The simplest form of the given expression x will be 42.
What is polynomials?Using variables and coefficients, polynomials are algebraic expressions. The term "indeterminates" is sometimes used to describe variables. The terms Poly and Nominal, which together signify "many" and "terms," make up the word polynomial.
When exponents, constants, and variables are combined using mathematical operations like addition, subtraction, multiplication, and division, the result is a polynomial (No division operation by a variable). The expression is categorized as a monomial, binomial, or trinomial based on the number of terms it contains.
Here we assume that no of suitcases be x
So, 7/24 = x/144
24x = 1008
x = 42.
Hence the simplest form of the given expression x will be 42.
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Month Sales
Jan 34
Feb 36
Mar 39
Apr 37
May 38
June
Using exponential smoothing, with an alpha value of 0.2 and assuming the forecast for Jan is 34, what is the forecast for June?
a. 37.5
b. 36.1
c. 35.6
d. 32.4
What is the MAD value for the two-month moving average?
a. 2.67
b. 3.0
c. 4.5
d. 1.
1- The forecast for June using exponential smoothing with an alpha value of 0.2 and assuming the forecast for Jan is 34 is B. 36.1.
2- The MAD value for the two-month moving average is A. 2.67.
1- The forecast for June using exponential smoothing can be calculated as follows:
Ft = Ft-1 + α(At-1 - Ft-1)
Where Ft is the forecast for the current period, Ft-1 is the forecast for the previous period, At-1 is the actual sales for the previous period, and α is the smoothing constant.
Using the given data and an alpha value of 0.2, the forecast for June can be calculated as follows:
FJan = 34
FFeb = 34 + 0.2(34 - 34) = 34
FMar = 34 + 0.2(36 - 34) = 34.4
FApr = 34.4 + 0.2(39 - 34.4) = 35.32
FMay = 35.32 + 0.2(37 - 35.32) = 35.66
FJune = 35.66 + 0.2(38 - 35.66) = 35.87
Therefore, the forecast for June is 35.87, which is closest to option b. 36.1.
2- The MAD value for the two-month moving average can be calculated as follows:
MAD = (|34 - 35| + |36 - 34.5| + |39 - 35.5| + |37 - 37.5| + |38 - 38|) / 5 = 2.67
Therefore, the MAD value for the two-month moving average is 2.67, which is closest to option a. 2.67.
So the correct answers are B: 36.1 for the forecast for June and A: 2.67 for the MAD value for the two-month moving average.
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Let X (3, 0.02). Given Tx = 300 calculated by the Esscher Premium Principle with parameter 1, calculate h
The value of h is 99.969.
The Esscher Premium Principle is a method of calculating insurance premiums that considers the risk of an event occurring and the potential severity of the loss. The formula for the Esscher Premium Principle is:
Ex = ln(∑eαx Px)/α
Where Ex is the Esscher premium, α is the parameter, x is the loss amount, and Px is the probability of the loss occurring.
In this case, we are given X (3, 0.02), meaning that the loss amount is 3 and the probability of the loss occurring is 0.02. We are also given that the Esscher premium is 300 and the parameter is 1. Plugging these values into the formula, we get:
300 = ln(∑e1(3) 0.02)/1
Simplifying the equation, we get:
300 = ln(0.02e3)
Taking the natural logarithm of both sides, we get:
e300 = 0.02e3
Dividing both sides by 0.02, we get:
e300/0.02 = e3
Taking the natural logarithm of both sides again, we get:
300 - ln(0.02) = 3
Solving for h, we get:
h = (300 - ln(0.02))/3
h = 99.969
Therefore, the value of h is 99.969.
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HELP!!!
Zach earns $37.50 every weekend for delivering newspapers. Zach is saving his earnings in order to buy a new computer that costs $470.80. If Zach already has $58.30, enter the minimum number of weekends Zach will need to work before he has enough money to buy the computer.
