PLEASE HELP (WILL GIVE BRAINLIEST)

The graph is a function: yes

The domain of this function is: x ≥ -3.

The range of this function: all real numbers.

In Mathematics and Geometry, a domain is the set of all real numbers for which a particular function is defined.

Additionally, the vertical extent of any graph of a function represents all range values and they are always read and written from smaller to larger numerical values, and from the bottom of the graph to the top.

By critically observing the graph shown in the image attached above, we can reasonably and logically deduce the following domain and range:

Domain = {-3, ∞}, x ≥ -3, or -3 ≤ x ≤ ∞.

Range = {-∞, ∞} or all real numbers.

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The correct solution of the expression is,

⇒ 16 / e¹²ˣ

We have to given that;

The value of Expression is,

⇒ (2e⁻³ˣ)⁴

Now, We can simplify as;

⇒ (2e⁻³ˣ)⁴

⇒ 2⁴ × e⁻¹²ˣ

⇒ 16e⁻¹²ˣ

⇒ 16 / e¹²ˣ

Thus, The correct solution of the expression is,

⇒ 16 / e¹²ˣ

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The equation for contribution for each student is 185.5/14 = 13.25.

Price of new easel= $129

Set of blank canvases = $ 46

Sales tax = $ 10.50

So, the total amount is

= 129 + 46 + 10.5

= 185.5

Then, each student contribute

= 185.5 / 14

= 13.25

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Answer:

C. complementary

Michel-Eugène Chevreul discovered that placing complementary colors next to each other can create the greatest contrast and vibrancy in color perception. This is because complementary colors are located opposite each other on the color wheel and, when placed side by side, they enhance each other and create a strong visual impact. For example, placing yellow next to violet or blue next to orange can create a dynamic and eye-catching effect. In contrast, placing tertiary colors (colors made by mixing primary and secondary colors) or arbitrary colors next to each other may not create as much contrast or visual interest. Overall, understanding color theory and the relationships between different colors can be helpful for creating visually appealing designs, artworks, or other color-based projects.

Answer: the tangent of the smaller acute angle in this right triangle is 8/15.

Step-by-step explanation:

Since the side lengths of the correct triangle are given as 8, 15, and 17, able to see that the sides with lengths 8 and 15 are the legs of the proper triangle, and the side with length 17 is the hypotenuse.

We know that the littler intense point θ is inverse the shorter leg of length 8. Hence, the digression of θ is:

tan(θ) = opposite/adjacent = 8/15

The probability that you will get a 15-inch monitor = 1/3

We know that probability of event is the ratio of number of possible outcomes of event A and the total number of outcomes.

Let us assume that event A = you will get a 15-inch monitor

The number of favourable outcomes for event A are 2

So, n(A) = 2

The sample space for this experiment would be,

n(S) = 6

Using the definition of probability, the required proabability would be,

P(A) = n(A) / n(S)

P(A) = 2/6

P(A) = 1/3

Therefore, the required probability = 1/3

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Determining if the proportion is true. If is not true and correcting the error v/x = x/v+w is: B. false, it should be  w/x = x/v+w.

In order for us to know whether the proportion v/x = x/v+w is true or not we need to cross multiply and simplify both sides:

v(x + v + w) = x^2

Expand the left-hand side:

vx + v^2 + vw = x^2

Subtract vx from both sides:

v^2 + vw = x^2 - vx

Factor out v on the left-hand side and x on the right-hand side:

v(v + w) = x(x - v)

Divide both sides by (v + w)x:

v/(v + w) = x/(x - v)

Therefore the correct option is B.

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The amount of sand in each vase is 2.8 pounds by dividing the total amount by the number of vases.

Given that,

Raj combined white sand with black sand to make 14 pound mixture of sand.

Total amount of sand = 14 pounds

Number of vases to which sand is put = 5 vases

Amount of sand in each vase can be found by dividing the total amount by the number of vases.

Amount of sand in each vase = 14 / 5 = 2 4/5 pounds = 2.8 pounds

Hence the total amount of sand is 2.8 pounds.

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The calculated value of the area of the figure is 230.5 sq meters

From the question, we have the following parameters that can be used in our computation:

The composite figure

The area is the sum of the individual areas

Using the above and the area formulas as a guide, we have the following:

Area = 5 * 5 + (6 + 5) * 4 + 1/2 * 17 * (15 + 4)

Evaluate

Area = 230.5

Hence, the area is 230.5 sq meters

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The recipe will need 21 cups of sauce and three and a half teaspoons of oregano for 7 servings. The correct option is C.

