Please help!!!
Which evidence cards go with (Lesson 4.1: Pasteurizing water in an emergency)
Claim 1: If you follow the instructions, the POW kits will always heat the water above the correct temperature for pasteurization (65°C), but some people didn’t follow the instructions.

Claim 2: Even if you follow the instructions, the POW kits will not heat the water above the correct temperature for pasteurization (65°C).

Answers

Answer 1

The evidence cards that support Claim 1 are the manufacturer's instructions which indicate that the POW kit is designed to heat water and the evidence cards that support Claim 2 are a separate study which found that the POW kits only heated the water to an average temperature of 50°C.

What is temperature?

Temperature is a measure of the degree of hotness or coldness of an object or substance. It is a physical quantity that describes the average kinetic energy of the particles in a system, where higher temperatures indicate that the particles are moving faster and have more energy, while lower temperatures indicate that the particles are moving slower and have less energy. Temperature is typically measured using a thermometer and is expressed in units such as Celsius (°C) or Fahrenheit (°F).

The evidence cards that support Claim 1 are:

"According to the manufacturer's instructions, the POW kit is designed to heat water to a temperature between 65°C and 70°C for at least six minutes, which is sufficient to pasteurize water." (Source: Manufacturer's instructions)

"In a study conducted by XYZ organization, it was found that when the instructions were followed correctly, the POW kits successfully pasteurized the water 100% of the time." (Source: XYZ organization study)

The evidence cards that support Claim 2 are:

"In a separate study, it was found that the POW kits only heated the water to an average temperature of 50°C, which is not hot enough to pasteurize water." (Source: ABC organization study)

"Several people reported that even after following the instructions, they were unable to get the POW kits to heat the water to the required temperature for pasteurization." (Source: Anecdotal evidence from user reviews)

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Related Questions

Pls I need help urgently. What can be predicted about meniscus formation if the adhesion and cohesion forces were equal in the graduated cylinder?

Answers

Answer: Flat. The meniscus will be flat/neutral with no curves if adhesion and cohesion are equal.

a. If 0.25 mol Na2CO3 completely reacts with excess HCl, how many moles of NaCl and CO2
will be produced, respectively?

b. If 6.02 x 1022 particles of NaBr completely react with excess Ca(OH)2, how many particles of NaOH will be produced?

c. If 204.45 g of NH3 is completed used up in the reaction, how many grams of (NH4)2SO4 will be produced?

d. If 1 mol C5H9O reacts with 2 mol O2, how many mol of CO2 will be produced?

Answers

If 0.25 mol Na₂CO₃ completely reacts with excess HCl, 0.5 moles of NaCl and 0.25 mole of CO₂ respectively.

If 6.02 x 10²² particles of NaBr completely react with excess Ca(OH)₂, 6.02 x 10²² particles of NaOH will be produced

If 204.45 g of NH₃ is completed used up in the reaction, 794.5g of (NH₄)₂SO₄ will be produced.

If 1 mol C₅H₉O reacts with 2 mol O₂, 5 moles of CO₂ will be produced.

What is mole concept?

Avogadro's number is the number of units in one mole of any substance and equals to 6.02214076 × 10²³. The units can be electrons, atoms, ions, or molecules.

No. of moles is defined as a particular no. of particles that we can calculate with the help of Avogadro’s number.

Given,

a. 0.25 mol Na₂CO₃

Na₂CO₃ + 2HCl → 2NaCl + H₂O + CO₂

1 mol Na₂CO₃ forms 2 moles of NaCl and 1 mole of CO₂.

0.25 mol Na₂CO₃ forms 0.5 moles of NaCl and 0.25 mole of CO₂.

b. 6.02 x 10²² particles of NaBr

2NaBr + Ca(OH)₂ → CaBr₂ + 2NaOH

2 moles of NaBr forms 2 moles of NaOH

Hence, 6.02 x 10²² particles of NaBr forms 6.02 x 10²² particles of NaOH.

c. Mass of NH3 = 204.45 g

2NH₃ + H₂SO₄ → (NH₄)₂SO₄

34g of NH₃ forms 132.14g of (NH₄)₂SO₄

204.45 g of NH₃ forms 794.5g of (NH₄)₂SO₄

d. 1 mol C₅H₉O

4C₅H₉O + 27O₂ → 20CO₂ + 18H₂O

4 mol C₅H₉O forms 20 moles CO₂

1 mole C₅H₉O forms 5 moles CO₂

Therefore, If 0.25 mol Na₂CO₃ completely reacts with excess HCl, 0.5 moles of NaCl and 0.25 mole of CO₂ respectively.

