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The function f(x) = -3(2)²+¹ +90 represents the number of tokens a child has x hours after arriving at an arcade.
What is the practical domain and range of the function?
Enter your answer by filling in the boxes to correctly complete the statements. If necessary, round to the nearest hundrea
The practical domain of the situation is x
Basic
The practical range of the situation is 90
A
O

The roster method of the set X ∪ (Y ∩ Z) = {p, q, r, s, 21, 22, 23, 25}

The roster method is defined as a way to show the elements of a set by listing the elements inside of brackets.

A typical example of the roster method is to write the set of numbers from 1 to 5 as {1, 2, 3, 4, 5}.

Therefore,

X = {p, q, r, 21, 22, 23}

Y = {q, s, t, 21, 23, 25}

Z = {q, s, 22, 23, 25}

Therefore, let's find X ∪ (Y ∩ Z) as follows:

(Y ∩ Z) = {q, s, 23, 25}

X = {p, q, r, 21, 22, 23}

Therefore,

X ∪ (Y ∩ Z) = {p, q, r, s, 21, 22, 23, 25}

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Answer:

x = - 1

Step-by-step explanation:

P = [tex]\frac{x-2}{x+1}[/tex]

the denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the value that x cannot be.

x + 1 = 0 ( subtract 1 from both sides )

x = - 1

P is undefined when x = - 1

a) The experimental probability of landing on red or yellow is:

P(red or yellow) = 33/40

b) The theoretical probability can be computed as follows:

P(red or yellow)  = 8/10

c) As the number of spins increases: Option A: we expect the experimental and theoretical probabilities to become closer, though they might not be equal.

Theoretical probability represents the likelihood of an event occurring. The theoretical probability of getting heads is 1/2, because we know that the probability of heads and tails on a coin is equal. Experimental probability describes how often an event actually occurred in an experiment.  

a) The experimental probability of landing on red or yellow is:

P(red or yellow) = (20/40) + (13/40) = 33/40

b) The theoretical probability can be computed as follows:

P(red or yellow) = (4/10) + (4/10) = 8/10

c) As the number of spins increases, we expect the experimental and theoretical probabilities to become closer, though they might not be equal.

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The system of equations that is represented by the graph include:

D. y = x - 4

   [tex]y=\frac{x-4}{x+2}[/tex]

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):

y - y₁ = m(x - x₁)

Where:

First of all, we would determine the slope of the red line;

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = (0 + 5)/(4 + 1)

Slope (m) = 5/5

Slope (m) = 1

At point (4, 0) and a slope of 1, a linear equation for C can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 0 = 1(x - 4)

y = x - 4

Since the rational function has a y-intercept of (0, -2), it would have a vertical asymptote and the denominator would be undefined at x = 2;

[tex]y=\frac{x-4}{x+2}[/tex]

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The number of subsets in the given set is as follows:

128.

Considering a set with n elements, the number of subsets in the set is the nth power of 2, that is:

[tex]2^n[/tex]

The set in this problem is composed by integers between 2 and 8, hence it has these following elements:

{2, 3, 4, 5, 6, 7, 8}.

The set has four elements, meaning that n = 7, hence the number of subsets is given as follows:

[tex]2^7 = 128[/tex]

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The arrow is at a height of 48 ft after approx. 3 - √6 s and after 3 + √6 s.

To find the time it takes for the arrow to reach a height of 48 ft, we can use the formula for the height of the arrow:

s = v0t - 16t^2

Here, s represents the height of the arrow, v0 is the initial velocity, and t is the time.

Given that the initial velocity, v0, is 96 ft/s and the height, s, is 48 ft, we can set up the equation:

48 = 96t - 16t^2

Now, let's solve this equation to find the time it takes for the arrow to reach a height of 48 ft.

Rearranging the equation:

16t^2 - 96t + 48 = 0

Dividing the equation by 16 to simplify:

t^2 - 6*t + 3 = 0

We now have a quadratic equation in the form of at^2 + bt + c = 0, where a = 1, b = -6, and c = 3.