The sauce to oregano ratio for five servings is equal to 15 cups and 2.5 teaspoons, respectively. For a single portion of the recipe, this computes to 3 cups and 0.5 teaspoons.

It should be noted that to attain the correct amount needed for seven servings, simply multiply each part of the ratio by seven. Consequently, you should use 21 cups of sauce and three and one-half teaspoons of oregano. All together, this recipe requires 21 cups of sauce and three and a half teaspoons of oregano for 7 servings.

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Answer:

Suppose X ~ N(12,2) represents a normal distribution with mean 12 and standard deviation 2. According to the empirical rule, about 68% of the x values lie within one standard deviation of the mean .

We can calculate the endpoints of the interval that represents one standard deviation from the mean as follows:

Lower endpoint: 12 - 2 = 10

Upper endpoint: 12 + 2 = 14

Therefore, about 68% of the x values lie between 10 and 14 1.

Step-by-step explanation:

The annual premium for a Whole Life insurance policy, for the healthy male, would be A. $ 2, 881.61

From the given table, a 28 year old male would have to pay $ 17. 76 for each $ 1,000 of coverage of Whole Life Insurance.

For a policy that is worth $ 162, 253 therefore, the annual premium would therefore be:

= Amount per thousand / 1, 000 x  Policy coverage

= 17. 76 / 1, 000 x 162, 253

= 0.01776 x 162, 253

= $ 2, 881.61

In conclusion, the annual premium is $ 2, 881.61 .

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The addition of the given fraction expression is 7/8.

In mathematics, an expression is a combination of numbers, symbols, and/or operators that represents a mathematical quantity or relationship. It can be a simple combination of numbers or a more complex combination involving variables, functions, or other mathematical constructs.

When adding fractions with the same denominator, you simply add the numerators and keep the denominator the same.

In this case, both fractions have a denominator of 8, so we can add their numerators:

5/8 + 2/8 = (5 + 2)/8 = 7/8

Thus, the sum of 5/8 and 2/8 is 7/8.

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Answer:

[tex]f(x)=\dfrac{1}{20}x^5+\sinh(x)-\dfrac{1}{2}\sinh(2)x+6[/tex]

Step-by-step explanation:

Given:

    [tex]\phantom{ww} \bullet\;\;\;f''(x)=x^3+\sinh(x)[/tex]

    [tex]\phantom{ww} \bullet\;\;\;f(0)=6[/tex]

    [tex]\phantom{ww} \bullet\;\;\;f(2)=7.6[/tex]

To find f'(x), integrate f''(x):

[tex]\begin{aligned}\displaystyle f'(x)=\int f''(x)\; \text{d}x&=\int \left(x^3+\sinh(x)\right)\; \text{d}x\\\\&=\int x^3\;\text{d}x+\int \sinh(x)\; \text{d}x\\\\&=\dfrac{1}{4}x^4+\cosh(x)+\text{K}\end{aligned}[/tex]

To find f(x), integrate f'(x):

[tex]\begin{aligned}\displaystyle f(x)=\int f'(x)\; \text{d}x&=\int \left(\dfrac{1}{4}x^4+\cosh(x)+\text{K}\right)\;\text{d}x\\\\&=\int \dfrac{1}{4}x^4\; \text{d}x+\int \cosh(x) \; \text{d}x + \int \text{K}\; \text{d}x\\\\&=\dfrac{1}{20}x^5+\sinh(x)+Kx+\text{C}\end{aligned}[/tex]

Substitute f(0) = 6 to determine the value of the constant C:

[tex]\begin{aligned}f(0)=\dfrac{1}{20}(0)^5+\sinh(0)+K(0)+\text{C}&=6\\\\0+0+0+\text{C}&=6\\\\\text{C}&=6\end{aligned}[/tex]

Substitute f(2) = 7.6 and C = 6 to determine the value of the constant K:

[tex]\begin{aligned}f(2)=\dfrac{1}{20}(2)^5+\sinh(2)+K(2)+6&=7.6\\\\1.6+\sinh(2)+2K+6&=7.6\\\\\sinh(2)+2K&=0\\\\2K&=-\sinh(2)\\\\K&=-\dfrac{1}{2}\sinh(2)\end{aligned}[/tex]

Therefore, function f(x) is:

[tex]\boxed{f(x)=\dfrac{1}{20}x^5+\sinh(x)-\dfrac{1}{2}\sinh(2)x+6}[/tex]

[tex]\textsf{As}\;\;\sinh(2)=\dfrac{e^4-1}{2e^2},\;\textsf{we can also write the equation as:}[/tex]

[tex]f(x)=\dfrac{1}{20}x^5+\sinh(x)-\dfrac{1}{2}\left(\dfrac{e^4-1}{2e^2}\right)x+6[/tex]

[tex]f(x)=\dfrac{1}{20}x^5+\sinh(x)-\left(\dfrac{e^4-1}{4e^2}\right)x+6[/tex]

The solution set for the given equation is 25.