If 6.02 x 10²² particles of NaBr completely react with excess Ca(OH)₂, 6.02 x 10²² particles of NaOH will be produced

If 204.45 g of NH₃ is completed used up in the reaction, 794.5g of (NH₄)₂SO₄ will be produced.

If 1 mol C₅H₉O reacts with 2 mol O₂, 5 moles of CO₂ will be produced.

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4Al + 3O2 -> 2Al203

How many Liters of oxygen gas at STP are required to react with 2.00 moles of aluminum?

Answers

Explanation:

Refer to picture above.........

_____ is a form of witty, amusing speech that is often used to bring people together.

Answers

There are four types of speeches, they are to inform, to instruct, to entertain, and to persuade. Entertaining speeches aim to amuse a crowd of people.

What is an Entertaining speech?

The speeches which are designed to capture the audience attention and to amuse or regale them while delivering a message is defined as the Entertaining speech. Like informative or persuasive speeches, the Entertaining speech should able to communicate a clear message.

These speeches are delivered on some special occasions like wedding, award show, motivational speech, etc. This speech is not just to humor but also to drama. The aim of this speech is to stir an audience emotion.

Thus the Entertaining speech is often used to bring people together.

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find the number of moles in 30 grams of HF

Answers

Answer:

1.5 moles

Explanation:

Molar mass of HF- 20.01g/mol

Grams needed- 30g

You observe that when oil and water combine, oil always rests on top of the water. What can be said about the density of oil and water?

The density of oil must be greater than the density of water.
The density of oil must be less than the density of water.
The density of oil must be the same as the density of water.

Answers

Answer: As a result, when you add oil to a cup of water the two don't mix with each other. Because oil is less dense than water, it will always float on top of water, creating a surface layer of oil.

Which of the following substances is least soluble in 100. g of water at 50C?

NH4Cl
NaCl
HCl
KCl

Answers

NaCl is least soluble in 100. g of water at 50C.

Which is more water soluble, alcohol or acid?

It forms a hydroxyl group with water molecules, but non-polar other hydrocarbons with equivalent molecular weights do not.As a result, alcohol dissolves better in water.

What does acid dissolve more readily than water?

Because of the formation of a weak acid or aluminum salt as a result of the reaction between aluminum phosphate and acid, aluminum phosphate is more accessible in acid than water.Acids can so dissociate aluminum phosphate more effectively than water.

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Imagine you had the good fortune to find a meteorite in your backyard that appears to be a piece of material from the early history of the solar system. Quantitatively, how would you expect its ratio of potassium-40 and argon-40 to be different from that of other rocks in your yard? Explain why. The half-life for the decay of potassium-40 to argon-40 is 1. 25 billion years

Answers

The ratio of potassium-40 and argon-40 in the meteorite would be much higher than in other rocks in your yard.

It is because the meteorite is from the early history of the solar system, and thus has had much less time for the potassium-40 to decay into argon-40. This is due to the long half-life of potassium-40, which is 1.25 billion years. Therefore, the meteorite would still contain a large amount of potassium-40 relative to argon-40, whereas other rocks in your yard would have had much more time for the decay to occur, resulting in a lower ratio of potassium-40 to argon-40. This material was not subjected to the same processes that shape materials on Earth, such as weathering, erosion, and sedimentation.

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(ALOT OF QUESTIONS) if anybody sees this can they help me out?

Which of the following statements is true about strong, weak, and nonelectrolytes?

A) Strong electrolytes partially dissociate in water, weak electrolytes partially dissociate, and nonelectrolytes completely dissociate.
B) Strong electrolytes partially dissociate in water, weak electrolytes completely dissociate, and nonelectrolytes do not dissociate.
C) Strong electrolytes completely dissociate in water, weak electrolytes do not dissociate, and nonelectrolytes partially dissociate.
D) Strong electrolytes completely dissociate in water, weak electrolytes partially dissociate, and nonelectrolytes do not dissociate.

Which of the following substances is insoluble in water, according to these solubility rules?

A) Sodium chloride (NaCl)
B) Calcium hydroxide (Ca(OH)2)
C) Potassium nitrate (KNO3)
D) Silver chloride (AgCl)

Which of the following ions is soluble in water when paired with according to the solubility rules chart?

