Please type in the bonus code you received after getting 100% on Unit 2 practice test. Please helppp!!!

Answer:

1.A 2.D

Explanation:

Answer:

a = 3H²o

b = 20.3 grams

ç = (NO³)³

Answer:

a. => LR is HNO₃

b. => 13.88 grams Fe(NO₃)₃

c. => 29.1%

Explanation:

a. Limiting Reactant:

Note => Determining LR is quite simple if you'll convert all data to moles and divide each mole value by the respective coefficient. The smaller value is the limiting reactant.

Given:   Fe      +                   6HNO₃ ⇒ Fe(NO₃)₃ + 3NO₂ + 3H₂O

          20.3g                          21.4g

         = 20.3g/56g/mole     =21.4g/63g/mole

         = 0.363 mole              = 0.340 mole

Divide by coefficient 1         Divide by coefficient 6

= 0.363/1 = 0.363                  = 0.340/6 = 0.057

Since 0.057 is the smaller value then HNO₃ is the limiting reactant. However, one must use the calculated mole values when applying to equation stoichometry.

b. Grams of Fe(NO₃)₃ Produced:

Problems like this can be greatly simplified if data is 1st converted to moles and solved with respect to equation reaction ratios. Then convert mole value to needed dimension.

Fe     +   6HNO₃ ⇒ Fe(NO₃)₃ + 3NO₂ + 3H₂O

Rxn Ratio between LR and Fe(NO₃)₃ => 1:6

0.340 mole HNO₃  =>  1/6(0.340mole Fe(NO₃)₃ Produced = 0.057mole Fe(NO₃)₃ x 242 g/mole = 13.8 grams of Fe(NO₃)₃ produced

c. Percent Yield:

Given:  Fe     +   6HNO₃ ⇒ Fe(NO₃)₃ + 3NO₂ + 3H₂O

Measured Lab Yield = 4.02 grams (given in problem)

Theoretical Yield = 13.8 grams (calculated in part b)

%Yield = (Lab Yield/Theoretical Yield)100%

= (4.02/13.8)100% = 29.1% (w:w)*

*w:w means calculation was based on weight values and not volume values.

Answer:

Explanation:

_____ grams of cobalt(II) oxide

Answer:

1450 k

Explanation:

We are given:

V1 = 250 mL                        V2 = 500 mL

T1 = 725k                             T2 = T

V1 / T1 = V2 / T2

Now, replacing the values:

250 / 725 = 500 / T

T = 500 * 725 / 250

T = 2 * 725

T = 1450 k

Answer:

36.08%

Explanation:

We are given the overall formula of the compound as: CuSO4•5H2O

Now, atomic mass of the elements are;

Cu = 63.55 g/mol

S = 32.07 g/mol

O = 16 g/mol

H20 = 18.02 g/mol

Now, let's calculate the total mass of the compound:

(63.55 g/mol) + (32.07 g/mol) + 4(16 g/mol) + 5(18.02 g /mol) = 249.72 g/mol

From the above, water in the compound is 5(H20)

Thus, total water atomic mass = 5 × 18.02 = 90.1 g/mol

Thus, percentage of water = (atomic mass of water/total mass of compound) × 100%

Percentage of water = (90.1/249.72) × 100% = 36.08%

Answer:

Explanation:

Helium’s

Answer:

the atomic mass of magnesium from the Periodic Table is the average sum of it's three most abundant isotopes.

Explanation:

We are told that the atomic mass of magnesium from the Periodic Table is

24.31 amu.

Now, this atomic mass is simply the weighted average of the individual isotopes.

This is because the common isotopes of magnesium are 24Mg, 25Mg, and

26Mg and they are respectively 79%, 10%, and 11% in abundance. The weighted average of these 3 listed isotopes of magnesium add up to 24.3 amu.

Thus, the atomic mass of magnesium from the Periodic Table is the average sum of it's three most abundant isotopes.

Taking into account the definition of isotopes and atomic mass of an element, the atomic mass of magnesium from the Periodic Table is  24.31 amu and represent the weighted average of the individual isotopes.

In first place you must know that isotopes are atoms whose atomic nuclei have the same number of protons but different numbers of neutrons.

So, the relative atomic mass is an average of the atomic masses of the different isotopes in a sample, considering the contribution of each isotope.

This is, the atomic mass of an element is the weighted average mass of its natural isotopes. Therefore, the atomic mass of an element is not a whole number.

