Please help !!!!!!!!!!!!!!!!

b) By basing on the findings in part (a), we rejected the null hypothesis. This implies that a Type I error – which is the mistake of disregarding a validly-true null supposition – could have potentially been made.

(c) Since the confidence interval holds both negative and positive values, we are not able to confirm that leastwise some dissimilarity might exist between these two proportions.

d) Raising the power of the test may be achievable by lessening the significance level.

In this state, it would indicate that we concluded that there exists a considerable divergence between the proportion of men and women intending to vote for Trump when factually there is no distinction.

Raising the power of the test may be achievable by lessening the significance level. Doing so will penalize us with being more lenient towards taking up the alternate assumption, consequently reducing the likelihood of having a Type II error.

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Answer:

0, -2.5

Step-by-step explanation:

First find the latitude coordinate (N-S)

=0

2nd find the longitude coordinate (W-E)

=-2.5

since it's between -3 and -2, we'll put a decimal 5 (.5)

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{13\% of 50}}{\left( \cfrac{13}{100} \right)50}\implies 6.5[/tex]

Answer: 6.5

Step-by-step explanation: You can find the percent of a number by multiplying the two together such as 50(0.13). This will give you the answer of 6.5.

The volume of the solid is 1922.7 in³.

The volume of a solid can be found by adding the volume of the shapes that make the solid. In this case:

Volume of solid = volume of hemisphere + volume of cylinder

Volume =  2/3πr³ + πr²h

where r = 12/2 = 6 in

height of cylinder (h) = 13 - 6 = 7 in

Volume =  (2/3 * π * 6³) + (π * 6² * 13)

Volume =  1922.7 in³

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The most accurate for a Zero-Based Budget is You put every dollar of your take-home pay into a budget category each month. Option A

Zero-based budgeting (ZBB) is simply defined as a method of budgeting having that all expenses must be checked for each new period.

The process of zero-based budgeting is one that begins from a zero account

Note that the budgets are carried out when it is needed for the upcoming period, regardless of whether the budget is less or greater than the previous one.

It is important to note the following;

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The given statement, "Signed numbers are also called directed numbers" is true.

Signed numbers are numbers that can be positive, negative, or zero, and they are sometimes referred to as directed numbers because they have a direction or orientation on the number line. Positive numbers are usually associated with movements to the right on the number line, while negative numbers are associated with movements to the left.

Therefore, the given statement, "Signed numbers are also called directed numbers" is true.

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Answer:

Given system of linear equations are

2x+3y+3z=5

x−2y+z=−4

3x−y−2z=3.

Represent it in matrix form

⎣

⎢

⎢

⎡

2

1

3

3

−2

−1

3

1

−2

⎦

⎥

⎥

⎤

⎣

⎢

⎢

⎡

x

y

z

⎦

⎥

⎥

⎤

=

⎣

⎢

⎢

⎡

5

−4

3

⎦

⎥

⎥

⎤

which is in the form of AX=B

A=

⎣

⎢

⎢

⎡

2

1

3

3

−2

−1

3

1

−2

⎦

⎥

⎥

⎤

∣A∣=10+15+15=40



=0

∴ A

−1

exists

To find adjoint of A

A

11

=5,A

12

=5,A

13

=5

A

21

=3,A

22

=−13,A

23

=11

A

31

=9,A

32

=1,A

33

=−7

Adj(A)=co-factor

⎣

⎢

⎢

⎡

5

3

9

5

−13

1

5

11

−7

⎦

⎥

⎥

⎤

=

⎣

⎢

⎢

⎡

5

5

5

3

−13

11

9

1

−7

⎦

⎥

⎥

⎤

A

−1

=

∣A∣

1

Adj(A)

=

40

1

⎣

⎢

⎢

⎡

5

5

5

3

−13

11

9

1

−7

⎦

⎥

⎥

⎤

X=A

−1

B

=

40

1

⎣

⎢

⎢

⎡

5

5

5

3

−13

11

9

1

−7

⎦

⎥

⎥

⎤

⎣

⎢

⎢

⎡

5

−4

3

⎦

⎥

⎥

⎤

X=

40

1

⎣

⎢

⎢

⎡

25−12+27

25+52+3

25−44−21

⎦

⎥

⎥

⎤

X=

40

1

⎣

⎢

⎢

⎡

40

80

−40

⎦

⎥

⎥

⎤

⎣

⎢

⎢

⎡

x

y

z

⎦

⎥

⎥

⎤

=

⎣

⎢

⎢

⎡

1

2

−1

⎦

⎥

⎥

⎤

Hence, x=1,y=2 and z=−1

The solution to the system of equations is

x = 3

y = 2

z = 2

To solve for x, y, and z, we can use the elimination method or substitution method. Here, we will use the elimination method.