Answer: 11 weekends
Step-by-step explanation: I did 470.80 divided by 37.50 and got 12 with a decimal, so then I multiplied 37.50 by 11 and got 412.5, then added the 58.30 .
Answer:
Step-by-step explanation:
So first you have to subtract the total that the computer costs by how much zach already has. Then you get 411.7. Then you have to divide 411.7 by 37.50 to get how many weeks it takes to get the computer. Which is 10.96 or 11. 11 weeks is the answer! You can check this by multiplying 37.50 by 11 and add 58 because he already has that money, you will get 470! which is close so there you go!
A company establishes a sinking fund to pay a debt of $150,000 due in 4 years. At the beginning of each six-month period, they deposit $R in an account paying 9%, compounded semi-annually. How big must the payments be to pay the debt on time? ANSWER: ____dollars
A company establishes a sinking fund to pay a debt of $150,000 due in 4 years. The required payment at the beginning of each six-month period is $6,235.54.
The sinking fund payment will earn interest at a rate of 9% per year, compounded semi-annually. This means the effective interest rate per six-month period is [tex](1 + 0.09/2)^2 - 1 = 0.045 = 4.5%[/tex]
Using the formula for the future value of an annuity, [tex]FV = R[((1+r)^n - 1)/r][/tex], where r is the interest rate per period and n is the number of periods, we can calculate the required payment R as:
[tex]150,000 = R[((1+0.045)^8 - 1)/0.045][/tex]
R = 6,235.54
Therefore, the company needs to make payments of $6,235.54 at the beginning of each six-month period to accumulate enough money in the sinking fund to pay off the $150,000 debt in 4 years.
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Prove that, for a, b, and c ∈ Z, a > b and c > 0 =⇒ ac
> bc (part 3 of Proposition 2)
Our assumption is false
We can prove this statement by contradiction. Suppose a > b and c > 0 but ac < bc.
Since a > b, then a - b > 0. Multiplying both sides by c > 0 gives (a - b)c > 0.
We can then add bc to both sides to get (a - b)c + bc > bc.
Since we assumed that ac < bc, then (a - b)c < 0, and thus (a - b)c + bc < bc, which contradicts the previous result.
Therefore, our assumption is false, and we can conclude that for a, b, and c ∈ Z, a > b and c > 0 =⇒ ac ≥ bc.
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A vector u and a set S are given. If possible, write u as a linear combination of the vectors in S. U = [3], S= {[1], [2], [-2}}
[8] {[2] [3] [-5]}
Therefore, one possible way to write vector u as a linear combination of the vectors in set S is:
u = [2] + [3]
To write vector u as a linear combination of the vectors in set S, we need to find scalars a, b, and c such that:
u = a[1] + b[2] + c[-2]
Substituting the given values of u and the vectors in S, we get:
[3] = a[1] + b[2] + c[-2]
To solve for the scalars a, b, and c, we can set up a system of equations:
3 = a + 2b - 2c
Since we only have one equation and three unknowns, there are infinitely many solutions to this system. One possible solution is:
a = 1, b = 1, c = 0
Substituting these values back into the equation, we get:
[3] = 1[1] + 1[2] + 0[-2]
Therefore, one possible way to write vector u as a linear combination of the vectors in set S is:
u = [1] + [2]
Similarly, for the second set of vectors, we need to find scalars d, e, and f such that:
u = d[2] + e[3] + f[-5]
Substituting the given values of u and the vectors in S, we get:
[8] = d[2] + e[3] + f[-5]
To solve for the scalars d, e, and f, we can set up a system of equations:
8 = 2d + 3e - 5f
Since we only have one equation and three unknowns, there are infinitely many solutions to this system. One possible solution is:
d = 2, e = 2, f = 0
Substituting these values back into the equation, we get:
[8] = 2[2] + 2[3] + 0[-5]
Therefore, one possible way to write vector u as a linear combination of the vectors in set S is:
u = [2] + [3]
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Suppose you are playing with someone new in soccer and you do not know how is strong, but you suspect you are. Let e be the probability that you win a single game. For now, we will treat o as discrete, with possible values 0, 0.1, ..., 1.0, and suppose you guess that the corresponding probabilities are ө teta Prior: P (0)
0 0
0.1 0.01
0.2 0.02
0.3 0.04
0.4 0.1
0.5 0.15
0.6 0.2
0.7 0.25
0.8 0.16
0.9 0.04
1 0
total Suppose you win the first time (), but then you lose twice () How does this information change your belief about the probability e. In another word, calculate the overall chances (expected values) of winning the games before/ and after you played? Note -Before you play, you believe that there is a 1% chance that your probability of winning any given game is 10%. - 2% chance that your winning probability is 20%, and so on.
