PLEASE HELP ASAP!!!!!!


Describe the graph of a function g by observing the graph of the base function ƒ.


g(x) = ƒ(x + 5) + 3

g(x) = ƒ(x + 3) + 5

g(x) = 2ƒ(x + 3)

g(x) = ƒ(x – 3) – 5

Answer:

[tex]\frac{\sqrt{10} }{2}[/tex]

Step-by-step explanation:

on a 45 - 45 - 90 triangle if the sides are x then the hypotenuse is x[tex]\sqrt{2}[/tex]

so,

[tex]\sqrt{5}[/tex] = x[tex]\sqrt{2}[/tex]                  (Divide by [tex]\sqrt{2}[/tex] )

[tex]\frac{\sqrt{5} }{\sqrt{2} }[/tex] = x                        (rationalize the denominator)

[tex]\frac{\sqrt{5} }{\sqrt{2} }[/tex] · [tex]\frac{\sqrt{2} }{\sqrt{2} }[/tex] = [tex]\frac{\sqrt{10} }{\sqrt{4} }[/tex] = [tex]\frac{\sqrt{10} }{2}[/tex]

The length of side is √10/2

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

The given triangle is a 45-90-45 so if the sides are x then the hypotenuse will be x√2

From the figure the hypotenuse of triangle is √5

SO equation it to x√2

We get √5=x√2

Divide both sides by √2

√5/√2=x

As the denominator should be a whole number we have to rationalize the denominator.

Multiply numerator and denominator with √2

√5/√2×√√2/√2

√10/2

Hence, the length of side is √10/2

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Answer:

See Explanation

Step-by-step explanation:

If a Function is differentiable at a point c, it is also continuous at that point.

but be careful, to not assume that the inverse statement is true if a fuction is Continuous it doest not mean it is necessarily differentiable, it must satisfy the two conditions.

                                          And

If function is differentiable at a point x, then function must also be continuous at x. but The converse does not hold, a continuous function need not be differentiable.

Given equation of the Circle is ,

[tex]\sf\implies x^2 + y^2 = 25 [/tex]

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

[tex]\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2[/tex]

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

[tex]\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }[/tex]

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

Answer:

Well the correct answer is 9=2+(x/3) or

(3/x)+2=9

Answer:

Um

Step-by-step explanation:

Its half of diameter

Are you thinking of circumference and area?

Answer:

60500

Step-by-step explanation:

110 x 550

= 60500

Answer:

60500

Step-by-step explanation:

caculator lol 110×550

Answer:

A. 2(I + w)

Step-by-step explanation:

The space bounded by a rectangle is its perimeter. So, I would use 2(l + w) where l = length of rectangle and w = width of rectangle.

As an example, suppose we have a rectangle of length, l = 40 meters and width, w = 20 meters and seek to find its perimeter that is, the space bounded by the rectangle, we substitute the values of l and w into the equation for the perimeter.

So, P = 2(l + w)

substituting the values of l and w into the equation, we have

P = 2(l + w)

P = 2(40 m + 20 m)

P = 2(60 m)

P = 120 m

So the space bounded by the rectangle is 120 m.

So, to find the space bounded by a rectangle, we use 2(l + w).

So, the answer is A.

Answer:

{-10. -9, -8}

Step-by-step explanation:

x ≤ -8 would be all values of x less than or equal to -8

x = -8, -9, -10

Answer:

[tex]x=8,\\y\approx 6.9[/tex]

Step-by-step explanation:

The side lengths of all 30-60-90 triangles are in ratio [tex]x:x\sqrt{3}:2x}[/tex], where [tex]2x[/tex] is the hypotenuse of the triangle and [tex]x[/tex] is the side opposite to the 30 degree angle.

In the given diagram, the side labelled 4 is opposite to the 30 degree angle. Since [tex]x[/tex] is labelled as the hypotenuse of the triangle, [tex]x[/tex] must be [tex]4\cdot 2=\boxed{8}[/tex].

Variable [tex]y[/tex] must then represent [tex]x\sqrt{3}[/tex] for [tex]x=4[/tex], yielding [tex]y=4\sqrt{3}\approx \boxed{6.9}[/tex]

Given:

In quadrilateral EFGH, [tex]FG\parallel EH,\angleE\cong \angle H,EF=4n-4,FG=3n+3, GH=2n+6[/tex]

To find:

The length of segment GH.

Solution:

Draw a figure according to the given information as shown below.

In quadrilateral EFGH, [tex]FG\parallel EH,\angleE\cong \angle H[/tex], it means the quadrilateral EFGH is an isosceles quadrilateral because base angles are equal.

Now, quadrilateral EFGH is an isosceles quadrilateral, so the sides EF and GH are equal.

[tex]EF=GH[/tex]

[tex]4n-4=2n+6[/tex]

[tex]4n-2n=4+6[/tex]

[tex]2n=10[/tex]

Divide both sides by 2.

