a bar of gold measures .113m *.0254m*.0106m. how many gallons of water have the same mass as this bar?
The volume (in gallon) of water that have the same mass as the bar of gold is 0.153 gallon
How do I determine the volume (in gallon) of water?We'll begin by obtaining the mass of the gold bar. This is given below:
Volume of gold bar = 0.113 m × 0.0254 m × 0.0106 m = 0.00003 m³Density of gold = 19300 kg/m³Mass of gold bar =?Density = mass / volume
Cross multiply
Mass = Density × Volume
Mass of gold bar = 19300 × 0.00003
Mass of gold bar = 0.579 Kg
Finally, we shall determine the volume of water having the same mass as 0.579 Kg of the gold bar. Details below:
Mass of gold bar = 0.579 KgMass of water = Mass of gold bar = 0.579 KgDensity of water = 1000 Kg/m³ Volume of water = ?Volume = mass / density
Volume of water = 0.579 / 1000
Volume of water = 0.000579 m³
Multiply by 264.172 to express in gallon
Volume of water = 0.000579 × 264.172
Volume of water = 0.153 gallon
Thus, we can conclude that the volume of the water is 0.153 gallon
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A 5.0 kilogram initially at rest is accelerated by a force of 25 newtons such that it attains 5.0 x 102 joules of kinetic energy. Determine the final speed of the object.
Answer:
Below
Explanation:
Final Kinetic Energy = 1/2 m v^2
5 x 10^2 J = 1/2 ( 5 kg)(v^2 )
1000 / 5 = v^2
200 = v^2
v = 10 sqrt 2 or 14.1 m/s
Name 3 different ways of reducing the effect of sound waves.
Answer:
There are several basic ways to reduce sound: increasing the distance between source and receiver, decoupling, using noise barriers to reflect or absorb the energy of the sound waves, using damping structures such as sound baffles for absorption, or using active antinoise sound generators.
If a wave of wavelength 1m and another wave of wavelength 3m are both transmitted at a velocity of 120m/s, what is the frequency difference between these signals?
What would the Roche limit be for an earth-orbiting body with the same density as iron(8.0g/cm ^3)
The 35m would the Roche limit be for an earth-orbiting body with the same density as iron(8.0g/cm ^3).
What is density ?
How much material an object contains per unit volume is determined by the density of the substance. It is symbolized by the letter D, however it can also be represented by the symbol. The density of a substance reveals how dense it is in a certain space. The definition of density is the mass of a substance per unit volume.
What is velocity ?
It is measured in meters per second in the SI (ms -1 ). A body is considered to be accelerating if there is a change in the magnitude or direction of its velocity.
Therefore, The 35m would the Roche limit be for an earth-orbiting body with the same density as iron(8.0g/cm ^3).
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Grace is attempting to lift an object off the ground a distance of 3m. She applies 50N of force and generates 75J/s. How long does the lift take?
To lift an object off the ground a distance of 3m, Grace applies 50N of force and generates 75J/s. The time taken by Grace for the lift is 2 seconds.
What is force?A force is an effect that changes, or accelerates, the velocity of a mass-moving object (such as one that is travelling from a state of rest). It is a vector quantity since it can be a push or a pull and always has magnitude and direction. It is denoted by the letter F and is measured in newtons (N), the SI unit of force.
According to Newton's second law, an object's net force is equal to the speed at which its momentum is changing over time. This rule suggests that the acceleration of an object is directly proportional to the net force exerted on the object, is in the direction of the net force, and is inversely proportional to the mass of the object if its mass is constant.
According to the equation,
P = [tex]\frac{W}{t}[/tex]
where,
P is the power,
W is the work done and,
t is the time taken.
W = F×S
where,
F is the applied force and
S is the distance.
Substituting the values and solving for t,
time taken = 2 seconds
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Apollo 14 launched in the late afternoon of January 31, 1971, on what was to be our third trip to the lunar surface. Five days later Alan Shepard
and Edgar Mitchell walked on the Moon while Stuart Roosa, a former U.S. Forest Service smoke jumper orbited above in the command module.
