Pls solve 50 points!!!!!!!!!​

Pls Solve 50 Points!!!!!!!!!

Answers

Answer 1

Refer to the attachment for solution

Pls Solve 50 Points!!!!!!!!!
Pls Solve 50 Points!!!!!!!!!

Related Questions

The 'bar-and-gauge' experiment is designed to show the effect clearly. It is difficult to see the expansion of a metal even when it is heated by several hundred degrees. The bar-and-gauge' experiment is often used to show that a metal expands when heated. Write a brief script for a teacher who wants to use this demonstration of thermal expansion and who also wants to show that metals contract on cooling. Include practical instructions.​

Answers

Thermal expansion is defined as the property of metals to expand when they are heated.

The metal expands when heated because the atoms move apart more.

An excellent method to demonstrate the concept of thermal expansion is using the bar and gauge experiment.

Both the diameter and the length are precisely comparable when both are at room temperature.

The bar will not fit within the gauge once it has been heated and cooled. Similar to the last instance; the bar will no longer fit flush inside the gauge if the gauge is heated and the bar is cooled.

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Gravity pulls objects downward. How much work is performed when gravity pulls the man down 0.5 m after each step?

Answers

Each time gravity pulls the man down 0.5 m, it does work of -367.5 J. This work is converted into kinetic energy as the man gains velocity while moving downwards.

The work performed by gravity pulling a man down 0.5 m after each step can be determined utilizing the recipe: work = force x distance x cos(theta), where power is the heaviness of the man (mass x speed increase because of gravity), distance is 0.5 m, and theta is the point between the course of power and the heading of movement (which is 180 degrees since the man is moving downwards).

Expecting the man has a mass of 75 kg, the weight can be determined as 75 kg x 9.8 m/s^2 = 735 N. In this way, the work done by gravity after each step is:

work = 735 N x 0.5 m x cos(180 degrees) = - 367.5 J

The negative sign demonstrates that the work done by gravity is the other way to the relocation of the man. In this way, each time gravity pulls the man down 0.5 m, it takes care of business of - 367.5 J. This work is changed over into active energy as the man acquires speed while moving downwards.

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The diagram shows two sets of vectors that result in a
single vector.
R
100 m
200 m
250 m
50 m
What are the first two steps for finding the magnitude of
the resultant vector?
find the square of the first horizontal vector and the
square root of the first vertical vector
O find the square root of the first horizontal vector and
the square root of the second horizontal vector
O find the sum of the two horizontal vectors and the
sum of the two vertical vectors
O find the difference between the two horizontal vectors
and the difference between the two vertical vectors

Answers

The magnitude of the resultant vector is obtained by finding the sum of two horizontal vectors and the sum of two vertical vectors. Thus, option C is correct.

The resultant vector is the single vector that has the same effect in the number of vectors collectively produced. The resultant vector in the horizontal and vertical direction is obtained by drawing a diagonal and hence by using the Pythagoras theorem.

To find resultant vector is obtained by finding the sum of two horizontal vectors and vertical vectors and then using the Pythagoras theorem.

Thus, the ideal solution is option C.

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In which circuit would ammeter A shows the greatest current?

Answers

In the circuit with two 10Ω resistors in parallel, ammeter A would show the greatest current. This is because, in a parallel circuit, the total resistance is lower than in a series circuit, which means that the current can flow more easily.

In this case, the two 10Ω resistors in parallel create a total resistance of 5Ω (1/Rtotal = 1/10 + 1/10 = 2/10, Rtotal = 10/2 = 5), while in the series circuit,https://brainly.com/question/11409042?referrer=searchResults the total resistance would be 20Ω (10 + 10). Ohm's law states that the current is directly proportional to the voltage and inversely proportional to the resistance, so the circuit with lower resistance will allow for greater current flow.

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--The complete Question is, In which circuit would ammeter A show the greatest current: a circuit with one 6V battery and two 10Ω resistors in parallel or a circuit with one 6V battery and two 10Ω resistors in series? --

1. Which of the following does not affect the resistance of a wire?
a) Length
b) Temperature
c) Usage time
d) Cross-sectional area
2. If a 12V battery is passing current through a resistor with a current of 2A, what is the value of the resistor?
a 24resistance
b) 14resistance
c) 10resistance
d) 6resistance
3. Describe the differences between series and parallel circuits.
4. A circuit contains resistors of 8resistance and 4resistance,what is combined resistance if the resistors are combined:
a) In series
b) In parallel
5. A 0.5A current is passing across three resistors of 8resistance, 4resistance and 12resistance that are linked in series.
What is the potential difference of the circuit?
6. Wire A has a resistance of 24resistance. If wire B is double the length and has a diameter four times as large as wire A, what is the resistance of wire B?