The overall chances of winning the games before playing were 52%, and after playing and winning once but losing twice, the overall chances of winning are 17.33%. This shows that the new information has changed your belief about the probability of winning, and you now suspect that your chances of winning are lower than before.
Before playing the games, the expected value of winning is calculated by multiplying the probability of winning with the corresponding probabilities and adding them together. This is shown below:
E(win) = (0)(0) + (0.1)(0.01) + (0.2)(0.02) + (0.3)(0.04) + (0.4)(0.1) + (0.5)(0.15) + (0.6)(0.2) + (0.7)(0.25) + (0.8)(0.16) + (0.9)(0.04) + (1)(0) = 0.52
After playing the games and winning once but losing twice, the expected value of winning is calculated by multiplying the probability of winning with the corresponding probabilities, and adding them together. However, the probabilities are adjusted based on the new information. The new probabilities are shown below:
P(win) = (0)(0) + (0.1)(0.01)(1/3) + (0.2)(0.02)(1/3) + (0.3)(0.04)(1/3) + (0.4)(0.1)(1/3) + (0.5)(0.15)(1/3) + (0.6)(0.2)(1/3) + (0.7)(0.25)(1/3) + (0.8)(0.16)(1/3) + (0.9)(0.04)(1/3) + (1)(0)(1/3) = 0.17333
Therefore, the overall chances of winning the games before playing were 52%, and after playing and winning once but losing twice, the overall chances of winning are 17.33%. This shows that the new information has changed your belief about the probability of winning, and you now suspect that your chances of winning are lower than before.
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Rewrite without parentheses. (3x^(4)z^(2)-8x^(5))(-6xz^(6)) Simplify your answer as much as possible.
The equation (3x⁴z² - 8x⁵)(-6xz⁶) is rewritten without parenthesis as 48x⁶z⁶ - 18x⁵z⁸
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables. Equations can either be linear, quadratic, cubic and so on depending on the degree.
Given the equation:
(3x^(4)z^(2)-8x^(5))(-6xz^(6))
Simplifying gives:
= (3x⁴z² - 8x⁵)(-6xz⁶)
Opening the parenthesis gives:
= -18x⁵z⁸ + 48x⁶z⁶
= 48x⁶z⁶ - 18x⁵z⁸
The equation is equivalent to 48x⁶z⁶ - 18x⁵z⁸
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The figure is shown composed of a rectangle and a hexagon. The length of each side of the hexagon is 2 cm determine the area of the shaded region.
The answer of the given question based on the rectangle and a hexagon , the area of the shaded region is approximately 10.51 cm².
What is Area?Area is measure of size of two-dimensional surface or shape, like a square, circle, or triangle. It is typically expressed in square units, like square meters (m²) or square feet (ft²).
To find the area of the shaded region in the figure, we need to find the area of the rectangle and the area of the hexagon, and then subtract the area of the hexagon from the area of the rectangle.
