Answer:
A. New problem or discovery Engineering solution Development Research Explanation:
A possible sequence of steps in the research and development cycle are A. New problem or discovery Engineering solution Development Research. In the research and development cycle, the first step is the problem that a scientist observe. After that we have discover a solution for that problem through many research so the above materials are the possible sequence of steps in the research and development cycle.
how to solve for resistors
9514 1404 393
Answer:
A1 = 3A, A2 = 1.5A
Effective resistance = 2Ω
Explanation:
When the switch is closed, the voltage across each resistor is 6V, so the current through it (A2) is ...
A2 = 6V/(4Ω) = 1.5A
There are two parallel paths, each with that current, so the current from the battery is ...
A1 = A2 +A2 = 1.5A +1.5A = 3.0A
Then the effective resistance is ...
Reff = 6V/(3.0A) = 2.0Ω
The solution to the circuit is ...
A1 = 3A, A2 = 1.5A
Effective resistance = 2Ω
Define Newton's law of motion?
how long the period of the earth's circulation (365 1/4) in seconds?
Answer:
31,556,736 seconds
Explanation:
The period of Earth's orbit around the Sun, T = (365 + 1/4) days (three hundred and sixty five and a quarter days
The period of Earth's orbit around the Sun in seconds is given by converting, T = [tex]365\frac{1}{4} \, days[/tex] into seconds as follows;
There are 60 seconds per minute, 60 minutes in each hour, 24 hours within each day, therefore, we get;
T = [tex]365\frac{1}{4}[/tex]×60 sec/min × 60 min/hr. × 24hr/day = 31,556,736 seconds
Which two factors affect the size of the gravitational field?
Answer:
Explanation:
mass and distance
13.Suppose a ball of mass m is thrown vertically upward with an initial speed v, its speed decreases continuously till it becomes zero. Thereafter, the ball begins to fall downward and attains the speed u again before striking the ground. It implies that the magnitude of initial and final momentums of the ball are same. Yet, it is not an example of conservation of momentum. Explain why?
Answer:
Law of conservation of momentum is applicable to isolated system (no external force is applied).
In this case, the change in velocity is due to the gravitational force of earth.When the ball is thrown up, negative force of gravity is applied and so the speed becomes zero.After that due to gravitational force the ball falls down with same initial velocity.
Two blocks, one of mass 5 kg and the other of mass 2 kg, are attached to opposite ends of a light string and hung vertically from a massless, frictionless pulley. Initially the heavier block is held in place a distance 2.5 m above the floor, the lighter block is just touching the floor, and the cord is taut. Then the heavier block is released and comes crashing to the floor while the cord slackens and the lighter block continues to rise. What is the maximum height reached by the lighter block
Answer:
[tex]H_{max}=3.4m[/tex]
Explanation:
From the question we are told that:
Mass 1 [tex]m_1=5kg[/tex]
Mass [tex]m_2=2kg[/tex]
Distance above floor [tex]d=2.5m[/tex]
Generally the equation for Conservation of energy is mathematically given by
[tex]0.5m_1v^2+0.5m_2v^2=2mg[/tex]
[tex]0.5m_1v^2+0.5m_2v^2=2g(m_1-m_2)[/tex]
[tex]v^2(0.5*m_1+0.5*m_2)=2*g(m_1-m_2)[/tex]
[tex]v^2(0.5*5+0.5*2) = 2 * 9.8 * (5 - 2)[/tex]
[tex]v^2=\frac{58.8}{3.5}[/tex]
[tex]v=4.1m/s[/tex]
Generally the equation for The maximum height of lighter block is mathematically given by
[tex]H_{max}=d+\frac{v^2}{2g}[/tex]
[tex]H_{max}=2.5+\frac{16.2}{2*9.81}[/tex]
[tex]H_{max}=3.4m[/tex]
TRUE OR FALSE. if an object covers equal distance at equal intervals of time, then it is moving at constant speed and not accelerating
Answer:
True
Explanation:
Speed = distance/time
If distance and time are the same, then the right hand side of the equation remains the same, causing us to solve the left to the same value
As the distance is the same (say 50m) and the time is the same (say 50s) then the speed must be the same (1m/s)
Which statement best describes an insulator
Define ELASTIC LIMIT, YIELD POINT AND ULTIMATE TENSILE STRENGTH?