Answers

The answer right there is b

A falling object accelerates from
-10.0 m/s to -30.0 m/s. How much
time does that take?
(Unit = s)
Remember: Falling = -v
a = -9.80 m/s²
Lost height = -Ay
Be careful with minus signs!!!/for acellus

Answers

It takes 2.04 seconds for the object to accelerate from -10.0 m/s to -30.0 m/s.

Velocity is a measure of an object's speed in a specific direction. It is calculated by dividing the distance traveled by the time taken and specifying the direction of the motion.

We can use the following formula to find the time taken for an object to change velocity under constant acceleration:

Δv = a × Δt

where Δv is the change in velocity, a is the acceleration, and Δt is the time taken.

In this case, the initial velocity is -10.0 m/s, and the final velocity is -30.0 m/s. So, the change in velocity is:

Δv = (-30.0 m/s) - (-10.0 m/s) = -20.0 m/s

The acceleration of the falling object is -9.80 m/s² (negative because the object is falling downward).

Now, we can rearrange the formula to solve for Δt:

Δt = Δv / a

Substituting the values we have:

Δt = (-20.0 m/s) / (-9.80 m/s²) = 2.04 seconds

Therefore, The object accelerates from -10.0 m/s to -30.0 m/s in 2.04 seconds.

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A flat-bottomed barge loaded with coal has a mass of 4.80 × 105 kg. The barge is 20.0 m long and 10.0 m wide. It floats in fresh water. What is the depth of the barge below the waterline?

Answers

The depth of the barge below the waterline is 2.40 m.

To calculate the depth of the barge below the waterline, we need to consider the buoyancy force acting on the barge. The buoyancy force is equal to the weight of the water displaced by the barge.

First, we need to calculate the volume of water displaced by the barge.

Since the barge is flat-bottomed, we can assume that the shape of the displaced water is rectangular with a length of 20.0 m, a width of 10.0 m, and a depth of d (which is what we're trying to find).

Therefore, the volume of water displaced is V = 20.0 m x 10.0 m x d = 200.0 m³.

The weight of the displaced water can be calculated using its density and volume. In fresh water, the density of water is approximately 1000 kg/m³.

Therefore, the weight of the displaced water is W = 1000 kg/m³ x 200.0 m³ = 2.00 × 10⁵ kg.

Since the buoyancy force is equal to the weight of the displaced water, we have [tex]F_b[/tex] = W = 2.00 × 10⁵ kg.

The weight of the barge is [tex]W_b[/tex] = 4.80 × 10⁵ kg. According to Archimedes' principle, the buoyancy force acting on an object in a fluid is equal to the weight of the fluid displaced by the object, so we can write:

[tex]F_b[/tex] = [tex]W_b[/tex] - [tex]W_d[/tex]

where [tex]W_d[/tex] is the weight of the water displaced by the submerged part of the barge. Solving for [tex]W_d[/tex], we get:

[tex]W_d[/tex] = [tex]W_b[/tex] - [tex]F_b[/tex] = 4.80 × 10⁵ kg - 2.00 × 10⁵ kg = 2.80 × 10⁵ kg.

The volume of water displaced by the submerged part of the barge is equal to the volume of the rectangular prism with a length of 20.0 m, a width of 10.0 m, and a depth of d. Therefore, we can write:

[tex]V_d[/tex] = 20.0 m x 10.0 m x d = 200.0 m³ x (d/10.0)

The weight of the displaced water is also equal to its density times its volume, so we have:

[tex]W_d[/tex] = 1000 kg/m³ x [tex]V_d[/tex]

Substituting [tex]V_d[/tex] in terms of d and solving for d, we get:

d = ([tex]W_d[/tex] / (1000 kg/m³ x 200.0 m²)) x 10.0 m = (2.80 × 10⁵ kg / (1000 kg/m³ x 200.0 m²)) x 10.0 m = 2.40 m

Therefore, the depth of the barge below the waterline is 2.40 m.

