Please please please help

I'm not sure if you mean ( [tex] \sqrt{x + 7} [/tex] ) or ( [tex] \sqrt{x} + 7[/tex] ) I solved it both ways .

[tex]f(x) = \sqrt{x + 7} \\ \\ f( \: g(x) \: ) = \sqrt{(8x - 11)+ 7} \\ = \sqrt{8x - 11 + 7} \\ = \sqrt{8x - 4} \\ = 2 \sqrt{2x - 1} [/tex]

____o_____o______

[tex]f(x) = \sqrt{x} + 7 \\ \\ f( \: g(x) \: ) = \sqrt{(8x - 11)} + 7 \\ = \sqrt{8x - 11} + 7\\ [/tex]

I hope I helped you^_^

Answer:

2.333333

Step-by-step explanation:

Answer:

[tex]slope = \frac{y2 - y1}{x2 - x1} \\ = \frac{4 - - 3}{ - 3 - - 8} \\ = \frac{4 + 3}{ - 3 + 8} \\ = \frac{7}{5} = 1.4 \\ thank \: you[/tex]

Step-by-step explanation:

5x+3y = 6

5x = 6 - 3y

5x = 3(2-y)

5x/3 = 2 - y

y = 2 - (5x/3)

slope = x coefficient.

= - 5/3

Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

new slope = 3/5

the equation formula

y = mx + b

m = new slope = 3/5

y = (3x/5) + b

From the point given (3 , -1 )

x = 3.

y = -1

-1 = (9/5) + b

b =( -5/5) - (9/5)

b = - 14 / 5

[tex]y = \frac{3}{5} x - \frac{14}{5} [/tex]

[tex] \large \mathfrak{Solution : }[/tex]

let's solve :

[tex] \huge \boxed{\mathfrak{Question} \downarrow}[/tex]

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

[tex] \sf2 [ 30 - ( 1 + 4 ) ^ { 2 } ][/tex]

[tex] \sf2\left(30-5^{2}\right) [/tex]

[tex] \sf2\left(30-25\right) [/tex]

[tex] \sf2\times 5 [/tex]

[tex] \boxed{ \boxed{ \boxed{ \mathfrak{ = 10}}}}[/tex]

Answer:

I think its P= 34/41. sorry

Answer:

34/41 yuuhhhh

Step-by-step explanation:

Answer:

.

Step-by-step explanation:

.............................

Answer:

v = [tex]\frac{fu}{u-f}[/tex]

Step-by-step explanation:

Given

[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{v}[/tex] + [tex]\frac{1}{u}[/tex]

Multiply through by fuv to clear the fractions

uv = fu + fv ( subtract fv from both sides )

uv - fv = fu ← factor out v from each term on the left side

v(u - f) = fu ← divide both sides by (u - f)

v = [tex]\frac{fu}{u-f}[/tex]

Answer:

(c) Write a directed number to show this single journey.

Step-by-step explanation:

Answer:

it would be false

Step-by-step explanation:

Answer:

mike spent 6 dollars, each pen cost 2$

Answer:

Number 8 the answer is 120

Number 10 answer is 115

Step-by-step explanation:

8. 180-60=120

it's because the straight line is 180 then you just need to solve it use this

10. 180-65=115

the reason same like number 8

Hope this answer can help you to solve the math problems

6

Step-by-step explanation: that’s math

Answer:

f(x) = 6

simple as me haha

Step-by-step explanation:

please give brainliest i need it

Step-by-step explanation:

Ahh!! that question is complicated....

I didn't realize that candy had genders.

Answer:

Not it is not a whole number, since when divided, it is a decimel

Answer:

[tex] \frac{46}{23} [/tex]

Step-by-step explanation:

[tex] \frac{2 + 4(7 + {2}^{2} )}{4 \times 2 + 5 \times 3} [/tex]

[tex] \frac{2 + 4(7 + 4)}{4 \times 2 + 5 \times 3} = \frac{2 + 4(7 + 4)}{8 + 5 \times 3} [/tex]

[tex] \frac{2 + 4(7 + 4)}{8 + 15} = \frac{2 + 4 \times 11}{8 + 15} [/tex]

[tex] \frac{2 + 4 \times 11}{23} = \frac{2 + 44}{23} [/tex]

[tex] = \frac{46}{23} [/tex]

Answer:

2+4(7+2)^2/4×2+5×3= 46/23

the answer is in the photo

Step-by-step explanation:

5/11 as a decimal is 0.45454545454545

Answer:

5/11 as a decimal is 0.45454545454545

Step-by-step explanation:

Answer:

-1,0 and -11,0 because you already factored and solved.