C) Chloride (Cl-)
B) Sulfate
D) Hydroxide (OH-)
A) Carbonate

Question 12 (1.25 points)
Which of the following combinations will result in a precipitate, according to solubility rules?

A) Sodium nitrate (Na2CrO4) and barium chloride (BaCl2)
B) Ammonium chloride (NH4Cl) and sodium hydroxide (NaOH)
C) Calcium sulfate (CaSO4) and sodium carbonate (Na2CO3)
D) Potassium iodide (KI) and silver nitrate (AgNO3)

Question 13 (1.25 points)
Which of the following statements is true about dilute and concentrated solutions?

A) Dilute solutions have a higher solvent-to-solute ratio than concentrated solutions.
B) Concentrated solutions contain more solute than dilute solutions.
C) Dilute solutions contain more solute than concentrated solutions.
D) Concentrated solutions have a higher solvent-to-solute ratio than dilute solutions.

Question 14 (1.25 points)
What volume of a 0.500 M sodium chloride solution is required to make 500. mL of a 0.100 M sodium chloride solution?

A) 100 L
B) 0.100 ml
C) 0.100 L
D) 1 L

Question 15 (1.25 points)
A student has a 0.500 M solution of hydrochloric acid (HCl) that is too concentrated for an experiment. The student needs to dilute the solution to 0.100 M. If the student needs 250 mL of the diluted solution, how much of the original solution should be used?

A) 250 ml
B) 50.0 ml
C) 125 ml
D) 500 ml

Answers

The statement that is true about strong electrolytes , weak electrolytes , and non-electrolytes is:

Strong electrolytes completely dissociate in water, weak electrolytes partially dissociate, and nonelectrolytes do not dissociate. Option D

Silver chloride (AgCl) is insoluble in water; option D.

Chloride (Cl-) ion is soluble in water; option C

Potassium iodide (KI) and silver nitrate (AgNO₃) will result in a precipitate, according to solubility rules; option D.

Dilute solutions have a higher solvent-to-solute ratio than concentrated solutions; option A.

What volume of a 0.500 M sodium chloride solution is required to make 500 mL of a 0.100 M sodium chloride solution?

The volume of sodium chloride solution required is calculated using the formula:

M1V1 = M2V2

Where:

M1 = 0.500 M (initial concentration)

V1 = volume of initial solution (unknown)

M2 = 0.100 M (final concentration)

V2 = 500 mL = 0.500 L (final volume)

Rearranging the formula to solve for V1, we get:

V1 = M2V2/M1

V1 = (0.100 M)(0.500 L)/(0.500 M)

V1 = 0.100 L

The volume of the 0.500 M sodium chloride solution required is 0.100 L.

15. The volume of the original solution required will be;

M1V1 = M2V2

Where:

M1 = 0.500 M (initial concentration)

V1 = volume of initial solution (unknown)

M2 = 0.100 M (final concentration)

V2 = 250 mL = 0.250 L (final volume)

Rearranging the formula to solve for V1, we get:

V1 = M2V2/M1

V1 = (0.100 M)(0.250 L)/(0.500 M)

V1 = 0.050 L or 50.0 mL

The volume of the original 0.500 M hydrochloric acid solution needed is 50.0 mL.

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Pls answer number 4, my grade depends on it

Answers

Answer: where are the photographs

Explanation:

The force of gravity is dependent on certain factors. According to the illustration, what factor(s) influence the gravitational attraction between two objects. A) mass and distance B) distance and pull C) composition and mass D) mass and density

Answers

According to the illustration, the factors that influence the gravitational attraction between two objects would be mass and distance. Option A.

Factors influencing gravitational attraction

The gravitational attraction between two objects is determined by two factors: their masses and the distance between them.

The greater the mass of each object, the greater the gravitational attraction between them. The farther apart the objects are, the weaker the gravitational force between them.

This is due to the inverse square law, which states that the force between two objects is proportional to the inverse square of the distance between them.

Therefore, the correct answer is mass and distance.

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Answer:it is A

Explanation:

Predict what will happen to reaction rates in the following scenarios and explain why!
1. You heat up a test tube containing reacting Magnesium metal and Hydrochloric acid. this reaction rate will...
2. You decrease the pressure in a syringe containing reacting Sodium chloride and Silver nitrate. This reaction rate will...