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4 Starting from rest on a level road a girl can reach a speed of 5 m/s in 10s on her bicycle. a Find the acceleration b Find the average speed during the 10s. c Find the distance she travels in 10 s. [2] Eventually, even though she still pedals as fast as she can, she stops accelerating and her speed reaches a maximum value. Explain in terms of the forces acting why this happens. ​

Answers

a. To find the acceleration, we can use the equation:

acceleration = change in velocity / time taken

Here, the initial velocity is 0 m/s (since she starts from rest), the final velocity is 5 m/s, and the time taken is 10 s. Therefore:

acceleration = (5 m/s - 0 m/s) / 10 s = 0.5 m/s^2

So the acceleration of the girl on her bicycle is 0.5 m/s^2.

b. The average speed during the 10 s can be found by dividing the total distance traveled by the time taken. We don't know the distance traveled yet, so we can use another equation:

distance = (initial velocity x time taken) + (0.5 x acceleration x time taken^2)

Here, the initial velocity is 0 m/s, and the time taken is 10 s. We already calculated the acceleration in part (a) as 0.5 m/s^2. Plugging these values in, we get:

distance = (0 m/s x 10 s) + (0.5 x 0.5 m/s^2 x (10 s)^2) = 25 meters

So the girl traveled 25 meters in 10 seconds.

c. As the girl pedals, she applies force to the pedals, which in turn transfers the force to the rear wheel. This force drives the bicycle forward, causing it to gain speed. However, when the bicycle picks up speed, air resistance (also called drag) comes into play, which increases. Eventually, the force of air resistance becomes equal and opposite to the force that propels the bicycle forward. This means that the net force on the bicycle becomes zero, stopping its acceleration and reaching its maximum speed, known as the terminal velocity. Even if the girl pedals faster, she won't be able to increase her speed because the drag force counteracts the propelling force.

Two glasses are filled with liquid to the same height . Glass W is filled with water and glass F is filled with fruit juice. Fruit juice has a higher density than water. Will the pressure in the glass of water be higher or smaller than the pressure in the glass of fruit juice.? Explain your answer​

Answers

The weight at the foot of each glass will be the same because it is decided by the stature of the fluid column over it and the increasing speed due to gravity. Be that as it may, the weight applied by the fluid on the dividers of the holder will be diverse due to contrasts in thickness.

Since natural product juice incorporates a higher thickness than water, the mass of the same volume of natural product juice will be more noteworthy than that of water.

This implies that the constraint applied by the natural product juice on the dividers of the glass will be more prominent than the constraint applied by the water on the dividers of its glass, as the drive is straightforwardly corresponding to mass.

Subsequently, the weight of the glass of natural product juice will be higher than the weight of the glass of water.

In rundown, in spite of the fact that the weight at the foot of each glass will be the same, the weight applied by the fluid on the dividers of the holder will be diverse due to the contrasts in thickness, with the natural product juice applying a more noteworthy weight. 

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a group of campers decide to take a canoe trip down the river. the campers traveled 25 miles in five hours. at what average speed did the group of campers travel down the river?

Answers

The average speed of the campers down the river was 5 miles per hour.

Total distance traveled by the campers = 25 miles

Total time taken by the campers = 5 hours

Speed is defined as the rate of change in distance or altitude reached. It is a time-based quantity. In the given question, a camper's average speed can be calculated by dividing the total distance travelled by the time taken.

Calculating the average speed of the campers -

Average speed = Total distance / Time taken

Substituting the values -

= 25 miles / 5 hours

= 5

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Which of the following gases is the major byproduct of fossil fuel combustion?
methane
water vapor
sulfuric acid
carbon dioxide

Answers

Answer:

Carbon dioxide and water vapour

Explanation:

So the products of a combustion reaction are primarily:

carbon dioxide + water vapour, however other gases such as nitrogen, methane, and sulphur dioxide are also produced in smaller concentrations.

Carbon dioxide and water vapour are the main byproducts

Answer:

Carbon dioxide

Explanation:

The major byproduct of fossil fuel combustion is carbon dioxide. When fossil fuels such as coal, oil, and natural gas are burned, they release carbon dioxide into the atmosphere. This is because fossil fuels are made up of hydrocarbons, which are compounds made up of carbon and hydrogen. When these compounds are burned, they react with oxygen in the air to produce carbon dioxide [tex]\rm (CO_2)[/tex] and water vapor [tex]\rm (H_2O)[/tex].

