Answer:
Step-by-step explanation:
As per the same approach I answered in a similar problem:
The slope is the Rise/Run between the two points. The change in y for every change in x. Take the two points and calculate theRise/Run:
RISE = (-11 - 9) = -20
RUN = (3 - (-2)) = 5
Rise/Run, or slope, is = -20/5 or -4
I graphed this line and the two points (attached).
Answer:
-20/5 or -4
Step-by-step explanation:
Answer:
Step-by-step explanation:
As per the same approach I answered in a similar problem:
The slope is the Rise/Run between the two points. The change in y for every change in x. Take the two points and calculate theRise/Run:
RISE = (-11 - 9) = -20
RUN = (3 - (-2)) = 5
Rise/Run, or slope, is = -20/5 or -4
The river is 602 feet wide at Big Bend Corner. A boy is in the shallow
water, 135 feet from the shore. How far is the boy from the other side of
the river?
we conclude that the distance to the other side is 467 feet.
How far is the boy from the other side of the river?
We know that the width of the river is 602ft. This means that the distance from shore to shore is 602 feet.
If the boy is at a distance of 135 from the shore, then the distance to the other side is given by the difference:
d = 602ft - 135ft = 467ft
Then, we conclude that the distance to the other side is 467 feet.
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Consider the function . find the vertical asymptote(s) of f(x). x = 0, –9 x = –9 x = 0, 9 x = 9
The vertical asymptote of f(x) is (A) x = 0, –9.
What is a function?A function is an expression, rule, or law in mathematics that describes a relationship between one variable (the independent variable) and another variable (the dependent variable). Functions are common in mathematics and are required for the formulation of physical relationships in the sciences.To find the vertical asymptote of f(x):
The vertical asymptotes of a function are the zeroes of the denominator of a rational function
The function is given as: [tex]f(x) = \frac{(x-9)}{(x^{3} -81x)}[/tex]
Set the denominator to 0:
[tex]x^{3} -81x=0[/tex]Factor out x:
[tex]x(x^{2} -81)=0[/tex]Express 81 as 9^2:
[tex]x(x^{2} -9^{2} )=0[/tex]Express the difference between the two squares:
[tex]x(x-9)(x+9)[/tex]Split, [tex]x=0[/tex] or [tex]x=-9[/tex] or [tex]x+9=0[/tex].
Solve for x:
[tex]x=0\\[/tex] or [tex]x=-9[/tex] or [tex]x+9=0[/tex].Therefore, the vertical asymptote of f(x) is (A) x = 0, –9.
(See attachment for the graph of f(x))
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The complete question is given below:
Consider the function f(x)=(x-9)/(x^3-81x) . find the vertical asymptote(s) of f(x).
A) x = 0, –9
B) x = –9
C) x = 0, 9
D) x = 9
Graph f(x) = 2x - 3 on a coordinate plane.
Can you explain what you are going to do in order to graph this equation?
What do you expect the graph to look like?
Answer:
Create a table.
Plug values into the equation to complete the table.
Use the table to plot points on the graph.
Draw lines through the points on your graph.
The graph should look linear because there is an x that doesn't have a power greater than or less than 1.
Use the definition of a Taylor series to find the first three non zero terms of the Taylor series for the given function centered at a=1. Write the Taylor series in summation notation
Answer:
[tex]e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...[/tex]
[tex]\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n[/tex]
Step-by-step explanation:
Taylor series expansions of f(x) at the point x = a
[tex]\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...[/tex]
This expansion is valid only if [tex]\text{f}\:^{(n)}(a)[/tex] exists and is finite for all [tex]n \in \mathbb{N}[/tex], and for values of x for which the infinite series converges.