Answers

Answer:

1. Heating up a test tube containing reacting Magnesium metal and Hydrochloric acid will increase the reaction rate. This is because heating increases the kinetic energy of the reactant particles, making them move faster and collide more frequently and with greater energy. The increased frequency and energy of collisions will result in a higher rate of successful collisions, leading to a faster reaction.

2. Decreasing the pressure in a syringe containing reacting Sodium chloride and Silver nitrate will not have any significant effect on the reaction rate. This is because the reaction rate is determined by the concentration of the reactants, not the pressure. Lowering the pressure will cause the gases to expand, but it will not affect the concentration of the reactants or the frequency of their collisions. Therefore, the reaction rate will remain unchanged.

Explanation:

Which of the following substances is insoluble in water, according to these solubility
rules?

Calcium hydroxide (Ca(OH)2)
Sodium chloride (NaCl)
Silver chloride (AgCl)
Potassium nitrate (KNO3)

Answers

Answer:

silver chloride

Explanation:

NOTE:

All nitrates are soluble in water

All sulphates are soluble in water apart from Barium sulphate and Lead (II) sulphate

All chlorides are soluble in water apart from Silver chloride and Lead (II) chloride

All hydroxides are soluble in water

Answer:

silver chloride

Explanation:

Calculate the ΔGr0 of the following reaction and state whether it is spontaneous at standard temperature or not. (You will need Table B-12 in your CRG.)
2HCl(aq) + Ca(OH)₂(s) CaCl₂(s) +2H₂O(1)
O 6.5 kJ, yes
O 61.5 kJ, no
O 61.5 kJ, no
O 6.5 kJ, no
O-61.5 kJ, yes
-

Answers

Explanation:

The ΔG° of a reaction can be calculated using the formula:

ΔG° = ΔH° - TΔS°

where ΔH° is the standard enthalpy change, ΔS° is the standard entropy change, and T is the absolute temperature in Kelvin.

From Table B-12 in the CRG, we have:

ΔH° = -65.2 kJ/mol for the reaction

ΔS° = -111.7 J/(mol*K) for the reaction

We need to convert ΔS° to kJ/(molK):

ΔS° = -111.7 J/(molK) × (1 kJ/1000 J) = -0.1117 kJ/(mol*K)

Now we can calculate ΔG°:

ΔG° = ΔH° - TΔS°

ΔG° = -65.2 kJ/mol - (298 K) × (-0.1117 kJ/(mol*K))

ΔG° = -65.2 kJ/mol + 33.4 kJ/mol

ΔG° = -31.8 kJ/mol

The negative value of ΔG° indicates that the reaction is spontaneous at standard temperature. Therefore, the answer is: 6.5 kJ, yes. However, this is not one of the options provided.

17. How many joules of heat are absorbed to raise the
temperature of 435 grams of water at 1 atm from
25°C to its boiling point, 100.°C?
A) 4.5 X 10^4 J
C) 2.5 X 10^7 J
B) 1.4 X 10^5 J
D) 7.4 X 10^7 J

Answers

The amount of heat absorbed to raise the temperature of 435 grams of water at 1 atm from 25°C to its boiling point, 100°C, is approximately 1.4 × 10^5 joules

What is specific heat?

Specific heat is the amount of heat energy required to raise the temperature of a substance by one unit of temperature per unit of mass. It is a physical property that helps to characterize a substance and is typically measured in units of joules per gram per degree Celsius (J/g°C) or calories per gram per degree Celsius (cal/g°C).

The amount of heat absorbed to raise the temperature of a substance can be calculated using the formula:

Q = mcΔT

where Q is the amount of heat absorbed (in joules), m is the mass of the substance (in kilograms), c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius), and ΔT is the change in temperature (in degrees Celsius).

Substituting the given values, we get:

m = 435 grams = 0.435 kg

ΔT = 100°C - 25°C = 75°C

The specific heat capacity of water is 4.184 J/g°C. We can convert this to joules per kilogram per degree Celsius (J/kg°C) by dividing by 1000:

c = 4.184 J/g°C ÷ 1000 = 4.184 J/kg°C

Substituting these values, we get:

Q = (0.435 kg) × (4.184 J/kg°C) × (75°C)

Q = 140,089.2 J

Therefore, the amount of heat absorbed to raise the temperature of 435 grams of water at 1 atm from 25°C to its boiling point, 100°C, is approximately 1.4 × 10^5 joules. The answer closest to this value is option (B).

