Please awnser asap I will brainlist

The left-hand side of the equation represents the logarithm of 64 with base x, and it is not possible to find a real value of x that satisfies the equation.

solve the equation logₓ(64) + 5 = 2, we can follow these steps:

Step 1: Move the constant term to the other side of the equation:

logₓ(64) = 2 - 5

logₓ(64) = -3

Step 2: Rewrite the equation in exponential form:

x^(-3) = 64

Step 3: Rewrite 64 as a power of x:

x^(-3) = x^6

Step 4: Set the exponents equal to each other:

-3 = 6

The equation -3 = 6 is not true, which means there is no real solution to the given equation.

Therefore, the equation logₓ(64) + 5 = 2 has no solution in the real number system.

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Answer:

Step-by-step explanation:

According to the triangle proportionality theorem (or thales theorem), the lines are parallel if AD/BD = AE/CE

15/12= 1.25

10/8 = 1.25

Because the ratios are equal, the lines are parallel to each other.  

The roster method of the set A' = {14, 15, 20}

The roster method is defined as a way to show the elements of a set by listing the elements inside of brackets.

A typical example of the roster method is to write the set of numbers from 1 to 5 as {1, 2, 3, 4, 5}.

Therefore,

U = universal sets = {14, 15, 16, 17, 18, 19, 20}

A = {16, 17, 18, 19}

Therefore, let's find A' as follows:

A' is the value not in A. Hence, in roster method.

A' = {14, 15, 20}

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The transformation of g(x) to f(x) is g(x) is shifted up 15 units and shifted left by 16 units

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

Where, we have

f(x) = 1/(x + 16) + 15

g(x) = 1/x

From the above, we have

Horizontal difference = 16 - 0 = 16

Vertical difference = 15 - 0 = 15

This means that the transformation of g(x) to f(x) is g(x) is shifted up 15 units and shifted left by 16 units

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Answer: 4 pages

Step-by-step explanation:

To solve this problem, we need to use the formula:

Rate = Output/Time

Let's use "p" to represent the number of pages Ethan can type and "t" to represent the time he has before the meeting starts.

Rate = 2 pages/(1/8 hour) = 16 pages/hour

Since the meeting starts 3/4 hour later than the scheduled time, Ethan has t = 1 - 3/4 = 1/4 hour to type pages before the meeting starts.

Output = Rate * Timep = (16 pages/hour) * (1/4 hour) = 4 pages

Therefore, Ethan can type 4 pages before the meeting starts.

Answer: 4 pages

The absolute extrema of the function f(x) = 6[tex]x^4[/tex] - 8[tex]x^3[/tex] on the closed interval (-∞, ∞) are: the minimum value of -2 at x = 1 and no maximum value.

To find the absolute extrema of the function f(x) = 6[tex]x^4[/tex]- 8[tex]x^3[/tex] on a closed interval, we need to evaluate the function at its critical points and endpoints and compare their values.

The critical points occur where the derivative of the function is equal to zero or undefined. Let's find the derivative of f(x) first. Taking the derivative of f(x) = 6[tex]x^4[/tex] - 8[tex]x^3[/tex], we get f'(x) = 24[tex]x^3[/tex] - 24[tex]x^2[/tex].

Setting f'(x) equal to zero, we have 24[tex]x^3[/tex] - 24[tex]x^2[/tex] = 0. Factoring out 24[tex]x^2[/tex]from the equation, we get 24[tex]x^2(x - 1)[/tex] = 0. This equation is satisfied when x = 0 or x = 1.

Now we evaluate the function at these critical points and the endpoints of the interval. The given interval is not specified, so we'll assume it as the entire real number line (-∞, ∞).

For x = 0, f(0) = 6[tex](0)^4[/tex] - 8[tex](0)^3[/tex] = 0.

For x = 1, f(1) = 6[tex](1)^4[/tex] - 8[tex](1)^3[/tex] = -2.

Since the function is a fourth-degree polynomial, it approaches negative infinity as x approaches negative infinity and approaches positive infinity as x approaches positive infinity.

Therefore, the absolute extrema of the function f(x) = 6[tex]x^4[/tex] - 8[tex]x^3[/tex] on the closed interval (-∞, ∞) are: the minimum value of -2 at x = 1 and no maximum value.