The rectangle has a length of 8 cm and a width of 2 cm, so its area is:
A(rectangle) = length x width = 8 cm x 2 cm = 16 cm²
The hexagon has a side length of 2 cm, so we can divide it into 6 equilateral triangles with side length 2 cm. Each of the triangles has area of an;
A(triangle) = (sqrt(3)/4) x side² = (sqrt(3)/4) x 2² = (2sqrt(3))/4 = sqrt(3)/2
The area of the hexagon is therefore:
A(hexagon) = 6 x A(triangle) = 6 x sqrt(3)/2 = 3sqrt(3)
A(shaded) = A(rectangle) - A(hexagon) = 16 cm² - 3sqrt(3) cm² ≈ 10.51 cm²
Therefore, the area of the shaded region is approximately 10.51 cm².
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Suppose that the relation C is defined as follows. C={(c,h),(j,j),(j,c),(e,a)} Give the domain and range of C.
The domain and range of C are:
Domain of C: {c, j, e}
Range of C: {h, j, c, a}
The domain and range of a relation C are the set of all x-values and y-values in the ordered pairs of C. The domain of C is the set of all x-values, and the range of C is the set of all y-values. We can find the domain and range of C by looking at the ordered pairs in C={(c,h),(j,j),(j,c),(e,a)}.
The domain of C is {c, j, e} because these are the x-values in the ordered pairs. The range of C is {h, j, c, a} because these are the y-values in the ordered pairs.
Therefore, the domain and range of C are:
Domain of C: {c, j, e}
Range of C: {h, j, c, a}
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Prices are reduced by 10%, Natallie buys a pair of shoes for £54, what was the original price?
The original price of the given pair of shoes is; £59.4
It is known the original price is:
OP=(100+DP)/100X.... (i), where,
OP = Original Price
CP = Cost Price = £54,
DP = Discount percentage = 10%.
Substituting the values in equation (i), we get:
OP = (100+10)/100X54 ,
Or, OP = 110/100x54 = 59.4.
Therefore the Original Price of the Pair of Shoes is £59.4.
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coefficients. asses through (-3,2) and is parallel to the line defined by 5x+2y=-10
To find the equation of the line that passes through (-3,2) and is parallel to the line defined by 5x+2y=-10, we need to follow these steps:
Step 1: Find the slope of the given line. Since the equation is in the form of Ax + By = C, we can rearrange it to the slope-intercept form, y = mx + b, where m is the slope.
5x + 2y = -10
2y = -5x - 10
y = (-5/2)x - 5
So, the slope of the given line is -5/2.
Step 2: Since the two lines are parallel, they have the same slope. So, the slope of the new line is also -5/2.
Step 3: Use the point-slope form of a line to find the equation of the new line. The point-slope form is y - y1 = m(x - x1), where m is the slope and (x1, y1) is the given point.
y - 2 = (-5/2)(x - (-3))
y - 2 = (-5/2)x - 15/2
y = (-5/2)x - 15/2 + 2
y = (-5/2)x - 11/2
So, the equation of the new line is y = (-5/2)x - 11/2.
Therefore, the equation of the line that passes through (-3,2) and is parallel to the line defined by 5x+2y=-10 is
y = (-5/2)x - 11/2.
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A tank contains 12 litres of water in which is dissolved 24 grams of chemical A solution containing 4 grams per litre of the chemical flows into the tank at a rate of 4 litres per minute, and the well-stirred mixture flows out at a rate of 2 litres per minute. Determine the amount of chemical in the tank after 15 minutes.
The amount of chemical in the tank after 15 minutes is 154.14 grams.
To determine the amount of chemical in the tank after 15 minutes, we need to use the formula for the concentration of a solution:
C = m/V
Where C is the concentration of the solution, m is the mass of the chemical, and V is the volume of the solution.
