Please show your work so we can see how you got your answers
1. You have a "small clean room" that is 144" x 144" square with a ceiling height of 120" and 6 HEPA filters in the ceiling that deliver 600 cfm each and 1 access door that is currently closed.
For the above room, answer the following questions;
• What is the area of the room in Sq. Ft?
• What is the volume of the room in Cu. Ft? • What is the Air Change (AC's) Rate if the equation for Air Change Rate is N=60Q/vol
N = # AC’s per hour
Q = Total CFM
Vol = Space volume in cubic ft.
• If the door to this room were now opened, would the room differential pressure with respect to the adjacent hallway, be;
o Positive
o Negative
• Neutral

Thus, the value of x and y for the given right angled triangle are found as:   x = 8 and y = 2√3.

The Pythagorean Theorem, a well-known geometric principle that states that the square just on hypotenuse (the side across from the right angle) of a right triangle equals the sum of the squares on its legs, is also known as the

a² + b² = c².

For the larger triangle, applying Pythagorean theorem:

4² + (4√3)² = x²

x² = 16 + 16*3

x² = 16 + 48

x² = 64

x = 8

Then, x - 6 = 8 - 6 = 2

Now applying Pythagorean theorem for smaller triangle:

y² + (x - 6)² = 4²

y² =  4² - 2²

y² =  16 - 4

y² =  12

y² =  √12

y = 2√3

Thus, the value of x and y for the given right angled triangle are found as:   x = 8 and y = 2√3.

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Answer: To test for unequal variances, we use Welch's t-test, which is a modification of the Student's t-test that adjusts for unequal variances. The null hypothesis for Welch's t-test is that the population means are equal, and the alternative hypothesis is that they are not.

The critical values for a two-tailed test at alpha level 0.10 with degrees of freedom df = 23.99 can be found using a t-distribution table or a calculator and are ±1.717.

For the first sample, we have:

Sample 1: s1 = 10.2, n1 = 22

Sample 2: s2 = 6.4, n2 = 16

Test: Two-tailed

The degrees of freedom can be calculated as follows:

df = ((s1^2 / n1) + (s2^2 / n2))^2 / ((s1^2 / n1)^2 / (n1 - 1) + (s2^2 / n2)^2 / (n2 - 1))

= ((10.2^2 / 22) + (6.4^2 / 16))^2 / ((10.2^2 / 22)^2 / 21 + (6.4^2 / 16)^2 / 15)

= 23.81

The calculated t-value is:

t = (x1 - x2) / sqrt(s1^2 / n1 + s2^2 / n2)

= (0 - 0) / sqrt(10.2^2 / 22 + 6.4^2 / 16) = 0

Since the calculated t-value is within the critical region (-1.717, 1.717), we fail to reject the null hypothesis. We can conclude that there is insufficient evidence to suggest that the population means are different.

For the second sample, we have:

Sample 1: s1 = 0.89, n1 = 25

Sample 2: s2 = 0.67, n2 = 18

Test: Right-tailed

The degrees of freedom can be calculated as follows:

df = ((s1^2 / n1) + (s2^2 / n2))^2 / ((s1^2 / n1)^2 / (n1 - 1) + (s2^2 / n2)^2 / (n2 - 1))

= ((0.89^2 / 25) + (0.67^2 / 18))^2 / ((0.89^2 / 25)^2 / 24 + (0.67^2 / 18)^2 / 17)

= 34.13

The critical value for a right-tailed test at alpha level 0.10 with degrees of freedom df = 34.13 can be found using a t-distribution table or a calculator and is 1.311.

The calculated t-value is:

t = (x1 - x2) / sqrt(s1^2 / n1 + s2^2 / n2)

= (0.89 - 0.67) / sqrt(0.89^2 / 25 + 0.67^2 / 18)

= 2.42

Since the calculated t-value (2.42) is greater than the critical value (1.311), we reject the null hypothesis. We can conclude that there is sufficient evidence to suggest that the population mean of Sample 1 is greater than the population mean of Sample 2.