In summary, the atomic mass of magnesium from the Periodic Table is  24.31 amu. This mass represent the weighted average of the individual isotopes.

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Answer:

b. lithium

Explanation:

Li the least likely, to lose an electron.

Answer:

[tex]n_{ FeC_2O_4\ 2H_2O}=0.020molFeC_2O_4\ 2H_2O[/tex]

Explanation:

Hello.

In this case, since the chemical reaction for the first step is:

[tex]Fe(NH_4)_2(SO_4)_2\ 6H_2O + H_2C_2O_4 \rightarrow FeC_2O_4\ 2H_2O + H_2SO_4 + (NH_4)_2SO_4 + 4H_2O[/tex]

Whereas we can see a 1:1 molar ratio between FeC2O4·2H2O(s) and H2C2O4, thus, we compute the moles of yielded FeC2O4·2H2O(s) in the first step as shown below:

[tex]n_{ FeC_2O_4\ 2H_2O}=0.01814L*1.1\frac{molH_2C_2O_4 }{L} *\frac{1molFeC_2O_4\ 2H_2O}{1molH_2C_2O_4} \\\\n_{ FeC_2O_4\ 2H_2O}=0.020molFeC_2O_4\ 2H_2O[/tex]

Best regards.

Answer: The element having number of protons 120 will belong to Group 2, Period 8 and has an atomic number of 120.

Explanation:

We are given:

Number of protons = 120

Atomic number is equal to the number of protons present in neutral atom.

Atomic number of element = 120

Electronic configuration of element: [tex]1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^24f^{14}5d^{10}6p^67s^25f^{14}6d^{10}7p^68s^2[/tex]

Electronic configuration of element in terms of noble gas: [tex][Og]8s^2[/tex]

As, the last electron is entering in s-orbital. So, it is an s-block element and there are 2 electrons in the outermost shell. So, it will belong to Group-2.

And, the value of Principal Quantum number (n) for this element is '8'. Therefor, it will belong to Period 8.

Hence, the element having number of protons 120 will belong to Group 2, Period 8 and has an atomic number of 120.

Answer:

there aint no evidence or answer for dis my man

Explanation:

Answer:

A hydrated compound loses water of crystallisation when it is heated. ... We can use difference in the mass between the hydrated and anhydrous compound to calculate the mass of water of crystallisation removed by heating. Heat to constant mass to ensure all of the water of crystallisation is removed.

Explanation:

Answer:

magnetite

Explanation:

proportion of iron in haematite = 3.5/5 x 100% = 70%

proportion of iron in magnetite = 7.2/10 x 100% = 72%

Answer:

The most stable resonance structure shown in fig (II).

Explanation:

Given that,

If oxygen is the central atom in the CON– ion

We know that,

Resonance :

The movement of electron is called resonance.

If the electronegativity is more of element then the element is more stable.

We need to find the most stable resonance structure

According to figure,

Electronegativity of N is more than C

So, N is the more stable in fig (II).

Hence, The most stable resonance structure shown in fig (II).

The most stable resonance structure is the resonance structure in which nitrogen has a formal charge of -2.

There are molecules and ions in which a single structure does not sufficiently explain the observed properties of the molecule or ion. In such cases, bonding can not be explained in terms of one single structure, the actual structure of the compound lies somewhere between many contributing structures.

For the ion CON–, the most stable resonance structure is the resonance structure in which the nitrogen atom which is more electronegative has a formal charge of -2 and less electronegative carbon has a formal charge of -1 as shown.

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Answer:

2Ag⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + H₂O (l)

Explanation:

Step 1: RxN

2AgNO₃ + 2NaOH → Ag₂O + 2NaNO₃ + H₂O

Step 2: Define states of matter

2AgNO₃ (aq) + 2NaOH (aq) → Ag₂O (s) + 2NaNO₃ (aq) + H₂O (l)

Step 3: Total Ionic Equation

2Ag⁺ (aq) + 2NO₃⁻ (aq) + 2Na⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + 2Na⁺ (aq) + 2NO₃⁻ (aq) + H₂O (l)

Step 4: Cancel out spectator ions

2Ag⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + H₂O (l)

Adam's design for an alarm clock being dependent on batteries is more favorable due to the reliable and consistent power supply, convenience, portability, and the ability to replace or recharge the batteries. Option 3.

