pleasee answer with solution ​

We can substitute the value of T to get the final answer: [4Frac (pi/2)^2/3 - 5((pi/2)^4/4)]


To solve this problem, we need to use the fundamental theorem of calculus, which states that the definite integral of a function f(x) over an interval [a, b] can be evaluated by finding an antiderivative F(x) of f(x) and then subtracting F(a) from F(b).

In this case, we are given that Fx = Frac X23 is an antiderivative of fx. Therefore, we can write:
∫T 4fx - 5x^3 dx = [4F(x) - 5(x^4/4)]T

To evaluate this expression, we need to substitute T for x in the above expression and then subtract the result of substituting 0 for x. We get:
[4F(T) - 5(T^4/4)] - [4F(0) - 5(0^4/4)]

Since Fx = Frac X23, we have:
F(T) = Frac T23 and F(0) = Frac 023 = 0

Therefore, the expression simplifies to:
[4Frac T23 - 5(T^4/4)]

Finally, we can substitute the value of T to get the final answer:
[4Frac (pi/2)^2/3 - 5((pi/2)^4/4)]

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Answer:

2

Step-by-step explanation:

In an arithmetic sequence, the common difference refers to the constant amount added or subtracted between consecutive terms. To find the common difference, we can subtract any term from the following term.

Let's subtract the second term (-13) from the first term (-15):

-13 - (-15) = -13 + 15 = 2

So, the common difference in the arithmetic sequence -15, -13, -11, ... is 2.

In the expression, n is equal to  -1/3.

We have,

First, let's simplify the left side of the equation by distributing 1/4 to n and 1/4 to 7:

(1/4)n + (1/4)(7) = 5n - 7n + 1

Simplifying further by adding the like terms:

(1/4)n + 7/4 = -2n + 1

To get rid of the fraction, we can multiply both sides of the equation by 4:

4(1/4)n + 4(7/4) = 4(-2n + 1)

Simplifying:

n + 7 = -8n + 4

Bringing all the n terms to one side and all the constant terms to the other side:

n + 8n = 4 - 7

9n = -3

Dividing both sides by 9:

n = -1/3

Therefore,

In the expression, n is equal to  -1/3.

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When 750 minutes is being converted to weeks, the number of weeks would be= 0.074 week.

To convert the number of given minutes to weeks to following is carried out using the provided parameters.

First convert to hours, that is;

60mins = 1 hour

750 mins = X hour

make X the subject of formula;

X = 750/60 = 12.5 hours

Secondly convert to days;

24 hours = 1 day

12.5 hours = y days

make y the subject of formula;

y = 12.5/24 = 0.52 day

But 1 week = 7 days

X week = 0.52 day

X = 0.52/7 = 0.074week.

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When the effect of one input factor on the output depends on the level of another input factor, this is known as an interaction.

In statistical analysis, interactions are important to consider because they can have a significant impact on the results of a study.

Specifically, interactions occur when the effect of one factor on the output variable differs at different levels of another factor.

For example, if we are studying the effect of two different drugs on blood pressure, we may find that the effect of one drug depends on the age of the patient, while the effect of the other drug does not. In this case, we would say that there is an interaction between the drug and age factors.

To test for interactions, we can use a statistical technique called analysis of variance (ANOVA), which allows us to determine whether the effect of one factor depends on the levels of another factor.

If an interaction is present, we may also need to use a technique called blocking to account for the variability in the data.

In summary, interactions are an important concept in statistical analysis that can impact the results of a study, and ANOVA and blocking are useful techniques for detecting and accounting for interactions.

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The series ∑=0infinity diverges, meaning it does not have a finite sum. The sequence of series of partial sums increases without bound, meaning it diverges.

The series ∑=0infinity is an infinite sum of the constant value 23. To determine whether this series converges or diverges, we can use the definition of convergence: if the sequence of partial sums converges to a finite value, then the series converges. Otherwise, if the sequence of partial sums diverges or oscillates, then the series diverges.

