please help!!
maths functions

Please Help!!maths Functions

Answers

Answer 1

Answer:

The Co-ordinate of C is (4/3, -1/2)

Step-by-step explanation:

We have two equation one is of straight line equation which is:

                                              y=2x-3           (i)

Other equation is of quadratic function which is:

                                         y=-3x^2+5         (ii)

Put the value of y from equation (i) in equation (ii)

So, we have:

                                     2x-3=-3x^2+5

                                      3x^2+2x-8=0

By factorization:

                                    3x^2+6x-4x-8=0

                                   3x(x+2)-4x(x+2)=0

                                        (x+2)(3x-4)=0

              x+2=0                             ;                      3x-4=0

              x=-2                                ;                       x=4/3

Put first x=-2 in equation (i)

                                                y=2(-2)-3

                                                  y=-4-3

                                                    y=-7

Now Put x=4/3 in equation (i)

                                             y=2(4/3)-3

                                                 y=8/3-3

                                                   y=-1/2

So, we have two Order pair One is (-2 , -7) and Second one is (4/3 , -1/2)

Hence the Co-ordinate of C is:

                                               C=(4/3 , -1/2)

Please Help!!maths Functions
Answer 2

Answer:

Point C:  (3, 3)

Point D:  (3, -22)

Step-by-step explanation:

If the distance between points C and D is 25 units, the y-value of point D will be 25 less than the y-value of point C.  The x-values of the two points are the same.

Therefore:

[tex]\textsf{Equation 1}: \quad y=2x-3[/tex]

[tex]\textsf{Equation 2}: \quad y-25=-3x^2+5[/tex]

As the x-values are the same, substitute the first equation into the second equation and solve for x to find the x-value of points C and D:

[tex]\implies 2x-3-25=-3x^2+5[/tex]

[tex]\implies 3x^2+2x-33=0[/tex]

[tex]\implies 3x^2-9x+11x-33=0[/tex]

[tex]\implies 3x(x-3)+11(x-3)=0[/tex]

[tex]\implies (x-3)(3x+11)=0[/tex]

[tex]\implies x=3, -\dfrac{11}{3}[/tex]

From inspection of the given graph, the x-value of points C and D is positive, therefore x = 3.

To find the y-value of points C and D, substitute the found value of x into the two original equations of the lines:

[tex]\begin{aligned} \textsf{Point C}: \quad 2x-3 & =y\\2(3)-3 & =3\\ \implies & (3, 3)\end{aligned}[/tex]

[tex]\begin{aligned} \textsf{Point D}: \quad -3x^2+5 & = y \\ -3(3)^2+5 & =-22\\ \implies & (3, -22)\end{aligned}[/tex]

Therefore, point C is (3, 3) and point D is (3, -22).


Related Questions

Calculus help please, will give brainiest

Answers

The most convenient way to capture [tex]D[/tex] is with the parameterization

[tex]D = \left\{(x,y) \mid -1 \le y \le 3 \text{ and } -\dfrac{y+1}2 \le x \le y+1\right\}[/tex]

so we only need one iterated integral.

[tex]\displaystyle \iint_D e^{x-y} \, dA = \int_{-1}^3 \int_{-(y+1)/2}^{y+1} e^{x-y} \, dx \, dy[/tex]

Compute the integral with respect to [tex]x[/tex].

[tex]\displaystyle \int_{-(y+1)/2}^{y+1} e^{x-y} \, dx = e^{x-y} \bigg|_{x=-(y+1)/2}^{x=y+1} = e^{(y+1)-y} - e^{-(y+1)/2-y} = e - e^{-(3y+1)/2}[/tex]

Compute the remaining integral.

