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The acceleration on a body that approached the earth and comes within 6 earth radii of the earth’s surface is 0.2 m/s².

The acceleration of the body can be calculated using the equation-

g = g0 R/(R + H)².

In the question, we have, h = 6R

g = 9.8 x R/(R + 6R)²

By putting in the values and calculating, we get,

g = 0.2 m/s².

Where g' = Gravitational Acceleration at Height, R = Earth's Radius, and g = Gravitational Acceleration at Earth's Surface. As a result, at a distance of 2R from the earth's surface, the acceleration of a body caused by the earth's attraction is equal to g/9.

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The area of the bone is 0.785 m². Then the maximum force that can be exerted on the femur bone if the shear stress is 9 × 10⁷ N/m² is 70650 kN.

The Young's modulus of a material is the ratio of its stress to strain. Where stress is the force per unit area and strain be the ratio of change in length to the original length.

given stress s = 9 × 10⁷ N/m²

diameter of the bone d = 9 cm = 0.09 m.

then area = π d²/4

a = 3.14 × (0.09 m )²/4 = 0.785 m².

Stress = maximum force/area

then Fmax  = stress × area

Fmax = 9 × 10⁷ N/m²  × 0.785 m²

         = 70650 kN.

Therefore, the maximum force that can be exerted to the bone is 70650 kN.

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To lift an object off the ground a distance of 3m, Grace applies 50N of force and generates 75J/s. The time taken by Grace for the lift is 2 seconds.

A force is an effect that changes, or accelerates, the velocity of a mass-moving object (such as one that is travelling from a state of rest). It is a vector quantity since it can be a push or a pull and always has magnitude and direction. It is denoted by the letter F and is measured in newtons (N), the SI unit of force.

According to Newton's second law, an object's net force is equal to the speed at which its momentum is changing over time. This rule suggests that the acceleration of an object is directly proportional to the net force exerted on the object, is in the direction of the net force, and is inversely proportional to the mass of the object if its mass is constant.

According to the equation,

P = [tex]\frac{W}{t}[/tex]

where,

P is the power,

W is the work done and,

t is the time taken.

W = F×S

where,

F is the applied force and

S is the distance.

Substituting the values and solving for t,

time taken = 2 seconds

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Based on the densities of the two liquids, the height of the light liquid in the right arm of the U-tube is 0.203 cm.

Let's first consider the situation before the light liquid is added. At this point, the heavy liquid fills both arms of the U-tube to the same height, h.

The pressure at point A is equal to the pressure at point B

Therefore:

P₀ + ρgh = P₀ + ρgh

where P₀ is the atmospheric pressure, ρ is the density of the heavy liquid, and g is the acceleration due to gravity.

Simplifying this equation, we get:

ρgh = ρgh

Canceling out the ρ and solving for h, we get:

h = h

In other words, the height of the heavy liquid is the same in both arms of the U-tube.

Now let's consider the situation after the light liquid is added to the right arm of the U-tube. We want to find the height, L, of the light liquid in the right arm.

Since the pressure at any two points in a connected vessel is the same, the pressure at point B (the top of the heavy liquid in the right arm) must be equal to the pressure at point C (the top of the light liquid in the right arm).

Therefore, we can write:

P₀ + ρgh = P₀ + ρg(L+h)

where L is the height of the light liquid in the right arm.

Simplifying this equation, we get:

ρgh = ρgL + ρgh

Canceling out the ρgh and solving for L, we get:

L = (ρ/ρ₀)h

where ρ₀ is the density of the light liquid.

Substituting the given values, we get:

L = (0.92 g/cm³ / 13 g/cm³)h

L = 0.070769h

Now we need to find h. We can use the fact that the volume of the heavy liquid in the left arm is equal to the volume of the heavy liquid plus the light liquid in the right arm.