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A piece of metal was heated and then
put it into 100.0 mL of water, initially at
23.7 °C. The metal and water were
allowed to come to an equilibrium
temperature, determined to be 27.8 °C.
How much energy did the water absorb?
J
CH,O = 4.18 _

Answers

The heat absorbed is  1713.8 J

What is the heat capacity?

Heat capacity is the amount of heat energy required to increase the temperature of a substance by one degree Celsius (or Kelvin). We can use it as the means that we can use to identify a given substance.

Heat capacity is important in engineering thermodynamics, materials science, and process engineering.

We know that;

H = mcdT

H = 100 g * 4.18 * (27.8 - 23.7)

H = 1713.8 J

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I am unable to solve this problem.

Answers

The dry hydrogen gas would occupy 0.152 L at 1 atm and 298 K when solving with the combined gas equation.

What is combined gas equation?

It is a mathematical expression that states the relationship between the pressure, volume, and temperature.

The gas equation can be stated as:

                                           (P₁V₁)/T₁ = (P₂V₂)/T₂

To solve this problem, we need to use the combined gas law:

We are given the initial pressure (707.3 Torr), but we need to calculate the initial volume and temperature of the hydrogen gas.

P_total = P_H₂ + P_H₂O

where P_H₂ is the pressure of the hydrogen gas and P_H₂O is the vapor pressure of water at 10 °C (9.21 Torr).

P_total = 707.3 Torr

P_H₂O = 9.21 Torr

So, P_H₂ = P_total - P_H₂O = 698.09 Torr

Converting the volume of hydrogen gas collected to the volume at standard temperature and pressure (STP) using the following equation:

V₂ = V₁(P₁/P₂)(T₂/T₁)

Solving for V₁ by rearranging the equation:

V₁ = V₂(P₂/P₁)(T₁/T₂)

Converting the volume of hydrogen gas collected to liters:

V₂ = 125 mL = 0.125 L

Next, we can putting in the values we know:

P₁ = 698.09 Torr

P₂ = 1 atm = 760 Torr

T₂ = 298 K

We can solve for T₁ by using the ideal gas law:

PV = nRT

T = PV/nR

Calculating the number of moles of hydrogen:

n = m/M

n = 0.4 g / 65.38 g/mol = 0.006118 mol

Now we can put in the values we know into the ideal gas law:

T₁ = (P₁V₁)/(nR)

= (698.09 Torr)(0.125 L)/(0.006118 mol)(0.08206 L·atm/mol·K)

= 343.2 K

Finally, we can solve for V₁:

V₁ = V₂(P₂/P₁)(T₁/T₂)

= (0.125 L)(760 Torr/698.09 Torr)(343.2 K/298 K) = 0.152 L

Therefore, the dry hydrogen gas would occupy 0.152 L at 1 atm and 298 K.

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give an example of false solution​

Answers

An example of false solution is a natural gas.

What is Natural Gas?

Natural gas is primarily methane with smaller quantities of other hydrocarbons.

It was formed millions of years ago when dead marine organisms sunk to the bottom of the ocean and were buried under deposits of sedimentary rock.

False solutions are those that do not actually address the problem at hand substantially but deceive people into believing that they do, while at the same time triggering other serious problems.

Examples of false solutions include:

clean development mechanisms; carbon markets; carbon capture and storage; burning trees and biomass as Bioenergy

Therefore, an example of false solution is a natural gas.

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How many coordinate covalent bonds, if any, does the ion AT3 have? A has 5
valence electrons, and T has 6 valence electrons. Both A and T cannot exceed the
octet. Explain your answer. Be sure to consider the Lewis structure with the proper
formal charges to determine your answer.

Answers

The ion AT3 has a total of 22 valence electrons: 5 from A and 6 from T, multiplied by 3 since there are three T atoms.

What is ion AT3?

Generally,  To determine the number of coordinate covalent bonds, we need to draw the Lewis structure and check the formal charges.

If A donates three electrons to each T atom, it will have a formal charge of +2 (5 valence electrons - 3 donated electrons - 0 non-bonding electrons). Each T atom will have a formal charge of -1 (6 valence electrons - 3 donated electrons - 2 non-bonding electrons).

The Lewis structure for AT3 will have single bonds between A and each T atom, and each T atom will have a lone pair of electrons.

The total number of electrons used in the bonds is 6 (2 from each bond). The remaining 16 electrons will be distributed among the three T atoms as lone pairs.

Therefore, there are no coordinate covalent bonds in the ion AT3.