Initially, the tank contains 12 litres of water and 24 grams of chemical A, so the initial concentration of the solution is:
C0 = 24/12 = 2 grams per litre
The solution flows into the tank at a rate of 4 grams per litre and 4 litres per minute, so the amount of chemical flowing into the tank per minute is:
4 grams per litre × 4 litres per minute = 16 grams per minute
The well-stirred mixture flows out of the tank at a rate of 2 litres per minute, so the amount of chemical flowing out of the tank per minute is:
C × 2 litres per minute = 2C grams per minute
The net change in the amount of chemical in the tank per minute is:
16 grams per minute - 2C grams per minute = 16 - 2C grams per minute
After 15 minutes, the net change in the amount of chemical in the tank is:
(16 - 2C) grams per minute × 15 minutes = 240 - 30C grams
The final amount of chemical in the tank is:
m = 24 + 240 - 30C = 264 - 30C grams
The final volume of the solution in the tank is:
V = 12 + 4 litres per minute × 15 minutes - 2 litres per minute × 15 minutes = 42 litres
The final concentration of the solution in the tank is:
C = m/V = (264 - 30C)/42
Solving for C, we get:
42C = 264 - 30C
72C = 264
C = 264/72 = 3.67 grams per litre
The final amount of chemical in the tank is:
m = C × V = 3.67 grams per litre × 42 litres = 154.14 grams
Therefore, the amount of chemical in the tank after 15 minutes is 154.14 grams.
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plsssssssss hlp, geometry
Answer:
I believe opposing angles are parallel, so it would be 98
Step-by-step explanation:
Select ALL the correct answers. Which of the following statements are true about the equation below? The graph of the quadratic equation has a minimum value. The extreme value is at the point (7,-3). The solutions are . The solutions are . The extreme value is at the point (3,-7). The graph of the quadratic equation has a maximum value.
The graph of the quadratic equation has a minimum value, The extreme value is at the point (7,-3), and The graph of the quadratic equation has a maximum value are all true about the equation.
What is a quadratic equation?A quadratic equation is a mathematical expression made up of four terms which are arranged in the form of a polynomial. It is usually used to solve for the unknown values of two or more variables. It is also defined as a mathematical equation containing a second-order polynomial that can be written in the form of ax2 + bx + c = 0.
The graph of the quadratic equation has a minimum value, The extreme value is at the point (7,-3), and The graph of the quadratic equation has a maximum value are all true about the equation. The solutions for the equation are 3 and 7, which can be found by using the Quadratic Formula. The extreme value is at the point (7,-3) since this is the lowest value of the graph.
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Find the inverse of each of the following matrices (g) \( \left[\begin{array}{ccc}-1 & -3 & -3 \\ 2 & 6 & 1 \\ 3 & 8 & 3\end{array}\right] \) (h) \( \left[\begin{array}{ccc}1 & 0 & 1 \\ -1 & 1 & 1 \\
For matrix g : \(\displaystyle g^{-1}=\frac{1}{\left| g \right|}\left[\begin{array}{ccc}6 & 1 & -3 \\ -8 & -3 & 2 \\ 3 & -1 & -3\end{array}\right] \)
For matrix h : \(\displaystyle h^{-1}=\frac{1}{\left| h \right|}\left[\begin{array}{ccc}1 & 0 & -1 \\ 1 & -1 & 1 \\ 0 & 1 & -1\end{array}\right] \)
For matrix g, the inverse can be found using the following equation:
\(\displaystyle g^{-1}=\frac{1}{\left| g \right|}\left[\begin{array}{ccc}6 & 1 & -3 \\ -8 & -3 & 2 \\ 3 & -1 & -3\end{array}\right] \)
For matrix h, the inverse can be found using the following equation:
\(\displaystyle h^{-1}=\frac{1}{\left| h \right|}\left[\begin{array}{ccc}1 & 0 & -1 \\ 1 & -1 & 1 \\ 0 & 1 & -1\end{array}\right] \)
Where \(\left| g \right|\) is the determinant of the matrix g and \(\left| h \right|\) is the determinant of the matrix h.
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Ella purchased a new car in 2000 for $27,600. The value of the car has been depreciating exponentially at a constant rate. If the value of the car was$8,300 in the year 2004, then what would be the predicted value of the car in the year 2009,? answer to the nearest dollar
The predicted value of the car in the year 2009 is $6,232.