The volume of the heavy liquid in the left arm is:

V₁ = Ah = (13.2 cm²)(h cm)

V₁ = 13.2h cm³

The volume of the heavy liquid plus the light liquid in the right arm is:

V₂ = A(L+h) = (2.11 cm²)(L+h cm)

V₂ = 2.11(L+h) cm³

Since these volumes are equal, we can set them equal to each other and solve for h:

13.2h = 2.11(L+h)

13.2h = 2.11L + 2.11h

11.09h = 2.11L

h = (2.11/11.09)L

Substituting this into our expression for L, we get:

L = 0.070769(2.11/11.09)L

L = 0.01345L

L = 0.01444h

Substituting the given value for the density of the heavy liquid, we get:

L = 0.01444h = 0.01444(13 g/cm³)/(0.92 g/cm³)

L = 0.203 cm

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Complete question:

A heavy liquid with a density 13 g/cm³ is poured into a U-tube as shown in the left- hand figure below. The left-hand arm of the tube has a cross-sectional area of 13.2 cm², and the right-hand arm has a cross-sectional area of 2.11 cm². A quantity of 90.2 g of a light liquid with a density 0.92 g/cm³ is then poured into the right-hand arm as shown in the right-hand figure below.

Determine the height L of the light liquid in the column in the right arm of the U-tube, as shown in the second figure above. Answer in units of cm.

Answer:

less than 100-J

Explanation:

The potential energy held in the stretched rubber band is turned into kinetic energy of the rock when it is released, assuming that the rubber band is used to launch a rock from a slingshot.

The mass of the rock and the effectiveness of the slingshot in transmitting the energy from the rubber band to the rock are two elements that affect how much kinetic energy the rock will have. To estimate the kinetic energy, though, we may make certain generalizations.

Assume that no energy is lost as a result of friction or air resistance and that the entire potential energy held in the rubber band is transformed into the kinetic energy of the rock. In this hypothetical situation, the potential energy of the stretched rubber band would be equal to the kinetic energy of the rock.

As a result, the rock will have 100 J of kinetic energy when it exits the slingshot if the rubber band contains 100 J of potential energy. The actual kinetic energy of the rock would be less than 100 J since some energy will be wasted owing to things like friction.

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In a genetic cross Rr x rr the percentage of offspring will be round will be 50% since this trait is associated with the recessive genotype (rr).

The recessive genotype in a genetic cross is the proportion of offspring that will be homozygous recessive and therefore will express the recessive trait such as in this case round plants that are produced by the combination of recessive and heterozygous parents.

Therefore, with this data, we can see that recessive genotypes in a genetic cross are generated by the combination of two recessive gametes.

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Answer:

Explanation:

The formula for kinetic energy is K = 1/2mv^2, where K is kinetic energy, m is mass, and v is velocity.

Substituting the given values:

K = 1/2(2.50 kg)(2.00 m/s)^2

K = 1/2(2.50 kg)(4.00 m^2/s^2)

K = 5.00 J

Therefore, the 2.50kg ball traveling at 2.00m/s has 5.00 J of kinetic energy.

As the speed of the car was less than the posted speed limit of 50 mi/h when the brakes were applied, skid marks provide evidence that driver was not speeding at the time of incident.

Measure of the amount of friction existing between the two surfaces is called as coefficient of friction.

Change in kinetic energy is: ΔK = 0 - 1/2mv²

W = fd

As f = μN

N = mg

fd = ΔK

μN d = 1/2mv²

μmgd = 1/2mv²

v = √(2μgd/m)

v = √(20.8025*0.45/1) ≈ 29.9 mi/h

Since the car's speed was less than the posted speed limit of 50 mi/h when the brakes were applied, the skid marks provide evidence that the driver was not speeding at the time of the incident.

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Answer:

31,500 joules

Explanation:

Work = force * distance * cos(theta)

Force = 4500N (weight of the barbell)

Distance = 7m (the height lifted)

Theta = 0 (cosine of 0 degrees is 1, since the force and distance are in the same direction)

So, Work = 4500 N * 7m * cos(0)

Work = 31,500 joules

Answer:

7.75 m/s.