First, we will eliminate y from the equations by multiplying the first equation by 3 and the second equation by 1, and then adding them:

(3) (2x – y + 3z = 10)

6x – 3y + 9z = 30

(1) (x + 3y – 2z = 5)

x + 3y – 2z = 5

Adding the two equations gives:

7x + 7z = 35

Simplifying, we get

x + z = 5 (Equation 1)

Next, we will eliminate y again by multiplying the second equation by 2 and the third equation by 3, and then adding them:

(2) (x + 3y – 2z = 5)

2x + 6y – 4z = 10

(3) (3x – 2y + 4z = 12)

9x – 6y + 12z = 36

Adding the two equations gives:

11x + 8z = 46

Substituting x + z = 5 from Equation 1 into the above equation, we get:

11(x + z) + 8z = 46

11x + 19z = 46

Solving for z, we get:

z = 2

Substituting z = 2 into x + z = 5 from Equation 1, we get:

x + 2 = 5

x = 3

Finally, substituting x = 3 and z = 2 into any of the original equations, we can solve for y:

2x – y + 3z = 10

2(3) – y + 3(2) = 10

6 – y + 6 = 10

y = 2

Therefore, the solution to the system of equations is:

x = 3

y = 2

z = 2

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Answer:

To find the area of the rectangle BCDE, we can use the formula:

Area = length x width

First, we need to find the length and width of the rectangle.

The length of the rectangle is the distance between points B and C, which can be calculated using the distance formula:

distance BC = sqrt((x2 - x1)^2 + (y2 - y1)^2)

= sqrt((-6 - (-9))^2 + (-8 - (-4))^2)

= sqrt(3^2 + (-4)^2)

= sqrt(9 + 16)

= sqrt(25)

= 5

The width of the rectangle is the distance between points C and D:

distance CD = sqrt((x2 - x1)^2 + (y2 - y1)^2)

= sqrt((10 - (-6))^2 + (4 - (-8))^2)

= sqrt(16^2 + 12^2)

= sqrt(256 + 144)

= sqrt(400)

= 20

Since BCDE is a rectangle, the length and width are perpendicular. Therefore, the area of the rectangle can be calculated by multiplying the length and width:

Area = length x width = 5 x 20 = 100

Therefore, the area of BCDE is 100 square units.

Step-by-step explanation:

The cost for a new customer to rent a bay for 6 hours at Top Golf is $22, which includes a $10 player card fee and a $12 bay rental fee at $2 per hour.

Let's let "x" be the total cost for a new customer to rent a bay for 6 hours.

We know that there is a flat fee of $10 for the player card, and then an additional $2 per hour for the bay rental.

So, the equation for the cost "x" can be written as

x = 10 + 2(6)

The expression 2(6) represents the cost of the bay rental for 6 hours. We can simplify the expression by multiplying 2 and 6, which gives us

x = 10 + 12

Now, we can combine like terms to find the final cost

x = 22

Therefore, the cost for a new customer to rent a bay for 6 hours at Top Golf is $22.

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--The given question is incomplete, the complete question is given

" For a new customer top golf charges $10 for a player card and $2 per hour. Write and solve a linear equation to find the cost for a new customer to rent a bay for 6 hours."--

Answer:

-7≤y≤2

Step-by-step explanation:

The range measures the highest and lowest numbers up and down on the y-axis for a line. In order to determine range, start with the smallest number (the farthest place the line touches going down) then write less than or equal to. This is because the two dots are closed, meaning they include what the line touches. Afterward, add another less than or equal to, and then add the biggest number (the highest place the line touches going up). The range basically gives you your boundaries, and tells you how high or low the line you are describing is. And after that, you're done!

I hope this helps :)

A belt runs a pulley at 80 revolutions per minute.

(a) To find the angular speed of the pulley in radians per second, we can use the formula

ω = 2πf

Where

ω = angular speed in radians per second

f = frequency in Hertz

We know that the pulley rotates at a rate of 80 revolutions per minute. To convert this to a frequency in Hertz, we can divide by 60 seconds per minute

f = 80 rev/min ÷ 60 min/s = 4/3 Hz

Now we can plug in this value for f into the formula

ω = 2πf = 2π(4/3) = 8π/3 rad/sec

Therefore, the angular speed of the pulley is 8π/3 radians per second.