The sequence of partial sums for this series is:

S1 = 23

S2 = 23 + 23 = 46

S3 = 23 + 23 + 23 = 69

...

As we can see, the sequence of partial sums increases without bound, meaning it diverges. Therefore, the series ∑=0infinity does not have a finite sum and is said to be divergent.

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Answer: b 1:4

Step-by-step explanation:

Answer:

The given expression 15:60 can be simplified by dividing both the numerator and denominator by their greatest common factor (GCF), which is 15 in this case. So, 15 divided by 15 is 1 and 60 divided by 15 is 4. Therefore, the simplified form of 15:60 is 1:4. 

So, the answer is (b) 1:4.

The graph of the equation of the circle x² + (y - 3)² = 4² is drawn below.

Given that:

Equation, x² + y² - 6y = 7

Let r be the radius of the circle and the location of the center of the circle be (h, k). Then the equation of the circle is given as,

(x - h)² + (y - k)² = r²

Convert the equation into a standard form, then we have

x² + y² - 6y = 7

x² + y² - 6y + 9 = 7 + 9

x² + (y - 3)² = 16

x² + (y - 3)² = 4²

The graph of the circle is drawn below.

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The marginal revenue (MR) curve for a monopoly firm is given by the derivative of the total revenue (TR) curve with respect to quantity (Q).

Total revenue (TR) is the product of price (P) and quantity (Q), i.e., TR = P × Q.

Differentiating TR with respect to Q, we get:

MR = dTR/dQ = d(P×Q)/dQ = P + Q×dP/dQ

The inverse demand curve given is: P = 400 - 8Q

Taking the derivative of P with respect to Q, we get:

dP/dQ = -8

Substituting this value into the above equation for MR, we get:

MR = 400 - 8Q + Q×(-8) = 400 - 16Q

Therefore, the correct answer is option (a) MR = 400 - 16Q.

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Based on the information, body B will fall 3.3 m in the first 3.0 s after the system is released.

The system of blocks will accelerate at a rate of:

a = (mB g - μk mA g) / (mA + mB)

= (15 kg * 9.8 m/s² - 0.20 * 25 kg * 9.8 m/s²) / (25 kg + 15 kg)

= 2.2 m/s²

Over a time of 3.0 s, body B will fall a distance of:

d = 0.5 * a * t²

= 0.5 * 2.2 m/s² * 3.0 s²

= 3.3 m

Therefore, body B will fall 3.3 m in the first 3.0 s after the system is released.

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The coefficient of kinetic friction between block A and the table is 0.20. Also, mA= 25 kg, mB= 15 kg. How far will body B fall in the first 3.0 s after the system is released?

The balance of the account after 7 years would be approximately $247.95.

We may use the compound interest calculation to determine the account balance after seven years:

[tex]A = P(1 + r/n)^{(nt)[/tex]

Where:

A = the final amount (balance) in the account

P = the principal amount (initial deposit)

r = annual interest rate (as a decimal)

n = number of times the interest is compounded per year

t = number of years

In this case, P = $150, r = 7.4% = 0.074 (as a decimal), n = 4 (quarterly compounding), and t = 7.

Plugging in these values into the formula, we get:

[tex]A = 150(1 + 0.074/4)^{(4\times7)[/tex]

Calculating this expression, we find:

A ≈ $247.95

Therefore, the balance of the account after 7 years would be approximately $247.95.

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Answer:

 Diameter

Step-by-step explanation:

You have to draw the diameter and perpendicularly bisect it. Then, where the bisector touches the circumference, connect them (there should be 4 points of contact).

Hope this helps!

