PLS HELP ME WILL MAKRK BRAINLIEST 1. In the distance, an airplane is taking off. As it ascends during take-off, it makes a slanted line that outs through the rainbow at two points. Create a table of at least four values for the function that includes two points of intersection between the airplane and the rainbow.
2. Analyze the two functions. Answer the following reflection questions in complete sentences
• What is the domain and range of the rainbow? Explain what the domain and range represent. Do all of the values make sense in this situation? Why or why not?
• What are the x- and v-intercepts of the rainbow? Explain what each intercept represents.
• Is the linear function you created with your table positive or negative? Explain.
¡a What are the solutions or solution to the system of equations created? Explain
what it or they represent.
13. Create your own piecewise function with at least two functions. Explain, using complete sentences, the steps for graphing the function. Graph the function by hand or using a graphing software of your choice (remember to submit the graph).

Answer:

-2,1,6,13,22

Step-by-step explanation:

cn = n^2 -3

Let n=1

c1 = 1^2 -3 = 1-3 = -2

Let n=2

c2 = 2^2 -3 = 4-3 = 1

Let n=3

c3 = 3^2 -3 = 9-3 = 6

Let n=4

c4 = 4^2 -3 = 16-3 = 13

Let n=5

c5 = 5^2 -3 = 25-3 = 22

The equation that represents the total cost of purchasing currency is 1.30x + 1.50y = 3200.00.

The equation that represents the relationship between the number of currency A and number of currency B is x = 5y.

x = 2000 and y = 400

There are 2000 of currency A and 400 of currency B

In order to write a system of linear equations to describe this situation, we would assign variables to the number of currency A and currency B, and then translate the word problem into an algebraic equation as follows:

Since she budgeted $3200.00 for spending money on an upcoming trip and currency A is trading at $1.30 per euro, and currency B is trading at $1.50 per pound, a system of linear equations to describe this situation is given by;

1.30x + 1.50y = 3200.00

x = 5y

1.30(5y) + 1.50y = 3200.00

8y = 3200

y = 3200/8

y = 400

x = 5y

x = 5(400)

x = 2000

Read more on linear equation here: brainly.com/question/25858757

#SPJ1

Answer:

The derivative of the function:

[tex]f'(x)=-\dfrac{1}{2\sqrt{5-x} }[/tex]

The tangent line of the function at the given point:

[tex]y=-\dfrac{1}{6}x-\dfrac{25}{3}[/tex]

Step-by-step explanation:

Find the equation of the tangent line of the given function using the given point.

[tex]f(x)=6+\sqrt{5-x}; \ (x,y)=(-4,9)[/tex]

[tex]\hrulefill[/tex]

To find the equation of the tangent line to a function at a given point, follow these step-by-step instructions:

Step 1: Identify the point of tangency

Step 2: Find the derivative of the function

Step 3: Substitute the x-coordinate into the derivative

Step 4: Write the equation of the tangent line

Step 5: Optional - Simplify the equation

Step 6: Optional - Verify the equation

[tex]\hrulefill[/tex]

Step 1:

[tex](x_0,y_0) \rightarrow (-4,9)[/tex]

Step 2:

[tex]f(x)=6+\sqrt{5-x}\\\\\\\Longrightarrow f(x)=6+(5-x)^{1/2}\\\\\\\Longrightarrow f'(x)=\dfrac{1}{2} (5-x)^{1/2-1} \cdot -1\\\\\\\therefore \boxed{f'(x)=-\dfrac{1}{2\sqrt{5-x} } }[/tex]

Step 3:

[tex]f'(x)=-\dfrac{1}{2\sqrt{5-x} } ; \ (-4,9)\\\\\\\Longrightarrow f'(-4)=-\dfrac{1}{2\sqrt{5-(-4)} } \\\\\\\Longrightarrow f'(-4)=-\dfrac{1}{2\sqrt{9}} \\\\\\\Longrightarrow f'(-4)=-\dfrac{1}{2(3)} \\\\\\\therefore \boxed{ f'(-4)=m=-\dfrac{1}{6} }[/tex]