[tex]\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1[/tex]
[tex]\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...[/tex]
[tex]\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}[/tex]
[tex]\text{f}(x)=e^{4x} \implies \text{f}(1)=e^4[/tex]
[tex]\text{f}\:'(x)=4e^{4x} \implies \text{f}\:'(1)=4e^4[/tex]
[tex]\text{f}\:''(x)=16e^{4x} \implies \text{f}\:''(1)=16e^4[/tex]
Substituting the values in the series expansion gives:
[tex]e^{4x}=e^4+4e^4(x-1)+\dfrac{16e^4}{2}(x-1)^2+...[/tex]
Factoring out e⁴:
[tex]e^{4x}=e^4\left[1+4(x-1)+8}(x-1)^2+...\right][/tex]
Taylor Series summation notation:
[tex]\displaystyle \text{f}(x)=\sum^{\infty}_{n=0} \dfrac{\text{f}\:^{(n)}(a)}{n!}(x-a)^n[/tex]
Therefore:
[tex]\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n[/tex]
general term for -13, -11, -9, -7
The general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.
Arithmetic progression-13, -11, -9, -7
First term, a = -13Second term = -11Common difference, d = Second term - first term
= -11 - (-13)
= -11 + 13
= 2
Therefore,
Tn = a + (n - 1)d
Where,
n = number of termsTn = a + (n - 1)d
= -13 + (n - 1)2
= -13 - 2n - 2
Tn = -15 - 2n
So therefore, the general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.
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A population of n = 10 scores has = 50 and = 5. what is the population variance? 5
The value of the Population Variance is 100.
According to the statement
we have given that the A population of N = 10 scores has μ = 50 and σ = 5. And we have to find the population variance.
So, For this purpose,
we know that the population variance can be defined as the average of the distances from each data point in a particular population to the mean squared, and it indicates how data points are spread out in the population.
Population variance = mean /(standard deviation/number of samples)
Population variance = μ / (σ /N )
Substitute the values in it and then
Population variance = 50 / (5 /10 )
Population variance = 50 / (0.5 )
Population variance = 100.
So, The value of the Population Variance is 100.
Disclaimer: This question was incomplete. Please find the full content below.
Question:
A population of N = 10 scores has μ = 50 and σ = 5. What is the population variance?
a. 10
b. the square root of 5
c. the square root of 50
d. 25
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Algebra 3, in the excercise size the graphs to determine the functions domain and range, x and y intercepts if any, and the functions values indicated below the graphs
Answer:
Read explanation
Step-by-step explanation:
I answered another one of your questions just like this in detail so I'll keep this one shorter.
Domain: (-∞, 0]
Range: (-3,∞)
x-intercept: Approximately -3.75
y=intercept: -3
what is the digit of 7 in 906point7
1. Find the length of a.
Answer:
Step-by-step explanation:
[tex]\dfrac{ 1 }{ 2 } \times 12\times 15\times \sin ( 110 )[/tex]
==> 84.57
Janice walks 2 kilometers every morning. how many meters does janice walk each day? a) 0.20 meters b) 20 meters c) 200 meters d) 2,000 meters
Answer: 2000 meters
Step-by-step explanation: A kilometer means 1,000 meters a kilo means 1000. So, 2 x1000 = 2000 meters.
You start at (-4, 0). You move left 1 unit and down 5 units. Where do you end?
Answer: (-5, -5)
Step-by-step explanation:
(-4, 0)
Here, -4 is our x value and 0 is our y value
The x value moves horizontal (left and right) while the y value moves vertical (up and down)
If we move 1 unit left, we change x by -1 so, -4 -1 = -5
If we move 5 units down, we change y by -5 so, 0 -5 = -5
Therefore,
our new endpoint is: (-5, -5)
Which of the following fractions has the largest value 11/20 10/21 9/19 8/17 or 6/13
Answer:
11/20
Step-by-step explanation:
You could turn them all into equivalent fractions, but the common denominator would be 1,763,580. Yuck.