(b) To find the linear speed of the belt in centimeters per second, we can use the formula

v = rω

Where

v = linear speed in centimeters per second

r = radius of the pulley in centimeters

ω = angular speed in radians per second

We know the radius of the pulley is given in centimeters. Let's assume it is r cm. We just found the angular speed to be 8π/3 radians per second. Now we can plug in these values into the formula

v = rω = r(8π/3) = (8π/3)r cm/s

Therefore, the linear speed of the belt is (8π/3)r centimeters per second.

The given question is incomplete and the complete question is ''A belt runs a pulley at 80 revolutions per minute. Find the angular velocity of the pulley in radians per second. (b)Find the linear speed of the belt in centimeters per second''.

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The rectangular coordinates from the polar coordinates are: (-4√2, -4√2)

The steps to  to convert polar coordinates to rectangular coordinates are:

Step 1: Find the x -coordinate for the rectangular coordinate form of the point by using the equation x = r cos(θ)

Step 2: Find the y -coordinate for the rectangular coordinate form of the point by using the equation y = rsin(θ)

Step 3: Write the rectangular coordinates as (x,y) using the results from steps 1 and 2.

We are given the polar coordinates as (8, 225°)

Thus:

x-coordinate of rectangular coordinate = 8 cos 225 = -4√2

y-coordinate of rectangular coordinate = 8 sin 225 = -4√2

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Answer: C. V ≈ 635.2 cm^3.

Explanation: The formula for the volume of a cone is V = (1/3)πr^2h, where r is the radius and h is the height (or slant height in this case).

Using the given values, we have:

V = (1/3)π(4.25 cm)^2(12 cm)

V ≈ 635.2 cm^3 (rounded to the nearest tenth)

Therefore, the answer is C. V ≈ 635.2 cm^3.

Answer:

b

Step-by-step explanation:

The critical value from the given data is 2.776.

Hypothesis Testing:

Step 1: State the null and alternative hypotheses.

Null Hypothesis (H0): The average number of units taken by students in PSY 190 is equal to the average number of units taken by Rio Hondo students.

Alternative Hypothesis (H1): The average number of units taken by students in PSY 190 is greater than the average number of units taken by Rio Hondo students.

Step 2: Calculate a test statistic.

To calculate a test statistic, we will use a one-sample t-test. The t-test will allow us to compare the average of the PSY 190 students to the average of all Rio Hondo students. The test statistic will be calculated as follows:

t = (x - μ) / (s/√n)

Where x is the sample mean, μ is the population mean, s is the sample standard deviation, and n is the sample size.

In this case, x = 10.6, μ = 9.1, s = 5.1, and n = 5.

Plugging these values into the equation, we get:

t = (10.6 - 9.1) / (5.1/√5) = 1.78

Step 3: Determine the critical value.

To determine the critical value, we need to determine the degrees of freedom, which is equal to n-1 = 4. We can then look up the critical value in a t-table with α = 0.05 and 4 degrees of freedom. The critical value is 2.776.

Step 4: Compare the test statistic to the critical value.

Since the test statistic (1.78) is less than the critical value (2.776), we fail to reject the null hypothesis.

Therefore, the critical value from the given data is 2.776.

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a) The probability that the student was female is 43/76

b) The probability that the student was female AND got a "C" is 9/38

c) The probability that the student was female OR got a "C" is 45/76

We have,

             A   B   C  

Male     16  15  2  33

Female 14  11  18  43

Total     30 26 20 76

a) The probability that the student was female

= 43/76

b) The probability that the student was female AND got a "C"

= 18/76

= 9/38

c) The probability that the student was female OR got a "C"

= 43 /76 + 20/76 - 18/76

= 45/76

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The quadratic polynomial with integer as coefficients that has four real roots including these conjugates is a² + b² - 2ab - 20a - 20b + 88 ≥ 0

One possible quartic polynomial with integer coefficients that has four real roots, including the conjugates 5+√3 and 5-√3, is:

(x - 5 - √3)(x - 5 + √3)(x - a)(x - b)

where a and b are the remaining two roots.