Clockwise rotation 90° about the center of (4,3)

From the given figure,

A, B, C: (1,6) (3,8) (5,6) transform to A'B'C' (7,6) (9,4) (7,2)

Apply clockwise 90° rotation formula:  

x' = (y - y₀) + x₀    

Where  x represent s original position and

            x₀ represents  center

Therefore,

⇒ y' = - (x - x₀) + y₀

For A (1,6) ⇒ A' (7 , 6)

7 = (6 - y₀) + x₀               x₀ - y₀ = 1   ... (1)

6 = - (1 - x₀) + y₀     ⇒           x₀ + y₀ = 7   ... (2)

From (1) + (2):  

2 x₀ = 8   ⇒          x₀ = 4

From (2)-(1):

2 y₀ = 6     ⇒         y₀ = 3

Rotation center is  (4 , 3).      

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Answer:

by 29.25 %

Step-by-step explanation:

that is the ans

Answer:

6.67%

Step-by-step explanation:

there are 125 + 100 = 225 students.

boys:

125 decreased by 8%

decrease in 8% means 100% - 8% = 92%

125 X 0.92 = 115 boys.

girls:

100 decreased by 5%

decrease in 5% means 100% - 5% = 95%

100 X 0.95 = 95 girls

now the total number of girls and boys on the honor roll = 95 + 115 = 210 students.

that is a reduction of 225 - 210 = 15.

we want the reduction in percentage

15/225 = 0.0667

= 6.67%

A 90% confidence interval for the proportion of Americans with cancer was found to be (0.185, 0.210). is a. 0.1975.

The point estimate for a confidence interval is the midpoint of the interval. In this case, the midpoint would be the average of the lower and upper bounds: (0.185 + 0.210) / 2 = 0.1975.

Conclusion: Therefore, the point estimate for the given confidence interval of (0.185, 0.210) for the proportion of Americans with cancer is 0.1975.


To find the point estimate for a confidence interval, you can calculate the average of the lower and upper bounds. In this case, the lower bound is 0.185 and the upper bound is 0.210.

Step 1: Add the lower and upper bounds together: 0.185 + 0.210 = 0.395
Step 2: Divide the sum by 2 to find the average: 0.395 / 2 = 0.1975

Therefore, the point estimate for the 90% confidence interval for the proportion of Americans with cancer is 0.1975 (option a).

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To find dy/dx, we can use the chain rule,To find d²y/dx², we can use the quotient rule, The curve is concave up where d²y/dx² > 0, and concave down where d²y/dx² < 0. From part (b), we know that d²y/dx² is negative for all values of t, so the curve is concave down everywhere except for at points where dy/dx is undefined.

a) We can find dy/dx by using the chain rule:

dy/dx = dy/dt ÷ dx/dt

dx/dt = -9cos^8(t)sin(t)

dy/dt = 16sin(t)cos(t)

Therefore,

dy/dx = (16sin(t)cos(t)) / (-9cos^8(t)sin(t))

= -16cos(t) / (9sin^2(t)cos^7(t))

= -16cot(t) / (9cos^6(t))

(b) To find d²y/dx², we differentiate dy/dx with respect to t:

d(dy/dx) / dt = d/dt (-16cot(t) / (9cos^6(t)))

= (16 / 9) csc^2(t) cot^2(t) - (96 / 9) cos^5(t) csc^2(t) cot(t)

= (16 / 9) csc^2(t) (cot^2(t) - 6cos^5(t) cot(t))

Now, using the fact that dy/dx = -16cot(t) / (9cos^6(t)), we can write

d²y/dx² = (d(dy/dx) / dt) ÷ (dx/dt)

= [(16 / 9) csc^2(t) (cot^2(t) - 6cos^5(t) cot(t))] ÷ [-9cos^8(t)sin(t)]

= -16csc^2(t) / (9cos^7(t)) + (96 / 9) csc^2(t) cos^4(t) / sin(t)

= (16 / 9) csc^2(t) (6cos^4(t) / sin(t) - cot^2(t) - 1 / cos^7(t))

(c) To determine the concavity of the curve, we look at the sign of d²y/dx². If d²y/dx² is positive, the curve is concave up. If d²y/dx² is negative, the curve is concave down.