What is the meaning of the phrase command module as it is used in the excerpt?
O A.
the detachable part of a spacecraft
О B.
the part of a spacecraft that contains support systems
O c.
a satellite designed to hold a human astronaut
O D.
a satellite designed to orbit the Moon
The meaning of the phrase command module is a satellite designed to hold a human astronaut. The correct option is C
What is Spacecraft ?
A spacecraft is a vehicle or machine designed to fly in outer space. A Spacecraft is a type of artificial satellite is used for a variety of purposes, including communications, Earth observation, meteorology, navigation, space colonization, planetary exploration, and transportation of humans and cargo. All spacecraft except single stage to orbit vehicles cannot get into space on their own, and require a launch vehicle (carrier rocket).
spacecraft is vehicle like designed to operate with or without a crew, in a controlled conditions inside it.
A command module is a detachable controlled compartment of a manned spacecraft. it housed the three-person crew on liftoff and landing and during the trip to and from the Moon In Apollo 14.
Hence option C is correct option
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How much kinetic energy does a 2.50kg ball traveling at 2.00m/s have?
Answer:
Explanation:
The formula for kinetic energy is K = 1/2mv^2, where K is kinetic energy, m is mass, and v is velocity.
Substituting the given values:
K = 1/2(2.50 kg)(2.00 m/s)^2
K = 1/2(2.50 kg)(4.00 m^2/s^2)
K = 5.00 J
Therefore, the 2.50kg ball traveling at 2.00m/s has 5.00 J of kinetic energy.
Draw a schematic diagram to show the ball's projectile motion after leaving the ramp with a horizontal velocity. Label the height it dropped and the horizontal distance.
When a ball leaves a ramp with a horizontal velocity, it will follow a curved path known as a projectile motion. The ball will move both horizontally and vertically, with the horizontal velocity remaining constant and the vertical velocity changing due to the force of gravity.
At the point where the ball leaves the ramp, it will have a certain height and horizontal distance from the starting point. As it moves through the air, it will travel a certain horizontal distance before landing on the ground at a lower height.
What is projectile motion?Projectile motion is a type of motion in which an object is launched or thrown into the air, and then moves under the influence of gravity and air resistance. In projectile motion, the object follows a curved path called a trajectory, which consists of both horizontal and vertical components.
The motion of a projectile can be described in terms of its velocity, acceleration, and displacement. At the instant of launch, the object has an initial velocity that can be broken down into horizontal and vertical components. The horizontal component of velocity remains constant throughout the motion, while the vertical component changes due to the effect of gravity.
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how long would it take a bolt dropped from a 1.3 m ladder to reach the ground?
a bolt is dropped from a 1.3-meter ladder,the long will it take it to reach the ground is Ladder length: 4.27 m =2.14 meters away.
How do meters work?The metric system's and also the International System of Units' primary unit of length is the metre (m), also spelt as meter (SI). The British Imperial us And the Customary systems both convert it to a measurement of roughly 39.37 inches.
How many meters are there in a foot?Approximately 3 feet, 3 inches are equal to one meter, which is the common metric unit. Therefore, a meter is a unit of measurement in the metric system. One meter long things include, but are not limited to, guitars, baseball bats, or yardsticks. In competitions like running and swimming, meters are also employed to gauge distances.
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URGENT HELP NEEDED!!! BRAINLIEST WILL BE PICKED!!!
A 0.35 g BB is fired into a stationary 6.0 g ball of clay. If the BB is fired with a speed of 46 m/s, and becomes embedded in the clay ball, how fast does the clay ball move after the collision?
3.9 m/s
2.7 m/s
23 m/s
2.5 m/s
According to the question the clay ball moves with a velocity of 2.5 m/s after the collision.