Using the quadratic formula:

t = (-b ± √(b^2 - 4ac)) / (2a)

Plugging in the values:

t = (6 ± √((-6)^2 - 413)) / (2*1)

t = (6 ± √(36 - 12)) / 2

t = (6 ± √24) / 2

Simplifying the square root:

t = (6 ± 2√6) / 2

t = 3 ± √6

Therefore, the arrow reaches a height of 48 ft after approximately 3 + √6 seconds and 3 - √6 seconds.

In summary, the arrow takes approximately 3 + √6 seconds and 3 - √6 seconds to reach a height of 48 ft, assuming an initial velocity of 96 ft/s.

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Note the complete question is

The height of an arrow shot upward can be given by the formula s = v0*t - 16*t², where v0 is the initial velocity and t is time.How long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s?  

Solve (t-3)^2=6

The arrow is at a height of 48 ft after approx. ___ s and after ___ s.

The equation of the lines expressed in point-slope form and the average rate of change of the functions indicates that we get;

The point-slope form of the equation of a line can be represented in the following form; y - y₁ = m(x - x₁), where; m is the slope of the line and (x₁, y₁) is a point on the line.

1. (a) The slope of the line parallel to the line; 5·x - 3·y = 10, can be obtained by writing the equation of the line in slope-intercept form as follows;

5·x - 3·y = 10, therefore; y = 5·x/3 - 10/3

The slope of the parallel line is therefore; 5/3

The point-slope form of the equation of the line is therefore;

y - 6 = (5/3)·(x - (-2)) = (5/3)·(x + 2)

y - 6 = (5/3)·(x + 2)

3·y - 18 = 5·x + 10

3·y - 5·x = 10 + 18 = 18

(b) The equation of the line, 2·x + 4·y - 12 = 0, indicates;

The slope of the line is; -2/4 = -1/2

The slope of the perpendicular line = -1/(-1/2) = 2

The equation of the perpendicular line passing through the point (2, -7) in point-slope form is therefore;

y - (-7) = 2·(x - 2)

y + 7 = 2·(x - 2)

(c) The line passing through point (-2, -4), and parallel to y = -3 is the line y = -4

(d) The line passing through point (4, -1), and perpendicular to x = 0 is the line y = -1

2. (a) f(-1) = 2 × (-1)² + (-1) - 1 = 0

f(3) = 2 × (3)² + (3) - 1 = 20

The average is; (f(3) - f(-1))/(3 - (-1)) = 20/4 = 5

(b) f(1) = 150, f(3) = 50

Average = (f(3) - f(1))/(3 - 1)

Average = (150 - 50)/(3 - 1) = 50

(c) f(4) = 4² - 4  

f(4 + h) = (4 + h)² - (4 + h) = (h + 3)·(h + 4)

Average = (f(4 + h) - f(4))/(4 + h - 4) = ((h + 3)·(h + 4) - (4² - 4))/(h)

((h + 3)·(h + 4) - (4² - 4))/(h) = (h² + 7·h + 12 - 12)/h = h + 7

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The measure of line segment x in the game board is approximately 13.6.

The secant-tangent power theorem states that "if a tangent and a secant are drawn from a common external point to a circle, then the product of the length of the secant segment and its external part is equal to the square of the length of the tangent segment.

It is expressed as:

( tangent segment )² = External part of the secant segment × Secant segment.

From the given figure:

Let;

Tangent segment = 12

Secant segment = 7 + x

External part of the secant segment = 7

Plug these values into the above formula and solve for x.

( tangent segment )² = External part of the secant segment × Secant segment.

12² = 7( 7 + x)

144 = 49 + 7x

7x = 144 - 49

7x = 95

x = 95/7

x = 13.6

Therefore, the value of x is approximately 13.6.

Option C) 13.6 is the correct answer.

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To determine the minimum sample size required to estimate the proportion of students who bring laptops to campus with a 99% confidence level and a margin of error within five percentage points, we can use the formula:

[tex]n = \frac{(Z^2 \times p \times (1 - p))}{ E^2}[/tex]

Where:

n is the required sample size,

Z is the Z-score corresponding to the desired confidence level,

p is the estimated population proportion (since no prior estimate is available, we use 0.5 as a conservative estimate),

E is the margin of error.

For a 99% confidence level, the Z-score is approximately 2.58 (obtained from the z table).

Plugging in the values:

[tex]n = \frac{(2.58^2 \times 0.5 \times (1 - 0.5))} { (0.05^2)}[/tex]

Simplifying the equation:

n = 663.924

Rounding up to the nearest whole number, the minimum sample size required is approximately 664 students.