For the third sample, we have:

Sample 1: s1 = 124, n1 = 12

Sample 2: s2 = 260, n2 = 10

Test: Left-tailed

The degrees of freedom can be calculated as follows:

df = ((s1^2 / n1) + (s2^2 / n2))^2 / ((s1^2 / n1)^2 / (n1 - 1) + (s2^2 / n2)^2 / (n2 - 1))

= ((124^2 / 12) + (260^2 / 10))^2 / ((124^2 / 12)^2 / 11 + (260^2 / 10)^2 / 9)

= 14.23

The critical value for a left-tailed test at alpha level 0.10 with degrees of freedom df = 14.23 can be found using a t-distribution table or a calculator and is -1.345.

The calculated t-value is:

t = (x1 - x2) / sqrt(s1^2 / n1 + s2^2 / n2)

= (0 - 0) / sqrt(124^2 / 12 + 260^2 / 10) = 0

Since the calculated t-value is not less than the critical value (-1.345), we fail to reject the null hypothesis. We can conclude that there is insufficient evidence to suggest that the population mean of Sample 1 is less than the population mean of Sample 2.

The decision rule for all three tests is:

If the calculated t-value is within the critical region, fail to reject the null hypothesis.

If the calculated t-value is greater than the critical value for a right-tailed test, reject the null hypothesis in favor of the alternative hypothesis that the population mean of Sample 1 is greater than the population mean of Sample 2.

If the calculated t-value is less than the critical value for a left-tailed test, reject the null hypothesis in favor of the alternative hypothesis that the population mean of Sample 1 is less than the population mean of Sample 2.

Step-by-step explanation:

Answer:

The surface area is 731 ft^2

a. The test statistic (1.174) falls within the acceptance region (± 1.96), we fail to reject the null hypothesis.

b. There is sufficient evidence to suggest a significant difference between the two population proportions at α = 0.10

The null hypothesis is a statement or assumption that there is no significant difference or relationship between two variables or groups.

a.  We can use a two-tailed z-test to test this hypothesis, which can be computed as follows:

[tex]\frac{(p_1' - p_2' )- (p_1 - p_2)}{\sqrt{[p'(1-p')/n_1] + [p'(1-p')/n_2}]}[/tex]

[tex]p'_1 = \frac{x_1}{n_1}[/tex]    = 175/368 = 0.4755

[tex]p'_2 = \frac{x_2}{n_2}[/tex]     = 182/405 = 0.4481

[tex]p' = \frac{x_1+x_2}{n_1+n_2}[/tex]  = (175+182) / (368+405) = 0.4622

n₁ = 368, n₂ = 405 and α = 0.05

the test statistic;

[tex]= \frac{(0.4755 - 0.4481) - 0}{\sqrt{[0.4622(1-0.4622)/368] + [0.4622(1-0.4622)/405]} }[/tex]

= 1.174

Since the test statistic (1.174) falls within the acceptance region (± 1.96), we fail to reject the null hypothesis  and conclude that there is insufficient evidence to suggest a significant difference between the two population proportions at α = 0.05 level of significance.

b. Given the sample data,

[tex]p'_1 =[/tex] 0.38

[tex]p'_2 =[/tex] 0.25

[tex]p' =[/tex] (0.38+0.25)/(649+558) = 0.3166

n₁ = 649, n₂ = 558 and α = 0.10

test statistic;

[tex]=\frac{(0.38 - 0.25) - 0 }{\sqrt{[0.3166(1-0.3166)/649] + [0.3166(1-0.3166)/558)]} }[/tex]

= 7.448

Since the test statistic (7.448) falls within the rejection region (z > 1.28) for a one-tailed test at α = 0.10 level of significance, we reject the null hypothesis  and conclude that there is sufficient evidence to suggest a significant difference between the two population proportions at α = 0.10 level of significance, in favor of the alternative hypothesis

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Option D, 1, represents the remainder obtained from the synthetic division of (x²-4x+7) by (x-2).