Note that dy/dx is undefined at t = kπ, where k is an integer, because cos^6(t) = 0. However, these points do not affect the concavity of the curve.

We can simplify d²y/dx² as

d²y/dx² = (16 / 9) csc^2(t) [(6cos^4(t) / sin(t)) - cot^2(t) - 1 / cos^7(t)]

The expression inside the square brackets is always positive, since cos^4(t) and cos^7(t) are both positive for all t and 1/sin(t) is positive for 0 < t < π. Therefore, the sign of d²y/dx² is determined by the factor csc^2(t), which is positive for 0 < t < π/2 and π/2 < t < π, and negative for π < t < 3π/2 and 3π/2 < t < 2π.

Therefore, the curve is concave up for 0 < t < π/2 and π/2 < t < π, and concave down for π < t < 3π/2 and 3π/2 < t < 2π.

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Answer:

£3250

Step-by-step explanation:

ann : ben : cheryll

  3  :    7   :     10

The difference between ben and ann in the ratio is 7 - 3 = 4

The real difference between ben and ann is £650.

The real numbers are in the ratio 3:7:10, but they are many times greater than 3, 7, and 10.

Introduce a variable in the ratio.

3x : 7x : 10x

The difference between ben and ann is 7x - 3x = 4x.

The real difference between ben and ann is £650.

Therefore,

4x = £650

x = 162.5

The total money in the ratio is 3x + 7x + 10x = 20x

20x = 20(162.5) = 3250

Answer: £3250

There are 35 possible combinations of 3 employees that can be chosen from the set of 7 at Dunder Mifflin Paper Company.

To find the number of combinations of 3 employees that can be chosen from the set of 7, we can use the formula for combinations:

nCr = n! / (r! * (n-r)!)

where n is the total number of employees (7 in this case) and r is the number of employees we want to choose (3 in this case).

Plugging in the values, we get:

7C₃ = 7! / (3! * (7-3)!)

= (7 * 6 * 5) / (3 * 2 * 1)

= 35

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The time it takes for the trains to be 297 miles apart is 297 miles / 135 mph = 2.2 hours.

To calculate the time it takes for the trains to be 297 miles apart, we can use the formula: time = distance / relative speed. Since the trains are moving in opposite directions, their relative speed is the sum of their speeds.

In this case, the relative speed of the passenger train and the freight train is 60 mph + 75 mph = 135 mph. Therefore, the time it takes for the trains to be 297 miles apart is 297 miles / 135 mph = 2.2 hours.

However, since time is typically measured in whole numbers of hours, we round up the decimal value to the nearest whole number. Therefore, it will take approximately 3 hours for the trains to be 297 miles apart.

It's important to note that this calculation assumes that the trains maintain a constant speed throughout the entire journey and that there are no stops or delays along the way.

Real-world factors such as acceleration, deceleration, and potential stops at stations would affect the actual time it takes for the trains to be 297 miles apart.

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The angle values that satisfy sin x = -0.39 are

In the question we were given that

sin x = -0.39

we find the angle by using the inverse sine function or arc sin on a calculator:

arc sin -0.39 = -23.45 degrees

sin functions are negative in the fourth and third quadrant hence we move the angle to these quadrants

Third quadrant: 180 + 23.45 = 203.45 degrees

fourth quadrant: 270 + 23.45 = 293.45 degrees

Therefore, the two angle values that satisfy sin x = -0.39 are approximately 203.45 degrees and 293.45 degrees

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The expected number of tosses required to obtain exactly k heads is k/2.