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Consider all of the different types of c-h bonds in cyclopentene and rank them in order of increasing bond strength? 10. 25 (

Answers

In cyclopentene, there are three types of C-H bonds:

Allylic C-H bond (bond adjacent to the double bond)

Bridgehead C-H bond (bond at the bridgehead carbon)

Methylenic C-H bond (bond in the ring)

The order of increasing bond strength is generally:

Allylic C-H bond

Methylenic C-H bond

Bridgehead C-H bond

Cyclopentene is a cyclic hydrocarbon with the molecular formula C5H8. It is an unsaturated compound with a double bond between two carbon atoms in the ring, making it an alkene. Cyclopentene is a clear, colorless liquid that is insoluble in water but soluble in many organic solvents. It is commonly used as a starting material in the synthesis of various organic compounds, including pharmaceuticals and agrochemicals.Cyclopentene undergoes various chemical reactions due to its unsaturated nature, such as addition reactions with electrophiles and hydrogenation reactions. It can also undergo polymerization to form poly(cyclopentene) with a high glass transition temperature and good mechanical properties.

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These symbols represent sodium hydroxide and hydrogen gas. Sodium hydroxide is
a strong base. (Chemicals that contain the hydroxide ion (OH) are bases.)

How do the products of the reaction relate to the phenol red test and the splint test?

Answers

The appearance of pink color in the phenol red test and the presence of flame and "pop" sound in the splint test indicate the production of NaOH and H2 gas, respectively, in the reaction between zinc, HCl, and NaOH.

How does sodium hydroxide and hydrogen gas appear from the phenol red test and the splint test?

Sodium hydroxide (NaOH) and hydrogen gas (H2) can be produced by the reaction between zinc and hydrochloric acid (HCl) in the presence of sodium hydroxide. This reaction can be tested using the phenol red test and the splint test.

In the phenol red test, phenol red indicator is added to the reaction mixture. Phenol red is a pH indicator that changes color depending on the acidity or basicity of the solution. When NaOH is added to the reaction mixture, it neutralizes the acid (HCl) and increases the pH of the solution. This causes phenol red to change from yellow (acidic) to pink (basic). The appearance of pink color indicates the presence of NaOH.

In the splint test, a lighted splint is brought near the reaction mixture. When H2 gas is produced in the reaction, it can be tested using the splint test. H2 is a highly flammable gas that reacts with oxygen (O2) to produce water (H2O) vapor. When a lighted splint is brought near the reaction mixture, it can ignite the H2 gas, producing a "pop" sound and a small flame. This appearance of flame and "pop" sound confirms the presence of H2 gas.

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What is the source of nearly all of the energy for producers and consumers? Responses A. sunlight B. oxygen C.plants D. water

Answers

Answer:

A. sunlight

Explanation:

The source of nearly all of the energy for producers and consumers is sunlight

what types of friction​

Answers

Answer:

Friction is the force that opposes the motion of a solid object over another. There are mainly four types of friction: static friction, sliding friction, rolling friction, and fluid friction.

can you guys help me do this science question

Answers

Jacinda Ardern got involved with Tonga after the eruption due to the following reasons:

To acquire more information about the volcano's current activity.To get rid of the ash plume that threatens to cover New Zealand.To provide assistance to the people of Tonga by giving them provisions.

The correct answer is: 2, 3, and 4.

What made Jacinda Ardern get involved with Tonga?

Jacinda Ardern, the Prime Minister of New Zealand, got involved with Tonga after the underwater volcanic eruption that occurred in January 2022.

There were several reasons why she got involved:

To assess the potential impact of the eruption on New Zealand and the wider region, including the risk of a tsunami or ash plume that could affect air travel and the environment.To provide assistance to the people of Tonga, including the supply of emergency provisions such as water, food, and medical supplies.To gather information about the volcano's activity and the risks it poses to the region, including the risk of further eruptions or seismic activity.To coordinate with other countries and international organizations in the response to the disaster and to provide support to Tonga in its recovery efforts.

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Complete question:

Which of these are the reasons why Jacinda Ardern got involved with Tonga after the eruption?

1. the desire to preserve ocean resources in the area through satellite monitoring

2. the desire to get rid of the ash plume that threatens to cover New Zealand

3. the desire to acquire more information about the volcano's current activity

4. the desire to provide assistance to the people of Tonga by giving them provisions

3 and 4

2, 3 and 4

1 only

O 1 and 2

What is the limiting reactant when 8 molecules of hydrogen gas is added to 3 molecules of nitrogen gas?