Explanation:

We can use the work-energy principle to solve this problem. The principle states that the work done on an object is equal to the change in its kinetic energy:

W = ΔK

where W is the work done, ΔK is the change in kinetic energy.

In this case, the work done on the ball is 45.0 J. Since the ball is initially at rest, its initial kinetic energy is zero. Therefore, the change in kinetic energy is:

ΔK = Kf - Ki = 1/2 mv^2 - 0

where Kf is the final kinetic energy, Ki is the initial kinetic energy, m is the mass of the ball, and v is its velocity.

Substituting the given values, we get:

45.0 J = 1/2 (1.50 kg) v^2

Solving for v, we get:

v^2 = (2 x 45.0 J) / (1.50 kg)

v^2 = 60.0

v = √60.0

v ≈ 7.75 m/s

Therefore, the velocity of the ball is approximately 7.75 m/s.

Answer:

Neutronic is not a defined type of energy.

Soft sand makes it challenging to ride a bicycle since the tires can't generate enough friction. The bicycle struggles to move ahead as a result, and its tires sink.

Riding a bicycle on soft sand poses a risk of the vehicle being stuck and challenging to move. Injuries might result if the rider loses balance and falls off the bicycle. The frame, tires, and other parts of the bicycle could also be harmed by the sand.

Furthermore, sand, dirt, wood chips, deep pea gravel, soft grass, and snow all drastically alter your speed. Sand, however, can be the most challenging of all of them because you typically enter the area quickly from grass or another hard surface.

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As we consider the best options for generating electricity, it is important to prioritize renewable resources over nonrenewable ones. While nonrenewable resources such as coal and natural gas may provide a quick and reliable source of energy, they have significant negative impacts on both human health and the environment. Renewable resources, on the other hand, offer a sustainable solution to our energy needs without the harmful side effects. Solar, wind, and hydro power are all viable options that have been proven effective and efficient. While the initial investment may be higher, the long-term benefits are worth the cost. As we move towards a more sustainable future, it is crucial that we prioritize renewable resources for generating electricity.

Answer:

Below

Explanation:

Final Kinetic Energy = 1/2 m v^2

           5 x 10^2 J    = 1/2 ( 5 kg)(v^2 )

                 1000 / 5 = v^2

                     200 = v^2

                         v = 10 sqrt 2      or   14.1 m/s

The vector described as "40 feet to the right" can also be expressed as a displacement vector. It represents the change in position of an object as it moves from one point to another.

Specifically, the vector denotes a horizontal displacement of 40 feet in the positive x-direction from the starting point.

Another way to describe the vector is to use a coordinate system. If we place the starting point at the origin (0,0) and define the x-axis to be the horizontal direction and the y-axis to be the vertical direction, then the vector can be represented as (40,0), where the first number corresponds to the x-coordinate and the second number corresponds to the y-coordinate. This notation emphasizes the fact that the vector has no vertical displacement, only a horizontal displacement of 40 feet.

Alternatively, we could describe the vector using magnitude and direction. The magnitude of the vector is simply its length, which in this case is 40 feet. The direction of the vector can be described as "to the right" or "in the positive x-direction." This notation is useful when comparing vectors with different magnitudes but the same direction or vice versa.

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Answer:

the asnsweis wavew

Explanation:

i just need rge points tbh

The object with the least kinetic energy, given the above instances is water with a mass of 12 Kg falling at 10 m/s (option B)

To know the object which has the least kinetic energy, we shall determine the kinetic energy of each objects. This is illustrated below:

For sand (Option A):

KE = ½mv²

KE = ½ × 120 × 12²

KE = 8640 J

For water (Option B):

KE = ½mv²

KE = ½ × 12 × 10²

KE = 60 J

For sand (Option C):

KE = ½mv²

KE = ½ × 12 × 8²

KE = 384 J

For water (Option D):