Among the given options, Adam's design for the alarm clock being dependent on batteries is more favorable compared to being dependent on sunlight or wind gusts. There are several reasons for this preference.Firstly, batteries provide a reliable and consistent source of power for the alarm clock.

Unlike sunlight, which is only available during the day and can vary depending on weather conditions and location, and wind gusts, which are unpredictable and intermittent, batteries can provide a constant power supply, ensuring that the alarm clock functions consistently and accurately.

Secondly, batteries offer convenience and portability. With a battery-dependent alarm clock, users are not limited by the need for direct exposure to sunlight or reliance on specific weather conditions. They can place the alarm clock anywhere in their room, without worrying about access to natural light or wind.

This portability allows for greater flexibility and convenience in using the alarm clock.

Additionally, batteries can be easily replaced or recharged, ensuring the long-term functionality of the alarm clock. If the batteries run out of power, users can simply replace them or recharge them, allowing the alarm clock to continue functioning without significant interruption.

In contrast, relying on sunlight or wind gusts may result in the clock not being operational when these natural energy sources are unavailable. Option 3 is correct.

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Answer:

3Fe + 2O2 → Fe3O4

Explanation:

Answer:

7.335 moles of  Cl₂ are required to react with 4.89 miles of Al.

Explanation:

Given data:

Moles of Al = 4.89 mol

Number of moles of Cl₂ required = ?

Solution:

Chemical equation:

2Al + 3Cl₂    →   2AlCl₃

Now we will compare the moles of Al and chlorine from balance chemical equation.

                            Al           :         Cl₂

                             2           :           3

                            4.89      :         3/2×4.89 =7.335 mol

Thus, 7.335 moles of  Cl₂ are required to react with 4.89 miles of Al.        

B) Oil spills in the environment might be cleaned up quicker.

Answer:

B is the right Choice

Explanation:

Answer:

The the empirical formula for magnesium chloride based on this experiment will be [tex]MgCl_{2}[/tex]

Explanation:

Given that,

Mass of Mg = 0.50 g

Mass of magnesium chloride found = 1.99 g

Let the formula of magnesium chloride be [tex]Mg_{x}Cl_{y}[/tex]

We know that,

Molar mass of Mg= 24 g/mol

Molar mass of magnesium chloride = (24x+35.5y) g/mol

We need to calculate the moles of Mg

Using formula of moles

[tex]Number\ of\ moles=\dfrac{mass}{molar\ mass\ of\ Mg}[/tex]

Put the value into the formula

[tex]Number\ of\ moles=\dfrac{0.50}{24}[/tex]

[tex]Number\ of\ moles=0.020\ mole[/tex]

We need to calculate the mole of magnesium chloride

Using formula of moles

[tex]Number\ of\ moles=\dfrac{mass}{molar\ mass\ of\ magnesium\ chloride}[/tex]

Put the value into the formula

[tex]Number\ of\ moles=\dfrac{1.99}{24x+35.5y}\ mole[/tex]

The reaction will be,

[tex]Mg+HCl\Rightarrow Mg_{x}Cl_{y}+H_{2}[/tex]

We need to calculate the value of x and y

Using number of moles of Mg in reactant and product

Moles of Mg atom in reactant=Moles of Mg atom in product

[tex]\dfrac{0.50}{24}=x\times\dfrac{1.99}{24x+35.5y}[/tex]

[tex]0.020(24x+35.5y)=x\times1.99[/tex]

[tex]0.48x+0.71y=1.99x[/tex]

[tex]0.71y=(1.99-0.48)x[/tex]

[tex]\dfrac{x}{y}=\dfrac{0.71}{1.99-0.48}[/tex]

[tex]\dfrac{x}{y}=0.47\approx0.5[/tex]

[tex]\dfrac{x}{y}=\dfrac{1}{2}[/tex]

Hence, The the empirical formula for magnesium chloride based on this experiment will be [tex]MgCl_{2}[/tex]

Answer:

23 g/cc

Explanation:

Density = mass ÷ volume

Density = 46.0 g ÷ 2cc

= 23 g/cc

Hope that helps.

Answer:

Element A = Oxygen

Element H =

Element B = Aluminum

Element J = Magnesium

Element C = Selenium

Element L = Carbon

Element D = Sodium

Element Q = Francium

Element F = Antimony

Element R = Calcium

Element G = Chlorine

Element S = Tellurium

Explanation:

Element A  is Oxygen because: oxygen 6 valence electrons ; is a gas at room temperature ; and is transported in blood to cells.