Methane is also produced during fossil fuel combustion, but in smaller amounts compared to carbon dioxide. Sulfuric acid is not a byproduct of fossil fuel combustion, but rather a product of the reaction between sulfur dioxide [tex]\rm (SO_2)[/tex] and water vapor in the atmosphere. While water vapor is also produced during fossil fuel combustion, it is not considered a major byproduct, as it is a natural component of the air and atmosphere.

what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees

Answers

Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:

You have the initial velocity (v): 35 m/s

You have the launch angle (θ): 45 degrees

We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.

To calculate vx (horizontal component):

vx = v * cosθ

vx = 35 * cos(45) = 24.7 m/s

To calculate vy (vertical component):

vy = v * sinθ

vy = 35 * sin(45) = 24.7 m/s

We can calculate the horizontal distance (d) traveled using:

d = vx * t (where t is time)

Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:

t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)

t = 24.7 / 9.8 = 2.52 seconds

Now we can calculate the full horizontal distance traveled:

d = vx * t

d = 24.7 * 2.52

= 62.3 meters

So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.

Let me know if you have any other questions!

Answer:

To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.

The horizontal component of the motion remains constant throughout the trajectory and is given by:

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.

The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:

Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)

Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.

The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.

Using these calculations, we can find the horizontal distance traveled by the object.

Let's calculate step by step:

Step 1: Calculate the time of flight

Vertical displacement = 0 (at the highest point)

0 = (35 * sin(45))^2 / (2 * 9.8)

0 = (24.75^2) / 19.6

0 = 616.0125 / 19.6

0 = 31.43

Step 2: Calculate the time of flight

Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2

0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2

0 = 24.75 * time - 4.9 * time^2

4.9 * time^2 - 24.75 * time = 0

time * (4.9 * time - 24.75) = 0

time = 0 (initial point) or 24.75 / 4.9

time = 5.05 seconds

Step 3: Calculate the horizontal distance

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

Horizontal distance = 35 * 5.05 * cos(45)

Horizontal distance = 35 * 5.05 * (sqrt(2)/2)

Horizontal distance = 88.96 meters

Therefore, when an object is thrown at 35 m/s at an angle of 45 degrees, the full distance traveled is approximately 88.96 meters.

Centripetal force
A. causes objects to increase their speed.
B. does not affect the speed of object.
C. does not change the velocity of an
object.
D. causes objects to slow down.

Answers

Answer:

C. does not change the velocity of an object.

Explanation:

Centripetal force is the force that acts on an object moving in a circular path and is directed towards the center of the circle. It is responsible for changing the direction of the object's velocity towards the center of the circle, but it does not change the magnitude of the velocity, which means that it does not affect the speed of the object. Therefore, option B and D are incorrect. The direction of the velocity is constantly changing due to the centripetal force, but the magnitude of the velocity, or speed, remains constant. Option A is also incorrect because centripetal force is not responsible for increasing the speed of the object, but rather for changing the direction of its velocity.

You will need to know that Force (N) is equal to mass (kg) multiplied by acceleration (m/s2) for this problem. A fearless space explorer has discovered a new planet with a frictionless surface! He pushes a large crate with a mass of 220kg a distance of 5.3 km, as he does so, it accelerates at a rate of 2m/s2. How much work has our intrepid hero done? PLSS helppp

Answers

The intrepid hero has done 2.332 x[tex]10^6[/tex] Joules of work in pushing the crate.

To ascertain the work done by the traveler, we first need to find the power he applied on the case. As per Newton's subsequent regulation, force is equivalent to mass times speed increase, so the power applied by the traveler on the container is:

Force = mass x speed increase

Force = 220 kg x 2 [tex]m/s^2[/tex] = 440 N

Then, we really want to work out the distance the case was moved. The pilgrim pushed the box a distance of 5.3 km, or 5,300 m.

At long last, we can compute the work done by the pioneer utilizing the equation:

Work = force x distance

Work = 440 N x 5,300 m

Work = [tex]2.332 x 10^6[/tex] Joules

Thusly, the valiant legend has done 2.332 x [tex]10^6[/tex] Joules of work in pushing the case.