How to predict the value of the car in the year 2009 ?First we need to use the formula for exponential decay:
V(t) = V0 × e^(-rt)
Where
V(t) is the value of the car at time tV0 is the initial value of the carr is the rate of decayt is the time elapsed since the initial purchaseWe know that the car was purchased in 2000 for $27,600, and that its value in 2004 was $8,300. Therefore, we can use these values to solve for the rate of decay:
$8,300 = $27,600 × e^(-r x 4)
e^(-4r) = 0.3
Taking the natural logarithm of both sides:
-4r = ln(0.3)
r = -0.3567
Now that we have the rate of decay, we can use the same formula to predict the value of the car in 2009, which is 9 years after the initial purchase:
V(9) = $27,600 × e^(-0.3567 x 9) = $6,232
Therefore, the predicted value of the car in the year 2009 is $6,232.
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What should be reason 8 in the following proof?
Answer: I think putting Prop of ║lines might work. I haven't done this in a long time, so I'm most likely wrong, but that might help. I'm so sorry.
Without making calculations, what data set has the smallest standard deviation?
Answer: the last option
Step-by-step explanation:
Standard derivation reflects the degree if dispersion of a data set
so the answer is 1,1,1,1,2,2,2,2
can any of you help me please
The two equivalent expressions are the second one and the last:
(56x + 24)/8 and 3 + 7x
How to identify the equivalent expression?We want to find an equivalent expression to 56x + 24 divided by 8, so we want to simplify the expression:
(56x + 24)/8 (that is the second expression)
We can distribute that division so we get:
(56x + 24)/8 = (56x)/8 + 24/8
Now we can simplify these two quotients so we get:
(56x)/8 + 24/8 = 7x + 3 (that is the last expression).
Then the two equivalent expressions are:
(56x + 24)/8 and 3 + 7x
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Help is greatly appreciated :). Will mark brainliest !:D
Answer:
The volume of a rectangular solid is given by the formula V = LWH, where L is the length, W is the width, and H is the height.
In this case, we have:
W = x + 3
L = x + 2
H = x
So the volume is:
V = (x + 2)(x + 3)(x)
V = x(x + 2)(x + 3)
V = x(x^2 + 5x + 6)
V = x^3 + 5x^2 + 6x
Therefore, the volume of the rectangular solid is given by the polynomial expression x^3 + 5x^2 + 6x.
The coach for the Lady Bugs basketball team kept track of the scores of their games. Lady Bugs Game Scores
57
50
57
53
53
62
57
What is the range of the scores of the games?
A. 62
B. 50
C. 57
D. 12
The range of the scores of the basketball games played by the Lady Bugs basketball team is equal to option D. 12.
Scores of the games played by Lady Bugs basketball team is equal to
57, 50, 57, 53, 53, 62, 57
Arrange the scores of the team in ascending order we get,
50, 53, 53, 57, 57, 57, 62
Highest score of the team = 62
Lowest score of the team = 50
Range = highest score - lowest score
Substitute the value in the formula we get,
⇒ Range = 62 - 50
⇒ Range = 12
Therefore, the range of the score of the game played by basketball team is equal to option D. 12.
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if tan t = 11/7 and 0≤ t≤????/2 find sin t, cost, csc t, sect, and cott. To enter the square root of a number, type "sqrt(a)". For example, type "sqrt(2)" to enter √2. sin t = cos t = csc t = sec t = cot t =
The hypotenuse is sqrt(11^2 + 7^2) = sqrt(170). Then, sin t = 11/sqrt(170), cos t = 7/sqrt(170), csc t = sqrt(170)/11, sec t = sqrt(170)/7, and cot t = 7/11.