In Mathematics and Geometry, a square root function is a type of function that typically has this form f(x) = √x, which basically represent the parent square root function i.e f(x) = √x.

Next, we would determine the solution set for the given equation by translating the word problem into an equation and then divide both sides of the square root function as follows;

-√x = 5

√x = -5

By taking the square of both both sides of the square root function, we have:

x = (-5)²

x = 25

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In a case wherby new bicycle sells for $300 It is on sale for 1/4 off the regular price all the expressions that represent the sale price of the bicycle in dollars are

From the option B)300•3/4, we cam see that (300*3)/4 = 225

From the option C)300•(1-1/4),   (300*3)/4 = 225

From the E.)300 - 1/4•300, 300 - 75 = 225

Therefore, the correct options are the option BCE as listd below because they are seen as the one that gives the  regular price all the expressions hence they are correct.

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The expression for the area under the graph of f(x) = √x as a limit of Riemann sums is A = lim [n -> ∞ ] Ax [f(x₁) + f(x₂) + ... + f(xₙ)]

For a continuous function f(x), the area A of the region S that lies under the graph of the function can be expressed as the limit of the sum of the areas of approximating rectangles. Each rectangle has a width of Ax, where A is the interval over which we want to find the area and x is a point within that interval. The height of each rectangle is f(x).

Using this definition, we can find an expression for the area under the graph of f(x) = √x, where 1 ≤ x ≤ 13. We start by dividing the interval [1, 13] into n subintervals, each of width Ax = (13-1)/n = 12/n. We can label the endpoints of the subintervals as x₁, x₂, ..., xₙ+1, where x₁ = 1 and xₙ+1 = 13.

Next, we approximate the area under the curve using n rectangles. The height of the ith rectangle is f(xi), where xi is any point in the ith subinterval. The width of each rectangle is Ax, so the area of the ith rectangle is f(xi) Ax. The total area of the rectangles is then the sum of the areas of each rectangle:

f(x₁) Ax + f(x₂) Ax + ... + f(xₙ) Ax

We can simplify this expression by factoring out the common factor of Ax:

Ax [f(x₁) + f(x₂) + ... + f(xₙ)]

Taking the limit as n approaches infinity, we obtain:

A = lim [n -> ∞] Ax [f(x₁) + f(x₂) + ... + f(xₙ)]

To evaluate the limit, we need to find a formula for the sum of f(xi) for i = 1 to n.

This is a sum of square roots, which can be approximated using numerical methods or evaluated exactly using calculus techniques such as the definite integral.

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Answer:

[tex]\displaystyle \lim_{n \to \infty}\sum^n_{i=1}\left(\dfrac{12}{n}\right)\sqrt[7]{1+\dfrac{12i}{n}}[/tex]

Step-by-step explanation:

The Riemann sum is a method by which we can approximate the area under a curve using a series of rectangles.

The area under the curve of f(x) on the interval [a, b] is represented by:

[tex]\boxed{\begin{minipage}{6cm}$\displaystyle \int^b_af(x)\; \text{d}x=\lim_{n \to \infty}\sum^n_{i=1}f(x_i) \cdot \Delta x$\\\\\\where $\Delta x=\dfrac{b-a}{n}$ and $x_i=a+\Delta x \cdot i&\\\end{minipage}}[/tex]

Δx is the width of each rectangle.

[tex]f(x_i)[/tex] is the height of each rectangle.

[tex]x_i[/tex] is the right endpoint of each rectangle.

Therefore:

[tex]\begin{aligned}\displaystyle \int^b_af(x)\; \text{d}x&=\lim_{n \to \infty}\sum^n_{i=1}f(x_i) \cdot \Delta x\\\\&=\lim_{n \to \infty}\sum^n_{i=1}f\left(a+\left(\dfrac{b-a}{n}\right)i\right) \cdot \left(\dfrac{b-a}{n}\right)\end{aligned}[/tex]

The given interval is [1, 13]. Therefore, a = 1 and b = 13:

[tex]\implies \Delta x=\dfrac{13-1}{n}=\dfrac{12}{n}[/tex]

As f(x) = ⁷√x then:

[tex]\implies f(x_i)=f(a+i \Delta x)=\sqrt[7]{a+\Delta x \cdot i}=\sqrt[7]{1+\dfrac{12i}{n}}[/tex]