The space pilgrim takes care of business on the case by applying a power that makes it speed up. The work done is equivalent to the power duplicated by the distance over which the power is applied. Involving the recipe for force, F=ma, and the given qualities for mass and speed increase, we can ascertain the power applied. Then, at that point, involving the recipe for work, W=Fd, and the given distance, we can ascertain the work done. The work done by the adventurer is 2.332 x [tex]10^6[/tex] J.

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A skier slides horizontally along the snow for a distance of 22 m before coming to rest. The coefficient of kinetic friction between the skier and the snow is 0.15. Initially, how fast was the skier going, in meters per second?

Answers

The skier was initially going at 8.046 m/s velocity.

Assume that the skier's initial velocity is v.

The skier travelled 22 metres before coming to a stop.

The kinetic friction coefficient between the skier and the snow is 0.15.

The force of friction acting on the skier is given by:

friction = coefficient of friction multiplied by normal force

The normal force is equal to the weight of the skier, which can be calculated as:

weight = mass x gravity

Assuming the mass of the skier to be m and the acceleration due to gravity to be g, we get:

weight = m x g

The force of friction can then be calculated as:

friction = 0.15 x m x g

The work done by the force of friction is equal to the initial kinetic energy of the skier, which can be expressed as:

work done by friction = 0.5 x m x [tex]v^2[/tex]

Equating the work done by friction to the initial kinetic energy, we get:

0.5 x m x [tex]v^2[/tex] = 0.15 x m x g x 22

Simplifying the equation, we get:

[tex]v^2[/tex] = 2 x 0.15 x 9.8 x 22

When we take the square root of both sides, we get:

v = 8.046 m/s

As a consequence, the skier began moving at 8.046 m/s.

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Which example best describes Newton's third law of motion?

F
When a glass slid across a table, it spilled water when it stopped suddenly.

G
An engine used less work to move a lighter car than when it moved a heavier car.

H When a passenger stepped from a boat to the shore, the boat moved away from the shore .

Answers

The best example of Newton's third law of motion is, When a passenger stepped from a boat to the shore, the boat moved away from the shore. Thus, option C is correct.

Sir Issac Newton gives three laws of motion. The first law states that an object remains at rest or in continuous motion unless an external force acted on it. The second law stated that the force is directly proportional to the acceleration of the object. Newton's third law states that, for every action, there is an equal and opposite reaction.

From the given, Newton's third law is applicable, When a passenger stepped from a boat to the shore, the boat moved away from the shore. This shows the action and reaction of the boat and shore.

Thus, the ideal solution is option C.

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Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?

Answers

Answer: τy = 2τx

Given: graph of L vs t
Ly = 20 at t = 5
Lx = 10 at t = 5
All L = 0 at t = 0
So change in angular momentum of y is 20 and x is 10

Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time

solve for average torque for each objects
τ(average) = ΔL / Δt

Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4

Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2

Relates τy and τx
2τx = τy


Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.

The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.

To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:

L = I * ω

Differentiating this equation with an appreciation of time, we get:

dL/dt = d(I * ω)/dt

Using the product rule of differentiation, we've got:

dL/dt = I * dω/dt + ω * dI/dt

Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:

τ = dL/dt

Substituting the expression for dL/dt in terms of angular velocity and second of inertia:

τ = I * dω/dt + ω * dI/dt

Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:

torquex = I0 * dω/dt + ω * dI0/dt

Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:

torquey = (2I0) * dω/dt + ω * d(2I0)/dt

torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)

torquey = 2I0 * dω/dt + 2ω * dI0/dt

Comparing the expressions for torquex and torquey, we will see that:

torquey = 2 * torquex

Therefore, the precise relation between torquey and torquex is;

torquey = 2 * torquex.

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The correct question is;

"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"

A plane wave in a nonmagnetic medium has E = 50 sin (10^8 + 2*z) ay V/m. Find (a) The direction of wave propagation (b) λ, f, and Er (c) H​

Answers

(a) The direction of wave propagation is along the negative z-axis.

(b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × [tex]10^{7}[/tex] Hz, and the wave impedance (Er) is approximately 0.1667 sin ([tex]10^{8}[/tex] + 2z) ohms.