Synthetic division is a shortcut method used to divide a polynomial by a binomial of the form (x-a), where a is a constant, without using long division.

According to the given information:

Synthetic division is a method used to divide a polynomial by a binomial of the form (x-a), where a is a constant. To find the correct synthetic division of (x²-4x+7) by (x-2), we write down the coefficients of the polynomial in descending order, as 1, -4, and 7. Then, we write the value of the constant a, which is 2, on the left side. We multiply a by the first coefficient, 1, and write the result underneath the next coefficient, -4. We add these two values to get -2, and write it underneath the next coefficient, 7. This gives us a quotient of 1 - 2x + 3/(x-2), and a remainder of 3. Therefore, the correct answer is option (D) 1, which represents the remainder of the synthetic division

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Therefore, it will take 173 months to pay off the loan, or approximately 14 years and 5 months.

A percentage is a way of expressing a number as a fraction of 100. The symbol for a percentage is "%". For example, 50% is the same as 50/100 or 0.5 as a decimal. Percentages are often used to express a portion or share of a whole. For instance, if you scored 90% on a test, it means you got 90 out of 100 possible points. In finance, percentages are commonly used to express interest rates, returns on investments, or changes in stock prices.

First, we need to convert the monthly interest rate from a percentage to a decimal by dividing by 100.

0.25% / 100 = 0.0025

Now we can plug in the values into the formula:

N= (-log⁡ (1-0.0025*70000/250))/ (log⁡ (1+0.0025))

Simplifying the equation in the parentheses:

N= (-log⁡ (1-175))/ (log⁡ (1.0025))

N= (-log⁡ (0.9964))/ (0.002499)

N= 172.9

Rounding up to the nearest whole number since we can't make partial payments:

N= 173

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The number of years it would take is approximately equal to 53 years.

In Mathematics, a population that increases at a specific period of time represent an exponential growth. This ultimately implies that, a mathematical model for any population that increases by r percent per unit of time is an exponential function of this form:

P(t) = I(1 + r)^t

Where:

By substituting given parameters, we have the following:

96627 = 11211(1 + 0.0418)^t

8.61894567835 = (1.0418)^t

By taking the ln of both sides, we have:

Time, t = ln(8.61894567835)/ln(1.0418)

Time, t = 52.60 ≈ 53 years.

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Rewriting the equations in matrix form, we get:

[1 78/1399 | 1]

[50 1 | 1149/1399]

What is square matrix?

A square matrix is a matrix that has the same number of rows and columns. That is, a matrix A is square if A has dimensions n x n, where n is a positive integer.

To create an augmented matrix, we need to represent the system of equations in matrix form. Let x be the number of months it will take Chris to pay off the total purchase price of the mattress using monthly payments and savings. Then the system of equations is:

1399/18 + 78x = 1399

50x + 250 = 1399

The first equation represents the fact that the total price of the mattress must be paid off in 18 months using monthly payments, and the second equation represents the fact that Chris sets aside $50 each month in savings to put towards the purchase.

Rewriting the equations in matrix form, we get:

[1 78/1399 | 1]

[50 1 | 1149/1399]

This is the augmented matrix for the system of equations, where the leftmost columns represent the coefficients of the variables (1 for x in the first equation, 50 for x in the second equation, and 78/1399 for the monthly payment in the first equation), and the rightmost column represents the constants on the right-hand side of each equation.

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      Column 1  Column 2  Column 3

Row 1--   50          -1               -250

Row 2--   78           1             1,399

I got it right on my test.

Your Welcome:)

Answer:

x=26

Step-by-step explanation:

5x=3x+52

5x-3x=52

2x=52

2x/2=52/2

x=52/2

x=26

Answer: 0.0972

Step-by-step explanation:

To find the probability that the first roll is a total of at least 7 and the second roll is a total of at least 10, we need to find the probabilities of each event separately and then multiply them together.