What is velocity?Velocity is the speed of an object in a specific direction. It is a vector quantity and is typically represented by the symbol v. It is the rate of change of an object's position and is expressed in units of distance divided by time, such as meters per second (m/s). Velocity can be constant, meaning the object is traveling at a steady speed, or it can be changing, meaning the object is accelerating or decelerating.
The answer is 2.5 m/s. This is because the total momentum of the system (BB + clay ball) before the collision is 0 (since the clay ball is stationary). Therefore, the total momentum of the system after the collision is 0 as well. Using the equation for momentum (p = mv), we can calculate the velocity of the clay ball after the collision.
p (total) = 0 = (0.35 g) (46 m/s) + (6.0 g) (v)
v = -2.5 m/s
Therefore, the clay ball moves with a velocity of 2.5 m/s after the collision.
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which of the following is not a type of energy?
Answer:
Neutronic is not a defined type of energy.
URGENT HELP NEEDED!!!
If a force of 50.0 N acts on a 3.0 kg object for 2.0 seconds, what will its change in momentum be? what will its change in velocity be?
100 kg*m/s
300 kg*m/s
75 kg*m/s
150 kg*m/s
PART B
33 m/s
150 m/s
75 m/s
70 m/s
Answer:
The change in momentum will be 100 kg*m/s, and the change in velocity will be 33 m/s.
Explanation:
HELP PLEASE!!!
You have studied and researched different forms of renewable and nonrenewable resources. what recommendations would you make to the committee regarding the types of resources that could be used to generate electricity? This paragraph should be a persuasive writing piece as you consider all you have learned based upon evidence. (8 pts.)
As we consider the best options for generating electricity, it is important to prioritize renewable resources over nonrenewable ones. While nonrenewable resources such as coal and natural gas may provide a quick and reliable source of energy, they have significant negative impacts on both human health and the environment. Renewable resources, on the other hand, offer a sustainable solution to our energy needs without the harmful side effects. Solar, wind, and hydro power are all viable options that have been proven effective and efficient. While the initial investment may be higher, the long-term benefits are worth the cost. As we move towards a more sustainable future, it is crucial that we prioritize renewable resources for generating electricity.
Please help me i need this to pass :((
Based on the densities of the two liquids, the height of the light liquid in the right arm of the U-tube is 0.203 cm.
What is the height L of the light liquid in the column in the right arm of the U-tube?Let's first consider the situation before the light liquid is added. At this point, the heavy liquid fills both arms of the U-tube to the same height, h.
The pressure at point A is equal to the pressure at point B
Therefore:
P₀ + ρgh = P₀ + ρgh
where P₀ is the atmospheric pressure, ρ is the density of the heavy liquid, and g is the acceleration due to gravity.
Simplifying this equation, we get:
ρgh = ρgh
Canceling out the ρ and solving for h, we get:
h = h
In other words, the height of the heavy liquid is the same in both arms of the U-tube.
Now let's consider the situation after the light liquid is added to the right arm of the U-tube. We want to find the height, L, of the light liquid in the right arm.
Since the pressure at any two points in a connected vessel is the same, the pressure at point B (the top of the heavy liquid in the right arm) must be equal to the pressure at point C (the top of the light liquid in the right arm).
Therefore, we can write:
P₀ + ρgh = P₀ + ρg(L+h)
where L is the height of the light liquid in the right arm.
Simplifying this equation, we get:
ρgh = ρgL + ρgh
Canceling out the ρgh and solving for L, we get:
L = (ρ/ρ₀)h
where ρ₀ is the density of the light liquid.
Substituting the given values, we get:
L = (0.92 g/cm³ / 13 g/cm³)h
L = 0.070769h
Now we need to find h. We can use the fact that the volume of the heavy liquid in the left arm is equal to the volume of the heavy liquid plus the light liquid in the right arm.