Since we know that tan t = 11/7, we can use the Pythagorean identity (sin^2 t + cos^2 t = 1) to find the other trigonometric functions. First, we will find sin t and cos t:
tan t = 11/7 = opposite/adjacent = sin t/cos t
sin t = 11*cos t
cos t = 7*sin t
Substituting the second equation into the first equation:
sin t = 11*(7*sin t)
sin^2 t = 121*sin^2 t
121*sin^2 t - sin^2 t = 0
120*sin^2 t = 0
sin^2 t = 0/120
sin^2 t = 0
sin t = 0
Since sin t = 0, cos t = 1. Now we can find the other trigonometric functions:
csc t = 1/sin t = 1/0 = undefined
sec t = 1/cos t = 1/1 = 1
cot t = 1/tan t = 1/(11/7) = 7/11
So, the values of the trigonometric functions are:
sin t = 0
cos t = 1
csc t = undefined
sec t = 1
cot t = 7/11
Note: Another way to find the values of the trigonometric functions is to use the Pythagorean Theorem to find the hypotenuse of the right triangle with sides 11 and 7.
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4: 7 and 12 : whats the ratio
heklllllllllllllllllllp
Answer:
15.2
Step-by-step explanation:
[tex]x^{2} =8.7^{2}+12.5^{2} \\x^{2} =231.94\\x=15.229...\\x=15.2[/tex]
Help me, please. I hate math and I suck at it
Answer:
See below.
Step-by-step explanation:
We are asked to find the value of x.
We should know that these angles are Same-Side Interior Angles.
What are Same-Side Interior Angles?
Same-Side Interior Angles are 2 angles that aren't equal, but supplementary. They're formed inside 2 parallel lines.
What are Supplementary Angles?Supplementary angles are 2 angles that add up to 180°.
Since these 2 angles are Same-Side Interior Angles, both can be added to equal 180°.
[tex]4x+2x+12=180[/tex]
Combine Like Terms:
[tex]6x=168\\x = 28[/tex]
The value of x is 28.
What is the greatest common factor of 3 and 9?
Answer:3
Step-by-step explanation:
The HCF of 3 and 9 is 3. To calculate the HCF (Highest Common Factor) of 3 and 9, we need to factor each number (factors of 3 = 1, 3; factors of 9 = 1, 3, 9) and choose the highest factor that exactly divides both 3 and 9 . i.e 3.
Which function grows at the fastest rate for increasing values of x?
Responses
h(x)=6x2+1
h open parentheses x close parentheses equals 6 x squared plus 1
g(x)=4x
g open parentheses x close parentheses equals 4 to the power of x end power
f(x)=9x+14
This is due tο the fact that as x grοws, the quadratic cοmpοnent in g(x) and f(x), respectively, predοminates οver the cοnstant term and the linear term.
what is functiοn?A functiοn is a mathematical fοrmula that relates every element in οne set, knοwn as the dοmain, tο a single element in anοther set, knοwn as the range. The relatiοnship between input and οutput, the relatiοnship between a variable and its rate οf change, and many οther real-wοrld phenοmena are all examples οf this basic mathematical idea. Algebraic expressiοns, graphs, tables, and even wοrds can be used tο describe functiοns. They are a crucial instrument in many disciplines, including cοmputer science, statistics, and calculus.
given:
Fοr rising values οf x, the fοllοwing functiοn exhibits the fastest grοwth:
h(x) = 6x² + 1.
This is due tο the fact that as x grοws, the quadratic cοmpοnent in g(x) and f(x), respectively, predοminates οver the cοnstant term and the linear term. As a result, οf the functiοns listed, h(x) grοws at the fastest pace.
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A puppy weighed 28 ounces on Monday. It gained 7 ounces in one week. What is the percent increase of the puppy's weight rounded to the nearest percent?
The percent increase of the puppy's weight is 25%
How to calculate the percentage increase of the puppy's weight?A puppy weighed 28 ounces on Monday
It gained 7 ounces in one week
Total weight is = 28 + 7
= 35
The percent increase can be calculated as follows
= 35/28
= 1.25
= 1.25-1
= 0.25 × 100
= 25%
Hence the percent increase of the puppy's weight is 25%
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Dave travel of 120 km/h it takes him 90 minutes to reach his destination It takes him. How far is his destination