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The magnitude of gravitational acceleration at the surface of a newly discovered exoplanet, having the mass to be 1.01 times the mass of Earth, and the radius of the planet to be 0.99 times the radius of Earth is 10.06 m/s².

The acceleration that an object experiences when gravity is the only force acting on it is known as gravitational acceleration.

In an empty space, all bodies accelerate at the same rate, regardless of their masses or compositions. This means that any two objects falling from the same height would always hit the ground at the same time if there was no air friction.

Depending on altitude, latitude, and longitude, this free-fall acceleration can range from 9.764 to 9.834 m/s² over the surface of the Earth. However, the accepted standard value is 9.80665 m/s². Gravity anomalies are the regions where this value dramatically varies.

According to the formula,

g = [tex]\frac{GM}{R^{2} }[/tex]

where,

g is gravitational acceleration

G is gravitational constant,

M is mass of planet and,

R is the radius of the planet.

G = 6.67 × 10⁻¹¹

M = 1.01 × 6 × 10²⁴ kg

R = 0.99 × 6.4 × 10⁶ m

substituting the values and solving for g,

g = 10.06 m/s²

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The work done in raising an object is equal to the force applied to the object multiplied by the distance it is moved.

Objects in programming are entities that contain data and can be manipulated by code. They are commonly used to represent real-world things, such as a customer or an employee, or even abstract concepts such as a bank account. Objects are made up of properties, which are the data associated with the object, and methods, which are functions that objects can perform. Objects interact with one another through messages, which are sent from one object to another, allowing them to work together.

Therefore, we can calculate the distance the apple is lifted using the formula:

Work = Force × Distance

2.0 J = (0.180 kg)(9.8 m/s2) × d

d = 2.0 J / (0.180 kg)(9.8 m/s2)

d = 12.2 m

The apple is lifted 12.2 meters.

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The modern and old cars are fantastic. But however they are different from one another. The vintage cars cannot compete with today's cars. The car engines are significantly advanced over the years.

The deceleration refers to the acceleration in the direction opposite to the direction of the velocity. It always reduces the speed of the objects. The slowing down of a bike in a traffic is an example of deceleration.

The modern cars have smaller deceleration, because the engines in today's cars are more powerful and reliable. They provide greater safety, stability and efficiency. The fuel tank in the modern cars are also greater than the old cars.

Thus the Passengers experience a much smaller deceleration in modern cars.

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To answer the question we have, 1.93401 J of energy is lost when the puck travels over the uneven surface.

Energy is referred to by scientists as the capacity for work. People have figured out how to transform energy from one kind to the other before employing it to accomplish tasks, making western civilisation possible.

Hockey weighs 0.171 kg.

Starting speed: 5.65 m/s

Ultimately, the speed was 3.05 m/s.

We must determine how much kinetic energy was lost on the tough patch.

[tex]E_{d}=\frac{1}{2} v^2_{2} -v^2_1[/tex]

Where, m = mass

v₁ = Initial velocity

v₂ = Final velocity

Put the value into the formula

[tex]E_{d}=\frac{1}{2}[/tex] × 0.171 × [tex](3.05^2 - 5.65^2)[/tex]

=  1.93401 J energy is dissipated as the puck slides over the rough patch.

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Self-care can be demonstrated in a healthy way by recalling a happy memory.

The first step toward self-care is allowing yourself to be honest and vulnerable. Through self-reflection, you can at last let out all that you've been keeping down. Your journal is your very own private platform on which you can record your successes, anxieties, and worries.

Taking care of oneself exercises can go from proactive tasks, for example, practicing and practicing good eating habits, to mental exercises like perusing a book or rehearsing care, to otherworldly or social exercises, for example, imploring or getting lunch with a companion.

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Answer:the shape

Explanation:

Answer:

We can use the kinematic equations to solve for the time it takes for the soccer ball to hit the ground.

Let's use the following variables:

h for the initial height of the soccer ball (12 m)

vi for the initial velocity of the soccer ball (4 m/s)

vf for the final velocity of the soccer ball (0 m/s)

d for the horizontal distance the soccer ball travels before hitting the ground (6.3 m)

t for the time it takes for the soccer ball to hit the ground (what we want to find)

Using the kinematic equation for vertical motion, we can find the time it takes for the soccer ball to reach the ground:

vf^2 = vi^2 + 2*a*h

0 = 4^2 + 2*(-9.8)*12

0 = 16 - 235.2

t_vertical = sqrt(235.2/16) = 3.05 s

So it takes 3.05 seconds for the soccer ball to hit the ground if we consider only the vertical motion.