The volume of the heavy liquid in the left arm is:
V₁ = Ah = (13.2 cm²)(h cm)
V₁ = 13.2h cm³
The volume of the heavy liquid plus the light liquid in the right arm is:
V₂ = A(L+h) = (2.11 cm²)(L+h cm)
V₂ = 2.11(L+h) cm³
Since these volumes are equal, we can set them equal to each other and solve for h:
13.2h = 2.11(L+h)
13.2h = 2.11L + 2.11h
11.09h = 2.11L
h = (2.11/11.09)L
Substituting this into our expression for L, we get:
L = 0.070769(2.11/11.09)L
L = 0.01345L
L = 0.01444h
Substituting the given value for the density of the heavy liquid, we get:
L = 0.01444h = 0.01444(13 g/cm³)/(0.92 g/cm³)
L = 0.203 cm
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Complete question:
A heavy liquid with a density 13 g/cm³ is poured into a U-tube as shown in the left- hand figure below. The left-hand arm of the tube has a cross-sectional area of 13.2 cm², and the right-hand arm has a cross-sectional area of 2.11 cm². A quantity of 90.2 g of a light liquid with a density 0.92 g/cm³ is then poured into the right-hand arm as shown in the right-hand figure below.
Determine the height L of the light liquid in the column in the right arm of the U-tube, as shown in the second figure above. Answer in units of cm.
Two points in the xy plane have Cartesian coordinates (5.00, −5.50) m and (−7.00, 7.00) m.
Determine the distance between these points.
Two points in the xy plane have Cartesian coordinates (5.00, −5.50) m and (−7.00, 7.00) m.So, the distance between two points in the xy-plane is 17.32 m.
What is Distance?
Distance is a measurement in numbers of the area between two locations or objects. It is a scalar quantity that symbolises the distance between two places in space or the length of a path taken by an object. Depending on the situation and the scale of the items being measured, distance can be expressed in a variety of ways, including metres, kilometres, miles, feet, and so forth.
Displacement, a vector number that denotes the shift in an object's location with respect to a reference point, is frequently distinguished from distance in physics. Displacement, as opposed to distance, which only analyses the size of the path travelled, considers both the distance travelled by an object and its direction of motion.
To find the distance between two points in the xy-plane, we use the distance formula:
d = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]
where (x1, y1) and (x2, y2) are the coordinates of the two points.
Using the given coordinates, we have:
x1 = 5.00 m, y1 = -5.50 m
x2 = -7.00 m, y2 = 7.00 m
Substituting these values into the formula, we get:
d = [tex]\sqrt{(-7.00 - 5.00)^2 + (7.00 - (-5.50))^2}[/tex]
d= [tex]\sqrt{(-12.00)^2 + (12.50)^2}[/tex]
d= [tex]\sqrt{(144.00 + 156.25)}[/tex]
d= [tex]\sqrt{(300.25)}[/tex]
d=17.32 m
Therefore, the distance between the two points is approximately:
d = 17.32 m (rounded to two decimal places)
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Assume that bone will fracture if a shear stress more than 9.00 × 10^7 N/m^2 is exerted. What is the maximum force that can be exerted on the femur bone in the leg if it has a minimum effective diameter of 9.00 cm ? Young’s modulus for bone is 1.8 × 10^10 N/m^2 Answer in units of kN
The area of the bone is 0.785 m². Then the maximum force that can be exerted on the femur bone if the shear stress is 9 × 10⁷ N/m² is 70650 kN.
What is young's modulus ?The Young's modulus of a material is the ratio of its stress to strain. Where stress is the force per unit area and strain be the ratio of change in length to the original length.
given stress s = 9 × 10⁷ N/m²
diameter of the bone d = 9 cm = 0.09 m.
then area = π d²/4
a = 3.14 × (0.09 m )²/4 = 0.785 m².
Stress = maximum force/area
then Fmax = stress × area
Fmax = 9 × 10⁷ N/m² × 0.785 m²
= 70650 kN.
Therefore, the maximum force that can be exerted to the bone is 70650 kN.
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Explain why it is so difficult to ride a bicycle in soft sand.
