Please help!!!!
I’m using Plato

Step-by-step explanation:

The Answer Is Provided Below ➳

(2²)² = 2⁴/2⁴ = 2⁰ × 2⁰ = 2⁰/2⁰

Answer:

65 solve theprob

Step-by-step explanation:

sinolove ko po yan paki brainly

Answer:

Range = -1 ≤ y ≤ 2

Step-by-step explanation:

The function's range is the y-values the function can have as its output. -1 is the minimum y-value and 2 is the maximum y-value.

Answer:

I have not been able to answer it sorry

Answer:

0.03 more flour per cupcake

Step-by-step explanation:

3.12/8 = 0.39

2.52/7 = 0.36

0.39 - 0.36 = 0.03

Hope this helps c:

Answer:

[tex] \theta = 4~radians [/tex]

Step-by-step explanation:

[tex] s = \theta r [/tex]

[tex] 20~cm = \theta \times 5~cm [/tex]

[tex] \theta = 4~radians [/tex]

Answer:

1. +30

2. +64

3. 0

4. -3

5. +24

6. +18

7. -48

8. -64

9. +21

10. -30

11. +12

12. 0

13. -4

14. +56

15. +2

Step-by-step explanation:

When multiplying integers:

two negatives = positive

two positives = positive

one negative x one positive = negative

So, if the signs are the same, the answer is positive.

If you have two different signs, the answer is negative.

You multiply the integers like normal.

Anything multiplied by zero = 0.

Anything multiplied by one = itself (just be careful of the sign).

Answer:

[tex]f(g(2)) = 2[/tex]

Step-by-step explanation:

Given

[tex]x \to f(x)[/tex]

[tex]-6 \to 1[/tex]

[tex]-3 \to 2[/tex]

[tex]g(x) = f^{-1}(x)[/tex] --- inverse

Required

[tex]f(g(2))[/tex]

For two functions f(x) and g(x) where f(x) and g(x)are inverse;

[tex]f(g(x)) = x[/tex]

So, by comparison:

[tex]f(g(2)) = 2[/tex]

Answer:

Step-by-step explanation:

slope = (y2 - y1)/(x2 - x1)

x2 = -3

x1 = 1

y2 = 1

y1 = - 11

slope = (1 - - 11) / (-3 - 1)

slope = 12 / - 4

slope = - 3

Answer:

The volume is maximum when the height is 3 cm.

Step-by-step explanation:

let the side of the removed potion is x.

length of the box = 18 - 2 x

width of the box = 18 - 2 x

height = x

Volume of box

V = Length x width x height

[tex]V = (18 - 2 x)^2 \times x\\\\V = x(324 + 4x^2 - 72 x)\\\\V = 4 x^3 - 72 x^2 + 324 x \\\\\frac{dV}{dx} = 12 x^2 - 144 x + 324 \\\\So,\\\\ \frac{dV}{dx} =0\\\\x^2 - 12 x + 27 = 0 \\\\x^2 -9 x - 3 x + 27 =0\\\\x (x - 9) - 3 (x -9) = 0\\\\x = 3, 9[/tex]

Now

[tex]\frac{d^2V}{dx^2}=24 x - 144 \\\\Put x = 3 \\\\\frac{d^2V}{dx^2}=24\times 3 - 144 = - 72\\\\Put x = 9\\\\\frac{d^2V}{dx^2}=24\times 9 - 144 = 72\\[/tex]

So, the volume is maximum when x = 3 .

Answer:

2×(6ײ+3×-1)=18.

2×(6×3×+4)(6×4×-3)=144

2×(6×3×-2)(4×2+4×-6)=1154..