KE = ½mv²

KE = ½ × 120 × 12²

KE = 8640 J

From the above calculations, it is evident that the water with a mass of 12 Kg falling at 10 m/s has the least kinetic energy. Thus, the correct answer is option B

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The meaning of the phrase command module is a satellite designed to hold a human astronaut. The correct option is C

A spacecraft is a vehicle or machine designed to fly in outer space. A Spacecraft is a type of artificial satellite is used for a variety of purposes, including communications, Earth observation, meteorology, navigation, space colonization, planetary exploration, and transportation of humans and cargo. All spacecraft except single stage to orbit vehicles cannot get into space on their own, and require a launch vehicle (carrier rocket).

spacecraft is vehicle like designed to operate with or without a crew, in a controlled conditions inside it.

A command module is a detachable controlled compartment of a manned spacecraft. it housed the three-person crew on liftoff and landing and during the trip to and from the Moon In Apollo 14.

Hence option C is correct option

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Answer:

There are several basic ways to reduce sound: increasing the distance between source and receiver, decoupling, using noise barriers to reflect or absorb the energy of the sound waves, using damping structures such as sound baffles for absorption, or using active antinoise sound generators.

The potential energy of the mass is 0.0452 J when it is at a distance of

0.0600 m from equilibrium.

How to calculate potential energy?

The potential energy stored in a spring when it is stretched or compressed by a displacement x is given by:

[tex]$PE = \frac{1}{2}kx^2$[/tex]

where k is the spring constant.

In this problem, the spring constant is given as 26.6 N/m, and the displacement of the mass from equilibrium is

[tex](0.120 m - 0.0600 m) = 0.0600 m.[/tex]

Therefore, the potential energy stored in the spring when the mass is at a distance of 0.0600 m from equilibrium is:

[tex]$PE = \frac{1}{2}kx^2 = \frac{1}{2}(26.6 N/m)(0.0600 m)^2 = 0.0452 J$[/tex]

So the potential energy of the mass is 0.0452 J when it is at a distance of 0.0600 m from equilibrium.

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Answer: 0.0479

Explanation: This answer works for Acellus! :D

hope this helps!

Two points in the xy plane have Cartesian coordinates (5.00, −5.50) m and (−7.00, 7.00) m.So,  the distance between two points in the xy-plane is 17.32 m.

What is Distance?

Distance is a measurement in numbers of the area between two locations or objects. It is a scalar quantity that symbolises the distance between two places in space or the length of a path taken by an object. Depending on the situation and the scale of the items being measured, distance can be expressed in a variety of ways, including metres, kilometres, miles, feet, and so forth.

Displacement, a vector number that denotes the shift in an object's location with respect to a reference point, is frequently distinguished from distance in physics. Displacement, as opposed to distance, which only analyses the size of the path travelled, considers both the distance travelled by an object and its direction of motion.

To find the distance between two points in the xy-plane, we use the distance formula:

d = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]

where (x1, y1) and (x2, y2) are the coordinates of the two points.

Using the given coordinates, we have:

x1 = 5.00 m, y1 = -5.50 m

x2 = -7.00 m, y2 = 7.00 m

Substituting these values into the formula, we get:

d = [tex]\sqrt{(-7.00 - 5.00)^2 + (7.00 - (-5.50))^2}[/tex]

d= [tex]\sqrt{(-12.00)^2 + (12.50)^2}[/tex]

d= [tex]\sqrt{(144.00 + 156.25)}[/tex]

d= [tex]\sqrt{(300.25)}[/tex]

d=17.32 m

Therefore, the distance between the two points is approximately:

d = 17.32 m (rounded to two decimal places)

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The force required to lift a load of 100 newtons using machine with mechanical advantage of 4 is 25 newtons.

The ratio of output force to the input force is called as mechanical advantage of a machine. In this case, mechanical advantage is given as 4.