Next, using the kinematic equation for horizontal motion, we can find the time it takes for the soccer ball to travel the horizontal distance of 6.3 m:

d = vi*t_horizontal

t_horizontal = d/vi = 6.3/4 = 1.575 s

So it takes 1.575 seconds for the soccer ball to travel the horizontal distance of 6.3 m.

Since we know the soccer ball takes the same amount of time to travel horizontally as it does to hit the ground, we can conclude that the time it takes for the soccer ball to hit the ground is 1.575 seconds.

If the velocity is 294 ft/s and the acceleration is 22 ft/[tex]s^{2}[/tex], the time will be 13.36 s.

Given,

Final velocity, v = 294 ft/s

acceleration, a = 22 ft/[tex]s^{2}[/tex]

According to the first equation of motion

v = u + at

Where u = initial velocity

and t = time

To find out time (t) we will use the first equation of motion as

v = u + at

or, t = [tex]\frac{v-u}{a}[/tex]

where u = 0 ft/s

So, t = [tex]\frac{294-0}{22}[/tex]

= 13.36 s

Hence, the time will be 13.36 s.

A) the train's final velocity after 12 seconds of accelerating at 0.2 m/s^2 from rest is 2.4 m/s, and its displacement is 14.4 m.

B) it will take the train 75 seconds to reach a velocity of 54 km/h (15 m/s) if it continues to accelerate at the same rate of 0.2 m/s^2.

A) If the train starts from rest, its initial velocity is 0 m/s. Using the equation for constant acceleration, we can find the final velocity and displacement of the train after 12 seconds:

Final velocity = initial velocity + acceleration x time

Final velocity = 0 m/s + 0.2 m/s^2 x 12 s

Final velocity = 2.4 m/s

Displacement = (initial velocity x time) + (1/2 x acceleration x time^2)

Displacement = (0 m/s x 12 s) + (1/2 x 0.2 m/s^2 x (12 s)^2)

Displacement = 14.4 m

Therefore, the train's final velocity after 12 seconds of accelerating at 0.2 m/s^2 from rest is 2.4 m/s, and its displacement is 14.4 m.

B) First, we need to convert the final velocity to m/s:

54 km/h = 15 m/s (rounded to two decimal places)

Using the same equation for constant acceleration, we can solve for the time it takes for the train to reach a velocity of 15 m/s with an acceleration of 0.2 m/s^2:

Final velocity = initial velocity + acceleration x time

15 m/s = 0 m/s + 0.2 m/s^2 x time

time = 75 seconds

Therefore, it will take the train 75 seconds to reach a velocity of 54 km/h (15 m/s) if it continues to accelerate at the same rate of 0.2 m/s^2.

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Answer:40m East

Explanation:

a) Minimum speed required for the riders so that they stay pinned against the inside of the drum is 18m/s.

b) Angular velocity of the drum at this speed having diameter of the drum is 10 m is 3.6 rad/s

Friction is a resistance to motion of the object. for example, when a body slides on horizontal surface in positive x direction, it has friction in negative x direction and that measure of friction is a frictional force.

frictional force is directly proportional to the Normal(N).

i.e. [tex]F_{fri}[/tex] ∝ N

[tex]F_{fri}[/tex] = μN

where μ is called as coefficient of the friction. It is a dimensionless quantity.

When a body is kept on horizontal surface, its normal will be straight upward which is reaction of mg. i.e. N=mg.

Given,

Diameter of the drum D = 10m , Radius r = 5m

Coefficient of static friction = 0.15

a) To stay everyone pinned against the wall of drum. Frictional Force must be equal to weight mg which are opposite to each other.

μN = mg ........1)

Centrifugal acceleration = Normal

mv²÷r = N

With this equation 1 becomes

μ[tex]\frac{mv^{2} }{r}[/tex] = mg

v² = rg÷μ

v² = 5m*9.8m/s ÷ 0.15

v² = 326.6

v= [tex]\sqrt{326.6}[/tex] = 18.07 ~ 18 m/s

Hence minimum speed required for the riders is 18m/s.

b) for angular velocity of the drum, V=rω

ω = v÷r

ω = 18m/s ÷ 5m

ω = 3.6 rad/s

hence angular velocity of the drum at 18m/s speed is 3.6 rad/s

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The correct answer is D. The height of a dam is only one of many factors that determine its ability to produce electricity. Other important factors include the volume of water that can be held in the reservoir, the flow rate of the water, and the efficiency of the power generation equipment. Therefore, it is impossible to determine which dam has the ability to produce the most electricity based solely on its height.