[tex]n=\dfrac{10}{2}[/tex]

[tex]n=5[/tex]

Now,

[tex]GH=2n+6[/tex]

[tex]GH=2(5)+6[/tex]

[tex]GH=10+6[/tex]

[tex]GH=16[/tex]

Therefore, the correct option is C.

Answer:

the answer is C

Step-by-step explanation:

:]

Answer:

?=83 degrees

Step-by-step explanation:

74+120=194

360-194=166

166÷2=83

You divide by two because it is an inscribed angle, so it will always be half the measure of the arc it is inscribing or enclosing.

Answer:

I am a piano so yeah I'm just typing to fill the character requirement

Step-by-step explanation:

get got

Answer:

12

Step-by-step explanation:

Multiply to get the number of girls they've given you.

3 x 6 = 18 girls.

2 x 6 = 12 boys.

Answer:

Number of boys = 12

Step-by-step explanation:

Let the total number of children in the class be x

Number of girls = 18

Number of boys = x - 18

Ratio of girls and boys = 3 : 2

Sum of the ratio = 5

Find the value of x

[tex]\frac{3}{5 } \times x = 18\\\\3 \times x = 18 \times 5\\\\x = \frac{90}{3} = 30[/tex]

Therefore, total number of children in the class = 30

Hence number of boys  = x - 18 = 30 - 18 = 12

Answer:

810

Step-by-step explanation:

(-5)×(-6) = 30

9*3 = 27

27*30 = 810

Answer:

[tex]g(-2)=20[/tex]

Step-by-step explanation:

Given [tex]g(x)=2x^2-2x+8[/tex], substitute what is in the parentheses for [tex]x[/tex] to find an output.

For [tex]g(-2)[/tex], the term [tex]-2[/tex] is in the parentheses. Thus, substitute [tex]x=-2[/tex] into [tex]2x^2-2x+8[/tex] to find [tex]g(-2)[/tex]:

[tex]g(-2)=2(-2)^2-2(-2)+8,\\g(-2)=2\cdot 4+4+8,\\g(-2)=8+4+8,\\g(-2)=\boxed{20}[/tex]

Answer:

a) 8

b) 20

c) 20

Step-by-step explanation:

a) Insert X=0 from g(0) to the equation: 2(0) power of 2 - 2x0 +8.

b) Insert X=(-2) from g(-2) to the equation: 2(-2) power of 2 - 2x(-2) +8.

c) Insert X=3 from g(3) to the question 2(3) power of 2 - 2x3 +8.

Answer:

[tex] \large{ \tt{❃ \: TAKING \: \angle \: \: A \: AS \: A \: ANGLE \: OF \: REFERENCE : }}[/tex]

[tex] \large{ \tt{❁ \: sin \: 60 \degree = \frac{perpendicular}{hypotenuse} }}[/tex]

[tex] \large{ \tt{➝ \: \frac{ \sqrt{3} }{2} = \frac{6}{y} }}[/tex]

[tex] \large{ \tt{➝ \sqrt{3}y = 6 \times 2 }}[/tex]

[tex] \large{ \tt{➝ \: \sqrt{3} \: y = 12 }}[/tex]

[tex] \large{ \tt{➝ \: y= \frac{12}{ \sqrt{ 3} } }}[/tex]

[tex] \boxed{ \large{ \tt{➝ y = \: 4 \sqrt{3} }}}[/tex]

[tex] \large{ \tt{❇ \: TAKING \: \angle \: B \: AS \: THE \: ANGLE \: OF \: REFERENCE}} : [/tex]

[tex] \large{ \tt{❊ \: sin \: 30 \degree = \frac{perpendicular}{hypotenuse} }}[/tex]

[tex] \large{ \tt{⟶ \: \frac{1}{2} = \frac{x}{4 \sqrt{3} } }}[/tex]

[tex] \large{ \tt{⟶ \: 2x = 4 \sqrt{3} }}[/tex]

[tex] \large{ \tt{⟶ \: x = \frac{4 \sqrt{3} }{2} }}[/tex]

[tex] \boxed{\large{ \tt{⟶ \: x = 2 \sqrt{3} }}}[/tex]

[tex] \boxed{ \large{ \tt{❈ \: OUR \: FINAL \: ANSWER : \boxed{ \tt \: x = 2 \sqrt{3} \: \: y = 4 \sqrt{3} }✓}}}[/tex]

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Answer:

2,-12

Step-by-step explanation:

The given equation is ,

[tex]\implies |x + 5 | = -7 [/tex]

We know that modulus only gives positive value , Therefore on squaring both sides we have ,

[tex]\implies (x + 5 )^2=( -7)^2 \\\\\implies (x+5)^2=7^2\\\\\implies x + 5 =\pm 7 \\\\\implies x = 7-5,-7-5 \\\\\implies \boxed{ x = 2, -12} [/tex]