As, Mechanical Advantage = Output Force / Input Force

4 = Output Force / Input Force

So, Output Force = Mechanical Advantage x Input Force

Output Force = 4 x Input Force

100 newtons = 4 x Input Force

Input Force = 100 newtons / 4

Input Force = 25 newtons

Therefore, the force required to lift a load of 100 newtons using a machine with a mechanical advantage of 4 is 25 newtons.

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According to the question the clay ball moves with a velocity of 2.5 m/s after the collision.

Velocity is the speed of an object in a specific direction. It is a vector quantity and is typically represented by the symbol v. It is the rate of change of an object's position and is expressed in units of distance divided by time, such as meters per second (m/s). Velocity can be constant, meaning the object is traveling at a steady speed, or it can be changing, meaning the object is accelerating or decelerating.

The answer is 2.5 m/s. This is because the total momentum of the system (BB + clay ball) before the collision is 0 (since the clay ball is stationary). Therefore, the total momentum of the system after the collision is 0 as well. Using the equation for momentum (p = mv), we can calculate the velocity of the clay ball after the collision.

p (total) = 0 = (0.35 g) (46 m/s) + (6.0 g) (v)

v = -2.5 m/s

Therefore, the clay ball moves with a velocity of 2.5 m/s after the collision.

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When a ball leaves a ramp with a horizontal velocity, it will follow a curved path known as a projectile motion. The ball will move both horizontally and vertically, with the horizontal velocity remaining constant and the vertical velocity changing due to the force of gravity.

At the point where the ball leaves the ramp, it will have a certain height and horizontal distance from the starting point. As it moves through the air, it will travel a certain horizontal distance before landing on the ground at a lower height.

Projectile motion is a type of motion in which an object is launched or thrown into the air, and then moves under the influence of gravity and air resistance. In projectile motion, the object follows a curved path called a trajectory, which consists of both horizontal and vertical components.

The motion of a projectile can be described in terms of its velocity, acceleration, and displacement. At the instant of launch, the object has an initial velocity that can be broken down into horizontal and vertical components. The horizontal component of velocity remains constant throughout the motion, while the vertical component changes due to the effect of gravity.

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Revolutions per minute are needed for the space station which is at 385m from center of the planet is 1.52 rev/min

Orbital velocity is also called as critical velocity. It is minimum velocity must be given to the satellite or the body, so that it can revolve around the planet. i.e. orbital velocity is minimum velocity of body to revolve in stable orbit around a planet.

Orbital velocity is given by,

[tex]v_{c} = \sqrt{\frac{GM}{R+h}}[/tex] where  G = Gravitational constant (6.673×10⁻¹¹ Nm²/kg²

                               M = Mass of the planet

                               R = Radius of the planet

                                h = height of the object(satellite)

Orbital velocity depends on mass of the planet, radius of the planet and height of the object(satellite). It is independent of mass of the body(satellite).

Given,

Diameter of space station, D = 770m {Radius (R+h) = 385m}

Acceleration due to gravity [tex]g_{h}[/tex]= 9.8 m/s²

our given equation is,

[tex]v_{c} = \sqrt{\frac{GM}{R+h}}[/tex]

[tex]v_{c}^{2} = \frac{GM}{R+h}}[/tex].........1)

we know that v=rω

v²=r²ω²

where r = (R+h) = Radius of planet + height of space station from surface of the planet.

v²=(R+h)²ω²......2)

with equation 2), equation 1 becomes.

(R+h)²ω² = [tex]\frac{GM}{R+h}}[/tex]

ω² = GM÷ (R+h)³.............3)

we know that [tex]g_{h} = \frac{GM}{(R+h)^{2} }[/tex].....4)

equ 3 becomes,

ω² = [tex]\frac{g_{h}}{(R+h)}[/tex]

Putting all values in equation,

ω² = 9.8 ÷ 385

ω² = 0.025454

ω = 0.1595 ≅ 0.16 rad/s

let,

ω = 2πn

n= ω ÷ 2π

n = 0.02547 rev/s

n= 0.02547*60 = 1.52 rev/min

Hence 1.52 rev/min is needed for space station at artificial gravity of 9.8 m/s

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Since the initial velocity of ball A was 3.3 m/s east and the velocity of ball A after the collision is 6.7 m/s east, the velocity of ball A after the collision is 3.7 m/s east.