Look at the relationship for the numerators to the denominators. The only numerator that is more than half of its denominator is 11/20. Half of 20 would be 10 and 11 has a larger value than 10, so as a decimal, it would be more than .5. All of the other numerators are less than half, so that they have to less than .5.
If you changed all of the numbers to decimals, you would see that 11/20 has the largest value.
In quadrilateral qrst, angle r s t measures (5x 15)°. angle tqr measures (4x 3)°. circle p is inscribed with quadrilateral q r s t. what is the measure of angle rst?
The measure of the angle rst is [tex]105^{o}[/tex].
What is the inscribed quadrilateral theorem?According to the theorem, a quadrilateral can be inscribed by a circle if and only if its opposing angles are supplementary. A quadrilateral that may be encircled by a circle is known as a cyclic quadrilateral.
The sum opposite angles of a quadrilateral is 180 degrees.
We can see that the angles rst and angle tqr are opposite angles of quadrilateral qrst, hence supplementary angles.
Therefore,
<RST + <TQR = 180
5x+15 + 4x+ 3 = 180
9x + 18 = 180
9x = 180 - 18
9x = 162
x = 162/9
x = 18
Since <RST = 5x+15
<RST = 5(18) + 15
<RST = 90 + 15
<RST = 105degrees
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Pls help I’ll brainlest
Asap
Answer:
C. slope
Greetings !
The symbol for slope is "m". Slope can be calculated by taking any two locations along a line and calculating the ratio of the RISE to the RUN (the ratio of the difference between vertical positions of the locations to the difference between horizontal positions of the locations).
Answer: slope.
Step-by-step explanation:
Use the given data set to complete parts (a) through (c) below. (Use α=0.05.)
1. The value of the linear correlation coefficient r is given as 0.8159. The correct option is a. There is insufficient evidence to support the claim of a nonlinear correlation between the two variables
2. The scatterplot reveals a distinct pattern that is not a straight-line pattern.
What is the linear correlation coefficient?This is the data that we get when we try to get the existing relationship that is in existence between the variables that are used in a regression equation.
The value of r was calculated using a statistical tool online. The graph showed us it was not a straight line. The value of the r = 0.8159
The results of the test is in the attachment
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Después de 15 meses de haber prestado un capital al 5% de rédito, tengo que pagar de interés Q468.75. ¿Qué capital se ha prestado?
The capital borrowed, or the principal when the interest was Q468.75 is Q7500.
The principal P, amount borrowed, at a certain rate of interest R%, for a time of T years, giving an interest of I, can be calculated using the formula:
P = (I * 100)/(R * T).
In the question, we are asked to find the capital borrowed, that is, the principal, when the user pays Q468.75 after 15 months at 5% of income.
Thus, Interest (I) = Q468.75, rate of interest (R) = 5%, and time (T) = 15 months = 15/12 years = 1.25 years.
Thus, the principal P, can be calculated by substituting the values in the formula: P = (I * 100)/(R * T).
P = (468.75*100)/(5*1.25),
or, P = 46875/6.25,
or, P = 7500.
Thus, the capital borrowed, or the principal when the interest was Q468.75 is Q7500.
The provided question is in Spanish. The question in English is:
"After 15 months of having borrowed capital at 5% of income, I have to pay Q468.75 in interest. What capital has been borrowed?"
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Do the data in the table represent a direct variation or inverse variation? Write an equation to model the data in the table?
x 2 4 8 12
y 4 2 1 2/3
Based on the given data; the table represent an inverse variation and the equation that model the data in the table is y = 8/x
VariationDirect variationy = k × x
4 = k × 2
4 = 2k
k = 4/2
k = 2
when y = 2 and x = 4
y = k × x
= 2 × 4
y = 8
Indirect variationy = k/x
4 = k / 2
8 = k
when y = 2 and x = 4
y = k/x
2 = k/4
2 × 4 = k
k = 8
So,
y = k/x
y = 8/x
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1
2. Rotate Rectangle ABCD 90° counterclockwise.
Then, translate it along the vector (3,4).