Answer:

x = 9/2     y = 0

Step-by-step explanation:

2/3x + 5y = 3            5y = -2/3x + 3                y = -2/15x + 3/5

4/3x - 2(-2/15x + 3/5) = 6

4/3x + 4/15x - 6/5 = 6

8/5x - 6/5 = 6

8/5x = 36/5

x = 9/2

2/3(9/2) + 5y = 3

3 + 5y = 3

5y = 0

y = 0

Answer:

c: y=(x-1)(x-3)

Step-by-step explanation:

Answer:

domain=1

range= -2

hope it helps

Answer:

15 hour(s) and 30 minute(s).

Step-by-step explanation:

Answer:

krkrkrl4k3?8999kekek

Step-by-step explanation:

the UK. I have been a while. I have been a while. I have been a while. I have been a while 6e5 the UK. I have been a while. I have been a while. I have

. How do we have a look at the moment. The comments for the first time in the UK. I

Answer:

x=-3 and y=-2

Step-by-step explanation:

let the numbers be x and y

x+y=-5

x-y=-1

therefore x=-5-y

-5-y-y=-1

-2y=-1+5

-2y=4

y=-2

×=-5-(-2)

x=-5+2

x=-3

Answer: -2 and -3

Step-by-step explanation:

x + y = -5

x - y = -1 -> x = y - 1

(y - 1) + y = -5

y - 1 + y = -5

2y = 1 - 5

2y = -4

y = -2

x = y - 1 = -2 - 1 = -3

Answer:

The final result is 7/10

the "divisions" (divisor) is 1/10

thus the answer is 7/10 ÷ 1/10

the actual operation ....

"to divide fractions we INVERT and Multiply"

7/10 * 10/1 = 70/10 = 7

there are 7 arrows going to the right

Step-by-step explanation:

Answer:

α = 0.63 radians

Step-by-step explanation:

We are given;

Length of arc; L = 1.6 mm

Radius; r = 2.54 mm

The arc length equation is given by;

L = αr

Where;

L is length of arc

r is radius

α is angle in radians

Thus;

α = L/r

α = 1.6/2.54

α = 0.63 radians

They have a total time of 3 hours and they equally spend at each exhibit which means that they spent 18 minutes on each exhibit.

The four fundamental operations of arithmetic are addition, subtracting, multiplying, and dividing two or more numbers. Included is the study of integers, especially the order of operations, which is essential for all other aspects of mathematics, notably algebra, information management, and geometry.

As per the given information in the question,

Total time = 3 hours

Time in minutes = 3 × 60 = 180 minutes

They have 10 exhibits to visit.

The time spent on each exhibit is,

180/10 = 18 minutes on each exhibit.

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Answer:

The area is 22.5 units

The perimeter is 24.3 units

Step-by-step explanation:

The formula for the area of a triangle is A=bh(1/2)

So, base*height (5*9) is 45. Divide that by 2, and you get 22.5.

To find the perimeter, it looks like the triangle is a right triangle. To solve for that, use the Pythagorean theorem formula: a2 + b2 = c2.

5^2+9^2=c^2

25+81=106=c^2

Find the square root of 106

10.2956301

If your teacher usually asks to round, round.

I'll just round to the tenths place. 10.3

Add all the sides: 5+9+10.3

You get 24.3

Answer:

perimeter= 24.29

area=22.5

Step-by-step explanation:

a^2+b^2=c^2

5^2+9^2=106

106^(1/2)=10.29

perimeter= sum of all sides

""= 5+9+10.29

""=22.29

area= base × height ÷ 2

""= (5×9)÷2

""=22.5

Answer: b and c

a) 5x + 5 = -4x - 5

9x = - 10

x = -10/9

-

b) - 4x + 5 = -4x - 4

0x = -9 (no solution)

-

c) -4x + 5 = -4x - 5

0x = -10 (no solution)

-

d) 4x + 5 = -4x + 5

8x = 0

x = 0

-

hope it helps.

Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.

Answer:

pls give brainliest even if u dont want to. it will make u better person. when u give brainliest it makes u 3 times smarter

Step-by-step explanation:

Smith overtakes the bus at (2/3)×60=40 minutes

A body is said to have speed v if he travels v distance in unit time.

Suppose that Smith overtakes the bus at a time 't'. Then the distance traveled by bus is 48×t m and that by Smith is 64×(t-1/6).

Smith needs t-1/6 hours to reach the same position that the bus is in.

Since Smith leaves ten minutes later hence it takes t-1/6 hours for him to overtake the bus.

Because 10 minutes is equal to 10/60=1/6 hour.

So,

48×t=64×(t-1/6)

⇒t=2/3

Hence, Smith overtakes the bus at (2/3)×60=40 minutes

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