12×2=24

12×2+7×-12=60

12×2+25×-12=276

12×3+4×2-10×+12=76

12×3+4×2-26×+12=8

12×3+6×2-2=46

Answer:

a) 11670-0.09%

b)11670-1.8%=11459

Step-by-step explanation:

Answer:

a)  b^5/12

Step-by-step explanation:

b^2/3 ÷ b^1/4    [if bases are the same then subtract the exponents]

2/3 - 1/4 = 5/12

Complete question is;

Components arriving at a distributor are checked for defects by two different inspectors (each component is checked by both inspectors). The first inspector detects 83% of all defectives that are present, and the second inspector does likewise. At least one inspector does not detect a defect on 34% of all defective components. What is the probability that the following occurs?

(a) A defective component will be detected only by the first inspector?

b) A defective component will be detected by exactly one of the two inspectors?

(c) All three defective components in a batch escape detection by both inspectors (assuming inspections of different components are independent of one another)?

Answer:

A) 0.17

B) 0.34

C) 0

Step-by-step explanation:

a) We are told that the first inspector(A) detects 83% of all defectives that are present, and the second inspector(B) also does the same.

This means that;

P(A) = P(B) = 83% = 0.83

We are also told that at least one inspector does not detect a defect on 34% of all defective components.

Thus;

P(A' ⋃ B') = 0.34

Also, we now that;

P(A ⋂ B) = 1 - P(A' ⋃ B')

P(A ⋂ B) = 1 - 0.34

P(A ⋂ B) = 0.66

Probability that A defective component will be detected only by the first inspector is;

P(A ⋂ B') = P(A) - P(A ⋂ B)

P(A ⋂ B') = 0.83 - 0.66

P(A ⋂ B') = 0.17

B) probability that a defective component will be detected by exactly one of the two inspectors is given as;

P(A ⋂ B') + P(A' ⋂ B) = P(A) + P(B) - 2P(A ⋂ B)

P(A) + P(B) - 2P(A ⋂ B) ; 0.83 + 0.83 - 2(0.66) = 0.34

C) Probability that All three defective components in a batch escape detection by both inspectors is written as;

P(A' ⋃ B') - (P(A ⋂ B') + P(A' ⋂ B))

Plugging in the relevant values, we have;

0.34 - 0.34 = 0

Answer:

yes

Step-by-step explanation:

its correct because divide by 2/ 28/16=14/8

maybe

Answer: the answer is c

Step-by-step explanation:brainlist [tex]\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right][/tex]

Answer: 98%

Step-by-step explanation:

[tex]\frac{77+65+x}{3} =80\\\frac{142+x}{3} =80\\142+x=80*3\\x=240-142=98[/tex]

Answer:

49 mph

Step-by-step explanation:

RT=D

T = D/R

[tex]\frac{1995}{(350 + x) } =\frac{1505}{350-x}[/tex]

1995(350-x) = 1505(350+x)

x=49

Answer:

?????????????????

Step-by-step explanation:

????????

9514 1404 393

Answer:

  LCD = 18

Step-by-step explanation:

6 and 9 have a common factor of 3, so the LCD is ...

  (6×9)/3 = 18

Then the fractions can be written as ...

  3/6 = 9/18

  2/9 = 4/18

Answer:

x=70

y=30

z=20

Step-by-step explanation:

x=180-110 (angles on a straight line)

y=180-110-40 (angle sum of triangle)

z= 180-90-70 (angle sum of triangle)

Answer:

x=70°

y=30°

z=20°

Step-by-step explanation:

x=180°-110°(anlges on a straight line)

x=70°

y+110°+40°=180°(sum of angles of triangle)

y+150°=180°

y=180°-150°

y=30°

z+x+90°=180°(sum of angles of triangle)

z+70°+90°=180°

z+160°=180°

z=180°-160°

z=20°

Answer:

B = 25

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Distributive Property

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

4(9y - 5) = 10(3y + 17) - 40

Step 2: Solve for y

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{4(9y - 5) = 10(3y + 17) - 40}\\\\\large\textsf{4(9y) + 4(-5) = 10(3y) + 10(17) - 10(40)}\\\\\large\textsf{36y - 20 = 30y + 170 - 40}\\\\\large\textsf{COMBINE the LIKE TERMS}\\\\\large\textsf{36y - 20 = (30 y)+ (170 - 40)}\\\\\large\textsf{36y - 20 = 30y + 130}\\\\\large\textsf{SUBTRACT 30y to BOTH SIDES}\\\\\large\textsf{36y - 20 - 30y = 30y + 130 - 30}}\\\\\large\textsf{Cancel out: 30y - 30y because that gives you 0}\\\\\large\textsf{Keep: 20 - 30y because helps solve for the y-value}[/tex]

[tex]\large\textsf{NEW EQUATION: 6y - 20 = 130}\\\\\large\textsf{ADD 20 to BOTH SIDES}\\\\\large\textsf{6y - 20 + 20 = 130 + 20}\\\\\large\textsf{Cancel out: -20 + 20 because that gives you 0}\\\\\large\textsf{Keep: 130 + 20 because that helps solve for the y-value}\\\\\large\textsf{130 + 20 = \bf 150}\\\\\large\textsf{NEW EQUATION: 6y = 150}\\\\\large\textsf{DIVIDE 6 to BOTH SIDES}\\\\\mathsf{\dfrac{6y}{6}= \dfrac{150}{6}}\\\\\large\textsf{Cancel: }\mathsf{\dfrac{6}{6}\large\textsf{ because that gives you 1}}[/tex]

[tex]\large\textsf{Keep: }\mathsf{\dfrac{150}{6}}\large\textsf{ because it helps solve for the y-value}\\\\\large\textsf{\bf y = }\mathsf{\dfrac{150}{6}}\\\\\large\textsf{OR }\\\\\mathsf{\dfrac{150}{6} }\large\textsf{ = \bf y}\\\\\\\large\textsf{SIMPLIFY ABOVE AND TOU YOU HAVE YOUR Y-VALUE}\uparrow\\\\\\\\\boxed{\boxed{\large\textsf{\huge\textsf{Answer: \bf y = 25} (Option B.)}}}\huge\checkmark\\\\\\\\\large\text{Good luck on your assignment and enjoy your day!}\\\\\\\\\\\frak{Amphitrite1040:)}[/tex]

Answer:

(1/8x)-(5/6)

Step-by-step explanation:

-3/4x-1/3+7/8x-1/2

-6/8x-2/6+7/8x-3/6

-6/8x+7/8x-2/6-3/6

1/8x-5/6

Answer:

10 hours

Step-by-step explanation:

ok so we know he is getting payed $20 + $7 every hour so what i would do is keep the multiply the 7 till you get 70 so thats 7x10=70 and 70+20=90 so he worked for 10 hours last week :)  i hope this helps, i tried my best to explain it

Answer:

Yes, it is possible to have  a relation on the set {a, b, c} that is both symmetric and transitive but not reflexive

Step-by-step explanation:

Let

Set A={a,b,c}

Now, define a relation R on set A is given by

R={(a,a),(a,b),(b,a),(b,b)}

For reflexive

A relation is called reflexive if (a,a)[tex]\in R[/tex] for every element a[tex]\in A[/tex]

[tex](c,c)\notin R[/tex]

Therefore, the relation R is  not reflexive.

For symmetric

If [tex](a,b)\in R[/tex] then [tex](b,a)\in R[/tex]

We have

[tex](a,b)\in R[/tex] and [tex](b,a)\in R[/tex]

Hence, R is symmetric.

For transitive

If (a,b)[tex]\in R[/tex] and (b,c)[tex]\in R[/tex] then (a,c)[tex]\in R[/tex]

Here,

[tex](a,a)\in R[/tex] and [tex](a,b)\in R[/tex]

[tex]\implies (a,b)\in R[/tex]

[tex](a,b)\in R[/tex] and [tex](b,a)\in R[/tex]

[tex]\implies (a,a)\in R[/tex]

Therefore, R is transitive.