Substituting into the summation formula:

[tex]\begin{aligned}\displaystyle \int^{13}_1 \sqrt[7]{x}\; \text{d}x&=\lim_{n \to \infty}\sum^n_{i=1}\sqrt[7]{1+\left(\dfrac{13-1}{n}\right)i} \cdot \left(\dfrac{13-1}{n}\right)\\\\&=\lim_{n \to \infty}\sum^n_{i=1}\left(\dfrac{12}{n}\right)\sqrt[7]{1+\dfrac{12i}{n}}\\\\\end{aligned}[/tex]

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Answer: n>5

Step-by-step explanation:

The ratio of the sides of the medium box to the small box is 3:1, the ratio of the area of the bases is 9:1, and the ratio of the volumes is 27:1 and the volume of the medium box is 5832 cubic inches.

Let's denote the side length of the small cube as "s". Since it is a cube, all sides are equal.

Given that the volume of the small box is 216 cubic inches, we can set up the equation;

Volume of small box = s³ = 216

Taking the cube root of both sides, we get;

s = ∛216 = 6 inches

So, the side length of the small cube is 6 inches.

For the medium box, the length, width, and height are all tripled, so the new side length of the medium cube is 3 times the side length of the small cube:

Side length of medium cube = 3s = 3 × 6 = 18 inches

Now, let's calculate the ratio of the sides, area of the bases, and volumes of the small and medium boxes;

Ratio of sides: Side length of medium cube / Side length of small cube = 18 / 6 = 3

Ratio of area of bases: (Side length of medium cube)² / (Side length of small cube)² = (18)² / (6)² = 9

Ratio of volumes: (Volume of medium box) / (Volume of small box) = (Side length of medium cube)³ / (Side length of small cube)³ = (18)³ / (6)³ = 27

So, the ratio of the sides of the medium box to the small box is 3:1, the ratio of the area of the bases is 9:1, and the ratio of the volumes is 27:1.

The volume of the medium box is given by;

Volume of medium box = (Side length of medium cube)³ = 18³

= 5832 cubic inches

Therefore, the volume of the medium box is 5832 cubic inches.

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The measure of angle 3 is 52⁰.

The measure of angle 5 is 38⁰.

The measure of angle 6 is 52⁰.

The measure of angle 3, 5 and 6 is calculated as follows;

angle 1 + angle 2 + angle 3 = 180 (sum of angles in straight line )

90 + 38 + angle 3 = 180

angle 3 = 180 - 128

angle 3 = 52⁰

The measure of angle 5 is calculated as follows;

angle 5 = angle 2 (vertical opposite angles are equal)

angle 5 = 38⁰

The measure of angle 6 is calculated as follows;

angle 6 = angle 3 (vertical opposite angles are equal)

angle 6 = 52⁰

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The side x of the triangular base prism is 0.4 centimetres.

The diagram above is a triangular prism. The triangular base of the prism is a right triangle. Therefore, the unknown side x can be found using Pythagoras's theorem,

c²= a² + b²

where

Therefore,

x² = 0.5² - 0.3²

x² = 0.25 - 0.09

x = √0.16

x = 0.4 cm

Therefore,

x = 0.4 centimetres.

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Check the picture below.

Answer:

[tex]\huge\boxed{\sf x = 10\°}[/tex]

Step-by-step explanation:

According to the statement,

92° + x + 78° = 180°

170° + x = 180°

x = 180° - 170°

[tex]\rule[225]{225}{2}[/tex]

Answer: He would be spending $15.25 for each person including himself

Step-by-step explanation:

step 1. you need to find out how many people are getting food

step 2. divide that number (5) by how much the total cost is ($76.25) to get 15.25

1) For the following set of test scores for a history class, 100, 45, 60, 60, 50, 50, 45, 95, 60, 55, 40, it would be better for the teacher to consider D) The mean because it is higher and the teacher wants to feel good about the students.

2) The mode of these data about the high temperatures in Orlando for the past 8 days would be 90.

3) The median of these data about the high temperatures in Orlando for the past  8 days would be 80.

The mean, mode, and median are three centers of measurement.

The mean refers to the average value in the data set, obtained as the quotient of the total value divided by the number of items.

The mode refers to the value that occurs most in the data set.

Lastly, the median is the middle value for a data set arranged in descending or ascending order.