Let X be the random variable representing the number of tosses required to obtain exactly k heads. We can express X as a sum of indicator variables, where Xᵢ = 1 if the i-th toss is a head, and Xᵢ = 0 otherwise. Then, we have:

X = X₁ + X₂ + ... + Xₖ

The expected value of X is given by the linearity of expectation:

E(X) = E(X₁ + X₂ + ... + Xₖ) = E(X₁) + E(X₂) + ... + E(Xₖ)

Since the coin is fair, each toss has a probability of 1/2 of being a head. Therefore, the expected value of each indicator variable is:

E(Xᵢ) = P(Xᵢ = 1) * 1 + P(Xᵢ = 0) * 0 = 1/2

Using this, we can find the expected value of X:

E(X) = E(X₁ + X₂ + ... + Xₖ) = E(X₁) + E(X₂) + ... + E(Xₖ) = k * 1/2

Therefore, the expected number of tosses required to obtain exactly k heads is k/2. This result makes sense, since on average, we would expect to obtain one head for every two tosses of a fair coin.

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Least Integer are -

(a) n = 7

(b) n = 9

(c) n = 0

(d) n = 4

What is a polynomial?

A mathematical statement made up of variables, coefficients, and non-zero integer exponents is known as a polynomial. A sum of terms is represented by this algebraic equation, where each term is the product of a coefficient and one or more variables raised to non-negative integer exponents. Any symbols or letters, such as x, y, or z, can be used as the variables.

What is a degree of a polynomial?

The degree of a polynomial is the highest exponent/power of the variable (or variables) in the polynomial expression. It represents the degree of the highest term in the polynomial.

The smallest integer n with which f(x) is O(([tex]x^{n}[/tex]) for the given functions, we need to determine the highest power of x in each function. Let's analyse each function separately:

(a) f(x) = 2x² + x⁷log(x)

The highest power of x in this function is x⁷. Therefore, n = 7.

(b) f(x) = 3x⁹ + (log(x))⁴

The highest power of x in this function is x⁹. Therefore, n = 9.

(c) f(x) = (x⁴ + x² + 1)/(x⁴ + 1)

In this function, both the numerator and denominator have the highest power of x as x⁴. When we simplify the function, we can see that the highest power of x cancels out, resulting in a constant value of 1. So, f(x) is O([tex]x^{0}[/tex]) or simply O(1). Therefore, n = 0.

(d) f(x) = (x³ + 5log(x))/(x⁴ + 1)

The highest power of x in the numerator is x³, and the highest power of x in the denominator is x⁴. When we simplify the function, we can see that the x³ term becomes negligible compared to the x⁴ term as x approaches infinity. Therefore, f(x) is O(x⁴). Hence, the least integer n such that f(x) is O([tex]x^{n}[/tex]) is n = 4.

Therefore:

(a) n = 7

(b) n = 9

(c) n = 0

(d) n = 4

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The power factor in a system is defined as the cosine of the angle between the voltage and current waveforms. The power factor in this system is 0.906, indicating a relatively efficient use of power.

In this case, the voltage waveform is given as V = 120V sin(377t + 20°) and the current waveform is given as I = 60A sin(377t + 45°). To find the power factor, we need to determine the angle between the voltage and current waveforms. First, let's convert the voltage and current waveforms to phasor form:
V = 120V ∠ 20°
I = 60A ∠ 45°
The angle between the voltage and current phasors is given by:
θ = θv - θi = 20° - 45° = -25°
The power factor is the cosine of this angle, so:
PF = cos(-25°) = 0.906

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The critical value of F for a one-way between-subjects ANOVA with 4 and 43 degrees of freedom (5 levels minus 1, and 48 total participants minus 5 levels) at an alpha level of .01 is approximately 3.737.

To calculate the critical value of F, we need to use a statistical table or calculator. The F distribution table with 4 and 43 degrees of freedom at an alpha level of .01 gives a critical value of 3.737.

This means that if the calculated F value for the ANOVA is greater than 3.737, we can reject the null hypothesis at the .01 level of significance.

It's important to note that the critical value of F changes depending on the degrees of freedom and the alpha level chosen.