Element H  is Neon because: Neon is a noble gas ;   qppears as red light when charged with  electricity (Neon light signs)  and it has the second highest Ionization energy of the elements

Element B  is Aluminum because: Aluminum is a metal and its ion has charge of +3. It is also located on the borders of the Metalloid staircase .

Element J  is Magnesium because its ion has charge of 2+ and is  isoelectronic with Neon  because it loses two electrons to now have 10 electrons.

Element C  is Selenium because its ion that has a charge of -2  is formed by gaining two electrons in order to have 36 electrons which is isoelectronic with Kr ypton

Element L  is Carbon because carbon has the smallest atomic radius of any member in the Carbon family  because it is the first member of the family and atomic radius increases on going down the group.

Element D  is Sodium because its ion has charge of +1  and it has 2 inner core levels , the 1 and 2 energy levels.

Element Q  is Francium because it has the largest radius and lowest ionization  energy of any element

Element F  is Antimony. It is a member of Nitrogen family  and has the second highest ionization energy level in family .

Element R  is calcium because its on has charge of +2  which is isoelectronic with Argon . Calcium also has atomic radius is larger than Ar gon.

Element G  is Chlorine. It has the second to the smallest radius of elements in the 3rd period  as the second to the last element in the period because atomic radius decreases across a period from left to right.

Element S  is Tellurium. It has atomic mass larger than Iodine just to the right  of it and is found in the 5th period

The names of the elements as described are as follows;

For Element A:

Element A is oxygen as oxygen has 6 valence electrons ; is a gas at room temperature ; and is transported in blood to cells.

For Element H:

For Element B

For Element J

For Element C:

For Element L:

For Element D:

For Element Q:

For Element F:

For Element R:

For Element G:

Chlorine is element G It has the second to the smallest radius of elements in the 3rd period (only larger than Argon) because atomic radius decreases across a period

For Element S:

Tellurium is element S as it has atomic mass larger than Iodine just to the right of it and is found in the 5th period.

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Answer:

1.875 gallons

Explanation:

Answer:

Phosphate ion

Explanation:

When 325 grams of CHCl3 is produced, approximately 297.54 grams of HCl are also produced.

To determine the amount of HCl produced when 325 grams of CHCl3 (chloroform) is produced, we need to use the balanced chemical equation for the reaction:

CH4 + 3Cl2 -> CHCl3 + 3HCl

From the balanced equation, we can see that the stoichiometric ratio between CHCl3 and HCl is 1:3. This means that for every 1 mole of CHCl3, 3 moles of HCl are produced.

To calculate the number of moles of CHCl3, we need to divide the given mass (325 grams) by its molar mass:

Molar mass of CHCl3 = 12.01 g/mol (C) + 1.01 g/mol (H) + 3 x 35.45 g/mol (Cl) = 119.38 g/mol

Moles of CHCl3 = 325 g / 119.38 g/mol = 2.72 mol

Since the stoichiometric ratio between CHCl3 and HCl is 1:3, the number of moles of HCl produced is three times that of CHCl3:

Moles of HCl = 2.72 mol x 3 = 8.16 mol

To calculate the mass of HCl, we multiply the number of moles by its molar mass:

Molar mass of HCl = 1.01 g/mol (H) + 35.45 g/mol (Cl) = 36.46 g/mol

Mass of HCl = 8.16 mol x 36.46 g/mol = 297.54 g

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Answer:

it will affect the mass by changing in pressure will affect the volume (and therefore density) of gases, but will not noticeably affect the volume (or density) of solids and liquids. For gases: An increase in pressure leads to a decrease in volume and an increase in density. A decrease in pressure leads to an increase in volume and an decrease in density.

Explanation:

As the volume increases the mass of the liquid also increases as there is an increase in pressure.

Pressure is defined as the force applied on an object perpendicular to it's surface per unit area over which it is distributed.Gauge pressure is a pressure which is related with the ambient pressure.

There are various units by which pressure is expressed most of which are derived units which are obtained from unit of force divided by unit of area . The SI unit of pressure is pascal .

It is a scalar quantity which is related to the vector area element with a normal force acting on it.It is distributed over solid boundaries and across arbitary sections of fluid normal to the boundaries at every point.As the pressure increases, the volume decreases as they are inversely proportional at constant temperature.

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