First, let's find the probability of the first roll being a total of at least 7. There are a total of 36 possible outcomes when rolling a pair of dice (6 sides on each die, so 6 x 6 = 36). To get a total of at least 7, the following outcomes are possible:

7: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2)

9: (3, 6), (4, 5), (5, 4), (6, 3)

10: (4, 6), (5, 5), (6, 4)

11: (5, 6), (6, 5)

12: (6, 6)

There are 21 successful outcomes out of the total 36 possibilities. So, the probability of getting a total of at least 7 in the first roll is:

P(at least 7) = 21/36

Next, let's find the probability of the second roll being a total of at least 10. The following outcomes are possible:

10: (4, 6), (5, 5), (6, 4)

11: (5, 6), (6, 5)

12: (6, 6)

There are 6 successful outcomes out of the total 36 possibilities. So, the probability of getting a total of at least 10 in the second roll is:

P(at least 10) = 6/36

Now, to find the probability that both events happen, we multiply the probabilities of each event:

P(first roll at least 7 and second roll at least 10) = P(at least 7) * P(at least 10) = (21/36) * (6/36)

P(first roll at least 7 and second roll at least 10) = 126/1296

So, the probability that the first roll is a total of at least 7 and the second roll is a total of at least 10 is 126/1296, or approximately 0.0972 (rounded to four decimal places).

I'm afraid you forgot to add a picture?

It would take approximately 26.68 years to double the cost of the car with continuous compounding at an annual inflation rate of 2.6%.

The inflation rate is the rate at which the general level of prices for goods and services is increasing over time. In other words, it measures the percentage increase in the cost of living from one period to another.

In the context of the given problem, the annual inflation rate is 2.6%. This means that, on average, the cost of goods and services is increasing by 2.6% per year. If the cost of a car is $21,000 this year, next year it will be 21,000*(1+0.026) = $21,546. The following year it will be 21,546*(1+0.026) = $22,105.96, and so on.

We can use the formula for continuous compound interest to solve this problem:

[tex]A=Pe^{rt}[/tex]

where A is the final amount, P is the initial amount, e is the mathematical constant e (approximately equal to 2.71828), r is the annual interest rate, and t is the time in years.

In this case, we want to find the time t it takes for the cost of the car to double, so we can set A = 2P and solve for t:

[tex]2P=Pe^{rt}[/tex]

Dividing both sides by P, we get:

[tex]2=e^{rt}[/tex]

Taking the natural logarithm of both sides, we get:

ln(2) = rt

Solving for t, we get:

[tex]t = \frac{ln(2)}{r}[/tex]

Substituting the given values, we get:

[tex]t = \frac{ln(2)}{0.026}[/tex]

t ≈ 26.68 years

Therefore, it would take approximately 26.68 years to double the cost of the car with continuous compounding at an annual inflation rate of 2.6%.

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Answer:  the stream frontage has a fractal dimension between 1.67 and 2

Step-by-step explanation: The equation utilized to compute the fractal dimension of stream frontage is expressed as follows: D = (log N) / (log 1/s), where N represents the total count of constituent units and 1/s denotes the scaling factor.

At the scale of 10 meters, it has been determined that N equals one and the reciprocal of s equals one. At the scale of 1 meter, the sample size (N) is equal to 25, while the sampling interval (1/s) is equivalent to 0.1, which is obtained by dividing it by 10. At a distance of 10 centimeters, the number of observed particles is equivalent to 250 and the reciprocal of the standardized sensitivity value is 0.01. By employing the applicable formula, the fractal dimension can be computed as follows:

The equation can be expressed as D, which is equal to the logarithm of N divided by the logarithm of the reciprocal of s, represented as log 1/s.

At the 10-meter scale, it can be observed that D possesses a value of 0. This signifies that, within the scope of measurement, D does not exhibit any discernible magnitude.

At a scale of 1 meter, the value of D is approximately equal to 1.67.