[tex] \green{\huge{\red{\boxed{\green{\mathfrak{QUESTION}}}}}} [/tex]
ELASTIC LIMIT, YIELD POINT AND ULTIMATE TENSILE STRENGTH.
[tex] \orange{\underline{\huge{\bold{\textit{\green{\bf{TOPIC}}}}}}} [/tex]
Mechanical Properties Of Solid.
[tex] \huge\green{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}}}[/tex]
[tex] \bold{ \green{PART \: \: (1):-}} \\ \bold \green {{ ELASTIC \: \: LIMIT}}[/tex]
It is also called yield point
In this limit, energy provided to the material to cause deformation when removed then the material returns to its own shape and size.
In this limit each body shows elastic nature
[tex] \bold{ \red{PART \: \: (2):-}} \\ \bold \red {{YIELD \: \: STRENGTH}}[/tex]
It is the fix amount of the energy which causes fixed permanent set of deformation.
In this body shows plastic deformation.
The level of stress that corresponds to the yield point is referred to as the yield strength of the material.
[tex]\bold{ \purple{PART \: \: (3):- \:ULTIMATE }} \\ \bold \purple {{TENSILE \: \: STRENGTH}}[/tex]
It is the amount of the stress which causes permanent set of deformation after the yield point.
Body show perfect plastic deformation.
This shows a permanent set of deformation.
[tex] \red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star[/tex]
b.
13. What i
c.
In a single movable pulley, a load of 500 N is lifted by applying 300 N effort
Calculate MA, VR and n.
[Ans: MA = 1.66, VR = 2, n = 8
83.33%]
Answer:
MA = 1.66, VR = 2, Efficiency = 83.33%
Explanation:
Given the following
Load = 500N
Effort = 300N
Mechanical Advantage = Load/Effort
MA = 500/300
MA = 5/3 = 1.66
Velocity ratio is the number of pulleyc present in the block and tackle system. Since the pulley is a single movable pulley, then VR = 2
Efficiecncy n = MA/VR * 100%
n = 1.66/2 * 100
n = 166/2
n = 83.33%
A gas at a pressure p is compressed to half it original volume and twice its original temperature. The new pressure is
Answer:
4p
Explanation:
If you halve the volume the pressure will double as they are inversely proportional. If you double the temperature the particles have double the kinetic energy so the pressure will double again.
So:
p×2×2 = 4p
Answer:
P V = n R T
P2 V2 / (P1 V1) = T2 / T1
P2 = (T2 / T1) (V1 / V2) P1 = 2 * 2 = 4
what happens to the force when the distance increases between 2 particales
convert 700kg into grams
Answer:
700,000g
Explanation:
1kg = 1000 Grams (or any kg x 1000)
Answer:
700 kilograms is equal to 700,000 grams
Explanation:
One kilogram has 1000 grams, or if you want the other way around, one gram is 1/1000th of one kilogram. If you follow this logic, we want to use the 'one kilogram has 1000 grams' "rule", so we would do some math here.
700 kg x 1000 g = ______ g
700*1000 = 700,000
700 kg = 700,000 g
Please let me know if I misunderstood and I hope this helped!
What is the period? Blank seconds.
Answer:
Period refers to the time for something to happen and is measured in seconds/cycle
Answer:
What is the period of time? 5.62 Seconds
What is the amplitude? 1 Centimeters
Explanation:
it just makes sense
A car moves with the speed of 40 km/hr for the first half and 60 km/hr
for Second half distance "What is the average distance of cars.