Explanation:

When you exercise the muscles in your body must contract, in order to do that they need oxygen, glucose, a molecule called ATP, and amino acids. As your muscles use these compounds and contract themselves, they will create waste products like carbon dioxide, and lactic acid that must be carried away from the muscles. When exercising many muscles will all require nutrients and elimination of waste products constantly at the same time. To meet this demand the heart must rapidly increase the rate at which it beats and pushes blood through the body. This is why the heart beats significantly faster during exercise.

Dividing this by 24.0 s gives a power output of 23,600 W.

Power is the ability to influence or control the behaviour of people, events, or things. It is the capacity to make decisions and take action in order to effect change. Power can be physical, economic, political, cultural, or social, and can be held by individuals, organizations, or governments. Power can be used positively to create positive change, or negatively to oppress or exploit. It can be used to create a sense of safety, stability, and justice, or to create uncertainty and chaos.

The power output of the crane is calculated by dividing the work done by the crane (the force multiplied by the distance moved) by the time taken to do the work. In this case, the work done is 13,700 N x 41.4 m = 570,380 Nm. Dividing this by 24.0 s gives a power output of 23,600 W.

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Answer:

F = G M1 M2 / R^2      attraction between 2 masses

M1 = F R^2 / (G M2)

M1 = 2.20E4 * (4.2E6)^2 / (6.67E-11 * 4.95E3) kg

M1 = 2.2 * 4.2^2 / (6.67 * 4.95) E24

M1 = 1.18E24 kg

Answer:

potential until moved than kinetic

Explanation:

a. The maximum height reached by the ballast bag is approximately 300 m + 8.45 m = 308.45 m.

b. 5.0 s after it is released, the ballast bag is at a height of approximately 177.5 m above the ground, and its velocity is approximately -36.5 m/s

c. The ballast bag hits the ground approximately 18.1 s after it is released.

(a) To find the maximum height reached by the bag, we can use the kinematic equation:

v_f^2 = v_i^2 + 2aΔy

where v_f is the final velocity (which is zero at the maximum height), a is the acceleration due to gravity (approximately -9.8 m/s^2), and Δy is the change in height.

Rearranging and solving for Δy, we get:

Δy = v_i^2 / (2a) = (13 m/s)^2 / (2*(-9.8 m/s^2)) ≈ 8.45 m

Therefore, the maximum height reached by the ballast bag is approximately 300 m + 8.45 m = 308.45 m.

(b) To find the position and velocity of the bag 5.0 s after it is released, we can use the equations:

y = y_i + v_it + (1/2)at^2

v_f = v_i + at

where y_i is the initial height (300 m), v_i is the initial velocity (13 m/s), t is the time elapsed (5.0 s), and a is the acceleration due to gravity (-9.8 m/s^2).

Using these equations, we can find:

y = 300 m + 13 m/s*(5.0 s) + (1/2)(-9.8 m/s^2)(5.0 s)^2 ≈ 177.5 m

v_f = 13 m/s + (-9.8 m/s^2)*(5.0 s) ≈ -36.5 m/s

Therefore, 5.0 s after it is released, the ballast bag is at a height of approximately 177.5 m above the ground, and its velocity is approximately -36.5 m/s (i.e., it is moving downward).

(c) To find the time at which the ballast bag hits the ground, we can use the equation:

y = y_i + v_i*t + (1/2)at^2

Setting y = 0 (since the ground is at y = 0), y_i = 300 m, v_i = 13 m/s, and a = -9.8 m/s^2, we get:

0 = 300 m + 13 m/st + (1/2)(-9.8 m/s^2)*t^2

Rearranging and solving for t using the quadratic formula, we get:

t = (-13 ± sqrt(13^2 - 4*(-4.9)(300))) / (2(-4.9))

The positive solution is the time at which the ballast bag hits the ground:

t ≈ 18.1 s

Therefore, the ballast bag hits the ground approximately 18.1 s after it is released.

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The location at the point where electric field becomes zero is at 3.6m, when a positive point charge Q1= 2.6×10−5 C is fixed at the origin and a negative point charge Q2= −5.1×10−6 C is fixed at 2.0m.

Electric field is field around electrically charged particle where columbic force of attraction or repulsion can be experienced by other charged particles. It is denoted by letter E and it's SI unit is V/m Volt per meter or N/C newton per coulomb.