[tex]\displaystyle \int_{-1}^3 \left(e - e^{-(3y+1)/2}\right) \, dy = \left(ey + \frac23 e^{-(3y+1)/2}\right)\bigg|_{y=-1}^{y=3} \\\\ ~~~~~~~~ = \left(3e + \frac23 e^{-(9+1)/2}\right) - \left(-e + \frac23 e^{-(-3+1)/2}\right) \\\\ ~~~~~~~~ = \boxed{\frac{10e}3 + \frac2{3e^5}}[/tex]

If we had chosen the opposite order of variables, we would have used

[tex]D = \left\{(x,y) \mid -2 \le x \le 4 \text{ and } \max\left(-2x-1,x-1\right)\le y\le3\right\}[/tex]

where

[tex]\max(-2x-1, x-1) = \begin{cases} -2x-1 & \text{when } x<0 \\ x-1 & \text{when } x\ge0\end{cases}[/tex]

so we would have needed two iterated integrals,

[tex]\displaystyle \iint_D e^{x-y} \, dA = \int_{-2}^0 \int_{-2x-1}^3 e^{x-y} \, dy \, dx + \int_0^4 \int_{x-1}^3 e^{x-y} \, dy \, dx[/tex]

ASAP HELP ME WITH THIS QUESTIONN

Answers

Answer:

inductive reasoning

Step-by-step explanation:

When a force of 60 N acts on a certain object, the acceleration of the object is 6/ms2. if the acceleration of the object becomes 7/ms2, what is the force?

Answers

When the acceleration is 7 m/s², it means that the force will be 70 N.

How to find the force on an object?

From newton's first law of motion, we know that;

F = ma

where;

m is mass

a is acceleration

We are given;

F = 60 N

a = 6 m/s²

Thus;

m = F/a = 60/6

m = 10 kg

When acceleration is 7 m/s², we have;

F = 10 * 7

m = 70 N

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Item3 4.28 points eBookReferencesCheck my workCheck My Work button is now enabledItem 3 Yarra Fabrication estimates that its manufacturing overhead will be $2,342,400 in year 1. It further estimates that direct material costs will amount to $1,464,000. During July, Yarra worked on four jobs with actual direct materials costs of $76,000 for Job 0701, $104,000 for Job 0702, $135,000 for Job 0703, and $67,000 for Job 0704. Actual manufacturing overhead costs for the year were $2,480,000. Actual direct materials costs were $1,630,000. Manufacturing overhead is applied to jobs based on direct materials cost using predetermined rates. Required: a. How much overhead was applied to each of the four jobs, 0701, 0702, 0703, and 0704? b. What was the over- or underapplied manufacturing overhead for year 1?

Answers

The amount of overhead applied to each of the four jobs are $121,600, $166,400, $216,000 and $107,200 respectively.The overapplied manufacturing overhead for year 1 is equal to $128,000.

How to calculate the amount of overhead?

First of all, we would calculate the predetermined overhead rate by using this formula:

Predetermined overhead rate = Manufacturing overhead/Direct material costs

Predetermined overhead rate = $2,342,400/$1,464,000

Predetermined overhead rate = 1.6 per DM $.

Next, we would calculate the overhead applied by using this formula:

Overhead applied = Job × DM cost

For job 0701, we have:

Overhead applied = 76,000 × 1.6

Overhead applied = $121,600.

For job 0702, we have:

Overhead applied = 104,000 × 1.6

Overhead applied = $166,400.

For job 0703, we have:

Overhead applied = 135,000 × 1.6

Overhead applied = $216,000.

For job 0704, we have:

Overhead applied = 67,000 × 1.6

Overhead applied = $107,200.

Part B.

For the overapplied manufacturing overhead for year 1:

Less applied overhead = $1,630,000 × 1.6

Less applied overhead = $2,608,000.

Overapplied manufacturing overhead = Actual overhead cost - Less applied overhead

Overapplied manufacturing overhead = $2,480,000 - $2,608,000

Overapplied manufacturing overhead = $128,000.

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Find the surface area of the figure. Round to the nearest hundredth of a unit. Let a = 1.9,b = 0.1, and c = 2

Answers

Answer:

I believe its 20.8, but I may be wrong

Step-by-step explanation:

The functions fand g are defined as follows. f(x) = 3x-1 g(x)=3x³ +5 Find f(-6) and g (-4). Simplify your answers as much as possible. ƒ(-6) = g (-4) =​

Answers

Answer:

f(-6)= -19 and g(-4)= -187

What is an equation of the line that passes through the points (-6,0) and (8,7) ?

