Please help precal problem!

Find the value of side a.

A) 2.770

B) 3.516

C) 5.760

D) 7.309

E) None of these

The fractions found in the 2/n table in the Rhind Mathematical Papyrus.

2/7 = (m n 2 ) 1 n (m n 2 )

= (2 7 2 ) 1 7 (2 7 2 )

= (14 2 ) 1 7 (14 2 )

= 7 1 7 + 7 1 14

2/35 = (m n 2 ) 1 n (m n 2 )

= (2 35 2 ) 1 35 (2 35 2 )

= (70 2 ) 1 35 (70 2 )

= 35 1 35 + 35 1 70

2/91 = (m n 2 ) 1 n (m n 2 )

= (2 91 2 ) 1 91 (2 91 2 )

= (182 2 ) 1 91 (182 2 )

= 91 1 91 + 91 1 182

Using the identity (m n 2 ) 1 n (m n 2 ) we can decompose the fractions 2/7, 2/35, and 2/91 into unit fractions. For 2/7, we obtain the decomposition 7 1 7 + 7 1 14, for 2/35 the decomposition 35 1 35 + 35 1 70, and for 2/91 the decomposition 91 1 91 + 91 1 182. This matches the fractions found in the 2/n table in the Rhind Mathematical Papyrus.

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The arctan integral. 3 5 arctan 1 x d = 5 [ [tex]x[/tex] arctan ( [tex]\frac{1}{x}[/tex] ) dx - ( [tex]-(\frac{1}{2} )[/tex] [1+[tex]x^{2}[/tex]] ; where ([tex]\sqrt{3}[/tex] to 1 )

The basic arctan formula can be given by θ = tan-1(Perpendicular / Base). Here, θ is the angle between the hypotenuse and the base of a right-angled triangle.

The signed area of the region in the plane that is circumscribed by the graph of a specific function between two points on the real line can be used to describe definitive integrals. Areas above the plane's horizontal axis are often positive, whereas those below it are typically negative.

= [tex]\int\limits[/tex] 5 arctan ( [tex]\frac{1}{x}[/tex] ) dx ; where ([tex]\sqrt{3}[/tex] to 1 )

[tex]\int\limits[/tex] 5 arctan ( [tex]\frac{1}{x}[/tex] ) dx = [tex]5\frac{(2\sqrt{3} )ln(2)+2\pi -\sqrt{3} \pi }{4\sqrt{3} }[/tex]

= 5  [tex]\int\limits[/tex] arctan ( [tex]\frac{1}{x}[/tex] ) dx

= 5 [ x arctan ( [tex]\frac{1}{x}[/tex] ) dx - ( [tex]-(\frac{1}{2} )[/tex] [1+[tex]x^{2}[/tex]] ; where ([tex]\sqrt{3}[/tex] to 1 )[tex]x_{123}[/tex]

Therefore,

The arctan integral. 3 5 arctan 1 x d = 5 [ [tex]x[/tex] arctan ( [tex]\frac{1}{x}[/tex] ) dx - ( [tex]-(\frac{1}{2} )[/tex] [1+[tex]x^{2}[/tex]] ; where ([tex]\sqrt{3}[/tex] to 1 )

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After solving the equation the triangle given in question the 63.8°.

A triangle is a three-sided polygon with three angles. It is one of the basic shapes in geometry and is very versatile as it can be used to create many other shapes and structures. Triangles are generally classified by the length of their sides, which can be equal (an equilateral triangle), longer in one side than the other two sides (an isosceles triangle) or different in length on all three sides (a scalene triangle). They can also be classified by their angles, which can be acute (the angles are all less than 90 degrees), right (one angle is exactly 90 degrees) or obtuse (one angle is greater than 90 degrees).

x = 63.8°
Using the Law of Cosines, we can calculate the value of x:
x² = 17² + 9² - 2(17)(9)cos(90°)
x² = 289 + 81 - 306
x² = 64
x = √64
x = 8
Therefore, x = 63.8° (rounded to the nearest tenth).

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A quantum computer is a type of computer that uses quantum mechanics.