A
D
B
C
-4 -2
4
2
АУ
O
-2.
-4
2
4
X
A'(
B'(
C'(
D'(
A"(
B"(
C"(
D"(
)
)
)
)
HELP ME PLS
Rotating 90 degrees counterclockwise: [tex](x,y) \longrightarrow (-y,x)[/tex]
[tex]A(-4,4) \longrightarrow A'(-4, -4)\\\\B(-3, 4) \longrightarrow B'(-4, -3)\\\\C(-3, 1) \longrightarrow C'(-1, -3)\\\\D(-4, 1) \longrightarrow D'(-1, -4)[/tex]
Translate along [tex]\langle 3, 4 \rangle[/tex]: [tex](x,y) \longrightarrow (x+3, y+4)[/tex]
[tex]A'(-4, -4) \longrightarrow A''(-1, 0)\\\\B'(-4, -3) \longrightarrow B''(-1, 1)\\\\C'(-1, -3) \longrightarrow C''(2, 1)\\\\D'(-1, -4) \longrightarrow D''(2, 0)[/tex]
What would cause an Inequality sign in an equation to flip?
a.) When dividing both sides by a negative.
b.) When adding a negative to both sides.
c.) When multiplying a fraction by both sides.
d.) When subtracting a negative to both sides.
Answer:
When dividing both sides by a negative.
Step-by-step explanation:
When dividing OR multiplying both sides by a negative, we need to flip the inequality signs.
Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ?
Step-by-step explanation:
log 6 = log (2×3) = log 2 + log 3 = 0.3010+0.4771
=0.7781
Answer:
[tex]\sf \log_{10}6=0.7781[/tex]
Step-by-step explanation:
Given:
[tex]\sf \log_{10} 2 = 0.3010[/tex]
[tex]\sf \log_{10} 3 = 0.4771[/tex]
To find log₁₀ 6, first rewrite 6 as 3 · 2:
[tex]\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)[/tex]
[tex]\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay[/tex]
[tex]\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2[/tex]
Substituting the given values for log₁₀ 3 and log₁₀ 2:
[tex]\begin{aligned} \sf \implies \log_{10}3+\log_{10}2 & = \sf 0.4771+0.3010\\ & = \sf 0.7781 \end{aligned}[/tex]
Therefore:
[tex]\sf \log_{10}6=0.7781[/tex]
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please help 14 points ASAP
Here are yesterday's high temperatures (in Fahrenheit) in 12 U.S. cities. 48, 50, 54, 56, 63, 63, 64, 68, 74, 74, 79, 80 Notice that the temperatures are ordered from least to greatest. Give the five-number summary and the interquartile range for the data set. Five-number summary
Minimum:
Lower quartile:
Median: Upper quartile:
Maximum:
Interquartile range:
The desired measures for the data-set is given by:
Minimum: 48Lower quartile: 54.Median: 63.5.Upper quartile: 74.Maximum: 80.IQR: 20How to find the five number summary and interquartile range of the data-set?The five number summary is composed by the measures explained below, except the IQR.
The minimum value is the smallest value from the data-set, as the maximum value is the greatest value of the data-set.The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.The first quartile is the median of the first half of the data-set.The third quartile is the median of the second half of the data-set.The interquartile range is the difference of the third quartile and the first quartile.In this problem, we have that:
The minimum value is the smallest value, of 48.The maximum value is the smallest value, of 80.The data-set has even cardinality, hence the median is the mean of the middle elements, which are 63 and 64, hence the median is of 63.5.The first quartile is the median of the five elements of the first half, hence it is of 54.The third quartile is the median of the five elements of the second half, hence it is of 74.The IQR is the difference between the quartiles, hence 74 - 54 = 20.More can be learned about five number summaries at brainly.com/question/17110151
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What is the solution for x in the equation?