Answers

Answer:

y = 1/2 x  + 3

Step-by-step explanation:

Find slope, m = (y1-y2)/(x1-x2) =  (7-0) / (8- - 6)  = 7/14 = 1/2

   ( does not matter which one you assign as point 1 or point 2)

Point (-6,0)  slope form ( you can use either point)

(y-0) = 1/2 (x- -6)

y = 1/2 x +3

1. In the process of solving the radical equation, x − 5 =radical 3x −11 , you will need to solve which of the following quadratic equations?
a) x2 −7x+16=0
b) x2 −3x−14=0
c) x2 +13x−36=0
d) x2 −13x + 36 = 0 e)
none of these

Answers

In the process of solving the expression x − 5 =radical 3x −11 , you will need to solve the quadratic equation x² - 13x + 36 =0

Solving radical equations

Radical equations are expression that are under the square root. For instance √x is a radical expression.

Given the equation expressed as:

x − 5 = √3x −11

Square both sides to have;

(x-5)² = (√3x −11 )²

This can be further expressed as:

(x-5)² =3x −11

Expand

x² -10x + 25 = 3x - 11

Equate to zero

x² -10x + 25 - 3x +11 = 0
x² -10x - 3x +36 = 0
x² - 13x + 36 =0

Hence in the process of solving the expression x − 5 =radical 3x −11 , you will need to solve the quadratic equation x² - 13x + 36 =0

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Triangle Congruency Theorems: Edge High School Geometry

Answer is below:

Answers

DE ≅ CE given that side AD and side BC are equal and angle ∠BCD and angle ∠ADC are equal. This can be obtained by using triangle congruency theorems.

Prove that  side DE and side CE is equal:

Triangle congruency theorems required in the question,

SAS triangle congruency theorem - SAS means Side-angle-side. If two sides and the included angle of a triangle is equal to two sides and the included angle of another triangle then the triangles are congruent.AAS triangle congruency theorem - AAS means Angle-angle-side. If two angles and one side of a triangle is equal to two angles and one side of another triangle then the triangles are congruent.

 

In the question it is given that,

⇒ Side DE and side CE are equal ⇒ AD ≅ BC

⇒ angle ∠BCD and angle ∠ADC are equal ⇒ ∠BCD ≅ ∠ADC

AD ≅ BC (given in the question)∠BCD ≅ ∠ADC (given in the question)DC ≅ DC (since DC is a common side; reflexive property)

Therefore we can say that,

ΔADC ≅ ΔBCD according to the SAS triangle congruency theorem

∠DAE ≅ ∠CBE (corresponding parts of congruent triangles are congruent (CPCTC))AD ≅ BC (given in the question)∠DEA ≅ ∠CEB  (since they are vertically opposite angles - vertical angles theorem)

ΔAED ≅ ΔBEC according to the AAS triangle congruency theorem

Thus DE ≅ CE since corresponding parts of congruent triangles are congruent (CPCTC).

Hence DE ≅ CE given that side AD and side BC are equal and angle ∠BCD and angle ∠ADC are equal.

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Nationally, patients who go to the emergency room wait an average of 7 hours to be admitted into the hospital. Do patients at rural hospitals have a lower waiting time? The 13 randomly selected patients who went to the emergency room at rural hospitals waited an average of 6.3 hours to be admitted into the hospital. The standard deviation for these 13 patients was 1.3 hours. What can be concluded at the the
α
= 0.01 level of significance level of significance?

For this study, we should use
Select an answer
The null and alternative hypotheses would be:

H
0
:

?

Select an answer




H
1
:

?

Select an answer



The test statistic
?
=
(please show your answer to 3 decimal places.)
The p-value =
(Please show your answer to 4 decimal places.)
The p-value is
?

α

Based on this, we should
Select an answer
the null hypothesis.
Thus, the final conclusion is that ...
The data suggest the population mean is not significantly lower than 7 at
α
= 0.01, so there is statistically insignificant evidence to conclude that the population mean waiting time to be admitted into the hospital from the emergency room for patients at rural hospitals is equal to 7 hours.
The data suggest the populaton mean is significantly lower than 7 at
α
= 0.01, so there is statistically significant evidence to conclude that the population mean waiting time to be admitted into the hospital from the emergency room for patients at rural hospitals is lower than 7 hours.
The data suggest that the population mean awaiting time to be admitted into the hospital from the emergency room for patients at rural hospitals is not significantly lower than 7 hours at
α
= 0.01, so there is statistically insignificant evidence to conclude that the population mean waiting time to be admitted into the hospital from the emergency room for patients at rural hospitals is lower than 7 hours.