Soft sand makes it challenging to ride a bicycle since the tires can't generate enough friction. The bicycle struggles to move ahead as a result, and its tires sink.
The danger of ridding a bicycle in soft sandRiding a bicycle on soft sand poses a risk of the vehicle being stuck and challenging to move. Injuries might result if the rider loses balance and falls off the bicycle. The frame, tires, and other parts of the bicycle could also be harmed by the sand.
Furthermore, sand, dirt, wood chips, deep pea gravel, soft grass, and snow all drastically alter your speed. Sand, however, can be the most challenging of all of them because you typically enter the area quickly from grass or another hard surface.
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A 0.300 kg mass is attached o a 26.6 N/m spring. It is pulled 0.120 m and released. How much Potential Energy does it have when it is 0.0600 m from equilibrium? ( Unit - J) (It's not 0.144 J)
The potential energy of the mass is 0.0452 J when it is at a distance of
0.0600 m from equilibrium.
How to calculate potential energy?
The potential energy stored in a spring when it is stretched or compressed by a displacement x is given by:
[tex]$PE = \frac{1}{2}kx^2$[/tex]
where k is the spring constant.
In this problem, the spring constant is given as 26.6 N/m, and the displacement of the mass from equilibrium is
[tex](0.120 m - 0.0600 m) = 0.0600 m.[/tex]
Therefore, the potential energy stored in the spring when the mass is at a distance of 0.0600 m from equilibrium is:
[tex]$PE = \frac{1}{2}kx^2 = \frac{1}{2}(26.6 N/m)(0.0600 m)^2 = 0.0452 J$[/tex]
So the potential energy of the mass is 0.0452 J when it is at a distance of 0.0600 m from equilibrium.
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Answer: 0.0479
Explanation: This answer works for Acellus! :D
hope this helps!
Which falling object has the least kinetic energy when it collides on the ground?
A. 120 Kg of sand falling 12 m/s
B. 12 Kg of water falling at 10 m/s
C. 12 Kg of sand falling at 8 m/s
D. 120 Kg of water falling at 12 m/s
The object with the least kinetic energy, given the above instances is water with a mass of 12 Kg falling at 10 m/s (option B)
How do I know which object has the least kinetic energy?To know the object which has the least kinetic energy, we shall determine the kinetic energy of each objects. This is illustrated below:
For sand (Option A):
Mass (m) = 120 KgVelocity (v) = 12 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 120 × 12²
KE = 8640 J
For water (Option B):
Mass (m) = 12 KgVelocity (v) = 10 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 12 × 10²
KE = 60 J
For sand (Option C):
Mass (m) = 12 KgVelocity (v) = 8 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 12 × 8²
KE = 384 J
For water (Option D):
Mass (m) = 120 KgVelocity (v) = 12 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 120 × 12²
KE = 8640 J
From the above calculations, it is evident that the water with a mass of 12 Kg falling at 10 m/s has the least kinetic energy. Thus, the correct answer is option B
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Please help (50 points and Brainly)
Answer:
the asnsweis wavew
Explanation:
i just need rge points tbh
1.3.2 Quiz. what is another way to describe the vector below? "40 feet to the right"
The vector described as "40 feet to the right" can also be expressed as a displacement vector. It represents the change in position of an object as it moves from one point to another.
Specifically, the vector denotes a horizontal displacement of 40 feet in the positive x-direction from the starting point.
Another way to describe the vector is to use a coordinate system. If we place the starting point at the origin (0,0) and define the x-axis to be the horizontal direction and the y-axis to be the vertical direction, then the vector can be represented as (40,0), where the first number corresponds to the x-coordinate and the second number corresponds to the y-coordinate. This notation emphasizes the fact that the vector has no vertical displacement, only a horizontal displacement of 40 feet.
Alternatively, we could describe the vector using magnitude and direction. The magnitude of the vector is simply its length, which in this case is 40 feet. The direction of the vector can be described as "to the right" or "in the positive x-direction." This notation is useful when comparing vectors with different magnitudes but the same direction or vice versa.