Expanding the first two factors using the difference of squares formula, we get:

(x - 5)² - 3

Expanding the last two factors, we get:

x² - (a + b)x + ab

Putting it all together, the quartic polynomial is:

a² + b² - 2ab - 20a - 20b + 88 ≥ 0

To ensure that a and b are also real, we can use the fact that the discriminant of a quadratic equation ax² + bx + c = 0 with real coefficients is b² - 4ac ≥ 0. Applying this to the quadratic factor in the above polynomial, we get:

(a + b)² - 4ab ≥ 0

Expanding and simplifying, we get:

a² + b² - 2ab - 20a - 20b + 88 ≥ 0

To simplify the problem, we can set a = b, since the polynomial is symmetric with respect to the roots. Then, the inequality becomes:

2a² - 40a + 88 ≥ 0

Dividing by 2 and factoring, we get:

(a - 10)² - 12 ≥ 0

This inequality is always true for real values of a, so we can choose any real value for a and set b = a to obtain a quartic polynomial with integer coefficients that has four real roots, including the conjugates 5+√3 and 5-√3.

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Answer:

<HAG

Step-by-step explanation:
Two angles are adjacent when they have a common side and common vertex, and they do not overlap one another. In this case, <EAG, A is the vertex. <HAG has the same vertex, A, and it shares side AG.

Dela will use 24 teaspoons of vinegar and 75 teaspoons of olive oil to make 6 containers of salad dressing.

We have,

Dela uses a ratio of 4 teaspoons of vinegar to 12.5 teaspoons of olive oil.

So, for 6 containers

= 4 x 6

= 24 teaspoons of vinegar

and, = 12.5 x 6

= 75 teaspoons of olive oil

Thus, Dela will use 24 teaspoons of vinegar and 75 teaspoons of olive oil to make 6 containers of salad dressing.

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Answer:

16.

Step-by-step explanation:

The test score for Jason will be 55% for answering 11 questions right.

The percentage is defined as representing any number with respect to 100. It is denoted by the sign %. The percentage stands for "out of 100." Imagine any measurement or object being divided into 100 equal bits.

Given that Jason is taking a multiple-choice test with a total of 20 points available. Each question is worth exactly 1 point.

The test score will be calculated as,

[tex]\text{Test score} =\dfrac{\text{Total questions - wrong answers}}{\text{Total questions}} \times100[/tex]

[tex]\text{Test Score}=\huge \text[\dfrac{(20-9)}{20}\huge \text] \times100[/tex]

[tex]\text{Test Score}=0.55\times100[/tex]

[tex]\text{Test Score}=0.55\%[/tex]

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Note that the probabilities are given below.

a) the probability of a randomly selected catch being a mouse caught by Cyd

p(Catching a mount) x p(Cyd made the catch)

= 0.5x .2

= 0.1

b) the   probability of a bird not caught by Cyd is 0.5 x 0.8 = 0.4.

Thus

P(that a catch is a bird) x p(the Cyd didn't make the catch)

= 0.3 x 0.8

=0.24

c) The probability of a randomly selected catch being caught by Greg is 0.45

To calculate, we say

(0.5   x0.45) + (0.3 x 0.45) + (0.2 x .45)

= 0.45.

d)

P (mouse caught by Greg) = (0.45 x 0.5) / 1

= 0.225.

e) P(catch is a mouse caught by Ken and catch is a mouse)

= P(catch is a mouse | catch is made by Ken) x P(catch is made by Ken)

= 0.05 x 0.1

= 0.005

f)

P (catch made by Cyd | catch is a mouse)

= 0.1    x 0.2 / 0.5

= 0.04

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The  vector-valued function is continuous at t=2,

are

A vector-valued function, is described as a mathematical function of one or more variables whose range is a set of multidimensional vectors or infinite-dimensional vectors.

We are required  to check if the limit of the function as t approaches 2 exists and is equal to the value of the function at t=2, in order to determine if the  vector-valued function is continuous at t=2.

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The equation that could be used to find the distance that the tornado traveled is: log d = 0.7

We are told that The wind speed near the center of a tornado is represented by the equation S = 93 log d + 65,

where:

d is the distance, in miles, that the tornado travels.

S is the wind speed, in miles per hour.

When S = 130, we have:

130 = 93 log d + 65

93 log d = 130 - 65

93 log d = 65

log d = 65/93

log d = 0.7

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The most expensive car loan that Cindy can afford is $14,534.

The most expensive car loan is calculated by applying the following formula.

M.P = (Pr) / (1 - (1 + r)^(-n))

Where;

215 = (P x 0.00175) / (1 - (1 + 0.00175)^(-72))

215 = (P x 0.00175)/0.1183

(P x 0.00175) = 215 x 0.1183

P x 0.00175 = 25.44

P =  $14,534

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The solid formed when the right triangle is rotated around the side length of 5 is two cones with a radius of 1.5 units and a height of 1.8 units and 3.2 units.