Answers

For this study, we should use t-test and the null and alternative hypotheses would be given by H₀: μ = 7 and H₁: μ < 7.The test statistic is -1.941 and the p-value (0.0381) is greater than α = 0.01. Based on this, we should fail to reject the null hypothesis.Thus, the final conclusion is that the data suggest the population mean is not significantly lower than 7 at α = 0.01, so there is statistically insignificant evidence to conclude that the population mean waiting time to be admitted into the hospital from the emergency room for patients at rural hospitals is equal to 7 hours.

What is a null hypothesis?

A null hypothesis (H₀) can be defined the opposite of an alternate hypothesis (H₁) and it asserts that two (2) possibilities are the same.

How to calculate value of the test statistic?

The test statistics can be calculated by using this formula:

[tex]t=\frac{x\;-\;u}{\frac{\delta}{\sqrt{n} } }[/tex]

Where:

x is the sample mean.u is the mean.is the standard deviation.n is the number of hours.

For this study, we should use t-test and the null and alternative hypotheses would be given by:

H₀: μ = 7

H₁: μ < 7

[tex]t=\frac{6.3\;-\;7}{\frac{1.3}{\sqrt{13} } }\\\\t=\frac{-0.7}{\frac{1.3}{3.6056 } }[/tex]

t = -0.7/0.3606

t = -1.941.

For the p-value, we have:

P-value = P(t < -1.9412)

P-value = 0.0381.

Therefore, the p-value (0.0381) is greater than α = 0.01. Based on this, we should fail to reject the null hypothesis.

Thus, the final conclusion is that the data suggest the population mean is not significantly lower than 7 at α = 0.01, so there is statistically insignificant evidence to conclude that the population mean waiting time to be admitted into the hospital from the emergency room for patients at rural hospitals is equal to 7 hours.

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on a recent trip, the smiths drove at an average speed of 55 miles per hour. if the trip took 5 1/2 hours, how many miles did they drive?

Answers

Answer:

302.5

Step-by-step explanation:

5 1/2 = 5.5

55 miles per hour * 5.5 hours

55*5.5

302.5

Find the length of the a of a right triangle b=21.5 inches and the hypotenuse c =31.9.use the calculator to estimate the square root to one decimal place
The length of the leg a is approximately?

Answers

Answer:

Step-by-step explanation:

        a² + b² = c²

  a² + (21.5)² = (31.9)²

a² + 462.25 = 1017.61    

               a²  = 555.36

                  a = 23.6

Consider the following figure:

Answers

Answer:

x=90

y=148

Step-by-step explanation:

Since we know a line is 180 degrees, and we know that angle Q is 90, x must be a 90-degree angle as well.

With our given information we can add up the two given angles in the triangle which are 90 and 58

90+58=148

To find what R is, we must subtract 148 from 180 because all the angles in a triangle sum up to 180.

180-148=32

Now that we know that R is 32, because we know that a line is 180 degrees, we can subtract 32 from 180 to get our final answer for y as 148.

180-32=148

see attachment for question

Answers

The percentage when Potiphar woke up late is 14.4%.

How to calculate the percentage?

From the information, it was stated that Potiphar takes a horse and buggy to work everyday. In order to come on time, he must wake up promptly at 6.30am and then hop on the buggy and that anytime he wakes up late or the horse was in traffic, he will be late.

It was further illustrated based on the information given in the question that he was late 24.4% of the time and the horse was in traffic for 10% of the time.

Therefore, the percentage when he woke up late will be gotten by simply subtracting the percentages that we have above. This will be illustrated below:

= 24.4% - 10%

= 14.4%

Therefore, the percentage when Potiphar woke up late is 14.4%.

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a tree 20 feet tall with a circumference of 3 ft has a vine wound around 7 times how long is the vine?

Answers

The length of the vine wounded to the tree is 21 feet.

How to solve circumference?

Circumference is the perimeter of a circular object. Therefore,

circumference = 2πr

where

r = radius

The circumference of the tree is 3 feet. A vine was wound around 7 times .