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Answer:

Step-by-step explanation:

                                                   error

Answer:

x ≈ 75.2

Step-by-step explanation:

using the tangent ratio in the right triangle

tan62° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{x}{40}[/tex] ( multiply both sides by 40 )

40 × tan62° = x , then

x ≈ 75.2 ( to the nearest tenth )

The amount that can be withdrawn immediately after the last deposit is approximately $8,876.80.

We can use the formula for the future value of an ordinary annuity. The formula is given by:

[tex]FV = P * [(1 + r/n)^(^n^t^) - 1] / (r/n)[/tex]

Where

Given:

Plugging in the values, we have:

[tex]FV = 480 * [(1 + 0.045/2)^(^2*^8^) - 1] / (0.045/2)[/tex]

Calculating the expression inside the brackets

[tex](1 + 0.045/2)^(^2^*^8^) = 1.0225^1^6[/tex]≈ 1.4197

Substituting this value back into the formula:

FV = 480 * (1.4197 - 1) / (0.045/2)

FV = 480 * 0.4197 / 0.0225

FV ≈ $8,876.80

So, the amount that can be withdrawn immediately after the last deposit is approximately $8,876.80.

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The correct equation is sin h° = z ÷ x, which states that the sine of angle A is equal to the ratio of the length of side AB to the length of side AC.

The correct equation relating the angles and segments in triangle ACB depends on the specific trigonometric function and the angle we are considering.

In triangle ACB, angle C is a right angle, which means it measures 90 degrees. The other two angles, angle A and angle B, are complementary angles, meaning their sum is also 90 degrees. Therefore, angle A measures h degrees and angle B measures g degrees, where h + g = 90.

Now let's consider the segments in the triangle. Segment AC measures x, segment CB measures y, and segment AB measures z.

When it comes to trigonometric functions, sine (sin) and cosine (cos) are commonly used. These functions relate the angles and sides of a right triangle.

The correct equation involving the angles and segments can be determined based on the trigonometric function that relates the desired angle to the desired segment.

If we want to relate angle A (measuring h degrees) to the segment AB (measuring z), we can use the sine function. Therefore, the correct equation is:

sin h° = z ÷ x

This equation relates the sine of angle A to the ratio of the lengths of the side opposite angle A (segment AB) and the hypotenuse (segment AC).

In summary, the correct equation is sin h° = z ÷ x, which states that the sine of angle A is equal to the ratio of the length of side AB to the length of side AC.

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Answer:

(A) AA similarity

Step-by-step explanation:

In ΔABC,

∠A + ∠B + ∠C = 180

∠A + 27 + 90 = 180

∠A = 180 - 90 - 27

∠A = 63

Comparing ΔABC and ΔMNP,

∠A = ∠M = 63

∠C = ∠P = 90

Therfore, by AA property, the two triangles are similar

The quadratic function with the solutions given in the problem is defined as follows:

x² + 3x + 3 = 0.

The standard definition of a quadratic function is given as follows:

y = ax² + bx + c.

The solutions are given as follows:

[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

Comparing the standard solution to the solution given in this problem, the parameters a and b are given as follows:

The coefficient c is then obtained as follows:

b² - 4ac = -3.

9 - 4c = -3

4c = 12

c = 3.

Hence the function is:

x² + 3x + 3 = 0.

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The area of the irregular shape is 34 square feet.

To find the area of the irregular shape, we need to break it down into smaller components and calculate their individual areas.

We will assume the irregular shape is composed of three rectangles.

Rectangle 1: Length = 6 ft, Width = 4 ft.

Area = Length × Width

Area = 6 ft × 4 ft

Area = 24 square feet.

Rectangle 2: Length = 4 ft, Width = 1 ft.

Area = Length × Width

Area = 4 ft × 1 ft

Area = 4 square feet.

Rectangle 3: Length = 1 ft, Width = 6 ft.

Area = Length × Width

Area = 1 ft × 6 ft

Area = 6 square feet.

Total Area = Area of Rectangle 1 + Area of Rectangle 2 + Area of Rectangle 3

Total Area = 24 square feet + 4 square feet + 6 square feet

Total Area = 34 square feet.

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