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Answer:

If Delaware was proportional to Alabama in enrollment to the district, it would have approximately 37 districts.

The ratio of students to districts in Alabama is 630,683/137 = 4,603 students per district. If Delaware had the same ratio of students to districts, it would have 120,475/4,603 = 26.16 districts. Rounding to the nearest whole number, Delaware would have approximately 26 districts if it was proportional to Alabama in enrollment to the district.

To find the rate at which the light projected onto the wall is moving along the wall, we can use trigonometry and calculus. Let's denote the angle between the rotating light and the wall as θ.

Given:

Distance from the light to the wall, r = 15 feet

Rate of rotation, dθ/dt = 1 rotation every 4 seconds

We need to find the rate at which the light's projection moves along the wall, which is represented by dx/dt.

Using trigonometry, we know that the tangent of the angle θ is equal to the ratio of the distance along the wall (dx) to the distance from the light to the wall (r).

tan(θ) = dx / r

Differentiating both sides of the equation with respect to time t, we get:

sec^2(θ) * dθ/dt = dx/dt

Since we are given that the angle θ is 15 degrees, we can substitute the values and solve for dx/dt.

sec^2(15°) * (1 rotation / 4 seconds) = dx/dt

Simplify and calculate the value to find the rate at which the light's projection moves along the wall in feet per second.

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In 2025, both colleges will have an enrollment of 21,200 students.

To determine when the colleges will have the same enrollment, we need to set up an equation based on the projected enrollment increases and declines.

Let's assume the number of years from 2020 is represented by 'x'.

For College A, the projected enrollment can be represented by: 18,700 + 500x.

For College B, the projected enrollment can be represented by: 26,200 - 1000x.

To find when the colleges will have the same enrollment, we need to solve the equation:

18,700 + 500x = 26,200 - 1000x

Combining like terms, we get:

1500x = 7,500

Dividing both sides by 1500, we find:

x = 5

Therefore, the colleges will have the same enrollment in 5 years, or in the year 2025.

To determine the enrollment at that time, we substitute x = 5 into either equation. Let's use College A's equation:

Enrollment in College A in 2025:

18,700 + 500(5) = 18,700 + 2500 = 21,200 students

Enrollment in College B in 2025:

26,200 - 1000(5) = 26,200 - 5000 = 21,200 students

Both colleges will have an enrollment of 21,200 students in the year 2025 when they have the same enrollment.

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These lines are not sufficient for me to evaluate their content and determine their truthfulness or accuracy.

In order to provide a meaningful response, I would need you to provide the specific lines or statements you would like me to evaluate.

However, I can assure you that as an AI language model, I generate responses based on the data I have been trained on up until September 2021. I do not have real-time information or access to the internet to verify the accuracy of specific statements made after that time.

I generate responses based on patterns and information from the training data, but I do not copy content from specific sources without attribution.

However, if you copy and paste any responses I provide without proper attribution, that would be considered plagiarism.

It is always important to provide proper citations and references when using information from any source, including AI-generated content.

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Answer:

[tex]\displaystyle 64-32\sqrt{2}+\frac{32\sqrt{2}}{3}\approx3.66[/tex]

Step-by-step explanation:

[tex]\displaystyle \iint_R(3x-y)\,dA\\\\=\int^\frac{\pi}{2}_\frac{\pi}{4}\int^4_0(3r\cos\theta-r\sin\theta)\,r\,dr\,d\theta\\\\=\int^\frac{\pi}{2}_\frac{\pi}{4}\int^4_0(3r^2\cos\theta-r^2\sin\theta)\,dr\,d\theta\\\\=\int^\frac{\pi}{2}_\frac{\pi}{4}\int^4_0r^2(3\cos\theta-\sin\theta)\,dr\,d\theta\\\\=\int^\frac{\pi}{2}_\frac{\pi}{4}\frac{64}{3}(3\cos\theta-\sin\theta)\,d\theta\\\\=\int^\frac{\pi}{2}_\frac{\pi}{4}\biggr(64\cos\theta-\frac{64}{3}\sin\theta\biggr)\,d\theta[/tex]