The length of the vine can be calculated as follows:

Therefore,

circumference = 3 ft

length of the vine = 7 × 3

length of the vine = 21 feet

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If Jamaal has 13 nickels and dimes in his pocket, and they have a combined value of 110 cents, how many
of each coin does he have?
dimes
nickels
0/4 pts 3 19 0

Answers

He has 9 dimes and 4 nickels

At the beginning of 2000 Randall's house was worth 234 thousand dollars and Damien's house was worth 110 thousand dollars. At the beginning of 2003, Randall's house was worth 176 thousand dollars and Damien's house was worth 154 thousand dollars. Assume that the values of both houses vary at an exponential rate.

Write a function [tex]f[/tex] ,that determines the value of Randall's house (in thousands of dollars) in terms of the number of years [tex]t[/tex] since the beginning of 2000.

Write a function [tex]g[/tex] that determines the value of Damien's house (in thousands of dollars) in terms of the number of years [tex]t[/tex] since the beginning of 2000.

How many years after the beginning of 2000 will Randall's and Damien's house have the same value?

Answers

Using linear functions, we have that:

Randall's value is: f(t) = -19t + 234.Damien's value is: g(t) = 14.67t + 110They will have the same value in 3.68 years since the start of 2000.
What is a linear function?

A linear function is modeled by:

y = mx + b

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

We consider the initial values as the y-intercepts. Randall's house decayed 58 thousand dollars in 3 years, hence the slope is:

m = -58/3 = -19.

Hence the function for the value, in thousands of dollars, is:

f(t) = -19t + 234.

Damien's initial value was of 110, and it increased 44 thousand in 3 years, hence the slope is:

m = 44/3 = 14.67

Hence the function for the value of Damien's house, in thousands of dollars, in t years after 2003, is:

g(t) = 14.67t + 110

They will have the same value when:

f(t) = g(t)

-19t + 234 = 14.67t + 110

33.67t = 124

t = 124/33.67

t = 3.68

They will have the same value in 3.68 years since the start of 2000.

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what is the range of the function f (x) = lxl +5?

Answers

The range of the function f(x)= IxI+5 is x+5 for x>=0 and -x+5 for x<0.

Given that the function is f(x)=IxI+5.

We are required to find the range of the function.

Function is relationship between two or more variables expressed in equal to form. In a function each value of x must have a corresponding value of y. The value of x is known as domain of the function and the value of y is known as codomain of the function. Range of a function is a limit of values in which the values of function lies.

Function is f(x)= IxI+5

We know that IxI=x for x>=0 and -x<0.

We have to just put the value of IxI in f(x) to get the range of function.

f(x)=x+5 for x>=0 and -x+5 for x<0.

Hence the range of the function f(x)= IxI+5 is x+5 for x>=0 and -x+5 for x<0.

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need heeeelp please

Answers

Step-by-step explanation:

For a rational function, we cannot values in the domain that will make the denominator 0.

So set the denominator =0

[tex] {x}^{2} - 1 = 0[/tex]

[tex] {x}^{2} = 1[/tex]

[tex]x = 1[/tex]

or

[tex]x = - 1[/tex]

So the answer is (-1,1)

Which expression has a value of -24 when a = -2 and b = 3?
A. a√16 + b - 10
B. a(√16 + b) -10
C. a√16 + (b - 10)
D. (a√16) + b - 10

Answers

The option B is correct, The second expression gives the correct value -24.

According to the statement

we have given that the some expression and a = -2 and b = 3 and we have to which expression gives a output of answer -24 after put the values in the expressions.

So, For this purpose

First expression:

[tex]a\sqrt{16} + b - 10[/tex]

Put a = -2 and b = 3

then

[tex]= -2\sqrt{16} + 3 - 10\\= -8 -7\\= 15[/tex]

Second expression:

[tex]a(\sqrt{16} + b) -10[/tex]

Put a = -2 and b = 3

then

[tex]a(\sqrt{16} + b) -10\\-2(4 +3) -10\\-14-10\\-24[/tex]

Now,

Third expression:

[tex]a\sqrt{16} + (b - 10)[/tex]

Put a = -2 and b = 3

then

[tex]a\sqrt{16} + (b - 10)-2*4 + (-7)\\-8-7\\-15[/tex]

Now,

Fourth expression and first expression are same,

So,

Fourth expression:

[tex]a\sqrt{16} + b - 10[/tex]

Put a = -2 and b = 3

then

[tex]= -2\sqrt{16} + 3 - 10\\= -8 -7\\= 15[/tex]

The second expression gives the correct value -24.