Answer:
50 km/h
Explanation:
[tex](40 + 60) / 2[/tex]
-> [tex]50[/tex] (km/h)
A thin rod of length 1.4 m and mass 180 g is suspended freely from one end. It is pulled to one side and then allowed to swing like a pendulum, passing through its lowest position with angular speed 1.80 rad/s. Neglecting friction and air resistance, find (a) the rod's kinetic energy at its lowest position and (b) how far above that position the center of mass rises.
Answer:
[tex]K.E = 0.1905 J[/tex]
Explanation:
From the question we are told that:
Length [tex]L=1.4m[/tex]
Mass [tex]m=180g[/tex]
Angular Velocity [tex]\omega=1.80rads/s[/tex]
Generally the equation for Kinetic energy K.E is mathematically given by
[tex]K.E =0.5 (1/3 ML^2 )w^2[/tex]
[tex]K.E =0.5 ( 1/3 * 0.18 * 1.4^2 ) 1.8^2[/tex]
[tex]K.E = 0.1905 J[/tex]
what is the least count of screw gauge and vernier calliper (9th grade) please help!
Why are the largest craters we find on the Moon and Mercury so much larger than the largest craters we find on the Earth
Answer:
Because Moon and Mars has no atmosphere.
Explanation:
Moon and Mars has no atmosphere, so there is no friction on the falling object due to the atmosphere. The speed of the falling object is more at Moon and Mars.
When a small object impact on the surface of moon or Mars with high speed, the size of crater is large than the earth as out earth has atmosphere.
Please help
Will give the brainliest!
c. aluminium
d. it cannot travel through glass
e. mass of 55kg, takes 25s to gain a height of 15m
when you order clothes, does the sweater has to be longer than your shirt to fit you just like the shirt?
Answer:
Yes.⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Which type of stress is most likely the cause of irritability?
eustress
O hypostress
O distress
O peripheral stress
Answer:
The correct answer is - distress.
Explanation:
Eustress is a type of stress that is beneficial to person and caused by adrenaline. Hypostress is a stress that is caused due to boredom or no work. It is stress comes with wasting the time.
Distress is the bad stress caused by anxiety, sadness, grief, and such type of stress that is caused irritability. Irritability is caused not just by stress but many factors.
Is torque only produced when the force is applied perpendicular to the moment arm?
The Torque is only produced when the force is applied perpendicular to the moment arm.
What is moment of force?The equal and opposite force acting at a point from the axis of rotation is called the moment.
M = F x r
Moment of force is also called as Torque.
Moment arm is the distance of the point of application of force from the axis of rotation of the body.
Thus, the perpendicular component only, produces the torque.
Learn more about moment of force.
https://brainly.com/question/6278006
#SPJ2
A cup of mass 0.4 kg with its base radius of 4 cm is kept on a table. Calculate the pressure exerted by the cup on the table.
Answer:
779.87 N/m²
Explanation:
Pressure = Force (F) / Area (A)
Recall :
Force = ma ; mass * acceleration due to gravity
a = 9.8 m/s² ; mass = 0.4kg
Force, F = 0.4 * 9.8 = 3.92 N
Area = πr² ; r = Radius = 4cm = 4 / 100 = 0.04 m
Area = π0.04² = 0.0050265 m²
Hence,
Pressure = 3.92 / 0.0050265
Pressure = 779.86670 N/m²
Pressure = 779.87 N/m²
A 4 LBfweight is attached to a spring suspended from the ceiling. When the weight comes to rest at equilibrium, the spring has been stretched 3 inches. The damping constant for the system is 2 LBf−sec ft . If the weight is raised 9 inches above equilibrium and given an initial upward velocity of 2 ft/sec, determine the equation of motion of the weight and give its damping factor, quasiperiod and quasifrequency.