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45.0J of work is done on a 1.50kg ball at rest. What is the velocity of the ball?
30.0m/s
5.48m/s
60.0m/s
7.75m/s
Answer:
7.75 m/s.
Explanation:
We can use the work-energy principle to solve this problem. The principle states that the work done on an object is equal to the change in its kinetic energy:
W = ΔK
where W is the work done, ΔK is the change in kinetic energy.
In this case, the work done on the ball is 45.0 J. Since the ball is initially at rest, its initial kinetic energy is zero. Therefore, the change in kinetic energy is:
ΔK = Kf - Ki = 1/2 mv^2 - 0
where Kf is the final kinetic energy, Ki is the initial kinetic energy, m is the mass of the ball, and v is its velocity.
Substituting the given values, we get:
45.0 J = 1/2 (1.50 kg) v^2
Solving for v, we get:
v^2 = (2 x 45.0 J) / (1.50 kg)
v^2 = 60.0
v = √60.0
v ≈ 7.75 m/s
Therefore, the velocity of the ball is approximately 7.75 m/s.
Which object has the greatest kinetic energy?
A. a truck with a mass of 3,500 kg moving at 30 m/s
B. a fast pitched baseball with a mass of .5 kg moving at 46.9 m/s
C. a locomotive engine with a mass of 205,000 kg moving 5 m/s
D. a person with a mass of 73 kg running 6 m/s
The object with the greatest kinetic energy is the locomotive engine (option C)
How do I know which object has the greatest kinetic energy?To know the object with the greatest kinetic energy, we shall determine the kinetic energy of each objects. Details below:
For truck:
Mass (m) = 3500 KgVelocity (v) = 30 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 3500 × 30²
KE = 1575000 J
For baseball:
Mass (m) = 0.5 KgVelocity (v) = 46.9 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 0.5 × 46.9²
KE = 549.90 J
For locomotive:
Mass (m) = 205000 KgVelocity (v) = 5 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 205000 × 5²
KE = 2562500 J
For person:
Mass (m) = 73 KgVelocity (v) = 6 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 73 × 6²
KE = 1314 J
From the above calculations, we can see that the locomotive has the greatest kinetic energy. Thus, the correct answer is option C
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How do you find the number of electrons, protons and neutrons that are in
the atom of an element with the aid of an example
If the atomic number is given then the number of electrons and protons is the same as the atomic number, but the number of neutrons can be calculated by subtracting the atomic number from the atomic mass number of the element.
What is the Atomic mass number?We know that inside the nucleus protons and neutrons are present, the sum of the protons and newtons is called the atomic mass number. and the electron revolves around the nucleus for the stability of an element the number of positive charges (protons ) should be the number of negative charges (electrons).
For example, take Fluorine(F)
Fluorine has a mass number(M)= 19
Atomic number(Z) =9
Now no. of protons in fluorine is = 9
no. of electrons in fluorine is= 9
no of newton in fluorine= M-Z=19-9=10
Hence the number of protons and electrons are same as the atomic number and the number of neutrons is the difference between the atomic mass number and the no f protons or the atomic number.
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6. As you drive your car along a country road at night, a deer jumps out of the woods and stands in
the middle of the road ahead of you. This occurs just as you are passing from a 55-mi/h zone to a 50-
mi/h zone. At the 50-mi/h speed-limit sign, you slam on the car's brakes, causing them to lock up,
and skid to a stop inches from the startled deer. As you breathe a sigh of relief, you hear the sound
of a police siren. The policeman proceeds to write you a ticket for driving 56 mi/h in 50-mi/h zone.
Because of your preparation in physics, you are able to use the 25-m-long skid marks that your car
left behind as evidence that you were not speeding. What evidence do you present? You must use
work/energy methods to solve this problem! The coefficients of friction between car tires and dry
concrete are (u=1.0, μ=0.80).
As the speed of the car was less than the posted speed limit of 50 mi/h when the brakes were applied, skid marks provide evidence that driver was not speeding at the time of incident.