So, The option B is correct, The second expression gives the correct value -24.

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A local anime fan club surveyed 81 of its members regarding their viewing habits last weekend, and the following information was obtained: 40 members watched an episode of Naruto, 54 watched an episode of Death Note, 40 watched an episode of Inuyasha, 32 watched both Naruto and Inuyasha, 12 watched Naruto and Inuyasha but not Death Note, 25 watched both Death Note and Inuyasha, and 23 watched only Death Note. a. How many of the club members watched exactly one of the shows? b. How many of the club members watched all three shows? c. How many of the club members watched none of the three shows?

Answers

The solutions for the Questions are

a) Given that, the minimum requirement is 58 out of 75.

a=0.7733

b) For  16 out of a total of 75

b=0.2133

c)  For 11 out of a total of 75

c =0.1466

How many of the club members watched all three shows? c. How many of the club members watched none of the three shows?

Generally, we need to determine the total number of students who exhibit each behavior by seeing the habits and assets contained inside a Venn diagram.

Therefore, let's assume that:

- In Set A, I watched one of the Naruto episodes.

Set B: Observed a new segment of the anime series Death Note.

Hence, 23 of them have seen an episode of Death as well as an episode of Naruto, which means that

(A intercept B) equals 23.

In addition to this, it is a given that 42 has seen one episode of Death Note.

This indicates that B is equal to 42.

This pertains to us:

[tex]B = (B-A)+(A \cap B)[/tex]

In this case, members of B through A are individuals who have only viewed Death Note. So

42=(B−A)+23

(B-A) = 11

Finally, It is a known fact that 39 of the members have seen at least one episode of Naruto.

Therefore, the value of A is 39.

A=(A−B)+(A intercept B)

39=(A−B)+23

(A−B)= 16

(A union B)= 42+ 39- 23

(A union B)=58

In conclusion, the total number of pupils is:

58 with at least one and 17 with none, for a total of 75

a) Given that, the minimum requirement is 58 out of 75.

a=58*100/75

a=0.7733

b) For  16 out of a total of 75

b= 16/75*100

b=0.2133

c)  For 11 out of a total of 75

c= 11/75*100

c =0.1466

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Which statement is true?
A) All trapezoids are similar.
B) All rectangles are squares.
C) All squares are parallelograms.
D) All equilateral triangles are congruent.

Answers

I believe the answer should be D, since equilateral triangles means that all the sides are the same length, and congruent means two figures having the same length, and the same shape.
Hope this helps!

1-cos(12x)=____.
A. 2cos^2(12x)
B. 2cos^2(6x)
C. 2sin^2(12x)
D. 2sin ^2(6x)

Answers

By applying trigonometric expressions and algebra properties, the trigonometric equation 1 - cos 12x is equivalent to the trigonometric equation 2 · sin² 6x. (Correct choice: D)

How to simplify a trigonometric equation

Herein we have a trigonometric equation which has to be simplified. Simplification procedure consists in applying trigonometric expressions and algebra properties to transform the function from the form f(cos 12x) to the form f(cos 6x). Now we present the solution in detail:

1 - cos 12x      Given1 - cos² 6x + sin² 6x         cos 2x = cos² x - sin² x / (- 1) · a = - a1 - 1 + sin² 6x + sin² 6x       cos² x + sin² x = 1 / (- 1) · a = - a2 · sin² 6x     Definitions of subtraction and addition / Existence of additive inverse / Modulative property / Result

By applying trigonometric expressions and algebra properties, the trigonometric equation 1 - cos 12x is equivalent to the trigonometric equation 2 · sin² 6x. (Correct choice: D)

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Match the matrix operations with the resulting matrices. Image Attached.

Answers

Answer:

1. 2A + 3A

2. 2A - B

3. 2A

4. 2(A-B)

Step-by-step explanation:

When multiplying matrix by a number you just multiply each number in the matrix by whatever you are multiplying. When adding 2 matrices you just add the corresponding number in each matrix. Ex: You add the top left number to the top left number. The same goes with subtraction.