Quantum computers use quantum mechanics, a branch of physics that deals with the behavior of matter and energy at the subatomic and quantum scale, to perform operations and solve problems.

Unlike classical computers, which use binary digits (bits) to represent and process information, quantum computers use quantum bits, or qubits, which can exist in multiple states at the same time, allowing for exponentially faster processing of complex computations and simulations. Quantum computers have the potential to revolutionize fields such as cryptography, drug discovery, and artificial intelligence.

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The length of the other diagonal is 22.36 cm.

Diagonal is defined as a sloping line or the slant line, that connects to the vertices of a shape.

Let's call the length of the other diagonal "d".

Since a rhombus has perpendicular diagonals that bisect each other

we can use the Pythagorean theorem to find the length of the other diagonal:

d^2 = 10^2 + 10^2 = 100

d = sqrt(100) = 10 * sqrt(10) = 10 * 2.236 = 22.36 cm

Therefore, the length of the other diagonal is 22.36 cm.

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The Coase theorem states that if property rights are well-defined and transaction costs are low, then the allocation of resources will be efficient, regardless of the initial allocation of property rights.

If Winston and Chloe successfully apply the Coase theorem to solve the problem of Winston's loud music externalizing a cost onto Chloe, they may reach a mutually beneficial agreement. This could result in either Winston reducing the volume of his music or compensating Chloe for the cost of the externalization, or a combination of both.

The goal is to reach a solution where the costs and benefits are more efficiently allocated between the two parties.

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The correct values that create ordered pairs that are solutions to the solutions to the equation 3x - 5y = 20 are,

⇒ y₁ = - 1

⇒ x₂  = 10

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

We have to given that;

The equation is,

⇒ 3x - 5y = 20

Now, If (5, y₁) is the solution of above equation, then it satisfy the equation.

⇒ 3x - 5y = 20

⇒ 3 × 5 - 5y₁ = 20

⇒ 15 - 5y₁ = 20

⇒ 15 - 20 = 5y₁

⇒ - 5 = 5y₁

⇒ y₁ = - 1

And, If (x₂, 2) is the solution of above equation, then it satisfy the equation.

⇒ 3x₂ - 5y = 20

⇒ 3x₂ - 5×2 = 20

⇒ 3x₂ - 10 = 20

⇒ 3x₂ = 20 + 10

⇒ 3x₂ = 30

⇒ x₂  = 10

Thus, The correct values that create ordered pairs that are solutions to the solutions to the equation are,

⇒ y₁ = - 1

⇒ x₂  = 10

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If the contractor's truck can haul 17 cubic yards per load, then 21 truckloads are needed.

Earth removed from a building site is 357 cubic yards.

A contractor's truck can haul 17 cubic yards per load.

To find how many truckloads were needed, we needed to divide the earth removed from the building site by the contractor's truck capable of hauling.

That is,  

The number of truckloads = earth removed from the building site/contractors' truck capable of hauling.

The number of truckloads = 357 cubic yards/17 cubic yards per load

The number of truckloads = 21 truckloads.

Therefore, the required truckloads are 21.

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An equation to model the relationship between the number of weeks, x, and the number of site visits, f(x) is 4800 = a(1.5)^x.

He found that before launching the new marketing plan, there were 4,800 visits.

Over the course of the next 5 weeks, the number of site visits increased by a factor of 1.5 each week.

Over the course of the next 5 weeks, initial visitor at x = 0, 4800

Increasing factor = 1.5

Equation of the model is given as:

f(x) = a(b)^x

From the question b = 1.5

Now the equation of model is:

f(x) = a(1.5)^x

At x = 0, f(x) = 4800

Now the equation of the model is:

4800 = a(1.5)^x

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The real exponential sequence for f[k]=f[kt] is f[k]=b^k.

What is exponential sequence ?

The exponential function is a mathematical function denoted by f(x)=\exp or e^{x}. Unless otherwise specified, the term generally refers to the positive-valued function of a real variable, although it can be extended to the complex numbers.