[tex]\displaystyle =\biggr(64\sin\theta+\frac{64}{3}\cos\theta\biggr)\biggr|^\frac{\pi}{2}_\frac{\pi}{4}\\\\=\biggr(64\sin\frac{\pi}{2}+\frac{64}{3}\cos\frac{\pi}{2}\biggr)-\biggr(64\sin\frac{\pi}{4}+\frac{64}{3}\cos\frac{\pi}{4}\biggr)\\\\=64-\biggr(64\cdot{\frac{\sqrt{2}}{2}}+\frac{64}{3}\cdot{\frac{\sqrt{2}}{2}}\biggr)\\\\=64-32\sqrt{2}+\frac{32\sqrt{2}}{3}\biggr\\\\\approx3.66[/tex]

Answer:

{e, 24}

Step-by-step explanation:

U = {a, b, c, d, e, f, 19, 20, 21, 22, 23, 24}

X = {a, b, c, 20, 21, 22}

Y = {b, d, f, 19, 21, 23}

X' ∩ Y' = (X U Y)'

= ({a, b, c, 20, 21, 22} U {b, d, f, 19, 21, 23})'

= ({a, b, c, d, f, 19, 20, 21, 22, 23})'

={e, 24}

Answer:

The rates are not equivalent since Maria saves $0.50 more per month than Ralph.

Step-by-step explanation:

We can determine if two rates are equivalent by comparing the rates at which they save per month.

Maria's savings per month:

Both 50 and 4 can be divided by 2, which gives us 25/2.  As a regular number, this becomes 12.5/1 which means Maria saves $12.5 per month.

Ralph's savings per month:

Both 60 and 5 can be divided by 5, which gives us 12.  Thus, Ralph saves $12 per month.

Thus, the rates are not equivalent as Maria saves $0.50 more per month than Ralph.

Answer:

Lat A34,13,14) and E = [8] Insert or to make the statement trus

A \ mathbb E

Insert or to make the statement trun

A)-

(1)0$

a. The vertical shift of the graph of G(x) compared to the graph of F(x) is an upward shift of 1 unit.

b. The vertical shift of the graph of G(x) compared to the graph of F(x) is an upward shift of 1 unit, while there is no horizontal shift between the two graphs.

In the functions G(x) = 2^(-x) and F(x) = 2^x:

Vertical Shift:

The vertical shift refers to the movement of a graph up or down along the y-axis. In this case, comparing G(x) = 2^(-x) to F(x) = 2^x, there is a vertical shift present.

The graph of F(x) = 2^x has its vertex (the lowest point of the graph) at the point (0, 1) on the coordinate plane.

The graph of G(x) = 2^(-x) is obtained by reflecting the graph of F(x) about the x-axis. This reflection results in a vertical shift of the graph. The graph of G(x) will have its vertex (the highest point of the graph) at the point (0, 1).

Therefore, the vertical shift of the graph of G(x) compared to the graph of F(x) is an upward shift of 1 unit.

Horizontal Shift:

The horizontal shift refers to the movement of a graph left or right along the x-axis. In this case, comparing G(x) = 2^(-x) to F(x) = 2^x, there is no horizontal shift present.

Both G(x) = 2^(-x) and F(x) = 2^x have their graphs centered at the y-axis, passing through the point (0, 1). Therefore, there is no horizontal shift between the two functions.

To summarize, the vertical shift of the graph of G(x) compared to the graph of F(x) is an upward shift of 1 unit, while there is no horizontal shift between the two graphs.

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The following question may be like this:

Consider the functions G(x) = 2^(-x) and F(x) = 2^x.

State the vertical shift of the graph of G(x) compared to the graph of F(x).

State the horizontal shift of the graph of G(x) compared to the graph of F(x). explain

The rest of the amount, represented by R, is $2000 in this case.

If the total amount is $3000 and a certain amount, c, is deposited in one investment, we can represent the remaining amount in dollars by subtracting the deposited amount from the total.

Let's denote the remaining amount as R.

R = Total amount - Deposit amount

R = $3000 - c

Here, R represents the rest of the amount in dollars after the deposit of c dollars. By subtracting the deposit amount from the total amount, we can determine the value of the remaining amount.

For example, if $1000 is deposited in one investment (c = $1000), we can find the remaining amount as follows:

R = $3000 - $1000

R = $2000

Therefore, the rest of the amount, represented by R, is $2000 in this case.