(c) The magnetic field (H) is (50 sin ([tex]10^{8}[/tex] + 2z)) / (3 × [tex]10^{8}[/tex]) ay A/m.

If the direction of wave propagation is specified as along the negative z-axis, we can conclude that the wave is traveling in the opposite direction to the positive z-axis. In the given expression: E = 50 sin(10^8 + 2z) ay V/m

Since the wave is traveling along the negative z-axis, it means that as z increases (in the positive direction), the wave is propagating in the opposite direction.

Hence, the direction of wave propagation for the given wave is along the negative z-axis.

To find the wavelength (λ), frequency (f), and wave impedance (Er), we can relate the electric field (E) and magnetic field (H) components using the wave equation in a nonmagnetic medium:

E = c * H,

where c is the speed of light in the medium, which can be approximated as 3 × [tex]10^{8}[/tex] m/s in free space.

(a) Direction of wave propagation: Along the positive z-axis.

(b) Calculating λ, f, and Er:

Since the electric field (E) is given as E = 50 sin ([tex]10^{8}[/tex] + 2z) ay V/m, we can see that the angular frequency (ω) is [tex]10^{8}[/tex] rad/s and the wave number (k) is 2.

The relationship between wave parameters is given by: c = λ * f, where c is the speed of light.

Using the relation c = ω/k, we can solve for λ and f:

λ = 2π/k = 2π/2 = π m (meters)

f = ω/2π = [tex]10^{8}[/tex]/2π ≈ 1.59 × [tex]10^{7}[/tex] Hz (Hertz)

To find the wave impedance (Er), we can use the equation Er = E/H:

Er = E/c = (50 sin ([tex]10^{8}[/tex] + 2z)) / (3 × [tex]10^{8}[/tex]) ≈ 0.1667 sin ([tex]10^{8}[/tex] + 2z) ohms.

(c) The magnetic field (H) can be calculated using the relationship H = E/c:

H = (E/c) = (50 sin ([tex]10^{8}[/tex] + 2z)) / (3 × [tex]10^{8}[/tex]) ay A/m.

The direction of wave propagation is along the negative z-axis. (b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × [tex]10^{7}[/tex] Hz, and the wave impedance (Er) is approximately 0.1667 sin ([tex]10^{8}[/tex] + 2z) ohms. The magnetic field (H) is (50 sin ([tex]10^{8}[/tex] + 2z)) / (3 × [tex]10^{8}[/tex]) ay A/m.

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Which statement best suscribes what happens during chemical change?

Answers

Chemical change involves the rearrangement of atoms or molecules in a substance, resulting in the formation of new substances with different properties than the original substance.

A chemical change in a chemical reaction is a process where one or more substances undergo a chemical transformation, resulting in the formation of new substances with different chemical and physical properties than the original substances. During a chemical change, the atoms or molecules of the reacting substances are rearranged through chemical reactions, leading to the breaking and forming of chemical bonds and the release or absorption of energy.

Chemical changes occur when a material's chemical makeup is changed, creating one or more new compounds with qualities that are distinct from those of the original substance. Chemical reactions that result in the breaking and building of chemical bonds occur when the atoms or molecules of the substances involved are reorganized during a chemical shift. The release or absorption of energy in the form of heat, light, or sound is typically accompanied by this process.

Therefore, Rearranging atoms or molecules in a substance causes chemical change, which creates new compounds with differing properties from the original one.

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Waves portfolios I will give brainliest!

Now, leave the frequency constant, but play with the amplitude. What is the affect of changing the
amplitude on the tone generated?

Answers

Now, leave the frequency of wave constant, but play with the amplitude. then the effect of changing the amplitude on the tone generated is its loudness. more the amplitude more it will be loud.

Wave is is a disturbance in a medium that carries energy as well as momentum . wave is characterized by amplitude, wavelength and phase. Amplitude is the greatest distance that the particles are vibrating. especially a sound or radio wave, moves up and down. Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.

Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform. There are two types of the wave longitudinal wave and transverse wave.

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A hot water tap delivers water at the rate of 20kg per minute at 80°C. A cold water tap delivers cold water at the rate of 10kg per minute at 20 °C. If both tabs are open for 3 minutes, calculate the final temperature of the mixture of cold and hot water.​

Answers

The final temperature of the mixture of cold and hot water is 60°C.