The value of D on a 10 centimeter scale is equivalent to 2.

The required equation of the rational function is f(x) = -8(x-1)(x-4) (ax + 3/2)/(3(a+3/2)(x-5)(x-2))

To create a rational function with the given characteristics, we can start by setting up the general form for a rational function:

f(x) = (ax + b) / (cx + d)

To ensure that the function has vertical asymptotes at x=5 and x=2, we need the denominators of our function to be (x-5) and (x-2), respectively. So we can rewrite our function as:

f(x) = (ax + b) / ((x-5)(x-2))

To make sure that the function passes through the x-intercepts at x=1 and x=4, we need the numerator of the function to be equal to zero at those values of x. So we add two factors of (x-1) and (x-4) to the numerator:

f(x) = k(x-1)(x-4) (ax + b) / ((x-5)(x-2))

where k is a constant that we will determine shortly.

To find the value of k, we use the fact that the function has a y-intercept at (0,3). This means that when x=0, f(x) = 3. So we substitute these values into our equation and solve for k:

3 = k(0-1)(0-4) (a(0) + b) / ((0-5)(0-2))

3 = 20k b / 10

b = 3/2

Now our equation becomes:

f(x) = k(x-1)(x-4) (ax + 3/2) / ((x-5)(x-2))

To find the value of k, we can use one of the x-intercepts. Let's use x=1:

0 = k(1-1)(1-4) (a(1) + 3/2) / ((1-5)(1-2))

0 = -3k/4 (a + 3/2)

Solving for k:

k = -8/(3(a+3/2))

Now our equation becomes:

f(x) = -8(x-1)(x-4) (ax + 3/2) / (3(a+3/2)(x-5)(x-2))

Therefore, an equation for the rational function with vertical asymptotes at x=5 and x=2, x-intercepts at x=1 and x=4, and y-intercept at 3 is:

f(x) = -8(x-1)(x-4) (ax + 3/2)/(3(a+3/2)(x-5)(x-2))

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George's kitten is approximately 15.23 yards away from its bed

What is distance?

Distance is a measure of the length or spatial separation between two points. It is a scalar quantity, which means it has magnitude but not direction. In physics, distance is often measured in units such as meters (m), feet (ft), kilometers (km), or miles (mi).

We can use the Law of Cosines to solve this problem. Let's call the distance from the kitten's final position to the bed "d". Then, we have:

d² = 23² + 14² - 2(23)(14)cos(140°)

d² = 529 + 196 + 644cos(140°)

d² = 529 + 196 - 644(0.766)

d² = 529 + 196 - 493.304

d² = 231.696

d = sqrt(231.696)

d ≈ 15.23

Therefore, George's kitten is approximately 15.23 yards away from its bed

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Answer:

the 36th term is 187.

Step-by-step explanation:

To find the 36th term of a sequence, we need to know the rule that generates the sequence. Without that rule, we cannot find the 36th term.

However, if we assume that the sequence is an arithmetic sequence (meaning that there is a common difference between consecutive terms), we can use the given terms to find the common difference and then find the 36th term.

The common difference is found by subtracting the second term from the first term, or the third term from the second term.

Using the first and second terms, we get:

17 - 12 = 5

Using the second and third terms, we get:

22 - 17 = 5

Since both calculations give the same result, we can be confident that the common difference is 5.

Therefore, to find the 36th term, we can use the formula for the nth term of an arithmetic sequence:

an = a1 + (n - 1)d

where an is the nth term, a1 is the first term, n is the term number, and d is the common difference.

Using a1 = 12, d = 5, and n = 36, we get:

a36 = 12 + (36 - 1)5

a36 = 12 + 175

a36 = 187

So, if the sequence is an arithmetic sequence with a common difference of 5, then the 36th term is 187.

Answer:

The answer is 2√10

Step-by-step explanation:

Hyp²=opp²+adj²

let hyp be x

x²=6²+2²

x²=36+4

x²=40

square root both sides

√x²=√40

x=2√10

the dimensions of the table runner are  [tex]20[/tex] inches in length and [tex]4[/tex] inches in width.