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Answer:

11 yards and 3 feet

Answer:

  26.1°

Step-by-step explanation:

You want the value of angle x° in a right triangle that has the side adjacent to x being 53 cm, and the side opposite being 26 cm.

The tangent ratio is ...

  Tan = Opposite/Adjacent

The side opposite the angle is 26 cm; the side adjacent is 53 cm. The ratio of these is ...

  tan(x) = 26/53

The arctangent function is used to find the angle when the tangent is known.

  x = arctan(26/53) ≈ 26.1°

The angle x° is approximately 26.1°.

__

Additional comment

The calculator must be in degrees mode.

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Q1- The annual depreciation for the equipment is $2,000.

Q2- The book value of the equipment at the end of Year 3 is $6,500.

Q1: What is the annual depreciation for the equipment?

To calculate the annual depreciation, we need to determine the difference between the initial value and the salvage value, and divide it by the number of years.

Initial value = $12,500

Salvage value = $2,500

Number of years = 5

Annual depreciation = (Initial value - Salvage value) / Number of years

= ($12,500 - $2,500) / 5

= $10,000 / 5

= $2,000

Therefore, the annual depreciation for the equipment is $2,000.

Q2: What is the book value of the equipment at the end of Year 3?

The book value of the equipment at the end of a specific year can be calculated by subtracting the accumulated depreciation from the initial value.

Initial value = $12,500

Annual depreciation = $2,000

Number of years = 3

Accumulated depreciation = Annual depreciation * Number of years

= $2,000 * 3

= $6,000

Book value at the end of Year 3 = Initial value - Accumulated depreciation

= $12,500 - $6,000

= $6,500

Therefore, the book value of the equipment at the end of Year 3 is $6,500.

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The six terms of the series 247 are 2, 2, 2, 2, 2, and 2.

To find the six terms of a series, we need to first understand what a series is. A series is defined as the sum of the terms of a sequence. A sequence is a set of numbers in a specific order.

Therefore, a series is a sum of terms from a sequence. There are different types of series, and they have different formulas for calculating their terms.In this case, we are required to find the six terms of the series 247. Since this is a finite series, we can use a formula to calculate the nth term of a finite series.

The formula is given as follows:Tn = a + (n - 1) dWhere Tn is the nth term of the series, a is the first term of the series, n is the number of terms in the series, and d is the common difference between the terms of the series.To find the six terms of the series 247, we need to know the value of a and d. In this case, we can see that the first term of the series is 2. Therefore, a = 2.

Since this is a constant series, we can see that the common difference between the terms is 0. Therefore, d = 0.Substituting these values in the formula, we get:T1 = a + (1 - 1) dT1 = 2 + 0T1 = 2T2 = a + (2 - 1) dT2 = 2 + 0T2 = 2T3 = a + (3 - 1) dT3 = 2 + 0T3 = 2T4 = a + (4 - 1) dT4 = 2 + 0T4 = 2T5 = a + (5 - 1) dT5 = 2 + 0T5 = 2T6 = a + (6 - 1) dT6 = 2 + 0T6 = 2.

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Answer:

To determine the first term of the geometric progression, let's assume it is 'a'. From the given information, we know that:

Second Term = a + 50

(n + 1)th Term = a + 56

We also have the formula for the nth term of a geometric sequence:

nth term = a * r^(n-1)

where 'r' is the common ratio between consecutive terms. Since the difference between consecutive terms remains constant, i.e., 50 for the second term and 56 for the (n + 1)th term, we can set up the equation:

a + 50 = a * r^1

a + 56 = a * r^2

Solve the equations simultaneously:

a + 50 = a * r^1 => a - 50/r = 0

a + 56 = a * r^2 => a - 56/r = 0

Adding the two equations, we get:

2a - (50/r + 56/r) = 0

2a - (50 + 56)/r = 0

Simplifying the equation further, we obtain:

2a - (106/r) = 0

Now, solve for 'a':

2a - (106/r) = 0

2a = (106/r)

=> 2a = 106/r

The value of 'a' depends on the value of 'r', so we cannot determine its exact value without knowing 'r'. However, once we know 'r', we can calculate the value of 'a'.

To the nearest hundredth, the third side of the triangle is 62.74.