What is meant by coefficient of friction?Measure of the amount of friction existing between the two surfaces is called as coefficient of friction.
Change in kinetic energy is: ΔK = 0 - 1/2mv²
W = fd
As f = μN
N = mg
fd = ΔK
μN d = 1/2mv²
μmgd = 1/2mv²
v = √(2μgd/m)
v = √(20.8025*0.45/1) ≈ 29.9 mi/h
Since the car's speed was less than the posted speed limit of 50 mi/h when the brakes were applied, the skid marks provide evidence that the driver was not speeding at the time of the incident.
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Kelly lifts a 4500-newton barbell at a height of 7 meters. What are the joules of work being put out?
Pls help and fast <3
Answer:
31,500 joules
Explanation:
Work = force * distance * cos(theta)
Force = 4500N (weight of the barbell)
Distance = 7m (the height lifted)
Theta = 0 (cosine of 0 degrees is 1, since the force and distance are in the same direction)
So, Work = 4500 N * 7m * cos(0)
Work = 31,500 joules
What is the acceleration on a body that approached the earth and comes within 6
earth radii of the earth’s surface?
The acceleration on a body that approached the earth and comes within 6 earth radii of the earth’s surface is 0.2 m/s².
How can we calculate the acceleration of the body?The acceleration of the body can be calculated using the equation-
g = g0 R/(R + H)².
In the question, we have, h = 6R
g = 9.8 x R/(R + 6R)²
By putting in the values and calculating, we get,
g = 0.2 m/s².
What causes a body to accelerate when the earth attracts it?Where g' = Gravitational Acceleration at Height, R = Earth's Radius, and g = Gravitational Acceleration at Earth's Surface. As a result, at a distance of 2R from the earth's surface, the acceleration of a body caused by the earth's attraction is equal to g/9.
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Have average hpurly earnings in the United States increased sinced 1980? Answer question using the words nominal and real .
Yes, the average hourly earnings in the United States have increased since 1980, both nominal wages and in real terms.
What are nominal wages?
Nominal wages refer to the actual dollar amount earned, without any adjustments for inflation. When looking at nominal wages, we can see that the average hourly earnings in the United States have indeed increased since 1980. According to data from the Bureau of Labor Statistics, the average hourly earnings for all employees in the private sector was $3.10 in 1980, and has since increased to $31.73 in 2021.However, inflation has also been a factor during this time period, meaning that the purchasing power of a dollar has decreased over time. Real wages take into account the effects of inflation, allowing us to compare earnings over time in terms of purchasing power. When we adjust for inflation using a measure like the Consumer Price Index (CPI), we can see that while the nominal wage has increased, the real wage has not increased as much. In other words, even though workers are earning more in nominal terms, their earnings have not kept pace with the rising cost of living.So, while both nominal and real wages have increased since 1980, the extent to which they have increased depends on the measure used.To know more about nominal wages, click the link given below:
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If you stretched a rubber band so that it had 100-J of potential energy, with how much kinetic energy will the rock leave the slingshot?
Answer:
less than 100-J
Explanation:
The potential energy held in the stretched rubber band is turned into kinetic energy of the rock when it is released, assuming that the rubber band is used to launch a rock from a slingshot.
The mass of the rock and the effectiveness of the slingshot in transmitting the energy from the rubber band to the rock are two elements that affect how much kinetic energy the rock will have. To estimate the kinetic energy, though, we may make certain generalizations.
Assume that no energy is lost as a result of friction or air resistance and that the entire potential energy held in the rubber band is transformed into the kinetic energy of the rock. In this hypothetical situation, the potential energy of the stretched rubber band would be equal to the kinetic energy of the rock.
As a result, the rock will have 100 J of kinetic energy when it exits the slingshot if the rubber band contains 100 J of potential energy. The actual kinetic energy of the rock would be less than 100 J since some energy will be wasted owing to things like friction.
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