In this case, we have 5 levels/conditions and 48 participants, but if the sample size or number of levels changes, the critical value of F would be different.

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The value of the diameter of the base of the cylinder is,

⇒ d = 8

We have to given that;

The volume of a cylinder is 96 π cubic meters

And, the height is 6 meters.

Since, We know that;

Volume of cylinder is,

V = πr²h

Substitute all the values we get;

96π = π × r² × 6

16 = r²

r = √16

r = 4

Thus, The value of the diameter of the base of the cylinder is,

⇒ d = 4 × 2

⇒ d = 8

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Answer:

C

Step-by-step explanation:

To represent the system of equations step by step using matrices, we'll start by setting up the coefficient matrix and the constant matrix. Let's go through the process:

Step 1: Write down the equations:

Equation 1: y = 10

Equation 2: 4x - 5y = 3

Step 2: Set up the coefficient matrix (matrix A):

Coefficients of Equation 2: 4 and -5

Coefficients of Equation 1: 0 and 1

A =

| 4 -5 |

| 0 1 |

Step 3: Set up the constant matrix (matrix B):

Constants of Equation 2: 3

Constants of Equation 1: 10

B =

| 3 |

| 10 |

Step 4: Combine the coefficient matrix and constant matrix into an augmented matrix (matrix [A|B]):

[A|B] =

| 4 -5 3 |

| 0 1 10 |

This augmented matrix represents the system of equations:

4x - 5y = 3

0x + 1y = 10

Each row in the augmented matrix corresponds to an equation in the system. The first column represents the coefficients of x, the second column represents the coefficients of y, and the last column represents the constants.

Therefore, the matrix that represents the system of equations is:

C.

0 1 3

4 -5 10

The first question requires finding the roots of a quadratic equation using factorization, the second question requires finding the derivative of a given function with respect to x, the third question requires calculating compound interest for a given period, and the fourth question requires finding the sum of the first 70 terms of an arithmetic progression.

To solve the quadratic equation x² + 3x - 28 = 0 using factorization, we need to find two numbers whose sum is 3 and whose product is -28. The two numbers are 7 and -4. Therefore, we can write the quadratic equation as (x + 7)(x - 4) = 0, which gives the roots x = -7 and x = 4.

To find the derivative of 2-2ut4 with respect to x, we need to treat t as a constant and apply the power rule of differentiation. The derivative is -8ut3(d/dx)(2-2ux) = -8ut3(-4u) = 32u2t3.

To find the compound interest for 3 years at 8,000.00 with an annual interest rate of 10%, we can use the formula A = P(1 + r/n)nt, where A is the total amount, P is the principal, r is the annual interest rate, n is the number of times interest is compounded per year, and t is the time in years. In this case, P = 8,000.00, r = 10%, n = 1 (since interest is compounded annually), and t = 3. Plugging in these values, we get A = 8,000.00(1 + 0.10/1)1(3) = 10,480.00. Therefore, the compound interest for 3 years is 2,480.00.

To find the sum of the first 70 terms of an arithmetic progression whose 10th and 12th terms are 50 and 65, respectively, we need to first find the common difference (d) and the first term (a1). Using the formula for the nth term of an arithmetic progression, we can write the equations a10 = a1 + 9d = 50 and a12 = a1 + 11d = 65. Solving these equations simultaneously, we get a1 = 22 and d = 3. Therefore, the sum of the first 70 terms is given by the formula S70 = (n/2)(2a1 + (n-1)d), where n = 70. Plugging in the values, we get S70 = (70/2)(2(22) + (70-1)3) = 3,955.

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Answer:

4 pizzas

Step-by-step explanation:

first of all, subtract parking fee from total:

52 - 4 = 48.

now divide by 12:

48/12

4.

so he he pays for 4 pizzas at $12 each (4 X 12 = 48).

and he pays $4 for parking.

48 + 4 = 52.