10x − 4.5 + 3x = 12x − 1.1
x =
Answer: x= 3.4
Step-by-step explanation:
Solve for x by simplifying both sides of the equation, then isolating the variable.
Answer:
x = 3.4
Step-by-step explanation:
[tex]10x - 4.5 + 3x = 12x -1.1 \\ 13x - 4.5 = 12x - 1.1 \\ 13x - 12x - 4.5 = 12x - 12x - 1.1 \\ x - 4.5 = - 1.1 \\ x - 4.5 + 4.5 = - 1.1 + 4.5 \\ x = 3.4[/tex]
Find the length of the function over the given interval. y = 3x from x = 0 to x = 2
The length of the function y = 3x over the given interval [0, 2] is 3.2 units
For given question,
We have been given a function y = 3x
We need to find the length of the function on the interval x = 0 to x = 2.
Let f(x) = 3x where f(x) = y
We have f'(x) = 3, so [f'(x)]² = 9.
Then the arc length is given by,
[tex]\int\limits^a_b {\sqrt{1+[f'(x)]^2} } \, dx\\\\= \int\limits^2_0 {\sqrt{1+9} }\, dx\\\\=\sqrt{10}\\\\ =3.2[/tex]
This means, the arc length is 3.2 units.
Therefore, the length of the function y = 3x over the given interval [0, 2] is 3.2 units
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Five hats and three shirts cost $176. Three hats and five shirts cost $208. What is the cost of one hat?
The cost of one hat is __ dollars.
Let hats be x
Let shirts be y
We can set up a system of equations to figure out the cost of one hat.
5x+3y = 176 and 3x+5y = 208
Since we are finding the cost of the hats, we will need to isolate x from the equation. We can first get rid of y. One way we can do that is by multiplying the first equation with 5 and the second one with -3, effectively making y add up to 0 when we solve for x.
5(5x+3y = 176) --> 25x+15y = 880
-3(3x+5y = 208) --> -9x-15y = -624
We can now add the 2 equations together and solve for x.
25x+15y = 880
-9x-15y = -624
+>>>>>>>>>>>>>>>
16x = 256
x = 16
So the the cost of one hat is 16 dollars.
Answer:
$16
Step-by-step explanation:
Define the variables:
Let x = cost of one hatLet y = cost of one shirtCreate two equations using the defined variables and the given information.
Equation 1
Five hats and three shirts cost $176.
⇒ 5x + 3y = 176
Equation 2
Three hats and five shirts cost $208.
⇒ 3x + 5y = 208
Rewrite Equation 2 to make y the subject:
[tex]\implies \sf 3x+5y-3x=208-3x[/tex]
[tex]\implies \sf 5y=208-3x[/tex]
[tex]\implies \sf \dfrac{5y}{5}=\dfrac{208-3x}{5}[/tex]
[tex]\implies \sf y=\dfrac{208-3x}{5}[/tex]
Substitute the found expression for y into Equation 1 and solve for x:
[tex]\implies \sf 5x+3\left(\dfrac{208-3x}{5} \right)=176[/tex]
[tex]\implies \sf 5x+\dfrac{624-9x}{5}=176[/tex]
[tex]\implies \sf 5x+124.8-1.8x=176[/tex]
[tex]\implies \sf 3.2x+124.8=176[/tex]
[tex]\implies \sf 3.2x+124.8-124.8=176-124.8[/tex]
[tex]\implies \sf 3.2x=51.2[/tex]
[tex]\implies \sf \dfrac{3.2x}{3.2}=\dfrac{51.2}{3.2}[/tex]
[tex]\implies \sf x=16[/tex]
Therefore, the cost of one hat is 16 dollars.
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The equation for least regression line to this data set is ŷ = 76. 82x 88. 56. what is the predicted value (in dollars) for maintenance expenses when a truck is 7 years old?
The predicted value (in dollars) for maintenance expenses when a truck is 7 years old is $626.3.