Answer:

Behold!

Step-by-step explanation:

Find the x - and y -intercepts of the graph of the function f(x)=−4|x−3|+12 .

Answers

The x and y-intercept(s) of the graph of the function f(x)=−4|x−3|+12 are: ( 0, 0 ), ( 6, 0 ) and ( 0, 0 ) respectively.

What are the x and y -intercepts of the graph of the function f(x)=−4|x−3|+12 ?

Given the function;

f(x) = −4| x-3 | + 12

First, we find the x-intercepts by simply substituting 0 for y and solve for x.

f(x) = −4| x-3 | + 12

y = −4| x-3 | + 12

0 = −4| x-3 | + 12

−4| x-3 | + 12 = 0

−4| x-3 | = -12

Divide both sides by -4

| x-3 | = 3

We remove the absolute value sign

x - 3 = ±3

x = 3±3

x = 3-3, 3+3

x = 0, 3

Hence, x-intercepts are: ( 0, 0 ), ( 6, 0 )

Next, we find the y-intercept by substituting 0 for x and solve for y.

f(x) = −4| x-3 | + 12

y = −4| 0-3 | + 12

y = −4| -3 | + 12

We remove the absolute value sign

y = −4(3) + 12

y = −12 + 12

y = 0

Hence, y-intercept is: ( 0, 0 ).

The x and y-intercept(s) of the graph of the function f(x)=−4|x−3|+12 are: ( 0, 0 ), ( 6, 0 ) and ( 0, 0 ) respectively.

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need heeeelp please ​

Answers

Answer:

4[tex]v^{7}[/tex]x³(7[tex]y^{6}[/tex] - 3v²[tex]x^{6}[/tex])

Step-by-step explanation:

28[tex]v^{7}[/tex]x³[tex]y^{6}[/tex] - 12[tex]v^{9}[/tex][tex]x^{9}[/tex] ← factor out 4[tex]v^{7}[/tex]x³ from each term

= 4[tex]v^{7}[/tex]x³(7[tex]y^{6}[/tex] - 3v²[tex]x^{6}[/tex])

|x-4| if x>4 please answer

Answers

Step-by-step explanation:

if , X>4

---> y= x-4

if , X<4

---> y= -(x-4)

y= 4- X

because , the value of |x-4| is Always positive ....

A customers monthly bill is $50 including taxes. You mom ’ll offer a 30% discount applicable towards the $50 on a monthly basis. The discount started being applied to his account on June 16. Therefore for the month of June the customer will receive a discount on a prorated basis on the monthly bill. The customers billing cycle begins on the first the month. What is the total billed amount for the month of June?

Answers

Using proportions, the billed amount for the month of June is:

D. $42.50

What is a proportion?

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

The discount will be applied only for the second half of the month, from June 16 to June 30, hence instead of a discount of 30%, it will count as a discount of 15%, meaning that 85% of the bill will be paid, hence the amount paid will be of:

A = 0.85 x $50 = $42.50.

Hence option D is correct.

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Find the surface area of the composite figur
2 cm
5 cm
4 cm
3 cm
5 cm
SA =
4 cm
3 cm
5 cm
[?] cm²

Answers

By definition of surface area and the area formulae for squares and rectangles, the surface area of the composite figure is equal to 166 square centimeters.

What is the surface area of a composite figure formed by two right prisms?

According to the image, we have a composite figure formed by two right prisms. The surface area of this figure is the sum of the areas of its faces, represented by squares and rectangles:

A = 2 · (4 cm) · (5 cm) + 2 · (2 cm) · (4 cm) + (2 cm) · (5 cm) + (3 cm) · (5 cm) + (5 cm)² + 4 · (3 cm) · (5 cm)

A = 166 cm²

By definition of surface area and the area formulae for squares and rectangles, the surface area of the composite figure is equal to 166 square centimeters.

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Desperately need help and an explanation so I can do it on my own later.

Answers

Step-by-step explanation:

since the sumation of f(x) of a probability is 1

thw probability to win is o.5 and to lose is o.5 so expected value is xf(x

your expected value will b 0.5 multiply by 5 thats is 2.5 thats your expected gain

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