Electric field comes inward to the center of the negative charge and it is going outward for positive charge.

Given,

Q₁= 2.6×10⁻⁵ C

Q₂= −5.1×10⁻⁶ C

x = 2.0m,

In this case there are two charges, one at the origin and other is at 2m distance from origin. Both these charges are kept along positive x axis. looking at the situation there are 2 cases

Case 1 ( electric field in between two charges)

in this case direction of the resultant electric field in between two charges is along positive x direction (direction of electric field of positive charge is outward along x axis which is along positive x direction and direction of electric field of negative charge is inward along x axis which is also in positive x direction).

Case 2 ( right side of the negative charge)

In this case direction of electric field of positive charge is outward along x axis which is along positive x direction and direction of electric field of negative charge is inward along x axis but which is in opposite direction of electric field due to positive charge.

Hence our electric field is zero at right side of the negative charge.

on right side, electric fields due to both charges are opposite to each other then we can write mathematically E₁ - E₂ = 0 at the point where resultant electric field is zero. Where E₁ is elctric field due to positive charge and E₂ is electric field due to negative charge.

E₁ - E₂ = 0

E₁ = E₂

[tex]\frac{kQ_{1}}{x^{2}} = \frac{kQ_{2} }{(x+2)^{2}}[/tex]

[tex]\frac{Q_{1}}{x^{2}} = \frac{Q_{2} }{(x+2)^{2}}[/tex]

[tex]\frac{Q_{1}}{Q_{2} }} = \frac{x^{2} }{(x+2)^{2}}[/tex]

(2.6×10⁻⁵ C ÷ -5.1×10⁻⁶ C)  [tex]= \frac{x^{2} }{(x+2)^{2}}[/tex]

[tex]\frac{x^{2} }{(x+2)^{2}}[/tex] = 5.098 ≅ -5.1

x² = 5.1 (x+2)²

x = 2.25(x+2)

x=2.25x + 4.5

x(1-2.25) = 4.5

x(-1.25) = 4.5

x = 3.6m

Hence Electric field is zero at 3.6m from origin.

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The height the two balls will collide at 5.1 m above the ground after travelling for 1 second

Let's assume that the upward direction is positive, and the downward direction is negative. We can use the kinematic equations of motion to solve the problem.

For the ball that is dropped, we can use the equation:

y = y₀ + v₀t + 1/2 at²

Where:

Therefore, the equation becomes:

y = 10 + 0t - 1/2 (9.8)t²

For the ball that is thrown upward, we can use the equation:

y = y₀ + v₀t + 1/2 at²

where:

Therefore, the equation becomes:

y = 0 + 10t - 1/2 (9.8) t²

Since both balls will collide at the same height, we can equate the two equations to solve for t and y.

10 - 1/2 (9.8) t² = 10t - 1/2 (9.8) t²

Simplifying the equation, we get:

10t = 10

t = 1 second

Substituting t = 1 second into either equation, we get:

y = 10 * (1) - 1/2 (9.8) * (1)²

y = 5.1 meters

Therefore, the two balls will collide at a height of 5.1 meters above the ground.

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0.16*10^-3m is the distance between two charges according to Coulomb's Law

How does Coulomb's law work?

Coulomb listed the following characteristics of the electric field for charges in a resting state: Unlike charges draw each other while like charges repel one another. As a result, a positive charge pulls a negative charge toward it while two negative charges resist one another.

We can determine the electric force produced between two electrical charges using Coulomb's Law. In particular, it enables the determination of the direction and strength of electric energy. Coulomb's law states that the force of attraction or repulsion between two charged bodies is inversely proportional to the cube of the distance between them and directly proportional to the product of their charges. It operates on the segment connecting the two charges regarded as point charges.

F = kq1q2/r^2

460 = 9*10^9 *2.8*10^-5 *3.1*10^-7 / r^2

r = sqrt ( 9*10^9 *2.8*10^-5 *3.1*10^-7 / 460)

r = 0.16*10^-3m

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When a town puts in new power lines during the height of summer, it needs to be able to handle the increased electrical load on the power grid that will probably come from more people using air conditioners.

The power grid needs to be able to handle the increased demand for electricity that will result from the use of air conditioning when new power lines are installed. In order to guarantee that there is sufficient capacity to meet the increased demand, this may necessitate improvements to the existing infrastructure, which may include transformers, distribution lines, and substations.