The real exponential sequence for f[k]=f[kt] can be shown to be f[k]=b^k by using the definition of exponential functions. If f[k]=f[kt], then f[k]=f[k-1]t and f[k-1]=f[k-2]t, and so on. By substitution, we have:

f[k]=f[k-1]t

f[k-1]=f[k-2]t

f[2]=f[1]t

f[1]=f[0]t

So we can write:

f[k]=f[k-1]t=f[k-2]t^2=...=f[1]t^(k-1)=f[0]t^k

Next, we can define b as f[0] and substitute it into the above equation:

f[k]=b^k

Therefore, the real exponential sequence for f[k]=f[kt] is f[k]=b^k.

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The student's lifetime value for a four-year degree at this college is $80,000.

The student's lifetime value for a four-year degree can be calculated as follows:

Determine the cost per semester: $10,000 per semester

Determine the number of semesters for a four-year degree: 4 years * 2 semesters/year = 8 semesters

Multiply the cost per semester by the number of semesters to get the total cost of tuition: $10,000 * 8 = $80,000

Therefore, the student's lifetime value for a four-year degree at this college is $80,000.

It is important to note that this calculation only considers the cost of tuition and does not take into account other costs such as room, board, books, and supplies, which can add significantly to the total cost of obtaining a degree.

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Percentage is a concept used to express a fraction as a part of 100. It is typically expressed as a fraction with a denominator of 100 and is written as a number followed by the percent sign (%). For example, the fraction 3/20 can be expressed as 15%, which means 15 out of every 100. Percentage is a useful concept when comparing two or more values, as it provides a way to measure the relative size of each value. For example, if one group of people has 25% of the total number of votes, this means that they have more votes than the other groups, whose percentages are lower.

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Complete question:

A total of 28% of Americans smoke cigarettes, 7% smoke cigars and 5% smoke both cigarettes and cigars

We can graph a reciprocal function using the function’s table of values and transforming the graph of y=1/x

A new function called the reciprocal function is produced when the reciprocal function is found. These functions have intriguing characteristics and distinctive graphs. We also represent these patterns using reciprocal functions when two expressions are inversely proportional. A constant on the numerator and an algebraic expression in the denominator makes up reciprocal functions.

How to find the reciprocal of a function?

By dividing 1 by the provided number, we can find the reciprocal of a given number. Similar reasoning is used to get a function's reciprocal: we divide 1 by the function's expression.

We can graph a reciprocal function using the function’s table of values and transforming the graph of y=1/x

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Answer:

C' (-2, -2)

D' (-2, 2)

E' (2, 0)

F' (0, -2)

Step-by-step explanation:

A dilation of factor k about the origin is a transformation that enlarges a figure by a factor of k, while keeping the origin fixed.

It means that each point (x, y) on the pre-image is transformed to a new point (kx, ky) in the dilated figure.

Therefore, the rule for a dilation of 2 about the origin is:

From inspection of the given diagram, the vertices of the pre-image are:

Applying the dilation rule (x, y) → (2x, 2y):

The probability that vertex b will be the bottom vertex will be 1/16

The ant has four equally likely possibilities for his initial step from the top vertex, each heading to one of the four vertices close to the top vertex.

When the ant reaches vertex A, he has four equally likely next steps, each heading to one of the vertices next to vertex A.

Only one of these possibilities, however, will send him to the bottom vertex: the one that brings him straight to the bottom vertex.

As a result, the ant's chance of reaching the bottom vertex after two steps is 1/4 * 1/4 = 1/16.

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The fountain should be located at the coordinates (4,2). This is the midpoint of the line segment that connects the vertices a(-1,-1) and c(7,-1). It is also the same distance from b(4,4).

To find the location of the fountain, we first need to find the midpoint of the line segment connecting the vertices a(-1,-1) and c(7,-1). This midpoint is located at the coordinates (4,2). To verify that this is the correct location, we can calculate the distance between the midpoint and each vertex. To do this, we use the distance formula, which is d=√((x2-x1)2+(y2-y1)2). Using the coordinates for the midpoint (4,2) and the coordinates for vertex a(-1,-1), we get d=√((42-(-12))2+((22-(-12))2). This simplifies to d=√((52+52))=√(50)=7.07. We can repeat the same process for the midpoint and vertex b(4,4) and for the midpoint and vertex c(7,-1). In both cases, we find that the distance is 7.07, so the fountain should be built at the coordinates (4,2).