Let's denote the width of the table runner as "w" inches. Since the length is 5 times greater than the width, the length would be 5w inches.

The area of a rectangle is calculated by multiplying its length by its width. Given that the area of the table runner is 80 square inches, we can set up the following equation:

Length × Width = Area

[tex](5w) \imes w = 80[/tex]

Simplifying further:

[tex]5w^2 = 80[/tex]

Dividing both sides by 5:

[tex]w^2 = 16[/tex]

Taking the square root of both sides:

w = ±4

Since the width cannot be negative in this context, we discard the negative value. Therefore, the width (w) of the table runner is [tex]4[/tex] inches.

Substituting this value back into the equation for length:

Length   [tex]= 5w = 5 \times 4 = 20[/tex] inches

So, the dimensions of the table runner are  [tex]20[/tex] inches in length and 4 inches in width.

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One quadratic function that goes through the points (5, 3) and (8, 0) is:

and another quadratic function that goes through the points (5, 3) and (8, 0) is: .

A quadratic function is a polynomial function of degree two. In other words, it is a function in which the highest power of the independent variable (usually denoted as x) is two.

According to given information:

To write two different quadratic functions that go through the points (5, 3) and (8, 0), we can use the general form of a quadratic function:

To write two different quadratic functions that go through the points (5, 3) and (8, 0), we can use the general form of a quadratic function:

[tex]y = ax^2 + bx + c[/tex]

where a, b, and c are constants.

First, we can use the two points to form a system of two equations:

[tex]3 = a(5)^2 + b(5) + c0 = a(8)^2 + b(8) + c[/tex]

Simplifying each equation, we get:

25a+5b+c=3

64+8b+c=0

We can solve this system of equations using substitution or elimination to find the values of a, b, and c. However, since we only need two different quadratic functions, we can simply choose two different values of a and solve for b and c.

For example, if we choose a = 1, then we have:

25a+5b+c=3

64+8b+c=0

Simplifying each equation, we get:

5b+c=-22

8b+c= -64

Solving for b and c, we get:

b=-7

c=8

Therefore, one quadratic function that goes through the points (5, 3) and (8, 0) is:

[tex]y=x^2-7x+8[/tex]

To find another quadratic function, we can choose a different value of a, such as a = -2. Then we have:

-50-10b+c=3

-128-16b+c=0

Simplifying each equation, we get:

10b-c = 53

16b -c = -128

Solving for b and c, we get:

b =9/2

c= -31/4

Therefore, another quadratic function that goes through the points (5, 3) and (8, 0) is:

[tex]y= -2x^2+9x-31/4[/tex]

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Answer:

To solve for the value of z in the equation 6 = 1/2 × z, we can use algebraic manipulation. First, we can multiply both sides of the equation by 2 to eliminate the fraction:

2 × 6 = 2 × (1/2 × z)

Simplifying the right side:

12 = z

Therefore, the value of z is 12.

Step-by-step explanation:

Answer: C - 3a - 27

Step-by-step explanation:

We start with 2.5 + 3a - 20 - 9.5, and first solve for variables:

3a

Then we solve for constants:

2.5 - 20 - 9.5 = 2.5 - 29.5 = -27

Add the two together:

3a - 27

Answer:

y = 2x + 4

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 2x + 3 ← is in slope- intercept form

with slope m = 2

• Parallel lines have equal slopes , then

slope of line AB is m = 2

line AB crosses the y- axis at (0, 4 ) ⇒ c = 4

y = 2x + 4 ← equation of line AB

Answer:

a) The distance from Springton to Watworth is 200 km. Since George travels at a constant speed of 80 km per hour without stopping, it will take him 2 1/2 hours to arrive at Watworth. Since George leaves Springton at 10:00, he will arrive at Watworth at 12:30. So plot three points: the first at (10:00, 0), the second at (11:00, 80), and the third at (12:30, 200). Draw a line connecting the three points.

b) Karen arrived at Watworth at 13:50. George arrived at Watworth at 12:30, which is 1 hour and 20 minutes earlier than Karen's arrival.