To find the length of the third side of the triangle, we can use the Law of Cosines, which relates the lengths of the sides and the cosine of an angle in a triangle. The formula is as follows:

[tex]c^2[/tex] = [tex]a^2[/tex] + [tex]b^2[/tex] - 2ab*cos(C)

Where:

c = length of the third side,

a and b = lengths of the other two sides, and

C = included angle.

Given that the lengths of the two sides are 43 and 67, and the included angle is 27 degrees, we can substitute these values into the formula:

[tex]c^2[/tex] = [tex]43^2[/tex] + [tex]67^2[/tex] - 2 * 43 * 67 * cos(27°)

Now we can calculate the value of c:

[tex]c^2[/tex] ≈ 1849 + 4489 - 2 * 43 * 67 * 0.8910065242

[tex]c^2[/tex] ≈ 1849 + 4489 - 5946.654213618

[tex]c^2[/tex] ≈ 3931.345786382

Taking the square root of both sides to isolate c, we get:

c ≈ √3931.345786382

c ≈ 62.74

Therefore, to the nearest hundredth, the length of the third side of the triangle is approximately 62.74.

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Since each child buys a double scoop with 2 flavors and no two children choose the same combination, we can determine the number of children by finding the number of unique flavor combinations possible.

To calculate the number of unique flavor combinations, we can use the concept of combinations without repetition. The formula for this is given by nCr = n! / ((n-r)! * r!), where n is the total number of flavors and r is the number of flavors chosen for each double scoop.

In this case, there are 9 flavors available and each child chooses 2 flavors. Using the formula, we have:

9C2 = 9! / ((9-2)! * 2!) = 9! / (7! * 2!) = (9 * 8) / 2 = 36 / 2 = 18.

Therefore, there are 18 children in the group, as each child can choose from 18 unique flavor combinations without repetition.

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The equation that represents the total price of Michigan State University per semester is determined by the number of classes taken (c) and the total cost for the semester, which includes a one-time fee for room and board (t).

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Answer: true

Step-by-step explanation:

Answer:

D. √3

Step-by-step explanation:

The tangent ratio is given by:

tan (θ) = opposite/adjacent, where

Thus, we plug in 8√3 for the opposite side and 8 for the adjacent side, which gives us:

tan (60) = (8√3) / 8

Thus reduces down to √3 so D. is the correct answer.

Answer:

24 u jus gotta multiply by 3 cuz it is 1 out of 3

Step-by-step explanation: hi :)

Answer:

Domain: x [tex]\geq[/tex] -5

Range: y [tex]\geq[/tex] -3

Step-by-step explanation:

The domain is all the possible inputs or x value.  x will be greater than -5.

The range is all of the possible outputs or y value.   y will be greater than -3

Answer:

Domain:  [-5, ∞)

Range:  [-3, ∞)

Step-by-step explanation:

The given graph shows a continuous curve with a closed circle at the left endpoint (-5, -3) and an arrow at the right endpoint.

A closed circle indicates the value is included in the interval.

An arrow shows that the function continues indefinitely in that direction.

The domain of a function is the set of all possible input values (x-values).

As the leftmost x-value of the curve is x = -5, and it continues indefinitely in the positive direction, the domain of the  graphed function is:

The range of a function is the set of all possible output values (y-values).

From observation, it appears that the minimum y-value of the curve is y = -3. The curve continues indefinitely in the positive direction in quadrant I. Therefore, the range of the graphed function is:

The phrase "Then S ∖m ∅; otherwise S is a subset of a finite set; a contradiction" is expressing a logical statement and its implications. Let's break it down:

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The slope is represented by the number 1473 in the equation T = 1473c + 5495. The slope denotes the rate of change, or the amount by which the overall cost (T) rises with each new class attended (c).

In this scenario, the total cost of the semester increases by $1473 for each extra class attended at Michigan State University. The slope reflects the linear relationship between the total cos and the number of classes taken.

The number 5495 represents the y-intercept in the equation. When the number of classes (c) is 0, the y-intercept is the value of T. The y-intercept of $5495 shows the total cost for a semester at Michigan State University when no classes are taken. It includes a one-time accommodation and board price.

The y-intercept can be understood as the university's fixed cost component, which is independent of the number of classes taken. It includes expenditures such as housing and food plans that are incurred regardless of how many classes a student enrolls in.

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