The volume of the smaller cone is approximately 3.82 cubic units, and the surface area is approximately 20.94 square units.

The volume of the larger cone is approximately 6.04 cubic units, and the surface area is approximately 20.94 square units.

We have,

When the right triangle is rotated around the side length of 5, it forms two cones with different heights and radii.

Now,

r = base / 2 = 3 / 2 = 1.5 units

h = height = 4 units

Using the Pythagorean theorem,

l = √(1.5² + 4²) = √(18.25) ≈ 4.27 units

The first cone has a radius of 1.5 units and a height of 1.8 units (5 - 4.27)

The second cone has a radius of 1.5 units and a height of 3.2 units (5 - 1.8).

Now,

The volume of a cone.

V = (1/3)πr^2h

The surface area of a cone.

A = πrl + πr^2

For the first cone:

V = (1/3)π(1.5)²(1.8) = 3.82 cubic units

A = π(1.5)(4.27) + π(1.5)² = 20.94 square units

For the second cone:

V = (1/3)π(1.5)²(3.2) = 6.04 cubic units

A = π(1.5)(4.27) + π(1.5)² = 20.94 square units

Thus,

The solid formed when the right triangle is rotated around the side length of 5 is two cones with a radius of 1.5 units and a height of 1.8 units and 3.2 units.

The volume of the smaller cone is approximately 3.82 cubic units, and the surface area is approximately 20.94 square units.

The volume of the larger cone is approximately 6.04 cubic units, and the surface area is approximately 20.94 square units.

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Answer:

down your esophagus into your stomach

Step-by-step explanation:

After you swallow, peristalsis pushes the food down your esophagus into your stomach. Stomach. Glands in your stomach lining make stomach acid and enzymes that break down food. Muscles of your stomach mix the food with these digestive juices.

The estimated population of the city after 3 years would be 8,537 people.

To find the population of the city after 3 years, we can use the formula for compound interest;

A = P ×[tex](1+r)^{t}[/tex]

where;

A = the final amount (population after 3 years)

P = the initial amount (initial population of the city) = 5,741

r = the annual growth rate (as a decimal) = 14% = 0.14

t = the number of years = 3

Plugging in the values, we get

A = 5,741 × (1 + 0.14)³

Simplifying the expression inside the parentheses first;

A = 5,741 × (1.14)³

Then, raising 1.14 to the power of 3;

A = 5,741 × 1.485136

A ≈ 8,536.98

So, the estimated population of the city after 3 years would be approximately 8,536.98 people. Since population cannot be in decimal numbers, we can round it to the nearest whole number;

A ≈ 8,537

Therefore, the estimated population of the city after 3 years would be 8,537 people.

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Answer:

Step-by-step explanation:

You want the number of day passes sold for $61 and weekend passes sold for $110 if 257 more day passes were sold, and sales totaled $307745.

Let w represent the number of weekend passes sold. Then w+257 is the number of day passes sold. The total revenue is ...

  61(w+257) +110(w) = 307745

Simplifying the equation, we have ...

  171w +15677 = 307745

  171w = 292068 . . . . . . . . subtract 15677

  w = 1708 . . . . . . . . . . . divide by 171

  w+257 = 1965 . . . day passes sold

1965 day passes and 1708 weekend passes were sold.

<95141404393>

Answer:

The nearest tenth, Container A is about 46.3% full after the pumping is complete.

Step-by-step explanation:

To solve this problem, we need to find the volume of water in Container A and compare it to the volume of Container B.

The volume of water in Container A can be found using the formula for the volume of a cylinder:

V_A = πr^2h = π(6^2)(9) = 324π cubic feet

The volume of Container B can also be found using the same formula:

V_B = πr^2h = π(5^2)(12) = 300π cubic feet

After the water is pumped from Container A to Container B, Container B will be completely full, which means it will contain 300π cubic feet of water. To find the height of the water level in Container A, we need to find the height of the cylinder that would contain 300π cubic feet if it had a radius of 6 feet:

V_A' = πr^2h' = 300π

h' = 300/(36π) = 25/6 feet

So the height of the water level in Container A is 25/6 feet. Since the height of Container A is 9 feet, the percent of Container A that is full is:

(25/6) / 9 * 100% ≈ 46.3%

Therefore, to the nearest tenth, Container A is about 46.3% full after the pumping is complete.