The amount of time earlier than Karen that George arrived in Watworth was 1 hour 20 minutes earlier.

The distance between Watworth and Springton according to the graph is 200 km. This means that George covered this distance in:

= 200 / 80

= 2.5 hours

He arrived at :

= 10 + 2.5 hours

= 12 : 30 am

The difference was :

= 13: 50 arrival of Karen - 12 : 30

= 1 hour 20 minutes

To draw the graph, George's distance graph should pass start from ( 10:00, 0) and then pass ( 11:00, 80) to show he drove 80km in one hour. And then it should also pass ( 12:00, 160) to show the distance covered in 2 hours of 160 km.

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Therefore, the Left Riemann Sum for this function, interval, and number of subintervals is 50.

The top-left corner of these rectangles touched the y=f(x) curve. In other words, the value of f at the subinterval's left endpoint determined the height of the rectangle over that subinterval. This technique is called the left-endpoint estimate because of this.

With left endpoints and n = 5 subintervals, we may use the Left Riemann Sum formula to approximate the area under the curve of f(x) = x2 + 4 over the range [0, 5]:

Left Riemann Sum = ∑[i=1 to n] f(x_i-1) Δx

In this case, a = 0, b = 5, n = 5, and we will use the left endpoints, so:

Δx = (5 - 0)/5 = 1

Using the left endpoints, the subintervals and their left endpoints are:

[0,1],[1,2],[2,3],[3,4],[4,5]

[tex]so,\; x_0 = 0, x_1 = 1, x_2 = 2, x_3 = 3, x_4 = 4.[/tex]

Now we can calculate the Left Riemann Sum:

Left Riemann Sum= [tex]f(x_0)\Delta x + f(x_1)\Deltax + f(x_2)\Deltax + f(x_3)\Deltax + f(x_4)\Deltax[/tex]

= f(0)×1+f(1)×1+f(2)×1+f(3)×1 + f(4)×1

= 4+5+8+13+20

= 50

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Answer:

a) To solve the differential equation y''-2y'-3y= e^4x, we first find the characteristic equation:

r^2 - 2r - 3 = 0

Factoring, we get:

(r - 3)(r + 1) = 0

So the roots are r = 3 and r = -1.

The general solution to the homogeneous equation y'' - 2y' - 3y = 0 is:

y_h = c1e^3x + c2e^(-x)

To find the particular solution, we use the method of undetermined coefficients. Since e^4x is a solution to the homogeneous equation, we try a particular solution of the form:

y_p = Ae^4x

Taking the first and second derivatives of y_p, we get:

y_p' = 4Ae^4x

y_p'' = 16Ae^4x

Substituting these into the original differential equation, we get:

16Ae^4x - 8Ae^4x - 3Ae^4x = e^4x

Simplifying, we get:

5Ae^4x = e^4x

So:

A = 1/5

Therefore, the particular solution is:

y_p = (1/5)*e^4x

The general solution to the non-homogeneous equation is:

y = y_h + y_p

y = c1e^3x + c2e^(-x) + (1/5)*e^4x

b) To solve the differential equation y'' + y' - 2y = 3xe^x, we first find the characteristic equation:

r^2 + r - 2 = 0

Factoring, we get:

(r + 2)(r - 1) = 0

So the roots are r = -2 and r = 1.