Step 4 and 5:

[tex]y-y_0=m(x-x_0)\\\\\\\Longrightarrow y-9=-\dfrac{1}{6}(x-(-4)) \\\\\\\Longrightarrow y-9=-\dfrac{1}{6}(x+4) \\\\\\\Longrightarrow y-9=-\dfrac{1}{6}x-\dfrac{2}{3}\\\\ \\\therefore \boxed{\boxed{ y=-\dfrac{1}{6}x-\dfrac{25}{3}}}[/tex]

Thus, the problem is solved.

The fraction represented by point A, it is crucial to have information about the scale, intervals, and the relative position of point A on the number line.

With these details, you can calculate the fraction accurately.

Point A on the number line represents a fraction that requires additional information to determine its precise value.

I can provide you with a general approach to finding the fraction corresponding to a given point on the number line.

A number line represents a range of values, typically with a specific scale or interval.

The scale can be divided into equal parts, such as units or fractions.

To determine the fraction represented by point A, we need to know the scale and the position of point A relative to that scale.

Let's consider a number line that ranges from 0 to 1, with evenly spaced tick marks representing tenths.

If point A is located halfway between the tick marks representing 0.4 and 0.5, then it represents the fraction 0.45 (or 9/20 in simplified form).

If the number line has a different scale or is divided into different intervals, the fraction represented by point A will be different.

Without specific details about the number line and the position of point A, it is impossible to determine the fraction precisely.

For similar questions on fraction

https://brainly.com/question/78672

#SPJ8

Answer:

1. Geometric Sequence Equation for Table A:

[tex]\boxed{\tt a_n = a_1 \times r^{(n-1)}}[/tex]

2. Arithmetic Sequence Equation for Table B:

[tex]\boxed{\tt a_n = a_1 + (n-1) \times d}[/tex]

3.

Step-by-step explanation:

1. Geometric Sequence Equation for Table A:

The geometric sequence equation is given by the formula:

[tex]\tt \[a_n = a_1 \times r^{(n-1)}\][/tex]

where:

For Table A, since we don't have the actual values, we can represent the equation as:

[tex]\boxed{\tt a_n = a_1 \times r^{(n-1)}}[/tex]

[tex]\hrulefill[/tex]

2. Arithmetic Sequence Equation for Table B:

The arithmetic sequence equation is given by the formula:

[tex]\tt a_n = a_1 + (n-1) \times d[/tex]

where:

For Table B, since we don't have the actual values, we can represent the equation as:

[tex]\boxed{\tt a_n = a_1 + (n-1) \times d}[/tex]

[tex]\hrulefill[/tex]

3. Finding Term 20 for both sequences:

In order to find the 20th term for both sequences, we need the actual values for [tex]\tt \(a_1\), \(r\)[/tex] and d.

in the case of Table A

[tex]\tt a_{20} = a_1 \times r^{(20-1)}[/tex]

[tex]\boxed{\tt a_{20} = a_1 \times r^{19}}[/tex]

in the case of Table B.

[tex]\tt a_{20} = a_1 + (20-1) \times d[/tex]

[tex]\boxed{\tt a_{20} = a_1 + 19\times d}[/tex]

By using this formula, we can easily fill up the box.

Therefore, the solutions to the equation 0 = |3x + 3| + 3 are x = -2 and x = 0.

To solve the equation 0 = |3x + 3| + 3, we need to eliminate the absolute value. Remember that the absolute value of a number is always non-negative.

First, let's isolate the absolute value term on one side of the equation:

|3x + 3| = -3

Since the absolute value cannot be negative, there are no solutions to the equation as it stands. However, if we modify the equation to make the right side positive, we can find a solution.