In addition, it may be necessary to coordinate the installation of new power lines with the local utility company to avoid disrupting the existing power supply to homes and businesses. This may necessitate temporary power outages or other measures to guarantee that the installation goes off without a hitch and does not pose any safety risks.

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Answer:

38.22 kg

Explanation:

To use the formula F=ma to find the mass of an object, we need to know the force acting on it and its acceleration. In this case, the force acting on the object is its weight, which we can find using the equation:

weight = mass x acceleration due to gravity

The acceleration due to gravity on Earth is approximately 9.81 m/s^2. Therefore, we can write:

weight = mass x 9.81 m/s^2

We are given that the weight of the object is 375 N. Substituting this value into the equation, we get:

375 N = mass x 9.81 m/s^2

To solve for mass, we need to isolate it on one side of the equation. We can do this by dividing both sides by 9.81 m/s^2:

mass = 375 N / 9.81 m/s^2

Using a calculator, we can evaluate this expression to get:

mass = 38.22 kg

Therefore, if an object weighs 375 N, its mass is approximately 38.22 kg on Earth.

The following is example of uniform acceleration, that is : motion under force.

Uniform acceleration refers to constant rate of change in velocity, which means that acceleration of an object is constant over time. Motion under force can result in uniform acceleration if the force is constant and object is free to move in straight line.

Motion under gravity and motion under power can both result in acceleration but they are not necessarily uniform. For example,  object falling under gravity experiences constantly increasing acceleration due to increasing speed and gravitational force acting on it, which means acceleration is not uniform.

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The total distance traveled by the skier is  160 m.

option C.

Distance is a measure of how far apart two objects or points are. It can be defined as the numerical value of the physical space between two objects or points.

Distance can be measured in a variety of units, such as meters, feet, miles, or kilometers, depending on the system of measurement used.

Distance can also refer to the length of a path between two points, which can be a straight line or a curved line.

The total distance traveled by the skier is calculated as follows;

total distance = distance ( 0 min) + distance (1 min) + distance (2 min) + distance ( 3 mins)

total distance = 0 m + (120 m - 0 m) + ( 160 m - 120 m )

total distance = 0 m + 120 m + 40 m = 160 m

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Answer:

To calculate the resistance of the microwave, we can use Ohm's Law, which states that:

resistance = voltage / current

Substituting the given values into this equation, we get:

resistance = 5V / 0.3A

resistance = 16.67 ohms

Therefore, the resistance of the microwave with 5V and a current of 300mA is 16.67 ohms.

Answer:

750m/s

Explanation:

v = fλ = (1500 Hz)(0.5 m) = 750m/s

Answer:

0.5 m and 1500 Hz divided by 750 m/s equals 750 m/s.

Explanation:

Brainliest pls!

The wavelength of maximum intensity for a celestial body with a temperature of 50000 K is approximately 577 nm.

To find the wavelength of maximum intensity for a celestial body with a temperature of 50000 K, we can use Wien's displacement law, which relates the temperature of an object to the wavelength at which it emits the most radiation. The law is given by:

λ_max = b / T

where λ_max is the wavelength of maximum intensity, b is Wien's displacement constant (2.898 × 10⁻³ m·K), and T is the temperature in Kelvin.

We can convert the temperature of 50000 K to Kelvin by adding 273.15 to get:

T = 50000 K + 273.15 = 50273.15 K

Plugging in the values, we get:

λ_max = (2.898 × 10⁻³ m·K) / 50273.15 K

Simplifying, we get:

λ_max = 5.77 × 10⁻⁸ meters

To convert meters to nanometers, we can multiply by 10⁹:

λ_max = 5.77 × 10⁻⁸ meters × 10⁹ nm/m = 577 nm

Therefore, the wavelength of maximum intensity for a celestial body with a temperature of 50000 K is approximately 577 nm.

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Answer:

0.0312J

Explanation:

Given:

Want: Elastic potential energy stored in the spring

Solve:

The elastic potential energy stored in the spring can be calculated using the following formula:

Elastic potential energy = 0.5 * k * (L - L0)^2

Substituting the given values into the equation:

Elastic potential energy = 0.5 * 51.0 N/m * (0.150 m - 0.115 m)^2

Elastic potential energy = 0.5 * 51.0 N/m * (0.035 m)^2

Elastic potential energy = 0.5 * 51.0 N/m * 0.001225 m^2

Elastic potential energy = 0.0312 J

Therefore, the elastic potential energy stored in the spring when its length is 0.150 m is 0.0312 J.