The general solution to the homogeneous equation y'' + y' - 2y = 0 is:

y_h = c1e^(-2x) + c2e^x

To find the particular solution, we use the method of undetermined coefficients. Since 3xe^x is a solution to the homogeneous equation, we try a particular solution of the form:

y_p = (Ax + B)e^x

Taking the first and second derivatives of y_p, we get:

y_p' = Ae^x + (Ax + B)e^x

y_p'' = 2Ae^x + (Ax + B)e^x

Substituting these into the original differential equation, we get:

2Ae^x + (Ax + B)e^x + Ae^x + (Ax + B)e^x - 2(Ax + B)e^x = 3xe^x

Simplifying, we get:

3Ae^x = 3xe^x

So:

A = 1

Therefore, the particular solution is:

y_p = (x + B)e^x

Taking the derivative of y_p, we get:

y_p' = (x + 2 + B)e^x

Substituting back into the original differential equation, we get:

(x + 2 + B)e^x + (x + B)e^x - 2(x + B)e^x = 3xe^x

Simplifying, we get:

-xe^x - Be^x = 0

So:

B = -x

Therefore, the particular solution is:

y_p = xe^x

The general solution to the non-homogeneous equation is:

y = y_h + y_p

y = c1e^(-2x) + c2e^x + xe^x

c) To solve the differential equation y" - 9y' + 20y = x^2*e^4x, we first find the characteristic equation:

r^2 - 9r + 20 = 0

Factoring, we get:

(r - 5)(r - 4) = 0

So the roots are r = 5 and r = 4.

The general solution to the homogeneous equation y" - 9y' + 20y = 0 is:

y_h = c1e^4x + c2e^5x

To find the particular solution, we use the method of undetermined coefficients. Since x^2*e^4x is a solution to the homogeneous equation, we try a particular solution of the form:

y_p = (Ax^2 + Bx + C)e^4x

Taking the first and second derivatives of y_p, we get:

y_p' = (2Ax + B)e^4x + 4Axe^4x

y_p'' = 2Ae^4x +

Higher rates of depression and anxiety are one negative mental health outcome associated with social media use

The paragraph discusses the role of social media in modern life and its impact on mental health. It notes that social media has become a ubiquitous part of life that allows people to connect with others from around the world, including friends, family, and strangers.

However, the paragraph goes on to mention that social media use has been linked to negative mental health outcomes such as depression, anxiety, and stress.

These negative outcomes may be due to the pressure individuals feel to present a perfect image of themselves online, leading to feelings of inadequacy and self-doubt.

Despite these negative outcomes, the paragraph notes that social media can also be valuable for promoting social support and connection, especially among marginalized communities.

Furthermore, it can be a source of education and awareness, allowing people to learn about important social and political issues and engage with them.

Hence,

Higher rates of depression and anxiety are one negative mental health outcome associated with social media use

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The logarithm of the expression [tex]5^{(-3log_{5} 2 )} * 2^{(log_{2}3)}[/tex] is log(3/8).

Mathematical functions called logarithms let us change the scale at which numbers are expressed. They specifically aid in the transformation of numbers stated in exponential form into numbers expressed in standard form. The exponent to which the base must be raised in order to obtain a given number is given by the logarithm of the number to the specified base. For instance, since 23 = 8, the logarithm base 2 of 8 is 3. Natural logarithms, which are logarithms to the base e (about 2.718), and common logarithms, which are logarithms to the base 10, are the two types of logarithms that are most frequently used.

The given logarithmic expression is:

[tex]5^{(-3log_{5} 2 )} * 2^{(log_{2}3)}[/tex]

Using the properties of logarithm we have:

[tex]5^{(-3log_{5} 2 )} 2^{(log_{2}3)}\\= (5^{(log_{5}2)})^{(-3)} * 3\\= 2^{(-3)} * 3\\= 3/8[/tex]

Hence, the logarithm of the expression [tex]5^{(-3log_{5} 2 )} * 2^{(log_{2}3)}[/tex] is log(3/8).

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Answer:

c = - 100

Step-by-step explanation:

z² - 20c + c

to complete the square

add/subtract ( half the coefficient of the z- term )² to z² - 20c

= z² + 2(- 10)z + 100 - 100

= (z - 10)² - 100 ← with c = - 100

Answer:

Step-by-step explanation:

we can't say because we don't have a couple of coordinates