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using inverse relation, If p= 60, then q= 3x because i find the constant value is 180.

P is approximately equal to 1/Q since P has an inverse relationship to Q. x=k/3 for P=x and Q=3. P = k/x when Q = x.

The correlation between bond prices and interest rates is a prime illustration of an inverse connection. Bond prices normally fall with an increase in interest rates, whereas bond prices often rise with a decrease in interest rates.

P×1/q

( formula now)  P= K/Q here K is a constant

                                 30= k/6

                                 k=30×6

                                 k= 180

when P is equal to 60 then q=

because constant k=60

60= 180/q

q=180/60

q=3 unit .

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The graph of the inequality is added as an attachment

From the question, we have the following parameters that can be used in our computation:

x≤ 8

The above expression is an inequality that implies that

The value of x does not exceed 8

Next, we plot the graph

See attachment for the graph of the inequality

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Answer:

24 vowels

Step-by-step explanation:

A B C D E F G

  two out of 7 are vowels....you would expect to get 2/7 ths of 84 spins to be vowels

2/7 * 84 = 24 vowels

Salut/Hello!

Answer: 20 ft

Step-by-step explanation:
We can imagine the ladder, wall and ground as a triangle.
(And because we don't know if our triangle has a 90 degrees angle it means it's an ordinary triangle.)

We know that a triangle that has an angle with 60 degrees means all of its angles have 60 degrees because 180 : 3 angles = 60 degrees which means the triangle is equilateral.

Definition of the equilateral triangle: The triangle that has the 3 side with the exact same length.


From the equilateral triangle we know all sides are equal. If the ladder is 20 ft that means the distance between the building and the base of the ladder (which is actually the base of our triangle) is 20 ft.

I hope it was useful! :]

(x + 1) is not a factor of the  polynomial,

x¹⁴⁵ + 3x⁴⁵ - 4.

An expression that consists of variables, constants, and exponents that is combined using mathematical operations like addition, subtraction, multiplication, and division is referred to as a polynomial.

Given:

We have a polynomial,

x¹⁴⁵ + 3x⁴⁵ - 4.

If (x + 1) is a factor.

Then x = -1 is a zero of polynomial.

Now,

(-1)¹⁴⁵ + 3(-1)⁴⁵ - 4

= -8

Therefore, (x + 1) is not a factor.

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1.05 quarts of blue colors paint they mixed to make seafoam green paint.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

From the given figure, total quantity of paint is 1.5 quarts.

70% of blue paint and 30% of yellow paint.

Let the quantity of blue paint be x.

Now, x =70% of 1.5

x =70/100 ×1.5

x =0.7×1.5

x =1.05 quarts

Therefore, 1.05 quarts of blue colors paint they mixed to make seafoam green paint.

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The average wage of men is $819 and of women is $657 in 2009

An equation is the equality between two algebraic expressions, which have at least one unknown or variable.

Information about the problem:

To solve this problem we must establish the equations according to the given data and solve the operations:

M = W + 162                    (1)

M + W = 1476                  (2)

We have two equations with two unknowns, substituting the value (M) in the second equation, we have:

M + W = 1476

W + 162 + W = 1476

162 + 2W = 1476

2W = 1476 - 162

2W = 1314

W = 1314/2

W = 657

Substituting (W) into one of the equations (M) we have:

M = W + 162

M = 657 + 162

M = 819

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Answer:

26 R 1

Step-by-step explanation:

Answer:3/2

Step-by-step explanation: just did the test

As all sides have grown by 2/3 times, The scale factor is  2/3. Thus, option A is correct.

In its simplest form, a scale factor is the proportion between the model measurement and the actual measurement. The scale factor, as opposed to a scale ratio, does not contrast various measurement units. A model car that is scaled at one-twentieth of its real-world counterpart is said to be that size. The car is also 20 times bigger than the model, according to this statement.

16 feet is the length of a fence. The fence is depicted as being 4 inches tall on a map. Write a ratio comparing the two quantities before attempting to calculate the scale factor of the drawing to the actual fence.