Answer:
attached below
Explanation:
The initial conditions :
x(0) = - 9 inches = -3/4 ft
x'(0) = - 2 ft/sec
spring stretched 3 inches = 1/4 ft
mass = w / g = 4 Ib / 32 ft/sec^2 = 1/8 slug
the spring constant ( k ) = w / l = 4 / ( 1/4 ) = 16 Ib/ft
applying the second law of motion
m d^2x/dt^2 + b dx/dt + kx
= 1/8 d^2x/dt^2 + 2 dx/dt + 16 x
= d^2x/dt^2 + 16 dx/dt + 128 x ------- ( 1 )
we will resolve the above equation to obtain the required equation of motion x( t )
Attached below is the remaining part of the solution
Which describes an atom that has fewer neutrons than protons and more electrons than protons?
negative compound
positive compound
positive ion
negative ion
Answer:
Negative ion
.................
If you connected 10 of these 12V (10 W) lamps in parallel, to the 12V source, how much current would the source have to supply
Answer:
[tex]T=8.33A[/tex]
Explanation:
From the question we are told that:
Number of battery [tex]n=10[/tex]
Voltage source[tex]E=12V[/tex]
Lamp Power[tex]P=10W[/tex]
Generally the equation for Resistance is mathematically given by
[tex]R=\frac{V^2}{P}[/tex]
[tex]R=\frac{12^2}{10}[/tex]
[tex]R=14.4ohms[/tex]
Therefore
[tex]R_{eq}=\frac{14.4}{10}[/tex]
[tex]R_{eq}=1.44[/tex]
Generally the equation for Current is mathematically given by
[tex]T=\ffrac{V}{Req}[/tex]
[tex]T=\frac{12}{1.44}[/tex]
[tex]T=8.33A[/tex]
1. A rocket is forced forward by the ______ force of its engines, expelling gases out the rear of the rocket.
There are two forces acting on a rocket at the moment of lift off: Thrust pushes the rocket upwards by pushing gases downwards in the opposite direction.Weight is the force due to gravity pulling the rocket downwards towards the centre of the earth.So I'm thinking the answer is THRUST.
Mary drives at a speed of 35 mph (mile/hour). How long does it take for her to drive 98 miles?
__ hours
Answer:
2.8 hours
Explanation:
98 ÷ 35 = 2.8
what is latent heat of vaporization?
The amount of energy required for a unit mass of a substance to undergo a phase change from liquid to gas.
When cars travel around a banked (curved) road at the optimum angle,the normal reaction force (n) can provide the necessary centripetal force without the need for a friction force. (a)Describe whar would happen to Optimum banking angle when radius doubles? (b)Describe what would happen to optimum angle when speed doubles? (c)A car negotiate a turn of radius 80cm.What is the optimum banking angle for this curve if the speed is to be equal to 12m/s?
Answer:
(a) The optimum banking Decreases
(b) The optimum banking Increases
(c) The optimum banking is approximately 86.88°
Explanation:
(a) The equation of motion on a banked road is given as follows;
[tex]v = \sqrt{R \cdot g \times \left(\dfrac{tan (\theta) + \mu}{1 - \mu \cdot tan (\theta) }\right) }[/tex]
For no friction, we have;
v = √(R·g·tan(θ))
Where;
R₁ = The radius of the road
g = The acceleration due to gravity ≈ 9.81 m/s² = Constant
θ₁ = The bank angle
μ = The coefficient pf friction = Constant
v = The vehicle's speed
If the radius doubles, for no friction, we have;
v² = R·g·(tan(θ))
tan(θ) = v²/(R·g)
Therefore, when the radius doubles, tan(θ) becomes smaller and therefore, the optimum banking angle θ decreases (becomes smaller)
(b) When the speed doubles, we have;
v₁ = 2·v
∴ tan(θ₁) = (v₁)²/(R·g) = 4·(v)²/(R·g) = 4·tan(θ)
When the speed doubles, tan(θ) increases and therefore, the optimum banking angle θ increases increases
(c) The radius negotiated by the car, R = 80 cm = 0.8 m
The speed of the car, v = 12 m/s
From tan(θ) = v²/(R·g), we have;
tan(θ) = 12²/(0.8 × 9.81) ≈ 18.349
θ ≈ arctan(18.349°) ≈ 86.88°