To eliminate the absolute value, we can rewrite the equation as two separate equations, considering both the positive and negative cases:

   3x + 3 = -3

   -(3x + 3) = -3

Solving equation 1:

3x + 3 = -3

3x = -6

x = -2

Solving equation 2:

-(3x + 3) = -3

-3x - 3 = -3

-3x = 0

x = 0

For such more question on equation

https://brainly.com/question/29174899

#SPJ8

Answer:

  [tex]81x\cdot e^{9x}-36x^5\cdot\ln(x)[/tex]

Step-by-step explanation:

You want the derivative ...

  [tex]\displaystyle \dfrac{d}{dx}\int_{x^6}^{e^{9x}}{\ln{(t)}}\,dt[/tex]

The fundamental theorem of calculus tells you the derivative is ...

  [tex]\displaystyle \dfrac{d}{dx}\int_{u(x)}^{v(x)}{f(t)}\,dt=f(v(x))v'(x)-f(u(x))u'(x)\\\\\\\dfrac{d}{dx}\int_{x^6}^{e^{9x}}{\ln{(t)}}\,dt=\ln(e^{9x})\cdot9e^{9x}-\ln{(x^6)}\cdot6x^5\\\\\\\boxed{81x\cdot e^{9x}-36x^5\cdot\ln(x)}[/tex]

__

Additional comment

A factor of 9x can be brought out:

  = 9x(9e^(9x) -4x^4·ln(x))

You know that ln(e^u) = u, and ln(x^6) = 6·ln(x).

<95141404393>

Answer:

slope (m) = 2/3

Step-by-step explanation:

slope = change in x /change in y

Also, slope is y2 - y1 / x2 -x1. That is what I apply for this activity, hence:

slope = 3 - (-1) / 0 - (-6)

         = 3 + 1 / 0 + 6

         = 4 / 6

         = 2/3

∴ slope(m) = 2/3

By using trigonometric functions, the value of [tex]\sin \text{x}^\circ[/tex] is [tex]\frac{\text{a}}{\text{b}}[/tex].

Trigonometric functions are also known as Circular Functions can be simply defined as the functions of an angle of a triangle. It means that the relationship between the angles and sides of a triangle are given by these trig functions. The basic trigonometric functions are sine, cosine, tangent, cotangent, secant and cosecant.

Given

[tex]\sin \text{x}^\circ= \ ?[/tex]

[tex]\tan \text{x}^\circ=\dfrac{\text{a}}{4}[/tex]

[tex]\cos \text{x}^\circ=\dfrac{4}{\text{b}}[/tex]

Formula to find [tex]\sin \text{x}^\circ[/tex]

[tex]\sin \text{x}^\circ=\dfrac{\text{Opposite}}{\text{Hypotenuse}}[/tex]

[tex]\rightarrow\sin \text{x}^\circ=\bold{\dfrac{a}{b}}[/tex]

Therefore, by using trigonometric functions, the value of [tex]\sin \text{x}^\circ[/tex] is [tex]\frac{\text{a}}{\text{b}}[/tex].

To know more about trigonometric functions, visit:

https://brainly.com/question/31540769

Although the chef used fresh ingredients, Karen knew the pasta dish was tasty but not healthy.Type of Parallel Structure: Parallelism using correlative conjunctions

Every year, I go on a long hiking trip where I like to take a break away from the hustle of the city and enjoy the peacefulness within nature.

Type of Parallel Structure: Parallelism in a series of items

Derek enjoys playing baseball with his friends, going on camping trips with his dad, and traveling to different cities throughout the year.

Type of Parallel Structure: Parallelism in a series of items

I like playing hockey more than I like to play soccer.

Type of Parallel Structure: Parallelism in a comparative sentence

Jonathan enjoys watching comedy at the movie theater more than he likes watching horror films at the movie theater.

Type of Parallel Structure: Parallelism in a comparative sentence

When I go to the park, I like bringing a blanket and to pack a picnic basket full of sandwiches and fruit.

Type of Parallel Structure: Parallelism using the same verb tense

In these sentences, the type of parallel structure used in each sentence has been matched correctly.

For such more question on Parallelism

https://brainly.com/question/1466033

#SPJ8