Answer:

the orange line is the reflection y=-1

To plot the reflection of a function across the line y = -1, you'll need to follow these steps:Understand Reflection Across a Line: Reflection across a line involves flipping the points of the original function over the given line.

For reflection across the line y = -1, you'll be swapping the positions of the points above the line with those below it.

Choose a Function: Let's say you want to plot the reflection of a function f(x) across y = -1. Choose a function that you want to reflect. For demonstration purposes, let's consider a simple quadratic function, [tex]f(x) = x^2.[/tex]

Calculate the Reflected Points: To calculate the reflected points, follow these steps for each point (x, y) on the original function:

a. Find the vertical distance between the point and the reflection line (y = -1). This distance is the difference between the original y-coordinate and -1: distance = y - (-1) = y + 1.

b. The reflected y-coordinate (y') will be -1 minus the distance calculated in the previous step: y' = -1 - distance = -1 - (y + 1) = -2 - y.

c. The x-coordinate remains the same: x' = x.

d. The reflected point is (x', y').

Plot the Reflected Points: Plot the original function f(x) and then plot the reflected points (x', y') that you calculated in the previous step. This will show you the reflection of the function across y = -1.

To know more about reflection:

https://brainly.com/question/15487308

#SPJ3

Answer: Ello mate, this image I provided below should help you out, let me know if you need anything else.

Step-by-step explanation:

Answer:

15 p - 3 is the answer....

Answer:

[tex]\displaystyle \text{(1)}\\x=1+\sum_{k=1}^{n-1}2k\\\\\text{(2)}\\\displaystyle \frac{\displaystyle \sum_{k=1}^{n}2k\left(1+\displaystyle \sum_{k=1}^{n}2k \right)}{2}-\frac{\displaystyle \sum_{k=1}^{n-1}2k\left(1+\displaystyle \sum_{k=1}^{n-1}2k \right)}{2}[/tex]

Step-by-step explanation:

Notice that Group 1 starts with 1 and we keep counting up by 1.

Part 1:

The total number of numbers from Group 1 to Group [tex]n[/tex] can be found by:

[tex]\displaystyle \sum_{k=1}^{n}2k[/tex]

To find the first number in a certain group [tex]g[/tex], we'll find the total number of numbers from Group 1 to Group [tex]g-1[/tex], then add 1.

Here's why.

Let's say we want to find the first number of Group 3, which we can clearly see is 7. Take advantage of the fact that the sequence of numbers counts up by 1, starting from 1. We will use the formula above to to find the total number of numbers from Group 1 to Group 2, which is 6, then add 1 to achieve the number of 7.

Therefore, the first number in group [tex]n[/tex] must be:

[tex]\boxed{\displaystyle 1+\sum_{k=1}^{n-1}2k}[/tex]

Part 2:

Recall that the sum of the numbers from [tex]1[/tex] to positive integer [tex]n[/tex] inclusive is given by [tex]\displaystyle\frac{n(n+1)}{2}[/tex].

Therefore, if we find the total number of numbers from Group 1 to Group [tex]n[/tex], we can simply substitute that value into the formula above to find the total sum of the numbers from Group 1 to Group [tex]n[/tex].

To find the total sum of the numbers exclusively in Group [tex]n[/tex] simply subtract the sum of numbers from Group 1 to Group [tex]n-1[/tex].

Short example on how that works:

The sum of all numbers in Group 3 is equal to the sum of the numbers from Group 1 to Group 3 minus the sum of the numbers from Group 1 to Group 2.

We've already found the formula for the total number of numbers from Group 1 to Group [tex]n[/tex] in the previous part, so convert this concept into summation notation like such:

[tex]\boxed{\displaystyle \frac{\displaystyle \sum_{k=1}^{n}2k\left(1+\displaystyle \sum_{k=1}^{n}2k \right)}{2}-\frac{\displaystyle \sum_{k=1}^{n-1}2k\left(1+\displaystyle \sum_{k=1}^{n-1}2k \right)}{2}}[/tex]