Yes, it is possible to have  a relation on the set {a, b, c} that is both symmetric and transitive but not reflexive.

I believe your answer is D.) $900

204 + 96 = 300

300 x 3 = 900

I hope this is correct and helps!

Answer:

Part A)

2048π/3 cubic units.

Part B)

8192π/15 units.

Step-by-step explanation:

We are given that R is the finite region bounded by the graphs of functions:

[tex]f(x)=4\sqrt{x}\text{ and } g(x)=x[/tex]

Part A)

We want to find the volume of the solid of revolution obtained when rotating R about the x-axis.

We can use the washer method, given by:

[tex]\displaystyle \pi\int_a^b[R(x)]^2-[r(x)]^2\, dx[/tex]

Where R is the outer radius and r is the inner radius.

Find the points of intersection of the two graphs:

[tex]\displaystyle \begin{aligned} 4\sqrt{x} & = x \\ 16x&= x^2 \\ x^2-16x&= 0 \\ x(x-16) & = 0 \\ x&=0 \text{ and } x=16\end{aligned}[/tex]

Hence, our limits of integration is from x = 0 to x = 16.

Since 4√x ≥ x for all values of x between [0, 16], the outer radius R is f(x) and the inner radius r is g(x). Substitute:

[tex]\displaystyle V=\pi\int_0^{16}(4\sqrt{x})^2-(x)^2\, dx[/tex]

Evaluate:

[tex]\displaystyle \begin{aligned} \displaystyle V&=\pi\int_0^{16}(4\sqrt{x})^2-(x)^2\, dx \\\\ &=\pi\int_0^{16} 16x-x^2\, dx \\\\ &=\pi\left(8x^2-\frac{1}{3}x^3\Big|_{0}^{16}\right)\\\\ &=\frac{2048\pi}{3}\text{ units}^3 \end{aligned}[/tex]

The volume is 2048π/3 cubic units.

Part B)

We want to find the volume of the solid of revolution obtained when rotating R about the y-axis.

First, rewrite each function in terms of y:

[tex]\displaystyle f(y) = \frac{y^2}{16}\text{ and } g(y) = y[/tex]

Solving for the intersection yields y = 0 and y = 16. So, our limits of integration are from y = 0 to y = 16.

The washer method for revolving about the y-axis is given by:

[tex]\displaystyle V=\pi\int_{a}^{b}[R(y)]^2-[r(y)]^2\, dy[/tex]

Since g(y) ≥ f(y) for all y in the interval [0, 16], our outer radius R is g(y) and our inner radius r is f(y). Substitute and evaluate:

[tex]\displaystyle \begin{aligned} \displaystyle V&=\pi\int_{a}^{b}[R(y)]^2-[r(y)]^2\, dy \\\\ &=\pi\int_{0}^{16} (y)^2- \left(\frac{y^2}{16}\right)^2\, dy\\\\ &=\pi\int_0^{16} y^2 - \frac{y^4}{256} \, dy \\\\ &=\pi\left(\frac{1}{3}y^3-\frac{1}{1280}y^5\Bigg|_{0}^{16}\right)\\\\ &=\frac{8192\pi}{15}\text{ units}^3\end{aligned}[/tex]

The volume is 8192π/15 cubic units.

If the confidence level will increase, the margin of error will also increases.

The margin of error is defined a range of values below and above the sample statistic in a confidence interval.

The confidence interval is a way to show what is uncertainty is with a certain statistic.

According to the given question

Environmentalist estimating true mean weight or all cars.

For the true mean weights of 2.8 to 3.4 tons the confidence level is 90%.

Since, the confidence level increases, the critical value increases and hence the margin of error increases.

Therefore, if the confidence level will increase, the margin of error will also increases.

Find out more information about confidence interval and margin error here:

https://brainly.com/question/15079850

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