1. Test Scores:

100, 45, 60, 60, 50, 50, 45, 95, 60, 55, 40

Total value = 660

Number of data items = 11

Mean = 60 (660 ÷ 11)

Median = 55

Mode = 60

2. High Temperature:

91, 90, 90, 90, 84, 82, 81, 90

Total Value = 698

Number of data items = 8

Mean = (87.25 (698 ÷ 8)

Median = 90

Mode = 90

3. High Temperature:

91, 90, 90, 90, 84, 82, 81,90

Median = 80 (81, 82, 84, 90, 90, 90, 90, 91)

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The required mean will increase to about 12.6 when another student of age 15 joins the class, and the correct answer is C.

The original mean is the sum of the ages divided by the number of students:

Mean = (10 + 10 + 11 + 12 + 12 + 13 + 13 + 14 + 14 + 15) / 10

Mean = 124 / 10

Mean = 12.4

If another student of age 15 joins the class, the new sum of the ages is:

Sum = 10 + 10 + 11 + 12 + 12 + 13 + 13 + 14 + 14 + 15 + 15

Sum = 139

The new mean is the new sum of ages divided by the new number of students:

New mean = Sum / (Number of students + 1)

New mean = 139 / 11

New mean = 12.63636... or about 12.6 (rounded to one decimal place)

Therefore, the mean will increase to about 12.6 when another student of age 15 joins the class, and the correct answer is C.

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The answers are 1) 360,000, 2) 217,060, 3) 37,140 and 4) 180,080.

1) To calculate the amount of premium paid by the employee and the employer =

Consider employee medical insurance payable, and employee life insurance payable.

The journal entries for accrual payroll, including employee deductions, consider sales salaries expense office salaries expense, social sec taxes payable Medicare tax payable, employee income taxes, life insurance payable, union dues, salaries payable.

2) Journal entry for cash payment of net payroll for month of July consider salaries payable and cash.

3) Calculate the unemployment tax amount, consider state unemployment taxes and federal unemployment taxes,

Journey Entries for accrued employer payroll taxes,

Payroll taxes expenses, social taxes, Medicare taxes, state unemployment taxes, federal unemployment taxes, employee medical and life insurance.

4) Journal entries for cash payment of all libraries, consider, social medical taxes, employee fed, medical, life and state income taxes payable.  

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The points are not at a distance of 6 units from each other.

Given that the distance between point (2, 2) and point (8, 2) is 6 units a coordinate plane.

We need to find which other pairs of points are also 6 units apart.

The distance between two points (x₁, y₁), (x₂, y₂) are 6 if and only if either

( x₂ - x₁ = 6 and y₂ = y₁ )or ( x₂ = x₁ and y₂ - y₁ = 6 ).

If either of the conditions is satisfied, then only we can say that the two points has distance of 6 units between them.

Now, As given

Let (x₁, y₁) = ( 2, 2) , (x₂, y₂) = (8, 2)

Check whether the conditions are satisfied or not .

Here x₁ = 2 , x₂ = 8, y₁ = 2, y₂ = 2

Now,

x₂ - x₁ = 8 - 2 = 6 , y₂ - y₁ = 2 - 2 = 0

∴ we get

1st condition is satisfied, So the points have a distance of 6 units between them.

Now,

Let us suppose another point (x₁, y₁) = ( 4, 3) , (x₂, y₂) = (3, 3)

Here x₁ = 4 , x₂ = 3, y₁ = 3, y₂ = 3

Now,

x₂ - x₁ = 4 - 3 = 1 , y₂ - y₁ = 3 - 3 = 0

Here neither of the conditions are satisfied.

So, the points are not at a distance of 6 units from each other.

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The equation |x| = 9 has two solutions: x = 9 and x = -9. The shaded region includes all points to the left of -9 and all points to the right of 9.

The equation is given as follows:

|x| = 9

The equation |x| = 9 has two solutions: x = 9 and x = -9.

To check these solutions, we can substitute them back into the original equation and see if they satisfy it:

|x| = 9

|9| = 9 --> True

|-9| = 9 --> True

Therefore, the solutions x = 9 and x = -9 are both valid.

To graph the solution(s), we can draw a number line and mark the points x = 9 and x = -9 with closed circles (since the absolute value of x is equal to 9 at those points).

We can then shade the parts of the number line where the absolute value of x is greater than or equal to 9.

This includes all points to the right of 9 and all points to the left of -9.

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Answer

[tex]\large\textrm{There are two solutions: 9 and -9.}[/tex]

Further explanation

If we have the absolute value of x, that means x could be positive or negative.

This means that, in |x| = 9, x could be 9 or -9.

 Plug the answers into the original equation.

You should get a true statement.

because the absolute value of 9 is 9 so that's a solution

the absolute value of -9 is also 9 so that's also a solution

therefore, the solutions are 9 and -9.