Given triangle side are 6, 6, 8 and scaled triangle is 9,9,12

The corresponding sides are

6/9, 6/9, 8/12

When you simply, we get

2/3, 2/3, 2/3

As all sides have grown by 2/3 times, The scale factor is  2/3. Thus, option A is correct.

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Suppose X and Y have joint p.d.f. f(x, y) = cxy/(1+x² + y² ) for 0 < x < 1, 0 < y < 1, and whatever constant c makes the nasty mess integrate to 1 is No as well as x and y are not independent

What is variables?

Any qualities, quantity, or number that can be gauged or tallied qualifies as a variable. A data item is another name for a variable. Examples of variables include age, sex, company income and expenses, country of birth, capital expenditures, class grades, eye color, and vehicle kind.

The joint p.d.f of X and Y is f(x, y)

f(x,y) = cxy/ 1+[tex]x^{2}[/tex]+[tex]y^{2}[/tex] for 0 < x < 1 and 0 < y < 1

marginal p.d.f of x = f(x):

f(x) = {1y_of(x,y)dy

= {1y=0 /cxy/ 1+x+[tex]y^{2}[/tex] dy

Cx/2 ( {1y=0 /2y/1+ [tex]x^{2}[/tex] + [tex]y^{2}[/tex] dy)

Take substitute 1+[tex]x^{2}[/tex]+ [tex]y^{2}[/tex] = t⇒2y dy=dt

Lower limit: y = 0⇒t=1+[tex]x^{2}[/tex]

Upper limit: y=1➡t=1+[tex]x^{2}[/tex]+1

F(x) =  cx/2

f 1y= 0 2y

=0 1+2+[tex]y^{2}[/tex]dy)

=Cx/2({1+[tex]x^{2}[/tex]+1dt/t

=1+[tex]x^{2}[/tex]t)

=cx/2(In(t) - ln(1+[tex]x^{2}[/tex])/1[tex]x^{2}[/tex])

=cx/2 (In (1+[tex]x^{2}[/tex]+1))-In(1+[tex]x^{2}[/tex]))

=cx/2 (In (1+[tex]x^{2}[/tex]+1/1+[tex]x^{2}[/tex]))

=Cx (In(1+1/1+[tex]x^{2}[/tex]))

marginal p.d.f of y = f(y):

f(y) = {1x

=0(x,y)dx

= F1x

=0/cxy/ 1+[tex]x^{1}[/tex][tex]y^{2}[/tex]=dx

= cy/2({1x)

=0/2x/1+[tex]y^{2}[/tex]+[tex]x^{2}[/tex]dx}

Take substitute 1 + [tex]y^{2}[/tex] + [tex]x^{2}[/tex] = t 2x dx = dt

Lower limit: x = 0

t = 1 + [tex]y^{2}[/tex]

Upper limit: x =1

=t + [tex]y^{2}[/tex] + 1

F(y)=cy/2({1x=0 2x/1+[tex]y^{2}[/tex]+[tex]x^{2}[/tex]/dx)

=cy({1+[tex]y^{2}[/tex]+1dt/t

=1[tex]y^{2}[/tex]t/)

=Cy/2((In(t))1+[tex]y^{2}[/tex]+1/1+[tex]y^{2}[/tex])

=cy(In(1+[tex]y^{2}[/tex]+1) – In( 1+[tex]y^{2}[/tex]))

=cy(In(1+[tex]y^{2}[/tex]+1/1+[tex]y^{2}[/tex]))

=cy/2(In(1+1/1+y2))

Now we have to check for independence.

F(x,y)= cxy/1+[tex]x^{2}[/tex]+[tex]x^{2}[/tex] for0<x<1 and 0<y<1

F(x) = cx/2( In(1+1/1+[tex]x^{2}[/tex])) for 0<x<1

F(y)=cy/2(In(1+1/1+[tex]y^{2}[/tex])) for < y <1

=f(x)*f(y)

=c2xy/4 ( In ( 1+1/1+[tex]x^{2}[/tex] ) *In( 1+1/1+[tex]y^{2}[/tex])) #f(x,y)

F(x,y) #f(x)* f(y) for all x and y

=x and y are not independent.

no is correct answer.

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