N2 + 3H2 —> 2NH3

Answers

The stoichiometric concept is used here to determine the limiting reactant of the reaction. The relationship between the quantities of reactants and products of a chemical reaction is called stoichiometry. Here the limiting reactant is H₂ .

What is limiting reactant?

The substance which is totally consumed when the chemical reaction is complete is defined as the limiting reagent. The amount of the product formed is limited by this reagent.

The balanced equation is:

N₂ + 3H₂ → 2NH₃

8 mol H₂ × 2 NH₃ / 3 H₂  = 5.33 mol NH₃

3 mol N₂ × 2 NH₃ / 1 = 6 mol NH₃

Thus H₂ is the limiting reagent.

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Introduction:

Define the following terms:

Chemical reaction,
reactant,
product,
precipitate,
Law of Conservation of Mass

Answers

Answer:

chemical reaction: substances are converted to one or more different substances

reactant: A chemical substance that is present at the start of a chemical reaction and changes.

product: a substance that is present at the end of a chemical reaction.

Precipitate: an insoluble solid that emerges from a liquid solution

Law of conservation of mass: a discovery that mass is neither created nor destroyed in chemical reactions.

Explanation:

TASK 1 Metals A, B and B are given. Metal A is a stronger reducing agent than B. Metal B can displace metal 5 from solutions of its salts, but does not react with solutions of salts of A. Arrange metals A, B and In reducing their reduction capacity. We select om POAM two triplets meta- Au, koumo meet these conditions.​

Answers

Here, the metal A displaces metal B from its solution. Hence, the metal A has lower positive  reduction than B. Hence, the reduction potential of B is higher and it is less strong reducing agent.

What is reduction potential ?

The reduction potential of a metal electrode is the measure of the tendency of it to lose or gain electrons and is the equilibrium potential difference developed due to separation of charges at the metal - solution interface when a metal is kept in contact with solution of its own.

The higher the negative reduction potential, greater the reducing capacity of the metal. Hence, metals with higher positive potential are easily reducing or they are strong oxidizing agents.

The metals with strong reducing power displaces other metals with lower reducing power from their solution. Here, A is strong reducing agent. Hence, it can displace B from its salt solution and B reduces to its metallic form.

Therefore, the order of A and B in reducing their reduction capacity is A>B.

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HELP!!! CHEMISTRY QUESTION NEED ANSWERED QUICKLY!!!

(Picture attached)

The forward reaction for Reaction B is...
- endothermic
- exothermic

If Reaction B was at equilibrium and then was heated ______ CH3OH would be present after the reaction adjusts to the new temperature.
- more
- less
- the same amount of

If Reaction B was at equilibrium and then H2 was added, _____ CH3OH would be present after the reaction adjusts.
- more
- less
- the same amount of

If Reaction B was at equilibrium and then H2 was added, _____ CO would be present after the reaction adjusts.
- more
- less
- the same amount of

Answers

Answer:

#1 exothermic

The gaseous decomposition of N2O5 was studied at 35 ∘C.

2N2O5(g)→4NO2(g)+O2(g)

A plot of ln[N2O5] versus time has a slope of −9. 8×10−4s−1.

PART A

If 0. 100 mol of N2O5 is added to a 1. 0 L flask at 35 ∘C, calculate the concentration of N2O5 after 12. 0 minutes.

PART B

f 0. 100 mol of N2O5 is added to a 1. 0 L flask at 35 ∘C, calculate the concentration of NO2 after 12. 0 minutes.

PART C

If 0. 100 mol of N2O5 is added to a 1. 0 L flask at 35 ∘C, calculate the concentration of O2after 12. 0 minutes

Answers

The concentration of the compounds if the gaseous decomposition of [tex]N_2O_5[/tex] was studied at 35°C is,

a) [tex]N_2O_5[/tex] after 12 minutes is 0.0104 mol/L.

b) [tex]NO_2[/tex] after 12.0 minutes is 0.0208 mol/L.

c) [tex]O_2[/tex] after 12.0 minutes is 0.0052 mol/L.

To solve this problem, we need to use the integrated rate law for a first-order reaction, which is:

ln[[tex]N_2O_5[/tex]] = -kt + ln[[tex]N_2O_5[/tex]]₀

PART A:

We are asked to find the concentration of [tex]N_2O_5[/tex] after 12.0 minutes, given that the initial concentration is 0.100 mol/L.

