.0g / 138.5 g/mol) = 0.036 moles

And since 1 mole of KCIO3 produces 1 mole of KCI, 0.036 moles of KCIO3 will produce 0.036 moles of KCI.

To convert that to grams, we use the molar mass of KCI, which is 39 + 35.5 = 74.5 g/mol

So, 0.036 moles of KCI is equal to (0.036 moles * 74.5 g/mol) = 2.69g of KCI.

Answer:

The name of the super continent that was once made up of all current continents was Pangea

Explanation:

It is stated in this query that p above p is the rule when using the Clausius-Claparon equation.

According to what I'm going to explain, p not will be our boiling point, and that value will be equal to delta minus. The boiling point is determined by the formula: H, vapor pressure over r 1 over t minus 1 over t not and again t not. Thus, a pressure line can be seen here. According to what we've been told, it is 1 o 9 miles per hour. 680 would enter there, followed by delta h, at a distance of 6080000000 meters from Mercury. The vapourization factor is 2.46. I'm not going to include the units in this section because ideal gas has a constant 8.314 joules per mole.

It is - 66 degrees Celsius when mole kelvin is subtracted from the initial temperature. Since our boiling point would be 2 o 7 kelvin minus 1 over t, that would convert to that value. This will be plugged into my equation using the solver here, which yields 237 kelvin when accounting for t. The boiling point at 680 millimeters of mercury would be minus 273, which gives me a result of minus 36 degrees celsius, and we then translated that to degrees celsius.

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