To calculate the final temperature of the mixture of hot and cold water, we can use the principle of conservation of energy. The heat gained by the cold water is equal to the heat lost by the hot water.

Given:

Rate of hot water flow (m₁) = 20 kg/min

The initial temperature of hot water (T₁) = 80°C

Rate of cold water flow (m₂) = 10 kg/min

The initial temperature of cold water (T₂) = 20°C

Duration (t) = 3 minutes

Let's calculate the heat gained by the cold water and the heat lost by the hot water using the formula:

Heat gained = mass * specific heat capacity * temperature change

For the cold water:

Heat gained by cold water = m₂ * specific heat capacity * (final temperature - T₂)

For the hot water:

Heat lost by hot water = m₁ * specific heat capacity * (T₁ - final temperature)

Since the heat gained by the cold water is equal to the heat lost by the hot water, we can set up the equation:

m₂ * specific heat capacity * (final temperature - T₂) = m₁ * specific heat capacity * (T₁ - final temperature)

Let's substitute the given values and solve for the final temperature:

10 kg/min * specific heat capacity * (final temperature - 20°C) = 20 kg/min * specific heat capacity * (80°C - final temperature)

Simplifying the equation:

10 * (final temperature - 20) = 20 * (80 - final temperature)

10 * final temperature - 200 = 1600 - 20 * final temperature

30 * final temperature = 1800

final temperature = 1800 / 30

final temperature = 60°C

Therefore, the final temperature of the mixture of hot and cold water after 3 minutes will be 60°C.

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Some students are using the apparatus below to observe waves in a solid. The frequency of the generator is 19Hz. The wavelength of the waves in the string is 0.2m. Calculate the wave speed. Give your answer to two significant figures.​

Answers

Answer: 3.8

Explanation: speed = wavelength x frequency

The arrows in the diagram show the direction of the magnetic fields of the atoms that make up a certain material. Which object could the diagram represent ? A. A steel nail B. A refrigerator magnet C. A wooden log D. An iron bar

Answers

The diagram shows atoms with aligned magnetic fields, which means they are capable of producing a magnetic field themselves. The correct answer is option B.

This type of alignment is only found in materials that are magnetized, such as a refrigerator magnet. Steel nails and iron bars can also be magnetized, but they are typically only magnetic if they have been previously exposed to a magnetic field. Wood, on the other hand, is not capable of being magnetized as it does not have magnetic properties. Therefore, the diagram most likely represents a refrigerator magnet, which is made of a material that has been magnetized to produce a magnetic field. Option B is correct.

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Mercury has a mass of
3.30 x 1023 kg, and a radius of
2.44 x 106 m. What is the acceleration
of gravity on its surface?
[?] m/s² Please help!!!

Answers

Answer:

The acceleration due to gravity on the surface of a planet or celestial body is given by the formula:

g = G M / R^2

where G is the gravitational constant, M is the mass of the planet, and R is the radius of the planet.

Plugging in the values for Mercury, we get:

g = (6.674 x 10^-11 m^3/kg s^2) (3.30 x 10^23 kg) / (2.44 x 10^6 m)^2

Simplifying this expression gives:

g = 3.70 m/s^2

Therefore, the acceleration due to gravity on the surface of Mercury is approximately 3.70 m/s^2.

How many kilocalories of heat would be needed to melt 0.32 kg of ice at 0°C and increase the temperature to 25°C? The specific heat of water is 1 cal/g.°C, specific heat of ice is 0.5 cal/g.°C, the latent heat of ice to water is 80 cal/g. Keep one digit after the decimal.

Answers

To calculate the heat needed to melt the ice and raise the temperature, we need to break it down into two steps:

Step 1: Heat needed to melt the ice
The mass of ice is 0.32 kg, and the latent heat of ice to water is 80 cal/g. Therefore, the heat needed to melt the ice is:

0.32 kg x 80 cal/g = 25.6 kcal

Step 2: Heat needed to raise the temperature from 0°C to 25°C
The specific heat of water is 1 cal/g.°C, and the mass of water produced by melting the ice is also 0.32 kg. Therefore, the heat needed to raise the temperature from 0°C to 25°C is:

0.32 kg x 25°C x 1 cal/g.°C = 8 kcal

Total heat needed = Heat needed to melt the ice + Heat needed to raise the temperature
Total heat needed = 25.6 kcal + 8 kcal = 33.6 kcal

Therefore, 33.6 kilocalories of heat would be needed to melt 0.32 kg of ice at 0°C and increase the temperature to 25°C.