In this question,
The equation for least regression line to this data set is
y' = 76.82x + 88.56 ------- (1)
Number of years, x = 7
The general form of equation for least regression line is
y' = a + bx
where y is the dependent variable, x is the independent variable, a is the intercept of regression line and b is the slope of regression line.
The predicted value (in dollars) for maintenance expenses when a truck is 7 years old can be calculated as
y' = 76.82x + 88.56
Substitute the value of x in the above equation, we get
y' = 76.82(7) + 88.56
y' = 537.74 + 88.56
y' = 626.3
Hence we can conclude that the predicted value (in dollars) for maintenance expenses when a truck is 7 years old is $626.3.
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I need help here’s a picture can somone explain what I need to do??
Answer:
176 square feet
Step-by-step explanation:
add the areas of the rectangle and triangle
rectangle area is
16 times 8 which is
128
rectangle area is
1/2 times 12 times 8 which is
48
then add them
128 plus 48 is
176 square feet
K
Consider a study conducted in 2018 to estimate the percentage of people from a certain region who do not use the
Internet. Complete parts (a) through (c) below.
a. If a 99% confidence level is used, how many people should be included in the survey if the researchers wanted to
have a margin of error of 7%?
There should be people included in the survey.
(Round up to the nearest person as needed.)
rred
The number of people who must be included in the survey, that is, the sample size should be 340.
We assume the sample size to be n.
The confidence interval required is 99%.
The Z-score corresponding to the 99% confidence interval is (Z) 2.58.
The true proportion (p) of the sample is not given, so we assume it to be 50% or 0.5.
The margin of error for the sample (E) is given to be 7% or 0.07.
By the formula of margin of error, we know that:
E = Z√[{p(1 - p)}/n].
Putting in the values, we have, we get:
0.07 = 2.58√[{0.5*0.5}/n],
or, (0.07/2.58)² = 0.25/n,
or, n = 0.25/{(0.07/2.58)²} = 339.6122449 ≈ 340.
Thus, the number of people who must be included in the survey, that is, the sample size should be 340.
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A sampling method is _________ when the individuals selected for one sample are used to determine the individuals in the second sample.
Answer:
someone please help me check my page
someone please help me check my pageStep-by-step explanation:
Find the total surface area. A. 78 B. 98 C. 69 D. 92
The total surface area of the figure is 92 m².
How to find the surface area of a figure?The surface area of a figure is the sum of the whole sides of the figure.
Therefore,
surface area = 4 × 4 + 4 × 4 + 6 × 4 + 2 × 4 + 1 / 2 (2 + 6)3.5 + 1 / 2 (2 + 6)3.5
Hence,
surface area = 16 + 16 + 24 + 8 + 14 + 14
Therefore,
surface area = 32 + 24 + 8 + 28
surface area = 56 + 8 + 28
surface area = 92 m²
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Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter than the next lower category. For example, a day that is dazzling is 4 times brighter than a day that is radiant. How many times brighter is a radiant day than a dim day?
According to the developed scale, a radiant day is 16 times brighter than a dim day.
We assume the brightness of a dim day to be x.
According to the developed scale, the brightness of an illuminated day will be 4 times that of a dim day.
Thus, the brightness of an illuminated day = 4*the brightness of a dim day = 4x.
According to the developed scale, the brightness of a radiant day will be 4 times that of an illuminated day.
Thus, the brightness of a radiant day = 4*the brightness of an illuminated day = 4*4x = 16x.
Now, the ratio of the brightness of a radiant day to the brightness of a dim day = 16x:x = 16x/x = 16:1.
Thus, according to the developed scale, a radiant day is 16 times brighter than a dim day.
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The question provided is incomplete. The complete question is:
"Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter than the next lower category. For example, a day that is dazzling is 4 times brighter than a day that is radiant. How many times brighter is a radiant day than a dim day?
Dim=2
Illuminated=3
Radiant=4
Dazzling=5"