First, we need to find the value of the rate constant, k, using the given slope:

slope = -k = -9.8 x [tex]10^{-4} s^{-1}[/tex]

k = 9.8 x [tex]10^{-4} s^{-1}[/tex]

The integrated rate law may then be used to solve for ln[[tex]N_2O_5[/tex]] by including the values of k, t, and [[tex]N_2O_5[/tex]]:

ln[[tex]N_2O_5[/tex]] = -kt + ln[[tex]N_2O_5[/tex]]₀

ln[[tex]N_2O_5[/tex]] = -(9.8 x [tex]10^{-4} s^{-1}[/tex]) x (12.0 min x 1/60 s/min) + ln[0.100 mol/L]

ln[[tex]N_2O_5[/tex]] = -0.0066 + ln[0.100]

ln[[tex]N_2O_5[/tex]] = -4.714

Finally, we can exponentiate both sides of the equation to solve for [[tex]N_2O_5[/tex]]:

[[tex]N_2O_5[/tex]] = [tex]e^{(-4.714)}[/tex]

[[tex]N_2O_5[/tex]] = 0.0104 mol/L

Therefore, the concentration of [tex]N_2O_5[/tex] after 12.0 minutes is 0.0104 mol/L.

PART B:

We are asked to find the concentration of [tex]NO_2[/tex] after 12.0 minutes, given that the initial concentration of [tex]N_2O_5[/tex] is 0.100 mol/L.

We might derive from the synthetic condition that the molar proportion of [tex]NO_2[/tex] to [tex]N_2O_5[/tex] is either 4:1 or 2:1. In this way, 4 moles of [tex]NO_2[/tex] are made for every 2 moles of [tex]N_2O_5[/tex] that separate.

Since we know the concentration of [tex]N_2O_5[/tex] at 12.0 minutes from part (A), we can use the molar ratio to find the concentration of [tex]NO_2[/tex]:

[[tex]N_2O_5[/tex]] = 0.0104 mol/L

The molar ratio of [tex]NO_2[/tex] to [tex]N_2O_5[/tex] = 2:1

[[tex]NO_2[/tex]] = (2/1) x [[tex]N_2O_5[/tex]]

[[tex]NO_2[/tex]] = 2 x 0.0104 mol/L

[[tex]NO_2[/tex]] = 0.0208 mol/L

Therefore, the concentration of [tex]NO_2[/tex] after 12.0 minutes is 0.0208 mol/L.

PART C:

We are asked to find the concentration of [tex]O_2[/tex] after 12.0 minutes, given that the initial concentration of [tex]N_2O_5[/tex] 0.100 mol/L.

We may deduce from the chemical equation that [tex]O_2[/tex] and [tex]N_2O_5[/tex] have a molar ratio of 1:2. Therefore, 1 mole of [tex]O_2[/tex] is created for every 2 moles of [tex]N_2O_5[/tex] that breakdown.

Since we know the concentration of [tex]N_2O_5[/tex] at 12.0 minutes from part (A), we can use the molar ratio to find the concentration of [tex]O_2[/tex]:

[[tex]N_2O_5[/tex]] = 0.0104 mol/L

Molar ratio of [tex]O_2[/tex] to [tex]N_2O_5[/tex] = 1:2

[[tex]O_2[/tex]] = (1/2) x [[tex]N_2O_5[/tex]]

[[tex]O_2[/tex]] = 0.5 x 0.0104 mol/L

[[tex]O_2[/tex]] = 0.0052 mol/L

Therefore, the concentration of [tex]O_2[/tex] molecule after 12.0 minutes is 0.0052 mol/L.

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Ag+ is the Lewis ______
following reaction.
Ag+ (aq) + 2NH3(aq) = Ag (NH3)2 (aq)
=
A
base
B
acid

Answers

Ag^+ is an example of  a Lewis acid.

What is a Lewis acid?

According to the Lewis theory, a Lewis acid is any species that has an electron-deficient center or "hole" that can attract and accept a pair of electrons from a Lewis base. This electron-pair donation can result in the formation of a coordinate covalent bond between the Lewis acid and the Lewis base.

The concept of Lewis acids and bases is important in many areas of chemistry, including coordination chemistry, organometallic chemistry, and catalysis. It provides a useful framework for understanding chemical reactions and interactions between molecules in a wide range of chemical systems.

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