Velocity is a vector quantity that measures the rate and direction of an object's motion. It can be determined by measuring the displacement of the object over a certain period of time. Velocity is usually expressed in terms of distance per unit of time, such as meters per second (m/s). In physics, velocity is a fundamental concept that is used to describe the motion of objects.

The velocity of ball A after the collision can be calculated using the conservation of momentum equation. The equation is as follows:

m1v1 + m2v2 = m1v1' + m2v2'

where m1 is the mass of ball A, v1 is the initial velocity of ball A, m2 is the mass of ball B, v2 is the initial velocity of ball B, m1' is the mass of ball A after the collision, v1' is the velocity of ball A after the collision, m2' is the mass of ball B after the collision, and v2' is the velocity of ball B after the collision.

In this problem, the equation is:

(0.62 kg)(3.3 m/s east) + (0.62 kg)(1.6 m/s west) = (0.62 kg)(v1') + (0.62 kg)(1.2 m/s east)

We can solve this equation for v1':

(0.62 kg)(3.3 m/s east) + (0.62 kg)(1.6 m/s west) = (0.62 kg)(v1') + (0.62 kg)(1.2 m/s east)

0.62(3.3 + 1.6) = 0.62v1' + 0.74

4.9 = 0.62v1' + 0.74

4.9 - 0.74 = 0.62v1'

4.16 = 0.62v1'

v1' = 6.7 m/s east

Since the initial velocity of ball A was 3.3 m/s east and the velocity of ball A after the collision is 6.7 m/s east, the velocity of ball A after the collision is 3.7 m/s east.

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The 35m would the Roche limit be for an earth-orbiting body with the same density as iron(8.0g/cm ^3).

What is density ?

How much material an object contains per unit volume is determined by the density of the substance. It is symbolized by the letter D, however it can also be represented by the symbol.  The density of a substance reveals how dense it is in a certain space. The definition of density is the mass of a substance per unit volume.

It is measured in meters per second in the SI (ms -1 ). A body is considered to be accelerating if there is a change in the magnitude or direction of its velocity.

Therefore, The 35m would the Roche limit be for an earth-orbiting body with the same density as iron(8.0g/cm ^3).

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The object with the greatest kinetic energy is the locomotive engine (option C)

To know the object with the greatest kinetic energy, we shall determine the kinetic energy of each objects. Details below:

For truck:

KE = ½mv²

KE = ½ × 3500 × 30²

KE = 1575000 J

For baseball:

KE = ½mv²

KE = ½ × 0.5 × 46.9²

KE = 549.90 J

For locomotive:

KE = ½mv²

KE = ½ × 205000 × 5²

KE = 2562500 J

For person:

KE = ½mv²

KE = ½ × 73 × 6²

KE = 1314 J

From the above calculations, we can see that the locomotive has the greatest kinetic energy. Thus, the correct answer is option C

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The volume (in gallon) of water that have the same mass as the bar of gold is 0.153 gallon

We'll begin by obtaining the mass of the gold bar. This is given below:

Density = mass / volume

Cross multiply

Mass = Density × Volume

Mass of gold bar = 19300 × 0.00003

Mass of gold bar = 0.579 Kg

Finally, we shall determine the volume of water having the same mass as 0.579 Kg of the gold bar. Details below:

Volume = mass / density

Volume of water = 0.579 / 1000

Volume of water = 0.000579 m³

Multiply by 264.172 to express in gallon

Volume of water = 0.000579 × 264.172

Volume of water = 0.153 gallon

Thus, we can conclude that the volume of the water is 0.153 gallon

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