You will need to know that Force (N) is equal to mass (kg) multiplied by acceleration (m/s2) for this problem. A fearless space explorer has discovered a new planet with a frictionless surface! He pushes a large crate with a mass of 220kg a distance of 5.3 km, as he does so, it accelerates at a rate of 2m/s2. How much work has our intrepid hero done?

Answers

Our intrepid hero has done 2332 kJ of work pushing the crate on the frictionless surface of the newly discovered planet.

The work done by the space traveler can be determined utilizing the recipe W = F x d, where W is work, F is power, and d is distance. To find the power, we can utilize the recipe F = m x a, where m is mass and an is speed increase. Connecting the given qualities, we get F = 220 kg x 2 m/s^2 = 440 N.

Presently we can compute the work done by increasing the power by the distance: W = 440 N x 5.3 km = 2332 kJ. Accordingly, our fearless legend has done 2332 kJ of work pushing the container on the frictionless surface of the newfound planet.

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20N
10N
40N
30N
Balanced or Unbalanced?

Answers

Answer:

Unbalanced

Explanation:

An isolated charged conductor sphere of radius 12cm has an electric field 49000 N/C at distance 21cm its center
What is its surface charge denisty

Answers

The surface charge density of the isolated charged conductor sphere is approximately 22.15 [tex]C/m^{2}[/tex]

The surface charge density of an isolated charged conductor sphere can be determined using the formula:

σ = E / ([tex]4πr^{2}[/tex])

where σ is the surface charge density, E is the electric field strength, and r is the distance from the center of the sphere.

In this case, the electric field strength E is given as 49000 N/C, and the distance from the center of the sphere r is 21 cm (which can be converted to meters as 0.21 m). Plugging these values into the formula, we have:

σ = (49000 N/C) / [tex](4π * (0.21 m)^{2})[/tex]

Calculating this expression, we find:

σ ≈ 22.15 [tex]C/m^{2}[/tex]

Therefore, the surface charge density is approximately 22.15 [tex]C/m^{2}[/tex]. This indicates the amount of charge per unit area distributed on the surface of the sphere.

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You will need to know that Force (N) is equal to mass (kg) multiplied by acceleration (m/s2) for this problem. A fearless space explorer has discovered a new planet with a frictionless surface! He pushes a large crate with a mass of 220kg a distance of 5.3 km, as he does so, it accelerates at a rate of 2m/s2. How much work has our intrepid hero done?

Answers

Our intrepid hero has done 2332 kJ of work pushing the crate on the frictionless surface of the newly discovered planet.

The work done by the space traveler can be determined utilizing the recipe W = F x d, where W is work, F is power, and d is distance. To find the power, we can utilize the recipe F = m x a, where m is mass and an is speed increase. Connecting the given qualities, we get F = 220 kg x 2 m/s^2 = 440 N.

Presently we can compute the work done by increasing the power by the distance: W = 440 N x 5.3 km = 2332 kJ. Accordingly, our fearless legend has done 2332 kJ of work pushing the container on the frictionless surface of the newfound planet.

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what is the final velocity?

Answers

There are a few formulas you can use to calculate final velocity, depending on the information given:

If given initial velocity, acceleration, and time, use:

vfinal = vinitial + at

Where:

vfinal is the final velocity

vinitial is the initial velocity

a is the acceleration

t is the time

If given initial velocity, change in velocity, and time, use:

vfinal = vinitial + Δv

Where:

Δv is the change in velocity

If given displacement, initial velocity, acceleration, and time, use:

vfinal = √(vinitial2 + 2aΔx)

Where:

Δx is the displacement

If given initial and final displacements and time, use:

vfinal = Δx/t

So in summary, to calculate final velocity you need:

Initial velocity + Acceleration + Time

OR

Initial velocity + Change in velocity

OR

Initial velocity + Acceleration + Displacement + Time

OR

Initial/final displacement + Time

Then you can use the appropriate formula, plug in the known values, and solve for final velocity (vfinal).

Hope these formulas and explanations help! Let me know if you have any other questions.

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